In all of the following examples, the quantity of the resource
being used by humans is affected EXCEPT–
A petroleum taken from the ground and burned for fuel.

B fresh water used for agriculture, recreation, and
tourism.

C wind power used to provide energy for homes and
businesses.

D metal ores mined and used to create building
materials.

Answer:

according to the new geometry lesson alcometry which will after 11 years in geometry

Answer:

a

Explanation:

because it has  compact  molecules  

Explanation:

Hope ir helpful

brainliest me please

Answer:

98.13m

Explanation:

Complete question

Daniel is 50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building

CHECK THE ATTACHMENT

From the figure, using trigonometry

Tan(θ ) = opposite/adjacent

Where Angle (θ )= 63°

Opposite= X = height of the building

Adjacent= 50 m

Then substitute the values we have

Tan(63)= X/50

1.9626= X/50

X= 1.9626 × 50

X= 98.13m

Hence, the height of the building is 98.13m

Answer:

no it will not glow hope help you stay happy

[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTIONS}}}}}}} [/tex]

In an experiment to measure the specific heat capacity of copper, 0.02 kg of water at 70°C is poured into a copper calorimeter (with a stirrer) of mass 0.16 kg at 15°C. After stirring, the final temperature is found to be 45°C. If the specific heat of water is 4,200 J/kg/°C,

[tex] \blue{\huge{\red{\boxed{\green{\mathfrak{GIVEN}}}}}} [/tex]

WATER:-

Mass :- 0.02 kg at 70°C

Specific Heat Of Water is 4,200 J/kg°C,

COPPER:-

MASS:- mass 0.16 kg at 15°C

Temperatures r according to the part !

[tex]{\huge{\huge{\bold{\green{To \: Find :- }}}}}[/tex]

what is the quantity of heat released per kg of water per 1°C fall in temperature?

Calculate the heat energy released by water in the experiment in cooling from 70°C to 45°C.

Assuming that the heat released by water is entirely used to raise the temperature of calorimeter from 15°C to 45°C) calculate the specific heat capacity of copper.

[tex] \huge\red{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}[/tex]

[tex]{\blue{\star{\red{Part \: 1 :- What \: is \: the \: quantity \: of heat \: released \: per \: kg \: of \: w ater \: per \: 1°C \: fall \: in \: temperature }}}}[/tex]

[tex]\orange{Specific \: \: Heat}[/tex]

It is the amount of the heat released by unit mass of the body per 1°C fall in temperature.

It is the amount of the heat absorbed by the unit mass of the body per 1°C rise in temperature

So quantity of heat released per kg of water per 1°C fall in temperature is equal to the specific heat of the water which is 4,200 J/kg°C,

[tex]{\red{\star{\blue{Part \:2 :-\: Calculate \: the \: heat \: energy \: released \: by \: water \: in \: the \: experiment \: in \: cooling \: from \: 70°C \: to \: 45°C. }}}}[/tex]

MASS OF WATER --> 0.02 kg

INITIAL TEMPERATURE--> 70°C

FINAL TEMPERATURE--> 45°C

CHANGE IN TEMPERATURE--> (45-70)°C =(- 25)°C

SPECIFIC HEAT OF WATER--> 4200 J/ kg °C

[tex]Q = mc\triangle T \\ \\ Q = 0.02 \times 4200 \times ( -25) \\ \frac{2}{100} \times 4200 \times( - 25) =Q \\ ( - 50) \times 42 = Q \\ Q = ( - 2100) \: joules[/tex]

NEGATIVE INDICATES THAT HEAT IS RELEASED BY THE BODY!

IT MEANS COOLING HAS BEEN TAKEN PLACED.

[tex]{\red{\star{\green{Part \:2 :-\:Assuming \: that \: the \: heat \: released \: by \: water}}}} \\ \\ {\green{is \: entirely \: used \: to \: raise \: the temp \: of \: calorimeter \: from \: 15°C \: to \: 45°C }} \\ \\{\green{ calculate \: the \: specific \: heat \: capacity \: of \: copper.}}[/tex]

MASS OF COPPER :- 0.16 kg

INITIAL TEMPERATURE:- 15°C

FINAL TEMPERATURE:- 45°C

CHANGE IN TEMPERATURE--> (45-15)°C = 30°C

AMOUNT OF HEAT RELEASED BY WATER --> 2100 J ( From second part)

[tex]Q = mc\triangle T \\ \\ 2100 = 0.16 \times c \times 30 \\ 70 = 0.16 \times c \\ \\ c = \frac{7000}{16} \\ c = 437.5 \: \frac{J }{kg°C} [/tex]

The heat energy released by water in the experiment in cooling from 70°C to 45°C is 2100 joule.

The specific heat of copper is 437.5 J/kg/°C.

The amount of heat needed to raise a substance's temperature by one degree Celsius per gram is known as its specific heat. Calories or joules per gram per degree Celsius are used as the units of specific heat.

The heat energy released by water in the experiment in cooling from 70°C to 45°C is =

Mass of water × specific heat of water × Change is temperature

= 0.02 kg ×  4,200 J/kg/°C × (70°C - 45°C)

= 2100 joule.

This energy is absorbed by the copper calorimeter (with a stirrer).

Hence, specific heat of copper is = energy absorbed/ ( mass of  copper calorimeter (with a stirrer) × Change in temperature)

= 2100 joule ÷ { 0.16 × ( 45°C - 15°C)} J/kg/°C

= 437.5 J/kg/°C.

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Your question is incomplete, but most probably the question was:

In an experiment to measure the specific heat capacity of copper, 0.02 kg of water at 70°C is poured into a copper calorimeter (with a stirrer) of mass 0.16 kg at 15°C. After stirring, the final temperature is found to be 45°C. If the specific heat of water is 4,200 J/kg/°C,​

calculate the heat energy released by water in the experiment in cooling from 70°C to 45°C.

calculate specific heat of copper.

D) There will be less available for other living things.

There will be less available for other living things is the most likely effect on the amount of water and is denoted as option D.

This is a compound which is regarded as a universal solvent and can be found in rivers, streams etc.

People moving into and living in the area means water will be used which will make it less available for other living things.

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The answer is five dots.

sorry i  meant three dots not five

Answer:

Hands down, the strong nuclear force.

Answer:

strong nuclear force, hope it helps!

Explanation:

Actually, gravity is the weakest of the four fundamental forces. Ordered from strongest to weakest, the forces are 1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity.

source: https://wtamu.edu/~cbaird/sq/2013/05/22/why-is-gravity-the-strongest-force/

Answer:

20000000000)0000000000000

Answer:

8892 ml = 8892 gm = 8892000 mg

1 ml = 1 gram

8892 ml = 8892 gram

1 gram or ml = 1000 milligram

8892 ml = 8892 × 1000 = 8892000 milligram

hope this helps

have a good day :)

Explanation:

remember: 1 kilogram = 1000 gram = 1000000 milligram.

Milliliter is expressed same as gram and liter is expressed same as kilogram.

1 meter = 100 cm, 1 kilometer = 1000 meter,

1 cm = 10 millimeter.

You can't convert ml to gm unless you know the substance. They're all different.

Answer:

V of x is the velocity on the x graph so it is false

Hope it helps

Answer: False

Explanation:

Vx can't be acceleration because acceleration is velocity over time not distance over time (the equation for speed)

Answer:

E) 147 V

Explanation:

Ra+Rb+Rc = 14.0

V = IR

V = (10.5)(14.0)

V = 147 V

The potential difference across the source will be c)12V

Ohm's law states that  the current through a conductor between two points is directly proportional to the voltage across the two points .

since , R(A) , R(B) AND R(C) are in parallel combination , hence  equivalent

resistance of the circuit will be

1/R = 1/R(A) + 1/ R(B) + 1/ R(C)

1/R= 1/2 + 1/4 +1/8

1/R = 7/8

R = 8/7 ohm

from ohm's law

Voltage = current * resistance

V( source ) = current (in circuit ) * R (equivalent resistance)

V = 10.5 * (8/7)

V = 12 V

The potential difference across the source will be c) 12V

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Answer:

At 400 m the potential energy of the mountain climber doubled the initial value.

Explanation:

Given;

initial height of the mountain climber = 200 m

final height of the mountain climber, = 400 m

The potential energy of the mountain climber is calculated as;

Potential energy, P.E = mgh

At 200 m, P.E₁ = mg x 200 = 200mg

At 400 m, P.E₂ = mg x 400 = 400mg

Then, at 400 m, P.E₂ = 2 x 200mg = 2 x P.E₁

Therefore, at 400 m the potential energy of the mountain climber doubled the initial value.

Answer:

Explanation:

Initial velocity is 0. In the equation v = v0+at where v0 is the initial velocity of 0, we only have to fill in -9.8 for a and 2 for t to get the velocity after 2 seconds -19.6 m/s; after 5 seconds, when it hits the ground, a = -9.8 and t = 5 to give a velocity of -49 m/s. Gravity pulls down everything at the same rate, it doesn't matter whether we drop a feather or an elephant from the window!

Answer: C

Explanation: according to the law voltages = to current and resistance

Answer:

I think the answer would be c

Explanation:

A. is not scientific

B. is subjective, so it can't be scientific.

C. can be studied with an experiment

D. relates to regulations, not science

Answer:

The depth to which the hydrometer sinks is approximately 24.07 cm

Explanation:

The given parameters are;

The diameter of the hydrometer tube, d = 2.3 cm

The mass of the content of the tube, m = 80 g

The density of the liquid in which the tube floats, ρ = 800 kg/m³

By Archimedes' principle, the up thrust (buoyancy) force acting on the hydrometer = The weight of the displaced liquid

When the hydrometer floats, the up-thrust is equal to the weight of the hydrometer which by Archimedes' principle, is equal to the weight of the volume of the liquid displaced by the hydrometer

Therefore;

The weight of the liquid displaced = The weight of the hydrometer, W = m·g

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

∴ W = 80 g × g

The volume of the liquid that has a mass of 80 g (0.08 kg), V = m/ρ

V = 0.08 kg/(800 kg/m³) = 0.0001 m³ = 0.0001 m³ × 1 × 10⁶ cm³/m³ = 100 cm³

The volume of the liquid displaced = 100 cm³ = The volume of the hydrometer submerged, [tex]V_h[/tex]

[tex]V_h[/tex] = A × h

Where;

A = The cross-sectional area of the tube = π·d²/4

h = The depth to which the hydrometer sinks

h = [tex]V_h[/tex]/A

∴ h = 100 cm³/( π × 2.3²/4 cm²) ≈ 24.07 cm

The depth to which the tube sinks, h ≈ 24.07 cm.

coal or natural gas i think

Answer:

[tex]624\:\mathrm{m}[/tex]

Explanation:

We can use kinematics equation [tex]\Delta x =v_it+\frac{1}{2}at^2[/tex].

What we're given:

Solving for [tex]\Delta x[/tex]:

[tex]\Delta x=100\cdot 12+\frac{1}{2}\cdot -8\cdot 12^2=\boxed{624\:\mathrm{m}}[/tex]

Answer:

21.6m

Explanation:

Distance=speed×time

=1.2m/s×18min

=21.6m

Hope this helps u

Answer:

Explanation:

1 minute = 60 seconds

18 minutes = 18 * 60 sec = 1080 seconds

1 second allows 1.2 meters of a step

1080 second = x

1 / 1080 = 1.2 / x          Cross multiply

x = 1.2 * 1080

x = 1296 meters

I live 1296 meters from the school.

Answer:

Explanation:

The mass of the car doesn't matter because On a flat curve the mass of the car does not affect the speed at which it can stay on the curve. You would need the mass if you were solving the the centripetal force acting on the car, but not the acceleration.

[tex]a=\frac{v^2}{r}[/tex] and filling in

[tex]a=\frac{(8.5)^2}{48.0}[/tex] and we need 2 significant digits in our answer. That means that

a = 1.5 m/sec²

Explanation:

Now, looking down the solenoid tube determine what direction is the winding. If clockwise in relation to the positive wire then is the south pole, if anti-clockwise then is the north pole. So, to summarize the magnetic south pole is always clockwise in relation to the positive wire.

Answer:

F = 3000 N

Explanation:

Let's use the relationship between momentum and momentum

         I =  Δp

         F t = m v_f - m v₀

As the body when bouncing reaches the same height from which it begins to fall, the modulus of speed is the same, but in the opposite direction,

         v_f = - v₀ = v

         F t = m 2v

         F = 2 m v / t          (1)

This is the contact time t = 0.5 ms = 0.5 10⁻³ s

Let's use the kinematics to find the velocity at the point of touching the plate, as the total travel time is 3.0 s, the descent time must be half the total time

          t = 1.5 s

as the body solved its initial velocity is zero

         v = v₀ + g t

         v = g t

         v = 9.8  1.5

         v = 14.7 m / s

we substitute in equation 1

         F = 2 0.051 14.7 / 0.5 10-3

         F = 2,999 103 N

        F = 3000 N

The average force that the plate exerted on the ball is 3,000 N.

The given parameters;

The velocity of the ball is calculated as follows;

[tex]v = g\Delta t\\\\v = 9.8 \times 3\\\\v = 29.4 \ m/s[/tex]

The average force that the plate exerted on the ball is calculated as follows;

[tex]F = \frac{mv}{t} \\\\F = \frac{0.051 \times 29.4}{0.5 \times 10^{-3} } \\\\F = 3,000 \ N[/tex]

Thus, the average force that the plate exerted on the ball is 3,000 N.

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Answer:

Algunos se mueven en dos direcciones y algunos se mueven en las cuatro direcciones.

Explicación:

Para investigar la posición del cuerpo en general, la posición de la cabeza, la posición de los brazos y manos y los pies tienen algunos movimientos específicos. Algunos se mueven hacia arriba y hacia abajo significa en dos direcciones mientras que el otro se mueve en todas las direcciones. Los brazos se mueven solo hacia adelante y hacia atrás, mientras que, por otro lado, los pies, la mano y la cabeza se mueven hacia la izquierda, la derecha y hacia arriba y hacia abajo.

use the formula

v= u+ at

v is final velocity , u is initial velocity , a is acceleration and t is time

put the values

20 = 0+ a×5

a = 4 m/s²

Answer:

Initial velocity(u)=0

Final velocity(v) =20 meters/ second

Time(t)=5

Acceleration (a)=?

a=v-u/t

a=20-0/5

a=20/5

a=4meters/second

Answer:

False.

Explanation:

The plants rely on animals to spread their seeds, thats why they make fruits so the animals eat em, the seeds are strong enough to survive the animals stomach and come out the other end.