In an experiment, potassium chlorate decomposed according to the following chemical equation.

KClO3 → KCl + O2

(Molar mass of KClO3 = 122.5 g/mol; KCl = 74.55 g/mol; O2 = 31.998 g/mol)

If the mass of potassium chlorate was 240 grams, which of the following calculations can be used to determine the mass of oxygen gas formed?

(240 × 2 × 31.998) ÷ (122.5 × 3) grams
(240 × 3 × 31.998) ÷ (122.5 × 2) grams
(240 × 2 × 122.5) ÷ (31.998 × 3) grams
(240 × 3 × 122.5) ÷ (31.998 × 2) grams

Answers

Answer 1

Answer:

(240 × 3 × 31.998) ÷ (122.5 × 2) grams

Explanation:

To solve this problem, it is best to use the mole concept approach. Here find the number of moles of the given specie and use it to find that of the unknown.

Then convert the number of moles of the unknown to mass.

     Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

  Mass = number of moles x molar mass

Mass of potassium chlorate = 240g

The balanced reaction equation is given as:

              2KClO₃  →  2KCl  +  3O₂

Number of moles of KClO₃  = [tex]\frac{240}{122.5}[/tex]  

     Mole ratio:

              2 mole of KClO₃  will produce 3 moles of O₂

            [tex]\frac{240}{122.5}[/tex]  mole of KClO₃ will produce  [tex]\frac{240}{122.5}[/tex] x 3 / 2 mole of O₂

So, mass of oxygen;

        Mass  =   [tex]\frac{240}{122.5}[/tex] x 3 / 2   x 31.998  =   [tex]\frac{240}{122.5}[/tex]  x 3 x [tex]\frac{1}{2}[/tex]  x 31.998

 This gives (240 × 3 × 31.998) ÷ (122.5 × 2) grams

Answer 2

In the experiment the potassium and chlorate decompose as per the chemical equation of KClO3 → KCl + O2.

Hence the method to use the mole concept approach. Here find the number of moles of the given specie and use it to find that of the unknown. Then convert the number of moles of the unknown to mass.   Mass = number of moles x molar massThus (240 × 3 × 31.998) ÷ (122.5 × 2) grams.

Learn more about the potassium chlorate decomposed according.

brainly.com/question/14385367.


Related Questions

An irregularly-shaped piece of aluminum (Al) has a mass of 66.0 grams. What is the volume in cm³ of this piece of aluminum if its density is 2.70 g/cm³?

Answers

Answer:

[tex]V=24.45\ \text{cm}^3[/tex]

Explanation:

Given that,

Mass of a piece of Aluminium, m = 66 grams

The density of Aluminium, d = 2.70 g/cm³

We need to find the volume of this piece in cm³.

We know that,

Density = mass per unit volume

[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{66\ g}{2.7\ g/cm^3}\\\\V=24.45\ \text{cm}^3[/tex]

So, the volume of the piece is [tex]24.45\ \text{cm}^3[/tex].

all organisms begins life as a ________ cell.

Answers

Answer:

All organisms begin life as a single cell

Explanation:

Single cell also did you know 15 minutes can save you 15% more on car insurance

A chemist has a block of copper metal (density is 8.96 g/mL). They drop the metal into a graduated cylinder containing water, and find the volume change is 1.30 mL. What is the mass of the block, in grams

Answers

Answer:

11.648 g

Explanation:

From the question,

Note: an object immersed in a fluid, displaced an amount of fluid, equal to its volume.

Density = mass/volume.

D = M/V................................................................ Equation 1

Where D = density of the copper block, M = mass of the copper block, V = volume of the copper block.

make M the subject of the equation

M = D×V......................................... Equation 2

Given: D = 8.96 g/mL, V = 1.3 mL

Substitute into equation 2

M = 8.96×1.3

M = 11.648 g

Hence the mass of the block is 11.648 g

HELP PLEASE
Instantaneous speed is the rate of motion at an instant in time. Based on this statement, a reasonable conclusion is that if and object's instantaneous speed does not chang over time then,________.

•the object is quickly speeding up
•the object is very gradually slowing down
•the object is moving at a constant speed
•the object has returned to its beginning position ​

Answers

Answer:

The object is moving at a constant speed.

A student is making a glucose solution. The student is using 12.55 g of glucose (C6H1206) and a 500 mL volumetric flask. Use this information to calculate the molarity of the glucose solution.​

Answers

Answer:

M = 0.138 M

Explanation:

Given data:

Mass of glucose = 12.55 g

Volume of solution = 500 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 12.55 g/ 180.156 g/mol

Number of moles = 0.069 mol

Volume in L:

500 mL × 1 L /1000 mL

0.5 L

Molarity:

M = 0.069 mol / 0.5 L

M = 0.138 M

Which two elements have similar characteristics?

Answers

Answer:

The two elements are FLUORINE AND CHLORINE. These two elements have similar characteristics because they belong to the same group in the periodic table. On the periodic table, elements with similar properties are grouped together in the same group. Both chlorine and fluorine belongs to the halogen group.

Explanation:

Hope it helps, some how.

what is the molarity of a solutoin which contains 38.5 g of sodium chloride disolved in 325 ml solution ?

Answers

Answer:

Molarity =  2.02 M

Explanation:

Given data:

Molarity of solution = ?

Mass of sodium chloride = 38.5 g

Volume of solution = 325 mL (0.325 L)

Solution:

Number of moles = mass/molar mass

Number of moles = 38.5 g/ 58.44 g/mol

Number of moles = 0.658 mol

Molarity:

Molarity = number of moles / volume of solution in L

Molarity = 0.658 mol /0.325 L

Molarity =  2.02 M

A 175 g piece of iron and a 175 g piece of aluminum are placed in a hot water bath so that they are warmed to 99.7 o C. The metal samples are removed and cooled to 21.5 o C. Which sample undergoes the greater heat change

Answers

Answer:

The Aluminium sample

Explanation:

From the question,

ΔQ of the iron = Cm(t₂-t₁)........................ Equation 1

Given: C = specific heat capacity of iron, m = mass of iron, t₁ and t₂ = initial and final temperature respectively.

Given: m = 175 g = 0.175 kg, t₂ = 21.5°C, t₁ = 99.7°C

Constant: C = 444 J/kgK.

Substitute into equation 1

ΔQ = 0.175(444)(21.5-99.7)

ΔQ = -6076.14 J

Similarly, for aluminium,

ΔQ' = c'm'(t₂-t₁)...................... Equation 2

Given: m' = 175 g = 0.175 kg,

Constant: 900 J/kgK

ΔQ' = 0.175(900)(21.5-99.7)

ΔQ' = -12316.5 J

Hence the aluminium sample undergoes the greater heat change

The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.150 M NaOH. It requires 21.4 mL of the NaOH solution to reach the end point of the titration. A buret filled with a titrant is held above a graduated cylinder containing an analyte solution. What is the initial concentration of HCl

Answers

Answer:

0.321 M

Explanation:

The neutralization reaction of HCl with NaOH is the following:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

So, 1 equivalent of HCl reacts with 1 equivalent of NaOH. In this case:

1 equivalent HCl = 1 mol HCl

1 equivalent NaOH = 1 mol NaOH

At the equivalence point, the amount of HCl reacts completely with the added amount of titrant (NaOH). As 1 mol of reactant is calculated from the product of the molarity of the solution and the volume, in the equivalent point:

moles HCl = moles NaOH

M(HCl) x V(HCl) = M(NaOH) x V(NaOH)

We have:

M(NaOH) = 0.150 M

V(NaOH) = 21.4 mL = 0.0214 L

V(HCl) = 10.0 mL = 0.01 L

Thus, we calculate the initial concentration HCl as follows:

M(HCl) = (M(NaOH) x V(NaOH))/ (V(HCl))

            = (0.150 M x 0.0214 L)/(0.01 L) = 0.321 M

Can anybody answer this question of chemistry?

Answers

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

if you know an object's distance from the sun in kilometers,how can you find the distance in AU?​

Answers

Answer:

We divide our value by 1.5×10⁸

Explanation:

AU is a unit to determine distance in the space.

We know that AU means astronomic unit.

The value for conversion is 1.5×10⁸ Km

1 AU = 1.5×10⁸ Km

Let's see the example:

One star is located from the sun, around 3.35×10¹⁰ Km away. To determine the distance in AU we use the conversion factor:

3.35×10¹⁰ Km . 1 AU / 1.5×10⁸ Km = 223.3 AU

Conclusion
In this activity, thermal energy was transferred ( into / out of the hand warmer while it changed from
liquid to solid.

Answers

whats the question?

12. Which gas has the greatest kinetic energy at STP?

a. He

b. Ne

c. Ar

d. none of the above (all have the same kinetic energy)

Answers

Answer:

d. none of the above (all have the same kinetic energy)

Explanation:

The kinetic theory of gases states that the molecules of an ideal gas experience a constant random motion.

At standard temperature and pressure (STP), the kinetic energy of an ideal gas such as hydrogen, argon, neon, sodium, oxygen, helium, magnesium, beryllium, nitrogen, carbon, fluorine, chlorine etc are all the same.

The standard temperature and pressure (STP) of an ideal gas is 273K and 100 kPa.

Hence, all of the gases have the same kinetic energy at standard temperature and pressure (STP).

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where, K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

A student measures 48.8 mL of concentrated nitric acid, which has a density of 1.55g/ mL. What is the mass of the acid?

Answers

The mass of the acid : 75.64 g

Further explanation

Given

volume = 48.8 ml

density = 1.55 g/ml

Required

the mass

Solution

Further explanation

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

 Density formula:

[tex]\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}[/tex]

Input the value :

mass = ρ x V

mass = 1.55 g/ml x 48.8 ml

mass = 75.64 g

Chromuate found inside which of the following structures of a eukaryotic cell?

Answers

Answer:

Chromuates are found in the chromosomes of the eukaryotic cells!!!!

Explanation:

I learned this in 7th grade!!!!

Mark Me Brainliest plzz

< Progress: 19/21 groups Due Jan 15 at 11:55 PM Use the References to access important values if needed for this question. The compound cobalt (II) sulfate forms a hydrate with seven water molecules per formula unit. What are the name and formula of the hydrate

Answers

Answer:

CoSO4.7H2O

Cobalt II tetraoxosulphate VI heptahydrate

Explanation:

According to IUPAC nomenclature, compounds are named systematically.

We were told that there are seven water molecules in each formula unit Hence the correct formula of the compound is CoSO4.7H2O

According to IUPAC system, the metal is first named, followed by its oxidation state in Roman numerals. Then the name of the anion is mentioned as well as the number of water molecules. We have to take into account the correct prefix signifying the number of molecules of water of crystallization.

The Question A 1.80 x 10-2 kg block of metal has the following dimensions: 0.4981 inches by 0.531 inches, by 0.5839 inches. Determine the density of the block in g/mL. Using the provided list of metals and their respective densities, what is the metal's identity

Answers

Answer:

Zinc

Explanation:

m = Mass of block [tex]1.8\times 10^{-2}\ \text{kg}=18\ \text{g}[/tex]

Dimension of block is 0.4981 inches by 0.531 inches, by 0.5839 inches

[tex]1\ \text{inch}^3=16.3871\ \text{mL}[/tex]

Volume of block

[tex]V=0.4981\times 0.531\times 0.5839\times 16.3871\ \text{mL}[/tex]

Density is given by

[tex]\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{18}{0.4981\times 0.531\times 0.5839\times 16.3871}\\\Rightarrow \rho=7.112\ \text{g/mL}[/tex]

The density of the metal is [tex]7.112\ \text{g/mL}[/tex]. The metal here is zinc.

What is the mass of 1.0 × 10^9 molecules of aspartame?

Answers

Answer:

294.3 g/mol b.

The mass of 1.0*10^9 molecules of aspartame is 2.943*10^11 g/mol

ASPARTAME

Aspartame is  used as an artificial non-saccharide sweetener 200 times sweeter than sucrose, and is commonly used as a sugar substitute in foods and beverages.

CALCULATION

mass  of one molecule of aspartame = 294.3g/mol

mass of 1.0*10^9 molecules of aspartame =294.3*(1.0*10^9) g/mol

                                                                     =2.943*10^11 g/mol

refer https://brainly.com/question/25225559

#SPJ2

Does acid rain make new substances? Construct an argument that uses data from this investigation as evidence for your claim.

Answers

Answer:

Acid rain, like all acids, generates dissolution of chemical compounds, and reacts together with bases to be able to carry out oxide reduction reactions, which by deduction is very likely to form new substances as a result of the dissolution or acid erosion caused.

Explanation:

Acid rain is more likely to occur in large cities or large sources of pollution, since the excess of carbon dioxide in the atmosphere causes it to increase its partial pressure in a condensed way in the clouds, this is how then this cloud when being loaded with water and then generating the rain drags these masses of condensed carbon dioxide in the form of acid rain.

The degree of acidity is directly proportional to the amount of partial pressure of carbon dioxide in the atmosphere.

Insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. A bottle contains 225 mL of insulin at a concentration of 20.0 mg/mL . What is the total mass of insulin in the bottle?

Answers

The total mass of insulin in the bottle : m = 4500 mg

Further explanation

Given

225 ml of insulin

The concentration 20 mg/ml

Required

The total mass of insulin

Solution

Density is the ratio of mass per unit volume

Can be formulated

ρ = m / V

m = ρ x V

Input the value :

m = 20 mg/ml x 225 ml

m = 4500 mg

A scientist measures the standard enthalpy change for the following reaction to be -17.2 kJ : Ca(OH)2(aq) 2 HCl(aq)CaCl2(s)
2 H2O(l) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(aq) is kJ/mol.

Answers

Answer: [tex]\Delta H^{0}=-173.72[/tex] kJ/mol

Explanation: Enthalpy Change is the amount of energy in a reaction - absorption or release - at a constant pressure. So, Standard Enthalpy of Formation is how much energy is necessary to form a substance.

The standard enthalpy of formation of HCl is calculated as:

[tex]\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}[/tex]

[tex]Ca(OH)_{2}_{(aq)}+2HCl_{(aq)}[/tex] → [tex]CaCl_{2}_{(s)}+2H_{2}O_{(l)}[/tex]

Standard Enthalpy of formation for the other compounds are:

Calcium Hydroxide: [tex]\Delta H^{0}=[/tex] -1002.82 kJ/mol

Calcium chloride: [tex]\Delta H^{0}=[/tex] -795.8 kJ/mol

Water: [tex]\Delta H^{0}=[/tex] -285.83 kJ/mol

Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.

Calculating:

[tex]-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H][/tex]

[tex]-17.2=-1367.46+1002.82-2\Delta H[/tex]

[tex]2\Delta H=17.2-364.64[/tex]

[tex]\Delta H=-173.72[/tex]

So, the standard enthalpy of formation of HCl is -173.72 kJ/mol

1. How many moles of CO2 can be produced from a reaction of 10.0 moles CzHg?
2C₂H6 + 702 4 CO2 + 6H₂O

Answers

Answer:

[tex]20[/tex] moles of CO2 can be produced from a reaction of 10.0 moles C2H6

Explanation:

In this reaction -

2 moles of C₂H6 produces four molecules of Carbon dioxide (CO2)

So 1 mole of C₂H6 will produce [tex]\frac{4}{2} = 2[/tex] moles of Carbon dioxide (CO2)

Thus, 10 moles of C₂H6 will produce [tex]2 * 10 = 20[/tex] moles of Carbon dioxide (CO2)

What volume of gold would be equal in mass to a piece of copper with a volume of 121 mL? The density of gold is 19.3 g/mL; the density of copper is 8.96 g/mL.

Answers

Answer:

We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.

Explanation:

Details:

Density of Copper= 8.96 g/ml

Volume of Copper=141 ml

mass of Gold = mass of Copper

Density of Gold=19.3 g/ml

In order to solve for the mass of copper, we need to use the density formula

Density= mass/volume

Since we are to solve for the mass of copper

mass of copper= Density of Copper * Volume of Copper

mass of copper= 8.96 g/ml* 141 ml= 1263.36 g

Thus,

mass of gold=mass of copper=1263.36 g

Hence,

Using still the density formula to solve for the volume of gold,

Volume of gold=mass of gold/ Density of gold

Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL

Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper

When C2H4(g) reacts with H2O(g) to form CH3CH2OH(g) according to the following equation, energy is released into the surroundings. C2H4(g) H2O(g) CH3CH2OH(g) Is this reaction endothermic or exothermic

Answers

Answer:

Exothermic

General Formulas and Concepts:

Chemistry

Thermodynamics

Exothermic - releases heat as a productEndothermic - absorbs heat as a reactant

Explanation:

We are given that the reaction takes place between C₂H₄ (g) and H₂O (g) to form CH₃CH₂OH (g) and is releasing heat.

This means that heat would be product as it is being released during the reaction.

Therefore, we have an exothermic reaction.

Which of the following is an example of an electric force acting at a distance?

Answers

Answer:

The electric force acting at a distance can be observed when someone rubs a glass rod with something woolen then the rod is taken away from the woolen material. The piece of paper leaps into air and sticks on to the rod. This is due to the electrostatic force of attraction that the paper sticks on the glass rod.

Explanation:

Answer:

Pam rubs a glass rod with wool, then moves the rod over a pile of small paper scraps. The scraps leap into the air and stick to the rod.

Which of the following represents a compound made of five molecules
OCOS
OC205
Осо
5002

Answers

I think B I’m not sure

5. Infer if a water molecule (H20) has two hydrogen atoms and one oxygen atom, how would you describe the make- up of a carbon dioxide molecule (CO2)?

(please help)​

Answers

Answer:

The correct answer is - one carbon atom and two oxygen atoms.

Explanation:

Carbon dioxide is a gas that is present in the atmosphere of the earth. The chemical formula of carbon dioxide is CO₂. In this colorless gas, there is one molecule of carbon dioxide is made up of one atom of carbon covalently double bonded to the two atoms of the oxygens.

Thus, the make- up of a carbon dioxide molecule (CO2) includes one carbon atom and two oxygen atoms.

A 2.54 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder that contains 12.13 mL h2o. What will be the final volume reading on the graduated cylinder, in mL?

Answers

Answer: If I'm correct it's 12.54 mL but don't rely on this because I'm not sure

Explanation:

Answer:

12.49 ml

Explanation:

Density = mass / volume

Volume = mass / density

Volume of zinc = 2.54/7.14

Volume of zinc = 0.3557

Initial volume = 12.13 ml

Total volume = initial volume+ volume of zinc

Total volume = 12.13 + 0.3557

Total volume = 12.4857 = 12.49 ml

How to change 5 % W/V of NaCl to ppm , M ? molar mass = 58.5
please clear explain​

Answers

Answer:

50000ppm and 0.855M.

Explanation:

ppm is an unit of chemistry defined as the ratio between mg of solute (NaCl) and Liters of solution. Molarity, M, is the ratio between moles of NaCl and liters

A 5% (w/v) NaCl contains 5g of NaCl in 100mL of solution.

To solve the ppm of this solution we need to find the mg of NaCl and the L of solution:

mg NaCl:

5g * (1000mg / 1g) = 5000mg

L Solution:

100mL * (1L / 1000mL) = 0.100L

ppm:

5000mg / 0.100L = 50000ppm

To find molarity we need to obtain the moles of NaCl in 5g using its molar mass:

5g * (1mol / 58.5g) = 0.0855moles NaCl

Molarity:

0.0855mol NaCl / 0.100L = 0.855M

Calculate the molar mass of hafnium (II) iodide, HfI2. This is 1 Hf and 2 Iodine. No hydrogen.

Answers

It 3 iv been studying it my hole life
Other Questions
In which of the following situations would it be appropriate to use a Normal distribution to approximate probabilities for a binomial distribution with the given values of n and p? (a) n = 10, p = 0.5 (b) n = 40, p = 0.88 (c) n = 100, p = 0.2 (d) n = 100, p = 0.99 (e) n = 1000, p = 0.003 simplify the ratio 84: 36: 108: 60 45/27=x/3 solve for x pls help 3. Paige draws a blue rectangle and a red rectangle. The rectangles aresimilar. The blue rectangle is 8 inches wide and 4 inches longer than it iswide. The red rectangle is 12 inches wide. How long is the red rectangle? In the French and Indian war what were they fighting about ? Why does David Baker believe that someone other than a scientist could be the person to crack the code for protein designs? a Because scientists don't have the necessary b. Because people other than scientists are skills better qualified c. Because many people posses the problem-solving skills neededd. none of the above HELP MEEEEE THIS IS DUE TODAY!write a paragraph about having a dream for the nation in ur own wordspls don't answer if u don't know bc people have been doing thatI will mark you brainiest if u help me Got this one wrong can someone help me solve it 262 + 923 + 231 - 138 = ? CAN SOMEONE HELP ME WITH THIS Did the public agree or disagree on the District of Columbia vs Heller case in 2008? Charise's expenses for the month of July are outlined below. Car insurance: $120.54 Cell phone bill: $55.99 Groceries: $65.00 Her monthly income is $1,050.00. What percentage of her income are expenses? A skateboard park charges a $5 admission fee plus $2 for every hour spent at the park with a three-hour maximum stay. What are the input values of this problem situation? Write down the first five terms of the sequence which has the n th term A patient is in cardiac arrest. High-quality chest compressions are being given. The patient is intubated, and an IV has been started. The rhythm is asystole. What is the first drug/dose to administer? Please help!! I am struggling on cross-sections At the beginning of the year, Ms. Carter had 45 post it notes on her desk. Ms. Carter now has 60% more than the post its she started with, how many post its are on her desk now? landscape designer has 4/5 ton of mulch to divide equally among 8 customers. how much mulch will each customer get? What do people purchase as a form of risk management to protect themselves from losing a lot of money in the event something happens to them or their property?1. Deductibles2. Liability3. Warranty4. Insurance The embryonic stage where the embryo cells are arranged into a hallow ball is called A) MorulaB) BlastulaC) GrastulaD) Fetus PLEASE NO TIME WAISTERS