Mathematics College

In 2009 Zambrano's salary was 18,750,000. He pitched in 28 games in 2009. What was his salary per game in 2009? Round to the nearest cent.​

Answers

Answer 1

Answer:

his salary per game is  669,643

Step-by-step explanation:

The computation of the salary per game in the year 2009 is shown below

Given that

His salary  in the year 2009 is 18,750,000

And, he pitched 28 games in the year 2009

Based on the above information

His salary per game is

= 18,750,000 ÷ 28 games

= 669,643

hence, his salary per game is  669,643

The same is relevant

Related Questions

simplify 8x+7-x-4


help meeeeee!!!​

Answers

Answer:

7x + 3

Step-by-step explanation:

Let's simplify step-by-step.

8x + 7 − x − 4

= 8x + 7 + −x + −4

Combine Like Terms:

= 8x + 7 + −x + −4

= (8x + −x) + (7 + −4)

= 7x + 3

Answer:

= 7x + 3

hope this helps and is right. p.s i really need brainliest :)

if my answer is wrong then I am incredibly sorry!

Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with description of each step, thank you very much.
3x^2+4.5
________
x^2-1.5

lim
x → ∞

Answers

Answer:

[tex]\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3[/tex]

Step-by-step explanation:

We want to evaluate the limit:

[tex]\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}[/tex]

To do so, we can divide everything by x². So:

[tex]=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}[/tex]

Now, we can apply direct substitution:

[tex]\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}[/tex]

Any constant value over infinity tends towards 0. Therefore:

[tex]\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3[/tex]

Hence:

[tex]\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3[/tex]

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3x², and in the denominator it is x². So:

[tex]\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}[/tex]

Simplify:

[tex]\displaystyle =\lim_{x\to\infty}3=3[/tex]

The limit of a constant is simply the constant.

We acquire the same answer.

Find the value of f(4) for the function

Answers

Answer:

f(4) = 7

Step-by-step explanation:

The notation for these type of problems is very confusing. Just remember that f(x) is the same thing as y (or some variable). Even if there is a number or something on the inside of the parentheses, it's still just a variable.

In our case

f(a) = 2(a + 4) -9

could be rewritten as

y = 2(a + 4) - 9

the thing on the inside of the parentheses signifies what the equation is dependent on.

so when is says f(4), it just want's you to trade out a for a 4, but the equation is still the same.

f(4) = 2((4) + 4) - 9

Now, just follow the order of operations

f(4) = 2(8) - 9

f(4) = 16 - 9

f(4) = 7

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