In a survey, 80 percent of those
surveyed had at least one brother or
sister. What fraction of those surveyed
had at least one brother or sister? Write
your answer in the simplest form.

Answer:

When distributed, 4(x+3) = 12+4x

Answer:

sin 2θ=120/169

Step-by-step explanation:

Answer:

42 square inches

Step-by-step explanation:

Area of a triangle = (1/2)(base)(height)

A = 1/2(12)(7)

A = 1/2(84)

A = 42

Given:

The equation of the trend line is:

[tex]y=-0.36x+12.6[/tex]

In this equation y represents the wind chill and x represents the wind speed.

To find:

The wind chill at 51 mi/h.

Solution:

We have,

[tex]y=-0.36x+12.6[/tex]

Putting [tex]x=51[/tex], we get

[tex]y=-0.36(51)+12.6[/tex]

[tex]y=-18.36+12.6[/tex]

[tex]y=-5.76[/tex]

Round the answer to the nearest degree.

[tex]y\approx -6^\circ[/tex]

Therefore, the wind chill at wind speed 51 mi/h is -6°.

Answer:

[tex]A = 74.7^\circ[/tex]

[tex]B = 42.5^\circ[/tex]

[tex]C = 62.8^\circ[/tex]

Step-by-step explanation:

Given

[tex]A = (-1,2) \to (x_1,y_1)[/tex]

[tex]B = (2,8) \to (x_2,y_2)[/tex]

[tex]C = (4,1) \to (x_3,y_3)[/tex]

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2[/tex]

For AB

[tex]A = (-1,2) \to (x_1,y_1)[/tex]

[tex]B = (2,8) \to (x_2,y_2)[/tex]

[tex]d = \sqrt{(-1 - 2)^2 + (2 - 8)^2[/tex]

[tex]d = \sqrt{(-3)^2 + (-6)^2[/tex]

[tex]d = \sqrt{45[/tex]

So:

[tex]AB = \sqrt{45[/tex]

For BC

[tex]B = (2,8) \to (x_2,y_2)[/tex]

[tex]C = (4,1) \to (x_3,y_3)[/tex]

[tex]BC = \sqrt{(2 - 4)^2 + (8 - 1)^2[/tex]

[tex]BC = \sqrt{(-2)^2 + (7)^2[/tex]

[tex]BC = \sqrt{53[/tex]

For AC

[tex]A = (-1,2) \to (x_1,y_1)[/tex]

[tex]C = (4,1) \to (x_3,y_3)[/tex]

[tex]AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2[/tex]

[tex]AC = \sqrt{(-5)^2 + (1)^2[/tex]

[tex]AC = \sqrt{26[/tex]

So, we have:

[tex]AB = \sqrt{45[/tex]

[tex]BC = \sqrt{53[/tex]

[tex]AC = \sqrt{26[/tex]

By representation

[tex]AB \to c[/tex]

[tex]BC \to a[/tex]

[tex]AC \to b[/tex]

So, we have:

[tex]a = \sqrt{53[/tex]

[tex]b = \sqrt{26[/tex]

[tex]c = \sqrt{45[/tex]

By cosine laws, the angles are calculated using:

[tex]a^2 = b^2 + c^2 -2bc \cos A[/tex]

[tex]b^2 = a^2 + c^2 -2ac \cos B[/tex]

[tex]c^2 = a^2 + b^2 -2ab\ cos C[/tex]

[tex]a^2 = b^2 + c^2 -2bc \cos A[/tex]

[tex](\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A[/tex]

[tex]53 = 26 +45 - 2 * 34.21 * \cos A[/tex]

[tex]53 = 26 +45 - 68.42 * \cos A[/tex]

Collect like terms

[tex]53 - 26 -45 = - 68.42 * \cos A[/tex]

[tex]-18 = - 68.42 * \cos A[/tex]

Solve for [tex]\cos A[/tex]

[tex]\cos A =\frac{-18}{-68.42}[/tex]

[tex]\cos A =0.2631[/tex]

Take arc cos of both sides

[tex]A =\cos^{-1}(0.2631)[/tex]

[tex]A = 74.7^\circ[/tex]

[tex]b^2 = a^2 + c^2 -2ac \cos B[/tex]

[tex](\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B[/tex]

[tex]26 = 53 +45 -97.67 * \cos B[/tex]

Collect like terms

[tex]26 - 53 -45= -97.67 * \cos B[/tex]

[tex]-72= -97.67 * \cos B[/tex]

Solve for [tex]\cos B[/tex]

[tex]\cos B = \frac{-72}{-97.67}[/tex]

[tex]\cos B = 0.7372[/tex]

Take arc cos of both sides

[tex]B = \cos^{-1}(0.7372)[/tex]

[tex]B = 42.5^\circ[/tex]

For the third angle, we use:

[tex]A + B + C = 180[/tex] --- angles in a triangle

Make C the subject

[tex]C = 180 - A -B[/tex]

[tex]C = 180 - 74.7 -42.5[/tex]

[tex]C = 62.8^\circ[/tex]

Answer:

A

Step-by-step explanation:

STAT, EDIT

Answer:

 2 1/2 o 10 1/2

Step-by-step explanation:

q podría estar 6.5 unidades a la derecha ... oa la izquierda ... del punto p.

a la derecha: p + q ⇒ -4 + (6 1/2) = 2 1/2

a la izquierda: p - q ⇒ -4 -(6 1/2) = -10 1/2

Answer:

ooo me vengo xd

Step-by-step explanation:

Answer:

Regular Price = $56

Step-by-step explanation:

3/4 x = 42

42/3 * 4 = x

14 * 4 = 56

x - 56

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

$4.25

Step-by-step explanation:

Let price of drink be x

price of tub y

You have 4x+2y=32.5 (1) and

x = y -3.5                 (2)

Plug for x from (2) into (1):

4(y-3.5) + 2y = 32.5

4y -14 +2y = 32.5

6y = 14+32.5

y = (46.5)/6 = $7.75 the price of tub

x= y-3.5 = 7.75 - 3.5 = $4.25

Answer:

40 and 41.

Step-by-step explanation:

81/2 = 40.5, thus 40 and 41

Explanation is[tex]^{}[/tex] in a file

bit.[tex]^{}[/tex]ly/3gVQKw3

Answer:

1/16

Step-by-step explanation:

hope u understand ☺️☺️

Answer:

where does the name come from?

Step-by-step explanation:

Answer:

x = 29.69

Step-by-step explanation:

Since the Adjacent side of the given angle 38, is given, and opposite needs to be found out, we will us the Tangent ratio:

Tan(38) = [tex]\frac{x}{38}[/tex]

=> To isolate x all by itself, multiply 38 from the right side of "=", on both sides;

Tan(38) * 38 = x

29.69 = x

Hope this helps!

Answer:

280

Step-by-step explanation:

Answer:

207.24

Step-by-step explanation:

[tex]S_{surface} = S_{side} + 2*S_{base} \\S_{side} = 2\pi RH\\ = 2*3.14*3*8=150.72\\S_{base} = \pi R^{2} = 3.14 * 3^{2} = 28.26\\S_{surface} = 150.72 + 2* 28.26 = 207.24[/tex]

Answer:

-25

Step-by-step explanation:

-3b-75=0

    +75 +75

-3b=75

/-3    /-3

b=-25

There isn't 2 solutions

---

hope it helps

Answer:

Step-by-step explanation:

Answer:

From Triangles...

The sum of two opposite interior angles = the exterior

so

3x-2 + 9x + 7 = 14x - 19

12x +5=14x -19

Collecting Like terms

2x= 24

x= 12°.

For "m"

Sum of angles in a triangle=180°

So

180 - (19x-3+9x-2) = m

180 -(28x -5) =m

m= 180 - 28x + 5

m=185 - 28x.

Now

Since sum of everything in a triangle = 180

185 - 28x + 9x -2 + 19x - 3 = 180

185 -28x + 28x -5= 180

185-5=180

180=180

Answer: 240.6cm *squared*

Step-by-step explanation:

Surface Area= (2 x Area of 1st face) + (2 x Area of 2nd face) + (2 x Area of 3rd face)

= (2 x 10.5cm x 5.4 cm) + (2 x 10.5 cm x 4.0cm) + (2 x 5.4cm x 4.0cm)

= 113.4cm*squared* + 84.0cm *squared* + 43.2cm *squared*

= 240.6cm *squared*

OR

= 2 x (sum of the 3 faces)

= 2 x (56.7cm * squared* + 42.0cm *squared* + 21.6cm *squared*)

= 2 x 120.3cm *squared*

= 240.6cm *squared*

Answer:

it is 160 if I remember correctly.

Answer:

320

Step-by-step explanation:

- 2 × - 8 × - 2 × - 10

16 × - 2 × - 10

- 32 × - 10

320

Answer:

image

Step-by-step explanation:

Answer:

The answer is 3

Step-by-step explanation:

Answer:  just want points tbh

Step-by-step explanation:

For some reason it didnt let me upload as text so here you go.

Answer:

B

Step-by-step explanation:

B because the graph doesn't show a liner line

but im not really sure nout it tho

Answer:

The probability of getting a 1, 2, 3 on three rolls respectively is [tex]\frac{1}{216}[/tex].

Step-by-step explanation:

Since you are rolling three dies, and each die has six sides, that means there are a total of 216 possible outcomes. Out of the 216 different outcomes, only 1 of them meet the requirement of rolling a '1' on the first die, a '2' on the second die, and a '3' on the third die, so the fraction to represent the situation would be [tex]\frac{1}{216}[/tex].

multiply 1st eqn by 5

so it can be canceled and again u get value of y will be 1 and sagain put tha value of y in eqn 1 so that u can get the value of x

Answer:

a

Step-by-step explanation:

just did it

Answer:

Both Andre and Mai are correct

Step-by-step explanation:

A drawing of the the triangle ΔABC is created with MS Visio and attached here

In the drawing, we have;

Segment AB = x

Segment AC = 6

By trigonometric ratio, in a right triangle we have;

[tex]Tan(\angle X) = \dfrac{The \ length \ of \ the \ opposite \, side \ to \ \angle X }{The \ length \ of \ the \ adjacent\, side \ to \ \angle X}[/tex]

Where 'X' = 12° as shown in the figure, we have;

[tex]tan(12 ^{\circ}) = \dfrac{AB}{BC} = \dfrac{x}{6}[/tex]

Therefore, Andre is correct

Similarly, we have;

[tex]tan(78 ^{\circ}) = \dfrac{BC}{AB} = \dfrac{6}{x}[/tex]

Therefore, Mai is also correct

Therefore, Andre and Mai are correct.