In ΔTUV, the measure of ∠V=90°, the measure of ∠T=52°, and UV = 7 feet. Find the length of VT to the nearest tenth of a foot.

Answer:

5.5 feet

Step-by-step explanation:

Answer:

5.5 feet

Step-by-step explanation:

We have VT adjacent to angle T.

We know that VU, side length that is opposite to T, is 7.

We use the TAN function, which is opposite/adjacent, on T :)

tan(52) = 7/x

x tan(52) = 7

x = 7/tan(52) =~ that's around 5.469 --> 5.5 feet

YAS

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