If the object instance is created in a user program, then the object instance can access both the public and private members of the class using DOT notation (such as Rectangle r; r.area=10). True or False

Answers

Answer 1

Answer:

False

Explanation:

The private member of a class is not accessible by using the Dot notation ,however the private member are those which are not accessible inside the class they are accessible outside the class  .The public member are accessible inside the class so they are accessible by using the dot operator .

Following are the example is given below in C++ Language

#include<iostream>   // header file

using namespace std;  

class Rectangle

{    

   private:  

       double r; // private member  

   public:      

       double  area()  

       {     return 3.14*r*r;  

       }        

};  

int main()  

{    

  Rectangle r1;// creating the object  

   r1.r = 3.5;  

 double t= r1.area(); // calling

cout<<" Area is:"<<t;  

   return 0;  

}  

Output:

compile time error is generated

The correct program to access the private member of class is given below

#include<iostream>   // header file

using namespace std;  

class Rectangle

{    

   private:  

       double r; // private member  

   public:      

       double  area()  

       {    

r1=r;

double t2=3.14*r2*r2;

return(t2); // return the value  

       }        

};  

int main()  

{    

  Rectangle r1;// creating the object  

   r1.r = 1.5;  

 double t= r1.area(); // calling

cout<<" Area is:"<<t;  

   return 0;  

}  

Therefore the given statement is False


Related Questions

What would be suggested way to share and sustain knowledge with members in a team ?
A) Sharing of best practices and lessons learnt through emails
B) Sharing knowledge through knowledge sharing sessions
C) Sharing knowledge through informal conversations, for example, during lunch breaks.
D) Sharing best practices, lessons learnt and other topics in a central place where team can collaborate

Answers

Answer: D) Sharing best practices, lessons learned and other topics in a central place where the team can collaborate

Explanation: Knowledge sharing within a team is usually an important aspect of building a strong and efficient team. Acquiring knowledge usually comes from the experience gathered from previous projects, learning, or tips learned from various sources. Therefore, sharing knowledge is always a good way to ensure that what is gained is sustained by letting others know. Sharing and sustaining knowledge is most effective when transmitted or aired to a group of people usually a team gathered in an interactive setting which allows members to freely share experience and get feedback, views, or thoughts from other collaborators.

Distinguish among packet filtering firewalls, stateful inspection firewalls, and proxy firewalls. A thorough answer will require at least a paragraph for each type of firewall.
Acme Corporation wants to be sure employees surfing the web aren't victimized through drive-by downloads. Which type of firewall should Acme use? Explain why your answer is correct.

Answers

Answer:

packet filtering

Explanation:

We can use a packet filtering firewall, for something like this, reasons because when visiting a site these types of firewalls should block all incoming traffic and analyze each packet, before sending it to the user. So if the packet is coming from a malicious origin, we can then drop that packet and be on our day ;D

A customer contacts the help disk stating a laptop does not remain charged for more than 30 minutes and will not charge more than 15%. Which of the following components are the MOST likely causes the issue? (Select three.) A. LCD power inverter B. AC adapter C. Battery D. Processor E. VGA card F. Motherboard G. Backlit keyboard H. Wireless antenna

Answers

Answer:

A. LCD power inverter

B. AC adapter

C. Battery

k- Add the code to define a variable of type 'double', with the name 'cuboidVolume'. Calculate the volume of the cuboid and set this variable value.

Answers

Answer:

Here is the JAVA program to calculate volume of cuboid:

import java.util.Scanner; // Scanner class is used to take input from user

public class CuboidVol { // class to calculate volume of cuboid

public static void main(String[] args) { // start of main() function body

Scanner input= new Scanner(System.in); //create Scanner class object

// prompts user to enter length of cuboid

System.out.println("Enter the cuboid length:");

double length=input.nextDouble(); //reads the input length value from user

// prompts user to enter width of cuboid

System.out.println("Enter the cuboid width:");

double width=input.nextDouble(); //reads the input width from user

// prompts user to enter height of cuboid

System.out.println("Enter the cuboid height:");

double height=input.nextDouble(); //reads the input height from user

/* the following formula is to calculate volume of a cuboid by multiplying its length width and height and a double type variable cuboidVolume is defined to store the value of the resultant volume to it */

double  cuboidVolume= length*width*height; //calculates cuboid volume

//displays volume of cuboid and result is displayed up to 2 decimal places

System.out.printf("Volume of the cuboid (length " + length + "/ height " + height + "/ width" +width +" is: " + "%.2f",cuboidVolume);   } }

Explanation:

The formula for the volume of a cuboid is as following:

Volume = Length × Width ×  Height

So in order to calculate the volume of cuboid three variable are required for length, width and height and one more variable cuboidVolume to hold the resultant volume of the cuboid.

The program is well explained in the comments added to each statement of the program. The program prompts the user to enter the value of height width and length of cuboid and the nextDouble() method is used to take the double type input values of height length and width. Then the program declares a double type variable cuboidVolume to hold the result of the volume of cuboid. Then the last printf statement is used to display the volume of cuboid in the format format "Volume of the cuboid (length  / height  / width ) is" and the result is displayed up to 2 decimal places.

The screenshot of the program along with its output is attached.

In e-mail, SSL/TLS provides ________. link encryption end-to-end encryption both link encryption and end-to-end encryption neither link encryption nor end-to-end encryption

Answers

Answer:

link encryption

Explanation:

In e-mail, SSL/TLS provides link encryption.

The SSL is an acronym for Secured Socket Layer and it is one of the secured way of authenticating and encrypting data between a computer and the mail server.

In the case of a TLS, it is an acronym for Transport Layer Security and it basically is used for providing authentication and encryption of data between two communicating systems on a network.

This ultimately implies that, SSL/TLS are standard network protocols that provides data integrity and privacy to users when communicating over the internet or networking devices as they're made to encrypt user credentials and data from unauthorized access. The SSL/TLS are an application layer protocol used for the encryption of mails sent over the internet, in order to protect user information such as username and password.

How many times will the while loop that follows be executed? var months = 5; var i = 1; while (i < months) { futureValue = futureValue * (1 + monthlyInterestRate); i = i+1; }
a. 5
b. 4
c. 6
d. 0

Answers

Answer:

I believe it is A

Explanation:

Write code to create a list of numbers from 0 to 67 and assign that list to the variable nums. Do not hard code the list. Save & RunLoad HistoryShow CodeLens

Answers

Answer:

The program written in Python is as follows

nums = []

for i in range(0,68):

-->nums.append(i)

print(nums)

Explanation:

Please note that --> is used to denote indentation

The first line creates an empty list

nums = []

This line creates an iteration from 0 to 67, using iterating variable i

for i in range(0,68):

This line saves the current value of variable i into the empty list

nums.append(i)

At this point, the list has been completely filled with 0 to 67

This line prints the list

print(nums)

Write a sentinel-controlled while loop that accumulates a set of integer test scores input by the user until negative 99 is entered.

Answers

Answer:

Here is the sentinel-controlled while loop:

#include <iostream> //to use input output functions

using namespace std; // to identify objects like cin cout

int main(){ // start of main() function body

int test_score; // declare an integer variable for test scores

//prompts user to enter test scores and type-99 to stop entering scores

cout << "Enter the test scores (enter -99 to stop): ";

cin >> test_score; // reads test scores from user

while (test_score != -99){ // while loop keeps executing until user enters -99

cin >> test_score; } } // keeps taking and reading test scores from user

Explanation:

while loop in the above chunk of code keeps taking input scores from user until -99 is entered. Sentinel-controlled loops keep repeating until a sentinel value is entered. This sentinel value indicates the end of the data entry such as here the sentinel value is -99 which stops the while loop from iterating and taking the test score input from user.

The complete question is that the code should then report how many scores were  entered and the average of these scores. Do not count the end sentinel -99 as a score.

So the program that takes input scores and computes the number of scores entered and average of these scores is given below.

#include <iostream>  // to use input output functions

using namespace std;  // to identify objects like cin cout

int main(){  //start of main function body

double sum = 0.0;  // declares sum variable to hold the sum of test scores

int test_score,count =0;  

/* declares test_scores variable to hold the test scores entered by user and count variable to count how many test scores input by user */

cout << "Enter the test scores (or -99 to stop: ";

//prompts user to enter test scores and type-99 to stop entering scores

cin >> test_score;  // reads test scores from user

while (test_score != -99){  // while loop keeps executing until user enters -99

count++;  /* increments count variable each time a test cores is input by user to count the number of times user entered test scores */

sum = sum + test_score;  // adds the test scores

cin >> test_score;}  // reads test scores from user

if (count == 0)  // if user enters no test score displays the following message

cout << "No score entered by the user" << endl;

else  //if user enters test scores

//displays the numbers of times test scores are entered by user

cout<<"The number of test scores entered: "<<count;

/* displays average of test scores by dividing the sum of input test scores with the total number of input test scores */

cout << "\n The average of " << count << " test scores: " <<sum / count << endl;}

The program along with its output is attached.

g Write a C program that prompts the user for a string of, up to 50, characters and numbers. It can accept white spaces and tabs and end with a return. The program should keep track of the number of different vowels (a,e, i, o, u) and the number of digits (0, 1, 2, 3, 4, 5, 6, 7, 8,9). The program should output the number of occurrences of each vowel and the number of occurrences of all digits.

Answers

Answer:

Following are the code to this question:

#include <stdio.h> //defining header file

#include <string.h>//defining header file

int main()//defining main method

{

char name[50]; //defining character variable

int A=0,E=0,I=0,O=0,U=0,value=0,i,l; //defining integer variables

printf("Enter string value: ");//print message

gets(name);//input value by gets method

l=strlen(name);//defining l variable to store string length

for(i=0; i<50; i++) //defining loop to count vowels value

{

if(name[i] == 'A' || name[i] == 'a') //defining if condition count A value A++;//increment value by 1

else if(name[i] == 'E' || name[i] == 'e')//defining else if condition count E value

E++;//increment value by 1

else if(name[i] == 'I' || name[i] == 'i') //defining else if condition count I value

I++;//increment value by 1

else if(name[i] == 'O' || name[i]== 'o') //defining else if condition count O value

O++;//increment value by 1

else if(name[i] == 'U' || name[i] == 'u')//defining else if condition count U value

U++;//increment value by 1

else if(name[i]>= '0' && name[i] <= '9')//defining else if condition count digits value

value++;//increment value by 1 }

printf("A: %d\n",A);//print A value

printf("E: %d\n",E); //print E value

printf("I: %d\n",I);//print I value

printf("O: %d\n",O);//print O value

printf("U: %d\n",U);//print U value

printf("value: %d",value);//print digits value

return 0;

}

Output:

please find the attachment.

Explanation:

In the above code, a char array "name" and integer variables "A, E, I, O, U, i, value and l" declared, in which name array store 50 character value, which uses the gets function to take string value.after input value strlen method is used to store the length of the input string in l variable.In the next step, for loop is declared that uses multiple conditional statements to counts vowels and the values of the digits,if it is more then one it increments its value and at the last print method is used to print its count's value.

4. Discuss the advantages and disadvantages of using the same system call interface for both files and devices. Why do you think operating system designers would use the same interface for both

Answers

Answer:

According to the principles of design, Repetition refers to the recurrence of elements of the design

One of the advantages of this is that it affords uniformity. Another is that it keeps the user of such a system familiar or with the interface of the operating system.

One major drawback of this principle especially as used in the question is that it creates a familiar route for hackers.

Another drawback is that creates what is called "repetition blindness". This normally occurs with perceptual identification tasks.

The  phenomenon may be  due to a failure in sensory analysis to process the same shape, figures or objects.

Cheers!

Your boss wants you to start making your own Ethernet cables to save the company money. What type of connectors will you need to order to make them?

Answers

Answer:

Bulk Ethernet Cable - Category 5e or CAT5e

Bulk RJ45 Crimpable Connectors for CAT-5e

Explanation:

#Write a function called random_marks. random_marks should #take three parameters, all integers. It should return a #string. # #The first parameter represents how many apostrophes should #be in the string. The second parameter represents how many #quotation marks should be in the string. The third #parameter represents how many apostrophe-quotation mark #pairs should be in the string. # #For example, random_marks(3, 2, 3) would return this #string: #'''""'"'"'" # #Note that there are three apostrophes, then two quotation #marks, then three '" pairs. #Add your function here!

Answers

Answer:

def random_marks(apostrophe, quotation, apostrophe_quotation):

   return "'"*apostrophe + "\""*quotation + "'\""*apostrophe_quotation

   

print(random_marks(3, 2, 3))

Explanation:

Create a function called random_marks that takes apostrophe, quotation, and apostrophe_quotation as parameters. Inside the function, return apostrophe sign times apostrophe plus quotation mark times quotation plus apostrophe sign quotation mark times apostrophe_quotation.

Note that plus sign (+) is used to concatenate strings. Also, if you multiply a string with a number, you get that number of strings ("#"*3 gives ###).

Then, call the function with given parameters and print

The main path of the Internet along which data travels the fastest is known as the Internet ________. Group of answer choices

Answers

Answer:

Internet backbone

Explanation:

The internet backbone is made up of multiple networks from multiple users. It is the central data route between interconnected computer networks and core routers of the Internet on the large scale. This backbone does not have a unique central control or policies, and is hosted by big government, research and academic institutes, commercial organisations etc. Although it is governed by the principle of settlement-free peering, in which providers privately negotiate interconnection agreements, moves have been made to ensure that no particular internet backbone provider grows too large as to dominate the backbone market.

A security analyst is performing a BIA. The analyst notes that in a disaster, failover systems must be up and running within 30 minutes. The failover systems must use back up data that is no older than one hour. Which of the following should the analyst include in the business continuity plan?
A. A maximum MTTR of 30 minutes
B. A maximum MTBF of 30 minutes
C. A maximum RTO of 60 minutes
D. An SLA guarantee of 60 minutes

Answers

Answer:

D.  A maximum RPO of 60 minutes

Explanation:

Note that an option is not included in this list of options.

The complete list of options is:

A. A maximum MTTR of 30 minutes

B. A maximum MTBF of 30 minutes

C. A maximum RTO of 60 minutes

D.  A maximum RPO of 60 minutes

E. An SLA guarantee of 60 minutes

The Recovery Point Objective tells how old a backup file must be before it can be  recovered by a system after failure.

Since the data in the failover systems described in this question must be backup and recovered after the failure, it will be important to include the Recovery Point Objective (RPO) in the Business Continuity Plan.

Since the failover systems must use back up data that is no older than one hour, the backup of the system data must be done at intervals of 60 minutes or less. Meaning that the maximum RPO is 60 minutes.

Note that RPO is more critical than RTO in data backup

The advantage of returning a structure type from a function when compared to returning a fundamental type is that

Answers

Answer:

The function can return multiple values and the function can return an object

Explanation:

The advantage of returning a structure type from a function when compared to returning a fundamental type is that the function can return multiple values and also the function can return an object

A function in a structure can be passed to a function from any other function or from the main function itself and the definition of a structure can be seen in the function where it is found

When preparing a photo for a magazine, a graphic designer would most likely need to use a program such as Microsoft Excel to keep track of magazine sales. Microsoft Word to write an article about the photo. Adobe Photoshop to manipulate the photo. Autodesk Maya to create 3-D images that match the photo.

Answers

Answer:

Adobe Photoshop To Manipulate The Photo.

Explanation:

BLACKPINKS new album is amazing OMG I LOVE Lovesick Girls!!!

What are the pros and cons of using a linked implementation of a sparse matrix, as opposed to an array-based implementation?

Answers

Answer:

Linked lists and arrays are both linear data structures but while an array is a collection of items that can be accessed randomly, a linked list can be accessed sequentially.

A sparse matrix contains very few non-zero elements. For example;

_                        _

|  0   0   3  0  6    |

|   0   5   0  0  4   |

|   2   0   0  0  0   |

|_ 0   0   0  0  0 _|

In the implementation of a sparse matrix, the following are some of the pros and cons of using a linked list over an array;

PROS

i.  Linked lists are dynamic in nature and are readily flexible - they can expand and contract without having to allocate and/or de-allocated memory compared to an array where an initial size might need to be set and controlled almost manually. This makes it easy to store and remove elements from the sparse matrix.

ii. No memory wastage. Since the size of a linked list can grow or shrink at run time, there's no memory wastage as it adjusts depending on the number of items it wants to store. This is in contrast with arrays where you might have unallocated slots. Also, because the zeros of the sparse matrix need not be stored when using linked lists, memory is greatly conserved.

CONS

i. One of the biggest cons of linked lists is the difficulty in traversing items. With arrays, this is just of an order of 0(1) since the only requirement is the index of the item. With linked lists, traversal is sequential which means slow access time.

ii. Storage is another bottle neck when using linked lists in sparse matrix implementation. Each node item in a linked list contains other information that needs to be stored alongside the value such as the pointer to the next or previous item.

Your smartphone, digital camera, and printer are all part of a network in your workspace. What type of network is likely in use

Answers

Answer:

PAN

Explanation:

PAN, short form of Personal Area Network, is a type of computer network built for personal use typically within a building. This could be inside a small office or a bedroom in a residence. This type of network basically consists of one or more personal computers, digital camera, printer, Tv, scanner, telephones, peripheral devices, video games console, and other similar devices.

It is pretty much simple to set up and allow for great flexibility. In this network, a single modem can be set up to enable both wired and wireless connections for multiple devices within the building.

What is the difference between requirements and controls in the security process? Give examples of each.

Answers

Answer:

Security controls are those measures taken to prevent, identify, counteract, and reduce security risks to computer systems, whereas, Security Requirements are guidelines or frameworks that stipulates measures to ensure security control.

Explanation:

Security controls encompass all the proactive measures taken to prevent a breach of the computer system by attackers. Security requirements are those security principles that need to be attained by a system before it can be certified as safe to use.

Security controls are of three types namely, management, operational, and technical controls. Examples of technical controls are firewalls and user authentication systems. A statement like 'The system shall apply load balancing', is a security requirement with an emphasis on availability.

Define a function ComputeGasVolume that returns the volume of a gas given parameters pressure, temperature, and moles. Use the gas equation PV = nRT, where P is pressure in Pascals, V is volume in cubic meters, n is number of moles, R is the gas constant 8.3144621 ( J / (mol*K)), and T is temperature in Kelvin.Sample program:#include const double GAS_CONST = 8.3144621;int main(void) { double gasPressure = 0.0; double gasMoles = 0.0; double gasTemperature = 0.0; double gasVolume = 0.0; gasPressure = 100; gasMoles = 1 ; gasTemperature = 273; gasVolume = ComputeGasVolume(gasPressure, gasTemperature, gasMoles); printf("Gas volume: %lf m^3\n", gasVolume); return 0;}

Answers

Answer:

double ComputeGasVolume(double pressure, double temperature, double moles){

   double volume = moles*GAS_CONST*temperature/pressure;

    return volume;        

}

Explanation:

You may insert this function just before your main function.

Create a function called ComputeGasVolume that takes three parameters, pressure, temperature, and moles

Using the given formula, PV = nRT, calculate the volume (V = nRT/P), and return it.

12. Kelly would like to know the average bonus multiplier for the employees. In cell C11, create a formula using the AVERAGE function to find the average bonus multiplier (C7:C10).

Answers

Answer:

1. Divide each bonus by regular bonus apply this to all the data

2. In cell C11 write, "Average" press tab key on the keyboard and then select the range of the cells either by typing "C7:C10" or by selecting it through the mouse.

Explanation:

The average bonus multiplier can be found by dividing each bonus with the regular bonus applying this to all the data and then putting the average formula and applying it to the cells C7:C10.  

After dividing the bonus with regular bonus, in cell C11 write, "Average" press tab key on the keyboard and then select the range of the cells either by typing "C7:C10" or by selecting it through the mouse.

What are the differences between editing manually and editing digitally? What tools are used for each?

Answers

Answer:

Both manual and digital editing are concepts used in proofreading.

Manual editing is also called "hard proofreading" (or "hard proofing" for short). It is the process of proofreading, modifying or revising printed documents. In this type of proofreading, one would normally manually mark parts of the printed documents with editing materials such as ink, pen, marker e.t.c

Digital editing is also called "soft proofing". In contrast to manual editing, this type is done on digital documents. These documents include, but not limited to, DOC, txt, PDF, image, audio and video files.

Tools for editing manually are;

i. pen

ii. ink

iii. tipex

Tools for editing digitally are;

i. Photoshop application

ii. Text editors such as notepad++, Microsoft word

Proofreading has evolved in recent times as a result of advancements in technology. Now, manual proofreading has paved way for digital proofreading, which allows revising of PDF and  DOC files. The difference in both forms is as follows:

Manual Editing: In the process of revising or proofing printed documents, one would manually apply standard proofreading marks. Manual editing is also known as "Hard proofing", as the process requires proofreaders to mark the hard copies.

Digital Editing: In the process of revising or proofing digital documents i.e. PDF and DOC files, one would digitally apply the proofreading marks. Thus, corrections and edits are transferred electronically among authors, proofreaders. Digital editing is also known as "Soft proofing", as the process requires proofreaders to mark the soft copies i.e. without using any paper or pen.

There are a number of electronic tools and marks available for both techniques of

proofreading. Some tools used for manual proofreading include- deletion, capitalization, and  insertion, close-up, transpose.

Tools used in digital proofreading include- spell check, readability levels, trite expressions,  and comment, track changes.

Learn More: https://brainly.com/question/10002469

All of the following are examples of being computer literate, EXCEPT ________. knowing how to use the web efficiently knowing how to build and program computers knowing how to avoid hackers and viruses knowing how to maintain and troubleshoot your computer

Answers

Answer:knowing how to build and program computers.

Explanation:

ICMP
(a) is required to solve the NAT traversal problem
(b) is used in Traceroute
(c) has a new version for IPv6
(d) is used by Ping

Answers

Answer:

(b) is used in Traceroute

(d) is used by Ping

Explanation:

ICMP is the short form of Internet Control Message Protocol. It is a protocol used by networking devices such as routers to perform network diagnostics and management. Since it is a messaging protocol, it is used for sending network error messages and operations information. A typical message could be;

i. Requested service is not available

ii. Host could not be reached

ICMP does not use ports. Rather it uses types and codes. Some of the most common types are echo request and echo reply.

Traceroute - which is a diagnostic tool - uses some messages available in ICMP (such as Time Exceeded) to trace a network route.

Ping - which is an administrative tool for identifying whether a host is reachable or not - also uses ICMP. The ping sends ICMP echo request packets to the host and then waits for an ICMP echo reply from the host.

ICMP is not required to solve NAT traversal problem neither does it have a new version in IPV6.

24. Which of the following statements about Emergency Support Functions (ESFs) is correct?
O A. ESFs are not exclusively federal coordinating mechanism
O B. ESFs are only a state or local coordinating mechanism
O C. ESFs are exclusively a federal coordinating mechanism
O D. ESFs are exclusively a state coordinating mechanism

Answers

(ESFs) is correct: ESFs are not exclusively federal coordinating mechanism.

Write a program that create Employee class with fields id,name and sal and create Employee object and store data and display that data.

Answers

Answer:

Here is the C++ program for Employee class with fields id,name and sal.

#include <iostream>  // to use input output functions

#include <string>  //to manipulate and use strings

using namespace std;   // to access objects like cin cout

class Employee {  //class Employee

private:  

/* the following data members are declared as private which means they can only be accessed by the functions within Employee class */

  string name;  //name field

  int id; //id field

  double sal;   //salary field

public:    

  Employee();  // constructor that initializes an object when it is created

/* setName, setID and setSalary are the mutators which are the methods used to change data members. This means they set the values of a private fields i.e. name, id and sal */

  void setName(string n)  //mutator for name field

     { name = n; }        

  void setId(int i)  //mutator for id field

     { id = i; }        

  void setSalary(double d)  //mutator for sal field

     { sal = d; }  

/* getName, getID and getSalary are the accessors which are the methods used to read data members. This means they get or access the values of a private fields i.e. name, id and sal */

  string getName()  //accessor for name field

     { return name; }        

  int getId()  //accessor for id field

     { return id; }        

  double getSalary()  //accessor for sal field

     { return sal; }  };  

Employee::Employee() {  //default constructor where the fields are initialized

  name = "";  // name field initialized

  id = 0;  // id field initialized to 0

  sal = 0;   }   // sal field initialized to 0

void display(Employee);  

// prototype of the method display() to display the data of Employee

int main() {  //start of the main() function body

  Employee emp;  //creates an object emp of Employee class

/*set the name field to Abc Xyz which means set the value of Employee class name field to Abc Xyz  through setName() method and object emp */

  emp.setName("Abc Xyz");  

/*set the id field to 1234 which means set the value of Employee class id field to 1234  through setId() method and object emp */

  emp.setId(1234);

/*set the sal field to 1000 which means set the value of Employee class sal field to 1000  through setSalary() method and object emp */

  emp.setSalary(1000);    

  display(emp);  }   //calls display() method to display the Employee data

void display(Employee e) {  // this method displays the data in the Employee //class object passed as a parameter.

/*displays the name of the Employee . This name is read or accessed through accessor method getName() and object e of Employee class */

  cout << "Name: " << e.getName() << endl;  

/*displays the id of the Employee . This id is read or accessed by accessor method getId() and object e */

  cout << "ID: " << e.getId() << endl;

/*displays the salary of the Employee . This sal field is read or accessed by accessor method getSalary() and object e */

  cout << "Salary: " << e.getSalary() << endl;  }

Explanation:

The program is well explained in the comments mentioned with each statement of the program.

The program has a class Employee which has private data members id, name and sal, a simple default constructor Employee(), mutatator methods setName, setId and setSalary to set the fields, acccessor method getName, getId and getSalary to get the fields values.

A function display( ) is used to display the Employee data i.e. name id and salary of Employee.

main() has an object emp of Employee class in order to use data fields and access functions defined in Employee class.

The output of the program is:

Name: Abc Xyz                                                                                                      

ID: 1234                                                                                                                  

Salary: 1000

The program and its output are attached.

You are in a rectangular maze organized in the form of M N cells/locations. You are starting at the upper left corner (grid location: (1; 1)) and you want to go to the lower right corner (grid location: (M;N)). From any location, you can move either to the right or to the bottom, or go diagonal. I.e., from (i; j) you can move to (i; j + 1) or (i + 1; j) or to (i+1; j +1). Cost of moving right or down is 2, while the cost of moving diagonally is 3. The grid has several cells that contain diamonds of whose value lies between 1 and 10. I.e, if you land in such cells you earn an amount that is equal to the value of the diamond in the cell. Your objective is to go from the start corner to the destination corner. Your prot along a path is the total value of the diamonds you picked minus the sum of the all the costs incurred along the path. Your goal is to nd a path that maximizes the prot. Write a dynamic programming algorithm to address the problem. Your algorithm must take a 2-d array representing the maze as input and outputs the maximum possible prot. Your algorithm need not output the path that gives the maximum possible prot. First write the recurrence relation to capture the maximum prot, explain the correctness of the recurrence relation. Design an algorithm based on the recurrence relation. State and derive the time bound of the algorithm. Your algorithm should not use recursion

Answers

Answer:

Following are the description of the given points:

Explanation:

A) The Multiple greedy approaches could exist, which could be to reach for the closest emergency diamond, and yet clearly we are going to miss some very essential routes in that case. So, it can make every argument quickly, and seek to demonstrate a reference case for that.

B) An approach to the evolutionary algorithm and its users are going to just have states M x N. But each state (i, j) indicates the absolute difference between the amount of the selected diamond and the amounts of the costs incurred.

DP(i, j) = DimondVal(i, j) + max ((DP(i, j-1)-2), (DP(i-1,j-1)-3))

DP(i, j) is a description of the state.

DimondVal(i, j) is the diamond value at (i j), 0 if there is no diamond available.

This states must calculate the states of M N  and it involves continuous-time for each State to determine. Therefore the amount of time of such an algo is going to be O(MN).

Write down the information for your system’s active network connection (most likely either Ethernet or Wi-Fi).

Answers

Question:

1. Open a command prompt window, type ipconfig/ all and press Enter.

2. Write down the information for your system’s active network connection(most likely either Ethernet or Wi-Fi).

* Physical address in paired hexadecimal form.

* Physical address expressed in binary form.

Answer:

00000000 11111111 00000011 10111110 10001100 11011010

Explanation:

(i)First, open a command prompt window by using the shortcut: Windows key + X then select command prompt in the list.

(ii)Now type ipconfig/ all and press Enter. This will return a few information

(a) To get the Physical address in paired hexadecimal form, copy any of the Physical Addresses shown. E.g

00-FF-03-BE-8C-DA

This is the hexadecimal form of the physical address.

(b) Now let's convert the physical address into its binary form as follows;

To convert to binary from hexadecimal, we can use the following table;

Hex                 |         Decimal                |           Binary

0                      |          0                           |           0000

1                       |          1                            |           0001

2                      |          2                           |           0010

3                      |          3                           |           0011

4                      |          4                           |           0100

5                      |          5                           |           0101

6                      |          6                           |           0110

7                      |          7                           |           0111

8                      |          8                           |           1000

9                      |          9                           |           1001

A                     |          10                           |           1010

B                      |          11                           |           1011

C                      |          12                           |           1100

D                      |          13                           |           1101

E                      |          14                           |           1110

F                      |          15                           |           1111

Now, from the table;

0 = 0000

0 = 0000

F = 1111

F = 1111

0 = 0000

3 = 0011

B = 1011

E = 1110

8 = 1000

C = 1100

D = 1101

A = 1010

Put together, 00-FF-03-BE-8C-DA becomes;

00000000 11111111 00000011 10111110 10001100 11011010

PS: Please make sure there is a space between ipconfig/ and all

Modify the DemoSalesperson application so each Salesperson has a successive ID number from 111 through 120 and a sales value that ranges from $25,000 to $70,000, increasing by $5,000 for each successive Salesperson. Save the file as DemoSalesperson2.java.

Answers

Answer:

Here is the modified DemoSalesperson2

public class DemoSalesperson2{ // class DemoSalesperson2

public static void main(String[] args) { //start of main() function body

SalesPerson[] sp = new SalesPerson[10]; // creates an array of SalesPerson object named sp

int start_id =111; // assign 111 to starting id number

double start_sal=25000; //assign 25000 to starting salary means salary will start from amount 25000

 for (int i =0; i<sp.length; i++) { //loop iterates until the value of loop variable i remains less then length of the array object sp

  sp[i] =new SalesPerson(start_id+i,start_sal+5000*(i)); /*at each iteration  ID number from 111 through 120 and a sales value that ranges from $25,000 to $70,000, increasing by $5,000 for each successive is displayed using object array sp[] which calls the SalesPerson constructor to access id and sales */

 System.out.println(sp[i].getId()+"   "+sp[i].getAnnualSales() );  } } } /*uses object sp of class SalesPerson to access the methods getId which returns the id and getAnnualSales method which returns the annual sales, to display id and annual sales */

Explanation:

The question first requires a SalesPerson class with these requisites:

Class name: Salesperson.

Data fields for Salesperson: int ID number , double annual sales amount.

Methods: constructor SalesPerson() that requires values for both data fields, as well as get and set methods for each of the data fields.

So according to the complete question's requirement, I have implemented SalesPerson class:

public class SalesPerson {   // class name

//data members: integer type id variable and double type sales variable

   private int id;  

   private double sales;  

   public SalesPerson(int id_no, double annual_sales) {   //constructor that requires values for id and sales

       id = id_no;  

       sales = annual_sales;     }  

   public int getId() {   //accessor getId() method to get or access the value of id data field

       return id;     }  

   public void setId(int id_no) {   //mutator setId to set the value of id data field

       id = id_no;     }  

   public double getAnnualSales() {   //accessor getAnnualSales() method to get or access the value of sales data field

       return sales;     }  

   public void setAnnualSales(double annual_sales) { //mutator setAnnualSales to set the value of sales data field

       sales = annual_sales;     }  }

However you can use my DemoSalesperson2 application for your own SalesPerson class.

Now I will explain the working of for loop used in DemoSalesperson2

Iteration 1:

i=0

i<sp.length is true because length of sp[] is 10 so i<10

This means the body of for loop will execute.

The statement inside the body of for loop is :

 sp[i] =new SalesPerson(start_id+i,start_sal+5000*(i));

class SalesPerson constructor is used to access the data members of SalesPerson class

start_id = 111

start_sal=25000

start_id+i = 111 + 0 = 111

start_sal+5000*(i) = 25000 + 5000 (0) = 25000

The values 111 and 25000 are stored to sp[0] means at the first index of the sp array.

System.out.println(sp[i].getId()+"   "+sp[i].getAnnualSales() );  

This statement uses sp object to get access to the getId and getAnnualSales methods to print the id number and sales amount.

So the output at 1st iteration is:

111   25000.0

Iteration 1:

The value of i is incremented to 1 so now i = 1

i<sp.length is true because length of sp[] is 10 so i<10

This means the body of for loop will execute.

The statement inside the body of for loop is :

 sp[i] =new SalesPerson(start_id+i,start_sal+5000*(i));

class SalesPerson constructor is used to access the data members of SalesPerson class

start_id = 111

start_sal=25000

start_id+i = 111 + 1 = 112

start_sal+5000*(i) = 25000 + 5000 (1) = 25000 + 5000 = 30000

The values 111 and 25000 are stored to sp[1] means at the first index of the sp array.

System.out.println(sp[i].getId()+"   "+sp[i].getAnnualSales() );  

This statement uses sp object to get access to the getId and getAnnualSales methods to print the id number and sales amount.

So the output at 1st iteration is:

112   30000.0

The loop keeps iterating and the value of id is incremented by 1 and value of sales is increased by 5000 at every iteration.

This loop continues to execute until the value of i exceeds the length of sp array i.e. 10.

The values from iteration 1 to 8 following the above explanation are:

Iteration 1:

111    25000.0

Iteration 2:

112    30000.0

Iteration 3:

113    35000.0

Iteration 4:

114   40000.0  

Iteration 5:

115   45000.0  

Iteration 6:

116   50000.0                                                          

Iteration 7:

117   55000.0                                                                                                      

Iteration 8:                                                                                      

118   60000.0      

Iteration 9:                                                                                    

119   65000.0

Iteration 10:                                                                                    

120   70000.0

At iteration 11 the for loop body will not execute as value of i at 11th iteration is i = 10 and i<sp.length evaluates to false as i = sp.length because length of sp array is 10 and now the value of i is also 10. So the loop ends. Screenshot of the program and its output is attached.

I have tried looking for this answer everywhere, and I could not find the answer

I have a Windows 10 Laptop, with a 12GB RAM Card, okay? I also have my 1TB Disk Partitioned so that I have 3 Disks. 2 of them are my primary, both of those are 450GB apiece. The last one ([tex]Z:[/tex]) I named "RAM" and set that one to 100GB.

How do I turn the drive [tex]Z:[/tex] into strictly RAM?
I already did the Virtual Memory part of it, but I was wondering if I can make it strictly RAM so the system uses drive [tex]Z:[/tex] before using the RAM disk? If it is not possible, I'm sorry.

Answers

If my computer has 4 gigabytes of ram memory then I have 4e+9 bytes of memory.  I think-

Answer: That isn't a software problem, its a hardware problem. There is a difference between 12gb of ram versus 100 gb of HDD. Ram is temporary storage, you can not turn SSD or HDD storage into RAM. If you are a gamer, STEER AWAY FROM LAPTOPS, DO NOT BUY A GAMING LAPTOP. Either buy a DESKTOP (or build) or a console. They give more performance for the price and they are easily upgradable. Not many people can open up a laptop and put in more RAM because the hardware is incredibly small.

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