Select all expressions that equal −7−(−12) .
A
7+(−12)
B
−7+(−12)
C
−7+12
D
7+12
Answer:
C, -7+12
Step-by-step explanation:
-7--12= 5
-7--12 can also be -7+12
Answer:
The answer is c
Step-by-step explanation:
-7-(-12) = 5
In circle M secants overline PAMD and overline PBC are drawn from point P such that m arc BM=100 and m arc CD=62. Which of the following is the measure of angle P?
1) 19
2) 22
3) 34
4) 40
find the diameter of a circle with the circumference of 10cm
Carter needs to wrap seven presents. He lays the ribbon out flat and says that I'll have just enough pieces if I make six equally spaced cuts, I can use one piece for each package. And I won't have any pieces left over. Does he have enough pieces to wrap all the presents?
Answer:
Yes, he has enough pieces to wrap the present
Step-by-step explanation:
Given
[tex]Presents = 7[/tex]
[tex]Cuts = 6[/tex]
Required
Is there enough pieces to wrap all presents
As a general rule;
When a piece is cut in 1 place, you get 2 pieces
When a piece is cut in 2 places, you get 3 pieces
When a piece is cut in 3 place, you get 4 pieces
This implies that:
n cuts gives n + 1 pieces
i.e.
[tex]n \to n + 1[/tex]
So, we have:
[tex]6\ cuts \to (6 + 1) pieces[/tex]
[tex]6\ cuts \to 7\ pieces[/tex]
Hence, there are enough pieces.
?????????!!?????????????!!!????
Answer:
a
Step-by-step explanation:
Answer:
a
Step-by-step explanation:
An Australian Wallaby walked 5 miles to the coast in 3 and 3/4 hours. What was the wallabys speed in miles per hour?
Answer:
1 1/3 mph
Step-by-step explanation:
distance = rate x time
5 = 3.75r
5/3.75 = r
r = 1 1/3 mph
Which of the following set of angles is possible for a triangle
Answer:
2. Isosceles
4. 25, 65, 90
Step-by-step explanation:
Isosceles triangles have two equivalent sides
All the interior angles of triangles always add up to 180 degrees
If CD represents 100%, what is the length of a line segment that is 25%? Explain.
Answer:
(1/4)CD
Step-by-step explanation:
The length of a segment that represents 25% will be 1/4 as long as the segment representing 100%.
25% is 1/4 of 100%
25% = 1/4 = 0.25
The roof of an airplane hanger is a parabola with the focus located 32 feet from the vertex. If the building is 200 feet wide and the side walls are 25 feet tall, find the maximum height of the hangar.
Answer:
[tex]h_m=103.125ft[/tex]
Step-by-step explanation:
From the question we are told that:
Focus [tex]F=32ft[/tex]
Width of building [tex]W=200ft[/tex]
Height[tex]h=25[/tex]
Generally the equation for the Parabola is mathematically given by
[tex]y^2=4ax[/tex]
[tex]y^2=128x[/tex]
[tex]y^2=128b^2[/tex]
[tex]y=\pm8\sqrt{2b}[/tex]
[tex]b=\frac{25}{2\sqrt{2}}[/tex]
Therefore
[tex]x=b^2[/tex]
[tex]b^2=\frac{625}{8}[/tex]
Generally the Generally the equation for momentum is mathematically given by mathematically given by
[tex]h_m=x+h\\h_m=\frac{625}{8}+25[/tex]
[tex]h_m=\frac{825}{8}ft[/tex]
[tex]h_m=103.125ft[/tex]
Which answer choice correctly names the circle?
Answer:
Step-by-step explanation:
Is their suppposed to be a pic
A quadratic equation that has x-intercepts of (-2,0) and (8,0), a stretch of 3 and a vertex is a minimum. Find the equation of the parabola
Answer:
c) The standard form of the quadratic equation, y = a·x² + b·x + c
The standard form of the quadratic equation is y = 3·x² - 18·x - 48.
Step-by-step explanation:
(6. solve for x )
225 multiplyed by 1/3 = x
Answer:
Step-by-step explanation:
225*1/3=x
225/3=x
75=x
The diagram shows nine identical squares inside a rectangle.
The length of the rectangle is 18cm
Work out the width of the rectangle
Answer:
18 cm
Step-by-step explanation:
Let X represent a square
For it to be a rectangle, needs to be:
X X X
X X X
X X X
(It's a giant square made of squares)
This works since a square is a rectangle, but a rectangle isn't always a square. No other arrangement of the squares lead to a rectangle.
For Example:
X X X X
X X X X X
It doesn't work because there is an odd number of squares, and only would work if it was a multiple of 3,5,7 etc.. and 3 is the only number that fits.
So if the length is 18cm, the width is also 18cm.
Find the value of x.
6x
2x
11.25
0 16.25
58
032
Answer:
x = 11.25
Step-by-step explanation:
The sum of the angles is 90 degrees since it is a right angle
6x+2x = 90
8x = 90
Divide each side by 8
8x/8 =90/8
x =11.25
write answer in equation y=mx+b
Answer:
y = 50x + 150
Step-by-step explanation:
The y-intercept is 150. b = 150
The slope is found using two points such as (2014, 450) and (2010, 250)
m = (450 - 250)/(2014 - 2010) = 200/4 = 50
y = mx + b
y = 50x + 150
Find area of the composite figure..
Answer:
627square inches
Step-by-step explanation:
Area of the composite figure.. = area of triangle + area of parallelogram
Since the triangle is an equilateral triangle;
Area of the triangle = r²sintheta
Area of the triangle = 18²sin60
Area of the triangle = 324sin60
Area of the triangle = 324(0.8860)
Area of the triangle = 280.584 square in
Area of the triangle = 281 square inches
Area of parallelogram = absintheta
Area of parallelogram = 20(20)sin60
Area of parallelogram = 400(0.8660)
Area of parallelogram = 346.4square inches
Area of parallelogram = 346 square inches
Area of the figure = 346 + 281
Area of the figure = 627square inches
Of the 585 people that live in Benton, 187 live within two miles of the post office. Use mental math to find how many people live farther than two miles from the post office.
It clearly states to use mental math not brainly, sorry bro can't do anything for you
3/4 + (1/3 ÷ 1/6) - (-1/2)
Please give answer as a fraction
Answer: 13/4
Step-by-step explanation: it was 3.25 and that as a fraction is 13/4
3/4 + ( 1/3 × 6 ) + 1/2 =
3/4 + 2/4 + ( 2 ) =
3 + 2/4 + 8/4 =
5/4 + 8/4 =
5 + 8/4 =
13/4
DEFINATION OF HABIT IN 50 WORLDS?
Answer:
Something you do frequently or on a regular basis is known as a habit.
When he gets nervous, he has a cute habit of licking his lips. [includes]
...an investigation into the eating habits of people in the United Kingdom.
Step-by-step explanation:
Click here to log into Newsela
Once you are logged in you need to find an article related to Math to read. If you click the search button and type in Math you will find hundreds of articles to choose from.
The name of the article I chose is ____ and the author is ______.
Please write one paragraph in response to the article. In your paragraph summarize the article and specifically explain the connection it has to math.
Contain at least 4 complete sentences.
Have sentences that start with capital letters and end with punctuation.
Be written in your own words.
Include a specific quote or evidence from the article to show the math connection.
Answer:
n geometry, the notion of a connection makes precise the idea of transporting data[further explanation needed] along a curve or family of curves in a parallel and consistent manner. There are various kinds of connections in modern geometry, depending on what sort of data one wants to transport. For instance, an affine connection, the most elementary type of connection, gives a means for parallel transport of tangent vectors on a manifold from one point to another along a curve. An affine connection is typically given in the form of a covariant derivative, which gives a means for taking directional derivatives of vector fields, measuring the deviation of a vector field from being parallel in a given direction.
Connections are of central importance in modern geometry in large part because they allow a comparison between the local geometry at one point and the local geometry at another point. Differential geometry embraces several variations on the connection theme, which fall into two major groups: the infinitesimal and the local theory. The local theory concerns itself primarily with notions of parallel transport and holonomy. The infinitesimal theory concerns itself with the differentiation of geometric data. Thus a covariant derivative is a way of specifying a derivative of a vector field along another vector field on a manifold. A Cartan connection is a way of formulating some aspects of connection theory using differential forms and Lie groups. An Ehresmann connection is a connection in a fibre bundle or a principal bundle by specifying the allowed directions of motion of the field. A Koszul connection is a connection which defines directional derivative for sections of a vector bundle more general than the tangent bundle.
Connections also lead to convenient formulations of geometric invariants, such as the curvature (see also curvature tensor and curvature form), and torsion tensor.
Step-by-step explanation:
Answer:
n geometry, the notion of a connection makes precise the idea of transporting data[further explanation needed] along a curve or family of curves in a parallel and consistent manner. There are various kinds of connections in modern geometry, depending on what sort of data one wants to transport. For instance, an affine connection, the most elementary type of connection, gives a means for parallel transport of tangent vectors on a manifold from one point to another along a curve. An affine connection is typically given in the form of a covariant derivative, which gives a means for taking directional derivatives of vector fields, measuring the deviation of a vector field from being parallel in a given direction.
Connections are of central importance in modern geometry in large part because they allow a comparison between the local geometry at one point and the local geometry at another point. Differential geometry embraces several variations on the connection theme, which fall into two major groups: the infinitesimal and the local theory. The local theory concerns itself primarily with notions of parallel transport and holonomy. The infinitesimal theory concerns itself with the differentiation of geometric data. Thus a covariant derivative is a way of specifying a derivative of a vector field along another vector field on a manifold. A Cartan connection is a way of formulating some aspects of connection theory using differential forms and Lie groups. An Ehresmann connection is a connection in a fibre bundle or a principal bundle by specifying the allowed directions of motion of the field. A Koszul connection is a connection which defines directional derivative for sections of a vector bundle more general than the tangent bundle.
Connections also lead to convenient formulations of geometric invariants, such as the curvature (see also curvature tensor and curvature form), and torsion tensor.
Step-by-step explanation:
Awnser this please and thank you if u don’t not give me bad awnsers I will give u a brainliest
Answer:
slope = 20
Step-by-step explanation:
Calculate the slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (10, 200) ← 2 points on the line
m = [tex]\frac{200-0}{10-0}[/tex] = [tex]\frac{200}{10}[/tex] = 20
Question 8 (1 point)
At your high school, you are trying to determine the probability that a student takes
Spanish given that the student is taking Marketing. Which of the following
statements explains how to BEST gather the data to determine this probability?
Determine the number of students taking Marketing, the number of students
taking Spanish, the total number of students, and the distribution of students.
Survey students taking Marketing to determine how many also take Spanish.
Survey students taking Spanish to determine how many also take Marketing.
Determine the number of students taking Marketing, the number of students
taking Spanish, and the total number of students.
what is the pattern rule for 1. 25, 1, 0.75, 0.50,0.25
Answer:
-0.25n + 1
Step-by-step explanation:
Difference between all numbers: -0.25
Hence,
[tex]t_n = -0.25n + 1[/tex]
Feel free to mark it as brainliest :D
[tex]2h-3\ \textgreater \ 15[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\textsf{2h - 3 }\mathsf{>}\large\textsf{ 15}[/tex]
[tex]\large\text{ADD 3 to BOTH SIDES}[/tex]
[tex]\large\textsf{2h - 3 + 3 }>\large\textsf{ 15 + 3}[/tex]
[tex]\large\text{CANCEL out: \textsf{-3 + 3} because that gives you 0}[/tex]
[tex]\large\text{KEEP: \textsf{15 + 3} because it helps you solve for your h-value}[/tex]
[tex]\large\textsf{15 + 3 = \boxed{\large\textsf{\bf 18}}}[/tex]
[tex]\large\text{NEW EQUATION: \textsf{2h} }\mathsf{>}\large\textsf{ 18}[/tex]
[tex]\large\text{DIVIDE 2 to BOTH SIDES}[/tex]
[tex]\mathsf{\dfrac{2h}{2}>\dfrac{18}{2}}[/tex]
[tex]\large\text{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\text{ because it gives you 1}[/tex]
[tex]\large\text{KEEP: }\mathsf{\dfrac{18}{2}}\large\text{ because it gives you your h-value is being compared to}[/tex]
[tex]\large\text{NEW EQUATION: }\mathsf{h > \dfrac{18}{2}}[/tex]
[tex]\mathsf{\dfrac{18}{2}}[/tex]
[tex]\mathsf{= 18\div 2}[/tex]
[tex]=\boxed{\mathsf{\large\textsf {\bf 9}}}[/tex]
[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf h > 9}}}\huge\checkmark\\\\\boxed{\boxed{\rm \bf It\ it\ an\ O P E N E D\ circle\ shaded}}\\\boxed{\boxed{\rm \bf to\ the\ right\ starting\ at\ point\ 9}}\checkmark[/tex]
[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]
Let's solve![tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]
Add both sides by 3.[tex] \quad \quad \quad \quad\tt{2h - 3 + 3 > 15 + 3}[/tex]
[tex]\quad \quad \quad \quad\tt{2h \: \: \cancel{ \color{red}- 3 + 3} \: > 15 + 3}[/tex]
[tex]\quad \quad \quad \quad\tt{2h > 18}[/tex]
Divide it by 2.[tex]\quad \quad \quad \quad\tt{ \frac{2h}{2} > \frac{18}{2} }[/tex]
[tex]\quad \quad \quad \quad\tt{ \frac{ \cancel{ \color{red}2}h}{ \cancel{ \color{red}2}} > \frac{18}{2} }[/tex]
[tex]\quad \quad \quad \quad\tt{ h > \frac{18}{2} }[/tex]
[tex]\quad \quad \quad \quad\tt{ h > 9}[/tex]
Hence the answer is:[tex]\quad \quad \quad \quad \boxed{\tt { \color{green}h > 9}}[/tex]
________
#LetsStudy
What is the approximate measure of the length of the tennis court, x? A. 49.9 ft B. 72.0 ft C. 93.1 ft D. 78.0 ft
A ladder leans against the wall at the point B
(window end) from a ground level and makes an
angle horizontally at 52º. The height of ladder is 15
m. When the same ladder leans above the point B
at point A (window start) and makes an angle of 85°
horizontally. The distance between point A and
point B is
Answer:
..........
Step-by-step explanation:
Given:
The height of the ladder = 15 m
When the ladder leans at point B from the ground level, then it makes an angle of 52° with the horizontal
When the ladder leans at point A from the ground level, then it makes an angle of 85° with the horizontal
To find:
The distance between point A and point B is?
Solution:
To solve the above-given problem, we will use the following trigonometric ratio of a triangle:
Referring to the figure attached below, we will assume,
BD = AD = 15 m = height of the ladder
∠BDC = 52° = angle of elevation to the foot of the window
∠ADC = 85° = angle of elevation to the top of the window
Now,
In ΔBCD, we have
Opposite side = BC
Hypotenuse = BD = 15 m
θ = 52°
∴
and
In ΔACD, we have
Opposite side = AC
Hypotenuse = AD = 15 m
θ = 85°
∴
∴ The height of the window, AB = AC - BC = 14.94 m - 11.82 m = 3.12 m
Thus, the distance between point A and point B is 3.12 m.
-----------------------------------------------------------------------------------------------
Also View:
A ladder leaning against a wall makes an angle of 60 degree with the horizontal If the foot of the ladder is 2.5 m away from the wall , find the length of the ladder.
Write down the percentage multiplier used to decrease an amount by 45%
A tire has a diameter of 42 inches. How far along the ground does the tire travel if it rolls and makes 5 revolutions? Use 3.14 as an approximation for
Answer:
659.4 inches
Step-by-step explanation:
C = 2*3.14*21
C = 131.88
131.88*5 = 659.4 inches
13. Jack has to make at least $140 per week mowing lawns. He makes $20 per lawn. At least
how many lawns does he need to mow?
Answer:
7
Step-by-step explanation:
you divide 140 by 20 & it gives you 7 i hope this helps ..
En una compañía se realiza una encuesta a 200 personas, se encontró la siguiente distribución, en el uso de máquinas eléctricas, mecánicas y computadoras: Eléctricas 110, mecánicas 50, computadoras 60. Mecánicas y computadoras 25, eléctricas y computadoras 35, eléctricas y mecánicas 40. Las tres 20 y 60 nada. A) Encuentre el número de personas que o usan computadora. B) Que usen una maquina eléctrica pero no computadora. C) Que usen solo un equipo. D) Que usen mecánica y eléctrica pero no computadora. E) Cuantos no tienen ni maquina eléctrica ni mecánica.
Answer:
A) 140
B) 75
C) 80
D) 20
E) 80
Step-by-step explanation:
Para resolver este problema debemos construir un diabrama de Venn y llenarlo según los datos que se nos brindan.
Comenzamos nombrando cada círculo:
E= personas que usan máquinas eléctricas
M= personas que usan máquinas mecánicas
C = personas que usan computadoras.
- Luego llenamos el área central con un 20, el cual representa las personas que usan los 3 tipos de maquinas.
- En la parte exterior del diagrama de Venn colocamos un 60 por las personas que no usan ninguna de las máquinas.
- En la intersección entre M y C restamos:
25-20=5
Entonces colocamos este 5 en esa región.
- En la intersección entre E y C restamos:
35-20=15
Entonces colocamos este 15 en esa región.
- En la intersección entre E y M restamos:
40-20=20
Entonces colocamos este 20 en esa región.
- En la región de E restamos:
110-20-20-15=55
Entonces colocamos este 55 en esa región.
- En la región de M restamos:
50-20-20-5=5
Entonces colocamos este 5 en esa región.
- En la región de C restamos:
60-15-20-5=20
Entonces colocamos este 20 en esa región.
Y obtenemos el diagrama de Venn que representa esta encuesta (Ver figura adjunta)
Y ahora ya lo podemos usar para responder a las preguntas:
A) Número de personas que no usan computadora. Sumamos los números fuera del círculo C:
55+20+5+60=140
B) Número de personas que usan una máquina eléctrica pero no computadora: Sumamos los números dentro del círculo E con excepción de los números compartidos por el círculo C y obtenemos:
55+20=75
C) Número de personas que usan solo un equipo: Sumamos los números no compartidos en los círculos E, M y C
55+20+5=80
D) Número de personas que usan máquina mecánica y eléctrica pero no computadora: Usamos el número compartido entre E y M que no son compartidos con C
20
E) Sumamos el número que se encuentra solo en C y los que están afuera del diagrama:
20´60=80