if a wave has a frequency of 33 Hz, and a wavelength of 4 meters, determine the velocity of the wave. show work

Answers

Answer 1

Answer:

frequency=velocity/wavelength

ie velocity=frequency×wavelength=33×4=134m/s


Related Questions

how much heat is necessary to warm 500g of water from 20°c to 65°c​

Answers

Explanation:

so sorry

don't know but please mark me as brainliest please

I need help lol .........

Answers

Answer:

a

Explanation:

Which refers to the area on the thermometer marked with the letter A? scale bulb mercury strip number line

Answers

Answer:

The answer is numberline, D

Explanation:

I got it right on edge

Answer:

A

Explanation:

Scale

Got it right on Edge:)

feather is dropped from 13 m high after it has fallen 3 m what is its acceleration

Answers

Answer:

Explanation:

The constant acceleration of any object, neglecting air resistance and friction, is always -9.8. Proof:

[tex]s(t)=-4.9t^2+13[/tex] which is the position of this feather before it is dropped. The first derivative of position is velocity, so the velocity function for the feather is:

[tex]v(t)=-9.8t[/tex]. We could find the velocity that the feather is experiencing at 3 seconds, but that is not what we are being asked. What we are being asked is the acceleration of the feather at 3 seconds. So we find the acceleration function of the feather:

a(t) = -9.8

It turns out that the time doesn't matter to acceleration due to gravity because feathers and elephants all fall under the same pull.

If someone lifts less weight than you, explain why they can be considered more powerful.

Answers

Answer:

If they lift less weight, each time then they will grow stonger.

Whereas if you lifted more weight than them, and you couldn't do it then that means they are actually stronger than you.

I hope this helps!!!!

If someone lifts less weight that is force due to gravity than you many times than they are powerful.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

If they lift less weight, each time then they will grow stonger.

Whereas if you lifted more weight than them, and you couldn't do it then that means they are actually stronger than you.

If someone lifts less weight that is force due to gravity than you many times than they are powerful.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ2

WATS THE BEST ANIME
VERY IMPORTANT PLS ANSWER!!!!!!!​

Answers

There isn’t a best anime , but in my opinion any anime on Netflix is good other than DBZ too many episodes and storyline gets messed up.

Consider a trip to a lake. The sand warms up rapidly (and then burns your feet), while the water remains cool.
Which has the greater specific heat capacity, the sand or water?

Answers

Water has a greater specific heat capacity than sand.

What power is supplied to the starter motor of a large truck that draws 290 A of current from a 20.4 V battery hookup?

Answers

Answer:

Power = 5.916 Kw

Explanation:

Given:

Current = 290 A

Volt = 20.4 V

Find:

Power

Computation:

Power = IV

Power = (290)(20.4)

Power = 5916 w

Power = 5.916 Kw

А A pool of water of refractive index
4/3! is 60cm deep. Find its apparent
depth when viewed vertically through
air.​

Answers

Answer:

Apparent depth = 45 cm

Explanation:

The refractive index of water in a pool, n = 4/3

Real depth, d = 60 cm

We need to find its apparent  depth when viewed vertically through  air.​ The ratio of real depth to the apparent depth is equal to the refractive index of the material. Let the apparent depth is d'. So,

[tex]n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{60}{\dfrac{4}{3}}\\\\d'=45\ cm[/tex]

So, the apparent depth is 45 cm.

What is acceleration

Answers

[tex]{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}[/tex]

[tex]\longrightarrow[/tex] The rate of change of velocity per unit time is called acceleration.

[tex]\longrightarrow[/tex] Its SI unit is m/s².

[tex]\huge\boxed{\fcolorbox{blue}{red}{Thank you}} [/tex]

The rate of change of velocity is called acceleration.

can someone help im not sure of my answer

Answers

Answer:

Yes

Explanation:

But I feel also 2 is correct but your answer is right

If a point on the edge of a wheel 2 m in radius is accelerating at 2 m/s2, what is the angular acceleration of the wheel?

Answers

Answer:

[tex]\alpha =1\ rad/s^2[/tex]

Explanation:

It is given that,

The radius of a wheel, r = 2 m

Tangential acceleration of the wheel, [tex]a=2\ m/s^2[/tex]

We need to find the angular acceleration of the wheel. We know that the relation between angular and tangential acceleration is given by :

[tex]a=\alpha r\\\\\alpha =\dfrac{a}{r}\\\\\alpha =\dfrac{2}{2}\\\\\alpha =1\ rad/s^2[/tex]

So, the angular acceleration of the wheel is [tex]1\ rad/s^2[/tex].

Lauren walks 100m in half a minute. What must her speed have been to travel this distance?

Answers

Answer:

3.33 m/s

Explanation:

Using the formula: s = d / t (where s is speed, d is distance, and t is time)

[Convert minutes to seconds then solve]

Half a minute is 30 seconds. Therefore:

s = 100 / 30 = 3.33 m/s

it is dangerous to stand near the railway leak when train passing by,why?​

Answers

Answer:

Because a person may be pulled in the direction of the moving train. Thereby causing accident

Explanation:

According to Daniel Bernoulli's theorem, he was widely known as a Mathematician. He stated that due to the higher velocity of a moving train, there is higher kinetic energy in terms of volume around it, while the air pressure between the person and the train becomes lower.

As a result, a person near a moving train may be pulled in the direction of the moving train. Thereby causing accidents that may lead to death.

The diagram shows the top view of a 65-kg student at point A on an amusement park ride. The ride spins the student in a horizontal circle with a radius of 2.5 m, at a constant speed of 8.6 m/s. The floor is lowered and the student remains against the wall without falling to the floor.

The magnitude of the centripetal force acting on the student at point A is approximately

Question 4 options:

1398 N

47 N

223 N

1923 N

Answers

Answer:

1923 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 65 Kg

Radius (r) = 2.5 m

Velocity (v) = 8.6 m/s

Centripetal force (F) =?

The centripetal force, F, can be obtained by using the following formula:

F = mv²/r

F = 65 × 8.6² / 2.5

F = 65 × 73.96 / 2.5

F = 4807.4 / 2.5

F = 1922.96 ≈ 1923 N

Thus, the magnitude of the centripetal's force acting on the student is approximately 1923 N

Superman strikes a golf ball on the ground at a 38 degree angle above the horizontal at 147 m/s. What is the maximum height the golf ball reaches?

255 m


418 m


687 m


1103 m

Answers

The ball is hit with an initial vertical velocity of

(147 m/s) sin(38º) ≈ 90.5 m/s

Recall that

v ² - u ² = 2 ay

where u and v are initial and final velocities, respectively; a is acceleration; and ∆y is displacement.

Vertically, the ball is in freefall, so it is only subject to acceleration due to gravity, with magnitude g = 9.80 m/s² in the downward direction. At its maximum height, the ball has zero vertical velocity (v = 0) and the displacement is equal to the maximum height, so

0² - (90.5 m/s)² = 2 (-g) ∆y

y = (90.5 m/s)² / (2g)

y418 m

A barge is pulled by two tugboats. If the resultant of the forces exerted by the
tugboats is 5kN force directed along the axis of the barge, determine the tension in
each of the ropes for α = 45

Answers

Answer:

Approximately [tex]3.5\; \rm kN[/tex] in each of the two ropes.

Explanation:

Let [tex]F_1[/tex] and [tex]F_2[/tex] denote the tension in each of the two ropes.

Refer to the diagram attached. The tension force in each rope may be decomposed in two directions that are normal to one another.  

The first direction is parallel to resultant force on the barge.

The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \cos(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \cos(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].

These two components would be in the same direction. The resultant force in that direction would be the sum of these two components: [tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}}[/tex]. That force should be equal to [tex]5\; \rm kN[/tex].

The second direction is perpendicular to the resultant force on the barge.

The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \sin(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \sin(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].

These two components would be in opposite directions. The resultant force in that direction would be the difference of these two components: [tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}}[/tex]. However, the net force on the barge is normal to this direction. Therefore, the resultant force should be equal to zero.

That gives a system of two equations and two unknowns:

[tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}} = 5\; \rm kN[/tex], and[tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}} = 0[/tex].

The second equation suggests that [tex]F_1 = F_2[/tex]. Hence, replace the [tex]F_2[/tex] in the first equation with [tex]F_1[/tex] and solve for [tex]F_1\![/tex]:

[tex]F_1 = \displaystyle \frac{5\; \rm kN}{2\, \sqrt{2}} \approx 3.5\; \rm kN[/tex].

Because [tex]F_1 = F_2[/tex] (as seen in the second equation,) [tex]F_2 = F_1 \approx 3.5\; \rm kN[/tex].

In other words, the tension in each of the two ropes is approximately [tex]3.5\; \rm kN[/tex].

The tension in each of the rope is 3,535.5 N

The given expression:

the resultant force, R = 5 kN = 5000 N

the angle in between the forces, α = 45

To find:

the tension in each of the ropes

The tension in  each of the ropes  is calculated as follows;

The tension in vertical direction

[tex]F_y = F \times sin(\alpha)\\\\F_y = 5000 \times sin(45)\\\\F_y = 5000 \times 0.7071\\\\F_y = 3,535.5 \ N[/tex]

The tension in horizontal direction;

[tex]F_x = F \times cos(\alpha)\\\\F_x = 5000 \times cos(45)\\\\F_x = 5000 \times 0.7071\\\\F_x = 3,535.5 \ N[/tex]

Thus, the tension in each of the rope is 3,535.5 N

Learn more here:https://brainly.com/question/11194858

A car travels at a constant speed up a ramp making an angle of 28 degrees with the horizontal component of velocity is 40 kmh^-1, find the vertical and horizontal component of velocity.

Answers

Answer:

Vx = 35.31 [km/h]

Vy = 18.77 [km/h]

Explanation:

In order to solve this problem, we must decompose the velocity component by means of the angle of 28° using the cosine function of the angle.

[tex]v_{x} = 40*cos(28)\\V_{x} = 35.31 [km/h][/tex]

In order to find the vertical component, we must use the sine function of the angle.

[tex]V_{y}=40*sin(28)\\V_{y} = 18.77 [km/h][/tex]

A ball rotates on a string as shown below.



If the string in the image above breaks at point 1, which of the following images best shows the direction the ball will travel?

Question 8 options:

Diagram A

Diagram B

Diagram C

Diagram D

Diagram E

Answers

Answer:

Diagram A

Explanation:

When an object is travelling in a circular path it has an acceleration called centripetal acceleration, even if it is moving with uniform speed. This acceleration is attributed to the object due to change in the direction of velocity at every instant during the motion.

The direction of the velocity of the object is tangent to the circular path at every instant and if the object beaks free of the circular motion, such as breaking of the string, then it will go in the direction tangent to the circle at that instant. Hence, the diagram that best shows the direction ball will travel is:

Diagram A

Pls help me progress report just came in pls help me

Answers

Answer:

3rd. outer

Explanation:

they are electropositive have a tendency to give electrons

An object is pulled with a 85 N force inclined at 27° along a horizontal surface ABC
where AB is smooth but BC is rough.
a) Compute the mass of the object if the object moves with an acceleration of 5
ms-1 along AB.​

Answers

Answer:

m = 15.15 kg

Explanation:

Newton's Second Law of motion states that when an unbalanced force is applied on a body, an acceleration is produced in it in the direction of force. The component of force along the horizontal direction here, will be given by the Newton's Second Law as:

Fx = ma

F Cosθ = ma

where,

F = Magnitude of Force = 85 N

θ = Angle with horizontal = 27°

m = mass of object = ?

a = acceleration of object = 5 m/s²

Therefore,

85 N Cos 27° = m(5 m/s²)

m = 75.73 N/5 m/s²

m = 15.15 kg

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