In downtown Chicago, the east-west blocks are 400 ft long while the north-south blocks are 280 ft long. Because of the many one-way streets, it can be challenging to get around. Veronica starts at the corner of Dearborn and Ohio Streets. She drives four blocks north to Superior, two blocks east to Wabash, then a block south to get to her destination at Wabash and Huron.

Required:
What is the straight-line distance from her starting point?

Answer:

energy level

s,p

electrons

Explanation:

I already done this trust me

In the notation 1 s² number 1 represents energy levels where electrons are located.The 4 parts on periodic table are s,p,d and f blocks.The 2 in 1 s² represents number of electrons in energy level.

Electrons present in an atom revolve in different orbits which are stationary states and are also called as energy levels. The energy levels are numbered as integers which are also called as principal quantum numbers.

Energy of the stationary state is given as E= -R

1/n² where R

is the Rydberg's constant. When an electron is excited, and it moves from lower to higher energy levels there is absorption of energy, while when it moves from higher energy level to lower energy level it radiates or gives out energy in the form of radiation.

They can also be defined as the distances between electron and nucleus of an atom . Electrons present in K energy level have least energy .Energy level diagrams are studied to understand nature of bonding , placement of electrons in orbits and and elemental behavior under certain conditions.

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Answer:

d = 0.25 mm

Explanation:

The position that the Minimal fall in single silt diffraction pattern can be written as

y=λmD/d ..........eqn(1)

(y2 - y1 )= difference of y that exist between first and second minima

D= distance of slit from the screen=1.50m

d= width of the slit

λ= 633 nm = 633×10^-9m

y= position of pth minimal

eqn(1) can be written as

(y2 - y1)= λmD/d .........eqn(2)

If we substitute the given values we have

(y2 - y1 )= [ (2×633×10^-9 × 1.50) /d] -[ (1×633×10^-9 × 1.50) /d]

Simplyfying

(y2 - y1)=(9.495×10^-7)/d

But The distance between the first and second minima in the diffraction pattern = 3.75, which implies that (y2 - y1) = 3.75mm=

✓ we can substitute (y2 - y1)= 3.75mm=3.75 ×10^-3 into expression above

3.75 ×10^-3 =(9.495×10^-7)/d

The we can make "d" subject of the formula

d=(9.495×10^-7)/ (3.75 ×10^-3)

d=0.00025m

d=0.25×10^-3 m

d=0.25 mm

Hence, the width (in mm) of the slit is 0.25mm

Answer:

I) True,  II) False,  III) False,  IV) True    

Explanation:

In this exercise, it is asked to answer different statements, for this we will use the relationship between angular and linear velocity

           v = w r

let's review the claims

I) True. From the initial equation we see that the linear velocity depends on the radius

II) False. All points rotate with the same angular velocity

III) False. Linear velocity changes with radius

IV) True. The angular velocity of all points is the same

At various radial points on a rotating Ferris wheel have, different linear velocity (True), different angular velocity (false), equal linear velocity (false) and equal angular velocity (True).

The angular velocity of a rotating Ferris is calculated as follows;

[tex]\omega = \frac{v}{r} = 2\pi N[/tex]

The linear velocity of a rotating Ferris is calculated as follows;

v = ωr

where;

The linear velocity increases with increase in radius.

Thus, we can conclude that, at various radial points on a rotating Ferris wheel have;

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Answer:

C. the top line represents a greater velocity

Explanation:

The graph is a distance - time graph.

The distance is on the y-axis and time is on the x - axis.

For this graph, the slope is the velocity.

The lower line is not so steep and its slope is lesser compared to the upper one.

Answer:

1 Answer. The Periodic Table can predict the properties of new elements, because it organizes the elements according to their atomic numbers. Creating new elements is not a simple process. Scientists use a particle accelerator to smash light atoms into a thin metallic foil that contains heavier atoms.

Explanation:

Answer:

The correct answer to the question will be compass i.e compass is not a part of a DC motor. Various parts of a DC motor are coil of wire, armature, field magnets, brushes and commutator. The coil of wire plays a vital role in DC motor.

Explanation:

Answer:

  58.9 N [W24.8°N]

Explanation:

The vectors are at right angles, so the magnitude of their sum is ...

  √(38² +45²) ≈ 58.9 . . . . newtons

The angle Fc makes with Fa can be found using the arctangent:

  angle between Fa and Fc = arctan(45/38) ≈ 49.8°

The direction required for the sum of the vectors to be zero is the opposite of [E(49.8° -25°)S], so is [W24.8°N]

The vector that makes the sum zero is 58.9 N [W24.8°N].

Answer:

The specific charge is defined as a charge by mass ratio i.e e/m. The charge on an electron (e) = 1.602 X 10-19C. The mass of the electron (m) = 9.1×10−31Kg.

Answer:

a = 0.009 J

b = 0.19 m/s

c = 0.005 J and 0.004 J

Explanation:

Given that

Mass of the object, m = 0.5 kg

Spring constant of the spring, k = 20 N/m

Amplitude of the motion, A = 3 cm = 0.03 m

Displacement of the system, x = 2 cm = 0.02 m

a

Total energy of the system, E =

E = 1/2 * k * A²

E = 1/2 * 20 * 0.03²

E = 10 * 0.0009

E = 0.009 J

b

E = 1/2 * k * A² = 1/2 * m * v(max)²

1/2 * m * v(max)² = 0.009

1/2 * 0.5 * v(max)² = 0.009

v(max)² = 0.009 * 2/0.5

v(max)² = 0.018 / 0.5

v(max)² = 0.036

v(max) = √0.036

v(max) = 0.19 m/s

c

V = ±√[(k/m) * (A² - x²)]

V = ±√[(20/0.5) * (0.03² - 0.02²)]

V = ±√(40 * 0.0005)

V = ±√0.02

V = ±0.141 m/s

Kinetic Energy, K = 1/2 * m * v²

K = 1/2 * 0.5 * 0.141²

K = 1/4 * 0.02

K = 0.005 J

Potential Energy, P = 1/2 * k * x²

P = 1/2 * 20 * 0.02²

P = 10 * 0.0004

P = 0.004 J

The total energy of the system is 0.009 J

The maximum speed of the object is 0.19 m/s

The kinetic and potential energies of the system when the displacement is 2.00 cm are 0.005 J and 0.004 J respectively

The object is under simple harmonic motion.

Given that the mass of the object m =0.5 kg , spring constant k = 20N/m

(a) The total energy of the system in SMH,

[tex]E=\frac{1}{2}kA^2[/tex]

If the amplitude of motion A = 3cm = 0.03m, then total energy

[tex]E=\frac{1}{2}*20*0.03*0.03 J\\\\E = 0.009J[/tex]

E = 0.009J is the total energy of the system.

(b) maximum speed of the object

the maximum kinetic energy of the object = total energy of the object

[tex]\frac{1}{2} m(v_{max})^{2} =E\\\\v_{max}=\sqrt{2E/m}\\\\v_{max}=\sqrt{2*0.009/0.5}\\\\v_{max}=0.19m/s[/tex]

0.19 m/s is the maximum speed

(c) KE and PE when x = 2cm = 0.02m

potential energy at x = 0.02

[tex]PE=\frac{1}{2}kx^2\\\\PE=\frac{1}{2}*20*0.02*0.02\\\\PE= 0.004J[/tex]

Now, Kinetic energy + potential energy = total energy

KE + PE = E

KE = E - PE

KE = 0.009J - ).004J

KE = 0.005J

The kinetic and potential energies are 0.005 J and 0.004 J respectively.

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Answer:

false

Explanation:

i just took the test <3

The period of a pendulum is not directly proportional to the mass of the bob. The period of pendulum is independent of the mass of the bob. Thus, the given statement is false.

A simple pendulum is the one which consists of a small metal ball called as the bob or a mass which is suspended from a fixed point by a long piece of thread such that the bob is free to swing back and forth from its mean position under the influence of the gravity.

The time period of a simple pendulum is the time taken by it to complete one oscillation. The formula for the time period or period (T) of a simple pendulum is T = 2π (√L/g), where L is the length of the pendulum thread and g is the acceleration due to gravity.

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Explanation:

We need to use the conservation of energy to help us solve this one.

The energy imparted onto the bullet projectile is equal to the energy imparted into the recoiling gun. We can ignore potential energy and only consider the kinetic energy of the two masses (bullet and gun).

Remember that kinetic energy is expressed as [tex]K_E = \frac{1}{2}mv^2[/tex]

Conservation of energy means that both the gun and the bullet have the same amount of energy.

[tex]\frac{1}{2}m_gv_g^2 = \frac{1}{2}m_b v_b^2[/tex]

We'll want to put the mass terms into the same units. So the gun has a mass of 2340 grams.

Answer: F = 6262.2 kN

Explanation: Pressure is defined as force per area. But pressure varies according to the depth of a fluid: in air, it decreases the higher the altitude, while in water, it increases the deeper you go.

So, at the bottom of the tank, besides the pressure of air inside the tank and air outside the tank, there is pressure of water due to its depth.

Pressure due to the depth is calculated as

                                    [tex]P=h.\rho.g[/tex]

h is the depth in m

ρ is density of the fluid, in this case is water, so ρ = 997 kg/m³

g is acceleration due to gravity, which, in this case, is 3.71 m/s²

Then, pressure at the bottom of the tank due to variation in depth is

[tex]P=14.4(997)(3.71)[/tex]

P = 53263.73 Pa or 53.26 kPa

Assuming positive referential is downward, all pressures at the bottom point down, so total or resultant pressure is:

[tex]P_{r}=P_{1}+P_{2}+P_{3}[/tex]

[tex]P_{r}=150+88+53.26[/tex]

[tex]P_{r}=[/tex] 291.26 kPa

At last, pressure is force per area:

[tex]P=\frac{F}{A}[/tex]

[tex]F=P.A[/tex]

[tex]F_{r}=P_{r}.A[/tex]

[tex]F_{r}=291.26.10^{3}(2.15)[/tex]

[tex]F_{r}=[/tex] 626209 N or 626.2 kN

At the cylindrical tank's flat bottom, net force has magnitude 626.2 kN.

Answer:

1: E

2: A

3: C

4: B

5: D

Explanation:

1.

6090 J

2.

622 J

I bet so~

Answer:

Explanation:

Given;

electric field, E = 480 N/C

mass of electron, Me = 9.11 x 10⁻³¹ kg

mass of proton, Mp = 1.67 x 10⁻²⁷ kg

time of motion, t = 48.4 ns = 48.4 x 10⁻⁹ s

initial velocity of the particles, u = 0 (initially at rest)

let the speed of each particle after 48.4 ns = v

the magnitude of charge of the particles, q = 1.6 x 10⁻¹⁹ C

The force experienced by each particle is calculated as;

F = Eq

F = (480 N/C) x (1.6 x 10⁻¹⁹ C)

F = 7.68 x 10⁻¹⁷ N

The speed of each particle after 48.4 ns is calculated as;

[tex]F = ma\\\\F = \frac{m(v-u)}{t} \\\\F = \frac{m(v-0)}{t}\\\\F = \frac{mv}{t} \\\\mv = Ft\\\\v = \frac{Ft}{m} \\\\For \ electron;\\\\v_e = \frac{Ft}{m_e} \\\\v_e = \frac{7.68 \times 10^{-17} \ \times \ 48.4 \times 10^{-9}}{9.11 \times 10^{-31}} \\\\v_e = 4.08 \times 10^6 \ m/s[/tex]

[tex]For \ proton;\\\\v_p = \frac{Ft}{m_p} \\\\v_p = \frac{7.68 \times 10^{-17} \ \times \ 48.4 \times 10^{-9}}{1.67 \times 10^{-27}} \\\\v_p = 2,225 .82 \ m/s[/tex]

Answer:

Mean distance = 1.61 x 10^8 km

Explanation:

Given the following data;

Orbital period for Icarus, T2 = 410 days

To find the mean distance of Icarus, we would use Kepler's third law of motion.

According to Kepler's third law of planetary motion, the square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.

Mathematically, it is given by the formula;

[tex] (\frac {T_{1}}{T_{2}})^2 = (\frac {r_{1}}{r_{2}})^3 [/tex]

Where;

T1 & T2 is the orbital period of a planetary object.

r1 & r2 is the mean distance of a planetary object.

Also, we know that the orbital period for earth, T1 = 365 days

Mean distance of earth = 1.49x10^8 km

Substituting into the equation, we have;

[tex] (\frac {365}{410})^2 = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]

[tex] (\frac {365}{410}})^2 = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]

[tex] (0.8902)^2 = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]

[tex] (0.7925) = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]

Cross-multiplying, we have;

[tex] (r_{2})^3 = \frac {1.49x10^{8}}{0.7925} [/tex]

Taking the cube root of both sides;

[tex] r_{2} = 1.61 * 10^8 km[/tex]

Answer:5,880

Explanation:Lol if I get this wrong sorry I’m trying to do this also but if you add the 1,764 joules and 4,116 joules in total if you add them all up it’ll give you 5,880 hope that helps.

Answer:

138 km

Explanation:

Answer:

A

Explanation:

Answer:

physical quantity is a property of a material or system that can be qualified by measurement

[tex] \huge\mathfrak{ANSWER}[/tex]

the quantities by meals of which we describe the law of physics are known as physical quantities.

in order to measure a physical quantity we as you my certain magnitude of this quantity a standard and call its unit of that quantity to express the measurement of any physical quantity two thing must be mentioned.

For Example -:

[tex] \bold{ n_1 (u_1) = n_2(u_2)}[/tex]

Answer:

A) 10.0 m/s

Explanation:

the formula for average speed is  v=d/t

the distance is 100 meters

The time is 10.0 seconds

so  v=100m/10.0s

       = 10.0m/s

so the runners average speed was 10.0m/s

The average speed of the runner is equal to 10.0 m/s. Therefore, option (A) is correct.

The speed of a body can be described as the distance covered in a definite time interval. The average speed can be defined as a scalar parameter as it possesses magnitude with no direction.

The speed can be determined from the ratio of the distance traveled by the object to the time taken to travel that distance.

The speed of any object can be calculated from the formula equation mentioned below:

Speed =  total distance /time taken

Given, the distance covered by the runner = 100 m

The time taken by the runner, t = 10.0 s

The average speed of the runner can be calculated from the formula as shown below:

Speed = 100/10 = 10 m/s

Therefore, the average speed of the runner is 10.0 m/s.

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Answer:

first balance hydrogen.

Explanation:

2H2+O2---->2H2O

Answer:

2H^2 + 2H^2O

Explanation:

Put a 2 in front of both H's and the H's will be 4 and the O's will be 2. The chemical equation is balanced.

Answer: it will take 1000 guitar players for sound intensity level to be 100 dB

Explanation:

Given that;

noise level of a single player = 70 dB

Intensity of one guitar will be;

SL= 10 × log(I/I₀)

where I₀ is hum threshold intensity = 10⁻¹² W/m²

I is intensity of sound produced by 1 guitar

SL is intensity level of one guitar

so we substitute

70 = 10 × log(I/10⁻¹²)

70/10 = log (I/10⁻¹²)

I = 10⁻¹² × 10⁷

I = 10⁻⁵ W/m²  

now Suppose n guitars produce sound intensity of 100 dB, then intensity of n guitars (In) will be;

100 = 10 × log(In/10⁻¹²)

log(In/10⁻¹²)  = 100/10

In = 10⁻¹² × 10¹⁰ =  10⁻² Wm²

we know that Now intensity of 1 guitar I = 10⁻⁵ W/m²

so Intensity of n guitars will be;

n × I = In

n = In / I

we substitute

n = 10⁻² Wm² /  10⁻⁵ W/m²

n = 1000

Therefore, it will take 1000 guitar players for sound intensity level to be 100 dB

Answer:

Power = 2.5 [W]

Explanation:

To be able to solve this problem we must remember that power is defined as the relationship of the work done in a given time interval.

[tex]P=W/t[/tex]

where:

P = power [W] (units of watts)

W = work = 50 [J]

t = time = 20 [s]

Now replacing:

[tex]P=50/20\\P=2.5[W][/tex]

Answer:

2.5

Explanation:

Answer:

Gravitational force

Explanation:

Hope this helps :)

Answer:

Resistance of A is [tex]6\ \Omega[/tex] and B is [tex]3\ \Omega[/tex]

Explanation:

The voltage across both the resistances will be the same as they are connected in parallel.

V = Voltage = 6 V

[tex]I_B=2\ \text{A}[/tex]

Resistance is given by

[tex]R_B=\dfrac{V}{I_B}\\\Rightarrow R_B=\dfrac{6}{2}\\\Rightarrow R_B=3\ \Omega[/tex]

[tex]V_B=V_b-V_A\\\Rightarrow V_B=6-4\\\Rightarrow V_B=2\ \text{V}[/tex]

Series connection

[tex]V_A=4\ \text{V}[/tex]

The current is constant in series connection

[tex]I=\dfrac{V_B}{R_B}\\\Rightarrow I=\dfrac{2}{3}\ \text{A}[/tex]

[tex]R_A=\dfrac{V_A}{I}\\\Rightarrow R_A=\dfrac{4}{\dfrac{2}{3}}\\\Rightarrow R_A=6\ \Omega[/tex]

The resistance of A is [tex]6\ \Omega[/tex] and B is [tex]3\ \Omega[/tex].

Explanation:

if u apply more force to an object, it accelerates at a higher rate

Given :

Charge on glass bead, Q = 8 nC .

To Find :

The magnitude of the electric field 2.0 m from the center of the bead.

Solution :

Electric field at position r is given by :

[tex]E = \dfrac{kQ}{r^2}\\\\E = \dfrac{9\times 10^9\times 8\times 10^{-9}}{2^2}\\\\E = 18\ N/C[/tex]

Therefore, the magnitude of the electric field 2.0 m from the center of the bead is 18 N/C .