In order to determine the average price of hotel rooms in Atlanta, a sample of 64 hotels was selected. It was determined that the average price of the rooms in the sample was $112. The population standard deviation is known to be $16.

a. Which form of the hypotheses should be used to test whether or not the average room price is significantly different from $108.50?

H0:
-mu is greater than or equal to $108.50
mu is greater than $108.50
mu is less than $108.50mu is less than or equal to $108.50
mu is equal to $108.50mu is not equal to $108.50

Ha: -
-mu is greater than or equal to $108.50
mu is greater than $108.50mu is less than $108.50
mu is less than or equal to $108.50
mu is equal to $108.50mu is not equal to $108.50

b. Test to determine if whether or not the average room price is significantly different from $108.50, using an alpha level of .05.


Reject H0
or
Fail to reject H0

Answers

Answer 1

Answer:

Step-by-step explanation:

H0: mu is equal to $108.50

Ha: mu is not equal to $108.50

This test is a two tailed test and using the z tat formula, we can ascertain if there is a difference.

z = x-u / sd/√n

Where x is $112, u is $108.50 sd is $16 and n is 64

z = 112-108.50 / 16/√64

z = 3.5/(16/8)

z = 3.5/2

z = 1.75

To help us arrive at a conclusion, we need to find the p value using alpha id = 0.05. The p value is 0.08. Since the p value is great than 0.05, we fail to reject the null and conclude that there is not enough statistical evidence to prove that the average room price is significantly different from $108.50


Related Questions

Which equation represents the statement below?
 
Thirteen less than a number is forty-two.

Select one:

a. n – 13 = 42

b. 42 – 13 = n

c. 13 – n = 42

d. 13 – 42 = n

Answers

The answer is option A

Step-by-step explanation:

Thirteen less than a number is written as

n - 13

Equate it to 42

We have

n - 13 = 42

Hope this helps you

Question 1
You can ride a taxi and pay a flat rate of $25 to go anywhere in the city, or you can pay a
base rate of $15 and $1 per mile. For which trip would it make more sense to pay the base
rate and 1$ per mile?
15 mile trip
9 mile trip
25 mile trip
O 12 mile trip

Answers

Answer:

9 mile trip

Step-by-step explanation:

$15 + $15 = $30

$15 + $9 = $24

$15 + $25 = $40

$15 + $12 = $27

$30 > $25

$24 < $25

$40 > $25

$27 > $25

Pls help with this area question

Answers

Answer:

  1

Step-by-step explanation:

The lateral area of a cylinder is ...

  LA = 2πrh

The total area is that added to the areas of the two circular bases:

  A = 2πr² +2πrh

We want the ratio of these to be 1/2:

  LA/A = (2πrh)/(2πr² +2πrh) = h/(r+h) = 1/2 . . . . cancel factors of 2πr

Multiplying by 2(r+h) gives ...

  2h = r+h

  h = r . . . . . subtract h

So, the desired ratio is ...

  h/r = h/h = 1

The ratio between height and radius is 1.

Please answer this correctly

Answers

Answer:

Option 2

Step-by-step explanation:

The average temperature in January is -1 degrees celsius. Last year, it was 1 degrees celsius higher than the average.

-1 + 1 = 0

Answer:

The second answer.

Step-by-step explanation:

The average temp. is -1C.

'was 1C warmer' = +1

-1+1=0

It was reported that 23% of U.S. adult cellphone owners called a friend for advice about a purchase while in a store. If a sample of 15 U.S adult cellphone owners is selected, what is the probability that 7 called a friend for advice about a purchase while in a store

Answers

Answer:

[tex] P(X=7)[/tex]

And using the probability mass function we got:

[tex]P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271[/tex]  

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

[tex]X \sim Binom(n=15, p=0.23)[/tex]  

The probability mass function for the Binomial distribution is given as:  

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]  

Where (nCx) means combinatory and it's given by this formula:  

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]  

And we want to find the following probability:

[tex] P(X=7)[/tex]

And using the probability mass function we got:

[tex]P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271[/tex]  

graph y=8 sec1/5 Ø the answers are graphs I am just unsure of how to answer

Answers

Answer:

Use a graphing calc.

Step-by-step explanation:

Help me please! I need an answer!

Answers

Answer:  [tex]\bold{\dfrac{b_1}{b_2}=\dfrac{3}{2}}[/tex]

Step-by-step explanation:

Inversely proportional means a x b = k   --> b = k/a

Given that a₁ = 2   --> b₁ = k/2

Given that a₂ = 3   -->  b₂ = k/3

[tex]\dfrac{b_1}{b_2}=\dfrac{\frac{k}{2}}{\frac{k}{3}}=\large\boxed{\dfrac{3}{2}}[/tex]

co
Which graph represents the inequality?
-2
1-1
-12
1
1 2
NE
1
Y>-
2
2
А
++
1 -1
-12
ou
-2
od
1
NIE
1
B
1 2
2
2
---
Oto
-2
-1
1 2
-12
-
NIE
NI
12
D
-2
1 - 1
1
0
1
1 2
NIS
2
NI

Answers

Answer:

A

Step-by-step explanation:

Given the equality y > -½, it means the values of y is greater than -½.

The values of y would range from 0 upwards. I.e. 0, ½, 1, 1½, 2. . .

Thus, when graphed on a number line, the circle that appears like "o" would start from -½, and the "o" would not be full or shaded to indicate that -½ is not included in the values of y, which are greater than -½. Since the values of y are greater than -½ the direction of the arrow that indicates values of y would point towards our far right, to indicate the values included as y.

Therefore, the graph that indicates the inequality y > ½ is A

Answer:

A

Step-by-step explanation:

Betty tabulated the miles-per-gallon values for her car as 26.5, 28, 30.2, 29.6, 32.3, and 24.7. She wants to construct the 95% two-sided confidence interval. Which value should Betty use for the value of t* to construct the confidence interval?

Answers

Answer:

Betty should use T = 2.571 to construct the confidence interval

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.571

Betty should use T = 2.571 to construct the confidence interval

At noon, ship A is 120 km west of ship B. Ship A is sailing east at 20 km/h and ship B is sailing north at 15 km/h. How fast is the distance between the ships changing at 4:00 PM?

Answers

Answer:

  1.39 km/h

Step-by-step explanation:

Let the initial position of ship B represent the origin of our coordinate system. Then the position of ship A as a function of time t is ...

  A = -120 +20t . . . (east of the origin)

and the position of B is ...

  B = 15t . . . (north of the origin)

Then the distance between them is ...

  d = √(A² +B²) = √((-120 +20t)² +(15t)²) = √(625t² -4800t +1440)

And the rate of change is ...

  d' = (625t -2400)/√(625t² -4800t +14400)

At t = 4, the rate of change is ...

  d' = (625·4 -2400)/√(625·16 -4800·4 +14400) = 100/√5200 = 1.39 . . . km/h

The distance between the ships is increasing at about 1.39 km/h.

Determine what type of study is described. Explain. Researchers wanted to determine whether there was an association between high blood pressure and the suppression of emotions. The researchers looked at 1800 adults enrolled in a Health Initiative Observational Study. Each person was interviewed and asked about their response to emotions. In particular they were asked whether their tendency was to express or to hold in anger and other emotions. The degree of suppression of emotions was rated on a scale of 1 to 10. Each person's blood pressure was also measured. The researchers analyzed the results to determine whether there was an association between high blood pressure and the suppression of emotions.

Answers

Answer:

Experimental Study

Step-by-step explanation:

In an experimental study, the researchers involve always produce and intervention (in this case they were asked whether their tendency was to express or to hold in anger and other emotions. The degree of suppression of emotions was rated on a scale of 1 to 10) and study the effects taking measurements.

These studies are usually randomized ie subjects are group by chance.

As opposed to observation studies, where the researchers only measures what was observed, seen or hear without any intervention on their parts.

The three-dimensional figure below is a cylinder with a hole in the shape of a rectangular prism going through the center of it.
The radius is 10 yards. Find the volume of the solid in cubic yards, rounded to the nearest ten. Use 3.14 for pie.
A. 1,980
B. 1,788
C. 1,034
D. 1,884

Answers

Answer:

B. 1788

Step-by-step explanation:

The volume of solid shaped is expressed in cubic yards. The sides of the shape are multiplied or powered as 3 for the volume determination. Volume is the total space covered by the object. It includes height, length, width. The three dimensional objects volume is found by

length * height * width

The volume for current object is :

12 * 28 * 5

= 1788 cubic yards.

Answer: 1778

Step-by-step explanation:

because Ik I had the question

Is the area of this shape approximately 24 cm* ? If not give the correct area.

311
101
True
False

Answers

Answer:

19.2 feet square

Step-by-step explanation:

We khow that the area of an octagon is :

A= 1/2 * h * P where h is the apothem and p the perimeter

A= (1/2)*1.6*(3*8) = 19.2 feet square

In the diagram below, if AD= 100 and AC = 34, find CD.
A 59
B 76
C 45
D 66

Answers

Answer:

D. 66

Step-by-step explanation:

Well if AD is 100 and AC is 34 that leaves CD so we can just subtraction 34 from 100 and get 66.

Answer:

D. 66

Step-by-step explanation:

AD = 100

AC = 34

The whole line is 100. A part of the line is 34. The other part will be 66.

100 - 34 = 66

Calculate the volume of a rectangular prism with a length of 4.4 cm, a width of 3.1 cm, and a height of 6.3 cm. (As before, you do not need to enter the units since they are provided to the right of the answer box.)

Answers

Answer:

85.932 cm³

Step-by-step explanation:

The volume of rectangular prism is obtained as the product of its length (l) by its width (w) and by its height (h):

[tex]V=l*w*h[/tex]

The volume of a prism with a length of 4.4 cm, a width of 3.1 cm, and a height of 6.3 cm is:

[tex]V=4.4*3.1*6.3\\V=85.932\ cm^3[/tex]

The volume of this prism is 85.932 cm³.

Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1

Answers

The area bounded by region between the curve [tex]y = x^2- 24[/tex]  and [tex]y = 1[/tex] is

[tex]0[/tex] square units.

To find the Area,

Integrate the difference between the two curves over the interval of intersection.

Find the points of intersection between the curves [tex]y = x^2- 24[/tex] and [tex]y = 1[/tex] .

The point of Intersection is the common point between the two curve.

Value of [tex]x[/tex] and [tex]y[/tex] coordinate  will be equal for both curve at point of intersection

In the equation [tex]y = x^2- 24[/tex], Put the value of [tex]y = 1[/tex].

[tex]1 = x^2-24[/tex]

Rearrange, like and unlike terms:

[tex]25 = x^2[/tex]

[tex]x =[/tex]  ±5

The point of intersection for two curves are:

[tex]x = +5[/tex]  and  [tex]x = -5[/tex]

Integrate the difference between the two curve over the interval [-5,5] to calculate the area.

Area =   [tex]\int\limits^5_{-5} {x^2-24-1} \, dx[/tex]

Simplify,

[tex]= \int\limits^5_{-5} {x^2-25} \, dx[/tex]

Integrate,

[tex]= [\dfrac{1}{3}x^3 - 25x]^{5} _{-5}[/tex]

Put value of limits in [tex]x[/tex] and subtract upper limit from lower limit.

[tex]= [\dfrac{1}{3}(5)^3 - 25(5)] - [\dfrac{1}{3}(-5)^3 - 25(-5)][/tex]

= [tex]= [\dfrac{125}{3} - 125] - [\dfrac{-125}{3} + 125][/tex]

[tex]= [\dfrac{-250}{3}] - [\dfrac{-250}{3}]\\\\\\= \dfrac{-250}{3} + \dfrac{250}{3}\\\\\\[/tex]

[tex]= 0[/tex]

The Area between the two curves is [tex]0[/tex] square  units.

Learn more about Integration here:

https://brainly.com/question/30402524

#SPJ4

What is the value of this expression when n approaches infinity?

Answers

Answer:

C. Approaches 35

Step-by-step explanation:

If we graph the expression, we see that we have an asymptote at y = 35.

How do you write 0.00609 in scientific notation? ____× 10^_____

Answers

Answer:

6.09 * 10 ^-3

Step-by-step explanation:

We want one non zero digit to the left of the decimal

Move the decimal 3 places to the right

6.09

The exponent is 3 and it is negative since we move to the right

6.09 * 10 ^-3

Answer:

6.09(10⁻³)

Step-by-step explanation:

Step 1: Put number into proper scientific decimal form

6.09

Step 2: Figure out how many decimals places it moves

Since it moves to the left 3, our exponent would be -3

The ratio of the areas of two circles is 121/100. What is the ratio of the radii of the two circles

Answers

Answer:

  11/10

Step-by-step explanation:

The area ratio is the square of the radius ratio (k):

  (121/100) = k²

  k = √(121/100) = 11/10

The ratio of radii is 11/10.

Would this be correct even though I didn’t use the chain rule to solve?

Answers

Answer:

Dy/Dx=1/√ (2x+3)

Yeah it's correct

Step-by-step explanation:

Applying differential by chain differentiation method.

The differential of y = √(2x+3) with respect to x

y = √(2x+3)

Let y = √u

Y = u^½

U = 2x +3

The formula for chain differentiation is

Dy/Dx = Dy/Du *Du/Dx

So

Dy/Dx = Dy/Du *Du/Dx

Dy/Du= 1/2u^-½

Du/Dx = 2

Dy/Dx =( 1/2u^-½)2

Dy/Dx= u^-½

Dy/Dx=1/√ u

But u = 2x+3

Dy/Dx=1/√ (2x+3)

A child is playing games with empty soda cups. There are three sizes: small, medium, and large. After some experimentation
she discovered she was able to measure out 160 ounces in the following ways:
1) 2 small, 2 medium, 4 large
2) 2 small, 6 medium, 1 large
3) 5 small, 1 medium, 3 large
Determine the size of the cups.​

Answers

Answer:

S is the volume of the small cup, M the volume of the medium cup and L the volume of the large cup:

2*S + 2*M + 4*L = 160oz

2*S + 6*M + 1*L = 160oz

5*S + 1*M + 3*L = 160oz.

First, we must isolate one of the variables, for this we can use the first two equations and get:

2*S + 2*M + 4*L = 160oz = 2*S + 6*M + 1*L

We can cancel 2*S in both sides:

2*M + 4*L = 6*M + 1*L

now each side must have only one variable:

4*L - 1*L = 6*M - 2*M

3*L = 4*M

L = (4/3)*M.

now we can replace it in the equations and get :

2*S + 2*M + 4*(4/3)*M = 160oz

2*S + 6*M + (4/3)*M = 160oz

5*S + 1*M + 4M = 160oz.

simplifing them we have:

2*S + (22/3)*M +  = 160oz

2*S + (22/3)*M  = 160oz

5*S + 5*M  = 160oz.

(the first and second equation are equal because we used those to get the relation of M and L, so we now have only two equations):

2*S + (22/3)*M  = 160oz

5*S + 5*M  = 160oz.

We can take the second equation and simplify it:

S + M = 160oz/5 = 32oz

S = 32oz - M

Now we can replace it in the first equation and solve it for M

2*S + (22/3)*M = 2*(32oz - M) + (22/3)*M = 160oz

62oz - 2*M + (22/3)*M = 160oz

-(6/3)*M + (22/3)*M = 98oz

(18/3)*M = 98oz

M = (3/18)*98oz = 16.33 oz

Then:

L = (4/3)*M =(4/3)*16.33oz = 21.78 oz

and:

S = 32oz - M = 32oz - 16.33oz = 15.67oz

volume of a cube size 7cm​

Answers

Answer:

343 cm3

Step-by-step explanation:

Answer:

side(s) =7cm

volume (v)=l^3

or, v = 7^3

therefore the volume is 343cm^3.

hope its what you are searching for..

The number of degrees of freedom for the appropriate chi-square distribution in a test of independence is a. k – 1. b. A chi-square distribution is not used. c. number of rows minus 1 times number of columns minus 1. d. n – 1.

Answers

Answer:

Option C

Step-by-step explanation:

The chi square test of independence is used to determine if there is a significant association between two categorical variables from a population.

It tests the claim that the row and column variables are independent of each other.

The degrees of freedom for the chi-square are calculated using the following formula: df = (r-1) (c-1) where r is the number of rows and c is the number of columns.

Estimate the area under the graph of f(x)=2x^2-12x+22 over the interval [0,2] using four approximating rectangles and right endpoints.

Answers

Answer:

The right Riemann sum is 21.5.

The left Riemann sum is 29.5.

Step-by-step explanation:

The right Riemann sum (also known as the right endpoint approximation) uses the right endpoints of a sub-interval:

[tex]\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)[/tex], where [tex]\Delta{x}=\frac{b-a}{n}[/tex].

To find the Riemann sum for [tex]\int_{0}^{2}\left(2 x^{2} - 12 x + 22\right)\ dx[/tex] with 4 rectangles, using right endpoints you must:

We have that a = 0, b = 2, n = 4. Therefore, [tex]\Delta{x}=\frac{2-0}{4}=\frac{1}{2}[/tex].

Divide the interval [0,2] into n = 4 sub-intervals of length [tex]\Delta{x}=\frac{1}{2}[/tex]:

[tex]\left[0, \frac{1}{2}\right], \left[\frac{1}{2}, 1\right], \left[1, \frac{3}{2}\right], \left[\frac{3}{2}, 2\right][/tex]

Now, we just evaluate the function at the right endpoints:

[tex]f\left(x_{1}\right)=f\left(\frac{1}{2}\right)=\frac{33}{2}=16.5\\\\f\left(x_{2}\right)=f\left(1\right)=12\\\\f\left(x_{3}\right)=f\left(\frac{3}{2}\right)=\frac{17}{2}=8.5\\\\f\left(x_{4}\right)=f(b)=f\left(2\right)=6[/tex]

Finally, just sum up the above values and multiply by [tex]\Delta{x}=\frac{1}{2}[/tex]:

[tex]\frac{1}{2}(16.5+12+8.5+6)=21.5[/tex]

The left Riemann sum (also known as the left endpoint approximation) uses the left endpoints of a sub-interval:

[tex]\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)[/tex], where [tex]\Delta{x}=\frac{b-a}{n}[/tex].

To find the Riemann sum for [tex]\int_{0}^{2}\left(2 x^{2} - 12 x + 22\right)\ dx[/tex] with 4 rectangles, using left endpoints you must:

We have that a = 0, b = 2, n = 4. Therefore, [tex]\Delta{x}=\frac{2-0}{4}=\frac{1}{2}[/tex].

Divide the interval [0,2] into n = 4 sub-intervals of length [tex]\Delta{x}=\frac{1}{2}[/tex]:

[tex]\left[0, \frac{1}{2}\right], \left[\frac{1}{2}, 1\right], \left[1, \frac{3}{2}\right], \left[\frac{3}{2}, 2\right][/tex]

Now, we just evaluate the function at the left endpoints:

[tex]f\left(x_{0}\right)=f(a)=f\left(0\right)=22\\\\f\left(x_{1}\right)=f\left(\frac{1}{2}\right)=\frac{33}{2}=16.5\\\\f\left(x_{2}\right)=f\left(1\\\right)=12\\\\f\left(x_{3}\right)=f\left(\frac{3}{2}\right)=\frac{17}{2}=8.5[/tex]

Finally, just sum up the above values and multiply by [tex]\Delta{x}=\frac{1}{2}[/tex]:

[tex]\frac{1}{2}(22+16.5+12+8.5)=29.5[/tex]

Write the fraction in simplest form. (3/6) x (7/10)

Answers

Answer:
7/20
Explanation:
In order to do this, you must first simplify all the equations to the simplest forms. Do this by simplifying 3/6 to 1/2. We know this because 3 is half of 6, therefore it would reduce down to 1/2. 7/10 is already simplified; we know this because 7 is a prime number and can’t do down any further
Now, multiply the two fractions buy multiplying the numerators and denominations together. In other words, 1 x 7 is 7 so your numerator is 7, and 2 x 10 is 20 so your denominator is 20.

Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145 a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

Answers

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Answer:

a. Cumulative Probability Distribution

Grade             P(X ≤ x)

F                      0.145

D                     0.310

C                     0.670

B                     0.910

A                         1

b. P(at least B) = 0.330

c. P(pass) = 0.855

Step-by-step explanation:

Professor Sanchez has been teaching Principles of Economics for over 25 years.

He uses the following scale for grading.

Grade     Numerical Score      Probability

A                       4                            0.090

B                       3                            0.240

C                       2                            0.360

D                       1                            0.165

F                       0                            0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

The cumulative probability distribution is given by

Grade = F

P(X ≤ x) = 0.145

Grade = D

P(X ≤ x) = 0.145 + 0.165 = 0.310

Grade = C

P(X ≤ x) = 0.145 + 0.165 + 0.360 = 0.670

Grade = B

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 = 0.910

Grade = A

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 + 0.090 = 1

Cumulative Probability Distribution

Grade             P(X ≤ x)

F                      0.145

D                     0.310

C                     0.670

B                     0.910

A                         1

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

At least B means equal to B or greater than B grade.

P(at least B) = P(B) + P(A)

P(at least B) = 0.240 + 0.090

P(at least B) = 0.330

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Passing the course means getting a grade of A, B, C or D

P(pass) = P(A) + P(B) + P(C) + P(D)

P(pass) = 0.090 + 0.240 + 0.360 + 0.165

P(pass) = 0.855

Alternatively,

P(pass) = 1 - P(F)

P(pass) = 1 - 0.145

P(pass) = 0.855

For the triangle show, what are the values of x and y (urgent help needed)

Answers

we just have to use the Pythagoras theorem and then calculate the value of x and y.

Select the correct answer from each drop down menu. AB is dilated by a scale factor of 3 to form A 1 B1. Point O, which lies on AB, is the center of dilation. The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O.

Answers

Answer:

the slope of A'B' = 3

A'B' passes through point O

Step-by-step explanation:

A dilation with scale factor 3 gives the effect of stretching the line AB three times longer. As dilation does not change the direction of the line, the slope will stay the same. If point O lies on AB and is the center of dilation, then the point O must also lie on A'B'

The required black space in the statement "The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O". is filled by 3 and passes.

Given that,
To Select the correct answer from each drop-down menu. AB is dilated by a scale factor of 3 to form A 1 B1. Point O, which lies on AB, is the center of dilation. The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O.

What is the scale factor?

The scale factor is defined as the ratio of modified change in length to the original length.

Here, is o is the center of the line AB and slope of line AB is 3 than the line dilated with scale factor 3 A1B1 has also a scale factor of 3 because Position of dilation is center 0 thus dilation did not get any orientation.
And the center of dilation is O so line A1B1 passes through O.

Thus, the required black space in the statement "The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O". is filled by 3 and passes.

Learn more about line Scale factors here:

https://brainly.com/question/22312172

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A model for​ consumers' response to advertising is given by the equation N(a)=2600 + 470ln (a) Where​ N(a) is the number of units​ sold, a is the amount spent on​ advertising, in thousands of​ dollars, & a≥1.

Required:
a. How many units were sold after spending ​$1,000 on​ advertising?
b. Find N′(a).
c. Find the maximum​ value, if it exists.
d. Find lim a→[infinity] N′(a).

Answers

Answer:

a. [tex]N(1)=2600[/tex]

b. [tex]N'(a) = 470/a[/tex]

c. N(a) has no maximum value, max N'(a) = 470 (when a = 1)

d. lim a→[infinity] N′(a) = 0

Step-by-step explanation:

a.

the variable 'a' is the amount spent in thousands of dollars, so $1,000 is equivalent to a = 1. Then, we have that:

[tex]N(1)=2600 + 470ln(1)[/tex]

[tex]N(1)=2600 + 470*0[/tex]

[tex]N(1)=2600[/tex]

b.

To find the derivative of N(a), we need to know that the derivative of ln(x) is equal (1/x), and the derivative of a constant is zero. Then, we have:

[tex]N'(a) = 2600' + (470ln(a))'[/tex]

[tex]N'(a) = 0 + 470*(1/a)[/tex]

[tex]N'(a) = 470/a[/tex]

c.

The value of 'ln(a)' increases as the value of 'a' increases from 1 to infinity, so there isn't a maximum value for N(a).

The maximum value of N'(a) is when the value of a is the lower possible, because 'a' is in the denominator, so the maximum value of N'(a) is 470, when a = 1.

d.

When the value of 'a' increases, the fraction '470/a' decreases towards zero, so the limit of N'(a) when 'a' tends to infinity is zero.

by which number -7 /25 should be divided to get -1/15?

Answers

Answer:

21/5

Step-by-step explanation:

if a/b = c, then b=a/c

in other words:

divide -7/25 by -1/15 to get the answer

It also helps to use the fact that a/b / c/d = a/b * d/c

-7/25 / -1/15 = -7/25 * -15/1

= 105 / 25

= 21 / 5

Answer:

[tex]4 \frac{1}{5} [/tex]

Step-by-step explanation:

[tex] \frac{ - 7}{25} \div x = \frac{ - 1}{15} [/tex]

[tex]x = \frac{ - 7}{25} \div \frac{ - 1}{15} [/tex]

[tex] = \frac{7}{25} \times \frac{15}{1} [/tex]

[tex] = \frac{21}{5} = 4 \frac{1}{5} [/tex]

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