Answer:
Following are the responses to these question:
Explanation:
They might believe that it was an enhanced layout because the quality is not updated. For instance, its new XS Max iPhone does have a better display than the iPhone X, however, the performance wasn't enhanced. It also has the same processor or graphic cards however a bigger pixel every centimeter ratio. When its output AND is not altered, the layout doesn't change, basically the very same item.
Answer:
If an Improvement creates no significant change in a product’s performance, then it is a(n) Superficial design improvement.
Explanation:
DIFFERENT BREED!
Because the mechanism of creep deformation is different from the mechanism of slip in most metal deformation processes, one of the fundamental relationships between microstructure and mechanical properties of metals is reversed for creep deformation compared with normal deformation. Is it:________.
A. The Hume-Rothery Rules
B. The Hall-Petch Relation
C. The Schmid Equation
Answer:
B. The Hall-Petch Relation
Explanation:
The Hall-Petch relation indicates that by reducing the grain size the strength of a material is increased up to the theoretical strength of the material however when the material grain size is reduced below 20 nm the material is more susceptible to creep deformation and displays an "inverse" Hall-Petch Relation as the Hall-Petch relation then has a negative slope (k value)
The Hall-Petch relation can be presented as follows;
[tex]\sigma_y[/tex] = [tex]\sigma_0[/tex] + k·(1/√d)
Where;
[tex]\sigma_y[/tex] = The strength
σ₀ = The friction stress
d = The grain size
k = The strengthening coefficient
The model equation for the reverse Hall-Petch effect is presented here as follows;
[tex]\sigma_y[/tex] = 10.253 - 10.111·(1/√d)
Kim is working on the cost estimate and feasible design options for a building. Which stage of a construction plan is Kim working on now? A. design development B. schematic design C. mechanical D. structural
Answer:
B. schematic design
Explanation:
This correct for Plato/edmentum
Kim is working on the cost estimate. The stage of a construction plan is Kim working on now is schematic design. The correct option is B.
What is a schematic design?A schematic design is an outline of a house or a building or another construction thing. The schematic design makes the outline map of the exterior or interior of the building. It is the foremost phase of designing something.
The design expert discusses the project three-dimensionally at this point in the process. To define the character of the finished project and an ideal fulfillment of the project program, a variety of potential design concepts are investigated.
The schematic design consists of a rough sketch with markings and measurements.
Therefore, the correct option is B. schematic design.
To learn more about schematic design, refer to the link:
https://brainly.com/question/14959467
#SPJ5
A cylindrical specimen of some metal alloy 10 mm in diameter and 150 mm long has a modulus of elasticity of 100 GPa. Does it seem reasonable to expect a tensile stress of 200 MPa to produce a reduction in specimen diameter of 0.08 mm
Answer:
N0
Explanation:
It does not seem reasonable to expect a tensile stress of 200 MPa to produce a reduction in specimen diameter of 0.08 mm
Given data :
Diameter ( d ) = 10 mm
length ( l ) = 150 mm
elasticity ( ∈ ) = 100 GPa
longitudinal strain ( б ) 200 MPa
Poisson ratio ( μ ) ( assumed ) =0.3
Assumption : deformation totally elastic
attached below is the detailed solution to why it is not reasonable .
The Sd value = 0.08 > the calculated Sd value ( 6*10^-3 ) hence it is not reasonable to expect a tensile stress of 200 MPa to produce a reduction in specimen
An infinite cylindrical rod falls down in the middle of an infinite tube filled with fluidat a constant speed V (terminal velocity). The density of the rod and the fluid are different.Assume that the pressure field is hydrostatic.(a)[5pts] Solve for the velocity profileas a function of rin terms of V and the other variables.(b)[2pts] Calculate upward force per unit length of the rod from the fluid wall shear stress on the rod.(c)[2 pts] Calculate upward force per unit length of the rod from bouyancy.(d)[1pts] Calculate V.VR1
Answer:
the speed of your poop
Explanation:
You are designing a hydraulic power takeoff for a garden tractor. The hydraulic pump will be directly connected to the motor and supply hydraulic fluid at 250 psi for use by accessories. In order for the tractor to maintain normal operation, the maximum power the hydraulic system can use is limited to 11 hp. For what maximum hydraulic flow rate in gallons per minute (gpm) should you design
Answer:
required flow rate is 75.44 gal/min
Explanation:
Given the data in the question;
Power developed = 250 psi = 1.724 × 10⁶ Pa
hydraulic power W = 11 hp = 11 × 746 = 8206 Watt
now, Applying the formula for pump power
W = pgQμ
where p is density of fluid, Q is flow rate, μ is heat and W is power developed;
W = pgQμ
W = pgμ × Q
W = P × Q -------- let this be equ 1
so we substitute in our values;
8.2027 kW = 1.724 × 10⁶ Pa × Q
Q = 8206 / 1.724 × 10⁶
Q = 4.75986 × 10⁻³ m³/sec
We know that, 1 cubic meter per seconds = 15850.3 US liquid gallon per minute, so
Q = 4.75986 × 10⁻³ × 15850.3 gallon/min
Q = 75.44 gal/min
Therefore, required flow rate is 75.44 gal/min
Which option identifies the section of a project charter represented in the following scenario?
Updated POS terminals will be available to the following five departments by July 31, 2015.
O project assumptions
O project deliverables
O project constraints
O project requirements
Determine the convection heat transfer coefficient, thermal resistance for convection, and the convection heat transfer rate that are associated with air at atmospheric pressure in cross flow over a cylinder of diameter D = 100 mm and length L = 2 m. The cylinder temperature is Ts = ° 70 C while the air velocity and temperature are V = 3 m/s and T[infinity] = 20°C, respectively. Plot the convection heat transfer coefficient and the heat transfer rate from the cylinder over the range 0.05 m ≤ D ≤ 0.5 m.
Answer:
attached below
Explanation:
Attached below is a detailed solution to the question above
Step 1 : determine the Reynolds number using the characteristics of Air at 45°c
Step 2 : calculate the Nusselt's number
Step 3 : determine heat transfer coefficient
Step 4 : calculate heat transfer ratio and thermal resistance
Repeat steps 1 - 4 for each value of diameter from 0.05 to 0.5 m
attached below is a detailed solution
Match the example to the model type it represents.
1. The client complains about the way the keyboard feels
1.mock-up
2. The engineering team tests how the tire treads on a new SUV perform on 2.various road conditions
preproduction model
3. The engineering team performs tests on the efficiency of the manufacturing process used for a recumbent bicycle
3.presentation model
Answer:
represnt
Explanation:
The rate of flow through an ideal clarifier is 8000m3 /d, the detention time is 1h and the depth is 3m. If a full-length movable horizontal tray is set 1m below the surface of the water, a) determine the percent removal of particles having a settling velocity of 1m/h. b) Could the removal efficiency of the clarifier to be improved by moving the tray? If so, where should the tray be located and what would be the maximum removal efficiency? c) What effect would moving the tray have if the particle settling velocity were equal to 0.5m/h?
Answer:
a) 35%
b) yes it can be improved by moving the tray near the top
Tray should be located ( 1 to 2 meters below surface )
max removal efficiency ≈ 70%
c) The maximum removal will drop as the particle settling velocity = 0.5 m/h
Explanation:
Given data:
flow rate = 8000 m^3/d
Detention time = 1h
depth = 3m
Full length movable horizontal tray : 1m below surface
a) Determine percent removal of particles having a settling velocity of 1m/h
velocity of critical sized particle to be removed = Depth / Detention time
= 3 / 1 = 3m/h
The percent removal of particles having a settling velocity of 1m/h ≈ 35%
b) Determine if the removal efficiency of the clarifier can be improved by moving the tray, the location of the tray and the maximum removal efficiency
The tray should be located near the top of the tray ( i.e. 1 to 2 meters below surface ) because here the removal efficiency above the tray will be 100% but since the tank is quite small hence the
Total Maximum removal efficiency
= percent removal[tex]_{above}[/tex] + percent removal[tex]_{below}[/tex]
= ( d[tex]_{a}[/tex],v[tex]_{p}[/tex] ) . [tex]\frac{d_{a} }{depth}[/tex] + ( d[tex]_{a}[/tex],v[tex]_{p}[/tex] ) . [tex]\frac{depth - d_{a} }{depth}[/tex] = 100
hence max removal efficiency ≈ 70%
c) what is the effect of moving the tray would be if the particle settling velocity were equal to 0.5m/h?
The maximum removal will drop as the particle settling velocity = 0.5 m/h