ii) Sodium thiosulphate dissolves in dilute nitric acid at a steady rate. Copy out which
of the following changes would quicken up the reaction- 3
a. Cooling the reacting vessel to drop the temperature.
b. Breaking the reactants into smaller pieces.
c. Adding more concentrated acid.
d. Using more sodium thiosulphate.

Answers

Answer 1

Answer:

d

Explanation:

       


Related Questions

the element with atomic number 35 belongs to​

Answers

Bromine is a chemical element with the symbol Br and atomic number 35.
Bromine because if you look at the
Periodic table it will have the number on the top 35 with the letters Br which is short for Bromine.

You are performing an acid-base neutralization reaction in the laboratory to determine the concentration of an unknown base. You are supposed to titrate it with a monoprotic acid, but your lab partner accidentally fills your buret with sulfuric acid, a diprotic acid, with the same concentration as the acid called for in the experiment. How will the volume of diprotic acid compare to the volume of monoprotic acid you would have used

Answers

Answer:

Volume is reduced to half

Explanation:

Acid base titration are commonly used reactions in a lab, and are ofter used to get pH or different kind of solutions.

The neutralization of an acid base reaction is reached, when the solution (having added an indicator previously) changes its original color. chemically speaking, this occurs when the number of moles of the acid and the base are balanced and equal. In other words the following:

n₁ = n₂   (1)

This expression can also be expressed in function of concentration and volume:

M₁V₁ = M₂V₂   (2)

From here, solving for V₁:

V₁ = M₂V₂  / M₁

Now, this expression is true only when we have the same kind of substance that can lose or gain the same number of hydrogens.

Lets suppose that we have as base NaOH (Monoprotic base) and HCl (monoprotic acid), the titration reaction would be:

NaOH + HCl --------> NaCl + H₂O

As both of the species are monoprotic, the number of moles are the same  when they reach the equilibrium, so, expression  (2) can be used, and calculate volume or concentrations.

However, in this case, a partner made a mistake and use a diprotic acid, in this case, H₂SO₄, In this case, things chance because H₂SO₄ is diprotic, meaning that we need to dissociate two hydrogens in equilibrium, therefore, expression (2) would be something like this.

Acid: 1; Base: 2

H₂SO₄ + 2NaOH ------> Na₂SO₄ + H₂O

nH₂SO₄ = n₁ = 1

nNaOH = n₂ = 2

n₁/n₂ = 1/2

2n₁ = n₂   (3)

Writting this, in function of concentration and volume, it would be:

2M₁V₁ = M₂V₂   (4)

From here, if we solve for the volume of the acid (V₁):

V₁ = M₂V₂ / 2M₁

Therefore, according to this expression, we can see that the volume required of the acid would be half the volume required of the monoprotic acid. For example, if we need 50 mL of Chloridic acid to reach the equivalence point with NaOH, then, with H₂SO₄ it will only need 25 mL. This, of course, assuming that concentrations are the same, and volume of the base used, the same.

Hope this helps

The city of Annandale has been directed to upgrade its primary wastewater treatment plant to a secondary treatment plant with sludge recycle that can meet an effluent standard of 11 mg/l BOD5. The following data are available: Flow = 0.15 m3/s, MLSS = 2,000 mg/L. Kinetic parameters: K, = 50 mg/L, Hmax = 3.0 d-, kų = 0.06 d-1, Y = 0.6 Existing plant effluent BOD5 = 84 mg/L. a. Calculate the SRT (Oc) and HRT (0) for the aeration tank. b. Calculate the required volume of the aeration tank. c. Calculate the food to microorganism ratio in the aeration tank. d. Calculate the volumetric loading rate in kg BOD3/m3-d for the aeration tank. e. Calculate the mass and volume of solids wasted each day, when the underflow solids concentration is 12,000 mg/L. 10 A

Answers

Oh that’s hard I can’t figure that out sorry bud:(

7. Which object would be the least dense in a tub of
water?
A. Golf ball
B. Glass marble
C. Rubber ball
D. Beach ball

Answers

The most dense one out of all of the answers would be the glass marble with a higher density than that of the golf ball and the rubber ball
Beach ball because it has less mass causing it to float

Consider the oxidation of sodium metal to sodium oxide described by the balanced equation:
4 Na + O2 → 2 Na2O. What is the theoretical yield of Na2O in grams from 9.0 mol of O2?


show steps

Answers

Answer:

1116 g.

Explanation:

The balanced equation for the reaction is given below:

4Na + O₂ —> 2Na₂O

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of Na₂O.

Next, we shall determine the theoretical yield of Na₂O. This can be obtained as follow:

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of Na₂O.

Therefore, 9 moles of O₂ will react to produce = 9 × 2 = 18 moles of Na₂O.

Finally, we shall determine the mass in 18 moles of Na₂O. This can be obtained as follow:

Mole of Na₂O = 18 moles

Molar mass of Na₂O = (23×2) + 16

= 46 + 16

= 62 g/mol

Mass of Na₂O =?

Mass = mole × molar mass

Mass of Na₂O = 18 × 62

Mass of Na₂O = 1116 g

Thus, the theoretical yield of Na₂O is 1116 g.

What is the molarity of a solution containing 7.47 moles of solute in 4.31 liters of
solvent?

Answers

Answer:

1.73 M

Explanation:

Molarity is moles per liter, so we need to divide 7.47 moles by 4.31 liters to get the molarity of the solution.

7.47/4.31 ≈ 1.73 M

Howyiong did Newton live?

Answers

84 years (1643-1727)

Answer:4 January 1643 [O.S. 25 December 1642] Woolsthorpe-by-Colsterworth, Lincolnshire, England

Died 31 March 1727 (aged 84) [O.S. 20 March 1726] Kensington, Middlesex, Great Britain

Explanation:

A 35 Liter tank of Oxygen is at 315 K with an internal pressure of 190 atmospheres. How many moles of gas does the tank contain?

Answers

Bjhjjbhjhhjjhjbhuhbh

how do you solve the expending form for 3(2+5)​

Answers

Answer:

it's expanding from is 15

Answer:

Explanation:

3( 2+5 )

3. ( 7 )

3 . 7= 21

have a good day!

Lisa made observations of stars at different times of the year. She noticed a lot of patterns that the fall, while she couldn't find any patterns in the summer. Why might this be?

Answers

Answer: Because not all stars are in patterns

Answer:

Because the stars do not come out when the temperature rises on Earth

Explanation:

A sugar cube was placed into a beaker containing 100 mL of water at room temperature and completely dissolved into the water. This process is represented by the series of diagrams labeled A, B, and C below. Describe one way that the dissolved sugar at C could be separated from the water.

Answers

Answer:

Boil the water until it evaporates

Explanation:

If the water evaporates the sugar will no longer bond to it and then percipitate at the bottom of the beaker.

What is likely to happen to the trees if the trend continues?

Answers

Answer:

Trees could go extinct and people could die.

Explanation:

A metal forms two oxides X and Y when contains 28.9% and 21.0% oxygen respectively.
a) calculate the ratio by mass of metal in the two oxides
b) what chemical law does it illustrate
Please help no Link please

Answers

And metal phones to Oxsee’s ex and Y1 contains 28.9%Auction and we’re actually calculate the ratio

The number of atoms in a 158.4 g sample of CO2 gas at STP is:

1.277 x 1025 atoms

2.167 x 1024 atoms

6.502 x 1024 atoms

6.651 x 1024 atoms

Answers

Answer:

Option B, 2.167 x 1024 atoms

Explanation:

1 mole of CO2 = 44.01 grams

Number of moles of CO2 in 158.4 gram sample

[tex]\frac{158.4}{44.01} \\3.95[/tex]moles

Number of atoms in one mole is [tex]6.02*10^{23}[/tex]

Number of atoms in 3.95 moles [tex]2.167 *10^{24}[/tex]

Hence, option B is correct


14. A sample of carbon dioxide occupies a 2.54 dm² container at STP. What is the volume of the gas at a
pressure of 150.0 kPa and a temperature of 26.0°C?
0.180 dm
c. 2.24 dm3
b. 1.88 dm
d. 4.65 dm3

Answers

Your answer is D. Hope this helps

By using combined gas law , volume will be 1.88 [tex]dm^{3}[/tex].

What is combined gas law?

The combined gas law contains the laws of Charles, Boyle, and Gay-Lussac. When you know the pressure, volume, and temperature of a system and need to modify one of these, you can apply this law to compute the resulting unknown.

Combined gas law is expressed as:

[tex]$\frac{P_{1} V_{1}}{T_{1}}=\frac{P_{2} V_{2}}{T_{2}}$[/tex]

Calculation of volume by using combined gas law

It is given that, [tex]V_{1}[/tex] = 254[tex]dm^{3}[/tex], at STP P = 101.3 kPa and T = 273 K

Now, put the value of given data in above equation.

[tex]V_{2}[/tex] = (254[tex]dm^{3}[/tex]) (101.3 kPa) (26+273) /(150 kPa) (273)

[tex]V_{2}[/tex] = 1.88 [tex]dm^{3}[/tex].

By using combined gas law  volume will be 1.88 [tex]dm^{3}[/tex].

To know about combined gas law.

https://brainly.com/question/13154969.

#SPJ2


What is the difference between how a mercury barometer and an aneroid barometer measure air pressure?​

Answers

Answer:

Aneroid barometer and mercury barometer are such two types. The main difference between aneroid and mercury barometer is that aneroid barometer measures the atmospheric pressure using the expansion of a metal whereas mercury barometer measures the atmospheric pressure by adjusting the height of mercury inside a tube.

Explanation:

Unlike gases, the behavior of liquids and solids cannot be described by a set of laws that can be applied regardless of the identity of the substance

a. True
b. False

Answers

Answer:

a. True

Explanation:

The gases that we study are governed by different laws of physics. Gases behaves according to some given set of laws like the Universal gas laws, Boyles law, Charles law, Gay Lussac's law and many more.

But we do not see a definite pattern or rule when we study solids or liquids. The behavior of the solids and liquids are not described by the set of laws which are applied regardless of the identity of the substance.

Use the crisscross method to find the chemical formula for the ionic compound formed by aluminum (Al) and sulfur (S). A. Al₂S2 B. AlzS3 C. Al3S2 D. Als​

Answers

Answer:Al2s3

Explanation:

Just took quiz

Give the name of the products
formed
between Benzene and the following Compounds
Br2,Cl2,HNO3,H2SO4,HCOCl
1-chlore-2,2-dimethylpropane

Answers

Answer:

With Br2 - Bromobenzene

With Cl2 - Chlorobenzene

With HNO3- Nitrobenzene

With H2SO4 - Benzenesulphonic acid

With HCOCl - Benzoyl chloride

With 1-chloro-2,2-dimethylpropane - 2,2dimethyl-1-phenyl propane

Explanation:

All the reactions listed above are electrophillic reactions. They are electrophillic reactions because the attacking agents in each reagent is an electrophile. An electrophile means any specie that is electron deficient and attacks regions of high electron density in molecules.

The benzene molecule has rich electron density. Substituents that are electron pushing increases the tendency of benzene to undergo electrophillic substitution reactions while electron withdrawing substituents decrease the the tendency of benzene to undergo electrophillic substitution reactions.

The names of the compounds formed when benzene undergoes electrophillic reaction with different attacking agents have been listed in the answer section.

When determining the amount of an oxidant present by titration, you can use iodine and starch as an indicator.
First, the oxidant, like hypochlorite, oxidizes
Choose...
neutral iodine into iodide ion
iodide ion into neutral iodine
iodate polyatomic ion into iodide ion
When starch and iodine are both present, the solution is
Choose...
blue-black
brownish yellow
clear
During the titration, the titrant, like thiosulfate, reduces the
Choose...
iodide ion into iodate polyatomic ion
neutral iodine into iodide ion
iodide ion into neutral iodine
When the iodine has completely reacted at the endpoint of the titration, the solution should become
Choose...
clear
blue-black
brownish yellow

Answers

Answer:

1. iodide ion into neutral iodine

2. blue-black

3. neutral iodine into iodide ion

4. clear

Explanation:

The function of hypochlorite in iodine titration is to oxidize the iodide ion into iodine molecule as shown below;

ClO-(aq) + 2H+(aq) + 2I-(aq) ---------> 6 I2(l) + Cl- (aq)+ H2O(l)

The addition of starch to iodine leads to the formation of a starch iodide complex which has a blue black colour.

the titrant, thiosulfate, reduces neutral iodine into iodide ion as shown below;

I2  +  2S2O32-  → 2I- + S4O62-

At end point, the solution becomes clear again.

Based on the molar masses. how can you tell that an equation is balanced

Answers

You can tell if each side of the equation has the same molar mass.

CH4 +2H2S = CS2+ 4H2

If the reaction shifts to the right what are the products?

If the reaction shifts to the right, which chemicals decrease in The process?

If the reaction shifts to the left what are the products?

If the reaction shifts to the left, which chemicals decrease in the process?

Answers

Honestly bro I don’t even know I hope you find it

250 mL of a solution of calcium oxalate is the evaporated until only a residue of solid calcium
oxalate is left. The mass of the residue recovered from the container was 154 mg. What is the
solubility product of calcium oxalate?

Answers

Answer:

2.3 * 10^-5

Explanation:

Recall that the solubility of a solute is the amount of solute that dissolves in 1 dm^3 or 1000cm^3 of solution.

Hence;

Amount of calcium oxalate = 154 * 10^-3/128.097 g/mol = 1.2 * 10^-3 mols

From the question;

1.2 * 10^-3 mols dissolves in 250 mL

x moles dissolves in 1000mL

x = 1.2 * 10^-3 mols * 1000/250

x= 4.8 * 10^-3 moldm^-3

CaC2O4(s) ------->Ca^2+(aq) + C2O4^2-(aq)

Hence Ksp = [Ca^2+] [C2O4^2-]

Where;

[Ca^2+] = [C2O4^2-] = 4.8 * 10^-3 moldm^-3

Ksp = (4.8 * 10^-3)^2

Ksp = 2.3 * 10^-5

How many liters are there in 415.4 grams of carbon trioxide?

Answers

Answer:

155.1 L

Explanation:

Step 1: Given data

Mass of CO₃: 415.4 g

Step 2: Calculate the moles corresponding to 415.4 g of CO₃

The molar mass of CO₃ is 60.01 g/mol.

415.4 g × 1 mol/60.01 g = 6.922 mol

Step 3: Calculate the volume occupied by 6.922 moles of CO₃

The volume of a gas depends on conditions such as Temperature and Pressure. Since the conditions are not specified, we may assume that the gas is at Standard Pressure and Temperature (1 atm and 273.15 K). At STP, 1 mole of a gas occupies 22.41 L.

6.922 mol × 22.41 L/1 mol = 155.1 L

PLZ HELP "NO LINKS"
A vessel of volume 22.4 dm3 contains 2.0 mol H2(g) and 1.0 mol N2(g) at 273.15 K.
(a) Calculate the mole fractions of each component.
H2:

N2:

(b) Calculate the partial pressures of each component.
H2:

N2:

(c) Calculate the total pressure.

Thanks!

Answers

Answer: (a) Mole fraction of [tex]H_{2}[/tex] is 0.66.

Mole fraction of [tex]N_{2}[/tex] is 0.33

(b) The partial pressure of [tex]H_{2}[/tex] is 1.98 atm.

The partial pressure of [tex]N_{2}[/tex] is 0.99 atm.

(c) The total pressure is 3.0 atm

Explanation:

Given: Volume = [tex]22.4 dm^{3}[/tex]  (1 [tex]dm^{3}[/tex] = 1 L) = 22.4 L

Moles of [tex]H_{2}[/tex] = 2.0 mol

Moles of [tex]N_{2}[/tex] = 1.0 mol

Total moles = (2.0 + 1.0) mol = 3.0 mol

Temperature = 273.15 K

Now, using ideal gas equation the total pressure is calculated as follows.

[tex]PV = nRT\\[/tex]

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]PV = nRT\\P \times 22.4 L = 3.0 mol \times 0.0821 L atm/mol K \times 273.15 K\\P = 3.0 atm[/tex]

The mole fractions of each component:

The mole fraction of [tex]H_{2}[/tex] is calculated as follows.

[tex]Mole fraction = \frac{moles of H_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{2.0 mol}{(2.0 + 1.0) mol}\\= 0.66[/tex]

The mole fraction of [tex]N_{2}[/tex] is as follows.

[tex]Mole fraction = \frac{moles of N_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{1.0 mol}{(2.0 + 1.0) mol}\\= 0.33[/tex]

The partial pressures of each component:

Partial pressure of [tex]H_{2}[/tex] are as follows.

[tex]P_{H_{2}} = P_{total} \times mole fraction of H_{2}\\= 3.0 atm \times 0.66\\= 1.98 atm[/tex]

Partial pressure of [tex]N_{2}[/tex] are as follows.

[tex]P_{N_{2}} = P_{total} \times mola fraction of N_{2}\\= 3.0 atm \times 0.33\\= 0.99 atm[/tex]

HELP PLISSS !!!!! what did a criminal often use to poison? A. Eye medication. B. potassium cyanide​

Answers

Answer:

potassium cyanide

Explanation:

while eye medications do harm your immune system it is not enough to kill someone. criminals mainly used potassium cyanide because it was cheap. it serves as a substitute for ethanol.

Which statement best defines the term innate behavior?

behavior that is taught through watching others

behavior that is simple, untaught, and born knowing

behavior that is taught through both good and bad experiences

behavior that is untaught but very complex

Answers

Answer: behavior that is simple, untaught, and born knowing

Have a nice dam day!!

The term that describes innate behavior is:

D. behavior that is untaught but very complex

What does innate behavior stand for?

Intr-insic or "intuitive" ways of behaving are innate and don't need learning or related knowledge to be performed. Models incorporate romance and ways of behaving, departure and guarded moves, and hostility. Movement and Migration Innate or ins-tinctual behaviors rely on response to sti-muli.

Thus, option D is correct.

Find more information about Innate behavior here:

brainly.com/question/14311636

How does publishing in scientific journals help ensure that science leads to
reliable results?
A. It allows results to be reviewed and reproduced by other
scientists.
B. It allows the public to decide if science is worthwhile.
C. It shows which experiments are the most popular with scientists.
D. It gives scientists a reason to do more experiments.

Answers

Answer:

A. it allows results to be reviewed and reproduced by other scientists.

Two dogs, one with spots and one with no spots have the same mass and
are running with different velocities. Dog 1 (Dog with no spots) has a
velocity of 1 m/s while Dog 2 (Dog with spots) has a velocity of 2 m/s.
Which dog has a larger kinetic energy and how much larger is its kinetic
energy compared to the other dog

Answers

Answer:

dog 2 because it is running 1m faster a second than dog 1. Dog 2 can run 1 meter farther in a second than the other dog.

hsvsusvshssveuevsjsvsjdvsudvysvwkwhsjwvsgsbkwbsywvejwvsh​

Answers

Sorry, I won't understand your words.

hsjsjskkddemekkekekekekdldllsldldldkkdodoeoekejeqksjccc
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