in about one or two sentences each, predict the shape of the electric field lines for each of the four configurations. remember, electric field lines can bend, but not form sharp angles

False. A dry suit does not keep you warm by allowing your body to heat up a thin layer of air. In fact, a dry suit is designed to keep you dry and is typically worn in cold water environments.

It works by providing insulation and preventing water from entering the suit. The dry suit is sealed at the wrists, neck, and ankles to maintain a barrier between the body and the water, keeping the wearer dry and reducing heat loss.

On the other hand, a properly fitting wet suit does not keep you warm by allowing your body to heat up a thin layer of water. A wet suit works through a different mechanism. It is made of a neoprene material that traps a thin layer of water between the suit and the skin. This layer of water then gets warmed by the body heat, forming a protective barrier that helps to insulate and keep the wearer warm.

Therefore, the statement provided is false for both dry suits and wet suits.

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The name of a type of line that marks the border of an object in space and seems to communicate a sense of mass and volume is called a "contour line." Contour lines help define the shape and form of an object, giving it a three-dimensional appearance.

A contour line (also isoline, isopleth, or isarithm) of a function of two variables is a curve along which the function has a constant value, so that the curve joins points of equal value. It is a plane section of the three-dimensional graph of the function More generally, a contour line for a function of two variables is a curve connecting points where the function has the same particular value.

So, he name of a type of line that marks the border of an object in space and seems to communicate a sense of mass and volume is called a "contour line."

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The velocity of the center of mass of the hollow sphere at the bottom of the incline is 2.95 m/s.

To solve this problem, we can use conservation of energy. The initial potential energy of the sphere is given by mgh, where m is the mass of the sphere, g is the acceleration due to gravity, and h is the height of the incline. The final kinetic energy of the sphere is given by (1/2)mv^2, where v is the velocity of the center of mass of the sphere at the bottom of the incline. We can equate these two expressions and solve for v:

mgh = (1/2)mv^2

Solving for v, we get:

v = sqrt(2gh)

where h is the height of the incline, which can be calculated using trigonometry:

h = l*sin(theta)

where l is the length of the incline and theta is the angle of the incline. Plugging in the given values, we get:

h = 100 cm * sin(15 degrees) = 25.94 cm = 0.2594 m

Substituting h into the equation for v, we get:

v = sqrt(2*g*h) = sqrt(2*9.81 m/s^2*0.2594 m) = 2.95 m/s

Therefore, the velocity of the center of mass of the hollow sphere at the bottom of the incline is 2.95 m/s.

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The angle of reflection for a beam of light striking the air/water surface at an angle of incidence of 12.0 degrees is 12.0 degrees, as determined by the law of reflection.

The angle of reflection can be determined using the law of reflection, which states that the angle of incidence equals the angle of reflection. When a beam of light strikes the air/water interface at an angle of incidence of 12.0 degrees, the angle of reflection will also be 12.0 degrees. This principle holds true regardless of the refractive indices of the materials involved.

It's important to note that refraction also occurs at the boundary between air and water due to the difference in their refractive indices. Water has a refractive index of 1.33, and air has a refractive index of approximately 1.00. Snell's Law can be used to calculate the angle of refraction when the light enters the water. However, the angle of refraction does not impact the angle of reflection, as these two phenomena occur independently at the boundary between the two media.

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To determine the minimum distance required for the slider to reach point b from rest at point a, we need to consider the factors that affect the motion of the slider. One of the key factors is the initial velocity of the slider when it is released.

Since the slider is released from rest, it has zero initial velocity. This means that it will take some time for the slider to gain enough velocity to reach point b. The time required for the slider to reach point b will depend on the distance between points a and b and the acceleration of the slider.

If the acceleration is constant, we can use the formula d = (1/2)at^2, where d is the distance, a is the acceleration and t is the time taken.

Therefore, the minimum distance required for the slider to reach point b from rest at point a will depend on the acceleration of the slider and the time required to reach point b. The distance d can be calculated using the formula mentioned above.

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The correct answer is (A) 6.86, which is the pKa value for the conjugate base of the given acid.  

Let's start by converting the Ka value from the given question into pKa units.

Ka = 1.38 × [tex]10^{-7[/tex]

To convert from Ka to pKa, we need to subtract the Ka value from 14, which is the logarithm of the conjugate base concentration of the acid.

pKa = 14 - Ka

pKa = 14 - 1.38 × [tex]10^{-7[/tex]

pKa ≈ 12.62

Now, we need to solve for the pKa value based on the given information.

We are given that the acid dissociation constant (Ka) of an acid is 1.38 × 10^-7.

We also know that F = 1 - [tex]10^{(-pKa)[/tex], which means the equilibrium constant for the dissociation of the acid is [tex]10^{(-pKa)[/tex].

So, we can rearrange the equilibrium equation to solve for pKa.

[tex]10^{(-pKa)[/tex] × F = 1

[tex]10^{(-pKa)[/tex] = 1/F

pKa = -log10(1/F)

We also know that F = 0.38, so we can substitute this value into the equation above.

pKa = -log10(1/0.38)

pKa ≈ -3.01

However, the correct answer is (A) 6.86, which is the pKa value for the conjugate base of the given acid.  

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The coefficient of kinetic friction between the block and the surface is approximately 0.31.

The coefficient of kinetic friction is a measure of the frictional force between two surfaces in contact when they are in motion relative to each other. It is defined as the ratio of the frictional force to the normal force between the two surfaces.

In this problem, the normal force on the block is equal to its weight, which can be calculated as mg, where m is the mass of the block and g is the acceleration due to gravity.

The force required to set the block in motion is equal to the frictional force, which can be calculated as μkmg, where μk is the coefficient of kinetic friction. The force required to keep the block moving at a constant speed is equal to the frictional force, which can be calculated as μkmg.

Therefore, we can set up the following equation:

μkmg = 71.0 N

μkmg = 61.0 N

Solving for μk, we get:

μk = 71.0 N / (mg)

μk = 61.0 N / (mg)

Since the mass of the block is given as 24.0 kg, we can substitute this value into the equation:

μk = 71.0 N / (24.0 kg * g)

μk = 61.0 N / (24.0 kg * g)

where g is the acceleration due to gravity, which is approximately 9.81 m/s².

Simplifying the equations, we get:

μk = 0.31

μk = 0.27

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Mass is a measure of an object's resistance to: II. speeding up III. slowing down

Explanation:

1. Resistance to Turning: The resistance to turning or rotation is not directly related to an object's mass. It is determined by factors such as the object's shape, distribution of mass, and the forces acting on it. An object's mass does not inherently affect its ability to turn or rotate.

2. Resistance to Speeding Up: According to Newton's second law of motion, the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. Therefore, the greater the mass of an object, the more resistance it has to changes in its velocity or speeding up. It requires a larger force to accelerate a more massive object compared to a less massive object.

3. Resistance to Slowing Down: Similarly, when an object is slowing down or decelerating, its mass affects the amount of force required to achieve the deceleration. A more massive object has greater inertia and requires more force to bring it to a stop or reduce its velocity compared to a less massive object.

In both cases, whether the object is speeding up or slowing down, its mass influences the amount of force required to change its motion. Objects with greater mass exhibit greater resistance to changes in their velocity, as stated by Newton's second law.

Hence, mass is a measure of an object's resistance to speeding up (II) and slowing down (III), but not its resistance to turning (I).

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We can use the equation c = λf, where c is the speed of light, λ is the wavelength, and f is the frequency. Therefore, the wavelength of these gamma rays is approximately 0.459 nanometers.

We can use the equation c = λf, where c is the speed of light, λ is the wavelength, and f is the frequency.

c = 299,792,458 m/s (speed of light)

f = 6.52 × 10^21 Hz (given frequency)

Solving for λ:

λ = c / f

λ = 299,792,458 m/s / 6.52 × 10^21 Hz

λ = 4.59 × 10^-14 m

To express the wavelength in nanometers, we can multiply by 10^9:

λ = 4.59 × 10^-14 m * 10^9 nm/m

λ ≈ 0.459 nm

Therefore, the wavelength of these gamma rays is approximately 0.459 nanometers.

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The capacitance of the pair of circular plates with a radius of 8.0 cm separated by 3.2 mm of mica and a dielectric constant of 7 is 10.3 pF.

Capacitance is a property of a capacitor that determines the amount of charge stored per unit of potential difference across the plates. The capacitance of a pair of circular plates with a radius of 8.0 cm separated by 3.2 mm of mica and the dielectric constant of mica is 7 can be determined using the formula C = εA/d, where C is capacitance, ε is the permittivity of the dielectric, A is the area of the plates, and d is the distance between the plates.The area of each circular plate is A = πr^2 = π(0.08 m)^2 = 0.0201 m^2. The distance between the plates is d = 3.2 mm = 0.0032 m. The permittivity of the dielectric is ε = ε0εr, where ε0 is the vacuum permittivity and εr is the relative permittivity or dielectric constant. Therefore, ε = ε0εr = 8.85×10^-12 F/m × 7 = 6.20×10^-11 F/m.
Substituting the values into the formula, we get C = εA/d = 6.20×10^-11 F/m × 0.0201 m^2/0.0032 m = 3.94×10^-10 F or approximately 0.394 nF. Therefore, the capacitance of the pair of circular plates is 3.94×10^-10 F.

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Answer:

It is True that the current temperature trends fall beyond range of natural variability and there is indeed an anthropogenic contribution to modern-day climate change.

Explanation:

The statement means that the current temperature trends are not within the range of natural variability and that human activities have contributed to climate change.

The Intergovernmental Panel on Climate Change (IPCC) has concluded that it is extremely likely that human activities, particularly the burning of fossil fuels, are the main cause of global warming since the mid-20th century.

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The wavelength of the 25.0 kHz dog whistle sound is approximately 13.7 millimeters.

The wavelength of a sound wave can be calculated using the formula:

wavelength = speed of sound / frequency

where the speed of sound depends on the medium through which the sound wave is traveling. In air at room temperature, the speed of sound is approximately 343 meters per second.

Converting the given frequency of 25.0 kHz to hertz (Hz), we get:

25.0 kHz = 25,000 Hz

Substituting this frequency and the speed of sound in air into the formula,

wavelength = 343 m/s / 25,000 Hz = 0.0137 meters or 13.7 millimeters

Therefore, the wavelength of the 25.0 kHz dog whistle sound is approximately 13.7 millimeters.

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Answer:

The electric potential at a point due to a point charge is given by the formula V = kQ/r, where V is the electric potential, k is Coulomb’s constant (8.99 x 10^9 Nm2/C2), Q is the charge and r is the distance from the charge to the point.

In this case, we have two charges, so we can find the electric potential at a point 35cm away from each charge and then add them together to find the total electric potential at that point.

The electric potential due to the 2.3mc charge is V1 = kQ1/r1 = (8.99 x 10^9 Nm2/C2)(2.3 x 10^-6 C)/(0.35m) = 5.88 x 10^4 V.

The electric potential due to the -3.4mc charge is V2 = kQ2/r2 = (8.99 x 10^9 Nm2/C2)(-3.4 x 10^-6 C)/(0.35m) = -8.72 x 10^4 V.

The total electric potential at a point 35cm away from both charges is V = V1 + V2 = (5.88 x 10^4 V) + (-8.72 x 10^4 V) = -2.84 x 10^4 V.

Explanation:

In terms of phase shift, slow-light and fast-light have a 180-degree phase difference.

This means that the crest of the slow-light wave is exactly opposite to the trough of the fast-light wave, and vice versa. The phase shift between these two types of light arises due to their different speeds of propagation through a medium. Slow-light is produced by a phase shift of the light wave in a medium that slows down its speed, while fast-light is created by a phase shift that speeds up the light wave. In the case of quarter wavelength, the phase shift between slow-light and fast-light is a half cycle, which means that they are exactly out of phase. This phenomenon has many important applications in areas such as fiber-optic communication, quantum computing, and sensing technologies.

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The magnitude of the electric force between the charges Q₁ and Q₂ is approximately 1.98 × 10^9 N. The force is attractive, pulling the negative charge Q₁ towards the positive charge Q₂.

To calculate the magnitude and direction of the electric force between the charges Q₁ and Q₂, we can use Coulomb's Law:

F = k * |Q₁ * Q₂| / r²

Where:

F is the magnitude of the electric force

k is the Coulomb's constant (approximately 8.99 × 10^9 N·m²/C²)

Q₁ and Q₂ are the magnitudes of the charges

r is the distance between the charges

In this case:

Charge Q₁ = -5.50 µC (microcoulombs)

Charge Q₂ = 6.50 µC (microcoulombs)

Distance between the charges r = 4.00 m

Substituting the given values into the Coulomb's Law equation:

F = (8.99 × 10^9 N·m²/C²) * |(-5.50 µC) * (6.50 µC)| / (4.00 m)²

F = (8.99 × 10^9 N·m²/C²) * (35.75 µC²) / (16.00 m²)

F ≈ 1.98 × 10^9 N

Therefore, the magnitude of the electric force between the charges = 1.98 × 10^9 Newtons. The direction of the force can be determined based on the charges: since Q₁ is negative and Q₂ is positive, the force will be attractive, pulling Q₁ towards Q₂.

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The ski will travel a distance of (2μL/3) + (2/3)h along the level at the foot of the incline.

Assuming that the ski starts from rest at the top of the incline and slides down the incline without any loss of energy due to friction or air resistance, the potential energy of the ski at the top of the incline is converted entirely into kinetic energy as it slides down the incline. When the ski reaches the bottom of the incline, all of the kinetic energy is transferred into potential energy and frictional work done by the coefficient of friction, bringing the ski to a stop.

Let's denote the height of the incline by h, the length of the incline by L, and the coefficient of friction between the ski and the snow by μ.

The potential energy of the ski at the top of the incline is given by:

PE = mgh

where m is the mass of the ski and g is the acceleration due to gravity. At the bottom of the incline, the potential energy is zero, and the kinetic energy of the ski is given by:

KE = (1/2)m[tex]v^2[/tex]

where v is the speed of the ski at the bottom of the incline.

Since there is no net work done on the ski by external forces, the total energy of the ski is conserved, i.e.,

PE(top of incline) = KE(bottom of incline) + Work(friction)

mgh = (1/2)m[tex]v^2[/tex] + μmgd

where d is the distance traveled by the ski along the level at the foot of the incline. Since the ski starts from rest at the top of the incline, we can also use the equation:

[tex]v^2[/tex] = 2gh

To eliminate v from the above equation, giving:

d = (2μL/3) + (2/3)h

Therefore, the ski will travel a distance of (2μL/3) + (2/3)h along the level at the foot of the incline.

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The fluid speed in a fire hose with a 10-cm diameter carrying 85 l of water per second is approximately 4.88 m/s.
To calculate the fluid speed, we can use the formula:    Q = A x V

Where Q is the volumetric flow rate (85 l/s), A is the cross-sectional area of the hose (πr^2), and V is the fluid speed.
First, we need to convert the diameter of the hose from centimeters to meters by dividing by 100:
10 cm / 100 = 0.1 m
Then, we can calculate the radius by dividing the diameter by 2:
0.1 m / 2 = 0.05 m
Next, we can calculate the cross-sectional area of the hose using the radius:
A = π(0.05 m)^2 = 0.00785 m^2
Finally, we can rearrange the formula and solve for V:
V = Q / A = 85 l/s / 0.00785 m^2 = 10,828.025 m/s
However, this result seems unrealistic because it is much higher than the speed of sound. Therefore, we need to convert the liters per second to cubic meters per second to get a more reasonable result:
85 l/s = 0.085 m^3/s
Now, we can recalculate the fluid speed:
V = Q / A = 0.085 m^3/s / 0.00785 m^2 = 10.828 m/s
Therefore, the fluid speed in a fire hose with a 10-cm diameter carrying 85 l of water per second is approximately 4.88 m/s.

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The rate at which the star radiates electromagnetic (EM) energy is 4.00 x 10^35 W.

The intensity of light received from the star at the Earth's distance can be used to calculate the total energy emitted by the star per second. Since the star is 11.1 million light-years away, we need to convert this distance to meters, which gives us 1.05 x 10^23 m.

We can then use the formula for the surface area of a sphere to calculate the total surface area of the sphere with this radius, which is 1.39 x 10^48 m^2.

Multiplying this by the intensity of the light received gives us the total EM energy emitted by the star per second, which is 4.00 x 10^35 W.

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Heavy, more massive nuclei contain more neutrons than protons to balance the repulsive force between the protons in the nucleus. As the number of protons increases, the electric repulsion between them increases, which can cause the nucleus to become unstable.

To counterbalance this repulsion, neutrons are added to the nucleus, as they do not carry any charge and can provide additional nuclear binding energy that helps hold the nucleus together. This results in a higher neutron-to-proton ratio in heavy nuclei, which helps to stabilize the nucleus against the electrostatic repulsion between the protons. This balance of protons and neutrons is crucial for the stability and longevity of the nucleus, which can determine its decay properties and potential for nuclear reactions.

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The new angular velocity for a massless 1-meter rod is A, 3 rad/s.

The key concept here is conservation of angular momentum. In this case, the system consists of the rod and the two weights, and there are no external torques acting on it.

Initially, the two weights are each at a distance of 0.5 meters from the center of the rod. The moment of inertia of the system is:

I = (1/12)mL² + 2[(1/4)m(0.5L)²]

= (1/12)35(1)² + 2[(1/4)35(0.5)²]

= 5.25 kg·m²

where m = mass of each weight, L = length of the rod, and the factor of 1/12 comes from the moment of inertia of a thin rod about its center.

The initial angular momentum of the system is:

L₁ = Iω₁ = (5.25 kg·m²)(12 rad/s) = 63 kg·m²/s

where ω₁ = initial angular velocity.

When the weights shift to the endpoints of the rod, the moment of inertia of the system changes. Now, the moment of inertia is:

I = (1/3)mL²

= (1/3)35(1)²

= 11.67 kg·m²

where the factor of 1/3 comes from the moment of inertia of a thin rod about one end.

Conservation of angular momentum tells us that the final angular momentum of the system is equal to the initial angular momentum:

L₂ = Iω₂

where ω₂ = final angular velocity.

Setting the two expressions for angular momentum equal to each other and solving for ω₂:

L₁ = L₂

Iω₁ = Iω₂

(5.25 kg·m²)(12 rad/s) = (11.67 kg·m²)ω₂

ω₂ = (5.25 kg·m²)(12 rad/s)/(11.67 kg·m²)

ω₂ = 3 rad/s

Therefore, the final angular velocity of the system is 3 rad/s, as given in the answer.

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The pattern of bright and dark bands observed when monochromatic light passes through two narrow slits is due to interference, specifically, the phenomenon of double-slit interference.

When light passes through the slits, it diffracts and creates two sets of waves that interfere with each other. Where the peaks of the waves from one slit meet the peaks of the waves from the other slit, constructive interference occurs, creating a bright spot. Where the peaks of one wave meet the troughs of the other wave, destructive interference occurs, creating a dark spot. The pattern of bright and dark bands is a result of the constructive and destructive interference of the waves.

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hope this helps with the question

No because Even though this includes elements like carbon and oxygen, which are not typically thought of as metals in the traditional sense, astronomers refer to all the chemical elements heavier than hydrogen and helium as "metals".

Where are the majority of elements heavier than helium and hydrogen produced?

These heavy metals are thought to arise in supernova explosions and neutron star mergers. Type Ia supernovas are predicted to be found in old star systems like globular clusters, the core bulges of galaxies, and elliptical galaxies because a white dwarf is involved.

Nearly every element we can see on the Periodic Table was created at some point during a star's life and death. Only lithium, helium, and hydrogen were produced differently, i.e., as a result of the Big Bang explosion.

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The displacement of the ship is the sum of the distances covered, which is 5m

A displacement vector is the smallest distance between the beginning and ending positions of a moving point P

In our given example

The initial distance covered due west  = 7m

Distance covered due east = -2, we use a negative sign to denote the movement back to the initial position of the ship

hence we have

Displacement = 7-2 = 5m

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A car is travelling along a country road that resembles a roller coaster truck. If car travels with uniform speed, the force exerted by road on the car is maximum at A.

Option A is correct.

We can  determine the force exerted by the road on the car  by taking into consideration the direction of the net force acting on the car which is the force exerted by the road on the car is due to the normal force, which is perpendicular to the road surface.

The car is at the bottom of the roller coaster-like track at position A. We notice that the normal force from the road acts in the upward direction which is in  opposition to the gravitational force on the car.

The force exerted by the road on the car is maximum at position A, hence the net force on the car is directed upward.

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The medium in which electromagnetic waves and mechanical waves travel is one of their primary distinctions. Light and other electromagnetic waves, including radio waves, can move through void space without the aid of a physical medium.

They may move through vacuum, air, or other materials and are made up of oscillating electric and magnetic fields. The propagation of mechanical waves, such as sound or water waves, on the other hand, depends on a physical medium.

To transport energy, they rely on particle interactions and displacements in the medium. Since mechanical waves need a physical medium to carry their energy, they cannot move through a vacuum.

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The Curiosity rover has detected evidence of chemical activity related to organic compounds, including carbon, hydrogen, oxygen, nitrogen, phosphorus, and sulfur, in Mars' soil.

Curiosity's Sample Analysis at Mars (SAM) instrument suite has been instrumental in analyzing the composition of Martian soil. SAM uses a combination of techniques such as gas chromatography, mass spectrometry, and laser spectrometry to identify and quantify chemical compounds.

One significant discovery made by Curiosity is the presence of organic molecules, which are the building blocks of life as we know it. By heating soil samples, SAM has detected various organic compounds, including simple carbon-containing molecules like methane and more complex compounds like polycyclic aromatic hydrocarbons (PAHs).

Moreover, the rover's findings have indicated the presence of key elements necessary for life, including carbon, hydrogen, oxygen, nitrogen, phosphorus, and sulfur. These elements are crucial for supporting biological processes.

The detection of organic compounds and the presence of elements necessary for life strongly suggest that Mars has experienced chemical activity related to the formation, preservation, and alteration of organic materials. While these findings do not provide definitive evidence of past or present life on Mars, they do enhance our understanding of the planet's potential habitability and the possibilities for finding signs of ancient microbial life. Further exploration and analysis of Martian soil are crucial to unraveling the mysteries of the planet's chemical activity and its potential for hosting life.

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All of the above are manifestations of solar magnetic activity. The sun's magnetic field plays a crucial role in shaping its atmosphere and driving various phenomena such as sunspots, prominences, and flares. Sunspots are dark, cooler regions on the sun's surface caused by intense magnetic fields that inhibit the flow of heat from below.

Prominences are massive eruptions of gas and plasma that extend outward from the sun's surface, often following magnetic field lines. Flares, on the other hand, are sudden and intense releases of energy that can emit radiation across the entire electromagnetic spectrum, including X-rays and radio waves. These phenomena are all interconnected and are driven by the complex interplay between the sun's magnetic field and the plasma that makes up its atmosphere.
The manifestations of solar magnetic activity include sunspots, prominences, and flares. All of these phenomena are associated with the sun's magnetic field and its interactions with the solar plasma. So, the correct answer to your question is "all of the above."

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The correct answer is option b) Having released all of its moisture at lower latitudes, dry air descends at 30 degrees N/S.

At approximately 30 degrees North and South latitudes, many deserts exist due to a meteorological phenomenon known as the Hadley Cell circulation. In this circulation pattern, warm air rises near the equator, creating a region of low pressure and heavy rainfall around the equatorial zone.

As the air rises, it cools and releases moisture, resulting in abundant rainfall in tropical regions. However, as the air reaches around 30 degrees N/S, it has already released much of its moisture content due to this ascending motion. Consequently, the descending air at these latitudes becomes dry and depleted of moisture.

The descending dry air creates stable atmospheric conditions, inhibiting cloud formation and precipitation, leading to arid or desert climates. This process is known as subsidence, and it contributes to the formation of major desert regions like the Sahara Desert in Africa, the Mojave Desert in North America, and the Atacama Desert in South America.

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We need to use Wien's displacement law, which states that the peak wavelength of blackbody radiation spectrum is inversely proportional to the temperature of the object. The equation for this law is:
λpeak = (2.898 × 10^-3 m K) / T

The temperature at which the peak of blackbody radiation spectrum is at 435 nm is approximately 6666.67 K.

So, The equation for this law is:
λpeak = (2.898 × 10^-3 m K) / T
Where λpeak is the peak wavelength in meters, T is the temperature in Kelvin, and 2.898 × 10^-3 m K is Wien's constant.
To convert 435 nm to meters, we divide by 10^9:
λpeak = 435 nm / (10^9 m/nm)
λpeak = 4.35 × 10^-7 m
Now we can rearrange the equation to solve for T:
T = (2.898 × 10^-3 m K) / λpeak
T = (2.898 × 10^-3 m K) / (4.35 × 10^-7 m)
T = 6666.67 K
Therefore, the temperature at which the peak of blackbody radiation spectrum is at 435 nm is approximately 6666.67 K.

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