If it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution, what is the concentration, M, of the NaOH solution?

Answer:

There are 5 steps/rules of the ideal gases based on kinetic theory.

Explanation:

1. Particles in a gas are constant moving in random motion.

2. combined volume of the particles is negligible.

3. particles exert no forces on one another

4. any collisions between the particles are completely elastic

5. the average kinetic energy of particles is proportional to temperature in kelvins.

(I had help explaining steps from Sal Khan. I hope this helps! Have a great day!)

Answer:

Blank 1: 1

Blank 2: 2

Blank 3: 1

Blank 4: 1

Explanation:

Assuming this is to balance the equation, write out the amount of each element you have on the reactants side and on the products side

Reactants                                                   Products

Ca 1                                                             Ca 1

C 2                                                              C 2

H 2                                                              H 4

O 1                                                               O 2

Comparing the two, we can see that hydrogen and oxygen have different amounts between reactants and products. Therefore, we need to multiply by some number to get the two equal. If we multiply the reactants by 2 we will get the correct amount in the products. So we put a 2 in front of the H₂O to signify this.

The balanced chemical reaction is

CaC₂ + 2 H₂O --> C₂H₂ + Ca(OH)₂

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]  [tex]\text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles[/tex]

[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]  

According to stoichiometry :

1 mole of [tex]Cl_2[/tex] produce = 2 moles of [tex]NaCl[/tex]

Thus 7.04 moles of [tex]Cl_2[/tex] will produce=[tex]\frac{2}{1}\times 7.04=14.08moles[/tex]  of [tex]NaCl[/tex]

Mass of [tex]NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g[/tex]

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

Answer:

1 (NH4)2SO4 + Ba(NO3)2 → NH4NO3 + BaSO4

2 (NH4)2SO4 + Ba(NO3)2 → Ba(SO4) + (NH4)(NO3)

Explanation:

We convert the masses of our reactants to moles and use the stoichiometric coefficients to determine which one of our reactants will be limiting.

Dividing the mass of each reactant by its molar mass:

(10 g C2H6)(30.069 g/mol) = 0.3326 mol C2H6

(10 g O2)(31.999 g/mol) = 0.3125 mol O2.

Every 2 moles of C2H6 react with 7 moles of O2. So the number of moles of O2 needed to react completely with 0.3326 mol C2H6 would be (0.3326)(7/2) = 1.164 mol O2. That is far more than the number of moles of O2 that we are given: 0.3125 moles. Thus, O2 is our limiting reactant.

Since O2 is the limiting reactant, its quantity will determine how much of each product is formed. We are asked to find the number of grams (the mass) of H2O produced. The molar ratio between H2O and O2 per the balanced equation is 6:7. That is, for every 6 moles of H2O that is produced, 7 moles of O2 is used up (intuitively, then, the number of moles of H2O produced should be less than the number of moles of O2 consumed).

So, the number of moles of H2O produced would be (0.3125 mol O2)(6 mol H2O/7 mol O2) = 0.2679 mol H2O. We multiply by the molar mass of H2O to convert moles to mass: (0.2679 mol H2O)(18.0153 g/mol) = 4.826 g H2O.

Given 10 grams of C2H6 and 10 grams of O2, 4.826 g of H2O are produced.

Answer:

.11 mol

Explanation:

Convert mmHg to atms by dividing by 760. Then multiply 6.3 by the atms and divide by .08206*(273+28) to get mol

Answer:

p wave

Explanation:

The P wave is designated the primary preliminary wave because it is the first to arrive at a seismic station after an earthquake. It travels at a speed usually less than 6 kilometers per second in the Earth's crust and jumps to 13 kilometers per second through the core.

Answer:

0.0308 mol

Explanation:

In order to convert from grams of any given substance to moles, we need to use its molar mass:

Now we calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g:

Answer:

(-1,0)

Explanation:

Answer:

better mileage on cars, took lead out of paint, smaller packaging like for delivery and store products, EPA laws updating

Answer:

Reducing pollution from transportation sources has led to healthier air for Americans. In cities, smog has been visibly reduced.

Explanation:

i hope this helped

Answer:

Final Temp = 23.92°C

Explanation:

ΔH(total) = (m·c·ΔT)ice + (m·ΔH(f))melt'g + (m·c·ΔT)water

2182.5j = (5g)(2.092j/g·°C)(1°C) + (5g)(334.56j/g) + (5g)(4.184j/g·°C)(ΔT)

(2182.5 - 10.46 - 1672.8)j = 20.92j/°C·ΔT

ΔT = (2182.5 - 10.46 - 1672.8)j / 20.92j/°C = 23.92°C

Since the melting ice starts and ends at 0°C and is then warmed to 23.92°C then the temperature change is also the final temp of the water based upon given energy input values.

Answer:

To separate the components, a water wash may be attempted to remove benzoic acid, but benzoic acid is not particularly water-soluble due to its nonpolar aromatic ring, and only small amounts would be extracted into the aqueous layer

The method that can be used to separate Benzoic acid and potassium carbonate is :  The application of water wash separation method

Benzoic acid is slightly soluble in cold water but becomes more soluble as the temperature of water is increased. Water wash separation method is a methodology used for the selective removal of unwanted compounds in a mixture.

The separation of benzoic acid and potassium carbonate is based on the solubility differences between Benzoic acid and potassium carbonate when dissolved in a solvent ( water ) therefore the water wash separation method is the most effective method.

Hence we can conclude that The method that can be used to separate Benzoic acid and potassium carbonate is :  The application of water wash separation method.

Learn more about separation methods :  https://brainly.com/question/735172

Answer:

the youngest crust of the ocean floor can be found near the seafloor