In an Hfr x F cross pro+ enters as the first known marker, but the order of the other markers is unknown. If the Hfr is wild-type and the F is auxotrophic for each marker in question, what is the order of the markers in a cross where prot recombinants are selected if 43% are thrt, 4% are thi+ 18% are ilet, and 70% are met+? (20 marks)

Answers

Answer 1

The order of the markers in a cross where prot recombinants are selected if 43% are thrt, 4% are thi+ 18% are ilet, and 70% are met+ are ile, met, thr, and thi+.Hence, the correct option is (D) ile, met, thr, and thi+.

In an Hfr x F cross pro+ enters as the first known marker, but the order of the other markers is unknown. If the Hfr is wild-type and the F is auxotrophic for each marker in question, the order of the markers in a cross where prot recombinants are selected if 43% are thrt, 4% are thi+ 18% are ilet, and 70% are met+ are ile, met, thr, and thi+.Hfr stands for high frequency of recombination. F stands for the fertility factor. This means that when an F factor integrates into the chromosome of an E. coli cell, it will produce an Hfr cell. An Hfr x F cross occurs when an F- cell is mated with an Hfr cell that has an F factor integrated into its chromosome. Pro+ is a selectable marker that identifies the recombinant cells. Pro+ is a marker that stands for proline auxotrophs and is the first marker. It allows for the selection of proline prototrophic recombinants. The following are the percentages of recombinants:43% are thr+4% are thi+18% are ile+70% are me t+ Since the order of the markers is unknown, we can’t assume anything about the order of these markers.

Learn more about recombinants  here:

https://brainly.com/question/30867571

#SPJ11


Related Questions

A suspension of bacteriophage particles was serially diluted, and 0.1 mL of the final dilution was mixed with E. coli cells and spread on the surface of agar medium for plaque assay. Based on the results below, how many phage particles per mL were present in the original suspension?
Dilution factor
Number of plaques
106
All cells lysed
107
206
108
21
109
0

Answers

The solution to the given problem is:Given that a suspension of bacteriophage particles was serially diluted, and 0.1 mL of the final dilution was mixed with E. coli cells and spread on the surface of agar medium for plaque assay.

The table given below shows the number of plaques and the dilution factor.Number of plaquesDilution factor106All cells lysed10720610821Now, for finding the number of phage particles per mL in the original suspension, we need to use the formula as shown below:Formula to find the number of phage particles per mL = Number of plaques × 1/dilution factor.

Step 1: For the first dilution, the dilution factor is 106 and all cells are lysed.Hence, the number of phage particles present in the original suspension = 106 × 1/106= 1 phage particle/mLStep 2: For the second dilution, the dilution factor is 107, and the number of plaques formed is 206.Hence, the number of phage particles present in the original suspension = 206 × 1/107= 1.93 phage particles/mLStep 3: For the third dilution, the dilution factor is 108, and the number of plaques formed is 21.Hence, the number of phage particles present in the original suspension = 21 × 1/108= 0.194 phage particles/mLStep 4: For the fourth dilution, the dilution factor is 109, and no plaques are formed.Hence, the number of phage particles present in the original suspension = 0 × 1/109= 0 phage particles/mLTherefore, the original suspension contained 1 phage particle/mL + 1.93 phage particles/mL + 0.194 phage particles/mL + 0 phage particles/mL= 2.124 phage particles/mL.

To know more about bacteriophage visit:

https://brainly.com/question/29409301

#SPJ11

What is the most common cause of familial hypercholesterolemia (FH)? Why do people with FH have high levels of LDL cholesterol?

Answers

Familial hypercholesterolemia (FH) is most commonly caused by a genetic mutation that affects the liver's ability to remove low-density lipoprotein (LDL) cholesterol from the bloodstream.

As a result, people with FH have high levels of LDL cholesterol because their bodies cannot remove it effectively.

Familial hypercholesterolemia (FH) is an inherited condition that causes very high levels of LDL cholesterol in the blood. LDL cholesterol, often known as "bad" cholesterol, is a type of cholesterol that can clog arteries, increasing the risk of heart disease and stroke. FH is caused by a genetic mutation that affects the body's ability to clear LDL cholesterol from the bloodstream.

As a result, people with FH have high levels of LDL cholesterol, which can cause cholesterol build up in the arteries and an increased risk of cardiovascular disease. Familial hypercholesterolemia (FH) is caused by a genetic mutation that affects the liver's ability to remove LDL cholesterol from the bloodstream. This mutation is usually inherited from one parent and is present from birth.

The majority of people with familial hypercholesterolemia (FH) do not have any symptoms, and the condition is frequently detected during routine cholesterol testing. In some people, however, there may be physical signs of cholesterol build up, such as yellowish patches on the skin (xanthomas) or the development of cholesterol-filled lumps under the skin (xanthelasmas).

People with FH are more likely to develop heart disease at a young age and have a higher risk of heart attacks, strokes, and other cardiovascular problems. For this reason, early detection and treatment are critical in managing the condition and reducing the risk of complications.

To know more about hypercholesterolemia visit:

https://brainly.com/question/1145024

#SPJ11

Question 11 You are presented with the challenge of designing a new lie detector test. You know that some lies can be detected when the sympathetic nervous system is activated while the subject appear

Answers

To design a lie detector test based on the activation of the sympathetic nervous system while the subject appears calm, we can utilize a combination of physiological measurements and behavioral observations.  By combining physiological measurements with behavioral observations, a lie detector test can be designed to detect lies based on the activation of the sympathetic nervous system while the subject appears calm.

Physiological Measurements: Measure physiological responses that are indicative of sympathetic nervous system activation. This can include monitoring heart rate, blood pressure, respiration rate, and skin conductance (electrodermal activity). Changes in these parameters are often associated with heightened arousal and stress response.

Baseline Assessment: Before beginning the questioning phase, establish a baseline for each physiological measure by asking neutral or non-threatening questions. This baseline will serve as a comparison point for detecting deviations during the questioning phase.

Questioning Phase: Ask specific questions designed to elicit a deceptive response. It is important to include control questions that are unrelated to the main issue being investigated. Control questions help establish a reference for the subject's physiological responses during truthful responses.

Observation of Behavior: While monitoring physiological responses, closely observe the subject's behavioral cues. Look for signs of discomfort, avoidance of eye contact, fidgeting, or other non-verbal indicators of stress or anxiety.

Data Analysis: Analyze the physiological data collected during the questioning phase. Look for significant changes or deviations from the baseline measures, especially in response to the deceptive questions. Increases in heart rate, blood pressure, respiration rate, or skin conductance above the established baseline could indicate a potential lie.

It is important to note that a lie detector test based on physiological responses is not foolproof and can be influenced by factors such as anxiety, fear, or other physiological conditions. Therefore, it is crucial to interpret the results cautiously and consider them in conjunction with other evidence or information gathered through additional means.

Learn more about nerves here:

https://brainly.com/question/33351608

#SPJ11

Question 11: You are presented with the challenge of designing a new lie detector test. You know that some lies can be detected when the sympathetic nervous system is activated while the subject appears calm. Explain how you would design a lie detector test based on this information.

1. What are the single-letter and three-letter abbreviations for pyrrolysine? . Below are schematics of synthetic human proteins. Colored boxes indicate signal sequences. SKL, KDEL and KKAA are actual amino acid sequences. Answer the questions 2 to 6. (1) SKL (2) KDEL (3) KKAA (4) MTS (5) MTS GPI (6) MTS (7) SP KKAA (8) SP (9) SP (10) SP GPI (11) SP KDEL (12) SP SKL 2. Find all proteins that would be localized to the peroxisome. 3. Find all proteins that would be localized to the nucleus. 4. Find all proteins that would be associated with the cytoplamic membrane. 5. Find all proteins that would be targeted either to the lumen or membrane of the endoplasmic reticulum 6. Find all proteins that would be released from the cell. NLS NLS TM NLS TM

Answers

The single-letter and three-letter abbreviations for pyrrolysine are O and Pyl, respectively. Proteins are significant biomolecules that are present in living organisms. They have a wide range of functions that are critical to life, including catalyzing metabolic reactions, replicating DNA, and responding to stimuli, among other things.

What are proteins?

Proteins are composed of chains of amino acids that are connected by peptide bonds, with each chain of amino acids having a unique sequence of amino acids. Proteins can be targeted to different regions of the cell with the help of signal sequences. These signal sequences, which are usually short peptides at the amino or carboxyl terminus of the protein, serve as a "Zipcode" for the protein, allowing it to be sorted and delivered to its proper location within the cell.

Answers:2. Proteins that would be localized to the peroxisome: (4) MTS (5) MTS GPI (6) MTS3. Proteins that would be localized to the nucleus: (7) SP KKAA (8) SP (9) SP (10) SP GPI (11) SP KDEL (12) SP SKL4. Proteins that would be associated with the cytoplasmic membrane: (4) MTS (5) MTS GPI (6) MTS5. Proteins that would be targeted to the lumen or membrane of the endoplasmic reticulum: (3) KKAA (7) SP KKAA (8) SP (9) SP (10) SP GPI (11) SP KDEL (12) SP SKL6. Proteins that would be released from the cell:

(7) SP KKAA (8) SP (9) SP (10) SP GPI (11) SP KDEL (12) SP SKL

The single-letter and three-letter abbreviations for pyrrolysine are O and Pyl, respectively.

To know more about metabolic reactions visit:

https://brainly.com/question/3406551

#SPJ11

Which of the following can occur in the presence of oxygen? 1) neither glycolysis nor cellular respiration 2) glycolysis and not cellular respiration 3) cellular respiration and not glycolysis 4) both glycolysis and cellular respiration

Answers

Both glycolysis and cellular respiration can occur in the presence of oxygen. Option 4 is correct answer.

Glycolysis is the initial step in the breakdown of glucose to produce energy. It occurs in the cytoplasm and can take place both in the presence and absence of oxygen. During glycolysis, glucose is converted into two molecules of pyruvate, resulting in the production of a small amount of ATP and NADH.

Cellular respiration, on the other hand, is the process that follows glycolysis and occurs in the mitochondria. It involves the complete oxidation of glucose and the production of ATP through oxidative phosphorylation. Cellular respiration includes two main stages: the citric acid cycle (also known as the Krebs cycle) and the electron transport chain. Both of these stages require oxygen as the final electron acceptor.

In the presence of oxygen, glycolysis is followed by cellular respiration. Pyruvate, the end product of glycolysis, enters the mitochondria and undergoes further oxidation in the citric acid cycle. This generates more ATP, along with NADH and FADH2, which then enter the electron transport chain to produce a large amount of ATP through oxidative phosphorylation.

Therefore, in the presence of oxygen, both glycolysis and cellular respiration can occur, leading to the efficient production of ATP for cellular energy needs.

Learn more about glycolysis here

https://brainly.com/question/30632236

#SPJ11

Question 3 2 pts Which of the following pieces of evidence are used to construct a cloudogram? Choose all that apply. anatomy behavior geography 0 fossils mitochondrial genes nuclear genes

Answers

The evidence used to construct a cloudogram includes anatomy, behavior, geography, mitochondrial genes, and nuclear genes.

Therefore, the correct options are: AnatomyBehaviorGeography Mitochondrial genesNuclear genesCloudogram is a type of phylogenetic tree, used to depict the evolutionary relationships among a group of species. The cloudogram doesn't focus on any specific trait, but instead considers all the available evidence together. This method of constructing evolutionary trees includes many types of evidence like behavioral similarities, geographic location, genetic information, and anatomical features.

Learn more about cloudogram here:

https://brainly.com/question/14826967

#SPJ11

1. Describe the advantages to bacteria of living in a biofilm
2. Explain the relationship between quorum sensing and biofilm formation and maintenance

Answers

Advantages to bacteria of living in a biofilm.Biofilm has a number of advantages for bacteria. Biofilm is a surface-associated group of microorganisms that create a slimy matrix of extracellular polymeric substances that keep them together. The following are some of the benefits of living in a biofilm:Prevents Detachment: Biofilm protects bacteria from detachment due to fluid shear forces.

By sticking to a surface and producing a protective matrix, bacteria in a biofilm can prevent detachment from the surface.Protects from Antibiotics: Biofilm provides a protective barrier that inhibits antimicrobial activity. Bacteria in a biofilm are shielded from antimicrobial agents, such as antibiotics, that may otherwise be harmful.Mutual Support: The bacteria in a biofilm benefit from mutual support. For example, some bacteria can produce nutrients that others need to grow.

The biofilm matrix allows the transfer of nutrients and other substances among bacteria.Sharing of Genetic Material: Bacteria can swap genetic material with other bacteria in the biofilm. This exchange enables the biofilm to evolve rapidly and acquire new traits.Relationship between quorum sensing and biofilm formation and maintenanceQuorum sensing (QS) is a signaling mechanism that bacteria use to communicate with each other. It allows bacteria to coordinate gene expression and behavior based on their population density. Biofilm formation and maintenance are two processes that are influenced by QS. QS plays a significant role in the following two phases of biofilm development:1.

Biofilm Formation: Bacteria in a biofilm interact through signaling molecules known as autoinducers. If the concentration of autoinducers exceeds a certain threshold, it signals to the bacteria that they are in a group, and it is time to start forming a biofilm. Bacteria may use QS to coordinate the production of extracellular polymeric substances that are essential for biofilm formation.2. Biofilm Maintenance: QS is also critical for maintaining the biofilm structure. QS signaling molecules are used to monitor the population density within the biofilm. When the bacteria in the biofilm reach a particular threshold density, they begin to communicate with one another, triggering the production of matrix-degrading enzymes that break down the extracellular matrix. This process enables the bacteria to disperse and colonize other locations.

To know more about microorganisms visit:

https://brainly.com/question/9004624

#SPJ11

On average, over a long period of time genetic drift in a population will heritability of a trait. increase O decrease o not change change only the neutral alleles affecting O change only the additive

Answers

the effect of genetic drift on the heritability of a trait depends on the size of the population, the strength of selection, and other factors that can affect genetic variation. However, in general, genetic drift tends to reduce the heritability of a trait over time.

On average, over a long period of time, genetic drift in a population will cause the heritability of a trait to decrease. This is because genetic drift is a random process that can cause changes in allele frequencies in a population that are not related to the fitness or adaptability of those alleles.

In other words, genetic drift is a non-selective process that can lead to the loss of beneficial alleles and the fixation of harmful ones. As a result, genetic variation in a population can be reduced over time due to genetic drift, which in turn can reduce the heritability of a trait.

To know more about heritability visit:

https://brainly.com/question/29116728

#SPJ11

The ____ is a protruding area above the eyes found in many archaic human species. This is a feature that modern humans no longer have. supraorbital torus O occipital torus O mandibular condyle a chin"

Answers

The correct answer to the given question is "supraorbital torus."

The supraorbital torus is a ridge-like bulge positioned above the orbits of the eyes and is a distinguishing characteristic of archaic humans. It was formed by the thickening of the frontal bone's bony ridge.

This ridge, which covers the orbits' upper border, gives the skull a pronounced eyebrow appearance and protects the eyes. However, in modern humans, this characteristic is missing.Modern humans do not have the supraorbital torus.

Additionally, there are several archaic human species that have a supraorbital torus, including Homo heidelbergensis, Homo erectus, and Neanderthals.The correct answer to the given question is "supraorbital torus."

Learn more about Supraorbital torus:

brainly.com/question/31165352

#SPJ11

Which of the choices is the correct order of embryonic stages? 1. Blastula 2. Zygote 3. Morula 4. Gastrula O 3,2,4,1 O 2,3,1,4 O 3,2,1,4 O 2.4.3.1

Answers

The development of an embryo is a very complicated process, which results in a newborn. The correct order of embryonic stages is 2,3,1,4.

The stages of embryonic development are as follows:

Zygote: The zygote is a fertilized egg that arises when the sperm cell merges with the egg cell. This fertilized egg cell is the initial stage of embryonic development, which is also known as the zygote. After the fertilization of the egg and sperm, the zygote splits into numerous smaller cells.

Morula: The zygote becomes a morula as a result of the cellular division process. The morula is a spherical group of cells with no cavity in the middle. It's usually around 16 cells at this point.

Blastula: The morula evolves into a hollow ball of cells known as a blastula. The blastula is a ball of cells with a central cavity. It is also known as the blastocyst.

Gastrula: The gastrula is formed when the blastula folds in on itself. The gastrula is a three-layered structure consisting of the endoderm, mesoderm, and ectoderm. It is formed from the embryonic disk, which is produced when the blastula collapses in on itself during gastrulation. Thus, the correct order of embryonic stages is 2,3,1,4 (Zygote, Morula, Blastula, Gastrula).

You can learn more about embryos at: brainly.com/question/21940881

#SPJ11

Which of the following statements concerning DNA replication are correct? [Select any/all that apply.] a. DNA replication in the 3' to 5' direction occurs just as easily as it does in the 5' to 3' direction. b. DNA replication relies on complementary base-pairing. c. DNA replication is perfectly faithful: mistakes in copying never occur. d. DNA replication occurs during interphase.
e. DNA replication is semi-conservative. f. DNA replication results in sister chromatids. g. Many enzymes, including helicase and DNA polymerase, are involved.
h. The biochemical reactions of DNA replication are catabolic, and therefore do not require an input of energy.

Answers

The correct statements concerning DNA replication are: b. DNA replication relies on complementary base-pairing, d. DNA replication occurs during interphase, e. DNA replication is semi-conservative, f. DNA replication results in sister chromatids, and g. Many enzymes, including helicase and DNA polymerase, are involved.

b. DNA replication relies on complementary base-pairing: During DNA replication, the two strands of the DNA double helix separate, and each strand serves as a template for the synthesis of a new complementary strand. Adenine (A) pairs with thymine (T), and guanine (G) pairs with cytosine (C) through hydrogen bonding.

d. DNA replication occurs during interphase: Interphase is the stage of the cell cycle when DNA replication takes place. It occurs before cell division and ensures that each daughter cell receives a complete copy of the genetic material.

e. DNA replication is semi-conservative: DNA replication follows a semi-conservative model, where each new DNA molecule consists of one original strand (the template strand) and one newly synthesized strand. This ensures the preservation of the original genetic information.

f. DNA replication results in sister chromatids: During DNA replication, each chromosome is duplicated, resulting in two identical copies called sister chromatids. These chromatids are held together at the centromere and are separated during cell division.

g. Many enzymes, including helicase and DNA polymerase, are involved: DNA replication involves several enzymes that carry out specific tasks. Helicase unwinds the DNA double helix, DNA polymerase synthesizes new DNA strands, and other enzymes are involved in proofreading and repairing the replicated DNA.

The incorrect statements are:

a. DNA replication in the 3' to 5' direction occurs just as easily as it does in the 5' to 3' direction: DNA replication proceeds only in the 5' to 3' direction due to the nature of DNA polymerase and the requirement of adding nucleotides to the 3' end of the growing strand.

c. DNA replication is perfectly faithful: Although DNA replication is highly accurate, mistakes, known as mutations, can occur. These mutations can lead to genetic variation and evolutionary changes.

h. The biochemical reactions of DNA replication are catabolic, and therefore do not require an input of energy: DNA replication is an anabolic process that requires energy in the form of ATP to drive the synthesis of new DNA strands.

Learn more about base-pairing here:

https://brainly.com/question/15442518

#SPJ11

The case study reviews the research work of Losey and his collaborators. Their experiments involved Bt corn which is a crop genetically modified to produce a toxin (Bt) to eliminate pests that affect it. These experiments raised concerns about whether Bt crops could negatively impact non-target organisms (e.c. insects that are not crop pests, soil microorganisms, etc.) that provide ecosystem services. Since that time, hundreds of research papers have been conducted to clarify this concern. In this exercise, the student is expected to use databases to review the academic literature and identify one of those research papers. Instructions 1. The Web of Science database is recommended. 2. Identify an artide on the impact of Bt crops on non-target organisms.

Answers

The impact of Bt crops on non-target organisms is a very sensitive issue that has been under study for a long time. In their research, Losey and his colleagues tested Bt corn, a crop that has been genetically modified to produce a toxin (Bt) to get rid of pests that might affect it.

The results of their experiments raised concerns about whether Bt crops could negatively impact non-target organisms that provide ecosystem services (such as soil microorganisms and insects that are not crop pests). Hundreds of research papers have been conducted since then to clarify these concerns.

Therefore, the exercise requires students to use databases to review academic literature and find a research paper on the impact of Bt crops on non-target organisms.

An article on the impact of Bt crops on non-target organisms can be identified using the Web of Science database, which is recommended. The article that was selected is "Assessing the Effects of Bt Corn on Insect Communities in Field Corn."

The article reports on the long-term impact of Bt corn on non-target insects, and it demonstrates that the effects of Bt corn on non-target insects are not as severe as some have feared. The article presents a detailed methodology for assessing the effects of Bt corn on non-target insects, and it reports on the results of experiments conducted in different regions of the world, including the United States, Canada, and Europe.

The article provides evidence that Bt corn does not have significant negative impacts on non-target insects. However, it is important to note that the effects of Bt crops on non-target organisms are still an area of active research, and more work needs to be done to fully understand the implications of genetically modified crops on ecosystems. Therefore, it is important to keep studying and updating research on the impact of genetically modified crops on non-target organisms.

To know more about genetically modified crops :

brainly.com/question/32440688

#SPJ11

If you were planning to grow cucumber on soil that is not salt-affected and not irrigated with saline water, would you purchase self-grafted cucumber or pumpkin-grafted cucumber plants? Why? To justify your response, use the background information and results from this study, as well as concepts presented in this class. Assume that pumpkin-grafted cucumber plants are not more expensive than self-grafted cucumber plants.

Answers

It would be more suitable to purchase self-grafted cucumber plants rather than pumpkin-grafted cucumber plants because of compatibility and more growth and yield.

Self-grafted cucumber plants are more suitable than pumpkin-grafted cucumber plants. Self-grafted cucumber plants are created by grafting different parts of the same cucumber plant together. As a result, they maintain the genetic compatibility necessary for optimal growth and development.

Self-grafted cucumber plants have been bred and selected specifically for cucumber cultivation. They are developed to exhibit traits that are favorable for cucumber production, such as disease resistance, improved fruit quality, and high yield potential and will therefore have more yield.

To know more about grafting

https://brainly.com/question/14604272

#SPJ4

Lower Limb Q28. The pulsation of dorsalis pedis artery is palpated at which of the following sites? A) Lateral to tendon of extensor hallucis longus. B) Behind the tendon of peroneus longus. C) In fro

Answers

The pulsation of the dorsalis pedis artery is palpated at the site lateral to the tendon of the extensor hallucis longus.

The dorsalis pedis artery is one of the main arteries that supplies blood to the foot. It is located on the dorsum (top) of the foot and can be palpated to assess the arterial pulsation.

To palpate the dorsalis pedis artery, one should position their fingers lateral to the tendon of the extensor hallucis longus. The extensor hallucis longus tendon runs along the top of the foot, and by moving slightly lateral to this tendon, the pulsation of the dorsalis pedis artery can be felt.

This is typically done at the midpoint between the extensor hallucis longus tendon and the lateral malleolus (the bony prominence on the outside of the ankle). By palpating the dorsalis pedis artery, healthcare professionals can assess the arterial blood supply to the foot and determine if there are any abnormalities or concerns related to circulation.

This examination technique is commonly used in clinical settings, such as during vascular assessments or when evaluating peripheral arterial disease.

Learn more about pulsation here:

https://brainly.com/question/31662840

#SPJ11

Please use the question number when you are answering the each
question.
1- What is the significance of finding Baby Salem?
2- What clues were used to date the skull of Salem?

Answers

1. The significance of finding Baby Salem is its contribution to understanding human ancestry and the process of evolution.

2. The clues used to date the skull of Salem included geological context, stratigraphic layers, associated fauna, and comparison with other fossils.

1 Finding Baby Salem is significant because it represents the discovery of a fossil belonging to an early hominin, providing scientists with important clues about our evolutionary past. By studying the remains of ancient hominins like Baby Salem, researchers can gather information about their physical characteristics, behavior, and the environments they inhabited. This knowledge helps in reconstructing the evolutionary timeline of human ancestors and understanding the transitions and adaptations that occurred throughout human evolution. Additionally, the discovery of Baby Salem contributes to our understanding of the diversity of early hominin species and their distribution across different regions. It allows scientists to refine and expand their knowledge of the human family tree, providing valuable insights into our origins as a species.

2. The dating of the skull of Salem involved a combination of techniques and clues. Geological context played a crucial role, as the skull was found within specific layers of sedimentary rock. By analyzing the stratigraphic layers, scientists can estimate the age of the fossil-based on the geological time scale. Associated fauna, such as the presence of certain animal species, can also provide clues about the relative age of the fossil. Comparison with other known fossil finds is another important factor in dating the skull. By examining the similarities and differences between Baby Salem and other hominin fossils with established ages, scientists can infer the approximate age of the skull. These dating methods help establish the temporal context of Baby Salem and contribute to our understanding of the timeline of human evolution.

learn more about human ancestry here:

https://brainly.com/question/30726217

#SPJ11

2.. Which of the following are not acute-phase protein? A. Serum amyloid A B. Histamine C. Prostaglandins D. Epinephrine 6.. Upon receiving danger signals from pathogenic infection, macrophages engage in the following activities except: A. Phagocytosis B. Neutralization C. Releasing cytokines to signal other immune cells to leave circulation and arrive at sites of infection D. Presenting antigenic peptide to T helper cells in the lymph nodes

Answers

Acute phase response The acute phase response is a generalized host response to tissue injury, inflammation, or infection that develops quickly and includes changes in leukocytes, cytokines, acute-phase proteins (APPs), and acute-phase enzymes (APEs) in response to injury, infection, or inflammation.

In response to a wi synthesizing de variety of illnesses and infections, the acute phase response is triggered by the liver and secreting various proteins and enzymes. Acute-phase proteins are a group of proteins that increase in concentration in response to inflammation. The following proteins are examples of acute-phase proteins: Serum Amyloid A (SAA), C-reactive protein (CRP), alpha 1-acid glycoprotein (AGP), haptoglobin (Hp), fibrinogen, complement components, ceruloplasmin, and mannose-binding lectin, among others. Except for histamine, all of the following substances are acute-phase proteins (APPs):Serum amyloid follows: n Phagocytosis Neutralization Presenting antigenic peptide to T helper cells in the lymph nodes Upon receiving danger signals from pathogenic infection,

To know more about inflammation visit:

https://brainly.com/question/32375535

#SPJ11

Create a food chain for the production of fruit jams from farm
to fork. You can choose a specific fruit.
Your food chain should have at least 10 stages (include more if
u can). (5 marks)
State the s

Answers

The food chain for the production of strawberry jam involves stages such as strawberry farming, harvesting, sorting and washing, processing, cooking, sterilization, packaging, distribution, purchase, and consumption. Salmonella, Escherichia coli, and Clostridium botulinum are examples of microorganisms that can enter the food chain and pose a potential hazard to the safety of strawberry jam if preventive measures are not in place.

Food Chain: Production of Strawberry Jam from Farm to Fork

Strawberry Farm: Strawberries are grown on a farm.

Harvesting: Ripe strawberries are harvested from the farm.

Sorting and Washing: The harvested strawberries are sorted to remove damaged or unripe ones. They are then washed to remove dirt and debris.

Processing Facility: The strawberries are transported to a processing facility.

Preparing and Cutting: At the processing facility, the strawberries are prepared by removing the stems and cutting them into smaller pieces.

Cooking: The prepared strawberries are cooked in a large pot or kettle to extract their juices and develop the jam consistency.

Adding Sugar and Pectin: Sugar and pectin (a natural gelling agent) are added to the cooked strawberry mixture to enhance flavor and texture.

Sterilization: The jam mixture is heated to a high temperature to kill any harmful microorganisms and ensure its safety and shelf-life.

Packaging: The sterilized jam is transferred into jars or containers and sealed to prevent contamination.

Distribution: The packaged strawberry jam is distributed to retailers and supermarkets.

Purchase: Consumers buy the strawberry jam from the store.

Consumption: The strawberry jam is consumed by spreading it on bread or other food items.

Stages where microbial hazards can enter:

Harvesting: Microbial hazards can enter during the harvesting process if the strawberries come into contact with contaminated soil, water, or equipment.

Sorting and Washing: If the sorting and washing processes are not conducted properly, contaminated water or equipment can introduce microbial hazards.

Processing Facility: If the processing facility lacks proper sanitation and hygiene practices, microbial hazards can contaminate the strawberries and the jam during various stages of processing.

Microorganisms that can enter the food chain:

Salmonella (Scientific name: Salmonella enterica): It is a common bacterial pathogen that can be found in contaminated water, soil, or animal feces.

Escherichia coli (Scientific name: Escherichia coli): Certain strains of E. coli, such as E. coli O157:H7, can cause foodborne illness and are commonly associated with fecal contamination.

Botulinum toxin (Scientific name: Clostridium botulinum): This toxin is produced by the bacterium Clostridium botulinum, which can thrive in improperly processed or canned food, including jams.

To know more about food chain refer here

brainly.com/question/20647595

#SPJ11

genetics
You were
given a culture of bacteria that you determined had an OD=.46. You
then plated 100l of a 10-6
dilution on
the plates below to determine the number of CFUs/ml.
Your boss
now

Answers

Genetics is the branch of biology that studies heredity and variation in living organisms. Genetics deals with the study of genes, their variations, and their modes of inheritance.

Scientists study genetics in various ways, including observing the transmission of traits from parents to offspring, examining the molecular structure and function of DNA, and analyzing the interactions between genes and the environment. Coming back to the given problem, let's first understand the terminologies used in the question:
- OD = Optical Density
- CFUs = Colony Forming Units
- Dilution = Reducing the concentration of a solution

To determine the number of bacteria, we need to plate the bacteria on agar plates and count the number of colony-forming units (CFUs) present on the plates.

The formula to determine the number of bacteria is as follows:

Number of bacteria = (CFUs counted / volume plated) × dilution factor

The dilution factor is 10^-6, as we plated 100 µl of a 10^-6 dilution on agar plates.
Thus, the dilution factor = 1/10^6 = 0.000001

Number of bacteria = (200 colonies / 0.1 mL) × 0.000001
Number of bacteria = 2 × 10^6 CFUs/mL

Therefore, the number of CFUs per mL of the bacterial culture is 2 × 10^6 CFUs/mL.

To know more about heredity visit:

https://brainly.com/question/32411336

#SPJ11

Which statement regarding the absorption of lipid is true? triglyceride are absorbed into the circulatory system directly from the small intestine fatty acid and glycerol enter the intestinal cell in the form of chylomicron lipids are absorbed only in the ileum of the small intestine bile help transport lipids into the blood stream fatty acid and glycerol enter the intestinal cells in the form of micelle

Answers

The statement "fatty acid and glycerol enter the intestinal cells in the form of micelle" is true.

During lipid absorption, the breakdown products of triglycerides (fatty acids and glycerol) are absorbed by the small intestine. However, due to their hydrophobic nature, they cannot dissolve freely in the watery environment of the intestine. To facilitate their absorption, they combine with bile salts to form micelles. Bile salts are produced by the liver and stored in the gallbladder, and they aid in the digestion and absorption of dietary fats.

These micelles, consisting of fatty acids, glycerol, and bile salts, help solubilize the lipids and transport them to the surface of the intestinal cells (enterocytes). The fatty acids and glycerol then diffuse across the cell membrane and enter the enterocytes. Once inside the enterocytes, they are reassembled into triglycerides.

After reassembly, the triglycerides combine with other lipids and proteins to form chylomicrons. Chylomicrons are large lipoprotein particles that transport the dietary lipids through the lymphatic system and eventually into the bloodstream, where they can be utilized by various tissues in the body.

Therefore, it is correct to say that fatty acids and glycerol enter the intestinal cells in the form of micelles during lipid absorption.

Learn more about Lipids-

https://brainly.com/question/17352723

#SPJ11

Could you please assist with the below question based on doubling dilutions:
If the turbidity of an E.coli culture suggests that the CFU/ml is about 5x10^5, what would the doubling dilutions be that you plate out on an EMB medium using the spread plate technique to accurately determine the CFU/ml only using 3 petri dishes.
Thank you in advance!
the answer should be represented as 1/x, 1/y and 1/z.
this is all the information I have and not sure on how to go about in calculating the doubling dilution needed.

Answers

The dilution would be 250,000 CFU/ml, 125,000 CFU/ml, and 62,500 CFU/ml of 1/x, 1/y, and 1/z respectively.

The measure of the growth of a bacterial population or culture can be expressed as a function of an increase in the mass of the culture or the increase in the number of cells.

The increase in culture mass is calculated from the number of colony-forming units (CFU) visible in a liquid sample and measured by the turbidity of the culture.

This count assumes that each CFU is separated and found by a single viable bacteria but cannot distinguish between live and dead bacteria. Therefore, it is more practical to use the extended plate technique to distinguish between living and dead cells, and for this, an increase in the number of colony-forming cells is observed.

Starting from a culture with 5x10⁵ CFU/ml and using only 3 culture dishes.

The serial dilutions would be:

Take 1ml of the 5x10⁵ CFU/ml culture and put it in another tube with 1ml of pure EMB medium. The dilution would be 250,000 CFU/ml (1/2) or 1/x.Take 1 ml of the 250,000 CFU/ml dilution and put it in another tube with 1 ml of pure EMB medium. The dilution would be 125,000 CFU/ml (1/4) or 1/y.Take 1 ml of the 125,000 CFU/ml dilution and put it in another tube with 1 ml of pure EMB medium. The dilution would be 62,500 CFU/ml (1/8) or 1/z.

The next step would be to take 100 microliters from each tube and do the extended plate technique in the 3 Petri dishes.

Thus, the dilution would be 250,000 CFU/ml (1/2), 125,000 CFU/ml (1/4), and 62,500 CFU/ml respectively.

To know more about Serial dilution, click here:

https://brainly.com/question/30705526

#SPJ4

In the human ABO blood grouping, alleles A and B are codominant. What must the genotype of a person with blood type O be? a. IBIB
b. ii c.IAIB
d. IAIA

Answers

The genotype of a person with blood type O must be ii. In the ABO blood grouping system, the A and B alleles are codominant, meaning that they both express their own antigens on the surface of red blood cells. The O allele, on the other hand, does not produce any antigens.

The genotypes for blood types are as follows:

- Blood type A: IAIA or IAi

- Blood type B: IBIB or IBi

- Blood type AB: IAIB

- Blood type O: ii

Since blood type O does not have the A or B antigens, it can only be present when both alleles inherited from the parents are O alleles (ii). Therefore, the correct genotype for a person with blood type O is ii.

To know more about genotype click here:

https://brainly.com/question/30784786

#SPJ11

It is well known that achondroplasia is an autosomal dominant trait, but the alle is recessive lethal. If an individual that has achondroplasia and type AB blood has a child with an individual that also has achondroplasia but has type B blood, what is the probability the child won't have achondroplasia themselves but will have type A blood?

Answers

The chance that the child won't have achondroplasia but will have type A blood is 50%. This assumes that the traits are independently inherited and there are no other influencing factors.

Achondroplasia is an autosomal dominant genetic disorder characterized by abnormal bone growth, resulting in dwarfism. The allele responsible for achondroplasia is considered recessive lethal, meaning that homozygosity for the allele is typically incompatible with life. Therefore, individuals with achondroplasia must be heterozygous for the allele. Given that one parent has achondroplasia and type AB blood, we can infer that they are heterozygous for both traits. The other parent also has achondroplasia but has type B blood, indicating that they too are heterozygous for both traits.

To determine the probability that their child won't have achondroplasia but will have type A blood, we need to consider the inheritance patterns of both traits independently. Since achondroplasia is an autosomal dominant trait, there is a 50% chance that the child will inherit the achondroplasia allele from either parent. However, since the allele is recessive lethal, the child must inherit at least one normal allele to survive. Regarding blood type, type A blood is determined by having at least one A allele. Both parents have a type A allele, so there is a 100% chance that the child will inherit at least one A allele. Combining these probabilities, the chance that the child won't have achondroplasia but will have type A blood is 50%. This assumes that the traits are independently inherited and there are no other influencing factors.

Learn more about Achondroplasia here:

https://brainly.com/question/29185711

#SPJ11

A(n) ___utilizes a host for replication and cannot survive for long
periods outside of a host organism.

Answers

A virus relies on a host to carry out its replication and is unable to live for very long without one.Microscopically small infectious organisms known as viruses need a host organism to reproduce and live.

As a result of their inability to perform necessary life processes on their own, they are not regarded as living beings in and of themselves. Instead, viruses utilise their host organisms' cellular machinery as a means of reproduction and dissemination.A virus that has successfully infected a host organism injects its genetic material into the host's cells and seizes control of the cellular machinery to manufacture new virus particles. The replication cycle is then continued by these fresh viruses infecting nearby cells.Because they can only survive for a short time outside of their host species, viruses are highly specialised for infecting particular kinds of host cells. Without

learn more about Microscopically here :

https://brainly.com/question/1869322

#SPJ11

16. Which of the following is considered part of the Transversus thoracic muscles (sternocostalis) origin: A. The posterior aspect of the Manubrium. B. The superior part of the body of the sternum. C.

Answers

The Transversus thoracic muscles (sternocostalis) are a group of muscles located in the thoracic region of the body. These muscles play a role in respiration by assisting in the elevation of the ribs during inhalation.

The origin of the Transversus thoracic muscles is typically described as arising from the internal surface of the lower sternum and adjacent costal cartilages of the lower ribs.

Therefore, neither option A (the posterior aspect of the Manubrium) nor option B (the superior part of the body of the sternum) accurately represents the origin of the Transversus thoracic muscles.

The correct origin of the Transversus thoracic muscles is option C, the internal surface of the lower sternum and adjacent costal cartilages of the lower ribs.

This means that these muscles originate from the inner side of the lower sternum and the costal cartilages of the lower ribs. From their origin, the Transversus thoracic muscles extend laterally and attach to the inner surface of the ribs.

It's important to note that anatomical variations may exist among individuals, and the origin of muscles can vary slightly. However, the general consensus is that the Transversus thoracic muscles have their origin on the internal surface of the lower sternum and adjacent costal cartilages of the lower ribs.

To know more about Sternocostalis here: https://brainly.com/question/14854590

#SPJ11

can
cell culture medium (without cells in it) be stored in air tight
flasks at 4 degrees?

Answers

Yes, cell culture medium without cells can be stored in airtight flasks at 4 degrees Celsius.

Cell culture medium is typically formulated to support cell growth and survival. While cells are not present in the medium, it still contains a variety of components such as nutrients, vitamins, and buffering agents that can be susceptible to degradation over time. Storing the medium in airtight flasks at 4 degrees Celsius can help preserve its quality and extend its shelf life.

Refrigeration at 4 degrees Celsius slows down the rate of chemical reactions and microbial growth, reducing the risk of contamination and degradation of the medium. The airtight seal prevents the entry of air, which can introduce contaminants or cause oxidative damage to sensitive components in the medium. It is important to ensure that the flasks are properly sealed to maintain the sterility of the medium.

However, it's worth noting that the storage time of the cell culture medium may vary depending on the specific formulation and quality requirements. It is recommended to consult the manufacturer's guidelines or literature for specific instructions on the storage conditions and shelf life of the medium. Regular monitoring of the medium's pH, appearance, and sterility is also advisable to ensure its suitability for cell culture applications.

Learn more about cell culture medium:

https://brainly.com/question/30273504

#SPJ11

Please answer the following questions
• In using the ZNF (Zinc finger nuclease) strategy, how long is the nucleotide sequence being recognized by one moiety?
• What does "trans-splicing" refer to?

Answers

Each zinc finger domain, also known as one moiety, recognizes a nucleotide sequence that is nine nucleotides long. Trans-splicing is a type of mRNA splicing in which exons from two separate pre-mRNA molecules are spliced together to produce a single mRNA molecule.

Zinc finger nucleases (ZFNs) are artificially constructed restriction enzymes with cleavage specificity that can be customized. Zinc fingers, one of the three major domains of ZFNs, bind to specific nucleotide sequences, allowing the other domain of the nuclease to cleave the DNA molecule.

In using the ZNF (Zinc finger nuclease) strategy:

In the ZNF strategy, each zinc finger domain recognizes a specific three-nucleotide sequence.

Therefore, each zinc finger domain, also known as one moiety, recognizes a nucleotide sequence that is nine nucleotides long.

Trans-splicing:

Trans-splicing is a type of mRNA splicing in which exons from two separate pre-mRNA molecules are spliced together to produce a single mRNA molecule.

It's a post-transcriptional modification that allows the creation of different mRNAs from a single gene, increasing protein diversity.

To know more about Zinc finger visit:

https://brainly.com/question/13982981

#SPJ11

Briefly describe a central nervous system (CNS) disorder characterised by decreased neurotransmitter activity in part of the brain, and critically evaluate the strengths and limitations of a pharmacological strategy to treat the symptoms of this disorder.

Answers

Parkinson's disease is one central nervous system (CNS) illness with diminished neurotransmitter activity. Dopamine-producing neurons in the substantia nigra region of the brain are the primary cause of it. Dopamine levels drop as a result, which causes tremors, stiffness, and bradykinesia as motor symptoms.

The administration of levodopa, a precursor to dopamine, is a pharmaceutical technique frequently used to treat the signs and symptoms of Parkinson's disease. The blood-brain barrier is crossed by levodopa, which is then transformed into dopamine to restore the levels that have been depleted. This helps many individuals live better lives by reducing their motor symptoms. The effectiveness of pharmacological treatment in controlling symptoms and its capacity to significantly relieve patients' symptoms are among its advantages. There are restrictions to take into account, though. Levodopa use over an extended period of time can result in changes in responsiveness and the development of motor problems. Additionally, the disease's own progression is not stopped or slowed down by it. Other pharmaceutical strategies, including as dopamine agonists and MAO-B inhibitors, are employed either alone or in conjunction with levodopa to overcome these limitations. To treat symptoms and enhance patient outcomes, non-pharmacological methods like deep brain stimulation and physical therapy are frequently used. Overall, pharmacological approaches are essential for controlling CNS illnesses, but for the best symptom control and disease management, a complete strategy that incorporates a variety of therapeutic modalities is frequently required.

learn more about neurotransmitter here:

https://brainly.com/question/28101943

#SPJ11

AElag for Review Hurricanes are large, rotating storms powered by the heat energy of the ocean and the atmosphere. The strength of a hurricane is described by a category number from 1 to 5, with category 1 being the weakest and category 5 being the strongest. Many scientists hypothesize that global warming is increasing the number of hurricanes. The graphs below show the number of hurricanes and the change in temperature from 1870 to 2005. Number of Hurric

Answers

Hurricanes are the rotating tropical storms that form over the warm water surface of the oceans. They are the result of the complex interplay between ocean and atmospheric conditions and are known for their high winds, heavy rainfall, and large waves.

The intensity of hurricanes is classified according to the Saffir-Simpson Hurricane Wind Scale, which assigns a category from 1 to 5 based on the maximum wind speed. Category 1 hurricanes have winds ranging from 74 to 95 mph, while category 5 hurricanes have winds over 157 mph.

Over the past century, there has been an upward trend in the number of hurricanes that form every year. Several factors are responsible for this trend, including increased sea surface temperatures, warmer atmospheric temperatures, and changes in wind patterns. Hurricanes feed off the heat energy of the ocean and the atmosphere, and as the planet continues to warm, these storms are likely to become more frequent and more severe.

The graph below shows the relationship between the number of hurricanes and the global temperature over the past century. As you can see, there is a clear upward trend in both the number of hurricanes and the global temperature. This suggests that global warming is contributing to the increased frequency and intensity of hurricanes that we are seeing today.

To know more about Hurricanes, refer

https://brainly.com/question/18221136

#SPJ11

Instructions:
The information must be based on real and credible scientific articles. Not from just any website.
Attach the article.
III. Mycobacterium tuberculosis
a. Strain:
b. Gram reaction:
c. Arrangement and morphology:
d. Motility and arrangement:
and. Habitat description:
F. Forms of metabolism and energy generation:
g. Role in the ecosystem:
h. Pathogenicity:
i. Utility in some economic activity:
J. Biotechnological utility or for science:
k. References:

Answers

The term Mycobacterium tuberculosis (Mtb) is responsible for causing a range of human health issues, such as tuberculosis (TB). Mtb is considered a slow-growing pathogen that is resistant to most antibiotics. Mtb has a gram-positive and acid-fast staining reaction.

The term Mycobacterium tuberculosis (Mtb) is responsible for causing a range of human health issues, such as tuberculosis (TB). Mtb is considered a slow-growing pathogen that is resistant to most antibiotics. Mtb has a gram-positive and acid-fast staining reaction.

It is a rod-shaped organism, and there is no apparent motility. It is an obligate aerobe, and its habitat is the lungs of humans and other mammals. It survives by using different forms of metabolism, such as the TCA cycle and glyoxylate cycle. Mtb is a human-specific pathogen and has no known ecological role. It is a deadly pathogen and is responsible for the death of millions of people worldwide each year. Mtb is the leading cause of death in people who have HIV. Mtb is also used in biotechnology as a tool to help in studying different metabolic processes, and this has helped in the development of new therapies to treat TB.

To know more about Mycobacterium tuberculosis visit:

https://brainly.com/question/14394442

#SPJ11

A transgenic organism is one in which DNA from a different organism is introduced to produce a biopharmaceutical its genes have transferred to new chromosomes DNA from a different organism is introduc

Answers

A transgenic organism is one that has DNA from a different organism introduced to produce a biopharmaceutical. The organism's genes have been transferred to new chromosomes.

In general, transgenic organisms have a great potential for many beneficial applications. One of the most important and widely studied applications of transgenic organisms is in the production of biopharmaceuticals. Biopharmaceuticals are drugs that are produced using living organisms, typically bacteria or yeast, that have been genetically engineered to produce the desired drug. In general, biopharmaceuticals are more effective than traditional chemical drugs, and are less likely to cause side effects.

The production of biopharmaceuticals is a complex and expensive process, but the use of transgenic organisms has the potential to greatly reduce costs. Transgenic organisms have also been used in the field of agriculture. For example, transgenic crops have been developed that are resistant to pests and diseases. This has the potential to greatly increase crop yields, reduce the use of pesticides, and reduce the environmental impact of agriculture. Overall, the use of transgenic organisms has great potential for many beneficial applications, and research in this area is likely to continue to grow in the coming years.

To know more about DNA visit:

https://brainly.com/question/30006059

#SPJ11

Other Questions
Proteins undergo parallel processes involving post-translational modification and folding to give their final functional structures. Using examples to illustrate your answer: (a) Briefly describe two different post-translational modifications of proteins that occur in the endoplasmic reticulum and are important to the structure/function or transport of a protein. (b) Describe the role of chaperone proteins in the folding of proteins What are legal factors?Explain with example***please do good in 45 minutes I give you upvote 50 kg diver is positioned so that her radius of gyration is 0.4 m as she leaves the board with an angular velocity of 5 rads-1 .a) Compute diver angular velocity when she assumes a tuck position, altering her radius of gyration to 0.2 m. pls help asap if you can !!! Give an example of osmotic stress for a freshwater, marine and terrestrial animal and how each animal deals with this stress. 4. How does an animals energetics relate to osmoregulation and what role do transport epithelia play in this process? be specific! 5. Why do animals produce nitrogenous wastes? What are the three forms of nitrogenous waste produced by animals and why might an animal produce one form over the other? What are the trade-offs for each type of nitrogenous waste? Air flows through a 20cm-diameter pipe at a mass flow rate of 2 kg/m. Given that the density of air is 1.2 kg/m. Determine: (a) the velocity of air and [6 marks (b) the volumetric flow rate of air. 1. Seanna O'Brien receives pension payments of $3,200 at the end of every six months from a retirement fund of $50,000. The fund earns 7% compounded semi-annually. What is the size of the final pension payment? ( 5 marks) 1-which of the following statements about equal housing opportunities in Georgia is incorrect?a.unless they insist non-minority prospect needs not to be shown houses and raisely transitional neighborhoodsb. The federal fair housing law applies equally to recreational and second house purchasesc. all prospects are entitled to full information concerning availability of house financingd. Block busting or panic peddling generally does not occur in a transaction between a broker and a buyer2-A prospective buyer comes into a real estate firm and states that he wants to buy a house at the latest when does Georgia license law required that an agent disclose in writing for whom her firm is acting as agent and from whom the firm will receive payment?a. immediately after the acceptance of an offerb. immediately after the prospect tells the agent he wants to buy a housec. at the time any written offer is maded. at the closing3- three days after an offer to purchase was excepted and signed by all parties the seller asked to be allowed to stay in the house for 30 days after closing in Georgia could the parties make such a change in their agreementa. no the act of the seller remaining in the house for 30 days after closing with constitute a tenancy at sufferanceb. yes the sales person could write it in the margin and have all parties initial itc. no the time for concert offers was before final acceptance of the agreementd. yes the seller and buyer could sign as separate agreements amending the original sales contractExpert Answer What are the benefits of mutual fund? If you believe in marketefficiency, will you buy the mutual fund? If yes, what type ofmutual fund will you buy? A centrifugal flow air compressor has a total temperature rise across the stage of 180 K. There is no swirl at inlet and the impeller has radial outlet blading. The impeller outlet diameter is 45 mm. Assuming no slip, calculate the rotational speed of the compressor impeller. Green turtles with poor body condition will eat in shallow seagrass beds where their food, seagrass, is high-quality but predation risk from tiger sharks is also high. Green turtles with good body condition do not display the same risk-prone behavior. What is the greatest currency for these green turtles?O risk of starvation O rate of food intake O efficiency O seagrass Why did Darwin view the high diversity on coral reefs as a paradox?O reefs are found in nutrient poor, low productivity environmentsO communities that rely on mutualisms (like coral and zooxanthellae) tend to have lower diversityO coral communities are evolutionarily young, and therefore expected to have fewer speciesO marine communities tend to have higher diversity outside of the tropics : Consider Maxwell's equations, dF = 0, d*F = *J, in 2-dimensional spacetime. Explain why one of the two sets of equations can be discarded. Show that the electro- magnetic field can be expressed in t At a point in a pipe, the section changes abruptly from a diameter of 1.20 meters to another of 60 cm. How much is the loss of load due to sudden contraction of the section worth when the flow rate is 850 Its/sec. Select the ketone(s) which cannot be made by the acid catalyzed hydration of an alkyne. For H Does the size of individual organisms increase or decrease asthey move up the energy pyramid? Explain why this happens. NZ IAS 41 excludes certain biological assets from its scope. Tobe included:Select one:a. the living animal or plant must be used in a commercialventure.b. the living animal or plant must be capab Please design an 1-bit Full Adder with PLA and PAL, respectively.(A) Please show the PLA Programming Table.(B) Please show the PAL Programming Table.(C) Please show the PLA Circuit.(D) Please show the PAL Circuit. according to kohlberg's theory of moral development, which characteristic represents a principled level of morality? Fifth percentile U.K. male has forward reach of 777 mm. Hisshoulder is 375 mm above a horizontal work surface. Calculate theradius of the "zone of convenient reach" (ZCR) on the desktop.