Answer:
3yStep-by-step explanation:
each term has at least y^1
each term's coeficient is a factor of 3
3y(5y^2, 7y, 10)
3y is the GCFSuppose that insurance companies did a survey. They randomly surveyed 410 drivers and found that 300 claimed they always buckle up.
We are interested in the population proportion of drivers who claim they always buckle up.
NOTE: If you are using a Student's t-distribution, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.)
(i) Enter an exact number as an integer, fraction, or decimal.
x =
(ii) Enter an exact number as an integer, fraction, or decimal.
n =
(iii) Round your answer to four decimal places.
p' =
Which distribution should you use for this problem? (Round your answer to four decimal places.)
P' _ ( , )
Answer:
x = 300
n = 410
p' = 0.7317
[tex]\mathbf{P' \sim Normal (\mu = 0.7317, \sigma = 0.02188)}[/tex]
Step-by-step explanation:
From the given information;
the objective is to answer the following:
(i) Enter an exact number as an integer, fraction, or decimal.
Mean x = 300
(ii) Enter an exact number as an integer, fraction, or decimal.
Sample size n = 410
(iii) Round your answer to four decimal places.
Sample proportion p' of the drivers who always claimed they buckle up is :
p' = x/n
p' = 300/410
p' = 0.7317
Which distribution should you use for this problem? (Round your answer to four decimal places.)
P' _ ( , )
The normal distribution is required to be used because we are interested in proportions and the sample size is large.
Let consider X to be the random variable that follows a normal distribution.
X represent the number of people that always claim they buckle up
∴
[tex]P' \sim Normal (\mu = p' , \sigma = \sqrt{\dfrac{p(1-p)}{n}})[/tex]
[tex]P' \sim Normal (\mu = 0.7317, \sigma = \sqrt{\dfrac{0.7317(1-0.7317)}{410}})[/tex]
[tex]P' \sim Normal (\mu = 0.7317, \sigma = \sqrt{\dfrac{0.7317(0.2683)}{410}})[/tex]
[tex]P' \sim Normal (\mu = 0.7317, \sigma = \sqrt{\dfrac{0.19631511}{410}})[/tex]
[tex]P' \sim Normal (\mu = 0.7317, \sigma = \sqrt{4.78817341*10^{-4}})[/tex]
[tex]\mathbf{P' \sim Normal (\mu = 0.7317, \sigma = 0.02188)}[/tex]
Give me the correct format of report writing plzzz (subject English) help plz
Step-by-step explanation:
Hi, there!!..
The format of report writing are given in points;
Title (reflects of report as its main function and it should be clear, brief, specific and weighty.)After title you have to right place and date.and start your body,
Background information about the report. (it should be clear and have reasons)Purpose (the report should have purpose)Actions or, sequences of happening should be clearly written. Characters mentioned should be written properly.and write conclusion,
Observation (it should be clear, factual and objectives).You may add comments on it.
Hope it helps....
Solve for x. a) 10 b) 12 c) 13 d) 11
Answer:
A : 10
Step-by-step explanation:
Answer:
the correct answer is 12
Step-by-step explanation:
6/8=9/x
cross multiply
6x=72
divide by six
x=12
The diagram shows a right triangle and three squares. The area of the largest square is 363636 units^2 2 squared. Which could be the areas of the smaller squares?
Answer:
The answers are A. and B.
Step-by-step explanation:
Since the area of the largest square is 36. We need two numbers that equal 36. and A. had 6 and 30 so i picked it and it was right and B. is 28 and 8 which also equals 36. But, C. is 4 and 16 which is not 36. So A. and B. are the answers. Hope this helps! :)
We can use the Pythagorean theorem (a^2+b^2=c^2)(a
2
+b
2
=c
2
)left parenthesis, a, squared, plus, b, squared, equals, c, squared, right parenthesis to determine possible areas of the two smaller squares.
\text{Area of a square} =\text{side}^2Area of a square=side
2
start text, A, r, e, a, space, o, f, space, a, space, s, q, u, a, r, e, end text, equals, start text, s, i, d, e, end text, squared
So, we can substitute the areas of the squares that share side lengths with the triangle for a^2, b^2a
2
,b
2
a, squared, comma, b, squared and c^2c
2
c, squared in the Pythagorean theorem.
Hint #22 / 6
For example, in the diagram above, the area of the square that shares a side with the hypotenuse is 363636 square units. So, c^2=36c
2
=36c, squared, equals, 36.
Hint #33 / 6
Let's fill in the possible values to see if they make the equation true.
\begin{aligned} a^2 + b^2 &= c^2 \\\\ a^2 + b^2 &= 36 \\\\ 6 + 30 &\stackrel{\large?}{=}36 \\\\ 36 &\stackrel{\checkmark}{=}36\\\\ \end{aligned}
a
2
+b
2
a
2
+b
2
6+30
36
=c
2
=36
=
?
36
=
✓
36
The sum of the areas of the squares connected to the two shorter triangle sides is equal to the area of the square connected to the longest side.
So, 666 and 303030 could be the areas of the smaller squares.
Hint #44 / 6
\begin{aligned} a^2 + b^2 &= c^2 \\\\ a^2 + b^2 &= 36 \\\\ 8 + 28 &\stackrel{\large?}{=}36 \\\\ 36 &\stackrel{\checkmark}{=}36\\\\ \end{aligned}
a
2
+b
2
a
2
+b
2
8+28
36
=c
2
=36
=
?
36
=
✓
36
The sum of the areas of the squares connected to the two shorter triangle sides is equal to the area of the square connected to the longest side.
So, 888 and 282828 could be the areas of the smaller squares.
Hint #55 / 6
\begin{aligned} a^2 + b^2 &= c^2 \\\\ a^2 + b^2 &= 36 \\\\ 4 + 16 &\stackrel{\large?}{=}36 \\\\ 20 &\neq 36\\\\ \end{aligned}
a
2
+b
2
a
2
+b
2
4+16
20
=c
2
=36
=
?
36
=36
The sum of the areas of the squares connected to the two shorter triangle sides is not equal to the area of the square connected to the longest side.
So, 444 and 161616 could not be the areas of the smaller squares.
Hint #66 / 6
The area of the smaller squares could be:
666 and 303030
888 and 2828
17. Convert the following measures of liquid measure. a. 3,450 deciliters to cubic decimeters _______ b. 124.3 hectoliters to deciliters _______ c. 9 liters to cubic centimeters _______ d. 32.5 liters to cubic decimeters _______
Step-by-step explanation:
. 345,000 cm³.
b. 124,300 hl.
c. 9,000 cm³.
d. 32.5 dm³.
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
a. 3,450 deciliters to cubic decimeters:
1 deciliter=100 cubic decimeters
(3,450dl)(\frac{100cm^{3}}{1dl})=345,000cm^{3}(3,450dl)(
1dl
100cm
3
)=345,000cm
3
b. 124.3 hectoliters to deciliters:
1 hectoliter=1,000 deciliters
(124,3hl)(\frac{1,000dl}{1hl})=124,300hl(124,3hl)(
1hl
1,000dl
)=124,300hl
c. 9 liters to cubic centimeters:
1 liter=1,000 cubic centimeters
(9L)(\frac{1,000cm^{3}}{1L})=9,000cm^{3}(9L)(
1L
1,000cm
3
)=9,000cm
3
d. 32.5 liters to cubic decimeters:
1 liter=1 cubic decimeter
32.5L=32.5dm^{3}32.5L=32.5dm
3
your answer follow me plzzz
Answer:
The first one is 345,000 cm³.
The second is 124,300 hl.
the Third is 9,000 cm³.
Anddd the fourth one is 32.5 dm³
:)
The triangles in the diagram are congruent. If mF = 40°, mA = 80°, and mG = 60°, what is mB?
Answer:
40
Step-by-step explanation:
The measure of m∠B in the triangle is 40°.
What is a triangle?A triangle is a 2-D figure with three sides and three angles.
The sum of the angles is 180 degrees.
We can have an obtuse triangle, an acute triangle, or a right triangle.
We have,
Since the triangles are congruent, we know that their corresponding angles are congruent as well.
Therefore, we have:
m∠B = m∠F = 40°.
Note that we also have:
m∠C = m∠A = 80° (by corresponding angles)
m∠H = m∠G = 60° (by corresponding angles)
Finally, we can use the fact that the sum of the angles in a triangle is 180° to find the measure of angle D:
m∠D = 180° - m∠B - m∠C = 180° - 40° - 80° = 60°.
Therefore,
m∠B = 40°.
Learn more about triangles here:
https://brainly.com/question/25950519
#SPJ7
The average weight of a person is 160.5 pounds with a standard deviation of 10.4 pounds. 1. What is the probability a person weighs more than 150.2 pounds
Answer:
0.8390
Step-by-step explanation:
From the question,
Z score = (Value-mean)/standard deviation
Z score = (150.2-160.5)/10.4
Z score = -0.9904.
P(x>Z) = 1- P(x<Z)
From the Z table,
P(x<Z) = 0.16099
Therefore,
P(x>Z) = 1-0.16099
P(x>Z) = 0.8390
Hence the probability that a person weighs more than 150.2 pounds = 0.8390
Find the exact perimeter (in inches) and area (in square inches) of the segment shown, given that m∠O = 60° and OA = 24 in.
Answer:
A. Perimeter of segment = 49 in.
B. Area of segment = 52 in².
Step-by-step explanation:
Data obtained from the question include:
Radius (r) = 24 in.
Angle at the centre (θ) = 60°
Perimeter of segment =.?
Area of segment =.?
A. Determination of the perimeter of the segment.
Perimeter of segment = length of arc + length of chord
Length of arc = θ/360 x 2πr
Length of chord = 2r x sine (θ/2)
Pi (π) = 3.14
Length of arc = θ/360 x 2πr
Length of arc = 60/360 x 2 x 3.14 x 24
Lenght of arc = 25.12 in
Length of chord = 2r x sine (θ/2)
Length of chord = 2 x 24 x sine (60/2)
Length of chord = 24 in
Perimeter of segment = length of arc + length of chord
Perimeter of segment = 25.12 + 24
Perimeter of segment = 49.12 ≈ 49 in.
B. Determination of the area of the segment.
Area of segment = Area of sector – Area of triangle.
Area of sector = θ/360 x πr²
Area of triangle = r²/2 sine θ
Area of sector = θ/360 x πr²
Area of sector = 60/360 x 3.14 x 24²
Area of sector = 301.44 in²
Area of triangle = r²/2 sine θ
Area of triangle = 24²/2 x sine 60
Area of triangle = 249.42 in².
Area of segment = Area of sector – Area of triangle.
Area of segment = 301.44 – 249.42
Area of segment = 52.02 ≈ 52 in²
Cerra Co. expects to receive 5 million euros tomorrow as a result of selling goods to the Netherlands. Cerra estimates the standard deviation of daily percentage changes of the euro to be 1 percent over the last 100 days. Assume that these percentage changes are normally distributed. Use the value-at-risk (VaR) method based on a 95 percent confidence level. What is the maximum one-day percentage loss if the expected percentage change of the euro tomorrow is 0.5 percent
Answer:
The maximum one-day percentage loss = -1.15%
Step-by-step explanation:
Let assume that with the normal distribution, 95% of observations are smaller than 1.65 standard deviations above the mean.
Given that:
Cerra estimates the standard deviation of daily percentage changes of the euro to be 1 percent over the last 100 days.
if the expected percentage change of the euro tomorrow is 0.5 percent
and that Z value at 95% C.I level = 1.65
∵ The maximum one-day percentage loss = (expected percentage change - Z-Value) × standard deviation
The maximum one-day percentage loss = (0.5 - 1.65) × 1
The maximum one-day percentage loss = -1.15 × 1
The maximum one-day percentage loss = -1.15%
A certain medicine is given in an amount proportional to patient’s body weight. Suppose a patient weigh in 116 pounds requires 126 mg of medicine. What is the amount of medicine required by patient way and 174 pounds?
Answer: 189 mg.
Step-by-step explanation:
Let x be the weight of the body( in pounds) and y be the amount of medicine( in mg).
Given: A certain medicine is given in an amount proportional to patient’s body weight.
i.e. [tex]\dfrac{x_1}{y_1}=\dfrac{x_2}{y_2}[/tex]
Let [tex]x_1=116\ \ \ ,\ y_1=126[/tex] , [tex]x_2=174[/tex]
then,
[tex]\dfrac{116}{126}=\dfrac{174}{y_2}[/tex]
[tex]\Rightarrow\ y_2=\dfrac{174\times126}{116}\\\\\Rightarrow\ y_2=189[/tex]
Hence, he amount of medicine required by patient weighing 174 pounds = 189 mg.
Select all the equations where x=3 is a solution. A. x-3=0 B. 1+ x=2 C. 9-x=3 D. 6=2x E. 15x=3 F. x2=9
Answer:
A. x-3=0 D. 6=2x F. x^2=9
Step-by-step explanation:
Substitute x=3 into each equation
A. x-3=0 3-3 =0 0=0 x=3 is a solution
B. 1+ x=2 1+3 =2 4=2 false
C. 9-x=3 9-3 =3 6=3 false
D. 6=2x 6 = 2*3 6=6 x=3 is a solution
E. 15x=3 15*3 =3 45=3 false
F. x^2=9 3^2 = 9 9=9 x=3 is a solution
If F(x) = f(g(x)), where f(−4) = 8, f '(−4) = 3, f '(−3) = 5, g(−3) = −4, and g'(−3) = 6, find F '(−3). F '(−3)
Answer:
F'(-3) = 18
Step-by-step explanation:
Let g(x) = u and apply the chain rule
[tex]F(x)=f(g(x))=f(u)\\F'(x)=\frac{df(u)}{du}[/tex]
[tex]\frac{du}{dx}=g'(x)[/tex]
[tex]\frac{df(u)}{du}*\frac{du}{dx} = \frac{df(u)}{dx}\\F'(x)= \frac{df(u)}{du}*g'(x)\\F'(x)= f'(u)*g'(x)\\F'(x)= f'(g(x))*g'(x)[/tex]
We now have all of the necessary definite values to solve the expression for x= -3:
[tex]F'(-3)= f'(g(-3))*g'(-3)\\F'(-3)= f'(-4)*6\\F'(-3)= 3*6\\F'(-3)= 18[/tex]
Finally, we have that F'(-3)= 18.
Witch table represents a linear function ?
Answer:
If you compute the slope between any two points that must be the same, that's how you can tell if a table represents a linear function.
Remember that the slope between any two points (x1,y1), (x2,y2) is
slope = ( y2 - y1 ) / (x2 - x1)
Step-by-step explanation:
If you compute the slope between any two points that must be the same, that's how you can tell if a table represents a linear function.
Remember that the slope between any two points (x1,y1), (x2,y2) is
slope = ( y2 - y1 ) / (x2 - x1)
18. Which of the following equations is equivalent to 25x = 7?
A. x=
log2 (3)
+1+9= 3? Is
B.
log27
5
C.
X=
log, 2
5
log, 5
D. x=
2
Answer:
x = log (7)/ 2log 5
Step-by-step explanation:
25^ x = 7
Replace 25 with 5^2
5^ 2x = 7
Take log on each side
log (5 ^2x) = log ( 7)
We know that log a^ b = b log a
2x log 5 = log (7)
Divide each side by log 5
2x log 5/ log 5= log (7)/ log 5
2x = log (7)/ log 5
Divide each side by 2
x = log (7)/ 2log 5
Eli is making a party mix that contains pretzels and chex. For each cup of pretzels, he uses 3 cups of chex. He wants to make 12 cups of party mix.
Answer:
36 cups of Chex total.
Step-by-step explanation:
Well, he will obviously be using 12 cups of pretzels, so let's set that aside. For every cup of pretzels, there are 3 cups of chex. So, multiply 3x12. That will give you how much chex you will need.
Consider the y-intercepts of the functions. F(c)=1/5lx-15l, g(x) =(x-2)2, the y-coordinate of the greatest y-intercept is ______
Answer: 4
Step-by-step explanation:
Given functions:
[tex]f(x)=\dfrac{1}{5}|x-15|\\\\ g(x)=(x-2)^2[/tex]
We know that the y--intercept of a function is the value of the function at x=0.
so, put x=0 in both the functions.
The y-coordinate of the y-intercept of f(x) = [tex]f(0)=\dfrac{1}{5}|0-15|=\dfrac{15}{5}=3[/tex]
The y-coordinate of the y-intercept of g(x) = [tex]g(0)=(0-2)^2=2^2=4[/tex]
As 4 > 3, that means he y-coordinate of the greatest y-intercept is 4.
If parallelogram EFGH is a rhombus, calculate the area of rhombus EFGH if EG=1.7 and FH=1.1, if there is not enough information say there is not enough info. Picture of rhombus:
Write an inequality and show on a number line all numbers: greater than (−3) but less than or equal to 3
To write an inequality and show on a number line all numbers: greater than (−3) but less than or equal to 3
Let n be the number, then -3 < n ≤3 .
On number line we mark open circle at -3 (since it has a strictly less than sign) and a closed circle at 3 (since it has a less than and equal to sign) .
To the required inequality that shows all the numbers greater than (−3) but less than or equal to 3 : -3 < n ≤3 and the number line is represented below.
Please help. I’ll mark you as brainliest if correct!
Answer:
[tex]\large \boxed{\sf \ \ x=0, \ \ y=-5 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
We have two equations:
(1) -2x - 4y = 20
(2) -3x + 5y = -25
5*(1)+4*(2) gives
-10x - 20y -12x + 20y = 100 - 100 = 0
-22x = 0
x = 0
I replace in (1)
-4y = 20
y = -20/4 = -5
There is one solution x = 0, y = -5
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Answer:
The two equations are
-2x-4y=20
-3x+5y=-25
multiply equation 1 by 5 and equation 2 by 4
-10x-20y=100
-12x+20y=-100
-22x=0
x=0
Substitute value in either equation
y=-5
So,option 1 is correct only one solution
Suppose we want to choose 5 letters, without replacement, from 10 distinct letters. How many ways can this be done, if the order of the choices is relevant? How many ways can this be done, if the order of the choices is not relevant?
Step-by-step explanation:
If the order is relevant, the number of permutations is:
₁₀P₅ = 30,240
If the order is not relevant, the number of combinations is:
₁₀C₅ = 252
The number of ways to choose 5 letters among 10 without replacement will be 252 and with replacements will be 30240.
What are permutation and combination?When the order of the arrangements counts, a permutation is a numerical approach that establishes the total number of alternative arrangements in a collection.
The number of alternative configurations in a collection of things when the order of the selection is irrelevant is determined by combination.
The number of ways to choose r quantity among n without replacement is given as nCr = n!/(r!(n - 1)!)
n = 10 and r = 5
10C5 = 252
The number of ways to choose r quantity among n with replacement is given as, nPr = n!/(n - r)!
n = 40 and r = 5
10P5 = 10!/(10 - 5)! = 30240
Hence "The number of ways to choose 5 letters among 10 without replacement will be 252 and with replacements will be 30240".
For more about permutation and combination,
https://brainly.com/question/13387529
#SPJ2
A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 17 subjects had a mean wake time of 104.0 min. After treatment, the 17 subjects had a mean wake time of 97.5 min and a standard deviation of 21.9 min. Assume that the 17 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 104.0 min before the treatment? Does the drug appear to be effective?
Answer:
The 95% confidence interval of mean wake time for a population with treatment is between 86.2401 and 108.7599 minutes.
This interval contains the mean wake time before treatment and which does not prove to be effective
Step-by-step explanation:
GIven that :
sample size n = 17
sample mean [tex]\overline x[/tex] = 97.5
standard deviation [tex]\sigma[/tex] = 21.9
At 95% Confidence interval
the level of significance ∝ = 1 - 0.95
the level of significance ∝ = 0.05
[tex]t_{\alpha/2} = 0.025[/tex]
Degree of freedom df = n - 1
Degree of freedom df = 17 - 1
Degree of freedom df = 16
At ∝ = 0.05 and df = 16 , the two tailed critical value from the t-table [tex]t_{\alpha/2 , 16}[/tex] is :2.1199
Therefore; at 95% confidence interval; the mean wake time is:
= [tex]\overline x \pm t_{\alpha/2,df} \dfrac{s}{\sqrt{n}}[/tex]
= [tex]97.5 \pm 2.1199 \times \dfrac{21.9}{\sqrt{17}}[/tex]
= 97.5 ± 11.2599
= (86.2401 , 108.7599)
Therefore; the mean wake time before the treatment was 104.0 min
The 95% confidence interval of mean wake time for a population with treatment is between 86.2401 and 108.7599 minutes.
This interval contains the mean wake time before treatment and which does not prove to be effective
what is the average when you add 122.99%, 108.46% and 102.65%? I don't know how to add percentages.
Answer:
111.33667
Step-by-step explanation:
You add percentages just like you would any other number.
122.9% + 108.46% + 102.65% = 334.01%
334.01%/3 = 111.33667
i give you brailenst
Answer:
The answer is #3 which is 24%.
Step-by-step explanation:
6 × 100
25
25 into 100 is 4, then 6×4 = 24%
I really hope this helps :)
The winery sold 81 cases of wine this week. If twice
as many red cases were sold than white. how many
white cases were sold this week?
Answer:
21 cases
Step-by-step explanation:
red cases=2x. white cases=x
2x+x=81
3x=81
x=21 cases
Please answer this correctly without making mistakes
Answer:
2 km
Step-by-step explanation:
Since we know that the TOTAL distance from Kensington to Greenville is 4.3 km, and we also that the distance from Kensington to Springfield is 2.3 km, we can subtract these values to find the distance from Springfield to Greenville.
[tex]4.3-2.3=2[/tex]
I hope this helped!
Answer:
Simple math, different numbers.
Step-by-step explanation:
Take the total distance, 4.3
And subtract it from the given segment of the road.
4.3 - 2.3 = 2.0
So the distance between Springfield and Greenville is 2 kilometers.
Franklin the fly starts at the point $(0,0)$ in the coordinate plane. At each point, Franklin takes a step to the right, left, up, or down. After $10$ steps, how many different points could Franklin end up at?
Answer: Franklin could end at 4 different points.
Step-by-step explanation:
Given: Franklin the fly starts at the point (0,0) in the coordinate plane.
At each point, Franklin takes a step to the right, left, up, or down.
i.e. there are 4 choices of directions [A coordinate plan has 4 quadrants]
If he moves 10 steps, then the number of different points Franklin could end up at = choices of directions
= 4
Hence, Franklin could end at 4 different points.
what is the cross section if i Move the intersecting plane of a cylinder parallel to the verticle axis
Answer:
A horizontal cross-section is obtained when the plane that passes through the solid object is parallel to its base. On the other hand, a vertical cross section is found when the intersecting plane is perpendicular to the base of the solid. These are known as a parallel cross-section and perpendicular cross section.
Step-by-step explanation:
Harry is trying to complete his hill walking scouts badge. He is using a map with a scale of 1 cm : 2 km. To earn the badge he needs to walk 14 km. What is the distance he needs to walk on the map?
Answer:
7 cm
Step-by-step explanation:
14 / 2 = 7 cm
7cm is the distance Harry needs to walk on the map?
What is Distance?Distance is a numerical or occasionally qualitative measurement of how far apart objects or points are.
Given that,
Harry is trying to complete his hill walking scouts badge.
He is using a map with a scale of 1 cm : 2 km.
To earn the badge he needs to walk 14 km.
Let the distance he needs to walk on the map is x.
By given data we write an equation
1/2=x/14
Apply Cross Multiplication
14/2=x
7=x
Hence, 7cm is the distance he needs to walk on the map.
To learn more on Distance click:
https://brainly.com/question/15172156
#SPJ5
Five less than the product of 14 and Vanessa's height Use the variable v to represent Vanessa's height.
Answer:
14v - 5
Step-by-step explanation:
The product of 14 and v is 14v. 5 less than that is 14v - 5.
Answer:
7v = 119
Step-by-step explanation:
Kelly bought Mason’s home for $255,500. Mason had prepaid the annual property taxes of $2,650. If closing costs are calculated on a 365-day year, and the transaction closes on March 5, how much will Kelly owe Mason for property taxes? Carry numbers out four decimal places, but round to two decimal places for your final answer. The proration is calculated up to the day of closing, meaning that the buyer owns the day of closing. Be sure to include the last day of the year in your calculations.
Answer:
$2192.60
Step-by-step explanation:
March 4 is day 63 of the year. So, the amount of tax that Kelly needs to refund to Mason is the tax for the remaining 365 -63 = 302 days of the year.
Kelly will owe Mason ...
(302/365)($2650) = $2192.6027 ≈ $2192.60