Imagine that a researcher develops a new cancer drug that shrinks tumors, which she measures using an MRI. The researcher needs to determine if the new drug performs differently from, or the same as, the current gold-standard drug therapy which shrinks tumor diameter by an average of 0.1 mm. After performing an experiment to test the new drug on a group of 6399 cancer patients, the researcher analyzes the measurements of tumor shrinkage by using a one-sample z-test for a mean at the significance level of α = 0.05, with power of 0.94. Assume that the researcher knows the standard deviation of tumor reduction is Ï = 2.5 mm. perhaps from, previous studies with similar populations. Assuming that in fact the null hypothesis is true and that the new cancer drug shrinks tumors by the same amount as the gold-standard drug, what is the probability that the test will lead the researcher to this decision? Give the probability as a percentage to the nearest whole number. _________%

Answer:

It is a 9/10 chance of having at least one boy. The probability is also high enough for the couple to be very confident in having at least one boy in 9 children.

Step-by-step explanation:

I listed all of the possible combinations below

GGGGGGGGG           BGGGGGGGG

BBGGGGGGG           BBBGGGGGG

BBBBGGGGG           BBBBBGGGG

BBBBBBGGG            BBBBBBBGG

BBBBBBBBG             BBBBBBBBB

Total number of combinations with at least one boy is 9/10

This is a very high percentage, which means the couple is very likely to have at least one boy.

Answer:

[tex]\boxed{\sf \ \ \ a = 1 \ \ \ }[/tex]

Step-by-step explanation:

Hello,

saying that [tex]x-\sqrt{a}[/tex] is a factor means that [tex]\sqrt{a}[/tex] is a zero which means

[tex]2(\sqrt{a})^4-2a^2(\sqrt{a})^2-3*\sqrt{a}+2a^3-2a^2+3=0\\\\<=> 2a^2-2a^3-3*\sqrt{a}+2a^3-2a^2+3=0\\\\<=>3-3*\sqrt{a}=0\\\\<=>\sqrt{a}=\dfrac{3}{3}=1\\\\<=> a = 1[/tex]

so the solution is a = 1

Do not hesitate if you have any question

Answer:

u forgot picture

Step-by-step explanation:

if not then define ea

werido modz... up for a laugh? I can't answer a question that is measure ea with no picture nor any info

Answer:

Step-by-step explanation:

Given the expression [tex]log_81000 = log_210[/tex], to prove this expression is true using the properties of logarithm, we will follow the following steps.

Starting from the Left Hand Side:

Step-by-step explanation:

use length x width x height

Answer: 13.5

Step-by-step explanation:

30% = 0.3.

Thus, simply do 0.3*45 to get 13.5.

Hope it helps <3

Answer:

A. 2x

Step-by-step explanation:

Step 1: Factor out a 2

2(2x³ - x² + 4x)

Step 2: Factor out an x

2x(2x² - x + 4)

So our answer is B.

Answer:

20% probability that a box weighs more than 32.2 ounces

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X higher than x is given by the following formula.

[tex]P(X > x) = \frac{b-x}{b-a}[/tex]

Uniform distribution ranging from 31 to 32.5 ounces.

This means that [tex]a = 31, b = 32.5[/tex]

What is the probability that a box weighs more than 32.2 ounces?

[tex]P(X > 32.2) = \frac{32.5 - 32.2}{32.5 - 31} = 0.2[/tex]

20% probability that a box weighs more than 32.2 ounces

Step-by-step explanation:

[tex] \frac{2}{ \sqrt{9} } [/tex]

[tex] \frac{2 \times \sqrt{9} }{ \sqrt{9} \times \sqrt{9} } [/tex]

[tex] \frac{2 \sqrt{9} }{9} [/tex]

Answer:

[tex]\frac{2\sqrt{9} }{9}[/tex]

Step-by-step explanation:

[tex]\frac{2}{\sqrt{9} } \\[/tex]

[tex]\frac{2}{\sqrt{9} } * \frac{\sqrt{9} }{\sqrt{9} }[/tex]

[tex]\frac{\sqrt{9} }{\sqrt{9} }[/tex]  is equal to 1, so it doesn't change the value, just helps us simplify.

[tex]\frac{2\sqrt{9} }{9}[/tex]

There are no common factors between 2 and root 9, so we are done

Answer:

Step-by-step explanation:

Factors of 12

2, 3 , 6 , 4, 1, 12

Answer:

Step-by-step explanation:

Let x represent the rate of the freight train. If the rate of the passenger train is 15 MPH faster than the rate of the frieght train, it means that the rate of the passenger train is x + 15

Time = distance/speed

Time that it will take a passenger train to travel 245 miles is

245/(x + 15)

Time that it will take a fright train to travel 200 miles is

200/x

Since both times are the same, it means that

245/(x + 15) = 200/x

Cross multiplying, it becomes

245x = 200(x + 15)

245x = 200x + 3000

245x - 200x = 3000

45x = 3000

x = 3000/45 = 66.67 mph

Rate of freight train is 66.67 mph

Rate of passenger train is 66.67 + 15 = 81.67 mph

Step-by-step explanation:

let the larger number be x and smaller number be y

according to this question

x=y+33----------(1)

y+33+5y=129----------(2)

6y+33=129

y=16

x=16+33(takimg equation (1)

x=49

Answer:

Larger number: 49.

Smaller number: 16.

Step-by-step explanation:

Let's say that the larger number is represented by y, and the smaller is represented by x.

y = 33 + x

y + 5 * x = 129

(33 + x) + 5x = 129

6x + 33 = 129

6x = 96

x = 16

y = 33 + 16

y = 49

Check our work...

49 + 5 * 16 = 49 + 80 = 129

49 = 33 + 16 = 49

Since it all works out, the larger number is 49 and the smaller number is 16.

Hope this helps!

The mass of the lamina is 6 units.

The center of mass of the lamina is (X,Y) = (-3/2, 9/2).

Here,

To find the mass and center of mass of the lamina, we need to integrate the density function ρ(x, y) over the triangular region D.

The mass (M) of the lamina is given by the double integral of the density function over the region D:

M = ∬_D ρ(x, y) dA

where dA represents the differential area element.

The center of mass (X,Y) of the lamina can be calculated using the following formulas:

X = (1/M) ∬_D xρ(x, y) dA

Y = (1/M) ∬_D yρ(x, y) dA

Now, let's proceed with the calculations:

The triangular region D has vertices (0, 0), (2, 1), and (0, 3). We can define the limits of integration for x and y as follows:

0 ≤ x ≤ 2

0 ≤ y ≤ 3 - (3/2)x

Now, let's calculate the mass (M):

M = ∬_D ρ(x, y) dA

M = ∬_D 2(x + y) dA

We need to set up the double integral over the region D:

M = ∫[0 to 2] ∫[0 to 3 - (3/2)x] 2(x + y) dy dx

Now, integrate with respect to y first:

M = ∫[0 to 2] [x(y²/2 + y)] | [0 to 3 - (3/2)x] dx

M = ∫[0 to 2] [x((3 - (3/2)x)²/2 + (3 - (3/2)x))] dx

M = ∫[0 to 2] [(3x - (3/2)x²)²/2 + (3x - (3/2)x²)] dx

Now, integrate with respect to x:

[tex]M = [(x^3 - (1/2)x^4)^2/6 + (3/2)x^2 - (1/4)x^3)] | [0 to 2]\\M = [(2^3 - (1/2)(2^4))^2/6 + (3/2)(2^2) - (1/4)(2^3)] - [(0^3 - (1/2)(0^4))^2/6 + (3/2)(0^2) - (1/4)(0^3)]\\M = [(8 - 8)^2/6 + 6 - 0] - [0]\\M = 6[/tex]

So, the mass of the lamina is 6 units.

Next, let's calculate the center of mass (X,Y):

X = (1/M) ∬_D xρ(x, y) dA

X = (1/6) ∬_D x * 2(x + y) dA

We need to set up the double integral over the region D:

X = (1/6) ∫[0 to 2] ∫[0 to 3 - (3/2)x] x * 2(x + y) dy dx

Now, integrate with respect to y first:

X = (1/6) ∫[0 to 2] [x(y² + 2xy)] | [0 to 3 - (3/2)x] dx

X = (1/6) ∫[0 to 2] [x((3 - (3/2)x)² + 2x(3 - (3/2)x))] dx

X = (1/6) ∫[0 to 2] [x(9 - 9x + (9/4)x² + 6x - (3/2)x²)] dx

X = (1/6) ∫[0 to 2] [(9/4)x³ - (3/2)x⁴ + 15x - (3/2)x³] dx

Now, integrate with respect to x:

[tex]X = [(9/16)x^4 - (3/8)x^5 + (15/2)x^2 - (3/8)x^4] | [0 to 2]\\X = [(9/16)(2)^4 - (3/8)(2)^5 + (15/2)(2)^2 - (3/8)(2)^4] - [(9/16)(0)^4 - (3/8)(0)^5 + (15/2)(0)^2 - (3/8)(0)^4]\\X = [9/2 - 12 + 15 - 0] - [0]\\X = 15/2 - 12\\X = -3/2[/tex]

Next, let's calculate Y:

Y = (1/M) ∬_D yρ(x, y) dA

Y = (1/6) ∬_D y * 2(x + y) dA

We need to set up the double integral over the region D:

Y = (1/6) ∫[0 to 2] ∫[0 to 3 - (3/2)x] y * 2(x + y) dy dx

Now, integrate with respect to y first:

Y = (1/6) ∫[0 to 2] [(xy² + 2y²)] | [0 to 3 - (3/2)x] dx

Y = (1/6) ∫[0 to 2] [x((3 - (3/2)x)²) + 2((3 - (3/2)x)²)] dx

Y= (1/6) ∫[0 to 2] [x(9 - 9x + (9/4)x²) + 2(9 - 9x + (9/4)x²)] dx

Y = (1/6) ∫[0 to 2] [(9x - 9x² + (9/4)x³) + (18 - 18x + (9/2)x²)] dx

Now, integrate with respect to x:

[tex]Y= [(9/2)x^2 - 3x^3 + (9/16)x^4) + (18x - 9x^2 + (9/6)x^3)] | [0 to 2]\\Y = [(9/2)(2)^2 - 3(2)^3 + (9/16)(2)^4) + (18(2) - 9(2)^2 + (9/6)(2)^3)] - [(9/2)(0)^2 - 3(0)^3 + (9/16)(0)^4) + (18(0) - 9(0)^2 + (9/6)(0)^3)]\\Y = [18 - 24 + 9/2 + 36 - 36 + 12] - [0]\\Y= 9/2[/tex]

So, the center of mass of the lamina is (X,Y) = (-3/2, 9/2).

Learn more about mass here

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Answer:

Her temperature is 97.27ºF.

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 98.2, \sigma = 0.62[/tex]

Z = -1.5. What is her​ temperature?

Her temperature is X when Z = -1.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.5 = \frac{X - 98.2}{0.62}[/tex]

[tex]X - 98.2 = -1.5*0.62[/tex]

[tex]X = 97.27[/tex]

Her temperature is 97.27ºF.

Answer:

Function

Step-by-step explanation:

A function is a relation where each x-value has only one y-value. In this problem, all the x-values have a y-value of 3. It is a function because even though they all share the same y-value, they don't have more than one y-value. It would be a relation but not a function if one x-value had two y-values.

Hope this helps. :)

Answer:

For 90% CI = (0.428, 0.572)

For 98% CI = (0.399, 0.601)

The confidence interval (and Margin of error) reduces when 90% confidence level is used compared to when 98% confidence level is used.

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

p+/-z√(p(1-p)/n)

Given that;

Proportion p = 66/132 = 0.50

Number of samples n = 132

Confidence level = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

0.50 +/- 1.645√(0.50(1-0.50)/132)

0.50 +/- 1.645√(0.001893939393)

0.50 +/- 0.071589436011

0.50 +/- 0.072

(0.428, 0.572)

The 90% confidence level estimate of the true population proportion of students who responded "yes" is (0.428, 0.572)

For 90% CI = (0.428, 0.572)

For 98% CI = (0.399, 0.601)

The confidence interval (and Margin of error) reduces when 90% confidence level is used compared to when 98% confidence level is used.

Answer:

E = { x l x is a perfect square <36}

And we can rewrite it taking in count the list of all the perfect squares less than 36 and we have:

1= 1*1

4= 2*2

9 = 3*3

16 =4*4

25= 5*5

And we can rewrite the set on this way:

E= {1,4,9,16,25}

Step-by-step explanation:

For this problem we have the following set:

E = { x l x is a perfect square <36}

And we can rewrite it taking in count the list of all the perfect squares less than 36 and we have:

1= 1*1

4= 2*2

9 = 3*3

16 =4*4

25= 5*5

And we can rewrite the set on this way:

E= {1,4,9,16,25}

Answer:

The following combination describes a regression line that is a good fit for the data

a. Larger R-sq and small Se

Step-by-step explanation:

In regression analysis, we measure the goodness of fit in terms of two parameters.

1. R² ( R-squared or also called the coefficient of determination)

2. SE ( Standard Error)

1. R-squared

The R-squared indicates the relative measure of the percentage of the variance with respect to the dependent variable.

R-squared is measured in percentage so it doesn't have any unit.

The greater the R-squared percentage, the better is the goodness of fit.

2. Standard Error

The SE basically indicates that on average how far the data points are from the regression line.

The unit of the standard error is the same as the dependent variable.

The lower the SE, the better is the goodness of fit.

Therefore, the correct option is (a)

a. Larger R-sq and small Se

Answer:

Step-by-step explanation:

First we must first find the LCM

The LCM of x² + 3x + 2 and (x + 2)(x + 1 ) is

x² + 3x + 2

So we have

[tex] \frac{x}{ {x}^{2} + 3x + 2 } - \frac{1}{(x + 2)(x + 1)} \\ \\ = \frac{x - 1}{ {x}^{2} + 3x + 2 } [/tex]

Hope this helps you

Answer:

The answer is OPTION D!

Step-by-step explanation:

HoPe ThIs HeLpS!

Step-by-step explanation:

Net $103.92 [$25.98 ÷ 20%]

List. $129.90 [ $103.92 + $25.98]

Answer:

The nth term rule of the quadratic sequence is [tex]2n^{2} +5n-3[/tex].

Step-by-step explanation:

We are given the following quadratic sequence below;

4, 15, 30, 49, 72, 99, 130,...

As we know that the formula for the nth term of the quadratic sequence is given by =  [tex]an^{2}+bn+c[/tex]

Firstly, we will find the difference between the term of the given sequence;

1st difference of the given sequence;

(2nd term - 1st term), (3rd term - 2nd term), (4th term - 3rd term), (5th term - 4th term), (6th term - 5th term), (7th term - 6th term)

= (15 - 4), (30 - 15), (49 - 30), (72 - 49), (99 - 72), (130 - 99),....

= (11, 15, 19, 23, 27, 31,.....)

Now, we will find the second difference of the given sequence, i.e;

= (15 - 11), (19 - 15), (23 - 19), (27 - 23), (31 - 27),....

= (4, 4, 4, 4, 4)

Since the differences are same now, so to find the value of a we have to divide the value of second difference by 2, i.e;

The value of a  =  [tex]\dfrac{4}{2}[/tex] = 2

SO, the first term of the nth term rule equation is [tex]an^{2}[/tex] = [tex]2n^{2}[/tex].

Now, in the term [tex]2n^{2}[/tex], put the value of n = 1, 2, 3, 4 and 5 and then form the sequence, i.e;

If n = 1, then [tex]2n^{2}[/tex] = [tex]2 \times (1)^{2}[/tex] = 2

If n = 2, then [tex]2n^{2}[/tex] = [tex]2 \times (2)^{2}[/tex] = 8

If n = 3, then [tex]2n^{2}[/tex] = [tex]2 \times (3)^{2}[/tex] = 18

If n = 4, then [tex]2n^{2}[/tex] = [tex]2 \times (4)^{2}[/tex] = 32

If n = 5, then [tex]2n^{2}[/tex] = [tex]2 \times (5)^{2}[/tex] = 50

SO, the sequence formed is (2, 8, 18, 32, 50).

Now, find the difference of this sequence and the original quadratic sequence, i.e;

= (4 - 2), (15 - 8), (30 - 18), (49 - 32), (72 - 50)

= (2, 7, 12, 17, 22)

Now, as we can see that the above sequence resembles the general form of (5n - 3) because:

If we put n = 1, then (5n - 3) = 5 - 3 = 2

If we put n = 2, then (5n - 3) = 10 - 3 = 7 and so on....

From this, we concluded that the value of b and c are 5 and (-3) respectively.

Hence, the nth term rule for the given quadratic sequence is [tex]2n^{2} +5n-3[/tex].

Answer:

B

Step-by-step explanation:

Answer:

4. 9.1 – 10 = 0.2x

X= -4.5

Step-by-step explanation:

Let's solve for x in the equations given below

1. 9.1 = -0.2x + 10

9.1 - 10 = -0.2x

-0.9= -0.2x

-0.9/-0.2= x

4.5 = x

2. 10 = 9.1 + 0.2x

10-9.1 = 0.2x

0.9= 0.2x

0.9/0.2 = x

4.5 = x

3. 10 – 0.2x = 9.1

10-9.1= 0.2x

0.9= 0.2x

0.9/0.2= x

4.5 = x

4. 9.1 – 10 = 0.2x

-0.9 = 0.2x

-0.9/0.2= x

-4.5 = x

The different equation is equation 4

Reason because it's answer gave a negative value of x while others gave a positive value of x.

But in magnitude they all have same value of x

Answer:Its D

Step-by-step explanation:

I just did it on ed

Answer:

50 %

Step-by-step explanation:

p not greater than 5 means 5 or <5

so half of spinner means probability 50 %

Answer:

Where is the table because I dont see it up here?

━━━━━━━☆☆━━━━━━━

▹ Answer

#3. 1.89/100

▹ Step-by-Step Explanation

1.89 → hundreths place so..

1.89/100 is the correct answer

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

The required sample size increases.

Step-by-step explanation:

The margin of error of a confidence interval is given by:

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which z is related to the confidence level(the higher the confidence level the higher z), [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

In this question:

The confidence level decreases, so z decreases.

For the margin of error to stay the same, the sample size also has to decrease.

The required sample size increases.

Answer:

for us to be able to ascertain whether a function has no limit we approach from two points which are from zero and infinity.

Step-by-step explanation:

the two best path to approach a function is to approach from zero and approach from infinity, literary what we are trying to do is approach from the smallest to the greatest and it each point we can conclude with certainty whether the function has a limit or not.