In the diagram, which of the following is not a possible measure of angle DCB?

Answer:

52.5 inch square

Step-by-step explanation:

Area of pentagon: A = 1/2 × p × a;

where 'p' is the perimeter of the pentagon and 'a' is the apothem of the pentagon.

A = 1/2 x (6 x 5) x 3.5 = 1/2 x 30 x 3.5 = 15 x 3.5 = 52.5

The area of the regular pentagon with apothem 3.5 and side 6 is 52.5

In Mathematics, a pentagon is a polygon with 5 sides. A pentagon can be classified as a regular pentagon and irregular pentagon. When all the sides and the angles of a pentagon are of equal measure, then it is called a regular pentagon.

Given the question, we need to find the area of the regular pentagon with apothem 3.5 and side 6.

In order to find the area, the formula to calculate the area of the regular pentagon is given by:

[tex]\text{Area of pentagon} =\sf \huge \text(\dfrac{5}{2}\huge \text) \times s \times a[/tex]

Now,

[tex]\text{Area of pentagon} =\sf \huge \text(\dfrac{5}{2}\huge \text) \times s \times a[/tex]

[tex]\text{Area of pentagon} =\sf \huge \text(\dfrac{5}{2}\huge \text) \times 6 \times 3.5[/tex]

[tex]\text{Area of pentagon} =52.5[/tex]

Therefore, the area of the regular pentagon with apothem 3.5 and side 6 is 52.5

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To sketch the graph of the function y = 4(4)^x, we can start by plotting a few points to get an idea of the shape of the graph.

Let's choose some x-values and calculate the corresponding y-values:

For x = -2, y = 4(4)^(-2) = 4(1/16) = 1/4

For x = -1, y = 4(4)^(-1) = 4(1/4) = 1

For x = 0, y = 4(4)^0 = 4(1) = 4

For x = 1, y = 4(4)^1 = 4(4) = 16

For x = 2, y = 4(4)^2 = 4(16) = 64

Now we can plot these points on a coordinate plane and connect them to form the graph of the function.

The graph of y = 4(4)^x will start at the point (0, 4) and increase rapidly as x increases. It is an exponential growth function where the base is 4.

The domain of the function is all real numbers since there are no restrictions on the values of x.

The range of the function is the set of positive real numbers greater than zero. As x increases, y grows without bound, approaching positive infinity but never reaching zero or becoming negative.

Answer:

correct choice is the last one

Step-by-step explanation:

let h = cost of 1 hamburger meal

let c = cost of 1 chicken nugget meal

5h + 6c = 39

9h + 2c = 35

At a temperature of 20°C, the mouse would burn approximately 1,567.44 calories each day.

According to the given model C = 0.37219T + 1,560, where C represents the number of calories an idle mouse burns each day and T represents the temperature of its environment in °C.

To find the most comfortable temperature for an idle mouse, we need to determine the temperature at which the mouse burns the least amount of calories per day.

To find this temperature, we can minimize the equation C = 0.37219T + 1,560. To do so, we take the derivative of C with respect to T and set it equal to zero:

dC/dT = 0.37219 = 0

Solving this equation, we find that the derivative is a constant value, indicating that the function C = 0.37219T + 1,560 is a linear equation with a slope of 0.37219. This means that the mouse burns the least calories at any temperature, as the slope is positive.

Therefore, there is no specific "most comfortable" temperature for an idle mouse in terms of minimizing calorie burn. However, if we consider the range of temperatures mice typically encounter, we can find a temperature where the calorie burn is relatively low.

For example, if we take a temperature of 20°C, we can calculate the calorie burn:

C = 0.37219 * 20 + 1,560

C = 7.4438 + 1,560

C ≈ 1,567.4438 calories per day

Therefore, at a temperature of 20°C, the mouse would burn approximately 1,567.44 calories each day.

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Using Maxwell's equations, we can determine the magnetic flux density. One of the Maxwell's equations is:

[tex]\displaystyle \nabla \times \mathbf{H} = \mathbf{J} + \frac{\partial \mathbf{D}}{\partial t}[/tex],

where [tex]\displaystyle \nabla \times \mathbf{H}[/tex] is the curl of the magnetic field intensity [tex]\displaystyle \mathbf{H}[/tex], [tex]\displaystyle \mathbf{J}[/tex] is the current density, and [tex]\displaystyle \frac{\partial \mathbf{D}}{\partial t}[/tex] is the time derivative of the electric displacement [tex]\displaystyle \mathbf{D}[/tex].

In this problem, there is no current density ([tex]\displaystyle \mathbf{J} =0[/tex]) and no time-varying electric displacement ([tex]\displaystyle \frac{\partial \mathbf{D}}{\partial t} =0[/tex]). Therefore, the equation simplifies to:

[tex]\displaystyle \nabla \times \mathbf{H} =0[/tex].

Taking the curl of the given magnetic field intensity [tex]\displaystyle \mathbf{R} =2\cos( 10^{10} t-600x)\hat{a}_{z}\, \text{Am}[/tex]:

[tex]\displaystyle \nabla \times \mathbf{R} =\nabla \times ( 2\cos( 10^{10} t-600x)\hat{a}_{z}) \, \text{Am}[/tex].

Using the curl identity and applying the chain rule, we can expand the expression:

[tex]\displaystyle \nabla \times \mathbf{R} =\left( \frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial y} -\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial z}\right) \mathrm{d} x\mathrm{d} y\mathrm{d} z[/tex].

Since the magnetic field intensity [tex]\displaystyle \mathbf{R}[/tex] is not dependent on [tex]\displaystyle y[/tex] or [tex]\displaystyle z[/tex], the partial derivatives with respect to [tex]\displaystyle y[/tex] and [tex]\displaystyle z[/tex] are zero. Therefore, the expression further simplifies to:

[tex]\displaystyle \nabla \times \mathbf{R} =-\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial x} \mathrm{d} x\mathrm{d} y\mathrm{d} z[/tex].

Differentiating the cosine function with respect to [tex]\displaystyle x[/tex]:

[tex]\displaystyle \nabla \times \mathbf{R} =-2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z[/tex].

Setting this expression equal to zero according to [tex]\displaystyle \nabla \times \mathbf{H} =0[/tex]:

[tex]\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z =0[/tex].

Since the equation should hold for any arbitrary values of [tex]\displaystyle \mathrm{d} x[/tex], [tex]\displaystyle \mathrm{d} y[/tex], and [tex]\displaystyle \mathrm{d} z[/tex], we can equate the coefficient of each term to zero:

[tex]\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x) =0[/tex].

Simplifying the equation:

[tex]\displaystyle \sin( 10^{10} t-600x) =0[/tex].

The sine function is equal to zero at certain values of [tex]\displaystyle ( 10^{10} t-600x) [/tex]:

[tex]\displaystyle 10^{10} t-600x =n\pi[/tex],

where [tex]\displaystyle n[/tex] is an integer. Rearranging the equation:

[tex]\displaystyle x =\frac{ 10^{10} t-n\pi }{600}[/tex].

The equation provides a relationship between [tex]\displaystyle x[/tex] and [tex]\displaystyle t[/tex], indicating that the magnetic field intensity is constant along lines of constant [tex]\displaystyle x[/tex] and [tex]\displaystyle t[/tex]. Therefore, the magnetic field intensity is uniform in the given medium.

Since the magnetic flux density [tex]\displaystyle B[/tex] is related to the magnetic field intensity [tex]\displaystyle H[/tex] through the equation [tex]\displaystyle B =\mu H[/tex], where [tex]\displaystyle \mu[/tex] is the permeability of the medium, we can conclude that the magnetic flux density is also uniform in the medium.

Thus, the correct expression for the magnetic flux density in the given medium is:

[tex]\displaystyle B =6\cos( 10^{10} t-600x)\hat{a}_{z}[/tex].

Answer:

Ryan had a head start of 10 meters

Step-by-step explanation:

Out of the four children attending the party, with only two spots left, there are six different ways to select two children to fill those spots.

If there are four children and only two spots left at the party, we need to determine the number of combinations possible for selecting two children out of the four. To calculate this, we can use the concept of combinations from combinatorics.

Combinations refer to the selection of items from a larger set without considering the order. In this case, the order in which the children are selected does not matter; we only need to know which two children are chosen. The formula for combinations is given by:

C(n, r) = n! / (r! * (n - r)!)

where n is the total number of items (in this case, children) and r is the number of items we want to select (in this case, the two available spots at the party).

Using the formula, we can substitute n = 4 and r = 2:

C(4, 2) = 4! / (2! * (4 - 2)!)

Simplifying further:C(4, 2) = 4! / (2! * 2!)

Now, let's calculate the factorial terms:

4! = 4 * 3 * 2 * 1 = 24

2! = 2 * 1 = 2

Substituting the factorial terms:

C(4, 2) = 24 / (2 * 2)

Simplifying the denominator:

C(4, 2) = 24 / 4 = 6

Therefore, there are 6 different combinations possible for selecting two children out of the four to fill the two available spots at the party.

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Note the correct question is

4 childen go to a party but there is only 2 spots left. How many combinations  are there?

The Intel pays $7,760 to Bally Manufacturing on August 14.

The first step in calculating what Intel Corporation pays Bally on August 14 is to determine the net price of the machinery after the trade discount and the return of $100 due to defects.

The trade discount of 40% is calculated as follows:

Discount = List price × Discount rate

Discount = $13,100 × 0.40 = $5,240

So the net price of the machinery after the trade discount is:

Net price = List price - Discount

Net price = $13,100 - $5,240 = $7,860

After Intel returns $100 of machinery, the cost of the machinery is further reduced to:

Net price after return = Net price - Return

Net price after return = $7,860 - $100 = $7,760

Since the payment terms are 3/10 EOM (end of month), Intel receives a discount of 3% if payment is made within 10 days. The 10-day period begins on August 1 and ends on August 10 (the payment due date). Since Intel pays the bill on August 14, payment is late and the 3% discount does not apply.

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The rocket is at a height of 1876.1 meters after 9 seconds,the velocity of the rocket after 9 seconds is 143.8 m/s and  the acceleration of the rocket after 9 seconds is -9.8 m/s².

To find the height of the rocket when it was initially launched, we can plug in t = 0 into the equation h(t) = -4.9t² + 232t + 185.

h(0) = -4.9(0)² + 232(0) + 185

     = 0 + 0 + 185

     = 185

Therefore, the rocket was initially launched at a height of 185 meters.

To find the height of the rocket after 9 seconds, we can plug in t = 9 into the equation h(t) = -4.9t² + 232t + 185.

h(9) = -4.9(9)² + 232(9) + 185

     = -4.9(81) + 2088 + 185

     = -396.9 + 2088 + 185

     = 1876.1

Therefore, the rocket is at a height of 1876.1 meters after 9 seconds.

To find the velocity of the rocket after 9 seconds, we can take the derivative of the height function h(t) with respect to time (t) and evaluate it at t = 9.

The velocity function v(t) is the derivative of h(t) with respect to t:

v(t) = dh/dt = d/dt(-4.9t² + 232t + 185)

       = -9.8t + 232

v(9) = -9.8(9) + 232

       = -88.2 + 232

       = 143.8

Therefore, the velocity of the rocket after 9 seconds is 143.8 m/s.

To find the acceleration of the rocket after 9 seconds, we can take the derivative of the velocity function v(t) with respect to time (t) and evaluate it at t = 9.

The acceleration function a(t) is the derivative of v(t) with respect to t:

a(t) = dv/dt = d/dt(-9.8t + 232)

       = -9.8

a(9) = -9.8

Therefore, the acceleration of the rocket after 9 seconds is -9.8 m/s².

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[tex]\sqrt{200y^2} ~~ \begin{cases} 200=&2\cdot 10\cdot 10\\ & 2\cdot 10^2 \end{cases}\implies \sqrt{2\cdot 10^2 y ^2}\implies 10y\sqrt{2}[/tex]

Let's analyze Jenny's bowling expenses, considering the cost of renting bowling shoes and the price per game. By determining the total amount she paid and using the given information, we can calculate the number of games Jenny bowled.

Step-by-step explanation:

Let's set the number of games Jenny bowled as 'x'.

Jenny paid $2.75 for renting the bowling shoes and $4.25 for each game. The total amount she paid is $24.

The total amount Jenny paid for the games can be represented as: $4.25 * x.

So, the equation can be set up as:

$2.75 + $4.25 * x = $24.

To find the value of 'x', we need to solve the equation.

Subtracting $2.75 from both sides:

$4.25 * x = $24 - $2.75.

$4.25 * x = $21.25.

Dividing both sides by $4.25:

x = $21.25 / $4.25.

x = 5.

Answer: Therefore, Jenny bowled a total of 5 games.

The length of the other diagonal is 11.25 cm.

Area is the measure of a region's size on a surface. The area of a plane region or plane area refers to the area of a shape or planar lamina, while surface area refers to the area of an open surface or the boundary of a three-dimensional object.

In this question, we are given the following:

The area of a kite is 180. One of the diagonals is 16.

What is the length of the other diagonal?

The details of the solution are as follows:

We know that,

The area of a kite is the product of the diagonals divided by 2:

[tex]\text{A} = \dfrac{(\text{d}^1 \times \text{d}^2)}{2}[/tex]

You can substitute what we have:

[tex]180= \dfrac{(16 \times \text{d}^2)}{2}[/tex]

And solve.

[tex]180 = 16 \times \text{d}^2[/tex]

[tex]\text{d}^2=\dfrac{180}{16}[/tex]

[tex]\text{d}^2=\bold{11.25 \ cm}[/tex]

Therefore, the length of the other diagonal = 11.25 cm.

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Terri have to react 1.42 seconds before the volleyball hits the ground.

Quadratics can be defined as a polynomial equation of a second degree, which implies that it comprises a minimum of one term that is squared. It is also called quadratic equations. The general form of the quadratic equation is:

[tex]\text{ax}^2 + \text{bx} + \text{c} = 0[/tex]

Given data:

The height can be modeled by a quadratic equation.

[tex]h(t)=-16t^2+v_0t+h_0[/tex]

Where h is the height and t is the time.

[tex]h(t)=-16t^2+19.5t+4.5[/tex]

[tex]-16t^2+19.5t+4.5=0[/tex]

[tex]a = -16, b = 19.5, c = 4.5[/tex]

It looks like a quadratic equation. we can solve it by quadratic formula.

[tex]\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\rightarrow t=\dfrac{-19.5\pm\sqrt{(-19.5)^2-4\times(-16)(4.5)} }{2(-16)}[/tex]

[tex]\rightarrow t=\dfrac{-19.5\pm\sqrt{380.25+288} }{-32}[/tex]

[tex]\rightarrow t=\dfrac{-19.5\pm25.851 }{-32}[/tex]

[tex]\rightarrow t=\dfrac{-19.5-25.851 }{-32}, \ t=\dfrac{-19.5+25.851 }{-32}[/tex]

[tex]\rightarrow t=1.42, \ t=-0.20[/tex]

Time cannot be in negative. So neglect t = –0.235.

Hence, Terri have to react 1.42 seconds before the volleyball hits the ground.

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Using the physics concept of projectile motion and inputting the given values into the appropriate equation, we can determine the time it takes for the volleyball to hit the ground after being served

This question is a classic use of physics, more specifically, the concept of projectile motion. Here, the volleyball can be conceived as a projectile. When Patricia serves the ball upward, the ball will first ascend and then descend due to gravity.

Let's use the following equation which is a version of kinematic equations to solve this problem, adjusting for the fact that we're dealing with an initial height of 4.5 ft and an ending height of 0 ft (when the ball hits the ground). The equation y = yo + vot - 0.5gt² , where:

Setting y=0, yo=4.5 feet, vo=19.5 feet/second, and g=32.2 feet/second², and plug these values into the equation, we'll get a quadratic equation in the form of 0 = 4.5 + 19.5t - 16.1t². Solve that equation for t to find the time it takes for the ball to hit the ground.

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Answer:

Quadratic equation. Linear would be a straight line and exponential would continue to grow; only quadratic equations are shaped like parabolas.

linear

if you add 2 cats to a tree and took one down you would have 0 in the tree so if you add 2+2=4 you can find every answer in the book.

your wellcomed

The algebraic expression for the given phrase is: 17x - 8x. To simplify this expression, we can combine like terms by subtracting the coefficients of x. The simplified expression is: 9x.

In the given phrase, "The product of 8 and a number" can be represented as 8x, where x represents the number. Similarly, "The product of 17 and the number" can be represented as 17x. Since we are subtracting the product of 8x from the product of 17x, the algebraic expression becomes 17x - 8x.

To simplify the expression, we combine like terms. The coefficients of x are 17 and -8. Since we are subtracting 8x from 17x, we subtract the coefficient of 8x from the coefficient of 17x, resulting in 17x - 8x. Combining like terms gives us 9x.

In conclusion, the simplified expression for the phrase "The product of 8 and a number, which is then subtracted from the product of 17 and the number" is 9x.

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Answer:  [tex]\frac{8}{5}[/tex]  

Step-by-step explanation:

You can put it into a ratio when the units are the same.

Let's convert 15 ft to yards

3 ft  = 1 yd

So divide 15 by 3

15ft  = 5 yd

So the ratio you want is:

8 yds to 5 yds

To write that in fraction ratio form:

[tex]\frac{8}{5}[/tex]               >Keep as improper fraction for ratios

The inequality tha calculates the possible values of x is x < 2

From the question, we have the following parameters that can be used in our computation:

The figure

Where, we have

3x + 2 < 10

And, we have

2x + 6 < 10

Evaluate the expressions

So, we have

3x < 8 and 2x < 4

Evaluate

x < 8/3 and x < 2

Hence, the inequality tha calculates x is x < 2

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ANSWER

61.8 m^[2].

We first examine what we have which is:

A parallelogram with base 14m and height 8m

A circle with DIAMETER 8m

Given our area formulas, we know we have our b and h in our parallelogram formula given. If our circle diameter is 8m, our circle radius must be 4m. Therefore, we have every element of our formulas we need.

parallelogram area = b*h = 14*8 = 112m^[2]

circle area = pi*r^[2] = pi*4m^[2]=16*3.14=50.24m^[2].

now we just subtract our circle area from our parallelogram area, and round our answer to the nearest tenth (the first place to the right of the decimal):

112m^[2]-50.24m^[2]=61.76 m^[2].

Rounded to the nearest tenth, this number becomes 61.8 m^[2].

Answer:

29.4°

Step-by-step explanation:

The equation can be rearranged to give C directly.

 C = arccos((a^2 +b^2 -c^2)/(2ab))

 C = arccos((90^2 +55^2 -50^2)/(2·90·55))

 C = arccos(8625/9900) ≈ 29.4002°

 C ≈ 29.4°

The measure of angle C is approximately 29.46 degrees.

To find the measure of angle C (cos(C)) using the given values a = 55, b = 90, and c = 50, we can use the Cosine Rule formula:

cos(C) = (a² + b² - c²) / (2 * a * b)

Substitute the given values:

cos(C) = (55² + 90² - 50²) / (2 * 55 * 90)

Now, calculate the numerator:

cos(C) = (3025 + 8100 - 2500) / (2 * 55 * 90)

cos(C) = 8625 / 9900

Now, divide to get the final value of cos(C):

cos(C) ≈ 0.8707

To find the measure of angle C itself, we can take the inverse cosine (arccos) of this value:

C ≈ arccos(0.8707)

Using a calculator, you'll find:

C ≈ 29.46 degrees (rounded to two decimal places)

So, the measure of angle C is approximately 29.46 degrees.

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Answer:

D; 7 1/2

Step-by-step explanation:

:)

The graph of the function f(x)=√(x + 1) is in the first option

A radical graph, also known as a square root graph, represents the graph of a square root function. A square root function is a mathematical function that takes the square root of the input variable.

The general form of a square root function is f(x) = √(ax + b) + c,

where a, b, and c are constants that determine the characteristics of the graph.

In the given function:

a = 1

b = 1

c = 0

The graph is plotted and attached

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Answer:

4/10 simplified  2/5

if it does not help I am so sorry

Step-by-step explanation:

The expression equivalent to [tex]V(8y^4√√x / 5x * By^2√x / 5 * 5√√x * 8y^2 / 5x√√x * 8y^4) is V(Bx^7) * x^(1/4) / 5.[/tex]

The given expression is:

[tex]V(8y^4 * √√x / 5x) * (By²√x / 5) * √√x * 8y^2 / (5x√√x * 8y^4)[/tex]

To simplify this expression, let's break it down step by step:

Step 1: Simplify the terms inside the square root (√) and the fourth root (√√):

[tex]√√x = x^(1/4)√√x * 8y^2 = 8y^2 * x^(1/4)[/tex]

Step 2: Simplify the terms with exponents:

[tex]8y^4 * x^(1/4) = 8y^4x^(1/4)8y^2 * x^(1/4) = 8y^2x^(1/4)5x * x^(1/4) = 5x^(5/4)5x√√x = 5x^(5/4)[/tex]

Step 3: Simplify the remaining terms:

[tex]V(8y^4x^(1/4) / 5x) * (By^2x^(1/4) / 5) * 5x^(5/4) / (8y^4)[/tex]

Step 4: Cancel out common factors:

[tex]V(x^(1/4) / 5) * (Bx^(1/4) / 5) * x^(5/4)[/tex]

Step 5: Combine the expressions under the square root:

[tex]V(Bx^(1/4) * x^(1/4) * x^(5/4)) / 5 * 5 * x^(1/4)[/tex]

Step 6: Simplify the exponents:

V[tex](Bx * x * x^5) / 5 * 5 * x^(1/4)[/tex]

Step 7: Combine the terms inside the square root:

V([tex]Bx^7) / 5 * 5 * x^(1/4)[/tex]

Step 8: Simplify the remaining expression:

V(B[tex]x^7) * x^(1/4) / 5[/tex]

Therefore, the expression equivalent to [tex]V(8y^4√√x / 5x * By^2√x / 5 * 5√√x * 8y^2 / 5x√√x * 8y^4) is V(Bx^7) * x^(1/4) / 5[/tex]

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The coefficient of variation for Bank A is approximately 8.04%, while the coefficient of variation for Bank B is approximately 25.55%.

To find the coefficient of variation for each set of data, we need to calculate the mean and standard deviation for each set. The coefficient of variation is then calculated by dividing the standard deviation by the mean and multiplying by 100.

Let's calculate the coefficient of variation for each set of data:

Bank A (single line):

Mean: Calculate the mean of the data set.

Mean = (6.5 + 6.6 + 6.7 + 6.7 + 7.1 + 7.4 + 7.5 + 7.7 + 7.7 + 7.7) / 10 = 7.03 minutes

Standard deviation: Calculate the standard deviation of the data set.

Standard deviation = √[(6.5 - 7.03)² + (6.6 - 7.03)² + ... + (7.7 - 7.03)²] / 10 ≈ 0.565 minutes

Coefficient of variation:

Coefficient of variation = (0.565 / 7.03) * 100 ≈ 8.04%

Bank B (individual lines):

Mean: Calculate the mean of the data set.

Mean = (4.0 + 5.4 + 5.9 + 6.2 + 6.8 + 7.7 + 7.7 + 8.5 + 9.4 + 9.8) / 10 = 7.5 minutes

Standard deviation: Calculate the standard deviation of the data set.

Standard deviation = √[(4.0 - 7.5)² + (5.4 - 7.5)² + ... + (9.8 - 7.5)²] / 10 ≈ 1.916 minutes

Coefficient of variation:

Coefficient of variation = (1.916 / 7.5) * 100 ≈ 25.55%

Comparing the variation:

The coefficient of variation for Bank A is approximately 8.04%, while the coefficient of variation for Bank B is approximately 25.55%. Since the coefficient of variation measures the relative variability of the data, we can conclude that the waiting times at Bank B (individual lines) have a higher variation compared to Bank A (single line).

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The required probability is 3 √7 / 32.

Given, a square with sides of length 4 units and a red-shaded triangle with sides 3 units, 3 units and 4 units. We need to find the probability that a randomly selected point within the square falls in the red-shaded triangle.To find the probability, we need to divide the area of the red-shaded triangle by the area of the square. So, Area of square = 4 × 4 = 16 square units. Area of triangle = 1/2 × base × height.

Using Pythagorean theorem, the height of the triangle is found as: h = √(4² − 3²) = √7

The area of the triangle is: A = 1/2 × base × height= 1/2 × 3 × √7= 3/2 √7 square units. So, the probability that a randomly selected point within the square falls in the red-shaded triangle is:  P = Area of triangle/Area of square= (3/2 √7) / 16= 3 √7 / 32.

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An inequality to find the possible values of x is: D. x > 7.

In Euclidean geometry, the Triangle Inequality Theorem is represented by this mathematical expression:

b - c < n < b + c

Where:

n, b, and c represent the side lengths of this triangle.

By using the law of sine law, the value of x can be determined as follows;

28/sin(100°) = 20/sin(α)

sin(α) = sin(100°) × 20/28

α = arcsin(0.7034) = 44.70°

β = 180° - 110° - 44.70°

β = 25.3°

x/sin(β) = 28/sin(100°)

x = 28/sin(100°) × sin(25.3°)

x = 12.15

Based on the Triangle Inequality Theorem, we have:

20 + 12.15 > (5x - 7)

32.15 > (5x - 7)

5x > 39.15

x > 7.83

Read more on inequality here: https://brainly.com/question/16875793

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