if c= the number of cars in a parking lot which algebaraic expression represents the phrase below the number of cars increased by 9

Answer:

143º

Step-by-step explanation:

You want to find m<HBD

which is m<HBA minus m<BAD

180º minus 37º equals 143º

m<HBD is equal to 143º

Please give me brainliest

Can anyone who sees this answer my latest question?

I need help with it very soon.

Answer:

143 !

Step-by-step explanation:

Step-by-step explanation:

jannsonparker is correct and should be marked brainliest.

this is just an illustration for you

Answer:

The correct answer is 5 2/15

Step-by-step explanation:

Since the numerators on both numbers are opposite, you have to go through an equation to make them equal.

4/5 and 1/3 don't have the same numerator. Because of this, you have to find the least common multiple.

5, 10, 15

3, 6, 9, 12, 15

Now that we found said number, we have to multiply the denominators so they match as well. How we do that is by multiplying the number by how many times the numerator has been multiplied to.

Since 5 had to be multiplied by 3 to get to 15, you would multiply 4 by three, giving you 12/15. Same goes with the other fraction, 3 times 5 got us 15, so we would multiply 1 by 5, giving us 5/15.

Now it's as simple as adding. 12/15 + 5/15 = 17/15, which will make 1 2/15. Add that to the whole numbers you have and you will get 5 2/15. (Note: You cannot simplify 2/15, so you leave it as is)

Answer:

So, if we say Jiri's age is j (we can pick any letter), then Pamela's age is 2j, right?

j + 2j = 72

j is the same as 1j, but we wouldn't call you 1James, just James.

3j = 72

To isolate j, we do the opposite operation to both sides.

3j/3 = 72/3

j/j = 1, so that cancels out. 72/3 = 24.

j = 24

Jiri is 24 years old.

Answer:

Jiri is 7 years old.

explanation:

3j + j = 28

4j = 28

4j/4 = 28/4

j = 7

this can be proven:

Pamela's age: 3×7 = 21

the sum of their ages = 28

7 + 21 = 28

Answer:

Step-by-step explanation:

Answer:

An essay is, generally, a piece of writing that gives the author's own argument, but the definition is vague, overlapping with those of a letter, a paper, an article, a pamphlet, and a short story. Essays have traditionally been sub-classified as formal and informal. Formal essays are characterized by "serious purpose, dignity, logical organization, length," whereas the informal essay is characterized by "the personal element (self-revelation, individual tastes and experiences, confidential manner), humor, graceful style, rambling structure, unconventionality or novelty of theme," etc.[1]

Essays are commonly used as literary criticism, political manifestos, learned arguments, observations of daily life, recollections, and reflections of the author. Almost all modern essays are written in prose, but works in verse have been dubbed essays (e.g., Alexander Pope's An Essay on Criticism and An Essay on Man). While brevity usually defines an essay, voluminous works like John Locke's An Essay Concerning Human Understanding and Thomas Malthus's An Essay on the Principle of Population are counterexamples.

In some countries (e.g., the United States and Canada), essays have become a major part of formal education. Secondary students are taught structured essay formats to improve their writing skills; admission essays are often used by universities in selecting applicants, and in the humanities and social sciences essays are often used as a way of assessing the performance of students during final exams.

The concept of an "essay" has been extended to other media beyond writing. A film essay is a movie that often incorporates documentary filmmaking styles and focuses more on the evolution of a theme or idea. A photographic essay covers a topic with a linked series of photographs that may have accompanying text or captions.

Contents

1 Definitions

2 History

2.1 Montaigne

2.2 Europe

2.3 Japan

2.4 China

3 Forms and styles

3.1 Cause and effect

3.2 Classification and division

3.3 Compare and contrast

3.4 Expository

3.5 Descriptive

3.6 Dialectic

3.7 Exemplification

3.8 Familiar

3.9 History (thesis)

3.10 Narrative

3.11 Argumentative

3.12 Process

3.13 Economic

3.14 Reflective

3.15 Other logical structures

4 Academic

5 Magazine or newspaper

6 Employment

7 Non-literary types

7.1 Film

7.2 Music

7.3 Photography

7.4 Visual arts

8 See also

9 References

10 Further reading

11 External links

Step-by-step explanation:

Answer:

A) x = 0 and x = 3π∕4

Step-by-step explanation:

cot 0° = oo (infinite)

4/3 x = 0

=> x = 0

cot 180° = oo (infinite)

4/3 x= 180

x = 3/4 × 180

= 135°

= ¾π

The required speed of the driver is 33.4 mph.

To determine how fast was a driver going and if it left skid marks that were 63 feet long on wet concrete. (The coefficient of friction is 0.97)?

Speed is the ratio of distance traveled to time taken to travel that distance.

Friction is defined as resistance force from one surface to the other between two solid materials caused by reciprocal movement is called friction. And the force applied is called friction force.

Since from given
f = 0.97
left skid marks that were 63 feet long on wet concrete.
d = 63 feets
g = 9.8

V = √( 2g * F * D )
V = √(2 * 9.8 * 0.97 * 63 )
V = 33.4mph

Thus, The required speed of the driver is 33.4 mph.

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Answer:

2 1/6 miles

Step-by-step explanation:

1 1/2 miles + 2/3 miles = 2 1/6 miles

Answer:

0.601 = 60.1% probability that the weight of a bag will be less than the maximum allowable weight of 50 pounds

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 49.02 pounds and a standard deviation of 3.83 pounds.

This means that [tex]\mu = 49.02, \sigma = 3.83[/tex]

What is the probability that the weight of a bag will be less than the maximum allowable weight of 50 pounds?

This is the p-value of Z when X = 50. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{50 - 49.02}{3.83}[/tex]

[tex]Z = 0.256[/tex]

[tex]Z = 0.256[/tex] has a p-value of 0.601.

0.601 = 60.1% probability that the weight of a bag will be less than the maximum allowable weight of 50 pounds

Answer: if we were to say that the population was 50% male and 50% female, than 21% of the males would play the guitar and 15% of the females would also play the guitar, if it is talking about the population in geteral, than 21% of men and 15% of female play the guitar, but the remaining 64% of people don't play the guitar.... i don't think this is the answer, so if you chose my first case, the answer would be 0.105 for males or 10.5 % or percent of males play guitar in the state

Step-by-step explanation: chose one of my cases

Answer:0.21

Step-by-step explanation:

PLATO

Answer:Hence.the answer is 14.

Step-by-step explanation:

Got it right on my test

Answer:

Solution given;

we have

Cos 30=adjacent/hypotenuse

Cos 30=12/x

x=12/cos30

x=8√3

and

Sin 30=opposite/hypotenuse

Sin30=y/x

y=sin30*x

y=sin30*8√3

y=4√3

Option D.

x=8√3 and y=4√3 is a required answer.

Answer:

Supplementary is your answer

Answer:

-8x - 5 = 4x + 2

Answer:

Step-by-step explanation:

20% = 20/100 = 0.2

The amount you need to pay for a T shirt is

Cost = original amount(100% - 20%)

Original amount = 18

100% - 20% = 80%

80% = 80 / 100 = 0.8

What this means is that you will pay 80% of  the original cost.

Cost = 18*0.8

Cost = $14.40

Part B

Cost = 0.8 * x

Part C

Selling price = 0.8*Original Cost

Selling price = 18

18 = 0.8 * x

18/0.8 = x

x = 22.5

The original price was $22.50

Answer:

[tex](a)\ P(x = 0) = 0.2725[/tex]

[tex](b)\ P(x \ge 1) =0.7275[/tex]

[tex](c)\ P(x \le 2) = 0.8948[/tex]

Step-by-step explanation:

Given

[tex]n = 8[/tex] --- 8 friends

[tex]p = 15\%[/tex] --- proportion that one-time fling

This question is an illustration of binomial probability, and it is represented as:

[tex]P(X = x) = ^nC_x* p^x * (1 - p)^{n-x}[/tex]

Solving (a): P(x = 0) --- None has done one time fling

[tex]P(x = 0) = ^8C_0* (15\%)^0 * (1 - 15\%)^{8-0}[/tex]

[tex]P(x = 0) = 1* 1 * (1 - 0.15)^{8}[/tex]

[tex]P(x = 0) = 0.85^8[/tex]

[tex]P(x = 0) = 0.2725[/tex]

Solving (b): [tex]P(x \ge 1)[/tex]

To do this, we make use of compliment rule:

[tex]P(x = 0) + P(x \ge 1) =1[/tex]

Rewrite as:

[tex]P(x \ge 1) =1 - P(x = 0)[/tex]

[tex]P(x \ge 1) =1 - 0.2725[/tex]

[tex]P(x \ge 1) =0.7275[/tex]

Solving (c): [tex]P(x\le 2)[/tex]--- Not more than 2 has one time fling

This is calculated as:

[tex]P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)[/tex]

We have:

[tex]P(x = 0) = 0.2725[/tex]

[tex]P(x = 1) = ^8C_1* (15\%)^1 * (1 - 15\%)^{8-1}[/tex]

[tex]P(x = 1) = 8* (0.15) * (1 - 0.15)^7[/tex]

[tex]P(x = 1) = 0.3847[/tex]

[tex]P(x = 2) = ^8C_2* (15\%)^2 * (1 - 15\%)^{8-2}[/tex]

[tex]P(x = 2) = 28* (0.15)^2 * (1-0.15)^6[/tex]

[tex]P(x = 2) = 0.2376[/tex]

So:

[tex]P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)[/tex]

[tex]P(x \le 2) = 0.2725 + 0.3847 + 0.2376[/tex]

[tex]P(x \le 2) = 0.8948[/tex]

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{f(x) = 2\dfrac{1}{2}-3\dfrac{1}{3}}[/tex]

[tex]\rightarrow\mathsf{y = 2\dfrac{1}{2}- 3\dfrac{1}{3}}[/tex]

[tex]\rightarrow\mathsf{y = \dfrac{5}{2}- \dfrac{10}{3}}[/tex]

[tex]\rightarrow\mathsf{y =( \dfrac{5}{2}\times\dfrac{3}{3}) - (\dfrac{10}{3}\times\dfrac{2}{2})}[/tex]

[tex]\mathsf{5\times3=\boxed{\bf 15}}\\\\\mathsf{2\times3=\boxed{\bf 6}}}\\\\\mathsf{10\times2=\boxed{\bf 20}}\\\\\mathsf{3\times2=\boxed{\bf 6}}[/tex]

[tex]\rightarrow{\mathsf{y =\dfrac{15}{6}-\dfrac{20}{6}}[/tex]

[tex]\rightarrow\mathsf{y = \dfrac{15-20}{6}}[/tex]

[tex]\mathsf{15-20=\boxed{\bf -5}}\\\\\\\mathsf{6= \boxed{\bf 6}}\textsf{ because \underline{6} is the LCD (\underline{L}east \underline{C}ommon \underline{D}enominator}[/tex]

[tex]\boxed{\mathsf{y =\bf -\dfrac{5}{6}}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \bf y = }\mathsf{\bf -\dfrac{5}{6}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Step-by-step explanation:

6% of 35000

6/100×35000

=2100

hope it helps you

Step-by-step explanation:2100

Answer:

cosine

Step-by-step explanation:

fundamental trigonometric identities

Answer:

(-8,-3)

(-4,-1)

(0,1)

(2,2)

(6,4)

Step-by-step explanation:

One by one, substitue the x values and solve for y

Answer:

negative 4

Step-by-step explanation:

go

Answer:

.83

Step-by-step explanation:

we want

(sports∩Senior)/Senior

we can see that sports∩senior= 25

and senior= 25+5+5=30

25/30= .83

Answer:

−0.2542372881

Answer:

(c) 3360

Step-by-step explanation:

Given

The above arithmetic series where:

[tex]T_1 = 12[/tex] --- first term

[tex]d = 6[/tex] --- the common difference (18 - 12 = 6)

[tex]T_n = 198[/tex] --- The last term

Required

The value of the series

First, we calculate n using:

[tex]T_n = T_1 + (n - 1)d[/tex]

This gives:

[tex]198 = 12 + (n - 1)*6[/tex]

Collect like terms

[tex]198 - 12 = (n - 1)*6[/tex]

[tex]186 = (n - 1)*6[/tex]

Divide both sides by 6

[tex]31 = (n - 1)[/tex]

Make n the subject

[tex]n = 31 + 1[/tex]

[tex]n=32[/tex]

The sum of the series is:

[tex]S_n= \frac{n}{2}(T_1 + T_n)[/tex]

So, we have:

[tex]S_n= \frac{32}{2}(12 + 198)[/tex]

[tex]S_n= \frac{32}{2}*210[/tex]

[tex]S_n= 16*210[/tex]

[tex]S_n= 3360[/tex]

Answer:

x=2at/(1+t²)

dx/dt =[(1+t²)(2at)'-(2at)(1+t²)']/(1+t²)²

dx/dt=[(1+t²)(2a)-(2at)(2t)]/(1+t²)²

dx/dt=[2a+2at²-4at²]/(1+t²)²

dx/dt=[2a-2at²]/(1+t²)²

y=[b(1-t²)]/(1+t²)

dy/dt=[(1+t²)(b(1-t²))'-b(1-t²)(1+t²)']/(1+t²)²

dy/dt=[((1+t²)(-2bt)-b(1-t²)(2t)]/(1+t²)²

dy/dt=(-2bt-2bt³-2bt+2bt³)/(1+t²)²

dy/dt=(-4bt)/(1+t²)²

dy/dx=(dy/dt)/(dx/dt)

dy/dx=[(-4bt)/(1+t²)²]/[(2a-2at²)/(1+t²)²]

Cancelling common denominator

dy/dx=(-4bt)/(2a-2at²)

dy/dx=(-2bt)/(a-at²)

dy/dx=(2bt)/(at²-a)

Differentiating the above equation

y''=d²y/dx²=D[(2bt)/(at²-a)]

y''=[(at²-a)D(2bt)-(2bt)D(at²-a)]/(at²-a)²

y''=[(at²-a)(2b)(dt/dx)-(2bt)(2at)(dt/dx)]/(at²-a)²

dt/dx=(1+t²)²/(2a-2at²)

y''=[(at²-a)(2b)[(1+t²)²/(2a(1-t²))]-

(4abt²)[(1+t²)²/(2a-2at²)]/(at²-a)²

y''=[(-b)(1+t²)²-(2bt²)[(1+t²)²/(1-t²)]/(at²-a)²

y''=[(-b)(1+t²)²(1-t²)-(2bt²)(1+t²)²]/[(1-t²)(at²-a)²]

y''=[b(1+t²)²(t²-1)-2bt²(1+t²)²]/[(1-t²)(at²-a)²]

Step-by-step explanation:

Answer:

C is your answer.

Step-by-step explanation:

Hope is right, you're welcome, and good luck on your work.

please don't forget to click in the ❤, and on the ⭐.

The required solution for F(x) = -7 is x = -2.

F is the function defined by F(x)=3x−1

Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in set of y. x is independent variable while Y is dependent variable.

F(x) = 3x-1
Now F(x) = -7
⇒-7 = 3x-1
   x = -2

Thus, the required solution for F(x) = -7 is x = -2.

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Answer:

7 4 5 0

F O U R

+

4 8 1

O N E

=7 9 3 1

F I V E

Hope this is correct:)

Answer:

135787-

Step-by-step explanation:

ijjkmbnjgvnnhvbyyh

Answer:

the answer is 24%

Step-by-step explanation:

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