If the acceleration of an object is negative , the object must be slowing down .

As you drag the skater up higher, the potential energy increases. As you drag the skater down lower, the potential energy decreases.

This is because potential energy is determined by the skater’s height, so as the skater’s height changes, the amount of potential energy changes accordingly.

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases. The potential energy of a steel ball is greater when it is raised above the earth than when it is brought to Earth.

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In the followings set of the numbers given, 12.8 m have the fewest number of significant figures.

Significant figures can be described as the number of digits that is present in a in a value, and made up of the degree of accuracy of the value.

The rules for calculations using significant figures are:

1. All non-zero numbers  are included.

2. Leading zeros are not significant.

3. Zeros that is found in between two non-zero digits are included.

4. All trailing zeros to the right of the decimal are significant.

5. Trailing zeros in a whole number with no decimal shown are significant.

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Mrs. Suki is looking for a material to place on the floor under the preschooler's cubbies that will reduce the momentum of a dropped lunch box and prevent it from breaking.

A preschooler's cubby is a small, personal storage space designed for children to store their belongings at school, daycare, or a similar educational setting. It is typically an open shelf or cabinet with multiple compartments for each child to store their items.

Based on her testing, she found that Material #1 is the best option because it causes the lunch box momentum to decrease to 0 in the shortest amount of time, 1 second. Material #2 is a good option too, but it takes 2 seconds for the momentum to decrease to 0, which is slightly longer than Material #1. Therefore, Material #1 is the best choice for reducing the momentum of a dropped lunch box and keeping it from breaking.

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F_net = 6.672 × 10^-11 * ((111 * 23.9) / (0.396 / 2)^2 + (290 * 23.9) / (0.396 / 2)^2) N part 2) x = sqrt((111 * 23.9) / (290 * 23.9)) * (0.396/2) m

According to Newton's universal law of gravitation, force of attraction between any two bodies is directly proportional to product of their masses and is inversely proportional to square of the distance between them.

We know, F = G * (m1 * m2) / r^2

Given m1 = 23.9 kg and m2 = 290 kg

m1 and m2 are the masses of the two objects, r is separation distance between them, and G is universal gravitational constant.

F1 = G * (111 * 23.9) / (0.396 / 2)^2

F2 = G * (290 * 23.9) / (0.396 / 2)^2

As, F_net = F1 + F2

F_net = 6.672 × 10^-11 * ((111 * 23.9) / (0.396 / 2)^2 + (290 * 23.9) / (0.396 / 2)^2) N

part 2)  As, F = G * (m1 * m2) / r^2

G is the universal gravitational constant and r is distance between the two masses.

Let x be the distance of the 23.9 kg mass from 290 kg mass. Then the distance between 111 kg mass and 23.9 kg mass is x - 0.396/2.

So, F1 = G * (111 * 23.9) / (x - 0.396/2)^2

and F2 = G * (290 * 23.9) / x^2

Setting F1 = -F2, :

G * (111 * 23.9) / (x - 0.396/2)^2 = G * (290 * 23.9) / x^2

So, x = sqrt((111 * 23.9) / (290 * 23.9)) * (0.396/2) m

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The distance car travel at 9.00 s is 112.8 m.

Acceleration of car = (v - u)/t

Here given,

v = 0 m/s

u = 25 m/s

t = 9.00 s

By substituting values,

a = (0 m/s - 25.0 m/s) / 9.00 s

a = -2.77 ms⁻²

S = V² - u² / 2a

= ((0 ms⁻¹)² - (25.0 ms⁻¹)²) / 2 x -2.77 ms⁻²

= 112.8 m

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The work done by the force is √7 Newtons. The result is obtained by multiplying the distance by the force.

The work done on an object can be counted by the equation:

W = F × d

Where

Find the work done by the force!

We have:

The distance (straight line) is

[tex]d = \sqrt{(x_{1}- x_{2})^{2} + (y_{1}- y_{2})^{2} + (z_{1}- z_{2})^{2} }[/tex]

[tex]d = \sqrt{(9-19) + (-7 + 5) + ((-10) - (-9)) }[/tex]

[tex]d = \sqrt{(10) -2 + (-1 )[/tex]

d = √7 meters

The force is F.

Hence, the magnitude of the force on the object are √7 F.

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Upon coming into contact with an uncharged metal sphere B, metal sphere A becomes positively charged, making both spheres positively charged.

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Answer:(i) The magnitude of the force that is pressing the lawn-mower directly into the ground is 25 N

(ii) The magnitude of the effective force that moves the mower forward is approximately 43.3 N

(iii) Because there are no net downward force acting on the lawn-mower

Explanation:

Answer:

the answer it's flas

Explanation:

I wish I help you

The combined kinetic energy of the boy and the bicycle is 1920 J.

We know that kinetic energy of a body is given by K.E. : [tex]\frac{1}{2} mv^{2}[/tex]

Here m = combined mass = 45+15 kg = 60 kg

Given speed = v = 8 m/s

Putting these values in above equation we get K.E. = 1920 J

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The x-component of A vector is - 2.39 unit.

The y-component of A vector is  - 4.02  unit.

Vector is a colloquial term  that refers to some quantities that cannot be expressed by a single number (a scalar) or to elements of some vector spaces.

The magnitude of A vector is 4.68 unit.

The  direction of A vector is 30.7° to the left of the negative y-axis.

So, A vector is in 3rd co-ordinate.

Hence, the x-component of A vector is = - Asin30.7°

= - 4.68 × sin30.7°

= - 2.39 unit.

Hence, the y-component of A vector is = - Acos30.7°

= - 4.68 × cos30.7°

= - 4.02  unit.

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As the charge is relocated because of that charge, the configuration of the field lines inside will alter. The induced surface charge outside the sphere is uniformly dispersed throughout the exterior surface.

Two point charges A and B are set at a specific distance apart with force F acting between them. They have charges of +Q and -Q, respectively. It is accurate to say that only stationary electric charges are subject to Coulomb's law. This is because, in the case of moving charges, a current exists, which produces a magnetic field, which in turn exerts force on moving charges; as a result, Coulomb's Force is no longer the only force to be taken into account. A charge distribution that has a value solely at one specific place is known as a point charge. A test charge is a point charge that is so little that it has no impact on the charge distribution you are testing.

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The dog run 28 km back and forth between its owner and the road, at the speed of 10.0 km/hr.

Speed of the man throughout the whole distance, v₁ = 5 km/hr

After 1 km, the speed of the man is same but the speed of dog, v₂ = 10 km/h

The distance between the road and the dog's owner after he unleash the dog, d = (15 - 1) = 14 km

Time taken by the owner to reach the road, t = 14/5 = 2.8 hrs

Distance travelled by the dog in 2.8 hrs, = 2.8 × 10 = 28 km

So the dog run a total of 28 km distance.

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The expression for the buoyant force is F = ρghs²

Buoyant force is the force exerted on a object by a liquid.

Given that the pressure from the fluid at a certain depth is given by P = P₀ + ρgh where

We know that the buoyant for is due to the pressure difference frm the top and bottom of the fluid.

Since

P = P₀ + ρgh

P - P₀ = ρgh

ΔP =  ρgh

Now, we know that pressure difference, ΔP = F/A where

So, making F subject of the formula, we have that

F = ΔPA

Now since the object is a perfect cube of length, s, its area at its bottom surface perpendicular to F is A = s²

So, F = ΔPA

F = ΔPs²

So, substituting ΔP into the equation, we have that

F = ΔPs²

F = ρghs²

So, the buoyant force is F = ρghs²

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The strength of the electric field 4.0 cm from a small glass bead that has been charged to 5.0 nc will be 7.912 x 106 N/C.

The strength of an electric field 4.0 cm from a small glass bead that has been charged to 5.0 nC can be calculated using Coulomb's law.

According to this law, the electric field, E, is equal to the charge, Q, divided by the permittivity of free space, ε, multiplied by the distance between the charge and the point in space, r, squared.

Therefore, the electric field at a distance of 4.0 cm from the bead is equal to:

E = (5.0 nC) / (8.854 x 10-12 [tex]C^{2}/ nm^{2}[/tex]) x (0.04 m)

E = 7.912 x 106 N/C

This means that the electric field at a distance of 4.0 cm from the glass bead charged to 5.0 nC is 7.912 x 106 N/C.

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After the universe's 13.7 billion year old Big Bang, it has gone through numerous phases or epochs.

It may have experienced more activity and change in the first second than in all the billions of years since because of the harsh environment and violence of its very early beginnings.

We can construct a rough timeline as follows using our current understanding of how the Big Bang might have developed, taking into account notions about inflation, the Grand Unification, etc.

The Planck Epoch (or Planck Era), which spans from 0 to around 10-43 seconds (1 Planck Time), is the closest that modern physics can come to the beginning of time itself.

Therefore, After the universe's 13.7 billion year old Big Bang, it has gone through numerous phases or epochs.

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To find the speed at which the ball must be thrown, we need to use the conservation of energy. The final potential energy is  v = 8.14 m/s .

The initial potential energy of the ball is given by mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the height from which the ball is thrown. The final kinetic energy of the ball is given by 1/2mv^2, where v is the speed at which the ball bounces back.Since the ball bounces back to the same height, the final potential energy is also mgh. Since kinetic energy is lost when the ball bounces, we know that the final kinetic energy is 85% of the initial kinetic energy.

So we can set up the following equation:

mgh = 0.85 * (1/2mv^2)

Solving for v, we get:

v = sqrt(2gh/0.85)

v = sqrt(2 * 9.8 * 12.4 / 0.85)

v = 8.14 m/s

So the speed at which the ball must be thrown is 8.14 m/s vertically downward from a height of 12.4 m to have it bounce back to the same height.

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Eating broccoli absorbs chemical energy that your body converts to energy that your body needs, such as energy for movement , temperature control and other life processes.

 This refers to a green plant that is edible. It is in the cabbage famil. It has a large flowering head, stalk, and small associated leaves that are eaten as a vegetable. Broccoli is classified in the Italica cultivar group of the species Brassica oleracea.

Broccoli is a nutrient-rich vegetable that may enhance your health in a variety of ways, such as by reducing inflammation, improving blood sugar control, boosting immunity, and promoting heart health.

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(A) Units for derivative is d(t) = 16t^2, (B) height of the ledge is 0 feet, and stone is moving with a speed of 46.667 x s mph.

A. The units associated with the derivative of d(t) = 16t^2 are feet per second, and it measures the velocity of the object at a certain point in time.

B. To find the height of the ledge, we need to find the value of t when the stone reaches the ground. We can set d(t) = 0 and solve for t:

16t^2 = 0

t^2 = 0

t = 0

Since t = 0, the stone was dropped from rest, so the height of the ledge is d(0) = 16(0)^2 = 0 feet.

To find the velocity of the stone when it strikes the ground, we can find the derivative of d(t) = 16t^2 at t=s.

d'(t) = 32t

d'(s) = 32s

Since the stone was falling in feet per second. To convert to miles per hour we need to multiply the value by 1.46667 (conversion factor)

d'(s) x 1.46667 = 32s x 1.46667 = 46.667s mph

So the stone is moving at 46.667 x s mph when it strikes the ground.

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Significant figures are a number of digits used to describe a particular measurement. While considering the significant figures, it must be noted that to define a measurement, it is necessary to define its unit too. So unit consideration is also a factor before defining the number of reasonably significant figures.

a ) Considering the thickness unit to be ( mm ). So the thickness of the measurement book will satisfy two nondecimal digits. So its significant figure is 2.

b ) Considering air temperature unit to be ( °C ). So the outdoor temperature with bulb thermometer will satisfy with three decimal digits. Because it is a fluid measuring device it is difficult to get the measurement without decimal digits. So its significant figure is 3.

c ) Considering wind speed unit to be (m/s ). So the wind speed with a vane anemometer will satisfy with three decimal digits as a vane anemometer is also a device. So its significant figure is 3.

d ) As the weight of the platinum bar unit is defined as ( lb ). So significant figure with three decimal digits must satisfy the weight of approximately 50 lb. So its significant figure is 3.

Dimension is the quantification of attributes of an item or occasion, which may be used to compare with different items or activities. In different words, size is a technique of figuring out how massive or small a bodily amount is compared to a basic reference amount of the equal type. The scope and application of measurement are depending on the context and field.

In herbal sciences and engineering, measurements do now not observe nominal residences of items or events, that's constant with the recommendations of the worldwide vocabulary of metrology posted through the International Bureau of Weights and Measures. but, in different fields including facts as well as the social and behavioral sciences, measurements can have multiple tiers, which could consist of nominal, ordinal, c language, and ratio scales.

Dimension is a cornerstone of change, technological know-how, era, and quantitative studies in many disciplines. traditionally, many dimension systems existed for the various fields of human life to facilitate comparisons in those fields. frequently those have been achieved by means of local agreements among trading companions or collaborators.

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According to the problem the temperature of the light bulb is 1 Kelvin.

Temperature is a measure of how hot or cold something is. It is measured using a thermometer or thermocouple and is usually expressed as a number on a scale, such as Celsius or Fahrenheit.

The temperature of a light bulb can be calculated using the Stefan-Boltzmann law. This law states that the power emitted by a blackbody is proportional to the fourth power of its temperature. Therefore, the temperature of the light bulb can be calculated by taking the fourth root of the ratio of the power emitted by the human to the power emitted by the light bulb.
The power emitted by a human is around 100 watts and the power emitted by a 100 watt incandescent bulb is also 100 watts. Therefore, the temperature of the light bulb is the fourth root of 100/100, which is 1.
Therefore, the temperature of the light bulb is 1 Kelvin.

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The velocity of the sailboat is 12.5 meters per second.

Velocity is a measure of how fast an object is moving in a specific direction. It is calculated by dividing the distance traveled by the time it took to travel that distance. The unit of velocity is meters per second (m/s) or kilometers per hour (km/h).

To understand how the velocity of the sailboat was calculated, it is important to understand the concept of velocity and how it is measured. Velocity is a vector quantity, meaning it has both magnitude (size) and direction. The magnitude of velocity is measured in units of distance per unit of time, such as meters per second (m/s) or kilometers per hour (km/h). The direction of velocity is the direction in which an object is moving.

In this scenario, the sailboat was in a 1000-meter race and reached the finish line in exactly 1 minute and 20 seconds, or 80 seconds. To calculate the velocity of the sailboat, we used the formula: Velocity = distance / time. Substituting in the given values, we have: Velocity = 1000 meters / 80 seconds = 12.5 meters per second. This means that the sailboat was moving at a speed of 12.5 meters per second.

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As velocity, v of the object approach the speed of light c, the energy of the particles will increase.

From the famous equation of Einstein of mass-energy relationship, that is

E = m₀c²/√(1-v²/c²)

Where E denotes the energy, c is the speed of light, v is the speed of the object.

If mass of the object at rest is m₀, we can see from the above relationship that as we approaches c, the denominator terms goes closer to 0. And when v becomes speed of light c, then the denominator becomes zero. Thus making the Energy infinite. So the energy becomes infinite.

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We see the right side of the moon illuminated when the moon is waxing.

The Moon is in the Waxing Crescent phase when its western edge is bright but the majority of the surface that can be seen from Earth is dark. Waxing refers to the fact that the amount of light visible during this phase increases day by day.

The Earth's moon cycle has four phases, to start. A new moon, first quarter, third quarter, and full moon are among them.

There are 29.5 days in a lunar cycle. The moon completes one orbit of the Earth in around 27.3 days. Given that the Earth has travelled around 45 million miles during the time it takes the moon to complete one full orbit around the Earth, the 2.2-day delay is effectively the moon "catching up" to the Earth.

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Answer:

Once static friction gives up, it allows the box to begin sliding across the floor, the frictional force acting on the box, is now the force of sliding friction exerted by the floor on the box

Explanation:

.

the magnitude and the polarisation of the electric field at point p, with the polarisation of the electric field pointing away from charge B. (to the left). If the sphere has a nonconducting , the magnitude is force*q.

The magnitude of the electric field at point P is 3*10^5 N/C. The electric field strength at point P, which is along the straight line between point P and Q, is parallel to the direction of the charge Q. (since there is a negative charge). The equation E = F Q thus describes the electric field at point p that point charge Q produces. The electric field created by a point charge Q is shown in the accompanying graphic in its direction.

magnitude = force*q for q>0.

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A student connects a resistor to a cell for 60 seconds and resistor is 0. 97. So the charge flow is 58.2 coulombs.

What is meant by resistor ?

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The temperature in Fahrenheit is 146.799°F.

The equation of state for a fictitious ideal gas is known as the ideal gas law, sometimes known as the generic gas equation. Although it has some restrictions, it is a good approximation of the behavior of numerous gases under various circumstances. Benoît Paul Émile Clapeyron introduced it for the first time in 1834 as a synthesis of the empirical Boyle's law, Charles' law, Avogadro's law, and Gay's law. Lussac's. The empirical form of the ideal gas law is frequently used which is PV = nRT. The ideal gas constant is R.

Density = ρ = 4 kg/m3

Pressure = P = 400 kPa

As we know the ideal gas equation is PV = nRT

P =  ρRT

400 = 4 x 0.2968 x T

T = 336.927 K

The temperature in Fahrenheit is 146.799°F.

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You might need to slow down because, generally speaking, a bicycle moves more slowly than other vehicles.

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The bottom of the hill, the cart's kinetic energy would be 147150 joules.

In physics, an object's kinetic energy is the energy it has as a result of motion. It is explained as the amount of effort required to move a mass-based body from rest to the indicated velocity. The body keeps its kinetic energy, which it acquired during acceleration, unless its speed changes.

Let KE denote Kinetic Energy

As an equation, the relationship would be:

[tex]$m g h=\frac{1}{2} m v^2$$[/tex]

Kinetic Energy = m g h

Assuming the acceleration due to gravity near the earth's surface exists [tex]$9.81 \frac{\mathrm{m}}{\mathrm{s}}$[/tex], our equation becomes:

[tex]$$\begin{aligned}& K E=500 \mathrm{~kg} \cdot 9.81 \frac{\mathrm{m}}{\mathrm{s}} \cdot 30 \mathrm{~m} \\& K E=147150 \text { Joules }\end{aligned}$$[/tex]

Once a result, as the cart nears the base of the hill, where its gravitational potential energy is transformed into kinetic energy, its kinetic energy would be equal to its initial potential energy.

At the bottom of the hill, the cart's kinetic energy would be 147150 joules.

The complete question is:

A roller coaster car with a mass of 500 kg at the top of a hill that is 30 m high. Without friction, what would its kinetic energy be as it reached the bottom of the hill?

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