if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.​

Answers

Answer 1

Answer:

4 seconds

Explanation:

Given:

v₀ = 20 m/s

v = 0 m/s

a = -5 m/s²

Find: t

v = at + v₀

0 m/s = (-5 m/s²) t + 20 m/s

t = 4 s


Related Questions

Light rays that are reflected twice inside a rain water droplet can produce a second-order rainbow. True False mim​

Answers

Answer:

Yes

Explanation:

The answer is true.

The aqueous humor in a person's eye is exerting a force of 0.242 N on the 1.21 cm2 area of the cornea. What pressure is this in mm Hg?

Answers

Answer:

15.00124mmHg

Explanation:

Pressure is defined as the ratio of force applied to an object to its area.

Pressure = Force/Area

Given parameters

Force = 0.242N

Area = 1.21cm²

Required parameters

Pressure = 0.242/1.21

Pressure = 0.2N/cm²

Using the conversion to convert the pressure to mmHg

1N/cm² = 75.0062mmHg

0.2N/cm² = y

y = 0.2 * 75.0062

y = 15.00124mmHg

Hence the pressure in mmHg is 15.00124mmHg

Which of the following could not be responsible for the acceleration of an object? wind gravity density friction

Answers

Answer:

The correct answer to this question is D) Density

EXPLANATION:

From Newton's second laws of motion, we know that the external force acting on a body is equal to the product of mass with the acceleration of the body.

Mathematically Force F = m × a

Here, m is the  mass of the body.

a is the acceleration of the body.

Hence, it is the force which is responsible for creating acceleration in an object.

In the given question, we have four factors i.e wind, friction, gravity and density.

Out of the four options, wind, friction and gravity can exert force on an object and can create acceleration in it.

The density of a body is defined as the mass of that body per unit volume.

Mathematically it is written as -

Density d = \frac{m}{v} where v is the volume occupied by the body.

Hence, density will not be responsible for the acceleration of the body.

Answer:

Density

Explanation:

Hope this helps and its different for everyone for me it was C what was it for you

Four students measured the same line with a ruler like the one shown below. The results were as follows: 5.52 cm, 6.63 cm, 5.5, and 5.93. Even though you cannot see the line they actually measured, which of the recorded measurements are possible valid measurements for this instrument, according to its precision? Select all that apply. 1. 5.52 2. 6.63 3. 5.5 4. 5.93

Answers

Answer:

correct answer is 1 and 3

Explanation:

In direct measurement with an instrument, the precision or absolute error of the instrument is given by its appreciation, in this case we see that the measurements have two decimal places, so the appreciation of the instrument must be 0.01 cm

Based on this appreciation, the valid measurements are 5.52 and 5.5.

the other two measurements have errors much higher than the assessment of the instrument, for which there must have been some errors in the measurement.

The correct answer is 1 and 3

Alice drops a rock to a well. She hears the splash of the rock 4.1s later. The speed of sound is 340m/s. How deep is the well

Answers

Answer:

697 m

Explanation:

From the question above,

Note: Alice hears the splash of the rock in the well through the help of echo.

Applying,

v = 2x/t........................ Equation 1

Where v = speed of sound, x = depth of the well, t = time.

make x the subject of the formula in equation 1

x = vt/2................... Equation 2.

Given: v = 340 m/s, t = 4.1 s

Substitute these values into equation 2

x = 340(4.1)/2

x = 697 m.

A security guard walks at a steady pace, traveling 190 m in one trip around the perimeter of a building. It takes him 260 s to make this trip.what is his speed. express answer in 2 significant figures

Answers

Answer:

0.7 m/s

Explanation:

The following data were obtained from the question:

Distance travalled (d) = 190 m

Time (t) = 260 secs

Speed (S) =..?

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

Speed = Distance (d) /time(t)

S = d/t

With the above formula, we can calculate the speed of the security guard as follow:

Distance travalled (d) = 190 m

Time (t) = 260 secs

Speed (S) =..?

S = d/t

S = 190/260

S = 0.7 m/s

Therefore, the speed of the security guard is 0.7 m/s

A security guard walks at a steady pace, traveling 190 m in one trip around the perimeter of a building. The speed of the security guard is approximately 0.73 m/s.

Given:

Distance (d) = 190 m

Time (t) = 260 s

To calculate the speed of the security guard, we can use the formula:

Speed = Distance / Time

Speed = 190  / 260 = 0.73 m/s

Therefore, A security guard walks at a steady pace, traveling 190 m in one trip around the perimeter of a building. The speed of the security guard is approximately 0.73 m/s (rounded to two significant figures).

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Calculate the location xcm of the center of mass of the Earth-Moon system. Use a coordinate system in which the center of the Earth is at x

Answers

Answer:

The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.

Explanation:

Let suppose that planet and satellite can be treated as particles. The masses of Earth and Moon ([tex]m_{E}[/tex], [tex]m_{M}[/tex]) are [tex]5.972\times 10^{24}\,kg[/tex] and [tex]7.349\times 10^{22}\,kg[/tex], respectively. The distance between centers is 384,403 kilometers. The location of the center of mass can be found by using weighted averages:

[tex]\bar x = \frac{x_{E}\cdot m_{E}+x_{M}\cdot m_{M}}{m_{E}+m_{M}}[/tex]

If [tex]x_{E} = 0\,km[/tex] and [tex]x_{M} = 384,403\,km[/tex], then:

[tex]\bar x = \frac{(0\,km)\cdot (5.972\times 10^{24}\,kg)+(384,403\,km)\cdot (7.349\times 10^{22}\,kg)}{5.972\times 10^{24}\,kg+7.349\times 10^{22}\,kg}[/tex]

[tex]\bar x = 4.673\,km[/tex]

The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.

An ion has a mass of 6.79 × 10-27 kg and a charge of +4e. What is the magnitude of the electric field that will balance the gravitational force on the particle?

Answers

Answer:

Explanation:

200.34

An agent has just listed a power plant. This is an example of what type of real estate?

Answers

Answer: industrial properties

Explanation:

The power plant listed by the agent falls under industrial property. An industria property is a property which is either used in manufacturing, rentage, warehousing, processing e.t.c.

in this case the plant Would be used in the generation of power which would be sold. so yes the property falls under the category

A worker is pushing a crate of tools up a ramp into a truck. The crate has a mass of 120 kg and is accelerating at a rate of 1.05 m/s^2. Once he finishes pushing that crate up, he then takes another crate that is 3 times as massive and pushes it up the ramp with an acceleration of 0.71 m/s^2. What is the ratio of the force the worker used on the on the 120 kg crate and the more massive crate?

Answers

Answer:

B) 0.493

Explanation:

First Crate

Formula: F=ma

120kg*1.05m/s^2= 126N

Second Crate

Formula: F=ma

3*120kg=360kg

360kg*0.71m/s^2=255.6

Find the ratio by dividing

120kg/255.6kg=0.4929

Round 0.4929=0.493

Hope this Helps!!

Which of the following statements is/are true for ultrasonic test?a. Equipment used for ultrasonic testing is portableb. Complicated shapes can be easily scannedc. Waves generated are health hazardousd. All the above statements are true

Answers

Answer:

Equipment used for ultrasonic testing is portable

Explanation:

An ultrasonic tester is used to detect flaws such as cracks and leaks. Hence, an ultrasonic tester is an integral tool used in material testing and engineering, manufacturing quality control, equipment condition monitoring, building and bridge inspection and much more.

Ultrasonic testing can be performed on steel and other metals and alloys, though it can also be used on concrete, wood and composites, although with less resolution.

Unit 1 Horizontal Kinematics Homework #3 Acceleration 1. A bowling ball starts from rest and moves 300 m down the gutter in 22.4 seconds. a) What is its speed at the end of the track? b) What is its acceleration?

Answers

Answer:

Explanation:

since the object start its motion from rest and ends its motion at 300 m so

ΔS=S2-S1=300m-0m=300 m

given time is 22.4 sec therefore

v=ΔS/t

v=300/22.4=14.7 m/s

so the speed of the ball at the end of the track is 14.7 m/s

now to find the acceleration we know that

a=v/t

a=14.7/2.4

a=0.65m/sec²

A 21.3 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 45.7 cm from the wire.

Answers

Answer:

The magnetic field strength due to current flowing in the wire is9.322 x 10⁻ T.

Explanation:

Given;

electric current, I = 21.3 A

distance of the magnetic field from the wire, R = 45.7 cm = 0.457 m

The strength of the resulting magnetic field at the given distance is calculated as;

[tex]B = \frac{\mu_o I}{2\pi R}[/tex]

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ T.m/A

[tex]B = \frac{\mu_o I}{2\pi R}\\\\B = \frac{4\pi*10^{-7} *21.3}{2\pi(0.457)}\\\\B = 9.322 *10^{-6} \ T[/tex]

Therefore, the magnetic field strength due to current flowing in the wire is 9.322 x 10⁻ T.

In the park, there are 25 pigeons, 15 squirrels, 5 rabbits, and 5 stray cats. Why
can't you draw a line graph using only this information?

Answers

Answer: Line graph should be used to show how one variable changes over time not to show multiple categories or variables are at one specific point in time.

Explanation:

In maths, statistics, and related fields, graphs are used to visually display variables and their values. In the case of line graphs, these are mainly used to display evolution or change of a variable over time. For example, a line graph can show how the number of divorces changed from 1920 to 2010.

In this context, the number of different animals in the park cannot be represented through a line graph because this situation does not imply a variable changing over time. Moreover, this situation includes multiple variables or categories of animals and the data shows only one specific point in time, which can be better represented through a bar graph.

Consider position [x] = L, time [t] = T, velocity [v] = L/T and acceleration [a] = L/T 2 . Find the exponent A in the equation v = a^2 t^ A /x

Answers

Answer:

The exponent A in the equation is 3.

Explanation:

v = a^2 t^ A /x

[tex]v = \frac{a^2t^A}{x} \\\\vx = a^2t^A\\\\(\frac{L}{T})(L) = (\frac{L}{T^2})^2(T)^A\\\\ \frac{L^2}{T}= (\frac{L^2}{T^4})(T)^A\\\\ \frac{L^2}{T} *\frac{T^4}{L^2} = (T)^A\\\\T^3 = T^A\\\\\frac{T^3}{T^3} = \frac{T^A}{T^3}\\\\T^{3-3} = T^{A-3}\\\\3-3 = A-3\\\\0 = A-3\\\\A = 3[/tex]

Therefore, the exponent A in the equation is 3.

"For the lowest harmonic of pipe with two open ends, how much of a wavelength fits into the pipe’s length?"

Answers

Answer:

0.5 lambda(wavelength)

Explanation:

We know that

The first harmonic for both side open ended pipe is

L= 1/2lambda

So L = 0.5*wavelength

1
Name two safety measures commonly used in electric circuits and
appliances
lectric​

Answers

Answer:

always use insulated wire and use all the electrical appliances in proper way

A creature moves at a speed of 7.86 furlongs/fortnight (not a very common unit of speed). If 1.0 furlong = 220 yards 1 fortnight = 14 days 1 yard = 0.9144 meter and 1 day= 86400 sec find the speed of the creature (which is probably a snail).
1. 2.28745 × 109 m/s
2. 0.00130719 m/s
3. 1.16706 × 107 m/s
4. 47261.3 m/s
5. 0.25621 m/s
6. 39516.4 m/s
7. 5.29359 × 10−6 m/s

Answers

Answer:

2 0.00130719 m/s

Explanation:

Now we have

7.86 furlongs/fortnight

7.86 x 220 yards / fortnight

1729.2yards / fortnight

1647.8 yards / 14 days

123.5yards / day

So

123.5 x 0.9144 meter / day

112.meters / day

=112.9meters / 86400s

= 0.001307m/s

When you use a graduated cylinder in the lab, you can only use it to find the volume of liquids. (5 points)

True
False

Answers

this is true. they have numbers on the side that help to determine the volume.

Answer:

false

Explanation:

you can't only use it to find the volume of liquids

El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es de 32 cm de diámetro. ¿Qué presión de aire se tendrá de aire se tendrá que usar para levantar un automóvil de 17,640 N?`

Answers

Answer:

La presión neumática para levantar un automóvil de 17,640 newtons es 220,500 pascales.

Explanation:

Asumiendo que la presión ([tex]P[/tex]), medida en pascales, tiene una distribución uniforme sobre la superficie del pistón, se calcula a partir de la siguiente expresion:

[tex]P = \frac{F}{A}[/tex]

Donde:

[tex]F[/tex] - Fuerza motriz, medida en newtons.

[tex]A[/tex] - Área del pistón, medida en metros cuadrados.

La fuerza motriz es equivalente al peso del automóvil. El área del pistón ([tex]A[/tex]), medido en metros cuadrados, es determinado por:

[tex]A=\frac{\pi}{4}\cdot D^{2}[/tex]

Donde [tex]D[/tex] es el diámetro del pistón, medido en metros.

Si [tex]D = 0.32\,m[/tex] y [tex]F =17,640\,N[/tex], entonces la presión neumática es:

[tex]A = \frac{\pi}{4}\cdot (0.32\,m)^{2}[/tex]

[tex]A \approx 0.080\,m^{2}[/tex]

[tex]P = \frac{17,640\,N}{0.080\,m^{2}}[/tex]

[tex]P = 220,500\,Pa[/tex]

La presión neumática para levantar un automóvil de 17,640 newtons es 220,500 pascales.

A 1000 kg elevator is accelerated upward at a rate of 0.70 m/s2. What is the tension in the cable pulling the elevator upward when it experiences this acceleration?

Answers

Answer:

[tex]\Huge \boxed{\mathrm{700 \ N}}[/tex]

Explanation:

Tension is the force exerted.

[tex]\sf Force \ (N) = mass \ (kg) \cdot acceleration \ (m/s^2)[/tex]

[tex]F=1000 \cdot 0.70[/tex]

[tex]F=700[/tex]

The tension in the cable is 700 N.

The tension of an body moving upward can be calculated from its weight and normal force. The tension in cable pulling with an acceleration of 0.7 m/s² is 10500 N.

What is tension?

Tension is kind of force actually made by pulling a moving body. Like the force exerted by a cable, chain, string or a rope etc.

When an object gains potential energy with a restoring force if existing , then the restoring force will create a tension force. It is a transmitted force and can be calculated from the normal force acting.

It is given that the mass of the elevator is 1000 Kg, then its weight is mass multiplied by gravity of 9.8 m/s². Thus weight of the elevator is 1000 × 9.8 m/s² = 9800 N

The normal force is F = ma is calculated from the mass and acceleration as follows:

F = ma

   = 1000 kg ×0.70 m/s²

   = 700 N.

The tension force is the sum of weight of he body and the normal force,

Thus T = w + ma

T = 9800 N + 700 N

   = 10500 N.

Therefore, tension in cable pulling with an acceleration of 0.7 m/s² is 10500 N.

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Generator What does RPM stand for? What four things can you adjust to get the highest maximum voltage?

Answers

Answer:

revolution per minutes

Explanation:

increase number of turns on coil

increase speed

use of permanent magnet

increase in speed of object

RPM stands for revolution per minutes.

The four things you can adjust to get the highest maximum voltage are the number of turns of coil, the strength of the magnetic field, the area of the coil,  and the angular frequency of the coil.

RPM stands for revolution per minutes; which describes the number of turns made by the coil in a single minute.

The induced voltage in the generator coil is calculated as follows;

[tex]E_{max} = NBA \omega[/tex]

where;

N is the number of turnsB is the strength of the magnetic fieldA is the area of the coilω is the angular frequency

Thus, the four things you can adjust to get the highest maximum voltage are the number of turns of coil, the strength of the magnetic field, the area of the coil,  and the angular frequency of the coil.

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In which of these star groups would you mostly likely find the least heavy-element abundance for the stars within them: open clusters, globular clusters, or associations?

Answers

Answer: globular clusters

Explanation:

A globular cluster is a star which is usually spherical, it’s a collection of stars which is known to orbits a galactic core. Globular clusters are usually very tightly bound together by gravity, this helps in giving them their spherical shapes which they are known for, and it’s relatively high stellar densities which is found toward their centers.

An athlete needs to lose weight and decides to do it by “pumping iron.” (a) How many times must an 90.0 kg weight be lifted a distance of 0.890 m in order to burn off 1.00 lb of fat, assuming that that much fat is equivalent to 3500 kcal? (b) If the weight is lifted once every 2.10 s, how long does the task take?

Answers

Answer:

230kg would be the best answer

Explanation:

Does anybody know to solve this?

Answers

Answer:

25600 cm

2.56 x 10⁴ cm

Explanation:

Step 1: Find conversion

There are 100 cm in 1 m.

Step 2: Set up dimensional analysis

[tex]256m(\frac{100cm}{1 m} )[/tex]

Step 3: Multiply and cancel out units

25600 cm

2.56 x 10⁴ cm

14in^2
express your answer to two significant figures and include the appropriate units.

Answers

Answer:

= 9.3*10^-3m²

Explanation:

To solve this we must do some conversions

So we know that

1 inch=0.0254 m

And

So 1 inch x 1 inch = 6.4514 x 10^-m²

So 14 inch²= 14 * (6.4514 x 10^-4m²)

= 9.3*10^-3m²

The volume of a ball was measured at 500.0 cm3, and then mass was measured on this triple beam balance. What would be the most accurate reading for the mass of the ball?Using this mass, what would be the most accurate calculation of density for the ball? Round to the nearest ten thousandths.

Answers

Answer:

the answer is 0.8084

Explanation:

i just did it and got it correct

The digital exchange of structured data is called ?

Answers

Answer:

Electronic data interchange

Any body moving with simple harmonic motion is being acted on by a force that is:__________.
a) proportional to a sine or cosine function of the displacement
b) directly proportional to the displacement
c) proportional to the inverse square of the displacement
d) constant

Answers

Answer:

B

Explanation:

Because this oscillations occur when the restoring force is directly proportional to displacement, given as

F=-kx

Where k= force constant

X= displacement

Choose the box as the system of interest. What objects in the surroundings exert significant forces on this system

Answers

Answer:

Hello your question is incomplete attached below is the complete question

Your are lifting a heavy box we will consider this process for different choices of system and surroundings

Choose the box as the system of interest. What objects in the surroundings exert significant forces on this system

The floor the box you nonethe earth

answer : The earth and YOU

Explanation:

The objects that will exert significant force on this system would be the force exerted by the earth and force exerted by you

This is because the force exerted by the earth is an internal force and it can be calculated  as : m*g ( mass of the object * acceleration due to gravity ) also the force exerted by you are force due to normal reaction when lifting a load

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