Answer:
the answer is 750 because there are 30 days in the month of april and you just need to multiply it by how much meat they need to have per day.
Step-by-step explanation:
30 x 25 = 750
The graphed line shown below is y = negative 4 x minus 12. On a coordinate plane, a line goes through (negative 3, 0) and (negative 2, negative 4). Which equation, when graphed with the given equation, will form a system that has no solution? y = 4 x + 12 y = negative 4 x y = negative 12 y = negative 4 (x + 3)
Answer:
y = -4x or the second option on edge.
This is because after you form it into the given equation, it equals y = -4x.
In order to clarify, edge also states that's the answer.
Answer:
2nd option
Step-by-step explanation:
What is the range of the function f(x)=3/4|x|-3
Range is [tex]y\in[-3,+\infty)[/tex].
Hope this helps.
Find the perimeter of an equilateral triangle where area is 72cm.
Answer:
38.68 cm
Step-by-step explanation:
Perimeter of an equilateral triangle : P = 3a
Area of an equilateral triangle : A = [tex]\frac{\sqrt{3} }{4}a^2[/tex]
a = side length
The area is given, solve for a.
[tex]72= \frac{\sqrt{3} }{4}a^2[/tex]
[tex]a = 12.894839[/tex]
The side length is 12.894839 centimeters.
Find the perimeter.
P = 3a
P = 3(12.894839)
P = 38.684517 ≈ 38.68
The perimeter is 38.68 centimeters.
how many solutions does this linear system hacve y=2/3x+2 6x-4y=-10
Answer:
the linear system has two valid solution.
Answer:one solution
Step-by-step explanation:
What is the focus of the parabola? y=−1/4x2−x+3
Answer: Focus = (-2, 3)
Step-by-step explanation:
[tex]y=-\dfrac{1}{4}x^2-x+3\\\\\rightarrow a=-\dfrac{1}{4},\ b=-1[/tex]
First let's find the vertex. We do that by finding the Axis-Of-Symmetry:
[tex]AOS: x=\dfrac{-b}{2a}\quad =\dfrac{-(-1)}{2(\frac{-1}{4})}=\dfrac{1}{-\frac{1}{2}}=-2[/tex]
Then finding the maximum by inputting x = -2 into the given equation:
[tex]y=-\dfrac{1}{4}(-2)^2-(-2)+3\\\\y=-1+2+3\\\\y=4[/tex]
The vertex is: (-2, 4)
Now let's find p, which is the distance from the vertex to the focus:
[tex]a=\dfrac{1}{4p}\\\\\\-\dfrac{1}{4}=\dfrac{1}{4p}\\\\\\p=-1[/tex]
The vertex is (-2, 4) and p = -1
The focus is (-2, 4 + p) = (-2, 4 - 1) = (-2, 3)
which linear inequality is represented by the graph
Answer:
y > 2x + 1
Step-by-step explanation:
(1 is the y intercept) 2/1 is the gradient so 2 up and 1 across
Find the volume of the figure below. Round to the nearest tenth.
7 cm
7 cm
9 cm
20 cm
11 cm
Answer:
3057.6 cm³
Step-by-step explanation:
You have a cylinder and a rectangular prism. Solve for the area of each separately.
Cylinder
The formula for volume of a cylinder is V = πr²h. The radius is 7, and the height is 7.
V = πr²h
V = π(7)²(7)
V = π(49)(7)
V = 343π
V = 1077.57 cm³
Rectangular Prism
The formula for volume of a rectangular prism is V = lwh. The length is 20, the width is 11, and the height is 9.
V = lwh
V = (20)(11)(9)
V = (220)(9)
V = 1980 cm³
Add the areas of the two shapes.
1077.57 cm³ + 1980 cm³ = 3057.57 cm³
Round to the nearest tenth.
3057.57 cm³ ≈ 3057.6 cm³
Evaluate the following geometric sum.
1/2 + 1/10 + ( 1/50) + (1/250 ) + midline ellipsis + (1/31,250)
Answer:
39062/62,500Step-by-step explanation:
Given the following geometric progression; 1/2 + 1/10 + ( 1/50) + (1/250 ) + ... + (1/31,250),the sum of the arithmetic geometric progression is expressed using the formula below;
Sn = a(1-rⁿ)/1-r for r less than 1
r is the common ratio
n is the number of terms
a is the first term of the series
In between the mid-line ellipsis there are 2 more terms, making the total number of terms n to be 7]
common ratio = (1/10)/(1/2) = (1/50)/(1/10) = (1/250)/(1/50) = 1/5
a = 1/2
Substituting the given values into the equation above
S7 = 1/2{1 - (1/5)⁷}/1 - 1/5
S7 = 1/2(1- 1/78125)/(4/5)
S7 = 1/2 (78124/78125)/(4/5)
S7 = 78124/156,250 * 5/4
S7 = 390,620/625000
S7 = 39062/62,500
Hence the geometric sum is 39062/62,500
A potato chip company makes potato chips in two flavors, Regular and Salt & Vinegar. Riley is a production manager for the company who is trying to ensure that each bag contains about the same number of chips, regardless of flavor. He collects two random samples of 10 bags of chips of each flavor and counts the number of chips in each bag. Assume that the population variances of the number of chips per bag for both flavors are equal and that the number of chips per bag for both flavors are normally distributed. Let the Regular chips be the first sample, and let the Salt & Vinegar chips be the second sample. Riley conducts a two-mean hypothesis test at the 0.05 level of significance, to test if there is evidence that both flavors have the same number of chips in each bag. (a) H0:μ1=μ2; Ha:μ1≠μ2, which is a two-tailed test. (b) t≈1.44 , p-value is approximately 0.167 (c) Which of the following are appropriate conclusions for this hypothesis test? Select all that apply. Select all that apply:
Answer:
(a) H0:μ1=μ2; Ha:μ1≠μ2, which is a two-tailed test.
Step-by-step explanation:
We formulate the
H0: μ1=μ2; null hypothesis that the two means are equal and alternate hypothesis that the two mean are not equal.
Ha:μ1≠μ2 Two tailed test
Test statistic used is
t= x1`-x2` / s√n as the variances are equal and sample size is same
T value for 9 degrees of freedom for two tailed test at α = 0.05 is 2.26
P- value for t test for 9 degrees of freedom is 0.125 from the table.
Hence only a is correct .
Solve the initial value problem y′+y=f(t),y(0)=0 where f(t)={1,−1, if t<4 if t≥4 Use h(t−a) for the Heaviside function shifted a units horizontally.
Looks like the function on the right hand side is
[tex]f(t)=\begin{cases}1&\text{for }t<4\\-1&\text{for }t\ge4\end{cases}[/tex]
We can write it in terms of the Heaviside function,
[tex]h(t-a)=\begin{cases}1&\text{for }t\ge a\\0&\text{for }t>a\end{cases}[/tex]
as
[tex]f(t)=h(t)-2h(t-4)[/tex]
Now for the ODE: take the Laplace transform of both sides:
[tex]y'(t)+y(t)=f(t)[/tex]
[tex]\implies s Y(s)-y(0)+Y(s)=\dfrac{1-2e^{-4s}}s[/tex]
Solve for Y(s), then take the inverse transform to solve for y(t):
[tex](s+1)Y(s)=\dfrac{1-e^{-4s}}s[/tex]
[tex]Y(s)=\dfrac{1-e^{-4s}}{s(s+1)}[/tex]
[tex]Y(s)=(1-e^{-4s})\left(\dfrac1s-\dfrac1{s+1}\right)[/tex]
[tex]Y(s)=\dfrac1s-\dfrac{e^{-4s}}s-\dfrac1{s+1}+\dfrac{e^{-4s}}{s+1}[/tex]
[tex]\implies y(t)=1-h(t-4)-e^{-t}+e^{-(t-4)}h(t-4)[/tex]
[tex]\boxed{y(t)=1-e^{-t}-h(t-4)(1-e^{-(t-4)})}[/tex]
Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Among 2160 passenger cars in a particular region, 243 had only rear license plates. Among 358 commercial trucks, 55 had only rear license plates. A reasonable hypothesis is that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars. Use a 0.05 significance level to test that hypothesis. a. Test the claim using a hypothesis test. b. Test the claim by constructing an appropriate confidence interval.
Answer:
For 0,90 of Confidence we reject H₀
For 0,95 CI we reject H₀
Step-by-step explanation:
To evaluate a difference between two proportion with big sample sizes we proceed as follows
1.-Proportion 1
n = 2160
243 had rear license p₁ = 243/2160 p₁ = 0,1125
2.Proportion 2
n = 358
55 had rear license p₂ = 55/ 358 p₂ = 0,1536
Test Hypothesis
Null Hypothesis H₀ ⇒ p₂ = p₁
Alternative Hypothesis Hₐ ⇒ p₂ > p₁
With signficance level of 0,05 means z(c) = 1,64
T calculate z(s)
z(s) = ( p₂ - p₁ ) / √ p*q ( 1/n₁ + 1/n₂ )
p = ( x₁ + x₂ ) / n₁ + n₂
p = 243 + 55 / 2160 + 358
p = 0,1183 and then q = 1 - p q = 0,8817
z(s) = ( 0,1536 - 0,1125 ) / √ 0,1043 ( 1/ 2160 + 1 / 358)
z(s) = 0,0411 /√ 0,1043*0,003256
z(s) = 0,0411 / 0,01843
z(s) = 2,23
Then z(s) > z(c) 2,23 > 1,64
z(s) is in the rejection region we reject H₀
If we construct a CI for 0,95 α = 0,05 α/2 = 0,025
z (score ) is from z- table z = 1,96
CI = ( p ± z(0,025*SE)
CI = ( 0,1536 ± 1,96*√ 0,1043*0,003256 )
CI = ( 0,1536 ± 1.96*0,01843)
CI = ( 0,1536 ± 0,03612 )
CI = ( 0,11748 ; 0,18972 )
In the new CI we don´t find 0 value so we have enough evidence to reject H₀
The random variable x is the number of houses sold by a realtor in a single month at the Sendsom's Real Estate office. Its probability distribution is as follows:
Houses Sold (x) Probability P(x)
0 0.24
1 0.01
2 0.12
3 0.16
4 0.01
5 0.14
6 0.11
7 0.21
Find the mean of the given probability distribution.
A. μ = 3.35
B. μ = 3.50
C. μ = 3.60
D. μ = 3.40
Answer:
C. μ = 3.60
Step-by-step explanation:
Two tables have been attached to this response.
One of the tables contains the given data and distribution with two columns: Houses Sold and Probability
The other table contains the analysis of the data with additional columns: Frequency and Fx
=> The Frequency(F) column is derived from the product of the probability of each item in the Houses sold column and the total number of houses sold (which is 28). For example,
When the number of houses sold = 0
F = P(0) x Total number of houses sold
F = 0.24 x 28 = 6.72
When the number of houses sold = 1
F = P(1) x Total number of houses sold
F = 0.01 x 28 = 0.28
=> The Fx column is found by multiplying the Frequency column by the Houses Sold column. For example,
When the number of houses sold = 0
Fx = F * x
F = 6.72 x 0 = 0
Now to get the mean, μ we use the relation;
μ = ∑Fx / ∑F
Where;
∑Fx = summation of the items in the Fx column = 100.8
∑F = summation of the items in the Frequency column = 28
μ = 100.8 / 28
μ = 3.60
Therefore, the mean of the given probability distribution is 3.60
The mean of the discrete probability distribution is given by:
C. μ = 3.60
What is the mean of a discrete distribution?The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.
In this problem, the table x - P(x) gives each outcome and their respective probabilities, hence, the mean is:
[tex]E(X) = 0(0.24) + 1(0.01) + 2(0.12) + 3(0.16) + 4(0.01) + 5(0.14) + 6(0.11) + 7(0.21) = 3.6[/tex]
Hence option C is correct.
More can be learned about the mean of discrete distributions at https://brainly.com/question/24855677
"Radon: The Problem No One Wants to Face" is the title of an article appearing in Consumer Reports. Radon is a gas emitted from the ground that can collect in houses and buildings. At certain levels it can cause lung cancer. Radon concentrations are measured in picocuries per liter (pCi/L). A radon level of 4 pCi/L is considered "acceptable." Radon levels in a house vary from week to week. In one house, a sample of 8 weeks had the following readings for radon level (in pCi/L). 1.92.45.75.51.98.23.96.9 (a) Find the mean, median, and mode. (Round your answers to two decimal places.) mean 4.55 median 4.7 mode 1.9 (b) Find the sample standard deviation, coefficient of variation, and range. (Round your answers to two decimal places.) s CV % range (c) Based on the data, would you recommend radon mitigation in this house
Answer:
a) Mean = 4.55
Median = 4.7
Mode = 1.9
b) S = 2.3952
CV = 52.64 %
Range = 6.3
c) Yes, since the average and median values are both over "acceptable" ranges.
Step-by-step explanation:
Explanation is provided in the attached document.
Does it take more large paper clips or small paper cps lined up end to end to measure the
width of a piece of printer paper? Explain.
Answer:
Step-by-step explanation:
You haven't answered any questions, yet…
A group of patients select from among 38 numbers, with 18 odd numbers (black) and 18 even
numbers (red), as well as 0 and 00 (which are green). If a doctor pays $7 that the outcome is an odd
number, the probability of losing the $7 is 20/38 and the probability of winning $14 (for a net gain of
only $7, given you already paid $7) is 18/38
If a doctor pays $7 that the outcome is an odd number, how would you figure out what is the doctors
expected value is?
Answer: $2.95
Step-by-step explanation:
Given: Probability of losing the $7 = [tex]\dfrac{20}{38}[/tex]
Probability of winning $14 = [tex]\dfrac{18}{38}[/tex]
Then, the expected value = (- $7) x ( Probability of losing the $7) + $14 x(Probability of winning $14)
= [tex](-\$ 7)\times\dfrac{20}{38}+(\$14)\times\dfrac{18}{38}[/tex]
= [tex]-\dfrac{70}{19}+\dfrac{126}{19}[/tex]
= [tex]\dfrac{56}{19}\times\approx\$2.95[/tex]
∴ If a doctor pays $7 that the outcome is an odd number, the doctor's
expected value is $2.95.
Solve the following rational equation for x.
1/4x-3/4=7/x
Answer:
x1= -4, x2 = 7
Step-by-step explanation:
Move expression to the left-hand side:
1/4x-3/4-7/x=0
Write all the numerators above a common denominator:
x^2 - 3x - 28 /4x =0
When the quotient of expressions equal 0, the numerator has to be 0
x^2 + 4x - 7x - 28 = 0
x(x+4) - 7(x+4) =0
(x+4) × (x-7) =0
Separate into possible cases:
x+4=0
x-7=0
Answer: -9
Step-by-step explanation:
The letters "A", "B", "C", "D", "E", and "F" are written on six slips of paper, and the slips are placed into a hat. If the slips are drawn randomly without replacement, what is the probability that "E" is drawn first and "B" is drawn second?
Answer:
1/30
Step-by-step explanation:
The probability of getting ”E” is 1/6.
There is only 1 “E” out of 6 letters.
There is no replacement.
There are now 5 letters without “E”.
”A”, “B”, “C”, “D”, “F”
The probability of getting ”B” is 1/5.
There is only 1 “B” out of 5 letters.
⇒ 1/6 × 1/5
⇒ 1/30
A college administrator predicts that the proportion of students that are nursing majors is greater than 40%. To test this, a group of 400 students are randomly selected and it's determined that 190 are nursing majors. The following is the setup for this hypothesis test:
H0:p=0.40
Ha:p>0.40
In this example, the p-value was determined to be 0.001. Find the conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%)
Answer:
Step-by-step explanation:
Using the following data:
H0:p=0.40 (null hypothesis)
Ha:p>0.40 (alternative hypothesis)
The p-value was determined to be 0.001.
a significance level of 5%
Since the p value (0.001) is less than the significance level (0.05), we will reject the null hypothesis and then we would conclude that the proportion of students that are nursing majors is greater than 0.4.
Answer:
p value= 0.131
Step-by-step explanation:
Since we have calculated the test statistic, we can now proceed to find the p-value for this hypothesis test.Using the test statistic and since the hypothesis test is a left tailed test, the p-value will then be the area under the standard normal curve to the left of the test statistic of -1.12.Using the Standard Normal table given above, the area under the standard normal curve to the left of the test statistic of -1.12 is 0.131 (rounded to 3 decimal places.Thus the p-value = 0.131.
The circumference of C is 72cm. What is the length of AB (the minor arc)
Answer:
Step-by-step explanation:
Can you please include a image?
Thanks!!!
What are the explicit equation and domain for a geometric sequence with a first term of 2 and a second term of −8?
Step-by-step explanation:
the common ratio is -4
Gn=2 (-4)^n-1
The perimeter of a rectangular field is 344m . If the width of the field is 75m, what is its length?
Answer:
97 m
Step-by-step explanation:
Perimeter = 2 * (length + width); perimeter = 344, width = 75 (solving for length)
344 = 2(length + 75)
172 = length + 75
length = 97
help (6)(-1)(-3)(10)(-2)
Answer:
The answer is
- 360Step-by-step explanation:
(6)(-1)(-3)(10)(-2)
Multiply the terms in the bracket
That's
(6)(-1) = - 6
(-3)(10) = - 30
So we have
(-6)(-30)(-2)
= 180( - 2)
= - 360
Hope this helps you
calculate the value of angle A to one decimal place. Picture Attached
Answer:
[tex] A = 50.7 [/tex] (to nearest tenth)
Step-by-step explanation:
Use the Law of Cosines to find the value of angle A as follows:
[tex] cos(A) = \frac{b^2 + c^2 - a^2}{2*b*c} [/tex]
Where,
a = 7 in
b = 5 in
c = 9 in
Plug in the values into the formula
[tex] cos(A) = \frac{5^2 + 9^2 - 7^2}{2*5*9} [/tex]
[tex] cos(A) = \frac{57}{90} [/tex]
[tex] cos(A) = 0.6333 [/tex]
[tex] A = cos^{-1}(0.6333) [/tex]
[tex] A = 50.7 [/tex] (to nearest tenth)
A right triangle has legs with lengths equal to 10 inches and 9x inches. Its hypotenuse measures (x + 10) inches. What is the approximate value of the hypotenuse? 10 inches 10.25 inches 20.25 inches 81 inches
Answer:
10.25 inchesStep-by-step explanation:
Given,
Perpendicular ( p ) = 9x
Base ( b ) = 10
Hypotenuse ( h ) = x + 10
Now, let's find the value of x
Using Pythagoras theorem:
[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]
Plug the values
[tex] {(x + 10)}^{2} = {(9x)}^{2} + {(10)}^{2} [/tex]
Using [tex] {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} [/tex] , expand the expression
[tex] {x}^{2} + 20x + 100 = {(9x)}^{2} + {10}^{2} [/tex]
To raise a product to a power , raise each factor to that power
[tex] {x}^{2} + 20x + 100 = 81 {x}^{2} + {10}^{2} [/tex]
Evaluate the power
[tex] {x}^{2} + 20x + 100 = 81 {x}^{2} + 100[/tex]
Cancel equal terms on both sides of the equation
[tex] {x}^{2} + 20x = 81 {x}^{2} [/tex]
Move x² to R.H.S and change its sign
[tex]20x = 81 {x}^{2} - {x}^{2} [/tex]
Calculate
[tex]20x = 80 {x}^{2} [/tex]
Swap both sides of the equation and cancel both on both sides
[tex]80x = 20[/tex]
Divide both sides of the equation by 80
[tex] \frac{80x}{80} = \frac{20}{80} [/tex]
Calculate
[tex]x = \frac{20}{80} [/tex]
Reduce the numbers with 20
[tex]x = \frac{1}{4} [/tex]
The value of X is [tex] \frac{1}{4} [/tex]
Now, let's replace the value of x to find the approximate value of hypotenuse
Hypotenuse = [tex] \frac{1}{4} + 10[/tex]
Write all numerators above the common denominator
[tex] \frac{1 + 40}{4} [/tex]
Add the numbers
[tex] \frac{41}{4} [/tex]
[tex] = 10.25[/tex] inches
Hope this helps..
best regards!!
Answer:
10.25
Step-by-step explanation:
because I said so ya skoozie
Solve 2x^2 + x - 4 = 0
X2 +
Answer:
[tex]\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }[/tex]
Step-by-step explanation:
Hello, please find below my work.
[tex]2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0[/tex]
[tex]\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
A cash register has $10 and $50 dollars bills with total of $1080.there are 28 bills in total how many of each bills.
Hey there! I'm happy to help!
Let's set this up as a system of equations, where x is equal to the number of 10 dollar bills and y is equal to the number of 50 dollar bills.
10x+50y=1080
x+y=28
We want to solve for x or y. We can rearrange the second equation to find the value of one of the variables.
x+y=28
Subtract x from both sides.
y=28-x
Now, we have a value for y. So, we could replace the y in the first equation with 28-x and the solve for x.
10x+50(28-x)=1080
We use distributive property to undo the parentheses.
10x+1400-50x=1080
We combine like terms.
-40x+1400=1080
We subtract 1400 from both sides.
-40x=-320
We divide both sides by -40.
x=8
Since there are 28 total bills, this means that there must be 20 50 dollar ones because there are 8 10 dollar bills.
Have a wonderful day! :D
Please answer in the form of a number
Answer:
d ≈ 8.3
Step-by-step explanation:
This is kind of like the pythagorean theorem, but with one extra value. Thus, [tex]d^2=l^2+w^2+h^2[/tex].
Plug in the values to get:
[tex]d^2=2^2+7^2+4^2\\d^2=4+49+16\\d^2=69\\d=\sqrt{69} \\[/tex]
Thus d ≈ 8.3
P(x)=2x^5+9x^4+9x^3+3x^2+7x-6;x=i,-2
Answer:
The value of the polynomial function at P(1) and P(-2) is 24 and 0 respectively.
Step-by-step explanation:
We are given with the following polynomial function below;
[tex]\text{P}(x) = 2x^{5} +9x^{4} +9x^{3} +3x^{2}+7x-6[/tex]
Now, we have to calculate the value of P(x) at x = 1 and x = -2.
For this, we will substitute the value of x in the given polynomial and find it's value.
At x = 1;
[tex]\text{P}(1) = 2(1)^{5} +9(1)^{4} +9(1)^{3} +3(1)^{2}+7(1)-6[/tex]
[tex]\text{P}(1) = (2\times 1) +(9\times 1)+(9 \times 1)+(3\times 1)+(7\times 1)-6[/tex]
[tex]\text{P}(1) = 2 +9+9+3+7-6[/tex]
P(1) = 30 - 6
P(1) = 24
At x = -2;
[tex]\text{P}(-2) = 2(-2)^{5} +9(-2)^{4} +9(-2)^{3} +3(-2)^{2}+7(-2)-6[/tex]
[tex]\text{P}(-2) = (2\times -32) +(9\times 16)+(9 \times -8)+(3\times 4)+(7\times -2)-6[/tex]
[tex]\text{P}(-2) = -64 +144-72+12-14-6[/tex]
P(-2) = 156 - 156
P(-2) = 0
Hence, the value of the polynomial function at P(1) and P(-2) is 24 and 0 respectively.
The local diner offers a meal combination consisting of an appetizer, a soup, a main course, and a dessert. There are three appetizers, three soups, three main courses, and three desserts. Your diet restricts you to choosing between a dessert and an appetizer. (You cannot have both.) Given this restriction, how many three-course meals are possible
Answer:
There are 2 * 32 = 64 possible ways for choosing three course meal.
Step-by-step explanation:
1-If we choose an appetizer, main course and a soup then there are 32 ways to choose this three course meal. 4 * 2 * 4 = 32 ways. There will be an appetizer, main course and a soup in the meal.
2-If we choose a soup, main course and a dessert then there are 32 ways to choose this three course meal. 4 * 2 * 4 = 32 ways. There will be a soup, main course and a dessert in the meal.
There are 2 possible ways to choose either an appetizer or dessert in a 3 course meal. There will be 64 ways in total for the three course meal.
solve for the inequality ᵏ⁄₄ ≥ 6
Answer:
k ≥ 24
Step-by-step explanation:
ᵏ⁄₄ ≥ 6
Multiply each side by 4
ᵏ⁄₄ *4 ≥ 6*4
k ≥ 24
Answer:
k≥24
Step-by-step explanation:
k/4≥6
Use the multiplication property of equality by multiplying both sides by 4 to get
k≥24
If this is wrong or if I did something wrong, please tell me so I can learn the proper way, I am just treating this like a normal problem
Thank you