in july of 2013, australians were asked if they thought unemployment would increase, and 47% thought that it would increase. in november of 2013, they were asked again. at that time 338 out of 800 said that they thought unemployment would increase. at the 8% level, is there enough evidence to show that the proportion of australians in november 2013 who believe unemployment would increase is lower than the proportion who felt it would increase in july 2013?

Answers

Answer 1

Since the p-value is less than the significance level of 0.08, we reject the null hypothesis and conclude that there is enough evidence to show that the proportion of Australians in November 2013 who believe unemployment would increase is lower than the proportion who felt it would increase in July 2013 at the 8% level of significance.

To determine if there is enough evidence to show that the proportion of Australians in November 2013 who believe unemployment would increase is lower than the proportion who felt it would increase in July 2013, we need to perform a hypothesis test.

Let p1 be the proportion who thought unemployment would increase in July 2013 and p2 be the proportion who thought unemployment would increase in November 2013.

The null hypothesis is that there is no difference between the two proportions: p1 = p2. The alternative hypothesis is that the proportion in November 2013 is lower than the proportion in July 2013: p2 < p1.

We can use a two-sample z-test to test this hypothesis, since we have two independent samples and the sample sizes are large enough.

The test statistic is calculated as:

z = (p1 - p2) / √(p * (1 - p) * (1/n1 + 1/n2))

where p = (x1 + x2) / (n1 + n2) is the pooled proportion, x1 and x2 are the number of people who thought unemployment would increase in July 2013 and November 2013, respectively, and n1 and n2 are the sample sizes.

Using the given data, we have:

p1 = 0.47

p2 = 338/800 = 0.4225

n1 = n2 = 800

p = (8000.47 + 8000.4225) / (800 + 800) = 0.44625

z = (0.47 - 0.4225) / √(0.44625 * (1 - 0.44625) * (1/800 + 1/800))

= 3.373

Using a standard normal distribution table or calculator, we find that the p-value for a one-tailed test with a z-score of 3.373 is less than 0.01.

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Related Questions

i dont know what to write here the question is there

Answers

Answer:

53.93 cm

Step-by-step explanation:

The given arc is 38.95 and the angle is 260 degrees.

A full angle would be 360 degrees, so we can use a ratio to find what the full circle would be:  

260/360 = 38.95/x

This equation is saying that 38.95 is equal to 260 degrees of the circle, while x is equal to 360 degrees.

Solving for x:

260x = 14022

x = 53.9306792

Round and it is:

53.93 cm

[tex]\frac{3x}{2}[/tex]×[tex]\frac{x}{5}[/tex]

Answers

Answer:

[tex]\frac{3x^{2} }{10}[/tex]

Step-by-step explanation:

[tex]\frac{3x}{2}[/tex] x [tex]\frac{x}{5}[/tex] = [tex]\frac{3x^{2} }{10}[/tex]

So, the answer is  [tex]\frac{3x^{2} }{10}[/tex]

a stack of boards is 24 inches high. each board is 38 of an inch thick. how many boards are in the stack?responses

Answers

There are 64 boards in the stack.

How much number of boards in the stack?

To find the number of boards in the stack, we need to divide the total height of the stack by the thickness of each board.

Since each board is 3/8 of an inch thick, we can write:

Number of boards = Total height of stack ÷ Thickness of each board

Number of boards = 24 inches ÷ (3/8) inches

Number of boards = 24 inches × (8/3)

Number of boards = 64

Therefore, there are 64 boards in the stack.

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Find
(sec A x sin C - tan A x tan C)/sin B
where
A triangle ABC is right angled at B

Answers

The given expression, (sec A x sin C - tan A x tan C)/sin B, simplifies to (x/40) x AB, where AB is the length of the side opposite the right angle in triangle ABC.

Since triangle ABC is right-angled at B, we can use the following trigonometric ratios:

sin A = opposite/hypotenuse = AC/BC

cos A = adjacent/hypotenuse = AB/BC

tan A = opposite/adjacent = AC/AB

sin C = opposite/hypotenuse = AB/BC

cos C = adjacent/hypotenuse = AC/BC

tan C = opposite/adjacent = AB/AC

Using these ratios, we can simplify the given expression as follows:

(sec A x sin C - tan A x tan C)/sin B

= [(1/cos A) x sin C - tan A x tan C]/sin B (using sec A = 1/cos A)

= [(1/cos A) x (AB/BC) - (AC/AB) x (AB/AC)]/sin B (substituting sin C and tan C)

= [(AB/BCcos A) - (AC/BC)]/sin B (simplifying)

= [(AB/BC) - (ACcos A/BCcos A)]/sin B (getting a common denominator)

= [(AB - ACcos A)/BC]/sin B (simplifying)

= [(AB - ABsin A)/BC]/sin B (substituting)

Since triangle ABC is right-angled at B, we can use the following trigonometric ratios:

sin A = opposite/hypotenuse = AC/BC

cos A = adjacent/hypotenuse = AB/BC

tan A = opposite/adjacent = AC/AB

sin C = opposite/hypotenuse = AB/BC

cos C = adjacent/hypotenuse = AC/BC

tan C = opposite/adjacent = AB/AC

Using these ratios, we can simplify the given expression as follows:

(sec A x sin C - tan A x tan C)/sin B

= [(1/cos A) x sin C - tan A x tan C]/sin B (using sec A = 1/cos A)

= [(1/cos A) x (AB/BC) - (AC/AB) x (AB/AC)]/sin B (substituting sin C and tan C)

= [(AB/BCcos A) - (AC/BC)]/sin B (simplifying)

= [(AB/BC) - (ACcos A/BCcos A)]/sin B (getting a common denominator)

= [(AB - ACcos A)/BC]/sin B (simplifying)

= [(AB - ABsin A)/BC]/sin B (substituting sin A = AC/BC)

= [AB(1 - sin A)/BC]/sin B (factoring out AB)

= [(AB/BC) x (cos A/sin A)]/sin B (using sin A = opposite/hypotenuse and cos A = adjacent/hypotenuse)

= [cot A x (AB/BC)]/sin B (using cot A = cos A/sin A)

= (AB/BC) x (cos A/sin A) x (1/sin B) (multiplying fractions)

= (AB/BC) x (cos A/sin A) x csc B (using csc B = 1/sin B)

= (AB/BC) x cot A x csc B (using cot A = cos A/sin A)

= (BC/AB) x tan A x sin B (taking the reciprocal of both sides)

= (2BC/2AB) x (sin B/cos B) x (sin A/cos A) (multiplying and dividing by cos B and cos A)

= (BC/AB) x (2sin Bcos A)/(2sin A cos B) (simplifying)

= (BC/AB) x (sin (B + A)/sin (A + B)) (using sum and difference formulae)

= (BC/AB) x (sin C/sin 90) (since A + B + C = 90 degrees in a right-angled triangle)

= (BC/AB) x sin C

Substituting the given values, we get:

= [(2x + 20)/80] x AB

= (x/40) x AB

Therefore, the final answer is (x/40) x AB.

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The daily marginal revenue function associated with selling x widgets is given by R"(x) = -21x2 + 16x + 15 where R'(x) is measured in dollars per unit per day and x denotes the number of widgets produced and sold. (a) Determine the revenue function, R(x), associated with producing and selling x widgets. R(x) = (b) Determine the demand function relating unit price, p(x), to the quantity demanded, X. P(x)

Answers

The demand function relating unit price, p(x), to the quantity demanded, x, is: P(x) = -7x^2 + 8x + 15

(a) To determine the revenue function, we need to integrate the marginal revenue function R"(x).

R'(x) = -21x^2 + 16x + 15

Integrating R'(x) gives us the revenue function:

R(x) = -7x^3 + 8x^2 + 15x + C

where C is the constant of integration. Since we want to find the revenue associated with producing and selling x widgets, we can set C = 0.

Therefore, the revenue function associated with producing and selling x widgets is:

R(x) = -7x^3 + 8x^2 + 15x

(b) To determine the demand function, we need to use the inverse demand method.

First, we need to solve for the unit price, p(x), in terms of the quantity demanded, x. We know that revenue, R(x), is equal to the product of the unit price, p(x), and the quantity demanded, x:

R(x) = p(x) * x

Substituting the revenue function we found in part (a), we get:

-7x^3 + 8x^2 + 15x = p(x) * x

Solving for p(x), we get:

p(x) = (-7x^2 + 8x + 15)

Therefore, the demand function relating unit price, p(x), to the quantity demanded, x, is:

P(x) = -7x^2 + 8x + 15

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Helpppp (FIND THE LENGTH OF THE MAJOR ARC)

Answers

I believe the answer is 35

Answer:

290 degrees

Step-by-step explanation:

To find the length of the major arc subtracts 360-70.

You do this because angle LKM is a central angle, so the arc of LKM will be the same as the angle which is 70. If LKM was an inscribed angle the arc angles would be twice the degrees as the inscribed angle. And because arc LNM is a major arc and because a circle is 360 degrees all you have to do is subtract 70 from 360.

The image below shows an inscribed angle and a central angle.

the number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. a sample of 15 people is selected at random, and the number of hours worked per year per person is given below. calculate the 98% confidence interval for the mean hours worked per year in this state. round your answers to the nearest integer and use ascending order. time 2051 2061 2162 2167 2169 2171 2180 2183 2186 2195 2196 2198 2205 2210 2211 provide your answer below:

Answers

Using a t-distribution with 14 degrees of freedom (n-1) and a 98% confidence level (α = 0.02/2 = 0.01 for each tail), we have:

sample mean (x) = (2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)/15 = 2180.6

sample standard deviation (s) = 39

standard error of the mean (SEM) = s/√n = 39/√15 ≈ 10.077

t-score for a 98% confidence level and 14 degrees of freedom (from t-distribution table or calculator) = 2.977

Margin of error (ME) = t-score × SEM = 2.977 × 10.077 ≈ 30.05

Therefore, the 98% confidence interval for the mean hours worked per year in this state is:

(x- ME, x+ ME) = (2180.6 - 30.05, 2180.6 + 30.05) = (2150, 2211)

Rounding to the nearest integer and putting the limits in ascending order, we get:

(2150, 2211)

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helpppp fast i will give brainliest to best answer!!!
Explain why too!!

Answers

Answer:

Step-by-step explanation:

First get y byitself to oneside

[tex]2x-y\leq 5[/tex]

Subtract -2x to bothside

[tex]-y\leq 5-2x[/tex]

Divide -1 to make y positive. Dividing or Multiplying changes direction.

[tex]y\geq 2x-5[/tex]

y >= any value above the positive of the line.

Find the perimeter area and/or volume of the given figure

Answers

According to the information the volume of this figure would be 16cm³ and the surface area of this figure would be 24cm²

How to calculate the surface area and volume of this figure?

To calculate the surface area and volume of this figure we must perform the following procedure:

Volume:

Multiply height, width and length

2cm * 2cm *2cm = 16cm³

Surface area:

Multiply height by width and multiply the result by the number of faces the figure has.

2cm * 2cm = 4cm²

4cm² * 6 = 24cm²

According to the above, the volume of this figure is 16cm³ and the surface area is 24cm².

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Taylor Polynomial: Consider the approximation of the exponential by its third degree Taylor Polynomial: ex≈P3(x)=1+x+x^2/2+x^3/6
Compute the error e^x−P3(x) for various values of x.

Answers

The error between the exponential function e^x and its third degree Taylor polynomial P3(x) is given by e^x - P3(x).

Let's compute this error for various values of x:

For x = 0, we have e^0 - P3(0) = 1 - 1 = 0.

For x = 1, we have e^1 - P3(1) = e - (1 + 1 + 1/2 + 1/6) = e - 2.16667 ≈ -0.0803.

For x = -1, we have e^-1 - P3(-1) = 1/e - (1 - 1 + 1/2 - 1/6) = 0.581976 ≈ 0.582.

For x = 2, we have e^2 - P3(2) = e^2 - (1 + 2 + 4/2 + 8/6) = e^2 - 5.33333 ≈ 2.995.

For x = -2, we have e^-2 - P3(-2) = 1/e^2 - (1 - 2 + 4/2 - 8/6) = 0.133151 ≈ 0.133.

Overall, we can see that the error between the exponential function and its third degree Taylor polynomial decreases as x gets closer to 0. This is because the Taylor polynomial is centered at x = 0 and becomes a better approximation as x gets closer to the center. However, for larger values of x, the error can become quite significant.

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A recipe that makes s for 2/3 cup of flour how much flour is required to make 20 servings.

Answers

Answer:

14/13

Step-by-step explanation:

40/3

The number of values free to vary after certain restrictions have been placed on the data is the definition of O a confidence interval the central limit theorem degrees of freedom at score

Answers

We say that there are n-1 degrees of freedom in this case.

The number of values free to vary after certain restrictions have been placed on the data is the definition of degrees of freedom (df). Degrees of freedom are a key concept in inferential statistics and are often used in hypothesis testing and the calculation of confidence intervals. In essence, degrees of freedom represent the number of values in a data set that are free to vary after the mean has been calculated.

For example, if we have a sample of n observations and we know the mean of the sample, then we can calculate the sum of the n observations. However, we cannot set the value of the last observation, as it is determined by the values of the first n-1 observations and the mean. Therefore, we say that there are n-1 degrees of freedom in this case.

Degrees of freedom are also important in the calculation of standard errors, t-tests, and F-tests. In these cases, the degrees of freedom reflect the amount of information in the sample and are used to calculate the probability of observing a particular test statistic under the null hypothesis.

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what is meant by a marginal distribution? what is meant by a conditional distribution?

Answers

A marginal distribution refers to the distribution of one variable in a dataset without taking into account the other variables. It is the probability distribution of a single random variable. On the other hand, a conditional distribution refers to the distribution of one variable in a dataset given that another variable has a specific value. It is the probability distribution of a random variable, given that another random variable has a specific value. Marginal distributions are often used to calculate overall probabilities, while conditional distributions are used to calculate probabilities under specific conditions. Marginal and conditional distributions are important concepts in statistics and are used to analyze data and make predictions. In general, marginal distributions are useful when considering the overall distribution of a dataset, while conditional distributions are useful when considering the distribution of a dataset under specific conditions or circumstances.
Hi! A "marginal distribution" is meant to describe the probability distribution of a single variable in a multivariate setting, without considering the relationships with other variables. To find the marginal distribution, you sum or integrate the joint distribution over all possible values of the other variables.

A "conditional distribution," on the other hand, is meant to describe the probability distribution of a variable given the values of one or more other variables. In this case, you focus on a specific subset of the data where the given condition(s) hold true, and then calculate the probability distribution for the variable of interest within that subset.

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Other than translation, what transformation is used to create this frieze pattern?


180° rotation
vertical reflection
horizontal reflection
glide reflection

Answers

Other than translation, the other transformation used to create this frieze pattern is:

180° rotation

What is 180° rotation?

A 180-degree rotation is a transformation wherein an object or shape obtains a spin of half a full circle, indulging in the metamorphosis of facing the total opposite direction.

To demonstrate this more accurately, each point on the object must transition to a placement that is precisely polar to its primary site; centered by a fixed spot recognized as the axis of revolution.

A close examination of the pattern shows that it is not a reflection, hence making all the options of reflection unsuitable

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identify the type i error and the type ii error for a hypothesis test of the indicated claim. the percentage of adults who have a job is greater than 88%.

Answers

Type I Error: Concluding that the percentage of adults with jobs is greater than 88% when it is actually equal to 88%, Type II Error: Concluding that the percentage of adults with jobs is equal to 88% when it is actually greater than 88%

In a hypothesis test, a Type I error occurs when we reject a true null hypothesis. In the case of the indicated claim, this would mean rejecting the hypothesis that the percentage of adults who have a job is not greater than 88%, when in fact it is true. This would be a serious mistake as we would be making a false claim.

On the other hand, a Type II error occurs when we fail to reject a false null hypothesis. In this case, it would mean failing to reject the hypothesis that the percentage of adults who have a job is not greater than 88%, when in fact it is false. This error would lead us to miss the true claim that the percentage of adults who have a job is greater than 88%, which could have important implications for policy and decision-making.

Therefore, in the hypothesis test of the indicated claim, the Type I error would be to falsely claim that the percentage of adults who have a job is greater than 88%, while the Type II error would be to miss the true claim that it is indeed greater than 88%.

First, let's set up our null hypothesis (H0) and alternative hypothesis (H1):
- Null hypothesis (H0): The percentage of adults who have a job is equal to 88% (P = 0.88)
- Alternative hypothesis (H1): The percentage of adults who have a job is greater than 88% (P > 0.88)

Now, let's identify the Type I and Type II errors for this hypothesis test:

1. Type I Error: This occurs when we reject the null hypothesis (H0) when it is actually true. In this context, a Type I error would be concluding that the percentage of adults who have a job is greater than 88% (P > 0.88) when, in reality, it is equal to 88% (P = 0.88).

2. Type II Error: This occurs when we fail to reject the null hypothesis (H0) when it is actually false. In this context, a Type II error would be concluding that the percentage of adults who have a job is equal to 88% (P = 0.88) when, in reality, it is greater than 88% (P > 0.88).

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The graph below shows the value of the US dollar versus the Canadian dollar.

A graph titled Value of U S Dollar versus Canadian Dollar has month on the x-axis, from October 2012 to March 2013, and Canadian Dollars per U S Dollar on the y-axis, from 0.96 to 1.04. A line is drawn to connect the points on the graph. The line is at the lowest point in October, and it is the highest in March.

According to the graph, the American dollar was the strongest during which month?



October 2012.
November 2012.
February 2013.
March 2013.

Answers

Looking at the graph, the best time to make a purchase is in month March 2013.

Exchange rate refers to the value ascribed to a particular currency in a foreign currency.

We have to find on which month the  American dollar was the strongest

Usually, currency exchange rates are not static but depend on many factors.

As such, it is always advisable to carry out trading activities when the exchange rate between currencies is favorable.

Looking at the graph, the best time to make a purchase is in March 2013.

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Los brazos de un compás miden y forman un angulo de 40. Calcule el radio de la circunferencia que se puede trazar

Answers

The radius that can be traced with that opening will be 10.14cm

Given that arms of a compass, measure 12 cm, form an angle of 50 degrees, we need to find the radius of the circumference that can be drawn with that opening,

using the cosine theorem:

Assume that the compass forms a triangle, where sides c and b measure 12cm, we want to find outside a (which would be the radius sought), we have an angle that would be angle A.

Then the cosine theorem says:

a² = b² + c² - 2·b·c·cosA

a² = 12² + 12² - 2·12·12·cos50

a² = 102.88 (approximately)

a = 10.14cm (approximately)

Hence, the radius that can be traced with that opening will be 10.14cm

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The complete question :-

los brazos de un compas, miden 12 cm, forman un angulo de 50 grados ¿ cual es el radio de la circunferencia que puede trazarse con esa abertura?

The translation :-

The arms of a compass, measure 12 cm, form an angle of 50 degrees What is the radius of the circumference that can be drawn with that opening?

7. Classical or direct approach. Compare your t-statistic to thecritical value. Do you reject the null?8. Can you infer your results to the general population? Why orwhy not? How can you avoid biasDistributions Sobriety test seconds Confidence intervals Parameter Estimate Lower CI Upper CI 1- Alpha Mean 15.31333 9.557054 21.06961 0.950 Std Dev 10.39449 7.610086 16.39315 0.950 Quantiles 100.0% m 9. How can you improve on this experiment?

Answers

In the classical or direct approach, we compare the t-statistic from our experiment to the critical value from the t-distribution table. If the t-statistic is greater than the critical value, we reject the null hypothesis.

We cannot infer our results from the general population unless we have a representative sample. Even with a representative sample, there is always the potential for bias. To avoid bias, we can use random sampling and blind or double-blind experimental designs.

To improve on this experiment, we could increase the sample size to reduce sampling error and increase the power of the experiment. We could also use a control group to compare our results to a group that did not receive the treatment. Additionally, we could use a different statistical test or model to analyze the data or gather more variables to control for potential confounding factors.

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Calculate the area and circumference of a circle with diameter 8cm

Answers

area= 50.27
circumference= 25.13

a banker is interested in the percentage of banking customers who have a money market savings account. based on a recent banking newsletter, 50% of banking customers have a money market savings account. the banker believes this percent has decreased in recent months. if the banker wants to convert their test statistic to a probability, what is this called in hypothesis testing?

Answers

In hypothesis testing, converting a test statistic to a probability is called p-value. The p-value is the probability of obtaining a test statistic as extreme as the observed one or more extreme, assuming the null hypothesis is true.

If the p-value is less than the chosen level of significance, typically 0.05 or 0.01, the banker would reject the null hypothesis and conclude that there is evidence to support the alternative hypothesis, which is that the proportion of banking customers with a money market savings account has decreased. If the p-value is greater than the chosen level of significance, the banker would fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the proportion has decreased.

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all eight vertices of a unit cube are on a sphere (i.e. the cube is inscribed in the sphere). what is the surface area of the sphere?

Answers

To find the surface area of the sphere with a unit cube inscribed, we first need to determine the radius of the sphere. A unit cube has side length 1, and its vertices are at a distance of 1 unit from each other. Since all eight vertices of the cube are on the sphere, we can consider the longest diagonal of the cube to calculate the diameter of the sphere.

The longest diagonal of the cube can be calculated using the Pythagorean theorem in three dimensions: the square of the diagonal (d²) is equal to the sum of the squares of the side lengths (a² + b² + c²), where a, b, and c are the side lengths of the unit cube. In this case, a = b = c = 1. So, d² = 1² + 1² + 1² = 3. Thus, d = √3.

The diameter (d) of the sphere is equal to the longest diagonal of the cube. Therefore, the radius (r) of the sphere is half of the diameter: r = d/2 = √3/2.

Now that we have the radius, we can calculate the surface area (A) of the sphere using the formula: A = 4πr². Plugging in the radius, we get:

A = 4π(√3/2)² = 4π(3/4) = 3π.

So, the surface area of the sphere is 3π square units.

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Education: College Graduates - A local professor claims that college graduates in his program earn an annual salary of $53,500 or more in the first year after the completion of their master's degree. A rival university's faculty dispute that claim and claim that the actual value is less than that. A random sample of 20 program graduates found they earned an annual salary of $50,994 in the first year after the completion of their master's degree with a standard deviation of $521. Use a 5% error. What is the critical value for this problem? O-1.729 0-1.645 1.645 1.729

Answers

Since the rival university's faculty claim that the actual value is less than the professor's claim, we should use a one-tailed test (left-tailed) with a 5% error. For a one-tailed test with a 5% error, the critical value is:

-1.645

The critical value for this problem would be 1.729, as this corresponds to a 5% error level and a two-tailed test.
To explain further, we can use hypothesis testing to determine whether the claim made by the local professor is supported by the sample data.

H0: The true mean salary for college graduates in the program is equal to or less than $53,500.

And our alternative hypothesis as:

Ha: The true mean salary for college graduates in the program is greater than $53,500.

We can then use the sample mean and standard deviation to calculate the test statistic:

t = (sample mean - hypothesized mean) / (standard deviation / sqrt(sample size))
t = (50994 - 53500) / (521 / sqrt(20))
t = -2.01

Using a t-distribution table with 19 degrees of freedom (sample size minus 1), and a significance level of 0.05 (corresponding to a 5% error), we can find the critical value for a two-tailed test:

t_critical = +/- 2.093

Since our calculated test statistic falls outside of the critical value range, we can reject the null hypothesis and conclude that there is evidence to suggest that the true mean salary for college graduates in the program is less than $53,500. Therefore, the rival university's faculty may have a valid point in disputing the local professor's claim.
To find the critical value for this problem, we will use a one-tailed t-test since we want to test if the actual value is less than $53,500.

Given:
- Sample size (n) = 20 graduates
- Significance level (α) = 5% or 0.05
- Degrees of freedom (df) = n - 1 = 20 - 1 = 19

Now, let's find the critical value (t) using the t-distribution table. For a one-tailed test at a 5% significance level and 19 degrees of freedom, the critical value is -1.729.

So, the critical value for this problem is -1.729.

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suppose we wish to use the chi-squared test of independence to examine whether there is a relationship between two categorical variables. the contingency table we have has 3 rows and 7 columns, and we have a total sample size of 270. what degrees of freedom would we use, assuming we had a table big enough that would let us look up any value?

Answers

Therefore, we would use a chi-squared distribution with 12 degrees of freedom to conduct the hypothesis test of the sample.

The degrees of freedom for a chi-squared test of independence with a contingency table with r rows and c columns can be calculated as (r-1)(c-1). In this case, we have a contingency table with 3 rows and 7 columns, so the degrees of freedom would be (3-1)(7-1) = 12. A chi-squared test of independence is a statistical test used to determine if there is a relationship between two categorical variables. It is commonly used to analyze contingency tables, which are tables that display the frequency distribution of two or more categorical variables.

The degrees of freedom (df) for a chi-squared test of independence with a contingency table are calculated using the formula (r-1)(c-1), where r is the number of rows in the table and c is the number of columns.

In this case, we have a contingency table with 3 rows and 7 columns. Therefore, r = 3 and c = 7.

Substituting these values into the formula, we get:

df = (r-1)(c-1)

= (3-1)(7-1)

= 2 x 6

= 12

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The grams of fiber from 1,000 different breakfast cereals sold in the United States were collected.

Which graphical representation would be most appropriate for the data, and why?

Bar chart, because the data is categorical
Histogram, because there is a large set of data
Stem-and-leaf plot, because you can see the shape of the data
Line plot, because you can see the mode of the data

Answers

The most appropriate graphical representation for the grams of fiber from 1,000 different breakfast cereals sold in the United States is; Histogram, because there is a large set of data.

Since histogram is a graphical representation of the distribution of numerical data. This is consist of a series of adjacent rectangles, or bins, that are used to represent the frequency distribution of the data. The height of each bin corresponds to the number of data points that fall within a particular range or interval.

Hence, we have that each bin will represent the number of observations in an interval of grams of fiber.

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∠A and


∠B are vertical angles. If m


=
(
7


24
)

∠A=(7x−24)

and m


=
(
5

+
8
)

∠B=(5x+8)

, then find the value of x.

Answers

Based on the definition of vertical angles, the value of x is calculated as: x = 16.

What are Vertical Angles?

When two lines that are straight intersect each other at a point, they form two pairs of opposite angles which are referred to as vertical angles. These angles called vertical angles are congruent to each other.

We are given:

m∠A = (7x − 24)°

m∠B = (5x + 8)°

Given that angle A and angle B are vertical angles, therefore:

7x - 24 = 5x + 8

Combine like terms:

7x - 5x = 24 + 8

2x = 32

x = 16

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In a positively skewed distribution, what order (left to right) will we find the mean, median and more

Answers

So the order from left to right would be: Mode, Median, Mean.

In a positively skewed distribution, the mean is typically larger than the median, and the median is larger than the mode.

This can be illustrated in the following way:

Mean: The mean is affected by extreme values in the tail of the distribution, and will be pulled in the direction of the skew. Therefore, in a positively skewed distribution, the mean will be to the right of the median.

Median: The median is the value that separates the lower 50% of the data from the upper 50% of the data. In a positively skewed distribution, the tail of the distribution is on the right-hand side, which means that the median will be closer to the left-hand side than the mean.

Mode: The mode is the most frequent value in the distribution. In a positively skewed distribution, the mode will be the smallest value, located at the left-hand side of the distribution, while the mean and median will be to the right of it.

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Find the zeros of each function.
h(x) = 6x² + x − 1

Answers

The zeros of the function h(x) = 6x² + x − 1 are x = 1/3 and x = -1/2.

What are the zeros of the given function?

Given the function in the question:

h(x) = 6x² + x − 1

To determine the zeros of the function, we need to solve for x when h(x) equals zero.

Plug in h(x) = 0

0 = 6x² + x − 1

6x² + x − 1 = 0

We can use the quadratic formula to solve for x:

x = [-b ± √(b² - 4ac)] / 2a

where a, b, and c are the coefficients of the quadratic equation.

In the function, a = 6, b = 1, and c = -1.

Plug these values into the above formula

x = [-1 ± √(1² - 4(6)(-1))] / 2(6)

x = [-1 ± √(1 + 24)] / 12

x = [-1 ± √(25)] / 12

x = [-1 ± 5] / 12

Hence, the zeros of the function are:

x = (-1 + 5) / 12 = 4/12 = 1/3

and

x = (-1 - 5) / 12 = -6/12 = -1/2

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a bridge hand is defined as 13 cards selected at random and without replacement from a deck of 52 cards. in a standard deck of cards, there are 13 cards from each suit: hearts, spades, clubs, and diamonds. what is the probability of being dealt a hand that does not contain a heart?

Answers

In a standard deck of cards, there are 13 cards of each suit: hearts, spades, clubs, and diamonds. A bridge hand consists of 13 cards selected at random and without replacement. To calculate the probability of being dealt a hand that does not contain a heart, we need to find the total number of possible hands and the number of hands without any hearts.

There are 52 cards in total, but we're only interested in the 39 cards that are not hearts (13 spades, 13 clubs, and 13 diamonds). The number of ways to choose 13 cards from these 39 is calculated using combinations, denoted as C(n, r), where n is the total number of items and r is the number of items to choose. In this case, it's C(39, 13).

C(39, 13) = 39! / (13! * (39-13)!) = 8,122,425

Next, we need to find the total number of possible bridge hands, which is choosing 13 cards from a 52-card deck:

C(52, 13) = 52! / (13! * (52-13)!) = 635,013,559,600

Now, we can find the probability of a hand without any hearts by dividing the number of hands without hearts by the total number of possible hands:

Probability = (number of hands without hearts) / (total number of possible hands)
Probability = 8,122,425 / 635,013,559,600 ≈ 0.0128

Therefore, the probability of being dealt a hand that does not contain a heart is approximately 0.0128 or 1.28%.

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how many ways are there for 8 men and 5 women to stand in a line so that no two women stand next to each other?

Answers

Answer:

woman,man,woman,man,woman,man,woman,man,woman,man,man,man,man

Step-by-step explanation:

too easy

The number of taste buds a person has varies. There are three general classifications of​ taste: supertaster, medium​ taster, and nontaster. In one​ study, the number of women classified as supertasters was 3.25 times the number of men classified as supertasters. Suppose 65 women were classified as supertasters. Write an equation that represents the number of men x who were classified as supertasters.​ Then, solve the equation you wrote. How many men were classified as​ supertasters?

Answers

There were 20 mens that classified as supertasters.

We will use the unitary method which is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

we have been told that the number of women was 3.25 times the number of men. Therefore,

Number of women = 3.25 m

Since there are 65 women, the number of men will be:

3.25 m = 65

Men = 65/ 3.25

Men = 20

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