Answer:
[tex]\frac{d y}{d x} = \frac{2}{\sqrt{(2 x+1)^{2} -1} } + (\frac{-x}{|x|\sqrt{1-x^2}) }) + (1) Sec h^{-1} (x)[/tex]
Step-by-step explanation:
Step(i):-
Given function
[tex]y = cosh^{-1} (2 x +1) - x Sec h^{-1} (x)[/tex] ....(i)
we will use differentiation formulas
i) y = cos h⁻¹ (x)
Derivative of cos h⁻¹ (x)
[tex]\frac{d y}{d x} = \frac{1}{\sqrt{x^2-1} }[/tex]
ii)
y = sec h⁻¹ (x)
Derivative of sec h⁻¹ (x)
[tex]\frac{d y}{d x} = \frac{-1}{|x|\sqrt{(x^2-1} }[/tex]
Apply U V formula
[tex]\frac{d UV}{d x} = U V^{l} + V U^{l}[/tex]
Step(ii):-
Differentiating equation (i) with respective to 'x'
[tex]\frac{d y}{d x} = \frac{1}{\sqrt{(2 x+1)^{2} -1} } X \frac{d}{d x} (2 x+1) + x (\frac{-1}{|x|\sqrt{1-x^2}) }) + (1) Sec h^{-1} (x)[/tex]
[tex]\frac{d y}{d x} = \frac{1}{\sqrt{(2 x+1)^{2} -1} } X (2) + (\frac{-x}{|x|\sqrt{1-x^2}) }) + (1) Sec h^{-1} (x)[/tex]
Conclusion:-
[tex]\frac{d y}{d x} = \frac{2}{\sqrt{(2 x+1)^{2} -1} } + (\frac{-x}{|x|\sqrt{1-x^2}) }) + (1) Sec h^{-1} (x)[/tex]
Edwin has 3 1 2 gallons of green paint. He uses 2 3 of the paint to paint his bedroom. He uses the rest of the paint for a mural in his garage. How much paint does Edwin use for the mural?
Answer:
1 1/6
Step-by-step explanation:
Edwin used a quantity of 2.833 gallons of paint for the mural which is the difference between the quantity of paint at the beginning and the used for the bedroom.
We have been given that Edwin has 3 1/2 gallons of green paint. He uses 2/3 of the paint to paint his bedroom. He uses the rest of the paint for a mural in his garage.
What is the fraction?A fraction is defined as a numerical representation of a part of a whole that represents a rational number.
To determine the quantity of paint Edwin used for the mural.
The quantity of paint Edwin used for the mural is the difference between the quantity of paint at the beginning and the used for the bedroom.
The quantity of paint used for the mural = 3 1/2 gallons - 2/3 gallons
The quantity of paint used for the mural = 3.5 - 0.66
The quantity of paint used for the mural = 2.833
Thus, Edwin used a quantity of 2.833 gallons of paint for the mural.
Learn more about the fractions here:
brainly.com/question/10354322
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A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to compare the typical mortgage owed by their clients against other homebuyers. The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500. Suppose a random sample of 150 Americans is selected. Identify each of the following, rounding your answers to the nearest cent when appropriate:
1. $mu=?
2. $sigma=?
3. $=n=$
4. $mu_{overlinex}=$x=?
5. $sigma_{overlinex}=$x=?
Answer:
1. [tex]$ \mu = \$306,500 $[/tex]
2. [tex]\sigma = \$24,500[/tex]
3. [tex]n = 150[/tex]
4. [tex]$ \mu_{x}= \mu = \$306,500 $[/tex]
5. [tex]\sigma_x = \$ 2,000 \\\\[/tex]
Step-by-step explanation:
The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500.
From the above information, we know that,
The population mean is
[tex]$ \mu = \$306,500 $[/tex]
The population standard deviation is
[tex]\sigma = \$24,500[/tex]
Suppose a random sample of 150 Americans is selected
[tex]n = 150[/tex]
Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.
The sample mean would be the same as the population mean that is
[tex]$ \mu_{x}= \mu = \$306,500 $[/tex]
The sample standard deviation is given by
[tex]\sigma_x = \frac{\sigma}{\sqrt{n} }[/tex]
Where [tex]\sigma[/tex] is the population standard deviation and n is the sample size.
[tex]\sigma_x = \frac{24,500}{\sqrt{150} } \\\\\sigma_x = \$ 2,000 \\\\[/tex]
Therefore, the required parameters are:
1. [tex]$ \mu = \$306,500 $[/tex]
2. [tex]\sigma = \$24,500[/tex]
3. [tex]n = 150[/tex]
4. [tex]$ \mu_{x}= \mu = \$306,500 $[/tex]
5. [tex]\sigma_x = \$ 2,000 \\\\[/tex]
Deanna's Quiz Scores
Use the dot plots to answer the question
has quiz scores that are less variable and
typically higher
80 82 84 86 88 90 92 94 96 98 100
Amy's Quiz Scores
.
.
.
..
80 82 84 86 88 90 92 94 96 98 100
Answer:
1.90.93
2.90.27
Step-by-step explanation:
Answer:
one above correct
Step-by-step explanation:
1st - 90.93
2nd-90.27
Un importante grupo de inversionistas, asociado a una línea de buses interurbanos, está considerando instalar un centro logístico de mantención, a usted le ha encargado la evaluación de este proyecto, considerando un horizonte de 5 años. el estudio técnico del proyecto indica que se requiere disponer de un galpón 1000 m2 dentro de las instalaciones que la empresa ya cuenta, además de un acceso pavimentado con cimientos especiales de 6000 m2. el costo de construcción del galpón es de $ 42 por m2, y el costo de construcción del acceso pavimentado es de $ 32 por cada m2. adicionalmente, se requiere adquirir servidores de punta para realizar el check de los buses antes de comenzar sus recorridos, su costo se estima en $ 630.000, además se necesitan equipos especiales para la revisión de los neumáticos, con un costo de $ 400.000. finalmente, se deberá conseguir un terreno al interior del terminal de buses, con una superficie de 1 m2, con un costo de $50 por m2.
Answer:
Monto total de inicio requerido, de acuerdo con los detalles proporcionados en la pregunta = $ 1,264,000
Total start-up amount required, according to the details provided in the question = $1,264,000
Step-by-step explanation:
- Hay 1000 m² de espacio de almacén para construir a $ 42 por m². Dinero total requerido = 1000 × 42 = $ 42,000.
- Hay 6000 m² de espacio de acceso pavimentado para construir a $ 32 por m². Dinero total requerido = 6000 × 32 = $ 192,000.
- Compra de servidores de última generación para revisar los autobuses antes de comenzar sus recorridos. Costo total = $ 630,000.
- Se necesita comprar equipo especial para revisar los neumáticos. Costo = $ 400,000.
Monto total de inicio requerido, de acuerdo con los detalles proporcionados en la pregunta = 42000 + 192000 + 630000 + 400000 = $ 1,264,000
¡¡¡Espero que esto ayude!!!
English Translation
- There is 1000 m² of warehouse space to construct at $42 per m². Total required money = 1000 × 42 = $42,000
- There is 6000 m² of paved access space to construct at $32 per m². Total money required = 6000 × 32 = $192,000
- Purchase of state-of-the-art servers to check the buses before starting their tours. Total Cost = $630,000
- Purchase of special equipment is needed to check the tires. Cost = $400,000
Total start-up amount required, according to the details provided in the question = 42000 + 192000 + 630000 + 400000 = $1,264,000
Hope this Helps!!!
A group of campers is going to occupy 4 campsites at a campground. There are 14 campsites from which to choose. In how many ways can the campsites be chosen?
There are
possible ways to choose the campsites.
Check
Enter your answer in the answer box and then click Check Answer.
Clear All
All parts showing
Answer:
24024 are the total number of ways of choosing 4 campsites out of 14.
Step-by-step explanation:
We are given that there are a total of 14 campsite out of which 4 campsites are to be chosen.
It is a simple example of selection problem.
Number of ways to choose the first campsite = 14
Now, one campsite is chosen, 13 campsites are left.
Therefore,
Number of ways to choose the second campsite = 13
Now, one more campsite is chosen, 12 campsites are left.
Therefore,
Number of ways to choose the third campsite = 12
Now, one more campsite is chosen, 11 campsites are left.
Therefore,
Number of ways to choose the fourth campsite = 11
So, total number of ways for choosing 4 campsites out of 14:
14 [tex]\times[/tex] 13 [tex]\times[/tex] 12 [tex]\times[/tex] 11 = 24024
Hence, answer is 24024.
The height of seaweed of all plants in a body of water are normally distributed with a mean of 10 cm and a standard deviation of 2 cm. Which length separates the lowest 30% of the means of the plant heights in a sampling distribution of sample size 15 from the highest 70%? Round your answer to the nearest hundredth. Use the z-table below:
0.00 0.01 0.02 0.030.04 0.05 0.06 0.08 0.09 0.07 -0.8 0.212 0.209 0.206 0.203 0.201 0.198 0.195 0.192 0.189 0.187 -0.7 0.242 0.239 0.236 0.233 0.230 0.227 0.224 0.221 0.218 0.215 -0.6 0.274 0.271 0.268 0.264 0.261 0.258 0.255 0.251 0.248 0.245 -0.5 0.309 0.305 0.302 0.298 0.295 0.291 0.288 0.284 0.281 0.278 -0.4 0.345 0.341 0.337 0.334 0.330 0.326 0.323 0.319 0.316 0.312 -0.3 0.382 0.378 0.374 0.3710.367 0.363 0.359 0.356 0.352 0.348
Round the z-score and i to two decimal places. Provide your answer below: Z-Score =
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: height of seaweed.
X~N(μ;σ²)
μ= 10 cm
σ= 2 cm
You have to find the value of the variable X that separates the bottom 0.30 of the distribution from the top 0.70
P(X≤x)= 0.30
P(X≥x)= 0.70
Using the standard normal distribution you have to find the value of Z that separates the bottom 0.30 from the top 0.70 and then using the formula Z= (X-μ)/σ translate the Z value to the corresponding X value.
P(Z≤z)= 0.30
In the body of the table look for the probability of 0.30 and reach the margins to form the Z value. The mean of the distribution is "0" so below 50% of the distribution you'll find negative values.
z= -0.52
Now you have to clear the value of X:
Z= (X-μ)/σ
Z*σ= X-μ
X= (Z*σ)+μ
X= (-0.52*2)+10= 8.96
The value of seaweed height that divides the bottom 30% from the top 70% is 8.96 cm
I hope this helps!
Answer:-0.53 and 9.72
Step-by-step explanation:
How many pairs are shown ?????????
Answer:8 i ithink
Step-by-step explanation:
Answer:
12, go for 24.
Step-by-step explanation:
There are 6 sides of a cube.
There are 2 pairs of parallel line segments for each side.
6 x 2 = 12
Although that answer is not there, you should go for 24. Since there are 2 variables for each line segment, 12 x 2 = 24. Not sure, hope this helps.
:/
Which statements are true? Check all that apply. All rectangles are squares. All rhombi are parallelograms. All squares are rhombi. All trapezoids are parallelograms. No trapezoid is a rectangle.
Answer:
All rhombi are parallelograms.
All squares are rhombi.
No trapezoid is a rectangle.
Adult male heights are a normal random variable with mean 69 inches and a standard deviation of 3 inches. Find the height, to the nearest inch, for which only 8 percent of adult males are taller (i. find the 92nd percentile)
Answer:
The height (corresponding to the [tex] \\ 92^{nd}[/tex] percentile) is (to the nearest inch) 73 inches (and, approximately, only 8% of adult males are taller than this height.)
Step-by-step explanation:
Roughly speaking, the [tex] \\ 92^{nd}[/tex] percentile is the x value (in the distribution) for which 92% of the observations in the [normal] distribution are below this x value, and 8% of the observations are above this x value.
To answer this question, we already know that:
Heights are a normal random variable, i.e, it follows a normal distribution.The mean for this distribution is [tex] \\ \mu = 69[/tex] inches.The standard deviation is [tex] \\ \sigma = 3[/tex] inches.Strategy for solving the question
For solving this, we have to use here the following key concepts: z-scores, the cumulative standard normal distribution, and the cumulative standard normal table.
Z-scores
To find the [tex] \\ 92^{nd}[/tex] percentile, we can use z-scores or standardized values. A z-score is a value that tells us the distance in standard deviations units from the mean. When the z-score is positive, it means that the value is above the mean. A negative indicates that the z-score is below the mean. The formula to obtain a z-score is as follows:
[tex] \\ z = \frac{x - \mu}{\sigma}[/tex] [1]
Where
z is the z-score.x is the raw score.[tex] \\ \mu[/tex] is the mean.[tex] \\ \sigma[/tex] is the standard deviation.Cumulative standard normal distribution and corresponding table
We still need to know the corresponding z-score, z, for the cumulative probability of 92%. For this, we have to consult the standard normal table, available on the Internet or in any Statistics books.
In this case, we look in the different columns of the standard normal table a probability value (exact or approximate) to 0.92 and then find the value for z that corresponds to this probability. The value for z is between 1.40 (0.91924) and 1.41 (0.92073).
Using z = 1.40 in [1], we have:
[tex] \\ z = \frac{x - \mu}{\sigma}[/tex]
[tex] \\ 1.40 = \frac{x - 69}{3}[/tex]
Then, solving for x:
Multiplying by 3 at each side of the equation:
[tex] \\ 1.40 * 3 = x - 69[/tex]
Adding 69 at both sides of the equation:
[tex] \\ (1.40 * 3) + 69 = x[/tex]
[tex] \\ x = (1.40 * 3) + 69[/tex]
[tex] \\ x = 4.20 + 69[/tex]
[tex] \\ x = 73.20[/tex]
That is, the [tex] \\ 92^{nd}[/tex] percentile is 73.20 inches, and to the nearest inch, this percentile is 73 inches.
This result indicates that, approximately, 92% of the heights are below 73 inches, and only 8% of heights are taller than this height.
The shaded area in the graph below shows an area of 0.08076 (8.076%) for 73.20 inches.
Please answer this correctly
Answer:
The range would decrease by 2
Step-by-step explanation:
The range is the difference between the highest number and the lowest number.
8 is the highest number and 1 is the lowest number here, so to find the range we would subtract 1 from 8. 8-1=7
But since 8 is being replaced by 6, we would subtract 1 from that instead.
6-1=5
The range decreased from 7 to 5, so it decreased by 2.
Hope that helps :)
Suppose that, in an experimental setting, 100 students are asked to choose between Gamble A and Gamble B, where: Gamble A: The student will receive $5,100 with a 70 percent probability and $200 with a 30 percent probability. Gamble B: The student will receive $5,100 with a 50 percent probability, $200 with a 25 percent probability, and $0 (nothing) with a 25 percent probability. What is the expected value (EV) of Gamble B
Focus on Gamble B only. Multiply each winnings with their corresponding probabilities.
5100*0.50 = 2550
200*0.25 = 50
0*0.25 = 0
Add up those results: 2550+50+0 = 2600
The expected value of gamble B is $2600
What is the area of the triangle below?
18
Answer:
D. 32 sq. unit s
Step-by-step explanation:
4×18/2=32
if 3x+2y=72 and y=3x, then x whoever solve I give them all my points
Answer:
[tex]x=8[/tex]
[tex]y=24[/tex]
Step-by-step explanation:
3x+2y=72
If y=3x, we plug it into our equation and get:
3x+2×3x=72
3x+6x=72
9x=72
Divide both sides by 9
x=8
Answer:
x = 8
Step-by-step explanation:
3x + 2y = 72
Put y as (3x), and solve for x.
3x + 2(3x) = 72
Multiply 2(3x).
3x + 6x = 72
Add like terms 3x and 6x.
9x = 72
Divide 9 into both sides and isolate x.
x = 72/9
x = 8
The value of x is 8.
how to solve the birth rate in a certain country in 1994 was 14.6 births per thousand population. in 2004 the birth rate was 14.32 births per thousand. let x represent years after 1994 and y represent the birth rate. assume the relationship is linear
Answer:
[tex]y(x)=-0.028x+14.6[/tex]
Step-by-step explanation:
We are to write a linear equation that relates y in terms of x
The Birth Rate in 1994 = 14.6 births per thousand population.
The Birth Rate in 2004 = 14.32 births per thousand population.
A linear equation is of the form y=mx+b, where:
x=Number of Years after 1994y=the birth ratem=Birth rate per yearStep 1: Determine the birth rate per year
In 1994, x=0, y=14.6 thousands
In 2004, x=10, y=14.32 thousands
[tex]m=\dfrac{14.32-14.6}{10-0}\\=\dfrac{-0.28}{10}\\m=-0.028[/tex]
Substituting m into our linear equation, we have:
[tex]y(x)=-0.028x+b[/tex]
When x=10, y=14.32
[tex]14.32=-0.028(10)+b\\b=14.32+0.28\\b=14.6[/tex]
Therefore, a linear equation that relates y in terms of x is:
[tex]y(x)=-0.028x+14.6[/tex]
What type of error is present in the underlined
sentence?
Which is the best revision to fix the error?
Answer:
Type of error: Run-on(comma splice).
Best revision to fix it: Adding a semicolon after beginners .
Explanation:
A run-on sentence is described as a sentence in which two independent clauses are joined inappropriately. It could be either comma splice where the two independent clauses are incorrectly linked using a comma or fused sentence when the two clauses run-on without employing appropriate coordinating conjunction or punctuation marks to separate the two ideas.
In the given sentence, it exemplifies a comma splice type of run-on sentence error. To fix this error, a semicolon after 'beginners' can be employed instead of a comma. This will help in connecting the two ideas appropriately where the first idea leads the second. Thus, the final sentence reads as:
'The guitar is another excellent instrument for beginners; however, it takes more practice than a recorder.'
Answer:
Many people play a musical instrument music can be soothing. A lot of schools teach the recorder; it is inexpensive and easy to play. The guitar is another excellent instrument for beginners, it takes more practice than a recorder.
What type of error is present in the underlined sentence?
✔ run-on
Which is the best revision to fix the error?
✔ adding a semicolon after instrument
Step-by-step explanation:
The perimeter of a triangle is 39 feet one side of the triangle is 1 foot longer than the second side the third is 2 feet longer than the second side find the length of each side
Answer:
second side = s first side = s +1 third side = s +2
39 feet = s + (s+1) + (s +2)
39 feet = 3s +3
36 feet = 3s
s = second side = 12 feet
first side = 13 feet
third side = 14 feet
Step-by-step explanation:
Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system. [Start 2 By 3 Matrix 1st Row 1st Column negative 15 2nd Column 21 3rd Column h 2nd Row 1st Column 5 2nd Column negative 7 3rd Column negative 3 EndMatrix ]
Answer: h = 9
Step-by-step explanation: A system of linear equations is consistent when it has at least one solution.
The matrix given is:
[tex]\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right][/tex]
Transform this matrix in a row-echelon form:
[tex]\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right][/tex] [tex]R_{2} = 3R_{2}+R_{1}[/tex] [tex]\left[\begin{array}{ccc}-15&21&h\\0&0&-9+h\end{array}\right][/tex]
For this row-echelon form to have solutions:
-9 + h = 0
h = 9
For this system to be consistent: h = 9.
Which statements are true of the function f(x) = 3(2.5)x? Check all that apply
Answer:
The function is exponential.
The function increases by a factor of 2.5 for each unit increase in x.
The domain of the function is all real numbers
The true statements are:
[tex]\mathbf{y = 3(2.5)^x}[/tex] is an exponential functionThe function represents an exponential growthThe domain of the function is the set of all real numbersThe function is given as:
[tex]\mathbf{y = 3(2.5)^x}[/tex]
An exponential function is represented as:
[tex]\mathbf{y = ab^x}[/tex]
Where: a represents the initial value, and b represents the rate
This means that:
[tex]\mathbf{y = 3(2.5)^x}[/tex] is an exponential function
By comparison:
[tex]\mathbf{b = 2.5}[/tex]
When b > 0, then the function represents an exponential growth
2.5 is greater than 0.
So, the function represents an exponential growth
Lastly, there is no restriction to the values of x.
So, the domain of the function is the set of all real numbers
Read more about exponential functions at:
https://brainly.com/question/11487261
Suppose we take repeated random samples of 50 college students from the same population and determine a 95% confidence interval for the mean GPA from each sample. Which of the following statements is true regarding the confidence intervals?
A. The intervals are centered around the population mean GPA.
B. The intervals are centered around the sample mean GPA.
C. 95% of the intervals will contain the sample mean in the long run.
D. 95% of the intervals will contain the population mean in the long run.
Answer:
B. The intervals are centered around the sample mean GPA.
D. 95% of the intervals will contain the population mean in the long run.
Step-by-step explanation:
Confidence interval:
Depends on two things: The sample mean and the margin of error.
Lower end: Sample mean - margin of error
Upper end: Sample mean + margin of error
This means that the intervals are centered around the sample mean.
x% level:
x% of the intervals will contain the population mean in the long run.
So the true statements are:
B. The intervals are centered around the sample mean GPA.
D. 95% of the intervals will contain the population mean in the long run.
Engineers want to design passenger seats in commercial aircraft so that they are wide enough to fit 95 percent of adult men. Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. Find the 95th percentile of the hip breadth of adult men. Round your answer to one decimal place; add a trailing zero as needed. The 95th percentile of the hip breadth of adult men is [HipBreadth] inches.
Answer:
[tex]z=1.64<\frac{a-14.4}{1.1}[/tex]
And if we solve for a we got
[tex]a=14.4 +1.64*1.1=16.204[/tex]
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(14.4,1.1)[/tex]
Where [tex]\mu=14.4[/tex] and [tex]\sigma=1.1[/tex]
For this part we want to find a value a, such that we satisfy this condition:
[tex]P(X>a)=0.05[/tex] (a)
[tex]P(X<a)=0.95[/tex] (b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
[tex]P(X<a)=P(\frac{X-\mu}{\sigma}<\frac{a-\mu}{\sigma})=0.95[/tex]
[tex]P(z<\frac{a-\mu}{\sigma})=0.95[/tex]
And we have:
[tex]z=1.64<\frac{a-14.4}{1.1}[/tex]
And if we solve for a we got
[tex]a=14.4 +1.64*1.1=16.204[/tex]
The 95th percentile of the hip breadth of adult men is 16.2 inches.
A tree that is 40 feet tall casts a 30 foot shadow. At the same time another tree casts a 20 foot shadow. How tall is the second tree?
Answer:26 2/3 feet
Step-by-step explanation:40/30 = 4/3
(26 2/3) / 20= 4/3
Data on the number of work days missed and the annual salary increase for a company’s employees show that, in general, employees who missed more days of work during the year received smaller raises than those who missed fewer days. A detailed analysis shows that the number of days missed explains 60% of the variation in salary increases. What is the correlation between the number of days missed and salary increase?
Answer:
Step-by-step explanation:
Correlation describes how strongly pairs of given variablé are related. In this case, a detailed analysis that was carried out shows that the number of days missed by employees explains 60% of the variation in salary increases and also impressed upon this fact that employees who missed more days of work during the year received smaller raises than those who missed fewer days.
From the analysis, we can draw a conclusion that there is a correction between days missed and variation in salary increase and that this type of correction is a negative correlation where an increase in the number of days missed will lead to a decrease in the raises awarded to each employee.
Approximately 10% of all people are left-handed. If 200 people are randomly selected, what is the expected number of left-handed people? Round to the whole number. Do not use decimals. Answer:
Answer:
N(L) = 20
The expected number of left handed people is 20.
Step-by-step explanation:
Given;
Percentage of left handed people P(L) = 10%
Total number of selected people N(T) = 200
The Expected number of left handed people N(L) is;
N(L) = Total number of selected people × Percentage of left handed people/100%
N(L) = N(T) × P(L)/100%
Substituting the given values;
N(L) = 200 × 10%/100%
N(L) = 200 × 0.1
N(L) = 20
The expected number of left handed people is 20.
AC =
Round your answer to the nearest hundredth.
A
5
35
B
C
Answer:
2.87 = AC
Step-by-step explanation:
Since this is a right triangle we can use trig functions
sin theta = opp / hyp
sin 35 = AC /5
5 sin 35 = AC
2.867882182= AC
To the nearest hundredth
2.87 = AC
Brian invests £8300 into his bank account. He receives 1.4% per year compound interest. How much will Brian have after 7 years? Give your answer to the nearest penny where appropriate.
Answer:
The nearest penny will be £9146.6
Step-by-step explanation:
A = P[1 + (r/n)]^(nt)
A = final amount
P = initial principal balance
r = interest rate
n = number of times interest applied per time period
t = number of time periods elapsed
A = 8300 [ 1 + {1.4 / (7*100)}]^(7*7)
A = 8300 [ 1 + {0.002}]^(49)
A= 8300 [ 1.002 ]^(49)
A = 8300 [ 1.102 ]
A = £9146.6
What is Compound Interest (CI) ?
Compound Interest is all about adding interest to principal amount of loan , deposit .
For every 1% increase in
unemployment, there is a 2%
decrease in potential GDP. This
creates a GDP gap. What is the GDP
gap when there is 4.5%
unemployment?
Answer:
The GDP gap is 9 % when there is 4.5 % unemployment.
Step-by-step explanation:
The statement shows a reverse relationship, where an increase in unemployment is following by decrease in potential GDP and can be translated into the following rate:
[tex]r = \frac{2\,\% \,GDP}{1\,\% unemp.}[/tex]
The GDP gap at a given increase in unemployment can be estimated by the following expression:
[tex]\frac{g}{u} = r[/tex]
[tex]g = r\cdot u[/tex]
Where:
[tex]r[/tex] - GDP gap-unemployment increase rate, dimensionless.
[tex]u[/tex] - Increase in unemployment rate, measured in percentage.
[tex]g[/tex] - GDP gap, measured in percentage.
If [tex]r = \frac{2\,\% \,GDP}{1\,\% unemp.}[/tex] and [tex]u = 4.5\,\%\,unemp.[/tex], the GDP gap is:
[tex]g = \left(\frac{2\,\%\,GDP}{1\,\%\,unemp.} \right)\cdot (4.5\,\%\,unemp.)[/tex]
[tex]g = 9\,\%\,GDP[/tex]
The GDP gap is 9 % when there is 4.5 % unemployment.
An aircraft seam requires 30 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.)
(a) If 21% of all seams need reworking, what is the probability that a rivet is defective?
(b) How small should the probability of a defective rivet be to ensure that only 11% of all seams need reworking?
Answer:
a. 0.00783
b. 0.003876
Step-by-step explanation:
The computation is shown below;
a. The probability for the rivet to be defective is
Let us assume A is the event for seam failure and B would be event for rivets failure
Now
a) [tex]P[A] = 1 - P[B']^{30}[/tex]
[tex]0.21 = 1 - P[B']^{30}[/tex]
[tex]0.79 = P[B']^{30}[/tex]
[tex]P[B'] = 0.79^{\frac{1}{30}}[/tex]
P[B'] = 0.99217
P[B] = 1 - P[B']
= 0.00783
b) Now the Next one is
[tex]0.08 = 1 - P[B']^{25}[/tex]
[tex]0.89 =P[B']^{30}[/tex]
[tex]P[B'] = 0.89^{(\frac{1}{30})}[/tex]
= 0.99612
So,
P[B] is
= 1 - P[B']
= 0.003876
We simply applied the above formula so that each one part could be calculated i.e the probabilities of the given question
What is the slope of the line below
Answer:
C. [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
You can use the formula to find the slope: [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
(-1.5, 1.5) & (1.5, 0)
[tex]\frac{0-(-1.5)}{1.5-(-1.5)} =\\\\\frac{0+1.5}{1.5+1.5} =\\\\\frac{1.5}{3} =\\\\\frac{1}{2}[/tex]
The slope is [tex]\frac{1}{2}[/tex]
Simplify this radical.
V84
2/21
242
4/21
4/42
Answer:
2√21
Step-by-step explanation:
√81 is √4 times √21
Since √4 is a perfect square, √4 = 2
We are left with 2 times √21
2√21
Answer:
2√21
Step-by-step explanation:
√84
84 can be written as 4 × 21.
√(4 × 21)
Distribute the square root to both terms.
√4 × √21
4 is a perfect square.
2 × √21
A product is introduced to the market. The weekly profit (in dollars) of that product decays exponentially as function of the price that is charged (in dollars) and is given by P ( x ) = 95000 ⋅ e − 0.05 ⋅ x Suppose the price in dollars of that product, x ( t ) , changes over time t (in weeks) as given by x ( t ) = 53 + 0.95 ⋅ t 2 Find the rate that profit changes as a function of time, P ' ( t ) dollars/week How fast is profit changing with respect to time 7 weeks after the introduction. dollars/week
Answer:
1). [tex]P'(t) = (-9025t).e^{-0.05(53+0.95t^2)}[/tex]
2). (-435.36) dollars per week
Step-by-step explanation:
Weekly price decay of the product is represented by the function,
P(x) = [tex]95000.e^{-0.05x}[/tex]
And the price of the product changes over the period of 't' weeks is represented by,
x(t) = [tex]53+0.95t^2[/tex]
Function representing the rate of change in the profit with respect to the time will be represented by,
1). P'(t) = [tex]\frac{dP}{dx}.\frac{dx}{dt}[/tex]
Since, P(x) = [tex]95000.e^{-0.05x}[/tex]
P'(x) = [tex]95000\times (-0.05).e^{-0.05x}[/tex]
= [tex](-4750).e^{-0.05x}[/tex]
Since, x(t) = 53 + 0.95t²
x'(t) = 1.9t
[tex]\frac{dP}{dx}.\frac{dx}{dt}=(-4750).e^{-0.05x}\times (1.9t)[/tex]
By substituting x = 53 + 0.95t²
[tex]\frac{dP}{dx}.\frac{dx}{dt}=(-4750).e^{-0.05(53+0.95t^2)}\times (1.9t)[/tex]
P'(t) = [tex](-9025t).e^{-0.05(53+0.95t^2)}[/tex]
2). For t = 7 weeks,
P'(7) = [tex](-9025\times 7).e^{-0.05(53+0.95(7)^2)}[/tex]
= [tex](-63175).e^{-4.9775}[/tex]
= (-63175)(0.006891)
= (-435.356) dollars per week
≈ (-435.36) dollars per week