In many cases, a negatively charged compound (ex Cl-) will interact with a positively charged metal (ex Fe2 ). Usually we would consider this type of interaction to be ionic, but in the case of metals we do not. What type of bond is being formed when a ligand interacts with a metal and how could you know that the bond you are forming is that type of bond

Solution :

The balanced chemical equation are

The Catabolism of the glucose takes place in five stages :

1. Glucose + [tex]$ATP$[/tex] → glucose - [tex]$6$[/tex] - phosphate [tex]$+ ADP$[/tex]  ,  [tex]$\Delta G^0=-16.7 \ kJ/mol$[/tex]

2. Glucose - [tex]$6$[/tex] - phosphate → Fructose - [tex]$6$[/tex] - phosphate ,  [tex]$\Delta G^0=1.7 \ kJ/mol$[/tex]

3. Glucose - [tex]$6$[/tex] - phosphate + [tex]$ATP$[/tex] → [tex]$ADP$[/tex] + Fructose - [tex]$1,6- \text{biophosphate}$[/tex],  [tex]$\Delta G^0=-14.2 \ kJ/mol$[/tex]

4. Fructose - [tex]$1,6- \text{biophosphate}$[/tex]  → dihydroxyacetonephosphate + glyceraldehyde  [tex]$-3 - $[/tex] phosphate,   [tex]$\Delta G^0=23.8 \ kJ/mol$[/tex]

5. Dihydroxyacetonephosphate → glyceraldehyde  [tex]$-3 - $[/tex] phosphate , [tex]$\Delta G^0=7.5 \ kJ/mol$[/tex]

Therefore, the overall net equations

Glucose + [tex]$2ATP \rightarrow$[/tex] glyceraldehyde  [tex]$-3 - $[/tex] phosphate + [tex]$2ADP$[/tex] [tex]$\Delta G^0=2.1 \ kJ/mol$[/tex]

Answer:

answer po Yan hope it help

Answer:

16 g

Explanation:

Step 1: Write the balanced equation

2 CO + O₂ → 2 CO₂

Step 2: Calculate the moles of O₂ required to produce 1.0 moles of CO₂

The molar ratio of O₂ to CO₂ is 1:2.

1.0 mol CO₂ × 1 mol O₂/2 mol CO₂ = 0.50 mol O₂

Step 3: Calculate the mass corresponding to 0.50 moles of O₂

The molar mass of O₂ is 32.00 g/mol.

0.50 mol × 32.00 g/mol = 16 g

Answer:

[tex]\frac{1}{\lambda_{6-5}} \approx 752nm[/tex]

Explanation:

From the question we are told that

Light wavelength  [tex]\lambda_l=655nm[/tex]

Light wavelength atom fall [tex]x_L=5th-2nd[/tex]

Photon wavelength  [tex]\lambda_p=435nm[/tex]

Photon wavelength atom fall [tex]x_P=^th-2nd[/tex]

Generally the equation for the reciprocal of wavelength of emitted photon is is mathematically given by

[tex]\frac{1}{\lambda}=R(\frac{1}{ \lambda _f^2}-\frac{1}{\lambda _i^2} )[/tex]

Therefore for initial drop of 5th to 2nd

[tex]\frac{1}{\lambda_{5-2}}=R(\frac{1}{2^2}-\frac{1}{5^2} )[/tex]

Therefore for initial drop of 6th to 2nd

[tex]\frac{1}{\lambda_{6-2}}=R(\frac{1}{2^2}-\frac{1}{6^2} )[/tex]

Generally we subtract (5th to 2nd) from (6th to 2nd)

[tex]\frac{1}{\lambda_{5-2}}- \frac{1}{\lambda_{6-2}}=R(\frac{1}{2^2}-\frac{1}{5^2} )-\frac{1}R(\frac{1}{2^2}-\frac{1}{6^2} )[/tex]

[tex]\frac{1}{\lambda_{5-2}}- \frac{1}{\lambda_{6-2}}=R(\frac{1}{5^2}-\frac{1}{6^2} )[/tex]

[tex]\frac{1}{\lambda_{5-2}}- \frac{1}{\lambda_{6-2}}=\frac{1}{\lambda_{5-6}}[/tex]

[tex]\frac{1}{\lambda_{5-6}}=\frac{1}{4350nm}-\frac{1}{655nm}[/tex]

[tex]\frac{1}{\lambda_{5-6}}=1.33*10^{-3}[/tex]

Therefore for 6th to 5th stage is mathematically given by

[tex]\frac{1}{\lambda_{6-5}}=(1.33*10^{-3})^{-1}[/tex]

[tex]\frac{1}{\lambda_{6-5}}=751.879nm[/tex]

[tex]\frac{1}{\lambda_{6-5}} \approx 752nm[/tex]

Answer:

mi = 31.28 g

Explanation:

According to the law of conservation of energy:

[tex]Heat\ Gain\ by\ Ice = Heat\ Lost\ by\ Water\\m_iL = m_wC\Delta T\\[/tex]

where,

mi = mass of ice = ?

L = Latent heat of fusion of ice = 334 J/g

mw =  mass of water = 50 g

C = specific heat of water = 4.18 J/g.°C

ΔT = change in temperature of water = 75°C - 25°C = 50°C

Therefore,

[tex]m_i(334\J/g) = (50\ g)(4.18\ J/g.^oC)(50^oC)[/tex]

mi = 31.28 g

Answer:

Baking a cake

Explanation:

Ape-x aprroved

Answer:

in my opinion I think the answer the be "A"

Answer:

B. Particles of matter have spaces between them.

Explanation:

The particle nature model of matter is an model used to explain the properties and nature of matter. The statements of the particle nature model of matter are as follows :

1. Matter is made of small particles of atoms or molecules.

2. The particles of matter have space between them. The spaces between the particles are least in solids as they are closely packed together but are greatest in gases whose particles are far apart from each other.

3. The particles of matter are in constant motion at all times. Solids particles are not free to move due to strong molecular forces between the particles, but are constantly vibrating in their mean positions. Liquid particles free to move due to lesser molecular forces while gas molecules which have negligible intermolecular forces have the greatest ability to move.

4. The particles of matter are attracted to each other by intermolecular forces. These forces are greatest in solids and least in gases.

The correct option is B.

Answer:

Melting is endothermic, so the air temperature decreases.

Explanation:

Hello there!

In this case, according to the given statement, it is possible to infer that the ice is melt because energy is applied to the ice and thereafter its temperature increases; this is possible because the joined particles of a solid substance need energy to undergo such a separation that they become more far away to each other and therefore transcend to the liquid phase due to the new molecules arrangement. Thus, the answer is Melting is endothermic, so the air temperature decreases because as the ice heats up, the air cools down as it gives it energy to the ice.

Best regards!

Answer:

Ka=[H+][A−]/[HA]

which solution has the lower pH, 0.10MHF(aq) or 0.10MHC2H3O2(aq) :

Higher value of Ka indicates greater ionization thus more protons in solution, higher H+ concentration in solution means lower pH value.

Since HF have higher Ka have, thus HF solution will have lower pH.

The measurement is when the solution has the lower pH so HF should have higher ka.

In the given solution, it contains the  lower pH, 0.10MHF(aq) or 0.10MHC2H3O2(aq).

Here higher value of Ka represents the high ionization so there should be more protons in the solutions. and, the higher h+ concentration have the lower pH value.

So in the case when HF has higher Ka, due to this, HF solution will have lower pH.

Learn more about solution here: https://brainly.com/question/14619461

Answer:

1.15 M

Explanation:

Step 1: Given data

Step 2: Calculate the final concentration of the solution

We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M

Answer:

A. Autotrophs

Explanation:

an autotroph, def an organism that is able to form nutritional organic substances from simple inorganic substances such as carbon dioxide.

humans and other mammals, plants, and a select few other things

Answer:

[tex]\Delta H_{comb}=2043.85kJ/mol[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:

[tex]\Delta H_r=-\Delta H_{comb}=3\Delta _fH_{CO_2}+4\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-3\Delta _fH_{O_2}[/tex]

Thus, given the values of the enthalpies of formation on the attached file, we obtain:[tex]-\Delta H_{comb}=3(-393.5kJ/mol)+4(-241.8kJ/mol)-(-103.85kJ/mol)-3(0kJ/mol)\\\\-\Delta H_{comb}=-2043.85kJ/mol\\\\\Delta H_{comb}=2043.85kJ/mol[/tex]

Best regards!

Answer:

B. aq if the reaction is inorganic (double or single displacement), neutralization, etc.

Explanation:

Hello there!

In this case, unfortunately we are not given the undergoing chemical reaction; however, in the most of the double displacement, neutralization, precipitation and in general, inorganic reactions, the hydrochloric acid must be B. aq as it must be dissolved in water as the reaction media. On the other hand, in some organic reactions, it can be either aqueous or gaseous, the latter, specially as a product. For that reason, you will need to make sure whether your reaction is organic or inorganic to correctly figure out the phase label.

Best regards!

Answer:

Go to the pool , Bake, sleep, Watch ,Movies, go out with my freinds<3

Explanation:

Answer:

SnSO₄

Explanation:

Tin(II) sulfate is a chemical compound. It is a white solid that can absorb enough moisture from the air to become fully dissolved, forming an aqueous solution; this property is known as deliquescence.

Answer:

please give me brainlist and follow

Explanation:

SnSO₄

Answer:there different from the rocky like planets gas giants don't have such a firm surface like rocky terrestrial planets

Explanation:

Answer:

0. 070g

Mass of 1 Si atom =28.08/6.022*1023

So mass 1.5 *1021*4.6629*10-23

Answer:

[tex]\boxed {\boxed {\sf 0.070 \ g \ Si}}[/tex]

Explanation:

We are given a value of atoms and asked to find the mass. We can complete this in 2 steps.

1. Convert Atoms to Moles

First, we have to convert atoms to moles. We use Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance.

In this case, the particles are silicon atoms. We can set up a proportion.

[tex]\frac { 6.022 \times 10^{23} \ atom \ Si }{1 \ mol \ Si}[/tex]

Multiply by the value of atoms given.

[tex]1.5 \times 10^{21} \ atom \ Si *\frac { 6.022 \times 10^{23} \ atom \ Si }{1 \ mol \ Si}[/tex]

Flip the ratio. This allows the atoms of silicon units to cancel and leave the moles of silicon.

[tex]1.5 \times 10^{21} \ atom \ Si *\frac {1 \ mol \ Si } {6.022 \times 10^{23} \ atom \ Si}[/tex]

[tex]1.5 \times 10^{21}*\frac {1 \ mol \ Si } {6.022 \times 10^{23} }[/tex]

[tex]\frac {1.5 \times 10^{21} \ mol \ Si } {6.022 \times 10^{23} }[/tex]

[tex]0.002490866822 \ mol \ Si[/tex]

2. Convert Moles to Grams

Next, we convert the moles to grams. We use the molar mass, which is found on the Periodic Table. This value is the number of grams in 1 mole of a substance. Look for silicon (Si).

Use this value as a ratio.

[tex]\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]

Multiply by the number of moles we calculated.

[tex]0.002490866822 \ mol \ Si *\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]

The moles of silicon units cancel, so we are left with grams.

[tex]0.002490866822 *\frac {28.085 \ g \ Si}{1}[/tex]

[tex]0.002490866822 *{28.085 \ g \ Si}[/tex]

[tex]0.06995599469 \ g \ Si[/tex]

3. Round

Finally we must round our answer. The original value has 2 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

[tex]0.069\underline95599469 \ g Si[/tex]

The 9 tells us to round the other 9 to a 0, then the 6 to a 7.

[tex]0.070 \ g \ Si[/tex]

The mass of 1.5 × 10²¹ silicon atoms is 0.070 grams of silicon.

Answer:

1. Distance  = 5 cm

Displacement = 1 cm

2. Distance = 7 cm

Displacement = 1 cm

3. Distance = 5 cm

Displacement = -1 cm

4. Distance  = 6 cm

Displacement = -2 cm

5. Distance  = 4 cm

Displacement = 0 cm

Explanation:

The distance an object travels is a measure of the total ground cobpvered bybthe object without regard to the direction of motion. It is a scalar quantity as it only takes into account magnitude but not the direction of a quantity.

Displacement however, is a measure of how far away or apart an object is from its starting position.  It a vector quantity as it takes into account both the magnitude and direction in its measurement.

From the attachment provided, considering forward direction as positive and reverse as negative :

1. When a object moves from point 1 to point 4 and reverses to point 2.:

Distance  = from 1 to 4 = 3 cm; from 4 back to 2 = 2 cm;  3 + 2 = 5 cm

Displacement = from 1 to 4 = +3 cm; from 4 back to 2 = -2 cm;  3 - 2 = 1 cm

2. When an object moves from point 1 to 5 and reverses to 2:

Distance = from 1 to 5 = 4cm; from 5 back to 2 = 3 cm; 4 + 3 = 7 cm

Displacement = from 1 to 5 = +4 cm; from 5 back to 2 = -4 cm;  4 - 3 = 1 cm

3. When an object moves from point 1 to 3 and then reverses to 0.

Distance  = from 1 to 3 = 2 cm; from 3 back to 0 = 3 cm;  2 + 3 = 5 cm

Displacement = from 1 to 3 = +2 cm; from 3 back to 0 = -3 cm;  2 - 3 = -1 cm

4. When an object moves from point 3 to 5 and then reverses to 1:

Distance  = from 3 to 5 = 2 cm; from 5 back to 1 = 4 cm;  2 + 4 = 6 cm

Displacement = from 3 to 5 = +2 cm; from 5 back to 1 = -4 cm;  2 - 4 = -2 cm

5. When an object moves from point 2 to 4 and then reverses to 3.

Distance  = from 2 to 4 = 2 cm; from 4 back to 2 = 2 cm;  2 + 2 = 4 cm

Displacement = from 2 to 4 = +2 cm; from 4 back to 2 = -2 cm;  2 - 2 = 0 cm

Answer:

At D: Soil erosion us the process taking place.

Soil erosion is the washing away of the Earth's or soil's top layer by eroding agents.

Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

Explanation:

A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.

Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.

[tex]No. of moles = \frac{mass}{molar mass}\\= \frac{36 g}{58.4 g/mol}\\= 0.616 mol[/tex]

This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.

So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.

[tex]Moles = \frac{5.8 mol}{1000 mL} \times 100 mL\\= 0.58 mol[/tex]

[tex]Moles = \frac{3.25 mol}{500 mL} \times 100 mL\\0.65 mol[/tex]

[tex]Moles = \frac{1.85 mol}{300 mL} \times 100 mL\\= 0.616 mol[/tex]

Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

Answer:

Explanation:

Dear student, this question appears to be incomplete but in the diagram attached below, I have carefully drawn out the required organic structure.

The aim of this question is to show the mechanism of the given structure and to point out the resonance structure.

The first diagram shows the complete part (i.e. the structure of the organic compound) and its major product(answer).

The second diagram shows the mechanism by which we arrived at the major product.

From the second diagram attached below, the -oxo substituent of the methanol attacks the hydrogen atom as shown below, leading to the formation of the enolate ion (a resonance stabilized anion).

However, this is because the alpha carbon attaches to the hydrogens readily leaves as H⁺ to yield an enolate ion as a result of -C- that is doubly bonded to oxygen (an Electron withdrawing group).

Kindly check out the images attached below to see the mechanism.

Answer:

https://sensorex.com/ph-calculator/

Explanation:

go to this link and then scroll down a little bit and then you'll find the answer

Answer:

Six atoms of calcium, four of phosphorous and sixteen of oxygen for a total of twenty six

Explanation:

Hello there!

In this case, according to the molecular formula of the two moles of calcium phosphate:

[tex]2Ca_3(PO_4)_2[/tex]

Thus, in order to calculate the atoms of each atom, it is necessary to multiply the two in front of the formula by the subscripts in the reaction:

[tex]atoms Ca=2*3=6\\\\atoms P=2*2=4\\\\atoms O=2*2*4=16[/tex]

Thus, we obtain six atoms of calcium, four of phosphorous and sixteen of oxygen for a total of twenty six.

Best regards!

Answer:

0.22M

Explanation:

We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.

So: moles before dilution = moles after dilution & [tex]moles_{concentrated} = moles_{dilute}[/tex]. And M = moles/liter of solution, so if we express this as moles = M x [tex]L_{soln}[/tex].

That is how we derive the formula we will be using: [tex]M_{concentrated} * Vol_{conc} = M_{dilute} * Vol_{dilute}[/tex]

or

[tex]M_{1} * Vol_{1} = M_{2} * Vol_{2}[/tex]

Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.

M1 = 3.5M

V1 = 18.8mL

M2 = ?

V2 = 296.6mL

Equation: (3.5M)(18.8mL) = (296.6mL)(M2)

==> 65.8M*mL = 296.6mL * M2

==> M2 = (65.8 M*mL)/296.6mL

==> M2 = 0.22M

Answer: When two hydrogen atoms pair together, they form a  single bond to achieve a complete duet which is a stable configuration.

When two halogens poir together,they form a single bond to achieve a complete octet which is a stable configuration  

When two oxygen atoma pair together, they form a double bond to achieve a complete octet which is a stable configuration

When two nitrogen atoms pair together, they form a triple bond to achieve a complete octet which is a stable configuration

Explanation:

The tendency of atoms to achieve a noble gas configuration that is eight valence electrons is said to be octet rule.  This is done to attain noble gas configuration and stability.

In order to attain stability the atoms tends to have eight electrons in its valence shell which can be obtained by either by sharing of electrons or complete transfer of electrons.

Hydrogen [tex](H:1s^1)[/tex] has one valence electron each, so sharing of electrons result in formation of single bond and the same electron configuration as the Helium and thus complete its duet.

Halogens [tex](F:1s^22s^22p^5)[/tex]  have 7 valence electron each, so sharing of electrons result in formation of single bond. The stable noble gas configuration is attained and thus complete its octet.

Oxygen [tex](O:1s^22s^22p^4)[/tex]  has six valence electrons each, so sharing of two electrons result in a double bond. The stable noble gas configuration is attained and thus complete its octet.

Nitrogen [tex](N:1s^22s^22p^3)[/tex]  has 5 valence electrons, so sharing of three electrons result in a triple bond. The stable noble gas configuration is attained and thus complete its duet.

Answer:

0.67 cm³

Explanation:

We can solve this problem by using the definition of density:

We can rearrange the equation and isolate volume:

As we are given both the mass and the density, we can now calculate the volume: