Answer:
45 possible connections
Step-by-step explanation:
The general equation for finding the possible number of connections in a network is given as
[tex]\frac{n*(n - 1)}{2}[/tex]
where n is the number of computers on the network.
for 4 computers, we'll have
[tex]\frac{4*(4 - 1)}{2}[/tex] = [tex]\frac{4*3}{2}[/tex] = 6
for 5 computers, we'll have
[tex]\frac{5*(5 - 1)}{2}[/tex] = [tex]\frac{5*4}{2}[/tex] = 10.
therefore, for 10 computers, we will have
[tex]\frac{10*(10 - 1)}{2}[/tex] = [tex]\frac{10*9}{2}[/tex] = 45 possible connections
6÷7 ? 7÷8 A. > B. < C. =
Answer:
B:<
Step-by-step explanation:
You can solve this question with fractions. The way I did it was by changing both equations into fractions like this: 6÷7=6/1x1/7=6/7 and 7÷8=7/1x1/8=7/8. Since they don't have a common denomintor and you still dont know which fraction is bigger/smaller, we are going to find a common denominator which is 56. After converting both fractions, (6/7=48/56 and 7/8=49/56) Now you can see that 7/8 is bigger than 6/7, which shows that 6÷7<7÷8.
Do all systems of linear inequalities have solutions? If not, write a system of inequalities that has no solution. What would the graph of a system of linear inequalities with no solution look like?
Answer: There are systems with no solutions, and the graphs may show two regions with no intersections (as you know, the solution set is in the intersection of the sets of solutions for each inequality)
Step-by-step explanation:
Ok, suppose that our system is:
y > x
and
y < x.
This system obviously does not have any solution, because y can not be larger and smaller than x at the same time.
The graph of y > x is where we shade all the region above the line y = x (the line is not included)
and the graph of y < x is where we sade all the region under the line y = x (the line is not included)
So we will look at a graph where we never have a region with the two shades overlapping (so we do not have a intersection in the sets of solutions), meaning that we have no solutions.
In accounting, cost-volume-profit analysis is a useful tool to help managers predict how profit will be affected by changes in prices or sales volume. Net income, NININ, I, is calculated using the formula NI = (SP-VC)(V)-FCNI=(SP−VC)(V)−FCN, I, equals, left parenthesis, S, P, minus, V, C, right parenthesis, left parenthesis, V, right parenthesis, minus, F, C, where SPSPS, P is the sales price, VCVCV, C is the variable cost per unit, VVV is the sales volume, and FCFCF, C are fixed costs. Rearrange the formula to solve for sales volume (V)(V)left parenthesis, V, right parenthesis.
Answer:
(a)[tex]V=\dfrac{NI+FC}{SP-VC}[/tex]
(b)V=240 Units
Step-by-step explanation:
NI=(SP-VC)V-FC
We are required to make V the subject of the equation
Add FC to both sides
NI+FC=(SP-VC)V-FC+FC
NI+FC=(SP-VC)V
Divide both sides by SP-VC
[tex]V=\dfrac{NI+FC}{SP-VC}[/tex]
When
Net Income(NI)=$5000Sales Price(SP)=$40Variable Cost(VC)=$15Fixed Costs(FC)=$1000Volume of Sales
[tex]V=\dfrac{5000+1000}{40-15}\\=\dfrac{6000}{25}\\\\=240[/tex]
I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coins in cents in terms of k.
Answer:
40k + 35 cents
Step-by-step explanation:
Each quarter is worth 25 cents, each nickels is worth 5 cents and each dime is worth 10 cents.
Value of all quarters:
[tex]25k[/tex]
Value of all nickels:
[tex]5*(k+5)\\5k+25[/tex]
Value of all dimes:
[tex]10*(2k+1)\\20k + 10[/tex]
The value of all coins in terms of k is:
[tex]V=25k+5k+25+20k+10\\V= 40k +35\ cents[/tex]
All coins are worth 40k + 35 cents.
The time is 4 pm now and your plane is delayed by 15 hours. what time will the plane be available?
Answer:
7am
Step-by-step explanation:
What is the slope of the line that passes through the points (9, 4) and (9,-5)?
Write your answer in simplest form.
Answer: it’s undefined or 0
Step-by-step explanation:
Answer:
Undefined
Step-by-step explanation:
Slope= (y^2-y^1)/(x^2-x^1)
(x^1,y^1) and (x^2,y^2)
(9,4) and (9,-5)
SLOPE:
(-5-4)/(9-9)
-9/0
Undefined
kinda hard to show on brainy but there you go hope this helps
Tell whether the following set is an empty set or not? A = { A quadrilateral having 3 obtuse angles}
Answer:
No.
Step-by-step explanation:
A quadrilateral with 3 obtuse angles is possible. You could have 100°+100°+100°+60° quadrilateral or whatever. As long as it's inner angles add up to 360°, it is possible.
Answer:
[tex]\boxed{\mathrm{It \: is \: not \: an \: empty \: set}}[/tex]
Step-by-step explanation:
A quadrilateral with 3 obtuse angles is possible.
A obtuse angle has a measure of more than 90 degrees and less than 180 degrees.
Let’s say three angles are measuring 91 degrees in a quadrilateral.
91 + 91 + 91 + x = 360
x = 87
The measure of the fourth angle is 87 degrees which is less than 360 degrees and is a positive integer, so it is possible.
Please answer this correctly
Answer:
sorry about that that was my sister . the correct answer is yes
Step-by-step explanation:
please mark as brainliest
Of the last 100 customers entering Best Buy, 25 buy a computer. If the classical probability assessment applies, the probability that the next customer will buy a computer is:
Answer:
1/4
Step-by-step explanation:
The classical probability assessment works based on the principle that the probability of an event occurring is equal to the number of times the event occurs divided by total number of outcomes.
That is:
P(A) = n(A) / N
Therefore, the probability that the next customer will buy a computer will be:
P(c) = 25 / 100 = 1/4
Suppose you will perform a test to determine whether there is sufficient evidence to support a claim of a linear correlation between two variables. Find the critical values of r given the number of pairs of data n and the significance level α. n = 12, α = 0.01
Answer:
[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]
And is distributed with n-2 degreed of freedom. df=n-2=12-2=10
The significance level is [tex]\alpha=0.01[/tex] and [tex]\alpha/2 = 0.005[/tex] and for this case we can find the critical values and we got:
[tex] t_{\alpha/2}= \pm 3.169[/tex]
Step-by-step explanation:
In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:
Null hypothesis: [tex]\rho =0[/tex]
Alternative hypothesis: [tex]\rho \neq 0[/tex]
The statistic to check the hypothesis is given by:
[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]
And is distributed with n-2 degreed of freedom. df=n-2=12-2=10
The significance level is [tex]\alpha=0.01[/tex] and [tex]\alpha/2 = 0.005[/tex] and for this case we can find the critical values and we got:
[tex] t_{\alpha/2}= \pm 3.169[/tex]
Given the vector (4|3) and the transformation matrix (0|1|-1|0), which vector is the imagine after applying the transformation to (4|3)? A. (4|-3)
B.(-3|4)
C.(3|-4)
D.(-4|3)
Answer:
C.(3|-4)
Step-by-step explanation:
Given the vector:
[tex]\left[\begin{array}{ccc}4\\3\end{array}\right][/tex]
The transformation Matrix is:
[tex]\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right][/tex]
The image of the vector after applying the transformation will be:
[tex]\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right][/tex]
The correct option is C
The image after applying the transformation to the matrix is [tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex].
What is a matrix ?Matrix, a set of numbers arranged in rows and columns so as to form a rectangular array. The numbers are called the elements, or entries, of the matrix.
It is given that the vector is
[tex]\begin{bmatrix}4\\ 3\end{bmatrix}[/tex]
and the transformation matrix is
[tex]\begin{bmatrix}0 &1 \\ -1 &0 \end{bmatrix}[/tex]
The image after applying the transformation
[tex]\begin{bmatrix}4\\ 3\end{bmatrix}\begin{bmatrix}0 &1 \\ -1 &0 \end{bmatrix}[/tex]
[tex]\begin{bmatrix}0*4+0*3 \\-1*4+0*3 \end{bmatrix}[/tex]
[tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex]
Therefore the image after applying the transformation to the matrix is [tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex].
To know more about Matrix
https://brainly.com/question/9967572
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Mighty Casey hits two baseballs out of the park. The path of the first baseball can be described by the displacement (distance and direction) vector,
b1 = 100 i ^ + 10 j ^. The path of the second baseball can be described by the displacement vector b2 = 90 i ^ + (−20) j ^.
(a) How much farther did the first ball travel than the second? (Round your final answer to the nearest tenth.)
(b) How far are the baseballs apart? (Round your final answer to the nearest tenth.)
Answer:
a) 8.3 units of length
b) 31.6 units of length
Step-by-step explanation:
a) The distances traveled by each ball are given by:
[tex]d_1^2=100^2+10^2=10,100\\d_1=100.5\\\\d_2^2=90^2+(-20^2)=8,500\\d_2=92.2[/tex]
The diference between the distance traveled by both balls is:
[tex]d_1-d-2=100.5-92.2\\d_1-d_2=8.3[/tex]
The first ball traveled 8.3 units of length farther than the second ball.
b) The distance between both balls is:
[tex]d^2=(i_1-i_2)^2+(j_1-j_2)^2\\d^2=(100-90)^2+(10-(-20))^2\\d^2=1,000\\d=31.6[/tex]
The balls are 31.6 units of length apart.
Find the value of expression 21-2a if a =3
Answer:
15
Step-by-step explanation:
[tex]21-2a \\a =3\\21 -2(3)\\21-6\\15[/tex]
Answer:
Step-by-step explanation:
15 im sure
A supplier of heavy construction equipment has found that new customers are normally obtained through customer requests for a sales call and that the probability of a sale of a particular piece of equipment is 0.15. If the supplier has four pieces of the equipment available for sale, what is the probability that it will take fewer than six customer contacts to clear the inventory?
Answer:
The probability that it will take fewer than six customer contacts to clear the inventory is 0.8%.
Step-by-step explanation:
We have a probability of making an individual sale of p=0.15.
We have 4 units, so the probability of clearing the inventory with n clients can be calculated as:
[tex]P=\dbinom{n}{4}p^4q^{n-4}=\dbinom{n}{4}0.15^4\cdot 0.85^{n-4}[/tex]
As we see in the equation, n has to be equal or big than 4.
In this problem we have to calculate the probability that less than 6 clients are needed to sell the 4 units.
This probability can be calculated adding the probability from n=4 to n=6:
[tex]P=\sum_{n=4}^6P(n)=\sum_{n=4}^6 \dbinom{n}{4}0.15^4^\cdot 0.85^{n-4}\\\\\\P=0.15^4(\dfrac{4!}{4!0!}\cdot 0.85^{4-4}+\dfrac{5!}{4!1!}\cdot0.85^{5-4}+\dfrac{6!}{4!2!}0.85^{6-4})\\\\\\P=0.15^4(1\cdot0.85^0+5\cdot0.85^1+15\cdot0.85^2)\\\\\\P=0.00051(1+4.25+10.84)\\\\\\P=0.00051\cdot16.09\\\\\\P=0.008[/tex]
(X+3)(x+5)
Expand and simplify?
[tex](x+3)(x+5)[/tex]
[tex]x(x+5)+3(x+5)[/tex]
[tex]x^2+5x+3x+15[/tex]
[tex]\displaystyle x^2+8x+15[/tex]
Use the diagram to find the angle measures that satisfy each case. Find the measures of all four angles if 3·(m∠1+m∠3) = m∠2+m∠4.
Answer:
m∠1=45 degreesm∠2=135 degreesm∠3=45 degreesm∠4=135 degreesStep-by-step explanation:
Given that: 3(m∠1+m∠3) = m∠2+m∠4.
From the diagram:
m∠1=m∠3 (Vertical Angles)m∠2=m∠4 (Vertical Angles)Therefore:
3(m∠1+m∠1) = m∠2+m∠2
3(2m∠1)=2m∠2
Divide both sides by 2
3m∠1=m∠2
m∠1+m∠2=180 (Linear Postulate)
Therefore:
m∠1+3m∠1=180
4m∠1=180
Divide both sides by 4
m∠1=45 degrees
Since m∠1=m∠3
m∠3=45 degrees
Recall: m∠1+m∠2=180 (Linear Postulate)
45+m∠2=180
m∠2=180-45
m∠2=135 degrees
Since m∠2=m∠4
m∠4=135 degrees
When a ladder of length 2.5 m leans against the
of 55° with the ground. When the ladder leans
top edge of a window of a building, it forms an
angle
against the lower edge of the same window,
it forms an angle of 38° with the ground. Find the
height of the window, giving your answer in
centimetres.
Answer: window = 0.50 m
Step-by-step explanation:
First, draw a picture (see image below).
Then set up two equations that eventually you can set equal to each other.
Given: Ladder (hypotenuse) = 2.5
Angle to Top edge of window = 55°
Angle to Lower edge of window = 38°
[tex]\sin \text{Top}=\dfrac{opposite}{hypotenuse}\qquad \qquad \sin \text{Lower}=\dfrac{opposite}{hypotenuse}\\\\\\\sin 55^o=\dfrac{h+y}{2.5}\qquad \qquad \qquad \sin 38^o=\dfrac{y}{2.5}\\\\\\\underline{\text{Solve both equations for y:}}\\2.5\sin 55^o-h=y\qquad \qquad 2.5\sin 38^o=y\\\\\\\underline{\text{Set the equations equal to each other and solve for h:}}\\\\2.5\sin 55^o-h=2.5\sin 38^o\\2.5\sin 55^0-2.5\sin 38^o=h\\\large\boxed{0.50=h}[/tex]
What is the value of x to the nearest tenth?
Answer:
x ≈ 2.5
Step-by-step explanation:
Use tan∅ to solve this problem:
tan23° = x/6
x(tan23°) = x
x = 2.54685
The sound level measured in a room by a person watching a movie on a home theater system varies from 60 dB during a quiet part to 100 dB during a loud part. Approximately how many times louder is the latter sound
Answer:
The sound in a loud part of the room is 10000 times louder than sound in a quiet part of the same place.
Step-by-step explanation:
The acoustic intensity sound is a logarithmic function whose form is:
[tex]L = 10\cdot \log_{10}\left(\frac{I}{I_{o}} \right)[/tex]
Where:
[tex]L[/tex] - Acoustic intensity sound, measured in decibels.
[tex]I_{o}[/tex] - Reference sound intensity, measured in watts per square meter.
[tex]I[/tex] - Real sound intensity, measured in watts per square meter.
Sound intensity is now cleared:
[tex]10^{\frac{L}{10} } = \frac{I}{I_{o}}[/tex]
The ratio of the sound intensity in a loud part to the sound intensity in a quiet part is:
[tex]\frac{I_{100}}{I_{60}} = \frac{10^{\frac{100\,dB}{10} }}{10^{\frac{60\,dB}{10}}}[/tex]
[tex]\frac{I_{100}}{I_{60}} = \left(10^{100\,dB-60\,dB}\right)^{\frac{1}{10} }[/tex]
[tex]\frac{I_{100}}{I_{60}} = (10^{40\,dB})^{\frac{1}{10} }[/tex]
[tex]\frac{I_{100}}{I_{60}} =10^{4}[/tex]
The sound in a loud part of the room is 10000 times louder than sound in a quiet part of the same place.
Please answer this correctly
Answer:
9 bags
Step-by-step explanation:
130, 134, 136, 145, 145, 147, 147, 151, 154
9 bags had at least 130 peanuts.
standard form of line that passes thru (-3,5) and (-2,-6)
Answer:
11x + y = -28
Step-by-step explanation:
Step 1: Find slope
(6-5)/(-2--3) = -11
Step 2: Find y-intercept
y = -11x + b
5 = -11(-3) + b
5 = 33 + b
b = -28
Step 3: Write in slope-intercept form
y = -11x - 28
Step 4: Convert to standard form
11x + y = 28
And we have our final answer!
The personnel department of a large corporation wants to estimate the family dental expenses of its employees to determine the feasibility of providing a dental insurance plan. A random sample of 12 employees reveals the following family dental expenses (in dollars). See Attached Excel for Data. Construct a 97% confidence interval estimate for the average family dental expenses for all employees of this corporation.
The data cited is in the attachment.
Answer: 308.2±106.4
Step-by-step explanation: To construct a confidence interval, first calculate mean (μ) and standard deviation (s) for the sample:
μ = Σvalue/n
μ = 308.2
s = √∑(x - μ)²/n-1
s = 147.9
Calculate standard error of the mean:
[tex]s_{x} = \frac{s}{\sqrt{n} }[/tex]
[tex]s_{x}[/tex] = [tex]\frac{147.9}{\sqrt{12} }[/tex]
[tex]s_{x}[/tex] = 42.72
Find the degrees of freedom:
d.f. = n - 1
d.f. = 12 - 1
d.f. = 11
Find the significance level:
[tex]\frac{1-0.97}{2}[/tex] = 0.015
Since sample is smaller than 30, use t-test table and find t-score:
[tex]t_{11,0.015}[/tex] = 2.4907
E = t-score.[tex]s_{x}[/tex]
E = 2.4907.42.72
E = 106.4
The interval of confidence is: 308.2±106.4, which means that dental insurance plan varies from $201.8 to $414.6.
SOMEONE PLEASE HELP ME ASAP PLEASE!!!
Answer:
A = 45 units^2
Step-by-step explanation:
This is a trapezoid
A = 1/2 (b1+b2) h
b1 is the top = 7
b2 is the bottom = 11
h = 5
A = 1/2 ( 7+11) *5
A = 1/2 ( 18)*5
A = 45 units^2
Explain the steps you would take to complete this
conversion problem.
46 lb 1kg 1,000 g - 2
2.2 lb
1
1kg
Answer:
First, you would cancel out the lb in 2.2 lb, and cancel the kg in 1 kg. Then, you cross multiply. 46 x 1 x 1000 is 46000, you're just moving the decimal point. 1 x 2.2 x 1 would stay the same, so you would have 46000 over 2.2.
Step-by-step explanation:
Find the center and radius of the radius of the circle with the given equation. x^2 + (y+7)^2 = 64
Answer:
The standard form of a circle is (x - c)² + (y - d)² = r² where (c, d) is the center and r is the radius. This means that the center is (0, -7) and the radius is 8.
Answer: Center = (0, -7)
Radius = 8
Step-by-step explanation:
The equation of a circle is: (x - h)² + (y - k)² = r² where
(h, k) is the centerr is the radiusx² + (y + 7)² = 64
→ (x - 0)² + (y - (-7))² = 8²
↓ ↓ ↓
h=0 k=-7 r=8
(h, k) = (0, -7)r = 8I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
Answer:
[tex]g(2) = 4(2) + 6 = 14[/tex]
[tex]f(2) = 2(2) + 3 = 7[/tex]
[tex](g - f)(2) = 14 - 7 = 7[/tex]
problem decoded dude
thank and follow meh
Which is the cosine ratio of
Answer:The answer is B
Step-by-step explanation:
Answer:
Option B
Step-by-step explanation:
Cos A = [tex]\frac{Adjacent}{Hypotenuse}[/tex]
Where Adjacent = 28, Hypotenuse = 197
Cos A = [tex]\frac{28}{197}[/tex]
A toll bridge charges $1.00 for passenger cars and $2.25 for other vehicles. Suppose that during daytime hours, 60% of all vehicles are passenger cars. If 15 vehicles cross the bridge during a particular daytime period, what is the resulting expected toll revenue
Answer:
Total revenue = 13.5 + 9 = $22.5
Step-by-step explanation:
The toll charges $1.00 for passenger cars and $2.25 for other vehicles. During daytime hours 60% of all the vehicles are passenger vehicles.
A particular daytime period 15 vehicle crossed the bridge. Recall that during daytime period, 60% of all the vehicles are passenger vehicles . Therefore,
Passenger vehicles = 60% of 15
Passenger vehicles = 60/100 × 15
Passenger vehicles = 900/100
Passenger vehicles = 9
9 of the vehicles are passenger vehicle and the charges for passenger cars is $1.00. other vehicle is $2.25.
revenue for passenger cars = 1 × 9 = $9
revenue for other vehicles = 2.25 × 6 = $13.5
Total revenue = 13.5 + 9 = $22.5
It is advertised that the average braking distance for a small car traveling at 75 miles per hour equals 124 feet. A transportation researcher wants to determine if the statement made in the advertisement is false. She randomly test drives 37 small cars at 75 miles per hour and records the braking distance. The sample average braking distance is computed as 112 feet. Assume that the population standard deviation is 22 feet.
Answer:
[tex]z=\frac{112-124}{\frac{22}{\sqrt{37}}}=-3.318[/tex]
The p value would be given by this probability:
[tex]p_v =2*P(z<-3.318)=0.0009[/tex]
Since the p value is a very small value at any significance level used we can reject the null hypothesis and we can conclude that the true mean for this case is different from 124 ft
Step-by-step explanation:
Data given and notation
[tex]\bar X=112[/tex] represent the sample mean
[tex]\sigma =22[/tex] represent the population standard deviation
[tex]n=37[/tex] sample size
[tex]\mu_o =124[/tex] represent the value that we want to test
z would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value
Hypothesis to test
We want to check the following system of hypothesis:
Null hypothesis: [tex]\mu = 124[/tex]
Alternative hypothesis :[tex]\mu \neq 124[/tex]
The statistic is given by:
[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex] (1)
Replacing the info given we got:
[tex]z=\frac{112-124}{\frac{22}{\sqrt{37}}}=-3.318[/tex]
The p value would be given by this probability:
[tex]p_v =2*P(z<-3.318)=0.0009[/tex]
Since the p value is a very small value at any significance level used we can reject the null hypothesis and we can conclude that the true mean for this case is different from 124 ft
9+9+3=21
1234+1234+1234= 30
9+1224+12=?
Answer:
9+1224+12=1245
Hope this helps
Answer:
Mathematically,
9+1224+12 = 1245
But, Logically, here:
9+1224+12 = 21