If the white car experiences a change in momentum equal to 105,000 kg*m/s and is in contact with the red car for 5 seconds before coming to rest, how much force, in Newtons, does the white car experience during the collision?

Answer:

a) 0.1

b) density = mass/volume

                 = 0.5 /0.1

                 = 5 kg/[tex]m^{3}[/tex]

Answer:

Explanation:

The mass of an object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{18}{2} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

Explanation:

The average speed can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex]v = \frac{100}{10} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

It would go out the bottom hole faster.

Explanation:

It goes down the bottom hole faster because the water would get poured out the bottom before they even flipped the water bottle.

Answer:

Option (a) is correct.

Explanation:

Let the magnitude of the positive charge = [tex]q_1[/tex] and the magnitude of the negative charge = [tex]q_2[/tex]

Earlier, the distance between both the charge, d = 1m

By using Coulomb's law, the magnitude of the force between two charge

[tex]F=k\frac {q_1 q_2}{d^2}[/tex], where k is a constant.

So, the magnitude of the force in the initial configuration,

[tex]F_i = k\frac {q_1 q_2}{1^2}= k q_1q_2\cdots(i)[/tex]

The nature of the force is attractive, as both the charges are opposite in nature.

On replacing the positive charge from 1m left to 1 m right side of the negative charge, the distance between the charges remains the same, i.e d=1m.

Moreover, the magnitude, and nature of each charge, [tex]q_1[/tex] as well as [tex]q_2[/tex], are remain the same.

So, the magnitude of the force in the final configuration,

[tex]F_f = k\frac {q_1 q_2}{1^2}= k q_1q_2[/tex]

From equation (i), [tex]F_f=F_i[/tex]

The nature of the force is attractive, as both the charges are opposite in nature.

So, the electrostatic force remains attractive, and the magnitude does not change.

Hence, option (a) is correct.

When the electrostatic force lies between the charges so here the force should remain attractive, also the magnitude should remain the same.

Here we assume the magnitude of the positive charge should be q1 and the magnitude of the negative charge should be q2

Also, the distance between the charge should be d = 1 m

So here we use the columb law

F = kq1q2/d2

here k should be constant

Here the nature of the force should be attractive since the both the charges should be opposite.

Hence, the first option is correct.

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Answer:

μk = 0.106

Explanation:

When the box is moving across the flat surface with a constant velocity, the force applied on it must be equal to the kinetic frictional force applied on the object:

F = μk*W = μk*mg

Where,

F = Force applied on box = 52 N

m = mass of box = 50 kg

g = 9.8 m/s²

μk = coefficient of kinetic friction between box and floor = ?

Therefore,

52 N  = μk(50 kg)(9.8 m/s²)

μk = (52 N)/(490 N)

μk = 0.106

The coefficient of kinetic friction between the box and the floor will be 0.106.

A force that acts among sliding parts is referred to as kinetic friction. A body moving on the surface is subjected to a force that opposes its progressive motion

The size of the force will be determined by the kinetic friction coefficient between the two materials.

The given data in the problem is;

μ is the coefficient of kinetic friction=?

m is the mass = 50 kg

g is the acceleration due to gravity= 9.81 m/s²

v is the speed =3.5 m/sec

Force(F)= 52 Newton

The formula for kinetic friction force is;

[tex]\rm F= \mu_k R \\\\ R=mg \\\\ F= \mu_k mg \\\\\ 52 = \mu_k \times 50 \times 9.81 \\\\ \mu_k = 0.106[/tex]

Hence,the coefficient of kinetic friction between the box and the floor will be 0.106.

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b=36•3

momentum=mass×velocity

The total momentum of the given system is equal to zero. Therefore, option (C) is correct.

The linear momentum can be described as the product of the mass times the velocity of that object. Conservation of momentum is a property of an object as the total amount of momentum stays the same.

According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂v₂

where u₁ and u₂ are initial speed while v₁ & v₂ is final speed and m₁ and m₂ is the mass of the collided objects.

The first ball, m = 8.52 g and v = 2.13 m/s

The momentum of the first ball = 18.15 g.m/s

The second ball is moving in the opposite direction w.r.t. first ball,

The second ball, m = 8.52 g and v = - 2.13 m/s

The momentum of the first ball = - 18.15 g.m/s

The total momentum  of the system = 18.15 + (-18.15) = 0

Therefore, the total momentum of the given system is zero.

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Answer:

B. helium, xenon, neon

Explanation:

Answer:

i think its 20m for b

Explanation:

Answer:

The correct option is;

c. 22.6

Explanation:

The given parameters are;

The hypotenuse of the vector = 32

The angle of the vector = 45°

Therefore, the vector component in the y-axis is given as follows;

[tex]v_y = v \times sin(\theta)[/tex]

Substituting the values from the question gives;

[tex]v_y = 32 \times sin(45^{\circ}) \approx 22.6[/tex]

The vector component in the y-axis, [tex]v_y[/tex], is approximately 22.6.

Answer:

Following are the solution to this question:

Explanation:

That light takes a very long time to hit the planet, and the object is far off the earth. The light of such an item near to the planet takes less time to enter it. The star is 2,5 million light-years from the Planet on the far side of the Andromeda Galaxy. But on the other hand, the moon is 15 crore miles from the earth, so sunlight is quickly reached on the ground as the other thing.  

That milky way away from the earth is 66,500 light-years far, that distance between Earth and Orion nebula is 1,344 light-years, with such a distance of 4,367 light-years. The earth is 5.2261 trillion km apart from Pluto.

Answer:

   Gravitational potential energy.

   Chemical energy.

   Nuclear energy.

   Elastic potential energy

   Electrical potential energy

    Hope this helps :)

Answer:

d

Explanation:

Answer:

F = 800 [N]

Explanation:

To be able to calculate this problem we must use the principle of momentum before and after the impact of the hammer.

We must summarize that after the impact the hammer does not move, therefore its speed is zero. In this way, we can propose the following equation.

ΣPbefore = ΣPafter

[tex](m_{1}*v_{1}) - F*t = (m_{1}*v_{2})[/tex]

where:

m₁ = mass of the hammer = 0.15 [m/s]

v₁ = velocity of the hammer = 8 [m/s]

F = force [N] (units of Newtons)

t = time = 0.0015 [s]

v₂ = velocity of the hammer after the impact = 0

[tex](0.15*8)-(F*0.0015) = (0.15*0)\\F*0.0015 = 0.15*8\\F = 1.2/(0.0015)\\F = 800 [N][/tex]

Note: The force is taken as negative since it is exerted by the nail on the hammer and this force is directed in the opposite direction to the movement of the hammer.

Answer: mass = 10 kg, acceleration = 3 m/s2.

Explanation: I hope that helped!!

Just divide the d/t to get answer: 10.99

Explanation:

Answer:

    m v ´- MV = (m + M) v ’

Explanation:

If the astronaut initially has a speed v the satellite has a speed V, we can define a system that is formed by the two bodies, therefore the forces during the collision are internal, so the momentum is conserved

initial instant. Before the crash

          p₀ = m v - MV

final instatne. After the crash, we have two cases

1) inelastic shock

          m_f = (m + M) v '

          p₀ = p_f

         m v ´- MV = (m + M) v ’

2) elastic collision with the astronaut's velocity, zero in this case the moment remains

        m v - MV = mv ’+ Mv’

also the kinetic energy is conserved

       mv'2 + M V2 = mv'2 + m v'2

with these two equations we can find the speed of the cars

Line D represents a stationary object.

When an object is stationary, the line on the graph is horizontal.

We know, that an object is stationary means the slope of its position-time graph is zero or its pt graph is a straight line parallel to the x-axis.

The nest, or the resting place, is a stationary object, and one cannot put one's foot in front of it. A string is then tied from the head assembly to another stationary object.

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Answer:

Velocity ratio & input work

Explanation:

If u input velocity u can work the ratio...;D ;D ;D xD

Answer:

K = 0.045 J

Explanation:

It is given that,

Mass of a ball, m = 10 g = 0.01 kg

Speed of the ball, v = 3 m/s

To find,

The energy of the ball.

Solution,

Due  to the motion of the ball, it will have kinetic energy. It can be given by the formula as follows :

[tex]K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.01\times 3^2\\\\K=0.045\ J[/tex]

So, the ball will have a kinetic energy of 0.045 J.

Answer:

resultant force=16N→(TOWARDS THE DIRECTION OF 8N)

Explanation:

resultant force=8N+13N-5N

                        =16N→(TOWARDS THE DIRECTION OF 8N)

Answer:

67 meters (distance) +67 meters (displacement)

Explanation:

21 - (-46) meters

= 21 + 46 meters

= 67 meters

Hope this helped!

Answer:

67m

67m

both dist and displacement are the same oz it is on the same line

Answer:

I don't understand what is a power cane??

Answer/Explanation:

The mechanical energy is 200 joules. Mechanical energy is determined by adding the total kinetic energy by the total potential energy.

M = kp

100 + 100 = 200

Answer:

See the answers below.

Explanation:

to solve this problem we must make a free body diagram, with the forces acting on the metal rod.

i)

The center of gravity of the rod is concentrated in half the distance, that is, from the end of the bar to the center there is 40 [cm]. This can be seen in the attached free body diagram.

We have only two equilibrium equations, a summation of forces on the Y-axis equal to zero, and a summation of moments on any point equal to zero.

For the summation of forces we will take the forces upwards as positive and the negative forces downwards.

ΣF = 0

[tex]-15+T-W=0\\T-W=15[/tex]

Now we perform a sum of moments equal to zero around the point of attachment of the string with the metal bar. Let's take as a positive the moment of the force that rotates the metal bar counterclockwise.

ii) In the free body diagram we can see that the force acts at 18 [cm] of the string.

ΣM = 0

[tex](15*9) - (18*W) = 0\\135 = 18*W\\W = 7.5 [N][/tex]

42000 kilometers

Explanation:

distance is velocity × time

28000 ×1.5

42000

remember to match units

thats why i wrote 1.5 hours instead of 90minutes

Answer:

(a) 0.081 A (b) 1358.02 ohms

Explanation:

Voltage, V = 110 volt

Power of a LED bulb, P = 9 Watt

(a) Let the current is I. The formula for ower in terms of voltage and power is given by :

P = VI

[tex]I=\dfrac{P}{V}\\\\I=\dfrac{9}{110}\\\\=0.081\ A[/tex]

(b) Let R is the resistance of the bulb. Using Ohm's law as follows :

V = IR

[tex]R=\dfrac{V}{I}\\\\R=\dfrac{110}{0.081}\\\\=1358.02\ \Omega[/tex]

Hence, this is the required solution.

(a) The current in the bulb is 82mA

(b) The resistance of the bulb is 1340 Ω

Given information:

Supply voltage, V = 110V

The power rating of the bulb, P = 9 W

(a) Current in the bulb:

The electrical power is given by:

P = VI

where V is the voltage, and I is the current

So, I = P/V

I = 9W / 110V = 0.082A

I = 82 mA

(b) Resistance of the bulb:

According to the Ohm's Law:

The relation between voltage (V), current (I), and resistance (R) is given by:

V = IR

110 = 0.082R

R = 1340 Ω

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Question:

A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:

A. sinks slightly  

B. rises slightly  

C. floats at the same height  

D. bobs up and down about its old position

Answer:

The correct answer is C)  floats at the same height  

Explanation:

The liquid is incompressible because its density very high and leaves no room for further compaction whether or not there is atmospheric pressure. So when you put a cork on the liquid, pressure or no pressure, there is no displacement hence it floats on the same height regardless of the absence of air.

Cheers!