In a recent hockey game, one player (m=100kg) was moving at a velocity of 8 m/s when he ran into another player (m=300kg) who was at rest (v=0m/s). After the collision, the two players were stuck together (moving with the same velocity). What was their velocity after the collision?

Answers

Answer 1
At first you need the displacement/distance from the point he started to run to the other player
Buttttttttttt if they were at rest because the force was balanced it could be
0m/s^2
Or the other way around
25m/s^2
Answer 2

Their velocity after the collision was 2 m/s.

What is principle of conservation of momentum?

According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Given parameters:

one player (m=100kg) was moving at a velocity of 8 m/s initially.

Another  player (m=300kg) who was at rest (v=0m/s) initially.

After collision they stuck together and let the velocity of them is v.

According to principle of conservation of momentum,  total momentum remains conserved.

total initial momentum = total final momentum

100×8 + 300×0 = (100 + 300)v

400v = 800

v = 2.

Hence,  their velocity after the collision was 2 m/s.

Learn more about momentum here:

https://brainly.com/question/24030570

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