If you somehow subtracted a proton from a Zirconium atom, it would be?

Answer:

3843.96 × 10²³ atoms

Explanation:

Given data:

Mass of Li = 4430 g

Number of atoms = ?

Solution:

We will calculate the number of moles first.

Number of moles =mass/molar mass

Number of moles = 4430 g/ 6.94 g/mol

Number of moles = 638.32 mol

1 mole contain 6.022 × 10²³ atoms

638.32 mol × 6.022 × 10²³ atoms / 1 mol

3843.96 × 10²³ atoms

Answer:

7 sublimation

8 freezing

9 melting

10 condensation

11 evaporation

Explanation:

Answer:

1) Mass =  890.96 g

2) Mass =  7.67 g

3) 507.65 ×10²³ atoms

Explanation:

1) Given data:

Number of moles of lead = 4.3×10⁻³ mol

Mass of lead = ?

Solution:

Mass = number of moles × molar mass

Molar mass of lead = 207.2 g/mol

by putting values,

Mass = 4.3×10⁻³ mol × 207.2 g/mol

Mass =  890.96 g

2) Given data:

Number of atoms of antimony = 3.8×10²² atoms

Mass of antimony = ?

Solution:

1 mole contain 6.022 ×10²³ atoms

3.8×10²² atoms × 1 mol / 6.022 ×10²³ atoms

0.63×10⁻¹ mol

0.063 mol

Mass:

Mass = number of moles × molar mass

Molar mass of lead = 121.76 g/mol

Mass = 0.063 mol ×  121.76 g/mol

Mass =  7.67 g

3) Given data:

Mass of tungsten = 15.5 Kg (15.5 kg × 1000 g/ 1kg = 15500 g)

Number of atoms = ?

Solution:

Number of moles of tungsten:

Number of moles = mass/molar mass

Number of moles = 15500 g / 183.84 g/mol

Number of moles = 84.3 mol

1 mole contain 6.022 ×10²³ atoms

84.3 mol  × 6.022 ×10²³ atoms / 1mol

507.65 ×10²³ atoms

Answer:

H+ (aq)  +    ClO- (aq)  --->   HClO(aq)  

Explanation:

The net ionic reaction equation is a chemical equation that explicitly shows only the particular ions that undergo a chemical change in the course of a given reaction.

In this particular reaction, the molecular reaction equation is shown as follows;

HNO3(aq) + NaOCl(aq) -----------> NaNO3(aq) + HOCl(aq)

Ionically;

H+ (aq)  +    ClO- (aq)  --->   HClO(aq)

Answer:

To obtain one mole of copper atoms (6.02 x 1023 atoms), ... mol Ag? (b) How many atoms of Ag are in 0.0342 mol Ag? 7 ... contain one S atom and two O atoms; calculate its molar mass.

Answer:

66.5753 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A (⁶⁵X):

Mass of A = 65.0457 amu

Abundance of A = 20.53%

Isotope B (⁶⁷X):

Mass of B = 66.9704 amu

Abundance of B = 79.47%

Atomic mass of X =?

The atomic mass of X can be obtained as follow:

Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100]

= [(65.0457 × 20.53)/100] + [(66.9704 × 79.47)/100]

= 13.3539 + 53.2214

= 66.5753 amu

Therefore, the atomic mass of X is 66.5753 amu.

Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu,  79.47%).

The average atomic mass (atomic mass) of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance.

Element X has 2 isotopes:

We can calculate the average atomic mass of X using the following expression.

mX = m⁶⁵X × ab⁶⁵X + m⁶⁷X × ab⁶⁷X

mX = 65.0457 amu × 0.2053 + 66.9704 amu × 0.7947

mX = 66.58 amu

Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu,  79.47%).

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Answer:

Use less heat in your house.

Explanation:

You have blankets in your house, huddle up for a good movie together.

Answer:

Simple ways to reduce heat loss include

Heat loss through windows can be reduced by using double glazing

Heat loss through walls can be reduced using cavity wall insulation

Heat loss through the roof can be reduced by laying loft insulation

Explanation:

Answer:

44Kj

Explanation:

These are the equations for the reaction described in the question,

Vaporization which can be defined as transition of substance from liquid phase to vapor

H2(g)+ 1/2 O2(g) ------>H2O(g). Δ H

-241.8kj -------eqn(1)

H2(g)+ 1/2 O2(g) ------>H2O(l).

Δ H =285.8kj ---------eqn(2)

But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as

H2O(l) ------>>H2O(g)---------------eqn(3)

But the equation from eqn(2) the eqn does go with vaporization so we can re- write as

H2O ------> H2(g)+ 1/2 O2(g)

Δ H= 285.8kj ---------------eqn(4)

To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)

Δ H=285.8kj +(-241.8kj)= 44kj

Answer:

pH = 4.349

Explanation:

When HI is added to sodium acetate, CH3COONa, acetic acid is produced as follows:

CH3COONa + HI → CH3COOH + NaI

That means the moles of HI added are the moles of acetic acid produced and the moles of sodium acetate consumed.

Moles of HI:

0.0605L * (0.223mol/L) = 0.01349mol

To find pH of the buffer (Mixture of weak acid, acetic acid, and conjugate base, sodium acetate) we need to solve H-H euation:

pH = pKa + log [CH3COONa] / [CH3COOH]

Where pKa is -log of Ka of the acid: -log1.8x10⁻⁵ = 4.745

And [] could be taken as moles of each specie

Moles CH3COONa:

Inital moles: 0.086L * (0.385mol/L) = 0.03311

Final moles: 0.03311mol - 0.01349mol = 0.01962mol CH3COONa

Moles CH3COOH:

Inital moles: 0.086L * (0.410mol/L) = 0.03256

Final moles: 0.03256mol + 0.01349mol = 0.04875mol CH3COOH

pH = 4.745+ log [0.01962mol CH3COONa] / [0.04875mol CH3COOH]

pH = 4.3497

Rigth answer is:

Answer:

it's mass

Explanation:

just trust me it's just mass

Answer:

Batteries hold chemical energy

Explanation:

The battery acid in a battery leads to chemical energy.

Answer:

For example, when we bake a cake, it's a result of a mixture of eggs, flour, sugar, and other ingredients.  Any time two or more items are combined, a mixture is formed. Sometimes, the different parts of a mixture can be separated into individual entities. Other times, they're married for as long as they exist.

Explanation:

The phases of nitrogen in order of increasing density is solid, liquid, and gas.

In conclusion, the correct option is D.

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Answer:

See explanation below (Brainlist please)

Explanation:

First of all, we need to understand what is an acidic hydrogen.

An acidic hydrogen, is the atom of hydrogen which is more propense to undergo an acid base reaction, and form a stable ion or molecule in the process.

In other words, is the hydrogen that is more vulnerable to get substracted in an acid base reaction to form another compound.

Knowing this information, gives us an idea of how a molecule can be formed and which kind of compound is formed.

Now, in this question, we have 5 molecules. Each of them is either a ketone or aldehyde, so this mean that we have the carbonile group (C = O), which means that is easier to identify the acidic hydrogen. This is because the Carbonile group is an attractor group, so, it will attract the charges by inductive effect (in some cases by resonance), and the molecule is more stable.

This can be shown by drawing the enolate ion that is formed once the molecule undergo the acid base reaction. As it's an enolate form that we are looking for, then it means that the ketone or aldehyde is undergoing an electrofilic attack with a base. This base will substract the most acidic hydrogen to form a better and stable enolate. The acidic hydrogen and the enolate form can be seen in the attached picture.

a) In the case of acetaldehyde, the most acidic will be the hydrogen of carbon 2, because the hydrogen from the carbonile, once it's substracted, the charge of the carbon cannot be stabilized by resonance. Carbon 2 hydrogens, can do this job easily.

b) Propanal happens something similar to acetaldehyde, the terminal hydrogen cannot be substracted, and carbon 3, once the hydrogen is gone, the negative charge cannot be stabilized by resonance, so hydrogens of carbon 2 can do this.

c) in the case of acetone, is easier to look because we only have the C = O between two methyl group, so you can use either carbon 1 or 3 to do the job.

d) 4 heptanone the most acidic hydrogen would be carbon 3 or 5, because they are closer to the C=O and the ion can be stabilized by resonance.

e) Finally in ciclopentanone, the most acidic hydrogen would be carbon 2 or 5.

See picture for a better understanding.

Hope it helps.

Answer:

the answer is B:) have a good day

Answer:

nitrogen

Explanation:

The atmosphere contains many gases, most in small amounts, including some pollutants and greenhouse gases. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere. Why do I care?

nitrogen is the most abundant gas in the atmosphere

Answer:

Option C. 24 days / 4 grams

Explanation:

From the question given above, the following data were obtained:

Days Elapsed >>>> Mass Remaining

0 >>>>>>>>>>>>>>> 16

12 >>>>>>>>>>>>>>> 11

24 >>>>>>>>>>>>>>> 8

36 >>>>>>>>>>>>>>> 6

A. Determination of the half-life of Thorium-234.

To determine the half-life, it is important to know the definition of half life.

Half-life is defined as the time taken for a substance to reduce to half its original mass.

From the table given above, we can see that the original mass of the isotope is 16 g (i.e at 0 day). By day 24, the mass of the isotope is 8 g (i.e half the original mass). Thus, the half-life of the isotope is 24 days.

B. Determination of the mass of the isotope remaining after 2 half lives.

Original amount (N₀) = 16 g

Number of half-lives (n) = 2

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2² × 16

N = 1/4 × 16

N = 4 g

Thus, 4 g of the isotope is remaining after 2 half lives.

Summay:

Half-life = 24 days

Amount remaining after 2 half-lives = 4 g

Option C gives the correct answer to the question.

Answer:

11

Explanation:

Moles of KOH = [tex]10^{-2}[/tex]

Volume of water = 10 liters

Concentration of KOH is given by

[tex][KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}[/tex]

[tex][KOH][/tex] is strong base so we have the following relation

[tex][KOH]=[OH^{-}]=10^{-3}\ \text{M}[/tex]

[tex]pOH=-\log [OH^{-}]=-\log10^{-3}[/tex]

[tex]\Rightarrow pH=14-3=11[/tex]

So, pH of the solution is 11

Answer:

13896g

Explanation:

volume = 4.50×8.00×20.00 = 720 cm³

mass = density × volume

mass= 19.3 × 720 = 13896g

Answer:

B

Explanation:

Answer:

Extreme heat

Explanation:

Because when matter is heated up The molecules move faster.

Answer:

I think it's extreme heat

Answer: 5.77 * 10¹⁴s⁻¹

Explanation:

Speed = Frequency * Wavelength

Frequency = Speed/ Wavelength

Speed of light = 3 * 10⁸ m/s

Frequency =  (3 * 10⁸ m/s) / (5.20 x 10⁻⁷m)

= 5.77 * 10¹⁴hz

= 5.77 * 10¹⁴s⁻¹

Answer:

See answer below

Explanation:

In this case, I will put the original photo of this exercise, because we are missing one data. The first picture is the original exercise.

Now, according to this, we need to make a serial dilution of CO(NO₃)₂. We don't know the volume of this solution, but we do know the total volume of the preparing solution (In the picture states that the total volume will be 10 mL).

So, we know the final volume of the solutions to be prepared, so, le'ts use the expression that will help us to solve this:

C₁V₁ = C₂V₂

Where:

C₁: Concentration of the given solution (stock)

V₁: volume required to prepare the dilluted solution

C₂; Concentration of the dilluted solution

V₂: Total volume of the dilluted solution.

Now that we know the expression to use and the meaning of each value, let's prepare the solutions:

To prepare 10 mL of 0.1 M using a 0.25 M, we will replace these values in the above expression; from there, we will solve for V₁, that value will tell us the required volume to prepare solution 2, and then, by difference we can calculate the volume of water:

Volume of water (Vw) =V₂ - V₁  

Now replacing the values:

0.25V₁ = 0.1 * 10

V₁ = 1/0.25 = 4 mL

This means that we need 4 mL of the stock to prepare the 0.1 M of dilluted solution, therefore, the volume of water required is:

Vw = 10 - 4

Using these same steps for the other two solutions we will get V1 and V2 for both of them. In this case, I will go straight to the procedure without further explanation because it's the same of this one.

For solution 2:

0.1V₁ = 0.05 * 10

V₁ = 0.5/0.1

Vw = 10 - 5

Finally for solution 3:

V₁ = 0.01 * 10 / 0.05

Vw = 10 - 2 mL

Hope this helps

Answer:

The transfer was essential to understand the mutation and the possibility of new, more resistant strains in microorganisms.

Explanation:

the transfer of microorganisms is based on the transfer of genetic data through conductive pathways that penetrate the membranes, called pili or genetic bridges.

These mutated genes with higher resistance are transmitted and resistance is generated in entire populations and even species.

Answer:

[tex]M_{C_9H_{13}NO_3}=183.23g/mol[/tex]

Explanation:

Hello!

In this case, since the molar mass of a chemical compound is computed by averaging the atomic mass of each element in the molecule and the amount of atoms; which in this case there are 9 carbon atoms, 13 hydrogen atoms, 1 nitrogen atom and 3 oxygen atoms; thus, we compute the average as shown below:

[tex]M_{C_9H_{13}NO_3}=m_C*9+m_H*13+m_N+m_O*3[/tex]

Now, we plug in the atomic masses to obtain:

[tex]M_{C_9H_{13}NO_3}=12.01*9+1.01*13+14.01+16.00*3\\\\M_{C_9H_{13}NO_3}=183.23g/mol[/tex]

Best regards!

Answer:

hello your question is incomplete attached below is the complete question

answer :

Fe2O3 = 159 g/mol

CO = 28.01 g/mol

Fe = 55.85 g/mol

CO2 = 44.01 g/mol

Explanation:

       Fe = 55.85 g/mol

       O = 16.0 g/mol

       hence the molar mass of Fe2O3 = 2(55.85) + 3(16) = 159 g/mol

        C = 12.01 g/mol

        O = 16.0 g/mol

        hence the molar mass of CO = 28.01 g/mol

        Fe = 55.85 g/mol

        C = 12.01 g/mol

        O = 16.0 g/mol

        hence the molar mass of CO2 = 12.01 + 2(16) = 44.01 g/mol

Answer:

There ya go ;)

Explanation:

Answer: (2) releases 2260 J/g of heat energy

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.

Latent heat of condensation is energy released when 1 mole of  vapor condenses to form liquid droplets.

The temperature does not change during this process, so heat released goes into changing the state of the substance, thus it is called latent which means hidden. The energy released in this process is same in magnitude as latent heat of vaporization. The heat of condensation of water vapour is about 2,260 J/g.

Phase transition refers to the changes in the states of matter between gas, liquids, and solids.

The correct answer is:

Option 2. releases 2260 J/g of heat energy

The process can be explained as:

1. Condensation is the process of conversion of water vapor into the liquid state.

2. Latent heat of vaporization is defined as the amount of heat required for 1 mole of liquid to convert into a gaseous phase at atmospheric pressure.

3. The change in the temperature does not occur during the condensation, and the heat required for the phase transition is latent heat. The heat of condensation of water vapor is 2,260 J/g.

Thus, the correct answer is Option 2.

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