In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metallization. The etch rate is an important characteristic of this process and known to follow a normal distribution. Two different etching solutions have been compared using two random samples of 10 wafers for each solution. Assume the variances are equal. The etch rates are as follows (in ml per minute):

Solution 1 Solution 2
9.8 10.4 10.2 10.0
9.4 10.3 10.6 10.2
9.3 10.0 10.7 10.7
9.6 10.3 10.4 10.4
10.2 10.1 10.5 10.3
(a) Calculate the sample mean for solution 1.

(b) Calculate the sample standard deviation for solution 1.

(c) Calculate the sample mean for solution 2.

(d) Calculate the sample standard deviation for solution 2.

(e) Test the hypothesis
H
0
:
m
1
=
m
2
versus
H
1
:
m
1
â 
m
2
.

Calculate
t
0
.

(f) Calculate a 95% two-sided confidence interval on the difference in mean etch rate.

Answers

Answer 1

Answer:

[tex](a)[/tex] [tex]\bar x_1 = 9.94[/tex]

[tex](b)[/tex] [tex]x_2 = 10.4[/tex]

[tex](c)[/tex] [tex]\sigma_1 = 0.395[/tex]

[tex](d)[/tex] [tex]\sigma_2 = 0.231[/tex]

(e) There is sufficient evidence to reject the claim that the mean etch rate is the same for both solutions

[tex](f)[/tex] [tex]-0.75644 < \mu_1 - \mu_2 < -0.1556[/tex]

Explanation:

Given

Solutions 1 and 2

Solving (a): Mean of solution 1

For Solution 1, we have the following data:

[tex]9.8\ 10.4\ 9.4\ 10.3\ 9.3\ 10.0\ 9.6\ 10.3\ 10.2\ 10.1[/tex]

The sample mean is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

Where

[tex]n_1 = 10[/tex]

So, we have:

[tex]\bar x_1 = \frac{9.8+ 10.4+ 9.4+ 10.3+ 9.3+ 10.0+ 9.6+ 10.3+ 10.2+ 10.1}{10}[/tex]

[tex]\bar x_1 = \frac{99.4}{10}[/tex]

[tex]\bar x_1 = 9.94[/tex]

Solving (b): Mean of Solution 2

For Solution 1, we have the following data:

[tex]10.2\ 10.0\ 10.6\ 10.2\ 10.7\ 10.7\ 10.4\ 10.4\ 10.5\ 10.3[/tex]

The sample mean is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

Where

[tex]n_2 = 10[/tex]

So, we have:

[tex]x_2 = \frac{10.2+ 10.0+ 10.6+ 10.2+ 10.7+ 10.7+ 10.4+ 10.4+ 10.5+ 10.3}{10}[/tex]

[tex]x_2 = \frac{104}{10}[/tex]

[tex]x_2 = 10.4[/tex]

Solving (c): Sample Standard Deviation of solution 1

This is calculated as:

[tex]\sigma_1 = \sqrt{\frac{\sum (x-\bar x_1)^2}{n_1-1}}[/tex]

This gives:

[tex]\sigma_1 = \sqrt{\frac{(9.8 - 9.94)^2+ (10.4- 9.94)^2+ (9.4- 9.94)^2+................+ (10.2- 9.94)^2+ (10.1- 9.94)^2}{10 - 1}}[/tex]

[tex]\sigma_1 = \sqrt{\frac{1.404}{9}}[/tex]

[tex]\sigma_1 = \sqrt{0.156}[/tex]

[tex]\sigma_1 = 0.39496835316[/tex]

[tex]\sigma_1 = 0.395[/tex] --- approximated

Solving (d): Sample Standard Deviation of solution 2

This is calculated as:

[tex]\sigma_2 = \sqrt{\frac{\sum (x-\bar x_2)^2}{n_2-1}}[/tex]

So, we have:

[tex]\sigma_2 = \sqrt{\frac{(10.2 - 10.4)^2+ (10.0 - 10.4)^2+ (10.6 - 10.4)^2+ (10.2 - 10.4)^2+.......................+ (10.3 - 10.4)^2}{10-1}}[/tex]

[tex]\sigma_2 = \sqrt{\frac{0.48}{9}}[/tex]

[tex]\sigma_2 = \sqrt{0.05333333333}[/tex]

[tex]\sigma_2 = 0.23094010766[/tex]

[tex]\sigma_2 = 0.231[/tex]

Solving (e): Test the hypothesis

[tex]H_0: \bar x_1 = \bar x_2[/tex]

[tex]H_1: \bar x_1 \ne \bar x_2[/tex]

Start by calculating pooled standard deviation

[tex]s_p = \sqrt{\frac{(n_1 - 1)*\sigma_1^2 + (n_2 - 1)*\sigma_2^2}{n_1 + n_2 -2}[/tex]

[tex]s_p = \sqrt{\frac{(10 - 1)*0.395^2 + (10 - 1)*0.231^2}{10+ 10-2}[/tex]

[tex]s_p = \sqrt{\frac{1.884474}{18}[/tex]

[tex]s_p = \sqrt{0.104693}[/tex]

[tex]s_p = 0.324[/tex]

Calculate test statistic

[tex]t = \frac{\bar x_1 - \bar x_2}{s_p\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}[/tex]

[tex]t = \frac{9.94 - 10.4}{0.324 * \sqrt{\frac{1}{10} + \frac{1}{10}}}[/tex]

[tex]t = \frac{-0.46}{0.324 * \sqrt{0.2}}[/tex]

[tex]t = \frac{-0.46}{0.324 * 0.4472}[/tex]

[tex]t = \frac{-0.46}{0.1448928}[/tex]

[tex]t = -3.175[/tex]

Calculate the degree of freedom

[tex]df = n_1 + n_2 - 2[/tex]

[tex]df = 10+10 - 2[/tex]

[tex]df = 18[/tex]

The p value is the in the column title of the student t distribution in row 18

[tex]p = 002621[/tex]

The p value is less than the significance level (0.05).

i.e.

[tex]p < 0.05[/tex]

So: Reject the null hypothesis

Solving (f): 95% two-sided confidence interval

[tex]c = 95\%[/tex]

Calculate the degree of freedom

[tex]df = n_1 + n_2 - 2[/tex]

[tex]df = 10+10 - 2[/tex]

[tex]df = 18[/tex]

Calculate [tex]\alpha[/tex]

[tex]\alpha = (1 - c)/2[/tex]

[tex]\alpha = (1 - 95\%)/2[/tex]

[tex]\alpha = (0.05)/2[/tex]

[tex]\alpha = 0.025[/tex]

Using student t distribution

[tex]t_{\alpha/2} = 2.101[/tex]

Calculate margin of error (E)

[tex]E = t_{\alpha/2} * s_p * \sqrt{\frac{1}{n_1} + \frac{1}{n_2}}[/tex]

[tex]E = 2.101 * 0.324 * \sqrt{\frac{1}{10} + \frac{1}{10}}[/tex]

[tex]E = 2.101 * 0.324 * \sqrt{0.2}[/tex]

[tex]E = 0.3044[/tex]

The boundaries of the confidence are:

[tex](\bar x_1 - \bar x_2) -E[/tex] [tex]= (9.94- 10.4) - 0.3044 = -0.7644[/tex]

[tex](\bar x_1 - \bar x_2) + E[/tex] [tex]= (9.94- 10.4) + 0.3044 = -0.1556[/tex]

The confidence interval is:

[tex]-0.75644 < \mu_1 - \mu_2 < -0.1556[/tex]


Related Questions

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The narrator of the film "EPIC 2015" says that "at its worst," EPIC will:
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Answer:

b

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What is the role of a narrator?

One who narrates stories is a narrator. The narrator chooses the point of view of the tale in a fictional work. The narrative is considered to be in the first person if the narrator actively participates in the events of the story. A third-person narrative is one in which the narrator is not one of the characters.

Sometimes, narrators are classed according to how they tell their tales. An intrusive narrator is one who interrupts the tale to provide the reader with comments on some part of the story or on a more general issue. This style of narration was popular in many 18th and 19th-century works. An unreliable narrator is one who misinterprets the situation's significance or draws erroneous inferences from what was observed.

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Answers

Answer:

here is a link that will put you on a article you can read

Explanation:

https://edsitement.neh.gov/lesson-plans/native-americans-role-american-revolution-choosing-sides

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Answers

Answer:

hello! so Gender Discrimination is:-

Explanation:

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Hope it is right!

How did the French and American revolutions instigate the women's revolution?
А
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B
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с
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D
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Answers

Answer:

B. The calls for equality between classes inspired women to fight for equality.

Explanation:

The French Revolution was a revolution that started on the 5th of May, 1789 and ended on the 9th of November, 1799 at the kingdom of France.

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The American Revolutionary War was a war of independence of the United States of America that was fought between the 19th of April, 1775 and 3rd of September, 1783. The war started when the delegates from the thirteen (13) American colonies in Congress (First continental congress) revolted against the Great Britain over their lack of representation in the colonies and refusal to give consent to parliament's taxation such as Stamp Act and Townshend Acts.

The French and American revolutions instigated the women's revolution because the calls for equality between classes inspired women to fight for equality.

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A. White South Africans control most large farms and businesses.
B. Black South Africans have refused to hire any white employees.
C. Black South Africans have mostly left the country.
D. White South Africans were stripped of nearly all their property. ​

Answers

Answer: A or B

Explanation: A P E X

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Answers

Answer:

making frequency estimates based on the ease with which things come to mind

Explanation:

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True/False
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Answers

Answer:

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Explanation:

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Answers

Answer:

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Explanation:

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Answers

Answer:

The answers are:

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2) Control Group = None for this experiment

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Explanation:

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3. Independent Variable: These are variables whose value are predetermined or preconceived before the start of the experiment. They are the variables whose presence cause an outcome that is measured. In this example, levels of oxytocin are the independent variable.

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Do it!

Sentence stems

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Summarize the understanding section:



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Answers

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Explanation:

Answer:

b

Explanation:

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Answers

Answer:

Explanation:

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Answers

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Answers

Answer:

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Explanation:

we should take care of our culture.We can predict the quality of the community by understanding the culture of the community.Relationships between various people from the same cultural and having. different racial norms complex enough for the problem arising

The pursuance of the belief that Man is higher then Women and that people must have his/her religion are example of cultural views that can affect a relationship negatively.

What is a cultural views?

A cultural views refers to individual's opinions and beliefs on social, religious and traditional aspects of society.

The cultural view that influence the racial differences can also deteriorate the relationship between diverse races.

However, the way through which cultural views may affect relationship negatively includes the pursuance of:

the belief that Man is higher then Womenthat people must have his/her religion.

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A
B
C
D

Answers

Explanation:

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Answers

Answer:

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Explanation:

2.8
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Answers

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Answer:

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agricultural items.
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Answers

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While watching the TV news, you and your friends see a report on the capture of a suspected serial killer.
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Answers

Answer:

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