Mathematics High School

In the figure, [tex] \angle[/tex] AOB = [tex] \frac{1}{2} [/tex][tex] \angle[/tex] BOC and [tex] \angle[/tex] BOC = [tex] \frac{2}{3} [/tex][tex] \angle[/tex] COD . Show that [tex] \angle[/tex] COD = [tex] \frac{1}{2} \angle[/tex] AOD mentioning necessary axioms.

~Thanks in advance !

In The Figure, [tex] \angle[/tex] AOB = [tex] \frac{1}{2} [/tex][tex] \angle[/tex] BOC And [tex] \angle[/tex]

Answers

Answer 1

Answer:

See Below.

Step-by-step explanation:

Statements:                                                        Reasons:

[tex]1)\text{ }\angle AOD=180[/tex]                                                  Straight Angle Theorem

[tex]2)\text{ } \angle AOB+\angle BOC+\angle COD=\angle AOD[/tex]              Angle Addition    

[tex]3)\text{ } \angle AOB+\angle BOC+\angle COD=180[/tex]                   Substitution

[tex]\displaystyle 4)\text{ } \angle AOB=\frac{1}{2}\angle BOC[/tex]                                          Given

[tex]\displaystyle 5)\text{ } \angle BOC=\frac{2}{3}\angle COD[/tex]                                          Given

[tex]\displaystyle 6)\text{ } \frac{1}{2}\angle BOC+\frac{2}{3}\angle COD+\angle COD=180[/tex]              Substitution

[tex]\displaystyle 7)\text{ } \frac{1}{2}\Big(\frac{2}{3}\angle COD\Big)+\frac{2}{3}\angle COD+\angle COD=180[/tex]       Substitution

[tex]\displaystyle 8)\text{ } \frac{1}{3}\angle COD+\frac{2}{3}\angle COD+\angle COD=180[/tex]              Multiplication

[tex]\displaystyle 9)\text{ } 2\angle COD=180[/tex]                                                 Addition

[tex]10)\text{ } \angle COD=90[/tex]                                                   Division Property of Equality

[tex]\displaystyle 11)\text{ } \frac{1}{2}\angle AOD=90[/tex]                                                Division Property of Equality

[tex]\displaystyle 12)\text{ } \angle COD=\frac{1}{2}\angle AOD[/tex]                                        Substitution

Answer 2

Answer:

this is your answer. good luck.

In The Figure, [tex] \angle[/tex] AOB = [tex] \frac{1}{2} [/tex][tex] \angle[/tex] BOC And [tex] \angle[/tex]
In The Figure, [tex] \angle[/tex] AOB = [tex] \frac{1}{2} [/tex][tex] \angle[/tex] BOC And [tex] \angle[/tex]

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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The fraction (1/15)⁷ can be written as 15⁻⁷ after using the properties of the integer exponent.

What is an integer exponent?

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

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Answers

Answer:

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Step-by-step explanation:

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I hope this helps, have a good day or night:)

WILL MARK BRAINLIEST


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Answers

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Step-by-step explanation:

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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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A diagram is posted below.

===================================================

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----------------

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----------------

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Answers

Answer:

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Step-by-step explanation:

Answer:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Where is the question?

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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learn more about factor theorem here :

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Answer:

LOL i belive its 200 because i did this exact same thing yesterday for homework and got it right so yeah i guess it is?

Step-by-step explanation:

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