If the angle of incidence of a ray of light is 50 degrees, what would the angle of reflection
be?

Bii). If the angle of incidence of a ray of light is 45 degrees, what would the angle of reflection?​

Answer:

[tex](a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]

[tex](b)\ F_{No} = 771.125N[/tex]

Explanation:

Given

[tex]d_D = 6000ft[/tex] ---- Altitude of container in Denver

[tex]A = 0.0155m^2[/tex] -- Surface Area of the container lid

[tex]P_D = 79000Pa[/tex] --- Air pressure in Denver

[tex]P_{No} = 100250Pa[/tex] --- Air pressure in New Orleans

See comment for complete question

Solving (a): The expression for [tex]F_{No[/tex]

Force is calculated as:

[tex]F = \triangle P * A[/tex]

The force in New Orleans is:

[tex]F_{No} = \triangle P * A[/tex]

Since the inside pressure is half the pressure at sea level, then:

[tex]\triangle P = P_{No} - \frac{P_{area}}{2}[/tex]

Where

[tex]P_{area} = 101000Pa[/tex] --- Standard Pressure

Recall that:

[tex]F_{No} = \triangle P * A[/tex]

This gives:

[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]

Solving (b): The value of [tex]F_{No[/tex]

In (a), we have:

[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]

Where

[tex]A = 0.0155m^2[/tex]

[tex]P_{No} = 100250Pa[/tex]

[tex]P_{area} = 101000Pa[/tex]

So, we have:

[tex]F_{No} = [100250 - \frac{101000}{2}] * 0.0155[/tex]

[tex]F_{No} = [100250 - 50500] * 0.0155[/tex]

[tex]F_{No} = 49750* 0.0155[/tex]

[tex]F_{No} = 771.125N[/tex]

Explanation:

The voltage sensitivity of  a galvanometer is given by :

[tex]\dfrac{NBA}{RK}[/tex]

Where

N=Number of turns

A=Area of coil

B=Magnetic field produced in coil

K=Torsion constant of galvanometer

R=Resistance of galvanometer

The current sensitivity of  a galvanometer is given by :

[tex]\dfrac{NBA}{K}[/tex]

Hence, this is the required solution.

Answer:To explian the exact calculation of this pruduct we must not try!

Answer:

40*C

Explanation:

The relative error in this weight measurement as percentage is

is the ratio of the absolute error of a measurement to the measurement being taken. In other words, this type of error is relative to the size of the item being measured.

Therefore,

[tex]\% relative error = \frac{smallest division}{mass of apples}*100\\\\\% relative error = \frac{2.1g}{1900}*100\\\\\% relative error = 0.1105\%[/tex]

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Answer:

The relative error in this weight measurement is approximately 0.1105 %.

Explanation:

We know that,
Relative Error is the ratio of the absolute error of a measurement to the actual measurement . It can be mathematically represented as,

Relative Error  = (Measured Value - Actual Value)  / Actual Value * 100

In this case, the actual weight is 1.9 kg, and the smallest division of the spring scale is 2.1 g.

Actual Weight = 1.9  * 1000  = 1900  (As 1 kg = 1000g)

We know that the absolute error will be equal to the smallest division hence,

Measured Value - Actual Value = 2.1 g

By replacing this in the general formula we get,

Relative Error = (Measured Value - Actual Value) / Actual Value * 100

= [tex]\frac{2.1}{1900} *100[/tex] %

= [tex]\frac{2.1}{19}[/tex] %

≈ 0.1105 %

Therefore, the relative error in this weight measurement is approximately 0.1105 %.

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Answer:

slightly different frequencies

Explanation:

The alternate increase or decrease of sound produced by the interference of two sound waves of slightly  different frequencies is called ‘Beat’. The maximum beat frequency that a human ear can detect is 7 beats/sec.

This definition of the beats is clearly pointing out that the two waves whose frequencies are slightly different will add together to produce the beats.

Therefore, the correct answer will be:

slightly different frequencies

Answer:

[tex]P_c=-4v[/tex]

Explanation:

From the question we are told that:

Inner radius [tex]r_1=0.2[/tex]

Outer radius[tex]r_2=0.4[/tex]

Potential at the outer surface is [tex]P_o= -2 V[/tex]

Generally the equation for Potential at the outer surface P_o  is mathematically given by

[tex]P_o=\frac{KQ}{r_2}[/tex]

[tex]-2=\frac{KQ}{0.4}[/tex]

Therefore

[tex]KQ=-0.8v[/tex]

Generally the equation for Potential at Center of outer cavity [tex]P_c[/tex]  is mathematically given by

[tex]P_c=\frac{KQ}{r_1}[/tex]

[tex]P_c=\frac{-0.8}{0.2}[/tex]

[tex]P_c=-4v[/tex]

Therefore the potential at the center of cavity

[tex]P_c=-4v[/tex]

The potential at the center of the cavity of the spherical conducting shell is -0.4 V.

Electric potential of spherical shell is the total amount of work required to move a charge in s spherical shell from one point to other.

Electric potential of spherical shell at outer surface can be given as,

[tex]P_{outer}=k\dfrac{Q}{r_o}[/tex]

Electric potential of spherical shell at center of outer gravity can be given as,

[tex]P_{cavity}=k\dfrac{Q}{r_i}[/tex]

Here, (Q) is the charge, (k) is the constant and [tex](r_o, r_i)[/tex] is the outer and inner radius.

A spherical conducting shell has an outer radius of 0.4 m and the potential at the outer surface is -2 V. Thus, the potential at the outer surface can be find out using the above formula as,

[tex]-2=k\dfrac{Q}{0.4}\\kQ=-0.8\rm V[/tex]

The spherical conducting shell has an inner radius of 0.2 m. Thus, the potential at the outer surface can be find out using the above formula as,

[tex]P_{cavity}=k\dfrac{Q}{0.2}\\P_{cavity}=\dfrac{-0.8}{0.2}\\P_{cavity}=-0.4\rm V[/tex]

Thus, the potential at the center of the cavity of the spherical conducting shell is -0.4 V.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

We have

[tex]a = \frac{39}{5.6} \\ = 6.964285...[/tex]

We have the final answer as

Hope this helps you

Answer:

The moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

Explanation:

Given;

radius of the turnable, r = 60 cm = 0.6 m

rotational kinetic energy, E = 0.25 J

angular speed of the turnable, ω = 45 rpm

The rotational kinetic energy is given as;

[tex]E_{rot} = \frac{1}{2} I \omega ^2[/tex]

where;

I is the moment of inertia about the axis of rotation

ω is the angular speed in rad/s

[tex]\omega = 45 \frac{rev}{\min} \times \frac{2 \pi \ rad}{1 \ rev} \times \frac{1 \ \min}{60 \ s} \\\\\omega = 4.712 \ rad/s[/tex]

[tex]E = \frac{1}{2} I \omega ^2\\\\I = \frac{2E}{\omega ^2} \\\\I = \frac{2 \ \times \ 0.25}{(4.712)^2} \\\\I = 0.0225 \ kg.m^2[/tex]

Therefore, the moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

Answer:

in decimal form x = 1.5

in exact form x = 3/2

and as a mixed number x = 1  1/2

Explanation:

It increases

Explanation:

The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between object

Answer:

C: Gravity decreases

Explanation:

Answer:

ook soooooo

Explanation:

Answer:

A) 11.2 s

B) is 56 s

C) 170.8 s

Explanation:

Impacts of large meteorites have never been observed by humans. Much of our knowledge about what happens next must come from scaled experiments. As the solid object plows into the Earth, it will compress the rocks to form a depression and cause a jet of fragmented rock and dust to be expelled into the atmosphere.

This question is incomplete, the complete question  is;

Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies the initial conditions specified. Units are mks; γ is the damping coefficient, with units of kg/sec

m = 0.2, γ = 1.6 and k = 4

Initial displacement is 1 and initial velocity is -2

x" + _____ x' ____x = 0

x(t) =

Answer:

the solution that satisfies the initial conditions specified is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

Explanation:

Given the data in the question ;

m = 0.2, γ = 1.6, k = 4

x(0) = 1, x'(0) = -2

Now, the differential equation that governs the motions of spring mass system is;

mx" + γx' + kx = 0

so we substitute

0.2x" + 1.6x' + 4x = 0

divide through by 0.2

x" + 8x' + 20x = 0

hence, characteristics equation will be;

m² + 8m + 20 = 0

we find m using; x = [ -b±√(b² - 4ac) ] / 2a

m = [ -8 ± √((8)² - 4(1 × 20 )) ] / 2(1)

m = [ -8 ± √( 64 - 80 ) ] / 2

m = [ -8 ± √-16 ) ] / 2

m = ( -8 ± 4i ) / 2

m = -4 ± 2i

Hence, the general solution of the differential equation is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

From the initial conditions;

c₁ = 1, c₂ = 1

the solution that satisfies the initial conditions specified is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

Answer:

10m

Explanation:

Answer:

um let me know what i can do to try get you full access

Explatnation:

Answer:

2633.7 s

Explanation:

From the question,

Heat lost by the water heater = Heat gained by the water

Applying,

P = cm(t₂-t₁)/t.................. Equation 1

Where P = power of the heat, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature, t = time

make t the subject of the equation

t = cm(t₂-t₁)/P.............. Equation 2

From the question,

Given: c = 4190 J/kgK, P = 3.5 kW = 3500 W, m = 40 kg, t₁ = 20°C, t₂ = 75°C

Substitute these values into equation 2

t = 4190×40(75-20)/3500

t = 9218000/3500

t = 2633.7 s

Answer:

Independent, then dependent

Explanation:

Just took this on Edge 2021

Answer:

the wavelength of the sound in seawater is 90.1 m.

Explanation:

Given;

frequency of the sound, f = 17 Hz

speed of the sound in seawater, v = 1531 m/s

The wavelength of the wave is calculated as follows;

v = fλ

λ = v / f

where;

λ is the wavelength of the sound

λ = 1531 / 17

λ = 90.1 m

Therefore, the wavelength of the sound in seawater is 90.1 m.

Answer:

61.8

Explanation:

It must be going at a speed of 61.81 m/s when it reaches the plain below

The kinematic equations are a set of equations that describe the motion of an object with constant acceleration. Kinematics equations require knowledge of derivatives, rate of change, and integrals.

using  Kinematics equations

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2gs                         ( a = g)

   = [tex](53.7)^{2}[/tex] + 2 * 9.8 * 47.8 m

 v  = 61.81 m/s

It must be going at a speed of 61.81 m/s when it reaches the plain below

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Answer:

optimism

Explanation:

just an idea

....

Answer:

[tex]f_{U}= 1019.72hz[/tex]

Explanation:

From the equation we are told that:

Velocity of French sub [tex]V_{U}= 43.00km/h[/tex]

Velocity of U.S. sub at [tex]V_{F}|=64.00 km//h[/tex]

French Wave Frequency  [tex]F_{F}=1000Hz[/tex]

Velocity of wave  [tex]V_{s}=5470 km/h[/tex]

Generally the equation for Signal's frequency as detected by the U.S. is mathematically given by

Doppler effect

 [tex]f_{U} = \frac{ f_F (vs + v_{U})}{(v_s - v_F) }[/tex]

 [tex]f_{U}= \frac{ 1000 x ( 5470+64)}{(5470-43)}[/tex]

 [tex]f_{U}= 1019.72hz[/tex]

Answer:

B

Explanation:

Answer:

Rain water carries sediment and then these accumulate on the bottom of ponds, lakes and wetlands. This accumulation build up over time and eventually, the water disappears (because they sink into the ground) and the area once covered with water becomes land.

Answer:

The answer is "[tex]4659.2 \times 10^{-24} \ N[/tex]"

Explanation:

The magnetic field at ehe mid point of the coils is,

[tex]\to B=\frac{\mu_0 i R^2}{(R^2+x^2)^{\frac{3}{2}}}\\\\[/tex]

Here, i is the current through the loop, R is the radius of the loop and x is the distance of the midpoint from the loop.

[tex]\to B=\frac{(4\pi\times 10^{-7})(2.80\ A) (\frac{0.35}{2})^2}{( (\frac{0.35}{2})^2+ (\frac{0.24}{2})^2)^{\frac{3}{2}}}\\\\[/tex]

       [tex]=\frac{(12.56 \times 10^{-7})(2.80\ A) \times 0.030625}{( 0.030625+ 0.0144)^{\frac{3}{2}}}\\\\=\frac{ 1.07702 \times 10^{-7} }{0.0095538976}\\\\=112.730955 \times 10^{-7}\\\\=1.12\times 10^{-5}\ \ T\\[/tex]

Calculating the force experienced through the protons:

[tex]F=qvB=(1.6 \times 10^{-19}) (2600)(1.12 \times 10^{-5})= 4659.2 \times 10^{-24}\ N[/tex]