Answer:
40.34 g
Explanation:
First, we divide the heat to release by the heat of combustion to obtain the required moles of compound:
541.20 kJ/(1160.00 kJ/mol) = 0.4665 mol
So, we have to burn approximately 0.47 mol of the compound. We convert the moles to mass in grams by using the molar mass:
mass = molar mass x moles = 86.47 g/mol x 0.4665 mol = 40.34 g
Therefore, you must burn 40.34 grams of the compound to release 541.20 kJ of heat.
Base your answer on the information below. The hydrocarbon 2-methylpropane reacts with iodine as represented by the balanced equation below. At standard pressure, the boiling point of 2-methylpropane is lower than the boiling point of 2-iodo-2-methylpropane. Explain the difference in the boiling points of 2-methylpropane and 2-iodo-2-methylpropane in terms of both molecular polarity and intermolecular forces.
Answer:
See explanation
Explanation:
The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.
2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.
As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than 2-methylpropane.
what type of reaction is Au2S+H2---> 2Au+H2S
Answer:
single replacement reaction is type of reaction is Au2S+H2---> 2Au+H2S.