imagine you looked up the accelerations of the following objects: snails, humans, thomson's gazelles, the space shuttle, formula one race cars, and f-16 fighter jets. which of the following statements about the acceleration of a cheetah would you expect to be true?

i think it also doubles in area

The additional heat causes the kinetic energy of some of the liquid molecules to Increase So they can more easily escape into the gas phase.

When we add heat to the water immediately the temperature does not increase as before increasing the temperature the Kinetic Energy of molecules of water increases first and the heat is used for the same for increasing the temperature.

And As a result, the temperature of the boiling water remains constant. since some of the liquid water changes to gas, the amount of liquid water is. And the same phenomenon occurs when the water is boiling is starts becoming vapor instate of increasing the temperature it changes its state from liquid to gaseous.

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If we assume that the radius of Earth is 6,4 x 10° m and the acceleration of gravity is 9.8 m/s®, than the mass of Earth's atmosphere is 5.322 * 1016 kg.

What is pressure ?

The magnitude of force applied to a certain region is referred to as pressure. So either a strong force or a strong force applied over a short area can cause a lot of pressure (or do both).

Why does air pressure exist?

The atoms and molecules that comprise the many layers of the atmosphere are continually moving in arbitrary directions. Despite their modest size, when they hit a surface, they apply pressure that humans perceive as a force.

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The expression that represents the scenario forty-five seconds after a bowl begins to leak, the bowl is losing 0.28 ounces of liquid per second would be l(t) = 0.28t.

When a bowl begins to leak, it can be represented mathematically as a function of time, l(t). In this case, the bowl is losing 0.28 ounces of liquid per second, so after 45 seconds, the total amount lost would be 0.28 x 45 = 12.6 ounces.

This function can be used to calculate the amount of liquid lost over any given amount of time, depending on the rate of the leak. It is important to note that this calculation only applies to liquids with a known rate of flow.

The bowl's liquid level over time can be represented by the expression l(t) = 0.28t. This expression calculates the amount of liquid lost from the bowl each second.

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The spring constant can be calculated as: 12.51 N.

The formula for calculating the period of oscillation is written as the following:

[tex]T=2\pi \sqrt{\frac{m}{k} } \\[/tex]

m is the mass of the spring.

k is the spring constant.

Making the spring constant "k" the subject of the formula will give us the following expression;

[tex]k=4\pi ^{2} \frac{m}{T^{2} } \\[/tex]

Get the period of oscillation "T"

T= 1/f

frequency "f" can express the number of oscillations completed in one second.

If a student with a stopwatch finds that 12 oscillations take 15.0 s, the number of oscillations in one sec will be 9/14 = 0.64 osc.

Period T = 1/0.64 = 1.56sec

Get the required spring constant

[tex]K=4\pi ^{2} \frac{m}{T^{2} } \\k= 4(3.14)^{2}\frac{0.13}{0.64^{2} } \\[/tex]

K= 12.51 N

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The statement about crate that is true is that D. The crate will not move.

Force is any interaction that, when unopposed, will change the motion of an object. The maximum force that static friction can exert on the crate is

μsFN = μsFw =

μs mg = (0.4)(100 kg)(10 N/kg)

= 400 N

Since the force applied to the crate is only 344 N, static friction is able to apply that same magnitude of force on the crate, keeping it stationary. [B is incorrect because the static friction force is not the reaction force to F; both F and Ff (static) act on the same object (the crate) and therefore cannot form an action/reaction pair.]

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Complete question: A crate of mass 100 kg is at rest on a horizontal floor. The coefficient of static friction between the crate and the floor is 0.4, and the coefficient of kinetic friction is 0.3. A force F of magnitude 344 N is then applied to the crate, parallel to the floor. Which of the following is true?

A. The crate will accelerate across the floor at 0.5 m/s2.

B. The static friction force, which is the reaction force to F as guaranteed by Newton’s third law, will also have a magnitude of 344 N.

C. The crate will slide across the floor at a constant speed of 0.5 m/s.

D. The crate will not move.

E. None of the above

Hence option D is the correct choice.

The right statement is that the crate won't move.

Any interaction that alters an object's motion while it is unopposed is referred to as force. The crate can only withstand a maximum force of static friction of

μsFN = μsFw =

μs mg = (0.4)(100 kg)(10 N/kg)

= 400 N

The box is subjected to a force of just 344 N, therefore static friction may exert the same force, holding the crate immobile. [B is erroneous since F and Ff (static) operate on the same object, the crate, and so cannot form an action/reaction pair. F and Ff (static) are not the response force to F.]

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Note: The correct question would be as bellow,

A crate of mass 100 kg is at rest on a horizontal floor. The coefficient of static friction between the crate and the floor is 0.4, and the coefficient of kinetic friction is 0.3. A force F of magnitude 344 N is then applied to the crate, parallel to the floor. Which of the following is true?

A. The crate will accelerate across the floor at 0.5 m/s2.

B. The static friction force, which is the reaction force to F as guaranteed by Newton’s third law, will also have a magnitude of 344 N.

C. The crate will slide across the floor at a constant speed of 0.5 m/s.

D. The crate will not move.

E. None of the above

This is a physics problem involving Coulomb's Law, which states that the force between two point charges is given by the equation F = (k * q1 * q2) / r², where k is the Coulomb constant, q1 and q2 are the charges, and r is the distance between the charges.

To find the position of charge 3 to the right of charge 1, we need to find the value of x³,r such that the net force on charge 3 is zero. This is because if the net force on charge 3 is not zero, it will accelerate and move away from its current position.

Similarly, to find the position of charge 3 to the left of charge 1, we need to find the value of x3,l such that the net force on charge 3 is zero.

The exact value of x3,r and x3,l will depend on the values of q1, q3 and the distance from charge 3 to charge 1.

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The number of hydrogen atoms required to obtain 1.0 kg of hydrogen is 6.022 x 10^30.

1 kilogram is equal to 1000 grams and 1 atomic mass unit (u) is defined as one twelfth of the mass of a carbon-12 atom, which is 1.6605 x 10^-27 kg.

So, 1 u = 1.6605 x 10^-27 kg

Therefore, 1.0 kg of hydrogen is equal to 1.0 x 10^3 / 1.6605 x 10^-27 = 6.022 x 10^30 hydrogen atoms.

So, the number of hydrogen atoms required to obtain 1.0 kg of hydrogen is 6.022 x 10^30.

A conversion factor converts one unit to another by utilizing your knowledge of unit relationships. For example, if you know that there are 2.54 centimeters in an inch (or 2.2 pounds in a kilogram or 101.3 kilopascals in an atmosphere), converting between those units becomes simple algebra. It is critical to understand some common temperature, size, and pressure conversions, as well as metric prefixes.

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Answer:

The direct comparison method of measurement is a method of comparison in which an unknown measurement is compared to a known measurement. This method is used to determine the size, weight, or volume of an unknown object by comparing it to an object whose size, weight, or volume is already known. For example, if you need to determine the weight of an object and have a known weight that is similar in size, you can compare the two objects and estimate the unknown weight. This method of measurement is often used in situations where a more precise measurement is not possible or practical.

Due to the refraction of light when we look the coin embedded in a glass cube it appears to be closer at the top of the cube.

Refraction is the bending of a light ray when it goes from an optically rare medium to an optically denser medium. It is determined by the refractive index. Refractive index of a substance is the ratio the speed of light in a vacuum to the speed of light in the substance.

So refractive index 1.5 tells that the speed of light in the glass will be 1.5 times slower than the speed of light in vacuum. That's why it will gets bent towards the normal when it will pass through the glass. So the coin will appear closer to the top surface of the cube.

Hence the option C is correct.

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When the volume of a gas is decreased at a constant temperature the pressure increases because the molecules a.  Strike the unit area of the walls of the container more often.

We need to keep in mind that the kinetic energy or Speed of molecules of ideal gases depends on upon temperature and as the temperature increases the Kinetic energy of molecules increases.

So at constant pressure, the rest of the reasons(Options) mentioned can not increase.

Let's take an example of a small area on the surface or wall of the container. earlier when the volume was large, it had a lower probability of being hit by a molecule but now space is small, so it will be hit by more molecules so, high pressure will be generated on this area.

which results in pressure increases.

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Answer:

Displacement = √(4^2 + 4^2) = √(16 + 16) = √32 = 4√2 meters

Explanation:

To determine the magnitude of the cart's resultant displacement, we can use the Pythagorean theorem. The Pythagorean theorem states that the square of the length of the hypotenuse (the displacement) of a right triangle is equal to the sum of the squares of the lengths of the other two sides.

We can imagine the cart's displacement as the hypotenuse of a right triangle, where one side is 4 meters (the eastward displacement) and the other side is 4 meters (the northward displacement). Using the Pythagorean theorem, we can calculate the magnitude of the displacement as follows:

Displacement = √(4^2 + 4^2) = √(16 + 16) = √32 = 4√2 meters

So the magnitude of the cart's resultant displacement is 4√2 meters.

The weight of the cylinder in pounds is 26.45 lbs.

To determine the weight of the cylinder in pounds, we first need to calculate its volume. The volume of a cylinder is given by :

V = πr²h

where,

r = the radius

h = the height (or length) of the cylinder.

Given the radius and length, we can substitute these values into the formula to get:

V = π * (0.04 m)² * (0.11 m) = 0.001539 m³

Since the mass density of steel is 7850 kg/m3, we can multiply the volume by the mass density to find the mass of the cylinder:

mass = 7850 kg/m³ * 0.001539 m³

mass = 12 kg

To convert this mass to pounds, we can multiply it by 2.20462 (1kg = 2.20462 lbs)

12 kg * 2.20462 = 26.45 lbs

Hence, the weight of the cylinder in pounds is 26.45 lbs.

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An update can be caused by changes to props or state. These methods are called in the following order when a component is being re-rendered.

what is the co ordinates of initial and terminal points?

.

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This car is undergoing negative acceleration, meaning that its velocity is decreasing as it moves to the left. The car's motion can be described as decelerating to the left.

Acceleration is the rate of change of velocity. It is the rate at which an object's velocity changes over time. It is a vector quantity, meaning it has both magnitude and direction. Acceleration can be caused by a number of forces, such as gravity, friction, and applied forces. In one dimension, acceleration is the change in velocity divided by the time it takes for the change to occur. In two dimensions, acceleration is the rate at which an object's velocity vector changes in magnitude and/or direction. Acceleration can be positive, negative, or zero. Positive acceleration occurs when an object speeds up, negative acceleration occurs when an object slows down, and zero acceleration occurs when an object's velocity remains constant.

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In the 0/1/2 knapsack problem, the objective is to select the set of things that maximises the overall value of the items while staying within the limits of the knapsack. Each item may be selected up to twice.

Similar to the 0/1 knapsack problem, the issue can be written as a linear programming problem and resolved using dynamic programming or the branch and bound approach. The 0/1/2 knapsack problem and the 0/1 knapsack problem are fundamentally different from one another because in the latter, each item may be selected up to twice, but in the former, each item may only be selected once. Accordingly, depending on the particular issue instance, the 0/1/2 knapsack problem is more adaptable and might result in different solutions than the 0/1 knapsack problem. Using a modified version of the conventional 0/1 knapsack method is a common strategy for solving the 0/1/2 knapsack issue.

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Convergent boundaries occur when two plates move in the opposite direction until they collide and create mountains and volcanoes. In the image, the arrows direction is horizontal and oposite to each other.

Collision area between two plates. The collition might occur between,

When two oceanic plates collide, magma rises to the surface by crevices, creating volcanic arches. In these boundaries occur vertical movements and might originate from protruding areas. There is compressional stress between plates.

In the image, the arrows direction is horizontal and oposite to each other.

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Light refraction in spherical lenses & the lens maker formula are the notions that should be applied to the problem at hand. Utilize the lens mfg rule to get the fov of fixed lens & it verify if it is a high or low length.

A optical lens with such a contour that allows light beams to converge in diverge is called a spherical lens, also referred to as a singlet. One reason why spherical lenses are among the most popular ones is that they can project pictures onto the sensor with changing their aspect ratios.

It's an optical apparatus that the light rays pass through to converge / diverge before communicating. Thus, convex or convergent lenses and concave or divergent lenses are the two main categories of spherical lenses.

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A phenomenon is modeled using n dimensional variables with k primary dimensions, so the number of non-dimensional variables would be option c. n-k.

Measurements with quantitative data and distinct sizes are referred to as dimensional variables. Variables with dimensions and yet no constant value are called dimensional variables. Non-dimensional variables, on the other hand, are things that lack both dimensions and a variable value.

Quantities with dimensions but no constant value are called dimensional variables. Non-dimensional variables, on the other side, do not have the value of any variable or even the dimensions. Physical quantities with changing values but no dimensions are typically considered to be dimensionless variables.

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The rate at which the velocity changes is referred to as average acceleration. To determine the average acceleration of anything, we divide the change in velocity by the amount of time that has passed.

We refer to an object as accelerating when its velocity changes. As a result, acceleration is the rate at which a velocity changes over time. Acceleration is the common term used to describe an increase in speed.

For instance, the average acceleration of a crazy ball would be 20 cm/s/s if its velocity increased from 0 to 60 cm/s in 3 seconds. The marble's velocity will therefore rise by 20 cm/s per second as a result. You can better comprehend the operation by using the table below:

Note that an overview was given as the complete question wasn't found.

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Answer:

The correct answer is: B: The first 15 minutes is a curve that is concave downward, the middle portion is a straight line with slope 100 miles/hour, and the last portion is a concave upward curve.

Explanation:

The first 15 minutes of the journey, the train is accelerating from rest to reach a constant velocity of 100 miles/hour. The position vs time graph of this portion of the journey would be a curve that is concave downward, as the acceleration is positive and the velocity is increasing.

The middle portion of the journey, the train is moving at a constant velocity of 100 miles/hour. The position vs time graph of this portion of the journey would be a straight line with slope 100 miles/hour, as the velocity is constant.

The last 15 minutes of the journey, the train is slowing down to come to a stop. The position vs time graph of this portion of the journey would be a curve that is concave upward, as the acceleration is negative and the velocity is decreasing.

If a mass slides down an incline, and the slope is frictionless, the gravitational potential energy is transformed to kinetic energy as it descends.

In physics, an object's kinetic energy is the energy it has as a result of its motion. It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity. The body retains its kinetic energy after gaining it during acceleration until its speed changes. Kinetic energy is the energy that an item has as a result of its movement. If we wish to accelerate an item, we must apply force to it. Using force demands us to put in effort. After work is completed, energy is transferred to the item, and the thing moves at a new constant speed.

Here,

When a mass slides down an incline with no friction, its gravitational potential energy is converted to kinetic energy as it falls.

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Answer: Tim gains a potential energy of 3227.93 Joules.

Explanation:

Tim, with mass 76.6 kg, climbs a gymnasium rope a distance of 4.3 m. The acceleration of gravity is 9.8 m/s². How much potential energy does Tim gain?

Data:

m = 76.6 kg

h = 4.3 m

a = 9.8 m/s²

Ep = ?

To calculate potential energy, we have the formula

Where

Since it asks us to calculate Tim's potential energy, we should not do formula clearance.

Therefore, we substitute data in the formula and solve, then

Ep = 76.6 kg × 9.8 m/s² × 4.3 m

Ep = 3227.93 kg × m/s² × m

Ep 3227.93 N × m

Ep = 3227.93 Joules

Tim gains a potential energy of 3227.93 Joules.

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The density of the small spheres with a diameter of 1.05mm and a terminal velocity of 2.34 cm/s is 42.97m/s³.

Density is a measurement which compares the amount of matter occupied by an object with its volume. An object with much matter in a certain amount of volume has high density. Whereas, an object with a little matter in the same amount of volume has a low density.

We know that density of water,

σ = 1.00 × 10⁻³ kg/m³ and coefficient of viscosity for water, η = 10⁻³ Pa.s

Given,

Terminal speed, v = 2.34 cm/s = 0.0234 m/s

Radius of sphere, r = d/2 = 1.05/2 = 0.525mm = 0.0005m

Using the formula of terminal speed,

v = 2(ρ − σ)gr²/ 9η

0.0234 = 2(ρ - 1.00 × 10⁻³) × 9.8 × 0.0005²/ 9 × 10⁻³

0.0234 = 2(ρ - 1.00 × 10⁻³) × 9.8 × 0.00000025/ 9 × 10⁻³

0.0234 = 2(ρ - 1.00 × 10⁻³) × 0.00000245/ 9 × 10⁻³

0.0234 × 9 × 10⁻³/ 2 ×  0.00000245 = ρ - 1.00 × 10⁻³

0.2106× 10⁻³/ 0.0000049 = ρ - 1.00 × 10⁻³

0.0002106/ 0.0000049 = ρ - 1.00 × 10⁻³

42.97 = ρ - 1.00 × 10⁻³

ρ = 42.97m/s³

Therefore, the density of the small spheres is 42.97m/s³.

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The pressure at the beginning and the end of the pipe cannot be determined without additional information.

Velocity is a vector quantity that measures the rate of change of an object’s position in a given direction. It is the rate of displacement over time, or the speed at which an object is moving. Velocity is the speed of an object in a particular direction. It is measured in meters per second (m/s) or kilometers per hour (km/h). Velocity is a combination of both speed and direction, and it can also be represented by an arrow pointing in the direction of motion.

The pressure at the beginning of the pipe (P1) will be determined by the pressure of the source supplying the pipe, such as a pump, as well as the friction losses that occur along the pipe. The pressure at the end of the pipe (P2) will be determined by the available pressure of the source supplying the pipe, the friction losses that occur along the pipe, and the velocity at the end (v2). As such, without knowing the source pressure, the friction losses, and the velocities, it is impossible to determine whether P1 is less than, equal to, or greater than P2.

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When the price is set at $20, the rate of change in sales volume is -0.086. The number of units sold will fall by 86.

Volume is defined as the space occupied by an item inside the confines of three-dimensional space. It is also known as the object's capacity. Volume is a measurement of an object's capacity. For example, the capacity of a cup is 100 ml if it can carry 100 ml of water up to the brim. Volume is also the amount of space filled by a three-dimensional object. Volume and mass are the two fundamental qualities of matter. Volume is simply the amount of space occupied by a thing. There are several methods for measuring volume depending on the physical condition of an item.

Here,

dy/dp = -174/5 [3p + 1]^-7/5

Substitute p = 20 in the above equation, we get

dy/dp = -0.086

(b) The sales volume will decrease by 86 units.

The rate of change in sales volume when the price is $20 is -0.086. The sales volume will decrease by 86 units.

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The box will go 7.5 meter before it stops.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Initial speed of the box = 10 m/s.

Final speed of the box = 0 m/s.

Deacceleration of the box = (40 ÷ 6) m/s² = (20/3) m/s²

Hence, distance travelled  before it stops = u²/2a

= 10²/(2 ×20/3) m

= (100 × 3)/(2 × 20) m

= 7.5 m.

So, the box will go 7.5 meter before it stops.

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The problems ask to find and plot z[n] = x[2–2n] using [tex]a^{u[n]}[/tex] the function, reconstruct a[n] using linear interpolation and time scaling transformations, and find no and ni such that [n] = p[n+ni) is odd and sketch x[n] for the signal p[n] = u[n+ 7] – u[n+ 3] – u[n + no] + u[n +2].

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The question is -

For problems asking for a sketch, be sure to label heights and times. Show intermediate steps of your work. 1. Combinations of transformations: Let x[n] = a^u[n], where a > 1, find and plot z[n] = x [2–2n). 2. Example of noninvertible transformations: The signal x[n] and two series of time scaling transformations for x[n] are provided below. Try to reconstruct a[n] with each series of transformations. Are both series of transformations invertible? Use linear interpolation if you need to and write down the general formula for calculating the interpolated values. x[n] n -2 -1 0 1 2 3 4 5 5 x[3n] x/r/3] x[n/3] x[n] x[n] x[n/3] x[3n] x[n] x[n] 3. Even/Odd + Step Function: For the signal p[n] = u[n+ 7] – u[n+ 3] – u[n + no] + u[n +2], find no and nį such that [n] = p[n+ni) is odd and sketch x[n].

Answer:

speed of response and response time , lag , fidelity,and dynamic errors are the dynamic characteristics of instruments.