if a seismic wave has a period of 0.0202s, find the frequency of the wave.

Answer:

Force = 63.27 Newton

Explanation:

Given the following data;

Weight = 0.62 kN = 0.62 * 1000 = 620 N

Acceleration = 1 m/s²

To find the magnitude of the force of the elevator floor on the person;

First of all, we would determine the mass of the elevator;

Weight = mass * acceleration due to gravity

We know that acceleration due to gravity is equal to 9.8 m/s²

Substituting into the above formula, we have:

620 = mass * 9.8

Mass = 620/9.8

Mass = 63.27 kg

Next, we would determine the force by using the formula;

Force = mass * acceleration

Force = 63.27 * 1

Force = 63.27 Newton

Answer:

C = 2 pi R     circumference of orbit

V = C / P      speed of moon by dividing circumference by period of revolution

V = 2 pi R / P_ = 2 pi 3.8 * 10E8 m / 2.3308 * 10E6 sec = 1024 m/s

Answer:

Coefficient of friction is [tex]0.068[/tex].

Work done is [tex]320~J[/tex].

Explanation:

Given:

Mass of the box ([tex]m[/tex]): [tex]60[/tex] kg

Force needed ([tex]F[/tex]): [tex]40[/tex] N

The formula to calculate the coefficient of friction between the floor and the box is given by

[tex]F=\mu mg...................(1)[/tex]

Here, [tex]\mu[/tex] is the coefficient of friction and [tex]g[/tex] is the acceleration due to gravity.

Substitute [tex]40[/tex] N for [tex]F[/tex], [tex]60[/tex] kg for [tex]m[/tex] and [tex]9.80[/tex] m/s² for [tex]g[/tex] into equation (1) and solve to calculate the value of the coefficient of friction.

[tex]40 N=\mu\times60 kg\times9.80 m/s^{2} \\~~~~~\mu=\frac{40 N}{60 kg\times9.80 m/s^{2}}\\~~~~~~~=0.068[/tex]

The formula to calculate the work done in overcoming the friction is given by

[tex]W=Fd..........................(2)[/tex]

Here, [tex]W[/tex] is the work done and [tex]d[/tex] is the distance travelled.

Substitute  [tex]40[/tex] N for [tex]F[/tex] and [tex]8 m[/tex] for [tex]d[/tex] into equation (2) to calculate the work done.

[tex]W=40~N\times8~m\\~~~~= 320~J[/tex]

Answer:

Appliance A and B can work together without tripping

Explanation:

We will calculate the amount of current consumed by each appliances.

Appliance A

P = VI

I = P/V  

I = 250/120 = 2.08 A

Appliance B

I = 480 /120 = 4 A

Appliance C

I = 1450/120

I = 12.08 A

Hence, appliance C will trip the circuit as it consumes a lot of electricity.

Answer:

The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in the liquid *

Explanation:

Answer:

Plz mark brainliest

Explanation:

As with kinetic energy, potential energy can change. When two objects interact, each one exerts a force on the other that can cause energy to be transferred to or from the other object.

Answer:

Here's an explanation but not the answer

Explanation:

When a resistor is traversed in the same direction as the current, the ... Traversing the internal resistance r1 from c to d gives −I2r1. ... I1 = I2 + I3 = (6−2I1) + (22.5− 3I1) = 28.5 − 5I1.

Answer:

The correct answer is "8 V".

Explanation:

Given:

Potential difference across battery,

= 20 V

Potential difference across R1,

= 12 V

Now,

On applying the Kirchorff loop, we get

⇒ [tex]E-I_1R_1-I_2R_2=0[/tex]

⇒ [tex]E-V_1-V_2=0[/tex]

⇒ [tex]V_2=E-V_1[/tex]

On putting values, we get

⇒      [tex]=20-12[/tex]

⇒      [tex]= 8 \ V[/tex]  

The potential difference across the resistance R2 will be "8 Volts.

According to the kirchoff's law in a loop of a circuit when there are number of the resistances so the sum of all the potential differences will be zero.

It is given that:

Potential difference across battery,= 20 V

Potential difference across R1,= 12 V

Now,

On applying the Kirchorff loop, we get

⇒ [tex]\rm E-I_1R_1-I_2R_2=0[/tex]

⇒ [tex]\rm E-V_1-V_2=0[/tex]

⇒ [tex]\rm V_2=E-V_1[/tex]

On putting values, we get

⇒ [tex]V_2=20-12=8\ volt[/tex]

Hence the potential difference across the resistance R2 will be "8 Volts.      

To know more about Kirchoff's law follow

https://brainly.com/question/86531

Answer:

The atmosphere of planets will block or enable heat coming from the sun

Answer:

The third particle should be at 0.0743 m from the origin on the negative x-axis.

Explanation:

Let's assume that the third charge is on the negative x-axis. So we have:

[tex]E_{1}+E_{3}-E_{2}=0[/tex]

We know that the electric field is:

[tex]E=k\frac{q}{r^{2}}[/tex]

Where:

So, we have:

[tex]k\frac{q_{1}}{r_{1}^{2}}+k\frac{q_{3}}{r_{3}^{2}}-k\frac{q_{2}}{r_{2}^{2}}=0[/tex]

Let's solve it for r(3).

[tex]\frac{3.01}{0.0429^{2}}+\frac{9.03}{r_{3}^{2}}-\frac{6.02}{0.0429^{2}}=0[/tex]

[tex]r_{3}=0.0743\: [/tex]  

Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.

I hope it helps you!

Answer:

ON

Explanation:

Locate your computer's Power button.

Press and hold that button until your computer shuts down.

Wait until you hear the computer's fans shut off, and your screen goes completely black.

Wait a few seconds before pressing and holding the power button to initiate your computer's normal startup.

Answer:

Acceleration is the rate of change in velocity. Momentum is the mass times the velocity. So if you multiply the mass times the acceleration, you get the of change of momentum.

Answer:

motion

is form of energy

Answer:

1) mass

2) speed

3) kinetic energy

Explanation:

Nature I guess......

Answer:

7.48 cm

Explanation:

The diagrammatic representation of information is shown in the image below:

From the image, Δ X₁X₂ and Δ Y₁Y₂ are equivalent triangles.

where;

X₁X₂ = width of the aperture

Using equivalent triangles, It implies that:

[tex]\implies \dfrac{X_1X_2}{Y_1Y_2} = \dfrac{1.70}{1.70+0.800} \\ \\ \implies X_1X_2=\dfrac{1.70}{1.70+0.800}\times 11.0[/tex]

[tex]X_1X_2= \dfrac{1.70}{2.50}\times 11.0 cm[/tex]

X₁X₂ = 7.48 cm

Answer:

Explanation:

Given that:

mass of water = 2kg

Pressure P₁ = 10 bar

temperature T₁ = 200⁰ C

Obtaining the following value from superheated tables at P₁ = 10 bar and T₁ = 200⁰ C

v₁ = 0.2060 m³/kg

h₁ = 2827.9 kJ/kg

The heat transfer Q₁₋₂ = 1740 kJ

Using the energy balance equation:

Q₁₋₂ = m(h₂ - h₁)

1740 = 2(h₂ - 2827.9)

1740 = 2h₂ - 5655.8

1740 + 5655.8 = 2h₂

7395.8 = 2h₂

h₂ = 7395.8/2

h₂ = 3697.9 kJ/kg

Since P₁ = P₂ = 10 bar

Using the superheated table at P₂ = 10 bar and h₂ = 3697.9 kJ/kg;

v₂ = 0.4011 m³/kg

The temperature at final state = 600 °C

The work done [tex]W_{1-2} = \int P dv[/tex]

[tex]W_{1-2} = P\times m (V_2-V_1)[/tex]

= (10×10² kPa)×2kg (0.4011 - 0.2060) m³/kg

= (10×10² kPa)×2kg × 0.1951 m³/kg

= 390.2 kJ

Answer:

The table shows caolums that brenda uses for her notes on the properties of elements her notes state that some elements can react to from basic compounds where should brenda place this property in her table

Explanation:

Answer:

Explanation:

Hydrostatic pressure due to a water column of height  h can be given by the following expression.

P = hρg

where ρ is density of water and g is acceleration due to gravity .

Substituting the values.

P = 380 x 1000 x 9.8

= 3.72 x 10⁶ Pa.

Answer:

[tex]F=\dfrac{3.72\times 10^6\ Pa}{A}\ N[/tex]

Explanation:

Given that,

The density of water, d = 1000 kg/m³

Depth, h = 380 m

We need to find the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water. The force exerted by the hydrostatic pressure is given by :

[tex]P=\rho gh[/tex]

Put all the values,

[tex]P=1000\times 9.8\times 380\\\\P=3.72\times 10^6\ Pa[/tex]

Force exerted,

F = P/A

So,

[tex]F=\dfrac{3.72\times 10^6\ Pa}{A}\ N[/tex]

Where

A is the area of crosss section

Hence, this is the required solution.

Answer:

Hello There!!

Explanation:

The answer is O parallel.

hope this helps,have a great day!!

~Pinky~

Answer:

Uniform Circular Motion is the Movement or Rotation of an Object along a circular Path at constant speed.

OPTION C IS YOUR ANSWER!.

Answer:

the angular velocity of the car is 12.568 rad/s.

Explanation:

Given;

radius of the circular track, r = 0.3 m

number of revolutions  per second made by the car, ω = 2 rev/s

The angular velocity of the car in radian per second is calculated as;

From the given data, we convert the angular velocity in revolution per second to radian per second.

[tex]\omega = 2 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 4\pi \ rad/s = 12.568 \ rad/s[/tex]

Therefore, the angular velocity of the car is 12.568 rad/s.

Answer:

  v₀ = 6.64 m / s

Explanation:

This is a projectile throwing exercise

          x = v₀ₓ t

          y = y₀ + v_{oy} t - ½ g t²

In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m

the time to reach the basket is

        t = x / v₀ₓ

we substitute

        y- y₀ = [tex]\frac{ v_o \ x \ sin \theta }{ v_o \ cos \theta} - \frac{1}{2} g \ \frac{x^2 }{v_o^2 \ cos^2 \theta }[/tex]

        y - y₀ = x tan θ - [tex]\frac{ g \ x^2 }{ 2 \ cos^2 \theta } \ \frac{1}{v_o^2 }[/tex]

we substitute the values

        3 -1.8 = 3.0 tan 60 - [tex]\frac{ 9.8 \ 3^2 }{2 \ cos^2 60 } \ \frac{1}{v_o^2}[/tex]

        1.2 = 5.196 - 176.4 1 / v₀²

        176.4 1 / v₀² = 3.996

        v₀ = [tex]\sqrt{ \frac{ 176.4}{3.996} }[/tex]

        v₀ = 6.64 m / s

Answer:

I HOPE THIS IS CORRECT

Explanation:

It is heated from 20°C to 80°C. We need to find the heat absorbed. It can be given by the formula as follows : So, 1386 J of heat is absorbed.

Answer: [tex]1.23\ m/s^2[/tex]

Explanation:

Given

At an elevation of [tex]y=34.7\ km[/tex], spacecraft is dropping vertically at a speed of [tex]u=293\ m/s[/tex]

Final velocity of the spacecraft is [tex]v=0[/tex]

using equation of motion i.e. [tex]v^2-u^2=2as[/tex]

Insert the values

[tex]\Rightarrow 0-(293)^2=2\times a\times (34.7\times 10^3)\\\\\Rightarrow a=-\dfrac{293^2}{2\times 34.7\times 10^3}\\\\\Rightarrow a=-1.23\ m/s^2[/tex]

Therefore, magnitude of acceleration is [tex]1.23\ m/s^2[/tex].

Answer:

Energy =  1.5032*10^(-10) Joules

Explanation:

By Einstein's relativistic energy equation, we know that the energy of a given particle is given by:

Energy = rest energy + kinetic energy.

            = m*c^2  + (γ - 1)*mc^2

Where γ depends on the velocity of the particle.

But if the proton is at rest, then the kinetic energy is zero, and γ = 1

Then the energy is just given by:

Energy = m*c^2

Where we know that:

mass of a proton = 1.67*10^(-27) kg

speed of light = c = 2.9979*10^(8) m/s

Replacing these in the energy equation, we get:

Energy = ( 1.6726*10^(-27) kg)*( 2.9979*10^(8) m/s)^2

Energy = 1.5032*10^(-10) kg*m^2/s^2

Energy =  1.5032*10^(-10) J

Answer:

[tex]V_g=63.3m/s[/tex]

Explanation:

From the question we are told that:

Speed of Plane [tex]v_s=60m/s[/tex]

Wind speed [tex]V_w=20m/s[/tex]

Generally the equation for Speed of plane relative to the ground V_g is mathematically given by

 [tex]V_g=\sqrt{V_s^2+V_w^2}[/tex]

 [tex]V_g=\sqrt{60^2+20^2}[/tex]

 [tex]V_g=\sqrt{4000}[/tex]

 [tex]V_g=63.3m/s[/tex]

Answer: The mass of the second sphere is 8.76 kg

Explanation:

The equation for a perfectly inelastic collision follows:

[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]

where,

[tex]m_1\text{ and }u_1[/tex] are the mass and initial velocity of first sphere

[tex]m_2\text{ and }u_2[/tex] are the mass and initial velocity of second sphere

v = final velocity of the system

We are given:

[tex]m_1=4.38kg\\u_2=0m/s\\v=\frac{u_1}{3}[/tex]

Rearranging the above equation, we get:

[tex]m_1u_1-m_1v=m_2v\\\\m_2=m_1\frac{u_1-v}{v}\\\\m_2=m_1(\frac{u_1}{v}-1)[/tex]

Plugging values in the above equation, we get:

[tex]m_2=4.38(\frac{3u_1}{u_1}-1)\\\\m_2=(4.38\times 2)=8.76kg[/tex]

Hence, the mass of the second sphere is 8.76 kg

Answer:

7.47×10¯⁷ J

Explanation:

From the question given above, the following data were obtained:

Charge (Q) = 4.33×10¯⁷ C

Potential difference (V) = 3.45 V

Energy (E) =?

The energy stored in a capacitor is given by the following equation:

E = ½QV

Where

E => is the energy.

Q => is the charge.

V => is the potential difference.

With the above formula, we can obtain the energy stored in the capacitor as follow:

Charge (Q) = 4.33×10¯⁷ C

Potential difference (V) = 3.45 V

Energy (E) =?

E = ½QV

E = ½ × 4.33×10¯⁷ × 3.45

E = 7.47×10¯⁷ J

Thud, the energy stored in the capacitor is 7.47×10¯⁷ J

Answer:

The answer would be 7.47x10^-7J

Explanation:

Put in 7.47 then -7

Answer:

Magnetic Field

Explanation:

The area around a magnet containing all of magnetic Lines of force is called the magnetic field.

Answer:

d

Explanation:

there is not enough information about the liquid to know the force required for each. ie. stirring a cup of water is different than stirring a cup of pudding.