Answer:
96%
Explanation:
Step 1: Write the balanced neutralization reaction
Al(OH)₃ + 3 HCl ⇒ AlCl₃ + 3 H₂O
Step 2: Calculate the theoretical yield of AlCl₃
According to the balanced equation, the mass ratio of Al(OH)₃ to AlCl₃ is 81.03:133.34.
28 g Al(OH)₃ × 133.34 g AlCl₃/81.03 g Al(OH)₃ = 46 g AlCl₃
Step 3: Calculate the percent yield of AlCl₃
The real yield of AlCl₃ is 44 g. We can calculate the percent yield using the following expression.
%yield = real yield / theoretical yield × 100%
%yield = 44 g / 46 g × 100% = 96%
Which bodies of water in the list are found to the west of the Philippines?
Answer:
South China sea
Explanation:
To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).
If a light beam strikes a shiny object at a 90-degree angle, to what are the angle of incidence and the angle of reflection equal?
Answer:
Angle of incidence = angle of reflection = 0
Explanation:
Given that,
A light beam strikes a shiny object at a 90-degree angle.
The angle made by incident ray and normal to the mirror is called the angle of incidence and the angle made by the reflected ray and the normal is called the angle of reflection.
Here, the beam strikes normally. So, the angle of incidence is 0.
A/c to the law of reflection,
Angle of incidence = angle of reflection
So, the angle of reflection is also equal to 0.
If the distance the pepper flakes moved were a measure of the strength of the intermolecular force, would you say the effect was stronger or weaker in hand sanitizer compared to soap
Answer:
In the given case, the pepper flakes are considered virus particles. One of the applications of the principle of "like dissolves like" is the behavior of hand sanitizers and soaps. The polar molecules like alcohols comprise -OH as the functional groups, which are fascinated towards the water, thus, producing robust intermolecular associations. In comparison, the nonpolar molecules like fats and oils, proteins comprise hydrocarbon groups, which are hydrophobic to water.
The active constituents of both hand sanitizers and soaps show the features of both nonpolar and polar regions in their molecular compositions. As a consequence, part of the molecule is fascinated by water, while some parts are attracted towards organic molecules like fats and proteins.
The virus particles are enveloped with different kinds of proteins and fats, so when soaps and hand sanitizers come in contact with the virus, the nonpolar regions of sanitizers and soaps get fascinated towards the coating, and efficiently pulls apart the virus composition.
In the given case, one can model the principle by assuming pepper flakes as virus particles, which are coated with fats and proteins, and thus are insoluble in water. After this, one can simultaneously see the effect of soaps and sanitizers by using them one by one.
How many grams of oxygen are present in 93.98 g of CO2?
Answer:
There are about 68.33 grams of oxygen present in 93.98 g of CO2.
Suppose one was doing this experiment in the real world and the stockroom ran out of NaCl solutions. Which other solutions of similar concentration could be used in place of NaCl(aq)
Answer:
Polyethylene glycol
Explanation:
Because of the corrosive nature of Brine solution (solution of NaCl) , we can use organic liquid polyethylene glycol .
If a swimming pool contains 2850 kg liters of water how many gallons of water does it contain
Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures PA and inside the flasks are measured.
a. PA will be greater than
b. PA will be less than PB
c. PA will be equal to PB
d. It's impossible to predict whether PA or will be greater without more information.
The question is incomplete, the complete question is:
Liquid A is known to have a lower viscosity and lower vapor pressure than Liquid B. Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures [tex]p_A[/tex] and [tex]p_B[/tex] inside the flasks are measured.
a. [tex]p_A[/tex] will be greater than
b. [tex]p_A[/tex] will be less than [tex]p_B[/tex]
c. [tex]p_A[/tex] will be equal to [tex]p_B[/tex]
d. It's impossible to predict whether [tex]p_A[/tex] or will be greater without more information.
Answer: The correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
Explanation:
Vapor pressure is defined as the equilibrium pressure which is exerted by the vapor phase to be in thermodynamic equilibrium with its condensed state (liquid phase) in a closed system at a given temperature.
We are given:
Vapor pressure of A < Vapor pressure of B
This means that a lesser number of gaseous molecules will form over its surface and thus, will experience lower pressure.
Thus, [tex]p_A<p_B[/tex]
Hence, the correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
g Calculate the moles of methanol in a first distillate that has a total volume of 0.5 mL and contains 23.4% methanol. The density of methanol is 0.791 g/mL, and the molar weight of methanol is 32.04 g/mol. 2.9 x10-3 mol Methanol 9.3 x10-3 mol Methanol 1.17 x 10-2 mol Methanol None of the above
Answer:
2.9 × 10⁻³ mol
Explanation:
Step 1: Calculate the volume of methanol
0.5 mL of distillate contains 23.4% methanol.
0.5 mL × 23.4% = 0.117 mL
Step 2: Calculate the mass corresponding to 0.117 mL of methanol
The density of methanol is 0.791 g/mL.
0.117 mL × 0.791 g/mL = 0.0925 g
Step 3: Calculate the moles corresponding to 0.0925 g of methanol
The molar weight of methanol is 32.04 g/mol.
0.0925 g × 1 mol/32.04 g ≈ 2.9 × 10⁻³ mol
Given that vat contains 9600 kg of milk, what is the mass of mg of the milk that vat contains?
Answer:
9.6x10⁹ mg
Explanation:
In order to solve this problem we need to convert 9600 kg into mg.
First we convert 9600 kg into g, keeping in mind that 1 kg = 1000 g:
9600 kg * [tex]\frac{1000g}{1kg}[/tex] = 9.6x10⁶ g
Then we convert 9.6x10⁶ g into mg, keeping in mind that 1 g = 1000 mg:
9.6x10⁶ g * [tex]\frac{1000mg}{1g}[/tex] = 9.6x10⁹ mg
The mass of milk miligrams is 9.6x10⁹.
An aqueous salt solution is 15.0% mass sodium chloride. How many grams of salt are in 250.0 grams of this solution? Use correct
significant figures.
Answer:
37.5 g NaCl
Explanation:
Step 1: Given data
Concentration of NaCl: 15.0% m/mMass of the solution: 250.0 gStep 2: Calculate how many grams of NaCl are in 250.0 g of solution
The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.
250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the metal (M). Please provide your answer in 2 decimal places.
a. How many moles of oxygen atoms are found in 4.00 g of O2?
b. How many atoms of hydrogen are found in 0.400 mol of H2S?
c. How many hydrogen atomsare present in 0.235 g of NH3?
Answer:
See solution.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:
[tex]\% M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\% =\frac{m_M}{m_M+32.00}*100 \%[/tex]
Thus, we solve for the molar mass of the metal to obtain:
[tex]59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol[/tex]
For the subsequent problems, we proceed as follows:
a.
[tex]4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2[/tex]
b.
[tex]0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH[/tex]
c.
[tex]0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH[/tex]
Regards!
The ideal gas law is PV = nRT.
Use 8.31 for R. (8.31 Lx kPa / Kx mol)
What is the temperature of 3.0 moles of a gas that is in a closed container of
volume 9L, and has a pressure of 85kPa?
1. 3.4 kelvin
2. 0.03 kelvin
3. 30.7 kelvin
4. 28.6 kelvin
Answer: 30.66945 kelvin
Explanation:
If A Reaction Takes 10s To Go To Completion At 0°C, How Long Will It Take To Go At 100°C?
Answer:
1,000s
Explanation:
i just multiply it
If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.
What is reaction ?A chemical reaction is a procedure that causes one group of chemical components to change chemically into another.
Combination, decomposition, single-replacement, double-replacement, and combustion are the five fundamental types of chemical reactions. You can classify a reaction into one of these groups by looking at the reactants and products. Several categories will apply to some reactions.
When atoms establish or break chemical bonds, chemical processes take place. Reactants are the substances that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.
Thus,If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.
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PLEASE HELP ME!! WORTH 30 POINTS!!!
Drag the labels to the image. Each label can be used more than once.
Ryan holds a ball still at position A and then releases it. His friend stops the ball at position F. The image shows the path of the ball from position A to position F. Identify the kind of energy the ball has at each position
PE
KE
PE and KE
The kind of energy the ball has at each position are A: PE,B: KE,C: KE,D: PE and KE,E: KE,F: PE.
What is the energy ?Energy is defined as the capacity for doing work. It is a fundamental concept in physics, and can take many forms, such as thermal, electrical, kinetic, potential, light, and sound energy. Energy is the ability to cause change, and it is present in all physical processes. All forms of energy can be converted into each other, and they are often interlinked in complex ways. For example, electricity can be created from light energy, and energy can be stored in batteries. In the natural world, energy is used to power physical and chemical processes, such as digestion, photosynthesis, and respiration.
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Suppose that you add 21.0 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the added solute, you find that there is a freezing point depression of 2.58 oC compared to pure benzene. What is the molar mass (in g/mol) of the unknown compound
PLS HELP ME PLZ AND THANKS
Answer:
q6= third option
q7= third option
Explanation:
kinetic molecular theory deals with temperature
pressure inversely proportional to volume so when volume doubled, pressure halved given that mass and temperature constant
1.00 mL of 12.0 M HCl is added to 1.00 L of a buffer that contains 0.110 M HNO2 and 0.170 M NaNO2. How many moles of HNO2 and NaNO2 remain in solution after addition of the HCl
Answer:
Moles of NaNO2 = 0.158
Moles of HNO2 final = 0.098
Explanation:
Given
Moles of HCl = 12
Moles of HNO2 = 0.11
Moles of NaNO2 = 0.170
HCl +NaNO2 --> HNO2 + NaCl
1 mole of HCl react with one mole of NaNO2 to produce 1 mole of NaCl and 1 mole of HNO2
Moles of NaNO2 = 0.17 - 0.012 = 0.158
Moles of HNO2 final = 0.11 - 0.012 = 0.098
Two hundred forty-eight milliliters of an acid with an unknown concentration are titrated with a base that has a
concentration of 1.4 M. The indicator changed color when 82 milliliters of base were added. What is the concentration of
the unknown acid?
O 0.46 M
4.2 M
Answer:0.46
Explanation:
Which one of the mixtures would most likely produce a chemical reaction?
F2 + At- OR At2 + F-
Answer:
F₂ + At⁻
Explanation:
Astatine is the only Halogen that does not exist as a diatomic molecule. One Astatine atom would have a charge of 1⁻. Fluorine is the most electronegative element, and therefore very reactive and commonly forms a diatomic molecule.
A hot air balloon is filled to 1250 m3 at 27 C. At what temperature will the balloon be filled to 1600 m3 if the pressure remains constant?
Please help!!
Answer:
384.2 K
Explanation:
First we convert 27 °C to K:
27 °C + 273.16 = 300.16 KWith the absolute temperature we can use Charles' law to solve this problem. This law states that at constant pressure:
T₁V₂=T₂V₁Where in this case:
T₁ = 300.16 KV₂ = 1600 m³T₂ = ?V₁ = 1250 m³We input the data:
300.16 K * 1600 m³ = T₂ * 1250 m³
And solve for T₂:
T₂ = 384.2 K
The atomic particle with a charge of -1.6 x 10-19 C is
no sefdrcdftrgfkjj jhhhgfd
3 enzimas presentes en nuestro organismo e indique en que procesos actúan
Answer:
ATP asa, Helicasa, Proteasa, ARN polimerasa
Explanation:
Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.
Al momento de referirse a ellas, se utiliza la terminación asa.
ATPasa → Sintetizando ATP para el funcionamiento celular
Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.
Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.
ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.
Calculate the pKa of hypochlorous acid (HClO, a weak acid). A 0.015 M solution of hypochlorous acid has a pH of 4.64.
Answer:
"7.46" is the correct answer.
Explanation:
Given that:
[tex]pH=4.64[/tex]
[tex]C=0.015 \ M[/tex]
The equation:
⇒ [tex]HA \rightleftharpoons H^++A^-[/tex]
HA = C - Cα
H⁺ = Cα
A⁻ = Cα
now,
⇒ [tex]pH=-log(H^+)[/tex]
[tex]=-log(C \alpha)[/tex]
[tex]=4.64[/tex]
[tex]C \alpha = 2.3\times 10^-5 \ M[/tex]
As we know,
⇒ [tex]K_a=C \alpha^2[/tex]
[tex]=(\frac{C \alpha}{C} )^2\times C[/tex]
[tex]=\frac{(2.3\times 10^{-5})^2}{0.015}[/tex]
[tex]=3.5\times 10^{-8}[/tex]
hence,
⇒ [tex]pK_a=-log(K_a)[/tex]
[tex]=7.46[/tex]
Two experiments were conducted in a bomb calorimeter. The first one to determine the heat capacity of the calorimeter, the second the heat of combustion of the carcinogenic substance benzene (C6H6). a. In the first experiment, the temperature rises from 22.37 o C to 24.68 o C when the calorimeter absorbs 5682 J of heat. Determine the heat capacity of the calorimeter. Page 3 of 4 b. In the second experiment, the combustion of 0.258 g of benzene increases the temperature from 22.37 o C to 26.77 o C. Determine the heat of combustion for 1 mol of benzene.
Answer:
The right solution is:
(a) 2459.74 J/degree C
(b) 3271.769 KJ/moles
Explanation:
According to the question,
(a)
The heat capacity of the calorimeter will be:
= [tex]\frac{5682}{24.68-22.37}[/tex]
= [tex]\frac{5682}{2.31}[/tex]
= [tex]2459.74 \ J/degree \ C[/tex]
(b)
The change in temperature will be:
= [tex]26.77-22.37[/tex]
= [tex]4.4 \ Degree \ C[/tex]
The amount of heat released will be:
= [tex]2459.74\times 4.4[/tex]
= [tex]10822 \ Joules[/tex]
or,
= [tex]10.822 \ KJ[/tex]
Moles of benzene combusted will be:
= [tex]\frac{0.258}{78}[/tex]
= [tex]0.00330 \ Moles[/tex]
hence,
The heat combustion for 1 mol of benzene will be:
= [tex]\frac{10.822}{0.00330}[/tex]
= [tex]3271.769 \ KJ/moles[/tex]
What is the product of the unbalanced equation below?
Ca(s) + O2(g)
A. CaO2(5)
B. Cao(s)
C. 2Ca(s) + O2(9)
D. Ca20(s)
Answer:
I think B
Explanation:
2Ca + O2 -> 2CaO
The product of the unbalanced equation: [tex]\rm Ca(s) + O_2(g)[/tex] is [tex]\rm CaO(s)[/tex]. The correct answer is option B.
A product is a material which arises from a chemical process. It is the end result of the reaction and is produced by the rearrangement of the atoms or molecules of the reactants.
This reaction's balanced chemical equation is:
[tex]\rm 2Ca(s) + O_2(g) \rightarrow 2CaO(s)[/tex]
The reaction begins by heating calcium metal in the presence of oxygen gas or by exposing calcium metal to oxygen-containing air. Calcium oxide [tex](\rm CaO)[/tex] is formed by the reaction of calcium metal (Ca) with oxygen gas[tex]\rm (O_2)[/tex].
In this equation, two atoms of calcium react with one molecule of oxygen gas to form two molecules of calcium oxide. The reaction is exothermic, meaning it releases heat energy.Therefore, the result of the stated chemical reaction is [tex]\rm CaO(s)[/tex]. Option B is the correct answer.
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Explain the science of water pressure
"At sea level, the air that surrounds us presses down on our bodies at 14.7 pounds per square inch . (gooxgle) "
Basically the deeper you go under the water, whether that be a pool or the sea the pressure will increase because of the weight of the water above you. Which causes greater force.
Calculate the lattice energy of CuBr(s) using a Born–Haber cycle.
Data:
Enthalpy of sublimation of Cu(s) = 337.7 kJ/mol
1st ionization energy of Cu(g) = 745 kJ/mol
Enthalpy of vaporization of Br2(l) = 29.96 kJ/mol
PLEASE HELP ME SOLVE THIS.Thank you so much!
Answer: The coefficients for the given reaction species are 1, 6, 2, 3.
Explanation:
The given reaction equation is as follows.
[tex]Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}[/tex]
Now, the two half-reactions can be written as follows.
Reduction half-reaction: [tex]Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}[/tex]
This will be balanced as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O[/tex] ... (1)
Oxidation half-reaction: [tex]Cl^{-} \rightarrow Cl_{2} + 1e^{-}[/tex]
This will be balanced as follows.
[tex]6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-}[/tex] ... (2)
Adding both equation (1) and (2) we will get the resulting equation as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O[/tex]
Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.
Select the correct answer.
Which value of Keq represents a scenario where the reactants of an equilibrium reaction are favored?
A.
Keq=1
B.
Keq = 6.0 x 10-2
O C.
Keq = 3.8 x 104
OD
Keq = 490.5
O E. Keq = 2.5
Answer:
B. Keq = 6.0 x 10-2.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to remember that any equilibrium constant is computed by dividing the concentration of products by that of reactants:
[tex]Keq=\frac{[Prod]}{[Reac]}[/tex]
Thus, a reaction that is reactant-favored will have a Keq>1 because the concentration of reactants prevail over that of products at equilibrium, and thus, the correct answer is B. Keq = 6.0 x 10-2.
Regards!
Which compounds, on heating with an excess of concentrated sulfuric acid, produce only one product with molecular formula C7H10? [choices on the picture]
Answer:
1 and 2
Explanation:
When Concentrated H2SO4 reacted with the alcohols, they produce cycloalkenes. This is a mechanism known as dehydration of alcohols with an acid catalyst. This is because concentrated H2SO4 acts as a great oxidizing agent. In the process, the alcohols are heated to a high temperature with an excess of pure sulfuric acid. By passing the gases through a sodium hydroxide solution, the carbon dioxide and sulfur dioxide produced by reactive species are eliminated. The reaction mechanism shown in the image below indicates that only compounds 1 and 2 produce only one product.