111 visitors expect to buy more than one costume.
Out of 86 + 145 + 17 = 248 visitors, 17 bought more than one costume.
So, the proportion of visitors buying more than one costume is 17/248.
To estimate the number of visitors expected to buy more than one costume next week,
we can multiply this proportion by the expected number of visitors:
17/248 * 1600 ≈ 111
Therefore, we would expect about 111 visitors to buy more than one costume next week.
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Write a quadratic function f whose zeros 3 are and -8.
Answer: y=x²+5x−24
Step-by-step explanation:
on what branch of mathematics is axiomatic semantics based? group of answer choices recursive functional theory number theory calculus mathematical logic
Axiomatic semantics, a branch of formal semantics, is based on mathematical logic. It provides a formal framework for defining the behavior and meaning of programming languages or formal systems.
Mathematical logic serves as the foundation for axiomatic semantics, offering tools and methods to define and reason about formal systems. It encompasses propositional and predicate logic, set theory, and proof theory. In axiomatic semantics, mathematical logic is used to define syntax, semantics, and proof systems, allowing for precise specifications of program behavior and correctness.
While other branches of mathematics such as set theory and calculus may be utilized in defining underlying structures and functions, the core principles and techniques of axiomatic semantics are rooted in mathematical logic. This logical framework enables rigorous reasoning about program properties and supports the verification and analysis of programs and systems.
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if ŷ = 120 − 3x with y = product and x = price of product, what happens to the demand if the price is increased by 2 units?
Therefore, if the price of the product is increased by 2 units, the demand will decrease by 6 units.
To determine the change in demand when the price is increased by 2 units, we substitute the new price into the demand equation and compare it to the original demand.
Given:
ŷ = 120 - 3x
Let's assume the original price is denoted by x, and the new price is x + 2.
Original demand:
y = ŷ
= 120 - 3x
New demand:
y' = ŷ'
= 120 - 3(x + 2)
= 120 - 3x - 6
= 114 - 3x
Comparing the original demand (y = 120 - 3x) with the new demand (y' = 114 - 3x), we can see that the demand decreases by 6 units when the price is increased by 2 units.
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We are interested in whether the mean blood pressure for women is equal to the mean blood pressure for men or whether these two means are different. The null hypothesis is that these two means are equal. If they are different we have no prior view as to whether women or men have the higher mean blood pressure. We took a sample of the blood pressures of 16 women (group 1) and found an average blood pressure x 1 of 119.4. We also measured the blood pressures of their respective brothers (group 2) and found an average blood pressure x 2 of 121.2. In order to carry out the relevant t test we calculated s2d to be 25. We choose a Type I error value a = 0.05. Calculate the numerical value of the test statistic. [5] State the relevant critical point(s). [3] Carry out the test, indicating whether you accept or reject the null hypothesis.
There is insufficient evidence to conclude that the mean blood pressure for women is different from the mean blood pressure for men. To determine whether the mean blood pressure for women is equal to the mean blood pressure for men, a t-test is conducted using the sample data of 16 women (group 1) and their respective brothers' blood pressures (group 2).
The null hypothesis states that the means are equal, and the alternative hypothesis suggests they are different. The test statistic is calculated, critical points are identified, and the null hypothesis is either accepted or rejected based on the test results.
To carry out the t-test, we first calculate the test statistic. The formula for the test statistic (t) in this case is:
t = (x1 - x2) / sqrt((s1^2 / n1) + (s2^2 / n2))
where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.
Given:
x1 = 119.4 (average blood pressure for women)
x2 = 121.2 (average blood pressure for men)
s2d = 25 (pooled sample variance)
n1 = n2 = 16 (sample sizes)
α = 0.05 (Type I error value)
Now, we can calculate the test statistic:
t = (119.4 - 121.2) / sqrt((25/16) + (25/16))
= -1.8 / sqrt(3.125 + 3.125)
= -1.8 / sqrt(6.25)
= -1.8 / 2.5
= -0.72
Next, we determine the relevant critical point(s) for the t-test. Since the sample size is small (n1 = n2 = 16), we refer to the t-distribution with degrees of freedom equal to n1 + n2 - 2 = 30 - 2 = 28. Using a significance level (α) of 0.05, the critical value for a two-tailed test is approximately ±2.048.
Since the absolute value of the test statistic (0.72) is less than the critical value (2.048), we fail to reject the null hypothesis.
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Pls help!!!!!!!! 50 POINTS !!!!! Divide
[tex]6\sqrt{5} \ cis(\frac{11\pi}{6}) \div 3\sqrt{6} \ cis (\frac{\pi}{2} )[/tex] can be expressed in polar form as[tex]6\sqrt{5} \ cis(\frac{11\pi}{6}) \div 3\sqrt{6} \ cis (\frac{\pi}{2} )=\underline{\frac{\sqrt{30} }{3} } \ cis\ (\underline{\frac{4\pi}{3}})[/tex] . Therefore the values to be dragged in the box are [tex]\frac{\sqrt{30} }{3}[/tex] and [tex]\frac{4\pi}{3}[/tex].
We have to express in polar form, polar form of complex number:
[tex]r(cos\theta+isin\theta) \rightarrow rcis\theta[/tex]
where, r = modulus of complex number
[tex]\theta[/tex] = argument of complex number
The division of two complex number, [tex]z=[/tex] [tex]r_{1} cis \theta_{1}[/tex] and [tex]x=[/tex] [tex]r_{2} cis \theta_{2}[/tex]
[tex]\frac{z}{x} = \frac{r_{1} }{r_{2} }\ cis(\theta_{1}- \theta_{2})[/tex]
Similarly, let a = [tex]6\sqrt{5} \ cis(\frac{11\pi}{6})[/tex]
b = [tex]3\sqrt{6} \ cis(\frac{pi}{2})[/tex]
[tex]\frac{a}{b}= \frac{6\sqrt{5} }{3\sqrt{6} } \ cis (\frac{11\pi }{6}- \frac{\pi}{2} )[/tex]
[tex]= \frac{{\sqrt{2}}\times\sqrt{2}\times\sqrt{5} }{\sqrt{2} \times\sqrt{3} } \ cis(\frac{11\pi-3\pi}{6} )[/tex]
[tex]=\sqrt{\frac{10}{3} }\ cis\ \frac{8\pi}{6}[/tex]
[tex]\frac{a}{b}= \sqrt{\frac{10}{3} } \ cis\ \frac{4\pi}{3}[/tex]
It can also be written as, [tex]\frac{a}{b}= \frac{\sqrt{30} }{3} \ cis\ \frac{4\pi}{3}[/tex]
⇒ [tex]6\sqrt{5} \ cis(\frac{11\pi}{6}) \div 3\sqrt{6} \ cis (\frac{\pi}{2} )= \frac{\sqrt{30} }{3} \ cis\ \frac{4\pi}{3}[/tex]
Comparing it with the question we get:
[tex]6\sqrt{5} \ cis(\frac{11\pi}{6}) \div 3\sqrt{6} \ cis (\frac{\pi}{2} )=\underline{\frac{\sqrt{30} }{3} } \ cis\ (\underline{\frac{4\pi}{3}})[/tex]
Therefore, the first blank is [tex]\frac{\sqrt{30} }{3}[/tex] and the second blank is [tex]\frac{4\pi}{3}[/tex].
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kyle is tossing bean bags at a target. so far, he has had 22 hits and 14 misses. what is the experimental probability that kyle's next toss will be a hit?
The experimental probability that Sue will hit the bullseye on her next toss is 2/7.
We have,
The proportion of outcomes where a specific event occurs in all trials, not in a hypothetical sample space but in a real experiment, is known as the empirical probability, relative frequency, or experimental probability of an event.
Here, we have
Given: Sue is playing darts. So far, she has hit the bullseye 4 times and missed the bullseye 10 times.
We have to find the experimental probability that Sue will hit the bullseye on her next toss.
experimental probability = 4/(4+10) = 4/14 = 2/7
The next toss = P = 2/7
Hence, the experimental probability that Sue will hit the bullseye on her next toss is 2/7.
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complete question:
Sue is playing darts. So far, she has hit the bullseye 4 times and missed the bullseye 10 times. What is the experimental probability that Sue will hit the bullseye on her next toss?
consider the linear search algorithm, would it be faster asymptotically in the worst case scenario if we run it on a sorted list vs. an unsorted list. justify your answer.
In the context of the linear search algorithm, the time complexity in the worst-case scenario remains the same, whether the list is sorted or unsorted.
The linear search algorithm has a time complexity of O(n) in the worst case, which means that it takes n steps to search through a list of n elements.
Step-by-step explanation:
1. Start at the first element of the list.
2. Compare the current element with the target value.
3. If the current element is equal to the target value, return the index of the current element.
4. If the current element is not equal to the target value, move on to the next element.
5. Repeat steps 2-4 until you reach the end of the list or find the target value.
In the worst-case scenario, the target value is either at the end of the list or not present in the list. In both sorted and unsorted lists, the algorithm has to traverse the entire list to determine the result. Therefore, there is no asymptotic difference in the worst-case scenario between sorted and unsorted lists when using the linear search algorithm.
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Solve this quadratic equation using the quadratic formula.x²-6x+6=0
A.x=3±√3
B.x=-6±√6
C.x=-3±√3
D.x=6±√6
Let R be the set of real numbers, C = (0, 10], D = (9, 15], E = {1, 2, 3} and F = (7, 10). Find: (i) (CUD-E) specified using set builder notation without any words. (ii) (CE) specified using interval notation and set operations concisely without any words. (iii) (CDF) specified using the most concise notation. (3 marks) (b) Use element argument method to prove that if A and B are sets such that P(A) ≤ P(B), then A ≤ B, where P(A) and P(B) are power sets of A and B respectively. You must state your reasons clearly for every statement in your proof.
(i) (CUD-E) specified using set builder notation:
(CUD-E) = {x ∈ R | (x > 0 ∧ x ≤ 10) ∨ (x > 9 ∧ x ≤ 15) ∧ x ∉ {1, 2, 3}}
(ii) (CE) specified using interval notation and set operations concisely:
(CE) = (0, 10] ∩ {1, 2, 3} = {1, 2, 3}
(iii) (CDF) specified using the most concise notation:
(CDF) = (C ∩ D) ∩ F
(b) Proof using the element argument method:
Given: A and B are sets such that P(A) ≤ P(B).
To prove: A ≤ B.
Proof:
1. Let x be an arbitrary element in A.
2. Since x is in A, by definition, x is a subset of A. Hence, x ⊆ A.
3. Since x ⊆ A and A ≤ B, by the definition of ≤, x ⊆ B.
4. Therefore, x is a subset of B. Hence, x ∈ P(B), where P(B) is the power set of B.
5. Since x ∈ P(B), by definition, x is a subset of B. Hence, x ⊆ B.
6. Since x is an arbitrary element in A and x ⊆ B, by definition, A ≤ B.
7. Therefore, if P(A) ≤ P(B), then A ≤ B.
In this proof, we used the fact that if x is an element of A, then x is a subset of A. Also, if x is a subset of A and A ≤ B, then x is a subset of B. These properties are based on the definitions of subsets and the order relation between sets.
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area of a pentagon with a side length of 5 mi
The area of pentagon ABCDE is 36 times the area of pentagon PQRST.
Any five-sided polygon or 5-gon is referred to as a pentagon. The area of pentagon ABCDE is 36 times the area of pentagon PQRST.
We have,
Any five-sided polygon or 5-gon is referred to as a pentagon. A basic pentagon's interior angles add up to 540°. A pentagon might be straightforward or self-intersecting.
We know the formula for the area of a pentagon, therefore, the area of the pentagon PQRST can be written as,
A = 1/4 * √5(5+25)*a²
Given that the side of the side length of pentagon ABCDE is 6 times the side length of pentagon PQRST, therefore, the area of the pentagon ABCDE can be written as,
ABCDE = 1/4 * √5(5+25)* 6a²
ABCDE = 36 * A
Hence, The area of pentagon ABCDE is 36 times the area of pentagon PQRST.
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complete question:
Pentagon ABCDE is similar to pentagon PQRST. If the side length of pentagon ABCDE is 6 times the side length of pentagon PQRST, which
statement is true?
A.
The area of pentagon ABCDE IS 6 times the area of pentagon PQRST.
B.
The area of pentagon ABCDE is 12 times the area of pentagon PQRST.
C.
The area of pentagon ABCDE is 36 times the area of pentagon PQRST.
D.
The area of pentagon ABCDE IS 216 times the area of pentagon PQRST.
if we select 3 young women at random, what is the probability that their average height is shorter than / at most 63 inches (that is, they are at most 63 inches tall, on average)?
The probability that the average height of 3 young women is at most 63 inches is approximately 12.38%. Here option A is the correct answer.
To calculate the probability that the average height of 3 young women is at most 63 inches, we need to use the central limit theorem, which states that the distribution of the sample means of a sufficiently large sample from any population with a finite mean and variance will be approximately normally distributed.
Assuming the heights of young women follow a normal distribution, with a mean of μ and a standard deviation of σ, we can calculate the probability using the standard normal distribution table or a statistical software package.
First, we need to calculate the mean and standard deviation of the sample mean. The mean of the sample mean is equal to the population mean, μ, which we assume to be 65 inches. The standard deviation of the sample mean is equal to the population standard deviation divided by the square root of the sample size, which is 3 in this case. Assuming a standard deviation of 3 inches, the standard deviation of the sample mean is 3 / sqrt(3) = 1.73 inches.
Next, we need to calculate the z-score for a sample mean of 63 inches:
z = (63 - 65) / 1.73 = -1.16
Using the standard normal distribution table, we can find the probability that a z-score is less than or equal to -1.16. The probability is 0.1238, or approximately 12.38%.
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Complete question:
If we select 3 young women at random, what is the probability that their average height is shorter than / at most 63 inches (that is, they are at most 63 inches tall, on average)?
A - 12.38
B - 13.38
C - 15.48
D - 17.40
aider moi svp, merci.
Answer:
Step-by-step explanation:
a= 3(x+11)
B=9(x+8)
C=5(x+5)
D=3(3x+2)
Find the value of 5x + 3 given that -8 - 9 = 7.
Answer:
4.2
Step-by-step explanation:
5x+3-8-9=7
5x=7-3+8+9
5x=21
X =4.2
in the diagram of right triangle DCB below, altitude CA is drawn. which of the following ratios is equivalent to sin B?
-ca/cb
-ab/ca
-cb/db
-da/ac
What are the solutions of the quadratic equation x² - 7x=-12?
The solutions of the quadratic equation x² - 7x = -12 are x = 3 or x = 4
How to determine the solutions of the quadratic equationFrom the question, we have the following parameters that can be used in our computation:
x² - 7x=-12
Express properly
So, we have
x² - 7x = -12
Add 12 to both sides
x² - 7x + 12 = 0
When factored, we have
(x - 3)(x - 4) = 0
Using the zero product property , we have
x - 3 = 0 or x - 4 = 0
Evaluate
x = 3 or x = 4
Hence, the solutions of the quadratic equation are x = 3 or x = 4
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Nicole and Kim are in cities that are 170 miles apart when they begin driving toward each other. Nicole drives 5 mi/h faster than Kim. If they meet in 2 hours, what is the rate of each driver?
Group of answer choices
Nicole’s rate is 45 mi/h, and Kim’s rate is 40 mi/h. Nicole’s rate is 40 mi/h, and Kim’s rate is 45 mi/h. Nicole’s rate is 40 mi/h, and Kim’s rate is 35 mi/h. Nicole’s rate is 35 mi/h, and Kim’s rate is 40 mi/h
The correct answer is: Nicole’s rate is 45 mi/h, and Kim’s rate is 40 mi/h.
Nicole and Kim are driving towards each other at a combined speed of 170 miles in 2 hours, so their average speed is 85 miles per hour. Let's assume that Kim's speed is x miles per hour, then Nicole's speed is x+5 miles per hour.
So, the equation we get from their combined speed is:
x + (x+5) = 85
Simplifying the equation, we get:
2x + 5 = 85
2x = 80
x = 40
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suppose it has been determined that the probability is 0.8 that a rat injected with cancerous cells will live. if 45 rats are injected, how many would be expected to die?
We can expect approximately 9 rats to die after being injected with cancerous cells based on probability.
To answer your question, we will use the given probability and the number of rats injected to find the expected number of rats that would die.
1. The probability that a rat injected with cancerous cells will live is 0.8.
2. Therefore, the probability that a rat will die is 1 - 0.8 = 0.2 (since the sum of probabilities of all possible outcomes should be equal to 1).
3. We have 45 rats injected with cancerous cells.
4. To find the expected number of rats that would die, multiply the total number of rats by the probability of a rat dying: 45 rats * 0.2 = 9 rats.
So, we can expect approximately 9 rats to die after being injected with cancerous cells.
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Los costos de fabricación de maquetas se modelan a la siguiente función. C(x) = 10 + 2x. El fabricante estima que el precio de venta en soles de cada maqueta viene dado por: P(x) = 20 6x2 800 ¿Qué cantidad de maquetas debe producir?
Models should be produced of the function C(x) = 10 + 2 x is 329.4 .
Cost of manufacturing is
C(x) = 10 + 2 x
Sale price in soles of each model is
P(x) = 20 - [tex]\frac{6x^{2} }{800}[/tex]
U(x) is the utility function
U(x) = x P(x) - C(x)
U(x) = x (20 - [tex]\frac{6x^{2} }{800}[/tex] ) - (10 +2x)
U(x) = 20x - [tex]\frac{6x^{3} }{800}[/tex] - 10 - 2x
U(x) = 18x - [tex]\frac{6x^{3} }{800}[/tex] - 10
U'(x) = 18 - 18x²/800
For maximum model U'(x) = 0
18 - 18x²/800 = 0
18x²/800 = 18
x² = 800
x = √800
x = 20√2
U(x) = 18(20√2 ) - [tex]\frac{6(20\sqrt{2} )^{2} }{800}[/tex] - 10
U(x) = 329.5
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The question is in Spanish question in English :
The manufacturing costs of models are modeled to the following function. C(x) = 10 + 2x. The manufacturer estimates that the sale price in soles of each model is given by: P(x) = 20- 6x2/800 How many models should be produced?
1. Let U = \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9\} be a universal set. Let A = \{1, 2, 3, 4, 5\}; B=\ 2,4,6,8\ .C=\ 1,3,5,7,9\ .
a. Find (A cup B) n C.
b . Find A' . Find A'UB
d . Find (A cap C)^
If the universal set is {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} then (A ∪ B) ∩ C = {1, 3, 5}, A' U B = {0, 2, 4, 6, 7, 8, 9} and (A ∩ C)' = {0, 2, 4, 6, 7, 8, 9}.
The universal set is {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
To find (A ∪ B) ∩ C, we first need to find A ∪ B and then find the intersection with C.
A ∪ B is the set of all elements that are in A or B, so:
A ∪ B = {1, 2, 3, 4, 5, 6, 8}
Now we need to find the intersection of A ∪ B and C:
(A ∪ B) ∩ C = {1, 3, 5}
Therefore, (A ∪ B) ∩ C = {1, 3, 5}.
b. A' is the complement of A, which means it is the set of all elements in U that are not in A.
A' = {0, 6, 7, 8, 9}
A' U B is the set of all elements that are in A' or B, so:
A' U B = {0, 2, 4, 6, 7, 8, 9}
Therefore, A' U B = {0, 2, 4, 6, 7, 8, 9}.
c. A ∩ C is the set of all elements that are in both A and C:
A ∩ C = {1, 3, 5}
(A ∩ C)' is the complement of A ∩ C, which means it is the set of all elements in U that are not in A ∩ C:
(A ∩ C)' = {0, 2, 4, 6, 7, 8, 9}
Therefore, (A ∩ C)' = {0, 2, 4, 6, 7, 8, 9}.
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EXPLAIN PLEASEEEE, I need help
The value of angle x in the kite is 243 degrees.
How to find angle in a kite?The diagram above is a kite. The sum of angle in a kite is 360 degrees. Therefore, a kite kites have two sets of equivalent adjacent sides and one set of congruent opposite angles.
Therefore,
360 - 318 + 84 + 2y = 360
where
y are the inner congruent angles
Therefore,
42 + 84 + 2y = 360
2y = 360 - 126
2y = 234
divide both sides of the equation by 2
y = 234 /2
y = 117 degrees
Therefore,
x = 360 - 117
x = 243 degrees
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 From the attachment, what is the measure of Arc CDE?
The value of the measure of Arc CDE is,
⇒ Arc CDE = 128 degree
Since, An angle is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs and sometimes the arms of the angle.
Here, A circle is shown in figure.
And, By circle we have;
The measure of Arc CDE is,
⇒ Arc CDE = 128 degree
Thus, The value of the measure of Arc CDE is,
⇒ Arc CDE = 128 degree
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what is the probability that two people chosen at random were born during the same month of the year?
To calculate the probability that two people chosen at random were born during the same month of the year, we need to consider the total number of possible outcomes and the favorable outcomes.
There are 12 months in a year, so the total number of possible outcomes is 12 (one for each month).
Now, let's consider the favorable outcomes. To have two people born in the same month, we need to choose any one of the 12 months for the first person, and then the second person should also be born in the same month.
The probability that the second person is born in the same month as the first person is 1/12 since there is only one favorable outcome out of 12 possible outcomes.
Therefore, the probability that two people chosen at random were born during the same month of the year is 1/12 or approximately 0.0833 (rounded to four decimal places).
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what does a two tailed alternative theory look like
Answer:
In a two-tailed or nondirectional test, the alternative hypothesis claims its parameters don't equal the null hypothesis value. This means the two-tailed directional test states there are differences present that are greater than and less than the null value.
Step-by-step explanation:
have a nice day.
Unit 5 progress check: mcq part a ap calculus ab Let f be the function given by f(x)=5cos2(x2)+ln(x+1)−3. The derivative of f is given by f′(x)=−5cos(x2)sin(x2)+1x+1. What value of c satisfies the conclusion of the Mean Value Theorem applied to f on the interval [1,4] ?
By the Mean Value Theorem, there exists a value c in the interval [1,4] such that f'(c) is equal to the average rate of change of f on the interval [1,4], which is (f(4) - f(1))/(4-1).
We can start by computing f(4) and f(1):
f(4) = 5cos(2(4^2)) + ln(4+1) - 3 = -0.841 + 1.609 - 3 = -1.232
f(1) = 5cos(2(1^2)) + ln(1+1) - 3 = 2.531 - 0.693 - 3 = -1.162
Then, we can compute the average rate of change:
(f(4) - f(1))/(4-1) = (-1.232 - (-1.162))/3 = -0.023
To satisfy the conclusion of the Mean Value Theorem, we need to find a value c in the interval [1,4] such that f'(c) = -0.023. From the given expression for f'(x), we can see that there is no value of c that satisfies this equation, since f'(x) can never be negative. Therefore, there is no value of c that satisfies the conclusion of the Mean Value Theorem applied to f on the interval [1,4].
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can someone help real fast?
Answer:
51
Step-by-step explanation:
Sum of interior angles in a triangle is 180.
x + 90 + 39 = 180
x + 129 = 180
x = 180 - 129
x = 51
Answer:
51 degrees
Step-by-step explanation:
We are asked to find angle x.
To find angle x, we have to write an equation to find it.
We know that one angle is 39 degrees, and the other is 90 degrees because of the small box. We also know that all 3 angles in a triangle have to add up to 180.
Here's the equation for this:
180=39+90+x
simplify
180=129+x
subtract 129 from both sides
51=x
So, angle x is 51 degrees.
Hope this helps! :)
write the following as a system of first-order equations (t 1)2 d 3 y dt3 d 2 y dt2 2 dy dt 6y(t)
The system of first-order equations that is equivalent to the given second-order differential equation is dy/dt = z, dz/dt = w, and dw/dt = (-3z - 2w - 6y)/t².
To write the given second-order differential equation as a system of first-order equations, we need to introduce new variables.
Let z = dy/dt. Then, we can rewrite the given equation as
d³y/dt³ = dz/dt
d²y/dt² = dz/dt = z
Substituting these expressions into the original equation, we get
(t²) (d³y/dt³) + 3(d²y/dt²) + 2(dy/dt) + 6y = t² (dz/dt) + 3z + 2(dy/dt) + 6y
Simplifying and grouping the terms, we obtain
d/dt [y, z, w] = [z, w, (-3z - 2w - 6y)/t²]
where w = dt/dt = 1.
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suppose that a and b are events in a sample space s and that p (a), p (b), and p(aub) are known. derive a formula for p(aubc )
To derive a formula for P(A ∪ B ∪ C), we can use the inclusion-exclusion principle, which states that:
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)
We know P(A), P(B), P(A ∪ B), and P(C), but we need to find P(A ∩ B), P(A ∩ C), P(B ∩ C), and P(A ∩ B ∩ C).
We can use the following formulas to find these probabilities:
P(A ∩ B) = P(A) + P(B) - P(A ∪ B)
P(A ∩ C) = P(A) + P(C) - P(A ∪ C)
P(B ∩ C) = P(B) + P(C) - P(B ∪ C)
P(A ∩ B ∩ C) = P(A) + P(B) + P(C) - P(A ∪ B) - P(A ∪ C) - P(B ∪ C) + P(A ∪ B ∪ C)
Substituting these formulas in the inclusion-exclusion principle, we get:
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A) - P(B) - P(A ∪ B) - P(A) - P(C) + P(A ∪ C) - P(B) - P(C) + P(B ∪ C) + P(A) + P(B) + P(C) - P(A ∪ B) - P(A ∪ C) - P(B ∪ C) + P(A ∪ B ∪ C)
Simplifying this expression, we get:
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∪ B) - P(A ∪ C) - P(B ∪ C) + P(A ∩ B ∩ C)
Therefore, the formula for P(A ∪ B ∪ C) is:
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∪ B) - P(A ∪ C) - P(B ∪ C) + P(A ∩ B ∩ C)
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which of the following bit arrays below is the correct 4-bit combination for the decimal number 9?
The correct 4-bit combination for the decimal number 9 is 1001. To explain it in a long answer, we need to understand binary representation. In binary, each digit can either be 0 or 1, and the value of the digit depends on its position.
The rightmost digit represents the value 2^0 (which is 1), the next digit to the left represents the value 2^1 (which is 2), the next represents 2^2 (which is 4), and so on. To convert decimal number 9 to binary, we can start by finding the highest power of 2 that is less than or equal to 9, which is 2^3 (which is 8). We can subtract 8 from 9, and the remainder is 1. This means the leftmost digit in the binary representation is 1.
We repeat the same process with the remainder, which is 1, and find the highest power of 2 that is less than or equal to 1, which is 2^0 (which is 1). We subtract 1 from 1, and the remainder is 0. This means the rightmost digit in the binary representation is 0. Thus, the binary representation of decimal number 9 is 1001, which is the correct 4-bit combination.
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Given that
x
= 7.7 m and
θ
= 36°, work out BC rounded to 3 SF.
Answer:
Avg BC= 10.873 m
Step-by-step explanation:
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The probabilities of hitting the next bat are Mitchell = 5/12 and Travis= 9/20
How to determine the probabilities of hitting the next batFrom the question, we have the following parameters that can be used in our computation:
Mitchell hits 5 out of 12 times
Travis hits 9 out of 20 times
The probabilities of hitting the next bat is calculated as
P(Hit) = Hit/Total number of times
using the above as a guide, we have the following:
P(Mitchell Hit) = 5/12
P(Travis Hit) = 9/20
Hence, the probabilities of hitting the next bat are 5/12 and 9/20
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