Answer:
Dominant epistasis best explains this ratio of 12:3:1.
Genotype(s) AABB, AABb, AAbb, AaBB, AaBb and Aabb explain white phenotype of sheep.
Explanation:
It is a clear case of dominant epistasis which is in turn a result of gene interaction. In dominant epistasis, dominant allele of one gene masks the expression of another gene which is present at different locus.
When we will cross two heterozygous sheep AaBb x AaBb, progeny with following genotypes will be produced:
1- AABB - White
2- AABb - White
1- AAbb - White
2- AaBB - White
4- AaBb - White
2- Aabb - White
1- aaBB - Black
2- aaBb - Black
1- aabb - brown
In this case, dominant 'allele A' of gene A will mask the expression of gene B. This is the reason why genotype AABB, AABb, AAbb, AaBB, AaBb and Aabb are producing white phenotype. So in total, 12 sheep will produce white phenotype.
But when dominant 'allele A' is absent, then only gene B will be able to express if it is present in dominant form. This is the reason why aaBB and aaBb are producing black phenotype because here dominant allele A is absent and recessive allele a will not be able to mask the expression of gene B because gene B has dominant allele here i.e. BB and Bb. So 3 sheep will produce black phenotype.
But when when dominant 'allele A' is absent and gene B is in recessive form i.e. bb then a third phenotype will be produced which is brown. This is the reason why aabb will produce brown color. So only 1 sheep will produce brown phenotype.
many people try to eliminate fat from their diet
Answer:
yes they do
Explanation:
they do because they don't want to be big chungus anymore, they want to be a skinny queen
In an experiment, there are two groups. Which group is not changed in any way?
A. hypothesis
B. variable
C. experimental
D. control
Answer:
d) control
Explanation:
a control is what's kept the same throughout the experiment
Please describe the regulation of the blood glucose 6 hours after a meal?
Please include all relevant organs, hormones, and actions.
Answer:
Find the description below in the explanation section
Explanation:
The body system regulates the blood sugar level via the hand-in-hand working of insulin and glucagon hormones, both produced by the Pancreas. After a meal, the food undergoes digestion and is broken down into glucose, which is absorbed into the bloodstream. Insulin hormone is released by the pancreas (stimulated by a negative feedback) when the sugar level of the blood increases. This secretion of insulin causes cells to absorb glucose as source of energy, while liver and muscle cells store some of the excess blood glucose as GLYCOGEN.
However, after about 6 hours of taking the meal, the blood sugar (glucose) level must have decreased. This triggers the secretion of Glucagon hormone by the Pancreas. Glucagon hormone, acts in an opposite manner as Insulin hormone, by causing the stored GLYCOGEN in the liver and muscle cells to be converted back to Glucose in order for cells to make use of it.
This continuous process occurs and it is how the body regulates the blood glucose levels.
Biochemical changes in the body, that affect the rate of metabolism and elimination of a substance from the body and produce increased amounts to achieve the desired effects, may lead to development of
Answer:
Tolerance
Explanation:
Tolerance is the capacity of an organism to survive changes in certain environmental and biochemical conditions. It has to with changes an organism is able to withstand when is subjected to certain factors which can biotic or abiotic.
For example, in the consumption of alcohol, tolerance can occur when there is a fast elimination of alcohol from the body system. This is usually as a result of the activation of a group of enzymes that is responsible for the metabolism of alcohol in excessive alcohol drinkers. The activation of this enzymes increases the catabolism of alcohol and hence reduces the active time within the body, hence reducing the time by which alcohol intoxicates.
1. D Value is determined as a
A. Removing of microorganisms by washing
B. Concentration of disinfectant required to reduce microbial population 10 times
C. Time required to kill 10% of microbial population
D. Time frame in which microbial population of 5,600,000 cells would decrease to 560,000 cells
E. None of the above
2. The betadine or alcohol swab before blood donation is an example of A. Pasteurization
B. Disinfection
C. Sterilization
D. Preservation
E. None of the above
Answer:
1. D. Time frame in which microbial population of 5,600,000 cells would decrease to 560,000 cells.
2. Disinfection
Explanation:
Hope it helps .
molecular genetics experiment: In what way do the percentages of yellow leaves vary between dishes on Day 2? How do you account for this difference? Compare the percentage of yellow seedlings in dish 2 on day 2 with the percentage on day 4. What is the difference? What experimental variable accounts for this difference? How can you account for the difference between the seedlings in dish 1? Is the yellow color genetically or environmentally controlled? How can environmental factors affect inheritance? (Use human height as an example.)
Answer:
See below
Explanation:
There were yellow seedlings in Dish #1 during the light phase and also during the dark in Dish #2. The difference in these results is likely due to the period of exposure to light.
There are more number of yellow seedlings on Day 4. This is probably because of being kept in the dark for a long period of time. Light intensity is the experimental variable that accounts for this difference in appearance.
The yellow color is being environmentally controlled since the parent phenotype was wildtype in this experiment. The environment has an effect on which genes are expressed in the organism, which in turn influences the phenotype observed.
The process of succession is necessary to maintain and establish stable communities. T or F
Answer: True it is necessary
Answer:
True
Explanation:
The women has had two miscarriages. What is the chance that she could have a normal child? a. The chance of a normal child is approximately one in four; however, all of the normal children will be translocation carriers.b. The chance of a normal child is approximately one in two; however, all of the normal children will be translocation carriers.c. The chance of a normal child is approximately one in four; however, half of the normal children will be translocation carriers.d. The chance of a normal child is approximately one in two; however, half of the normal children will be translocation carriers
Comparison of glycogen synthesis and breakdown in muscle and liver reveals: A. Stimulation of glycogen breakdown in both tissues by epinephrine leads to enhanced glucose uptake by liver cells and enhanced glucose export from muscle cells. B. Stimulation of glycogen synthesis by insulin in both tissues leads to glycogenolysis in both liver and muscle. C. Inhibition of glycogen synthesis in both tissues by epinephrine leads to glycogenolysis in both liver and muscle. D. Stimulation of glycogen synthesis by insulin in both tissues is accompanied by decreased glycogenolysis. E. Epinephrine stimulates glycogen uptake in liver and breakdown in muscle.
Answer:
The correct options are C and D:
C- The inhibition of glycogen synthesis in both tissues by epinephrine leads to glycogenolysis in both the liver and muscle.
D- The stimulation of glycogen synthesis by insulin in both tissues is accompanied by a decrease in glycogenolysis.
Explanation:
The presence of epinephrine causes the glycogen reserve that is present in the liver and muscle to enter the glycogenolysis stage, that is, the chemical structures of glycogen are broken and simplified in energy coins (ATP) so that the activity muscle contract against stimulation of the adrenergic nervous system.
The adrenergic nervous system is one that promotes physical activity, physiological stress, flight from danger, and other activities, is also known as the sympathetic system and is where epinephrine or adrenaline predominates as a neurotransmitter.
The liver and muscle are the only possible organs to reserve glycogen in a limited way, once its reserve limits are exceeded it will begin to deposit in the form of adipose tissue, glycogenogenesis or formation of glycogen as reserve is promoted by insulin and the system parasympathetic nerve, visceversa to what we explained above with the sympathetic nervous system and epinephrine, since the latter break the glycogen reserves releasing glucose into the blood for muscle contraction.
Which type of mutation results in a frame shift mutation? Check all that apply? Substitute Insertion Deletion Point mutation
Answer: Insertion, Deletion
Explanation:
The frameshift mutation can be defined as a genetic mutation that is caused by the deletion or insertion of the DNA sequence or base pairs that shifts the sequence to be read. As a result of this the abnormal proteins are produced along with incorrect amino acid sequence that either shorter or longer than the normal protein.
Tryptophan is an amino acid necessary for E. coli survival and growth. E. coli contain genes coding for enzymes that synthesize tryptophan. These genes are grouped together on a segment of DNA called the tryptophan (trp) operon. Cells can use these enzymes to synthesize tryptophan when it is not present in the environment. owever, when tryptophan is already present in the environment, cellular resources are shifted away from manufacturing the enzymes for tryptophan synthesis. Tryptophan binds with and activates the trp repressor, which then binds to the trp promoter and blocks RNA polymerase. Blocking RNA polymerase decreases the normal transcription rate of the operon. What type of regulation does the trp operon exhibit?a. positive regulation b. protein modification c. negative regulation d. translational regulation
Answer:
The correct answer is - The tryptophan operon shows C. negative regulation.
Explanation:
Tryptophan is an amino acid, excessively synthesized by the organism, it regulates its transcription through “trp Operon.” In this operon, the corepressor of the tryptophan binds to the repressor protein and gets activated.
This activated repressor now binds to the operator site, and prevents the binding of RNA polymerase enzyme and inhibits the protein synthesis.
The basic unit of structure and function of living things is the A nucleus B cell C tissue or D membrane PLZ QUICK worth 20 points
Answer:
B. cell
Explanation:
A cell is the smallest unit of a living thing. A living thing, whether made of one cell (like bacteria) or many cells (like a human), is called an organism. Thus, cells are the basic building blocks of all organisms
Answer:
cell
Explanation:
Which of the following statements is NOT true? The three types of lipid anchors responsible for tethering proteins to the bilayer are acylation, prenylation, and GTPase anchors. Glycoproteins are always oriented so that the carbohydrate moieties are exoplasmic. Glycoproteins are the basis for blood type compatibility between donor and receiver. Movement of proteins from the cytoplasmic to the exoplasmic face of the lipid bilayer requires specialized transport proteins, often flippases.
Answer:
d
Explanation:
the last one because it dosent provide anything
In a songbird species, defending a territory saved the bird 584 calories a day in reduced foraging activity, but cost the bird 656 calories in defense of the territory. Is defending the territory consistent with the prediction from optimal foraging theory, and what can explain this
Answer:
The correct answer is "No, this is not consistent with the predictions on optimality".
Explanation:
The optimal foraging theory (OFT) establishes that an organism looks for the best foraging strategy, which involves maximizing the amount of energy that is available in its daily activities. In this case, the songbird species is not consistent with the predictions on optimality since it needs more calories than it intakes in order to defend its territory. In this scenario, the songbird will lose 72 calories per day.
If it is accepted that the information for how a protein is intended to fold lies within its primary sequence, explain why a purified protein denatured in vitro might not be able to renature accurately.
Answer:
Denaturation and renaturation are properties of protein but in some cases denaturation is irreversible and protein is unable to renature.
The primary sequence of a protein determines which portion of protein fold closely together in order to form three-dimensional conformation and the conformations are held by hydrogen bonds.
Denaturation of protein in-vitro is generally obtained by increasing temperature. Heat or high temperature disrupts hydrogen bonds that held between protein folds because high temperature increases the kinetic energy and the bonds are disrupted due to rapid heating. Disruption of hydrogen bonds will change the 3D structure of the protein and denatured proteins lose its function.
Chemicals are also used to disrupt hydrogen bonds such as alcohol.
So, high temperature and chemicals denature protein by affecting the hydrogen bonds holding 3D shape of primary sequence in protein and the change in protein becomes irreversible.
g If a pair of sister chromatids fail to separate during anaphase II (meiosis II), what will be the chromosome number of the four resulting gametes with respect to the normal haploid number (n)
Answer:
The result will be two gametes with a normal haploid number (n), one gamete containing an extra chromosome (n + 1) and one gamete missing one chromosome (n − 1).
Explanation:
Nondisjunction is caused by the failure in the mechanism of separation of homologous chromosomes or sister chromatids during meiosis and/or mitosis. The failure in the separation of sister chromatids during meiosis II is referred to as 'secondary nondisjunction' and it produces two daughter cells with abnormal chromosome numbers.
The fusion of one gamete containing an extra chromosome (n + 1) with a normal (n) gamete will lead to trisomy (2n + 1), while the fusion of one gamete missing one chromosome (n - 1) with a normal gamete will lead to monosomy (2n-1).
a strand of mRNA has the bases adenine- cytosine- uracil which amino acid corresponds to these bases?
Answer:
Threonine
Explanation:
Using the amino acid chart, the mRNA strand ACU corresponds to the amino acid Threonine.
Answer:
thr
Explanation:
i did test
Which of the following is found in the ' rungs' of a DNA strand?
Answer:
here
Explanation:
There will be the nitrogenous bases (adenosine, cytosine, guanine, thymine), held in complementary pairs (A T, C G) by hydrogen bonds. Weak van der Waal's forces exists between the 'rungs'.
The currently accepted model of the coeur laboratory you are observing skin cells labeled 'defective' to determine what is wrong with them. After careful observation you notice that the cytoskeleton is there, but the cell is still having trouble maintaining its shape. Infer what could be damaged.l membrane was discovered by
Answer:
Cell membrane
Explanation:
The cytoskeleton is known to be a kind of proteinous filaments which is found in the cytoplasm of organism but grow out to the cell membrane to give shape to the organism and likewise help in movement.
In the case highlighted above, the organism might still not be able to get a shape especially when the cell membrane is affected or being damaged.
A single point mutation in a gene results in a nonfunctional protein. Individuals heterozygous for this mutation were identified using a Southern blot. Which pair of wild-type (WT) and mutant alleles most likely contains the mutation?
A. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTCGATGCTTAGGCATCT-3
B. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTCGAAGCTTAGGCATAT-3
C. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTTGAAGCTTAGGCATCT-3
D. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTCCAAGCTTAGGCATCT-3
Answer:
C. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTTGAAGCTTAGGCATCT-3
Explanation:
In the wild type, the DNA sequence encodes the following aminoacidic segment: SRSLGI; while the mutant form has a stop codon in the second codon (TGA). A stop codon is a trinucleotide sequence in the messenger RNA (mRNA) that indicates a stop signal in protein synthesis. There are three types of stop codons: UGA, UAG and UAA, where U represents Uracile in the mRNA instead of Thymine in the DNA sequence.
Representation:
C. WT 5-T AGT CGA AGC TTA GGC ATC T-3 >> 5'3' Frame 1 = SRSLGI
Mutant 5-T AGT TGA AGC TTA GGC ATC T-3 >> 5'3' Frame 1 = S-, where - represents a stop codon (TGA) and therefore it is the end of the protein.
Second class levers are best described as follows:___________.
A) "The muscle force and resistive force act on opposite sides of the fulcrum, and the effort required to move the load is at a mechanical advantage"
B) "The muscle force and resistive force act on opposite sides of the fulcrum, but the effort required to move the load is at a mechanical disadvantage"
C) "The muscle force and resistive force act on the same side of the fulcrum, with a longer moment arm for the effort than for the load"
D) "The muscle force and resistive force act on the same side of the fulcrum, with a longer moment arm for the load than for the effort"
Answer:
A, B, C, D!
Explanation:
Rosa made a chart to summarize the characteristics of two types of social behavior. Which headings best complete the chart? X: Herding Y: Cooperative Hunting X: Flocking Y: Migrating X: Cooperative Hunting Y: Herding X: Migrating Y: Flocking
Answer:
Flocking (birds) and cooperative hunting (lions or wolves)
Explanation:
In large animal groups, social behavior enables to obtain an evolutionary advantage over non-social species by making decisions that are likely to be beneficial for the group. In humans, a comprehensive understanding of these benefits has shown to be useful in different areas ranging from social to economic systems.
Cooperative Hunting is a social behavior that enables predatory social species like lions to hunt larger organisms, thereby improving the adaptive fitness of individuals.
Bird flocking is another type of social behavior in which a group of bird is in flight. This behavior is shared by very different species such as insects and fish. Flocking has shown to be beneficial to individual birds to take care of predators and to find food.
Answer:
A.
Explanation:
Which of these is an organism?
Answer:
A wolf...........
.......................
Answer:
I believe the answer is heart
If your observations do not support your hypothesis, what
should you
you do?
Answer:
than admit defeat
Explanation:
During which phase of mitosis do the nuclear membrane, nucleoli, nucleus dissolve
Answer:
Prophase stage
Hope this helps
Which statement correctly describes glucose (CGH120.?
It is made of matter and contains twenty-four molecules.
It is an element made of three types of atoms.
It is an atom made up of carbon, hydrogen, and oxygen.
It is a compound made of twenty-four total atoms of three different elements
Answer:
It is made of matter and contains twenty-four molecules.
maggots feed on dead and decaying organisms for energy. what are maggots
Answer:
Decomposers, or as they're alternatively known, detritovores.
Explanation:
Their job is to break down decaying/dead organic matter to recycle it into the soil for plants (mainly). Fungi and bacteria make up the vast majority of decomposers.
The fact that there appears to be a genetic component to inflammatory bowel disease, but that it does not show clear Mendelian inheritance ratios suggests any of the following, EXCEPT: the gene for the disease has incomplete penetrance. the gene for the disease has limited expressivity. the disease is polygenic. the gene for the disease is recessive.
Answer:
Option D
Explanation:
(the gene for the disease has incomplete penetrance. the gene for the disease has limited expressivity. the disease is polygenic) - all these are examples of non-mendelian inheritance which include incomplete penetrance, polygenic inheritance etc. These do not follow the mendelian pattern of inheritance.
(the gene for the disease is recessive.)- this shows the mendelian pattern of inheritance... Dominant and recessive characteristics are examples that show Mendelian inheritance.
what is odontoid process in bones/
Answer:
The odontoid processIt exhibits a slight construction or neck, where it joins the main body of the vertebra...
Hope you like it please mark me as a brainliestSuppose a plant breeder wants to isolate mutants in tomatoes that are defective in DNA repair. However, this breeder does not have the expertise or equipment to study enzymes in DNA repair systems.
Which methods would best allow the breeder to identify tomato plants that are deficient in DNA repair?
A) Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants.
B) Measure the amount of post-translational processing that occurs in the putative DNA repair mutant plants. Measure the somatic mutation rates for the putative DNA repair mutant plants.
C) Expose the putative DNA repair mutant plants to a deaminating agent and select those that have a decreased mutation rate.
D) Measure the germ line spontaneous and induced mutation rates for the putative DNA repair mutant plants.
The provided question has marked options incorrectely the correct order as follows:
A) Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants.
B) Measure the amount of post-translational processing that occurs in the putative DNA repair mutant plants.
C) Measure the somatic mutation rates for the putative DNA repair mutant plants.
D) Expose the putative DNA repair mutant plants to a deaminating agent and select those that have a decreased mutation rate.
E) Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.
Answer:
The correct answer is: A), C) and E)
Explanation:
The breeder wants to isolate the mutants in tomatoes that are defective in DNA repair, to identify such plants breeder should follow these methods as they will allow best to identifying the defective tomatoes-
Measure the somatic mutation rates for the putative DNA repair mutant plants.
Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.
Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants. This will allow the breeder to see and analyze the ability of DNA repair in tomatoes