If the light goes through a single slit, the pattern that will appear on the target screen is: "A large bright band will appear directly across from the slit, that gets dimmer farther away from the center." The correct option is option A.
When light passes through a single slit, it diffracts and spreads out. This means that the light waves bend and interfere with each other as they pass through the slit, creating a pattern of bright and dark fringes on a screen behind the slit.
The central fringe is bright, with the maximum intensity of the light, and is surrounded by smaller and dimmer fringes on either side. These fringes are the result of constructive and destructive interference between the light waves passing through the slit.
The width of the slit plays an important role in determining the pattern of the fringes. If the slit is narrow, the diffraction of light will be more pronounced, resulting in a wider central fringe and smaller, more numerous side fringes. If the slit is wider, the central fringe will be narrower and the side fringes will be wider.
The distance between the slit and the screen also affects the pattern of the fringes. The closer the screen is to the slit, the wider the fringes will be, and the farther away the screen is from the slit, the narrower the fringes will be.
The diffraction of light through a single slit is an important phenomenon in physics and is used in various applications such as optical spectroscopy and the study of crystal structures.
Option B, "Two large bright bands will appear on the target screen, with less bright bands in between them," is incorrect. This pattern is actually the interference pattern that occurs when light passes through two parallel slits. When light passes through a single slit, the pattern is a central bright band with smaller, dimmer bands on either side.
Option C, "Two large bright bands appear very distant from each other on the target with nothing but dark bands in between them," is also incorrect. This pattern is the interference pattern that occurs when light passes through multiple slits, such as in a diffraction grating. When light passes through a single slit, the pattern is a central bright band with smaller, dimmer bands on either side.
Therefore, The correct answer is option A.
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When discussing you will be defending your thoughts of the following questions:
1. Children’s appetites and willingness to eat are strongly influenced by the mealtime environment. Identify and briefly discuss several features that can be used to create an atmosphere that encourages children to eat.
2. Review the My Plate food guide and suggest appropriate snack foods from each food group that would be appropriate for school-age children.
3. In what ways can adults help children learn to enjoy nutritious food and establish healthy eating habits?
To encourage children to eat, create a pleasant and distraction-free mealtime environment, serve a variety of visually appealing and small portions of favorite foods, involve them in meal planning and preparation, provide a relaxed and comfortable atmosphere, and avoid using food as a reward or punishment. Appropriate snack foods from each food group for school-age children can be selected from fruits, vegetables, grains, protein, and dairy. Adults can help children learn to enjoy nutritious food and establish healthy eating habits by modeling healthy eating behaviors, involving children in grocery shopping and meal planning, making meals enjoyable and fun, providing healthy food choices, and avoiding using food as a reward or punishment.
1. To create an atmosphere that encourages children to eat, several features can be used, such as:
A pleasant and inviting mealtime environment that is free of distractions such as television, mobile phones, or tablets.
Serve a variety of colorful, visually appealing foods in small portions, making sure to include favorite foods of the child.
Involve children in meal planning and preparation, giving them the opportunity to select foods and participate in simple meal preparation tasks.
Provide a relaxed and comfortable atmosphere by allowing enough time for meals and offering positive reinforcement for good eating behaviors.
Avoid using food as a reward or punishment and ensure that mealtimes are stress-free and enjoyable for children.
2. MyPlate is a visual representation of the five food groups that form a healthy and balanced diet. Appropriate snack foods from each food group for school-age children could include:
Fruits: apple slices, berries, bananas, or orange wedges.
Vegetables: carrot sticks, cherry tomatoes, cucumber slices, or celery sticks.
Grains: whole-grain crackers, granola bars, rice cakes, or air-popped popcorn.
Protein: hard-boiled eggs, cheese sticks, nut butter, or hummus.
Dairy: yogurt, milk, or cheese cubes.
3. Adults can help children learn to enjoy nutritious food and establish healthy eating habits by:
Modeling healthy eating behaviors and food choices themselves.
Encouraging children to try new foods and flavors, involving them in grocery shopping, and meal planning.
Making meals enjoyable and fun by creating a positive mealtime environment and involving children in meal preparation tasks.
Providing healthy food choices and limiting the availability of unhealthy options at home and school.
Offering regular mealtimes and avoiding using food as a reward or punishment.
Hence, Encourage children to eat by providing a pleasant and distraction-free mealtime environment, serving a variety of visually appealing and small portions of favorite foods, involving them in meal planning and preparation, providing a relaxed and comfortable environment, and avoiding using food as a reward or punishment. Fruits, vegetables, grains, protein, and dairy are examples of appropriate snack foods from each food group for school-age children. Adults can assist children in learning to enjoy nutritious food and develop healthy eating habits by modeling healthy eating behaviors, involving children in grocery shopping and meal planning, making meals enjoyable and fun, providing healthy food options, and avoiding using food as a reward or punishment.
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Margie, who weighs 573 N, is standing on a bathroom scale that weighs 40.0 N
With what magnitude force does the floor push up on the scale?
The floor will push up the scale with a combined force of 573 N and 40.0 N which is 613N
What is a force of reaction?A reaction force opposes an action force. Friction is the force produced by surface contact and adhesion while sliding. response forces and response moments are typically the outcomes of applied forces.
Take, for example, the interaction of a baseball bat and a baseball. The baseball pulls the bat to the left, while the bat pulls the ball to the right. These two forces acting on two distinct objects comprise the action-reaction force pair.
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Victoria ran around a circular field 3 times. If she ran a total
distance of 750 meters, what are the diameter and radius of
the field?
The diameter and the radius of the field that Victoria ran around would be = 80m and 40m respectively.
How to calculate the diameter and the radius of the field?The total distance covered by Victoria = 750meters
The number of time she ran around the field = 3
Therefore the circumference of the field = 750/3 = 250m
The formula for the circumference of circle = 2πr
That is ;
250 = 2×3.14 ×r
make r the subject of formula;
r = 250/ 6.28
r = 39.8 = 40 cm
Therefore the diameter = 2×40 = 80m
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An object that is 1.14 cm tall is placed 15.0 cm in front of a diverging lens of focal length 23.0 cm. How tall is the image (in centimeters, to three significant figures)?
The height of the image would be 9.64 cm.
We can use the thin lens equation to determine the position of the image:
1/f = 1/do - 1/di
where f is the focal length of the lens, do is the distance from the object to the lens, and di is the distance from the image to the lens. Rearranging this equation, we get:
1/di = 1/f - 1/d₀
Substituting the given values, we get:
1/di = 1/23 - 1/15
1/di = -0.007971
di = -125.3 cm
The negative sign for di indicates that the image is virtual (i.e., it appears on the same side of the lens as the object).
Now, we can use the magnification equation to determine the height of the image:
m = -di/d₀
where m is the magnification. Substituting the given values, we get:
m = -(-125.3 cm)/(15.0 cm)
m = 8.353
The negative sign for the magnification indicates that the image is inverted with respect to the object. The absolute value of the magnification tells us that the image is larger than the object by a factor of 8.353.
Therefore, the height of the image is:
hi = mho
hi = 8.3531.14 cm
hi = 9.64 cm
Rounding to three significant figures, the height of the image is 9.64 cm.
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Consider the group of three +2.4 nC point charges at three corners of a rectangle as shown in the figure. Point A is located at the 4th corner of the rectangle and point B is located 3 cm to the right of the top right charge. What is the potential difference, VB-VA, between points A and B?
The potential difference between points A and B is 2.95 volts.
To find the potential difference between points A and B, we need to first find the electric potential at each point.
The electric potential at a point due to a point charge can be calculated using the formula:
V = kq/r
where V is the electric potential, k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q is the charge, and r is the distance between the point charge and the point where we want to find the potential.
Using this formula, we can calculate the electric potential at point A due to each of the three charges:
V1 = kq/r1 = (9 x 10^9)(2.4 x 10^-9)/(3 x 10^-2) = 7.2 V
V2 = kq/r2 = (9 x 10^9)(2.4 x 10^-9)/(4 x 10^-2) = 5.4 V
V3 = kq/r3 = (9 x 10^9)(2.4 x 10^-9)/(3 x 10^-2) = 7.2 V
The total electric potential at point A due to the three charges is the sum of these individual potentials:
VA = V1 + V2 + V3 = 7.2 + 5.4 + 7.2 = 19.8 V
To find the electric potential at point B, we need to consider the electric potential due to the charge at the top right corner of the rectangle and the other two charges together.
The electric potential due to the charge at the top right corner can be calculated using the formula:
V4 = kq/r4 = (9 x 10^9)(2.4 x 10^-9)/(3 x 10^-2) = 7.2 V
To calculate the electric potential due to the other two charges at point B, we need to find the net electric field at point B due to these two charges. The electric field at point B due to each charge can be calculated using the formula:
E = kq/r^2
where E is the electric field, k is Coulomb's constant, q is the charge, and r is the distance between the point charge and the point where we want to find the field.
Using this formula, we can calculate the electric fields at point B due to the two charges:
E1 = kq/r1^2 = (9 x 10^9)(2.4 x 10^-9)/(4 x 10^-2)^2 = 4.5 x 10^4 N/C
E2 = kq/r2^2 = (9 x 10^9)(2.4 x 10^-9)/(3 x 10^-2)^2 = 7.4 x 10^4 N/C
Since these two charges are in opposite directions, we need to subtract their electric fields to find the net electric field at point B:
E_net = E2 - E1 = (7.4 x 10^4) - (4.5 x 10^4) = 2.9 x 10^4 N/C
The electric potential at point B due to the other two charges can be calculated using the formula:
V5 = E_net * d = (2.9 x 10^4) * (3 x 10^-2) = 870 V
The total electric potential at point B is the sum of the potentials due to the charge at the top right corner and the other two charges:
VB = V4 + V5 = 7.2 + 870 = 877.2 V
Using the formula for the potential difference between two points:
VB-VA = kq1q2/r1 - kq1q3/r2 + kq2q3/r3
where k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q1, q2, and q3 are the charges (in Coulombs) at the three corners, r1, r2, and r3 are the distances between the charges and point B, and the negative sign indicates that the potential at point A is higher than at point B.
Plugging in the given values, we have:
VB-VA = (9 x 10^9 Nm^2/C^2)(2.4 x 10^-9 C)(2.4 x 10^-9 C)/(0.03 m) - (9 x 10^9 Nm^2/C^2)(2.4 x 10^-9 C)(2.4 x 10^-9 C)/(0.04 m) + (9 x 10^9 Nm^2/C^2)(2.4 x 10^-9 C)(2.4 x 10^-9 C)/(0.03 m)
Simplifying, we get:
VB-VA = (9 x 10^9 Nm^2/C^2)(2.4 x 10^-9 C)(2.4 x 10^-9 C)(1/0.03 - 1/0.04 + 1/0.03)
VB-VA = 2.95 V
Therefore, the potential difference between points A and B is 2.95 volts.
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What is the Main impact that tsunamis have on humans? (Science)
Answer:
Explanation:
Tsunamis can have a devastating impact on human populations. The primary impact of a tsunami is the destruction of coastal communities and infrastructure. The powerful waves can inundate low-lying areas, destroying buildings, homes, and infrastructure such as roads, bridges, and ports. The destruction caused by tsunamis can result in the loss of life, injury, displacement, and economic disruption.
Tsunamis can also have secondary impacts on human populations, such as the disruption of essential services like water and electricity, which can exacerbate the already difficult living conditions in affected areas. The destruction of crops and fisheries can also have long-term economic impacts on affected communities.
It is essential to note that the impact of a tsunami can vary greatly depending on a range of factors, such as the size of the wave, the distance from the epicenter of the earthquake that caused the tsunami, and the preparedness and resilience of the affected communities. Therefore, it is crucial to have effective early warning systems and evacuation plans in place to minimize the impact of a tsunami on human populations.
Help! Photo Attached!!! WORTH: 60+ POINTS! Difficulty: Medium
The wavelength of the given wave is 4 meters and the amplitude of the wave is 2 meters.
Wavelength of the wave is the distance between two crests or two troughs and the amplitude is the maximum height of the wave.
From the given figure,
the distance between two crests or two trough,
wavelength = 4 × 1 meter
λ = 4 meter.
The maximum distance of the crest or trough,
Amplitude (a) = 2×1 meter
a = 2 meter
Hence, the wavelength of the wave is 4 meter and the amplitude of the wave is 2 meter.
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put the different features into the appropriate box, either Mars or Venus.
Venus is the 2nd planet of the solar system whereas the Mars is the fourth planet in the solar system. They are different from each other.
These two planets are terrestial planet and similar to earth. Venus is very close to the Sun and the Mars are away from the Sun with certain distance. These planets are the brightest of the others.
These planets have certain similarities like the presence of volcanoes, weathered surfaces and and atmosphere. Mars has two moons and the venus has no moon.
Mars and Venus also different from each other. Like Earth, these planets do not have the ability to produce magnetic field and hence they get affected by the solar winds. The atmosphere of Venus is thick and dense and the atmosphere of Mars is light and teneous.
The mars has ice and liquid water on its surface whereas in Venus, there is lack of water. The gravity of venus is twice that of mars. The rotational speed of the venus is lesser than that of mars. Venus is very hot as it present near to the Sun and mars is the comparatively cold.
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1 An indoor kart track hosts a racing competition. 3 A student measures the length of the track. State what other measurement should be made to determine the average speed of the kart.
The other measurement that should be made by the student in order to determine the average speed of the kart is time.
What is the average speed?The average speed of a moving object is the ratio of the total distance traveled and the total time taken.
Thus, to determine the average speed of the karts on the indoor track, the time it takes for the karts to complete one lap around the track should also be measured.
Once the length of the track has been determined by the student's measurement, a stopwatch or other timing device can be used to measure the time it takes for each kart to complete one lap.
The average speed can then be calculated by dividing the length of the track by the time it took for the kart to complete one lap.
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What would be the intensity of a sound wave produced by a 150 Watt speaker from a distance of 5.8 meters? (write your answer to two digits)
The intensity of the sound is determined as 0.36 W/m².
What is the intensity of the sound?
The intensity of a sound is defined as the amount of energy transmitted per unit area.
I = P/A
where;
I is the sound intensityA is the areaThe area is calculated as follows;
A = 4πr²
A = 4 x π x (5.8²)
A = 422.73 m²
The intensity of the sound is calculated as follows;
I = 150 W / 422.73
I = 0.36 W/m²
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The intensity of a sound wave can be calculated using the formula:
Intensity = Power / Area
In this case, we are given that the power of the speaker is 150 Watts. To calculate the area, we need to consider the distance at which the sound wave is measured. The area of a sphere can be calculated using the formula:
Area = 4πr^2
where r is the radius of the sphere. In this case, the distance from the speaker to the measuring point is given as 5.8 meters. So, the radius of the sphere is half of this distance, which is 2.9 meters.
Plugging these values into the formula, we get:
Area = 4π(2.9)^2 = 105.52 square meters
Now we can calculate the intensity:
Intensity = 150 / 105.52 = 1.42 Watts per square meter
Therefore, the intensity of the sound wave produced by the 150 Watt speaker from a distance of 5.8 meters is approximately 1.42 Watts per square meter.
Write your recommendation for the committee hearing Your speech should be at least 2 paragraphs long, and must:
Explain how personal freedoms will be effected if the law is passed Include the data from the state with a similar law • Discuss the cost of law enforcement ● Use the following vocabulary words: > Free-Market > Personal freedoms ➤ Government control > Recommendation ➤ Consumer rights (see and reference definition below)
Generally accepted basic consumer rights are: (1) Right to safety: protection from hazardous goods. (2) Right to be informed: availability of information required for weighing alternatives, and protection from false and misleading claims in advertising and labeling practices. (3) Right to choose: availability of competing goods and services that offer alternatives in terms of price, quality, service. (4) Right to be heard: assurance that government will take full cognizance of the concerns of consumers, and will act with sympathy and dispatch through statutes and simple and expeditious administrative procedures.
In order to safeguard the customer from unfair business practices, consumers have a legal right to information about the nature, purity, standard, and cost of the goods they purchase.
Before choosing or making a decision, the consumer should insist on acquiring all the facts about the goods or service.
Consumer protection laws by the Government do not restrict our freedom or paternalistically limit our options. They don't even prevent "free markets." Instead, they make sure we receive what we want when we go to the market and remove our anxiety of being taken advantage of by companies.
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Sam wants to upgrade his toy "golf ball launcher". Right now when he shoots the toy vertically,
the golf ball reaches a height of 1.75 m. A golf ball has a mass of 46 grams and the toy can
hold a spring that can be compressed 24 cm. Using a different spring, Sam believes he can
increase the distance it can be compressed to 32 cm. What spring constant will Sam need the
new spring to be if he wants it to launch the golf ball vertically to a height of 3.0 m?
A 70.0kg stuntman jumps off a bridge spanning a river from a height of 50m. Calculate the gravitational
potential energy of the stuntman.
The value of the gravitational potential energy can be obtained as 35kJ
What is the gravitational potential energy?Gravitational potential energy is the energy that an object has as a result of its position within a gravitational field.
Gravitational potential energy is most typically utilized for an object near the surface of the Earth when the gravitational acceleration may be considered to remain constant at around 9.8 m/s.
We can see that;
Gravitational potential energy = mgh
= 70 * 10 * 50
= 35kJ
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1. The wave speed of a wave through a medium is equal to the frequency times the wavelength. When the frequency changes, the wavelength must change to compensate. Why can't the velocity of the wave change?
a. The velocity must remain constant to keep the ratio of frequency and wavelength in check
b. The velocity of a mechanical wave is dependent on the medium
c. The wavelength is separate from the velocity, so it can change while the wavelength cannot
d. The velocity of the wave cannot change because it is set by the force that starts the oscillation
2. If a water wave has a velocity of 4.5 m/s and has a frequency of 25 Hz, what is the wavelength of the wave?
a. 0.80 m
b. 5.6 m
c. 0.35 m
d. 0.18 m
a. The velocity must remain constant to keep the ratio of frequency and wavelength in check. The wave speed is determined by the properties of the medium through which the wave travels, and is independent of the frequency and wavelength of the wave.
c. 0.35 m. The wavelength can be calculated using the formula: wavelength = wave speed / frequency. Plugging in the given values, we get wavelength = 4.5 m/s / 25 Hz = 0.18 m/Hz = 0.35 m (rounded to two decimal places).
11 A 2200 pound car travels at 25 mi/hr
The power of the car of weight 2200 pound is 11156.52 W.
What is power?
Power can be defined as the product of the force of a body and it velocity.
To calculate the power of the car, we use the formula below
Formula:
P = FV..................... Equation 1Where:
P = Power of the carV = Velocity of the carF = Weight/ Force of the carFrom the question,
Given:
F = 2200 pound = 997.9 kgV = 25 mi/hr = 11.18 m/sSubstitute these values into equation 1
P = 997.9×11.18P = 11156.52 WHence, the power is 11156.52 W.
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50 PINTS ANSWE CORRECT 3. Identify what elements are made in a Red Giant as it starts to die?
Answer: H=Hydrogen, He=Helium, C=Carbon, O=Oxygen, N=Nitrogen, Si=Silicon, Mg=Magnesium, Ne=Neon, Fe=Iron, Ni=Nickel
Explanation:
I believe this is the answer, but I'm not 100% sure.
An ideal gas, initially at a volume of 6 L and
pressure of 8 kPa, undergoes isothermal expansion until its volume is 8 L and its pressure
is 6 kPa.
1): Calculate the work done by the gas during
this process.
Answer in units of J.
2): Find the heat added to the gas during this
process.
Answer in units of J.
(1) The work done by the gas during this process is -13.71 J.
(2) The heat added to the gas during this process 13.71 J.
What is the work done by the gas?The work done by the gas is calculated as follows;
W = -nRT ln(V₂/V)
Where;
V₁ is the initial volume of the gasV₂ is the final volume of the gasn is the number of molesR is the ideal gas constantThe number of moles of gas is calculated as follows;
n = PV/RT
n = (8 kPa x 6 L) / (8.314 J/mol.K x 273 K)
n = 0.021 mol
The work done by the gas is calculated as follows;
W = -nRT ln(V₂/V)
W = -(0.021 x 8.314 x 273) ln(8/6)
W = -13.71 J
For isothermal process, the change in internal energy is zero.
So, the heat added to the gas is equal to the work done on the gas.
Q = -W = 13.71 J
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An ideal gas, initially at a volume of 6 L and
pressure of 8 kPa, undergoes isothermal expansion until its volume is 8 L and its pressure
is 6 kPa.
1): Calculate the work done by the gas during
this process.
Answer in units of J.
2): Find the heat added to the gas during this
process.
Answer in units of J.
The work done by the gas during the isothermal expansion is 421 J, and the heat added to the gas during the isothermal expansion is 421 J.
Isothermal expansion refers to a thermodynamic process in which a gas expands at a constant temperature. During this process, the gas absorbs heat from its surroundings, which is converted into work done by the gas as it expands. The pressure and volume of the gas change, but the temperature remains constant throughout the process.
1. We can use the ideal gas law and the formula for work done in isothermal expansion to solve this problem:
The work done by the gas during the isothermal expansion is given by:
W = nRT ln(V2/V1)
where W is the work done, n is the number of moles of gas, R is the gas constant, T is the temperature, V1 is the initial volume, and V2 is the final volume.
Since the process is isothermal, the temperature remains constant, so we can simplify the equation to:
W = nRT ln(V2/V1)
We can find n by using the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, and T is the temperature.
Solving for n, we get:
n = PV/RT
Substituting the given values, we get:
n = (8 kPa x 6 L) / (8.31 J/mol·K x 273 K)
n = 0.164 mol
Now we can calculate the work done:
W = nRT ln(V2/V1)
W = (0.164 mol)(8.31 J/mol·K)(273 K) ln(8 L / 6 L)
W = 421 J
Therefore, the work done by the gas during the isothermal expansion is 421 J.
2. Since the process is isothermal, the temperature remains constant and the change in internal energy is zero. So, the heat added to the gas is equal to the work done on the gas:
Q = W
Q = 421 J
So, the heat added to the gas during the isothermal expansion is 421 J.
Therefore, The gas expands 421 J of work during isothermal expansion, and the gas absorbs 421 J of heat during the process.
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20.
is a measure of its change over a single period..
a. Frequency
b. Amplitude
c. Hertz
Answer:
The Correct answer is A
frequency
V2 Problem 2.4 In the turbine of a gas turbine unit the gases flow through the turbine at 17kg/s and the power developed by the turbine is 14 000kW. The specific enthalpies of the gases at inlet and outlet are 1200 kJ/kg and 360 kJ/kg respectively, and the velocities of the gases at inlet and outlet are 60 m/s and 150 m/s respectively. Calculate the rate at which heat is rejected from the turbine. Find also the area of the inlet pipe given that the specific volume of the gases at inlet is 0.5m³/kg. Solution
The rate at which heat is rejected from the turbine is 14,000kW and the area of the inlet is 0.1417m²
Solution to Thermodynamic ProblemTo find the heat rejected from the turbine, we apply the First Law of Thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.
Mathematically,
ΔU = Q - W
where
ΔU = change in internal energy,
Q = heat added to the system,
W = work done by the system.
Assuming the gas turbine unit operates under steady-state conditions, the change in internal energy of the gases passing through the turbine is negligible. With that we can say, the heat rejected by the turbine is equal to the work done by the turbine:
Q = W = 14,000 kW
Therefore, the rate at which heat is rejected from the turbine is 14,000 kW.
To find the area of the inlet pipe, we can use the continuity equation:
m = ρ * A * V
but we are given:
m = mass flow rate = 17kg/s
V= velocity = 60m/s
v = specific volume = 0.5m³/kg
ρ = density = 1/v = 1/0.5 = 2kg/m
By making A the subject of the formula we have,
A = m / (ρ * V)
A = 17 / (2 * 60)
A = 0.1417 m²
Therefore, the area of the inlet pipe is approximately 0.1417 m².
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After an unfortunate accident occurred at a local warehouse, you were contracted to determine the cause. A jib crane collapsed and injured a worker. An image of this type of crane is shown in the figure. The horizontal steel beam had a mass of 86.80 kg per meter of length, and the tension in the cable was =12170 N. The crane was rated for a maximum load of 500 kg. The acceleration due to gravity is =9.810 m/s2.
B) If =6.160 m, =0.450 m, =1.500 m, and ℎ=1.980 m, what was the magnitude of L (the load on the crane) before the collapse?
C) What was the magnitude of force p at the attachment point P?
The load of the crane before collapse is 3942.8 N.
Mass per meter of length of the beam, m = 86.80 kg
Tension in the cable, T = 12170 N
Maximum load of the crane, M = 500 kg
Length of the beam, d = 6.16 m
Distance between the end point of beam and attachment end, s = 0.45m
Distance between the end point of the beam and point of inclination,
x = 1.5 m
Height between point P and top of attachment, h = 1.98 m
The moment about the point P,
[T(d - s) sinθ] - [W(L) (d - x)] - mg(d/2) = 0
So,
W(L) = [T(d - s) sinθ - mg(d/2)] / (d - x)
where θ is the angle made by the connecting line with the beam.
tanθ = h/(d - s)
tanθ = 1.98/(6.16 - 0.45)
tanθ = 0.3467
So, θ = 19.12°
Therefore, the load of the crane before collapse,
W(L) = [12170 (6.16 - 0.45)sin19.12°- 86.8 x 9.8(0.45/2) / (6.16 - 1.5)
W(L) = (18565.1 - 191.394) / 4.66
W(L) = 3942.8 N
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Consider the arrangement shown in the figure below where R = 8.50 Ω, ℓ = 1.10 m, and B = 2.00 T. A vertical bar and two parallel horizontal rails lie in the plane of the page, in a region of uniform magnetic field, vector B, pointing into the page. The parallel rails run from left to right, with one a distance ℓ above the other. The left ends of the rails are connected by a vertical wire containing a resistor R. The vertical bar lies across the rails to the right of the wire. Force vector Fapp points from the bar toward the right. HINT (a) At what constant speed (in m/s) should the bar be moved to produce a current of 1.70 A in the resistor? (b) What power (in W) is delivered to the resistor? W (c) What magnetic force (in N) is exerted on the moving bar? (Enter the magnitude.) N (d) What instantaneous power (in W) is delivered by the force Fapp on the moving bar?
The velocity of the conducting bar is 6.6 m/s.
Resistance, R = 8.5 Ω
Length of the bar, l = 1.1 m
Magnetic field, B = 2 T
Current in the bar, I = 1.7 A
The expression for motional emf is given by,
ε = B x l x v
where v is the velocity of the conducting bar.
a) Applying Ohm's law,
I x R = Blv
Therefore, v = IR/Bl
v = 1.7 x 8.5/(2 x 1.1)
v = 6.6 m/s.
b) Power delivered to the resistor,
P = (Blv)²/R = (2 x 1.1 x 6.6)²/8.5
P = 24.8 W
c) Force exerted on the bar,
F(ext) = B²l²v/R = (2 x 1.1)²x 6.6/8.5
F(ext) = 3.75 N
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inclined plane meaning
Answer:
inclined plane is another name of ramp
Explanation:
it is a machine which is used to lift a load L to the height h by applying an effort E along the distance l.
What is the final velocity of a car that accelerates from rest for 7 seconds at 2.5 m/s2?
Answer:
v=7.8
Explanation:
at rest v⁰ is zero
v²= v⁰t+1/2at²
=1/2×2.5×7²
=0.5×2.5×49
=7.8
What is the intensity of the sound waves produced by a trumpet at a distance of 3.2 m when the power
output of the trumpet is 0.20 W? Assume that the sound waves are spherical.
CAN SOMEONE HELP I REALLY NEED IT THANK YOU SO MUCH
The intensity of the sound wave produced by the trumpet at a distance of 3.2 m is 1.56×10⁻³ W/m²
How do i determine the intensity of the sound wave?From the question given above, the following data were obtained:
Distance from source (r) = 3.2 mPower output (P) = 0.20 WPi (π) = 3.14Intensity of sound wave (I) =?The intensity of the sound wave can be obtained as illustrated below:
Intensity (I) = P / 4πr²
Inputting the various parameters, we have:
I = 0.2 / (4 × 3.14 × 3.2²)
I = 0.2 / 128.6144
I = 1.56×10⁻³ W/m²
Thus, we can conclude from the above calculation that the intensity of the sound wave is 1.56×10⁻³ W/m²
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A regulation soccer ball has a mass of 0.45 KG in order to accelerate the ball at a rate of 8 m/s2 how much force would you need to apply when you kick the ball? Show FUN AL 
This is an exercise in Newton's second law, also known as the law of force or law of dynamics, which states that the net force acting on an object is equal to the object's mass multiplied by its acceleration. This law describes how force affects the motion of an object and is one of the fundamental laws of physics used to describe the motion of objects.
Net force refers to the sum of all forces acting on an object. If the net force is zero, the object is in equilibrium and is not moving. If the net force is greater than zero, the object accelerates in the direction of the net force. This acceleration depends on the mass of the object and the magnitude of the net force.
The mathematical formula that represents Newton's second law is F = m × a, where F represents the net force acting on the object, m represents the mass of the object, and a represents its acceleration. It is important to keep in mind that force, mass, and acceleration are vector magnitudes, that is, they have direction and magnitude.
Force is measured in newtons (N), mass in kilograms (kg), and acceleration in meters per second squared (m/s²). Therefore, the resulting unit of net force is newtons.
We solve the exercise:
To solve the force you will need the regulation soccer ball.
We apply the formula:
F = m × a
It tells us that the ball has a mass of 0.45 kg to accelerate the ball at a rate of 8 m/s².
We substitute and solve:
F = m × a
F = (0.45 kg)(8 m/s²)
F = 3.6 N
Therefore, to accelerate the ball at a rate of 8 m/s², a force of 3.6 N needs to be applied.
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Answer:
You would need to apply a force of 3.6 Newtons when you kick the ball in order to accelerate it at a rate of 8 m/s².
Explanation:
The force required to accelerate the soccer ball can be calculated using Newton's second law of motion, which states that the force (F) acting on an object is equal to its mass (m) times its acceleration (a):
[tex]\sf\qquad\dashrightarrow F = m * a[/tex]
In this case, the mass of the soccer ball is 0.45 kg and the desired acceleration is 8 m/s². Plugging these values into the equation above, we get:
[tex]\sf\qquad\dashrightarrow F = 0.45\: kg * 8\: m/s^2[/tex]
[tex]\sf\qquad\dashrightarrow F = \boxed{\bold{\:\:3.6\: N\:\:}}[/tex]
Therefore, you would need to apply a force of 3.6 Newtons when you kick the ball in order to accelerate it at a rate of 8 m/s².
A pendulum of mass 12 kg is released from rest at some height, as shown by
point A in the image below. At the bottom of its arc at point B, it is traveling at
a speed of 19 m/s. What is the approximate amount of energy that has been
lost due to friction and air resistance? (Recall that: g = 9.8 m/s²)
20 m
A35
B186
C78
D112
Answer:
B
Explanation:
We EXPECT all of the POTENTIAL energy (mgh) to be converted to KINETIC energy ( 1/2 mv^2) ...but some of the energy is lost due to air friction..... the difference between these two is what is lost
mgh = 1/2 mv^2 = energy lost
12 * 9.8 * 20 = 1/2 * 12 * 19^2 = 186 J lost
What is the style of Thomas Eakins's Max Schmitt in a Single Scull (1871)?
Naturalism
Pictorialism
Realism
Romanticism
The style of Thomas Eakins's Max Schmitt in a Single Scull (1871) is Realism.
The switch in the circuit of the figure has been in position "a" for a long time, so the capacitor is fully charged. The switch is changed to position "b" at t = 0. What is the current in the circuit immediately after the switch is closed? What is the current in the circuit 25 µs later?
The current in the circuit 25 µs later, given that the switch is changed to position "b" is 0.36 A
How do i determine the current in the circuit?From the question given above, the following data were obtained:
Voltage (V) = 9.0 VCapacitance (C) = 1.0 µF = 1×10⁻⁶ FResistance (R) = 10 Ω Time (t) = 25 µs = 25×10⁻⁶ sCurrent in circuit (I) =?The current in the circuit can be obtain as illustrated below:
Q = It
But,
Q = CV
Thus,
It = CV
I × 25×10⁻⁶ = 1×10⁻⁶ × 9
I × 25×10⁻⁶ = 9×10⁻⁶
Divide both sides by 25×10⁻⁶
I = 9×10⁻⁶ / 25×10⁻⁶
I = 0.36 A
Thus, from the above calculation, we can conclude that the current in the circuit is 0.36 A
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what might happen if the DMV closed and we let private companies offer their own driver licenses on the free market?
If the DMV closed and we let private companies offer their own driver licenses on the free market then the competition in the market will increase.
What would happen?If the DMV (Department of Motor Vehicles) were to close and private companies were allowed to offer their own driver licenses on the free market, then private companies are competing to offer the best driver's licenses, they may innovate, run more efficiently, and offer better customer service.
As a result, license application processes might become simpler, quicker, and perhaps even less expensive.
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