When the stretch distances are at half of their maximum displacement, the acceleration will be half of its maximum value by Hooke's Law.
F= -kx
In accordance with Hooke's law, a principle of elasticity, for relatively minor deformations of an object, the displacement or size of the deformation is directly proportional to the deforming force or load The elasticity of an object is likewise governed by Hooke's law; for example, a metal spring can only be stretched so far before being broken by too much effort. A mass that we already have is then expanded out by x. Displacement and acceleration are inversely related. When the stretch distances are at half of their maximum displacement, the acceleration will be half of its maximum value.
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a point charge of 8.47 x 10-6 c and a mass of 5.49 x 10-6 kg is initially at rest within a constant electric field with a magnitude of 914 n/c. what is the magnitude of the acceleration of the point charge assuming that only the electric field force acts on it?
The magnitude of the acceleration of the point charge assuming that only the electric field force acts on it is 1.54×[tex]10^{7}[/tex].
The magnitude of the acceleration of the point charge can be calculated using the equation a = F/m, where F is the electric field force and m is the mass of the point charge. The electric field force is equal to the charge of the point charge times the magnitude of the electric field, or
F = (8.47 ×[tex]10^{-6}[/tex] C) x (914 N/C).
Therefore, the magnitude of the acceleration can be calculated as
a = (8.47×[tex]10^{-6}[/tex]C x 914 N/C)/(5.49 ×[tex]10^{-6}[/tex] kg) = 1.54 ×[tex]10^{7}[/tex] m/s2.
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You are pushing a 30 kg wooden crate across the floor. The force of sliding friction on the crate is 90 N. How much force must you exert on the crate to keep it moving with a constant velocity
Answer:
f=90N
Explanation:
a negative charge moves in a direction opposite to that of an electric field. what happens to the energy associated with the charge? a negative charge moves in a direction opposite to that of an electric field. what happens to the energy associated with the charge? the electric potential energy of the charge increases, and the kinetic energy decreases. both the electric potential energy and the kinetic energy of the charge increase. both the electric potential energy and the kinetic energy of the charge decrease. the electric potential energy of the charge decreases, and the kinetic energy increases.
The electric potential energy of the charge decreases, and the kinetic energy increases.
What is Electric potential?Electric potential, the amount of work needed to move a unit charge from a reference point to a specific point against an electric field. Typically, the reference point is Earth, although any point beyond the influence of the electric field charge can be used.
What is Kinetic energy?In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.
What is potentially Energy ?Potential energy, stored energy that depends upon the relative position of various parts of a system. A spring has more potential energy when it is compressed or stretched. A steel ball has more potential energy raised above the ground than it has after falling to Earth.
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Which answer best describes the climate of an area?
A. Rain is falling from clouds
B. A hurricane cause several days of flooding
C. Snow is falling on a mountain
D. Most days are dry and Sunny
supply plane needs to drop a package of food to scientists working on a glacier in greenland. the plane flies 190 m m above the glacier at a speed of 160 m/s m / s . for help with math skills, you may want to review: mathematical expressions involving squares for general problem-solving tips and strategies for this topic, you may want to view a video tutor solution of dock jumping. part a how far short of the target should it drop the package? express your answer with the appropriate units.
The package should be dropped 25 m short of the target.
What is package?A package is a collection of related items, such as software components, that are combined into a single unit and distributed for installation or use. Packages can provide a wide range of functionality, from basic data types and libraries, to complete applications and services.
The package should be dropped 25 m short of the target.
To calculate this, we use the formula d = vt,
where d is the distance,
v is the velocity, and t is the time.
We know the velocity (160 m/s) and the time (0.15625 s).
We can determine the distance by plugging these values into the formula: d = 160 m/s × 0.15625 s = 25 m.
Therefore, the package should be dropped 25 m short of the target.
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write the formula of velocity ratio
a ball is tossed vertically upward with an initial speed of 25.5 m/s. how long does it take before the ball is back on the ground?
The ball will take 5.2 seconds to return back to its original position on the ground, if its initial speed is 25.5 m/sec.
The initial sped of the ball, u = 25.5 m/sec
Acceleration due to gravity of the earth, g = 9.81 m/s²
Let the time taken by the ball to reach highest point, = t
We know the final velocity of the ball after reaching the highest point is zero(0).
By the first equation of motion,
v = u + at
0 = 25.5 + (-9.81) × t
t = 25.5/9.81
t = 2.6 seconds
So the total time taken would be 2t = 2 × 2.6 = 5.2 seconds.
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approximately when does the full moon rise? select one: a. near sunrise b. near sunset c. near noon d. near midnight
approximately when does the full moon rise d. near midnight
When the full moon rises, where is the Sun?At Full Moon, the Moon is 180 degrees distant from the Sun and 12 hours behind it. As a result, the Moon rises as the Sun sets; it is high in the south around midnight and sets in the morning, at daybreak.
As a result, the moon advances eastward by around 12 degrees every day with regard to the sun (13 minus 1). This implies that the moon rises later and later each day, occasionally in the morning, occasionally in the afternoon, and occasionally at night.
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beneath the surface of which moon of saturn is there evidence for the existence of a subsurface ocean of liquid water?
Saturn's moons has evidence for the existence of a subsurface ocean of liquid water known as Enceladus
Enceladus is a living moon with a vast ocean of liquid salty water beneath its crust. Furthermore, jets of icy particles from that ocean, laced with a brew of water and simple organic chemicals, erupt from this fascinating ocean world on a continuous basis.
Saturn, like Jupiter, has no surface but an atmosphere that contains traces of water vapor. Furthermore, Saturn's spectacular rings are mostly composed of water ice. Titan, Saturn's largest moon, has a surface made up of water ice and other hydrocarbon-based ices.
Cassini discovered water constantly spewing out of jets around Saturn's moon Enceladus' south polar region, leading scientists to conclude that its subsurface ocean contains all of the ingredients for life - liquid water, heat, and food (methane).
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Four objects each with charge +2. 0×10−7C+2. 0×10−7C are located at the corners of a square whose sides are 2. 3 mm long.
Part A complete What quantities can be determined using this information?
The total electric potential energy of the system consisting of the four charged objects.
The electric force on a charged object placed at the center of the square.
The mass of each object.
Part B Find the electric force on a charged object placed at the center of the square.
Express your answer with the appropriate units
Negative electrons are more prevalent than positive protons or vice versa in charged things.
How can I determine the electric potential in a square's center? Negative electrons are more prevalent than positive protons or vice versa in charged things.Furthermore, the protons and electrons in neutral things are distributed equally, creating a balance of charge.Applied to things is the same idea that was previously stated for atoms.Electric force is the pressure exerted by charged objects on one another.Gravitational fields are similar to electric fields in that they are the area in which an object's gravitational pull is felt, such as the planet's orbit.The area around a charged object is similarly surrounded by an electric field.As a result, we have determined that the potential energy of the given system, which consists of four charges grouped as illustrated, is -0.021J.As a result, it is decided that Option E is the right response.To learn more about electric potential energy refer
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what is the stopping sight distance for a road with a design speed of 65 mph, a 0.25 coefficient of friction and a 2% uphill grade? assume that the perception-reaction time is 2 seconds.
The stopping sight distance (SSD) for a road with a design speed of 65 mph, a 0.25 coefficient of friction, and a 2% uphill grade would be 2673.87 feet.
What is Stopping sight distance?Stopping sight distance (SSD) is a measure of the distance a vehicle needs to travel in order to come to a complete stop after the driver perceives a potential hazard on the road. It is calculated by taking into account the driver's perception-reaction time, the vehicle's speed, the road's gradient, and the road's surface friction. SSD helps ensure that drivers have enough time and distance to stop safely in case of an emergency. It is often used to determine the appropriate placement of signs, signals, and other traffic control devices on a road.
The stopping sight distance (SSD) for a road with a design speed of 65 mph, a 0.25 coefficient of friction, and a 2% uphill grade can be calculated using the formula: SSD = (Speed x Perception-Reaction Time) + (Speed² / (2 x G x Friction Coefficient))
Where, Speed = 65 mph = 65 x 1.46667 = 94.44 ft/s
Perception-Reaction Time = 2 seconds = 2 x 1.46667 = 2.933 ft/s
G = 32.17 ft/s² (acceleration due to gravity)
Friction Coefficient = 0.25
Therefore,
SSD = (94.44 x 2.933) + (94.44² / (2 x 32.17 x 0.25))
SSD = 277.33 + 2396.54
SSD = 2673.87 ft
So, the stopping sight distance is 2673.87 feet.
This means that a driver should be able to see an obstacle at least 2673.87 feet ahead of them in order to be able to stop safely in case of an emergency.
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a smart phone charger delivers charge to the phone, in the form of electrons, at a rate of -0.75 c/s .how many electrons are delivered to the phone during 23 min of charging?
No. of electrons are delivered to the phone during 23 min of charging
6.46875 x 10^21
Charge is q = ne
where , e = - 1.6 x 10^-19
n = no.of electrons
The rate of accumulation of the electrons is ,q/t = Q
Q x t = -0.75 / 23 min = q
For time t = 23 min
1min = 60 sec
so time in sec, t = 23 x 60 = 1380 sec
therefore , Q x t = -0.75 x 1380
= -1035 c
No. of electrons = n = q/e
= -1035 / -1.6 x 10^-19
= 6.46875 x 10^21 electrons
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(c16p12) suppose that the attraction between the moon and the earth were due to coulomb forces rather than gravitational force. what would be the magnitude of the charge required if equal but opposite charges resided on both earth and moon? mass of earth
The magnitude of the charge required if equal but opposite charges resided on both earth and moon is 1.037 × 10²⁰ Coulombs.
The magnitude of the charge required would be very large. Coulomb's law states that the force between two charges is given by
F = (k × q1 × q2) / r²
where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between the charges.
To balance the gravitational force between the Earth and the Moon, we would need to set the Coulomb force equal to the gravitational force:
F_gravity = (G × m1 × m2) / r²
where G is the gravitational constant, m1 is the mass of the first object, m2 is the mass of the second object, and r is the distance between the objects.
By equating the two forces and solving for q1 and q2, we can find the magnitude of the charges required:
q1 × q2 = (m1 × m2 * G) / (k × r²)
q1 = q2 = √( (m1 × m2 × G) / (k × r²))
where mass of earth is 5.98 × 10²⁴ kg, mass of moon is 7.35 × 10²² kg, distance between earth and moon = 3.84 × 10⁸ m, and the Coulombs constant is 8.9875517873681764 × 10⁹ N×m²/C²
q1 = q2 = √( (5.98 × 10²⁴ kg × 7.35 × 10²² kg × 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²) / (8.9875517873681764 × 10⁹ N×m²/C² × (3.84 × 10⁸ m)²)) = 1.037 × 10²⁰ Coulombs
Both the charges on Earth and Moon would be of 1.037 × 10²⁰ Coulombs
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Your question seems incomplete, but I assume the full question is:
"Suppose that the attraction between the moon and the earth was due to Coulomb forces rather than the gravitational force. What would be the magnitude of the charge required if equal but opposite charges resided on both earth and moon? Mass of earth = 5.98 × 10²⁴ kg; mass of moon = 7.35 × 10²² kg; earth-moon distance = 3.84 × 10⁸ m."
a meter stick lies along the optical axis of a convex mirror of focal length 40 cm, with its nearer end 60 cm from the mirror surface. how long is the image of the meter stick?
The image of the meter stick is 8 cm long which is found by the mirror's formula.
Given:
Focal length of the convex mirror = f = -40 cm
Length of the stick =1m = 100 cm
Distance of the nearer/front end = s1 = 60 cm
Distance of the far/back end = s2 = 60 + 100 = 160 m
By finding out the image positions of the nearer end and the far end. We can find out the length of the image a meter stick.
Mirror formula,
1/s + 1/s' = 1/f
Using mirror formula we find expression for s',
s' = sf/(s-f)
To find the image position of front end of the stick facing towards the convex mirror
s'1 = (60 x- 40) / (60-(-40))
s'1 = -24 cm
Similarly, the image position of back end of the stick
s'2 = -32 cm
The length of the image is given by
s'1 - s'2 = -24 -(-32)
= 8 cm
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object a has a charge q on it, object b has a charge q on it, and object c has a charge 2q on it. these charges are arranged, one each at the vertices of an equilateral triangle. which charge has the greatest magnitude electic force on it?
Different from the forces operating on objects A and B, object C is subject to a force that is twice as great. Therefore, the electric force exerted on object C by its charge is of the highest magnitude.
F AB = (kqq)/r2, where k is the Coulomb's constant, q is the charge on object A, and r is the separation between object A and B, determines the electric force acting on object A.
F AC is calculated using the formula (kq2q)/r2, where r is the distance between item A and C, q is the charge on object A, and 2q is the charge on object C.
F BC = (kq2q)/r2, where k is the Coulomb's constant, q is the charge on object B, 2q is the charge on object C, and r is the separation between objects B and C, determines the electric force acting on object B.
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When seat and steering wheel are adjusted properly, the driver should be at least _HOW_MANY_ inches from the steering wheel?
The driver must be least "10 inches" away as from steering wheel when seated properly.
Explain some safety guidelines of driving?It is essential to become familiar with the local traffic laws when travelling to or relocating to a new nation.
No matter how you plan to use a vehicle, adhering to the traffic laws will ensure your safety.
Having stated that, here are some guidelines for driving: On left side of the vehicle is always where the steering wheel is located.Drive just on right side of the roadway at all times. The same-direction lanes of traffic are divided by white lines.opposing-direction traffic is divided by yellow lines.To pass other vehicles moving in the opposite way, use the left lane.Watch out for cyclists. They frequently share the highway with automobiles and are required to abide by standard traffic regulations.The driver must be least "10 inches" away as from steering wheel when seated properly.To know more about the safety guidelines of driving, here
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How much power is used if a force of 180N is used to push a box a distance if 60m in 20s
Answer:
Answer is in attached photo.
Explanation:
SolutionSolution is in attached photo, do take note there are 2 separate formulas to be used in this questions:
1) Work Done = Force x Distance
2) Power = [tex]\frac{Work \ Done}{Time}[/tex]
You are riding a bike with a bag in the front basket. A friend
on the sidewalk watches you ride by, heading south.
Which statement best describes how the bag's motion is
relative to the frame of reference - you and your friend?
O You observe the bag at rest, but your friend
observes it moving south.
You and your friend both observe the bag
moving to the south.
Your friend observes the bag accelerating
north, while you see it standing still.
O You and your friend observe the bag's velocity
decreasing.
Acceleration refers to an object's change in direction or speed or Velocity.
What is Acceleration?Forces have an impact on how things move. They have the power to initiate motion, as well as to stop, slow down, or alter the course of an item already in motion. We can contend that forces induce changes in velocity since they alter an object's velocity, which is the change in speed or direction.Remember that acceleration is a change in velocity. If the velocity is positive, a position is said to be increasing with time, and if the velocity is negative, a position is said to be decreasing with time.If the distance remains constant during that time, the velocity will remain zero. hence, the Acceleration Objects are said to be accelerating if they are altering their speed or direction.Forces affect how an object moves. They have the power to start anything moving, stop it mid-motion, slow it down, or change its course. Considering that forces alter an object's velocity, which is the change in speed or direction, we can claim that forces induce changes in velocity.As a result, when the object's velocity and acceleration are multiplied, the result is positive, the object moves faster, and when the result is negative, the object moves slower.To learn more about acceleration from the given link
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a diver measures an ambient absolute pressure of 0.686 atm while diving in the ocean. what is the divers depth in feet?
2.250656 feet which are around 68.6 cm is the depth of the ocean at the place where the diver measured an absolute pressure is 0.686 atm.
As we know the pressure on the depth is directly proportional to that of depth in the meter as 1 atm has a meter of the column of water below which results in 1 atm of pressure.
And as given the pressure was 0.686 atm which shows the column below is just 0.686 mt or 68.6 cm. And to convert cm to feet we need to divide it by 30.48. So in this case
68.6/ 30.48 => 2.250656
So length in feet will be 2.250656 feet. We can say 2.25 feet after the round-off.
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how far from the center of the earth would the net gravitational force of the earth and the moon on an object be zero?
At 346306 km from the center of the earth would the net gravitational force of the earth and the moon on an object be zero.
Let the mass of the earth and the mass of the moon be m1 and m2 respectively. The distance between the earth and the moon be D.
The formula for the gravitational force between two objects having masses m1 and m2 saperated by a distance D is given by the formula:
F = Gm1m2/r^2
The distance between the earth and the moon is also known:
D=384400km
Let at distance x from the earth the gravitational force between the earth and the sun is zero.
∴ Gm1/x^2=Gm2/(D-x)^2
⇒ (D-x)^2 /x^2 = m2/m1
Substituting the values we get of m1,m2 and D we get:
x=346306 km
Therefore, at 346306 km from the center of the earth would the net gravitational force of the earth and the moon on an object be zero.
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Why is the gravitational
force that a friend
exerts on you less than
the gravitational force
exerted on you by
Earth?
As compared to Earth, humans have relatively low masses, which results in a very small and negligible gravitational force.
What does gravity mean?
The force of gravity, often known as gravitation, affects every material object in the universe. The force of gravity tends to draw any two objects or particles with nonzero mass toward one another. From subatomic particles to galaxy clusters, gravity affects things of all sizes.
The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them, according to Newton's universal law of gravitation.
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suppose that the strength of the electric field about an isolated point charge has a certain value at a distance of 8 m. how will the electric field strength compare at a distance of 16 m from the point charge?
The electric field strength at 16m is weaker than the electric field strength at 8m.
What do you mean by electric field?A charged object creates an electric field, which acts as a force field on other charged things nearby. The size of the charge generating the field and its distance from the charge both affect how strong the electric field is. Lines of force can be used to illustrate electric fields, with the direction of the lines indicating the direction of the field. Many different physical phenomena, such as how electric charges behave and how electric circuits function, can be explained by electric fields.
The electric field strength around a point charge is inversely proportional to the square of the distance from the point charge. Specifically, the electric field strength at a distance of r from a point charge is given by the equation E = kq/r^2, where k is the Coulomb constant, q is the charge of the point, and r is the distance from the point charge.
Therefore, the electric field strength at 16m is (1/2)^2 = 1/4 times the electric field strength at 8m. So the electric field strength at 16m is weaker than the electric field strength at 8m.
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when the object of mass m2 has descended a distance h, the potential energy of the system has decreased by
When the object of mass m2 has descended a distance h, the potential energy of the system has decreased by mg x h
The potential energy of the system has decreased by m2 x g x h.
Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases. If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy.
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during a nascar race a car goes 76 m/s around a curved section of track that has a radius of 240 m. what is the car's acceleration?
The acceleration of the car is 24.07 m/s², if the velocity of the car is 76 m/s on a curve section of radius 240 m.
The speed of the car, v = 76 m/s
The radius of the curve, R = 240 m
On a curve there is a chance of overturning of the vehicle due to the lateral sloping of the curve(called super-elevation). This overturning force is balanced by the centrifugal force. Which is equal to, F = Mv²/R.
Where M is the mass of the vehicle and v, and R velocity and radius of the curve respectively.
So the acceleration would be, a = v²/R
a = 76²/240
a = 24.07 m/s²
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Two gases—neon and air—are compressed in a closed system from P1 to P2 using a polytropic process with n = 1. 5. _____ requires lesser work to be compressed. The gas constants for neon and air are R = 0. 4119 and 0. 287 kJ/kg·K, respectively
In a closed system, two gases—neon and air—are compressed via a polytropic process with n = 1.5 from P1 to P2. Neon gas requires lesser work to be compressed.
In a polytropic process with n = 1.5, the equation that relates the initial pressure, P1, the final pressure, P2, and the specific heat ratio, n, is:
P1 x V1^n = P2 x V2^n
where V1 and V2 are the initial and final specific volumes of the gas, respectively.
Since the work done to compress a gas is given by the equation:
work = n x R x T x (V2^(1-n) - V1^(1-n))
We can find the work done to compress the two gases neon and air by substituting the values of the gas constant and the specific heat ratio into the equation:
Work to compress neon = 1.5 * 0.4119 kJ/kg·K * (V2^(1-1.5) - V1^(1-1.5))
Work to compress air = 1.5 * 0.287 kJ/kg·K * (V2^(1-1.5) - V1^(1-1.5))
Since the gas constant for neon is greater than the gas constant for air, it requires less work to compress neon than air. Therefore neon requires lesser work to be compressed.
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How much work is done when a 100 Ib rock is lifted to a height of 3 ft? Work= . ft . lb
When a 100 lb rock is raised to a height of 3 feet, it takes 397.5 Joules to complete the work. It is a scalar quantity and is measured in units of energy such as Joules (J) or Foot-pounds (ft-lb).
When a force moves an object in the force's direction, work has been done. The formula: can be used to determine the amount of work completed.
work = force x distance x cos(theta)
where force is measured in newtons (N), distance is measured in meters (m) and theta is the angle between the force and the direction of motion.
In this case, the force required to lift the rock is equal to the weight of the rock, which can be calculated using the equation:
force = mass x gravity
where mass is measured in kilograms (kg) and gravity is 9.8 m/s^2.
To find the amount of work done, we need to convert the weight of the rock from pounds to kilograms, convert the height from feet to meters, and use the formula for work:
mass = 100 lb / 2.2 kg/lb = 45.45 kg
distance = 3 ft x 0.3048 m/ft = 0.9144 m
work = force x distance x cos(theta) = 45.45 kg x 9.8 m/s^2 x 0.9144 m = 397.5 J
So the amount of work done is 397.5 Joules.
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A student designs a gravity experiment. She will time how long it takes different objects to fall from her school’s roof to the ground. She will use three objects: a 2-foot-long board, a toy car, and a paper bag. What is wrong with her experiment’s design?(1 point)
The experiment’s design is not fair because the three objects do not have equal length to ensure they fall the same height.
What is a fair experiment?
A fair experiment or testis an investigation where one variable (the independent variable) is changed and all other conditions (controlled variables) are kept the same.
To fairly determine the time taken for different object to fall to the ground, the length of the objects should be the same, this ensures that the dependent variable is kept constant.
2-foot-long board is not the same length as a toy car, and a paper bag, so the experiment is not fair.
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A highway curves to the left with radius of
curvature of 38 m and is banked at 24° so
that cars can take this curve at higher speeds.
Consider a car of mass 1283 kg whose tires
have a static friction coefficient 0.66 against
the pavement.
With a static friction coefficient of 0.66 against the pavement at 29.131 m/s.
Explanation:
Describe the free body diagram. There are three forces at work: weight force mg drawing the object downward, normal force N pushing perpendicular to the road, and friction force N pushing the object downward similarly to the road.
force total acting in a centripetal direction:
F = ma N sin + N cos = m v2/r N (sin + cos) = m v2/r.
Combined forces acting vertically:
F = ma N (cos sin ) = mg N = mg / (cos sin ), where:
G (sin + cos) = v2 / r v2 = gr (sin + cos) / (cos sin) is the replacement for the equation: mg (sin + cos) / (cos sin)
Values to be entered:
v² = (9.8 m/s²) (39 m) (sin 30° + 0.72 cos 30°) / (cos 30° − 0.72 sin 30°)
v = 29.131 m/s
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Please someone help this is urgent!!!
The total amount of matter in an object is known as its mass. The weight of an object is the gravitational pull it feels as it falls.
What does mass mean in forces?A substance's mass is its total amount of matter. The gravitational force an object experiences as it falls is known as its weight. Because of gravity, the object accelerates. All falling objects on Earth experience some upward air resistance force, which prevents them from ever falling completely freely.
The quantity of material in an object is measured by its mass, which is inversely proportional to the quantity and type of atoms it contains. Unless material is added to or taken away from a body, mass does not change with changes in position, motion, or shape. The kilogram serves as the unit of mass in the SI system (kg).
Therefore, the correct answer is option A) the amount of matter in something.
The complete question is:
What does the word mass mean?
A) the amount of matter in something
B) the speed an object falls
C) how high a person can jump
D) how far an object can be thrown
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two speakers play a 500 hz sound in phase. the speakers are arranged to face each other a what is the minimum distance you can move speaker a to achieve constructive interference along the x-axis? give a positive answer regardless of direction, in m.d are 6 m apart. how many points of constructive interference are there between the speakers?
As n is not an integer, so there will be no constructive interference between the speakers, if speaker A is moved by minimum distance.
What is interference?Interference is a phenomenon in which two waves combine by adding displacement together at every single point in space and time and to form a resultant wave of greater, lower, or same amplitude.
Wavelength of a 500 Hz sound wave is the speed of sound (about 343 m/s) divided by the frequency of the sound, which is 343/500 m = 0.686 m. Therefore, minimum distance you can move speaker A to achieve constructive interference along x-axis is 0.686/2 m = 0.343 m.
Given, distance between the speakers is 6m. Constructive interference will occur when path difference between two waves is equal to integer multiple of the wavelength. To achieve constructive interference, distance between the speakers + the distance moved by speaker A should be equal to n*wavelength where n is integer.
So, 6 + 0.343 = n* 0.686
n = (6+0.343)/0.686 = 8.8
As n is not an integer, so there will be no constructive interference between the speakers, if speaker A is moved by minimum distance.
To know more about interference, refer
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