im so lost :(((((((((((((((((((

Answer:

I am doing this question right now once I submit I will come back and tell you

Step-by-step explanation:

If all 20 students joined the same event, the shape of the histogram will change as compared to the original. A.) The Chili Cook-off would be more skewed and D.) The Pie Eating Contest would be less symmetrical.

If 20 students get added to the 0-19 age group in Chili Cookoff contest, the frequencies of the number of students would be 50, 50, 40, 10. Since,  the frequencies are decreasing with increasing age group, the histogram is skewed.

If the data are symmetric, histogram have about the same shape on either side of the middle. In other words, if you fold the histogram in half, it looks about the same on both sides.

If we add 20 to the 0-19 age group in Pie eating contest, the frequencies of the number of students would be 40, 40, 60, 50. Since the frequencies are monotonically increasing and then decreasing, the histogram is symmetrical but it doesn't look exactly same on either side.

Learn more about symmetric and skewed histogram here

https://brainly.com/question/1812585

#SPJ2

Answer:

[tex] \sqrt{2} [/tex]

Hope it helps

pls give brainliest

Answer:

rotation

Step-by-step explanation:

Answer:

speak

Step-by-step explanation:

Answer:

Because there are 9 sour straws in total and 3 blue sour straws, the probability of pulling out a blue sour straw would be 3/9 or 1/3. Because we aren't replacing it, that means that there's one less straw in the box so there should only be 8 straws left. Because there's 4 pink sour straws, the probability of pulling out a pink sour straw is 4/8 or 1/2.

Answer:

0.1764

Step-by-step explanation:

This problem meets requirement that enables us to use the binomial probability relation :

Probability of success, p = 17% = 0.17

number of trials = 9

(1 - p) = 1 - 0.17 = 0.83

The binomial probability relation :

P(x = x) = nCx * p^x * (1 - p)^(n-x)

P(x = 3) = 9C3 * 0.17^3 * 0.83^6

P(x = 3) = 84 * 0.001606258054361897

P(x = 3) = 0.134925676566399348

P(x = 3) = 0.13492

P(x = 4) = 9C4 * 0.17^4 * 0.83^5

P(x = 4) = 126 * 0.000328992613544003

P(x = 4) = 0.041453069306544378

P(x = 4) = 0.04145

P(x = 3 or x = 4) = P(x = 3) + p(x = 4)

= 0.13492 + 0.04145

= 0.17637

= 0.1764

Answer:

i think the answer should be 4y(m+3)/a^2

Step-by-step explanation:

Answer:

347,392

Step-by-step explanation:

yes

Step-by-step explanation:

Make sure the bottom line of the angle points to 0. Then slowly go up until the other line hits a number. In this case, it's 40 degrees

Answer: $2

Step-by-step explanation:

Answer:

[tex]A(t) = 1400(1 - e^{\frac{-t}{50}})[/tex]

Step-by-step explanation:

The net mass flow rate dA/dt = mass flow rate in - mass flow rate out

mass flow rate in = concentration of brine in × brine flow rate in = 4 lb/gal × 7 gal/min = 28 lb/min

Let A(t) be the amount of salt at time t. The concentration of salt in the tank at time, thus C = amount of salt/volume of tank = A(t)/700 lb/gal.

Since the well mixed solution is pumped out at a rate of 14 gal/min, the mass flow rate out = concentration of salt in tank × volume flow rate out = A(t)/700 lb/gal × 14 gal/min = m(t)/50 lb/min

So, dA/dt = mass flow rate in - mass flow rate out

dA/dt = 28 lb/min - A(t)/50 lb/min

dA/dt = 28 - A(t)/50

dA/dt = [1400 - A(t)]/50

separating the variables, we have

dA/[1400 - A(t)] = dt/50

integrating both sides, we have

∫dA/[1400 - A(t)] = ∫dt/50

-1/-1 × ∫dA/[1400 - A(t)] = ∫dt/50

1/-1 × ∫-dA/[1400 - A(t)] = ∫dt/50

-1 × ㏑[1400 - A(t)] = t/50 + C

-㏑[1400 - A(t)] = t/50 + C

㏑[1400 - A(t)] = -t/50 - C

taking exponents of both sides, we have

[tex]1400 - A(t) = e^{\frac{-t}{50} - C} \\1400 - A(t) = e^{\frac{-t}{50}}e^{-C}\\1400 - A(t) = Be^{\frac{-t}{50}} ( B = e^{-C}) \\A(t) = 1400 - Be^{\frac{-t}{50}}[/tex]

when t = 0, A(0) = 0. So,

[tex]A(t) = 1400 - Be^{\frac{-t}{50}}\\A(0) = 1400 - Be^{\frac{-0}{50}}\\0 = 1400 - Be^{0}\\0 = 1400 - B\\B = 1400[/tex]

So,

[tex]A(t) = 1400 - 1400e^{\frac{-t}{50}}\\A(t) = 1400(1 - e^{\frac{-t}{50}})[/tex]

Answer:

Binomial distribution

Step-by-step explanation:

Each tiger:

For each tiger, there are only two possible possible outcomes. Either it is yellow, or it is not. The probability of a tiger being yellow is independent of any other tiger. This means that the binomial probability distribution is used to solve this question.

Answer:

x=[tex]\frac{4}{5}[/tex]

y=[tex]\frac{23}{5}[/tex]

Step-by-step explanation:

Look at the pictures!

Answer:

37.5x

Step-by-step explanation:

Answer:

ΔSTU ≅ ΔBDC

Step-by-step explanation:

In ΔSTU and ΔBDC,

∠S ≅ ∠B [Given]

∠T ≅ ∠D [Given]

SU ≅ BC [Given]

Since, two corresponding angles and non included side of the angles are equal in measure.

Therefore, ΔSTU ≅ ΔBDC [By AAS property of congruence]

Answer:

C, D and F

Step-by-step explanation:

Procedure:

9x+5=5x+21

4x+5=21 (subtract 5x)

4x=16 (subtract 5)

x=4 (divided by 4)

Answer:

A≈1385.44in²

Step-by-step explanation:

A=πr2=π·212≈1385.44236in²

Answer:

1384.74 inches.

Step-by-step explanation:

The formula for area of a circle is:

[tex]a=\pi *r^2(3.14*radius*radius)[/tex]

[tex]\pi =3.14, r=radius.[/tex]

According to the word problem, the radius of the circle is 21 inches.

Now, we can just plug the numbers into the formula.

[tex]\pi *21^2(3.14*21*21)=1384.74[/tex]

Therefore, the area of the circle is 1384.74 inches.

Answer:

Volume of iron used is 58982cm

Step-by-step explanation:

For hollow cylinder,

\bold{Height=9cm}Height=9cm

\bold{Internal \ radius=21cm}Internal radius=21cm

\bold{Externa \ radius=28cm}Externa radius=28cm

volume \: of \: cylinder = \pi \times {r}^{2} \times h \:volumeofcylinder=π×r

2

×h

\bold{Volume \ of \ cylinder \ with \ hollow \ part}Volume of cylinder with hollow part

\bold{=\frac{22}{7}×28^2×9}=

7

22

×28

2

×9

\bold{=22×4×28×9}=22×4×28×9

\bold{=71456cm^3}=71456cm

3

\bold{Volume \ of \ hollow \ part}Volume of hollow part

\bold{=\frac{22}{7}×21^2×9}=

7

22

×21

2

×9

\bold{=22×3×21×9}=22×3×21×9

\bold{=12474cm^3}=12474cm

3

\bold{Volume \ of \ iron \ used=}Volume of iron used=

\bold{Volume \ of \ cylinder \ with \ hollow \ part}Volume of cylinder with hollow part

\bold{- Volume \ of \ hollow \ part}−Volume of hollow part

{=71456-12474}=71456−12474

{=58982cm^3}=58982cm

3

\bold\red{Volume \ of \ iron \ used \ is \ 58982cm^3}Volume of iron used is 58982cm

3

Answer:

The man has made a profit, for with the same money he bought more British Pounds than he could have bought a week later.

Step-by-step explanation:

Given that a man converted Rs. 150000 into pound sterling, and after one week Nepalese rupees devalued by 5%, to find if you have obtained a profit or a loss, the following calculation must be performed:

150,000 / 77.02 = X

1,947.55 = X

150,000 / (77.02 x 1.05) = X

150,000 / 80.87 = X

1,854.82 = X

Therefore, the man has made a profit, for with the same money he bought more British Pounds than he could have bought a week later.

Answer:

Distance in ft = 597.57 feet

Step-by-step explanation:

As per the

First equation of motion

84 mph = 37.5514 m/s

45 mph = 20.1168 m/s

v-u = a* t

Substituting the given values, we get -

37.5514 m/s - 20.1168 m/s = a * 6.3

a = 2.76 m/s^2

Now as per Newton's third law of motion

v^2-u^2 = 2 *a*S

Substituting the given values, we get -

37.5514^2 - 20.1168^2 = 2 * 2.76 m/s^2 * S

S = 182.142 Meters

Distance in ft = 597.57 feet

Answer:

(-6,2)

Step-by-step explanation:

when it asks for the scale factor all you do is take your coordinates and multiply it by whatever the question gives you. Like in this question you would multiply -3 and 1 by 2 and whatever the number comes out to be then thats your answers.

Sorry if the explanation isnt very good!

Answer:

For a data set of N elements:

{x₁, x₂, ..., xₙ}

The median is the middle value (or the average of the two middle values)

The average or mean is:

[tex]m = \frac{x_1 + ... + x_n}{N}[/tex]

The mode is the value that is more repeated.

The range is the difference between the largest value and the smallest value.

Now, let's try to construct two sets A and B that meet the required conditions:

Let's suppose two sets of 5 values each:

A = {2, 2, 3, 4, 5}

The median of A is 3.

The range of A is = 5 - 2 = 3

The average of A is: (2 + 2 +3 +4 +5)/5 = 16/5

And the value "2" appears two times, so the mode is 2.

Now, let's try to find a data set B such that:

The mode is smaller than 2  (so for example, we can have a "1" that repeats two times)

The median is smaller than 3 (let's have a median equal to 2)

The average is larger than 16/5

The range is larger than 3

This is ratter simple:

B = {1, 1, 2, 6, 9}

The median of B is 2.

The mode of B is 1

The range of B is: 9 - 1 = 8

The average of B is: (1 + 1 + 2 + 6 + 9)/5 = 19/5

So, we just found an example for two data sets A and B such that A has a greater median and mode, while B has a greater average and range.

So the answer is yes, it is possible.

Answer: 6

6b+9y=0 then divide

Step-by-step explanation:

Answer:

64

Step-by-step explanation:

A square has 4 equal sides so all you have to do is divide 4 by 256. 256/4 is equal to 64. Therefore, the answer is 64 paving stones.

If this has helped please mark as brainliest

Answer:

160

Step-by-step explanation:

20 x 2 = 40

40 x 2 = 80

80 x 2 = 160

It stops at 3 years.

Answer:

120

Step-by-step explanation:

20+40+60 = 120

If we double it, we have to keep adding 20 each year and stop at 3 so the answer is 120