Physics College

If a central air conditioner (at its highest wattage) runs for 8 hours, how much energy is used?
A)4 kwh
B)8 kwh
C) 32 kwh
D)60 kwh

Answers

Answer 1

The central air conditioner's energy consumption while it operates at its maximum wattage for 8 hours: 40 kWh.

If a central air conditioner (at its highest wattage) runs for 8 hours, how much energy is used?

We need to know the air conditioner's power usage in watts (W) and how long it runs for in hours in order to determine the energy it consumes (h). Calculating energy usage uses the following formula:

Power (W) x Time (h) / 1000 = Energy (kWh)

We can determine the energy usage as follows if we assume that the air conditioner uses 5000 watts (5 kW) of power at its peak wattage for 8 hours:

Power (W) x Time (h) / 1000 = Energy (kWh)

Energy (kWh) = 5000 W x 8 hours / 1,000

Energy is equal to 40 kWh.

Consequently, choice D corresponds to the central air conditioner's energy consumption while it operates at its maximum wattage for 8 hours: 40 kWh.

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Related Questions

define power of a lens. the focal length of a lens is -10 cm. write the nature of the lens and find its power. if an object is placed at a distance of 20cm from the optical centre of this lens, according to the New Cartesian Sign Convention, what will be the sign of magnification in this case​

Answers

The power of a lens is the degree to which it can converge or diverge light rays and is expressed in dioptres (D).

Lens explained.

The power of a lens is the degree to which it can converge or diverge light rays and is expressed in dioptres (D). It is defined as the reciprocal of the focal length of the lens in meters.

Given that the focal length of the lens is -10 cm, we can convert it to meters by dividing it by 100:

f = -10 cm = -0.1 m

The negative sign indicates that the lens is a diverging lens, also known as a concave lens.

To find the power of the lens:

P = 1/f = 1/(-0.1 m) = -10 D

Therefore, the power of the lens is -10 dioptres.

If an object is placed at a distance of 20 cm from the optical centre of this lens, according to the New Cartesian Sign Convention, the object distance is positive (u = 20 cm). Since the lens is a diverging lens, the image formed will be virtual, erect and smaller than the object. The image distance will be negative (v < 0).

Using the formula for magnification:

m = -v/u

We get:

m = -(-10 cm) / (20 cm) = 0.5

Therefore, the negative sign indicates that the image is inverted, but since it is a virtual image, we say it is erect. The magnitude of magnification is less than 1, which means the image is smaller than the object.

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What is the Mass of a 80 n dog

Answers

Answer:

80 n

Explanation:

A box of mass 32.0 kg slides to the right across a horizontal surface with a coefficient of kinetic friction 0.50 while being pulled horizontally by a 750.0 N force. What is the acceleration of the box? Make sure your answer is in MKS units.​

Answers

The acceleration of the box when pulled horizontally by a 750.0 N force is a = 2.4 m/s2

The acceleration of the box can be calculated by using the equation

a = (F - (μk*M*g))/M,

where

F is the force pulling the box,

μk is the coefficient of kinetic friction,

M is the mass of the box, and

g is the acceleration due to gravity.

In this case,

F = 750N,

μk = 0.50,

M = 32.0 kg, and

g = 9.81 m/s2.

Therefore, the acceleration of the box can be calculated as follows:

a = (750N - (0.50*32.0 kg*9.81 m/s2))/32.0 kg = 2.4 m/s2.

The equation used to calculate the acceleration of the box takes into account the force pulling the box and the frictional force acting against it. The frictional force is determined by the coefficient of kinetic friction, which is a measure of the resistance to motion between two surfaces, and the mass of the box.

The acceleration of the box is also affected by gravity, which is why the acceleration due to gravity is included in the equation. Knowing the force and friction acting on the box, we can calculate the acceleration of the box.

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We build a mount with a convergent lens and an object of size 3 cm and we obtain on a screen an object of size 6 cm. The object is at a distance 10 cm from the convergent lens. How far does the screen need to be placed to make the image clean?

Answers

Let distance of screen from lens is V magnification

m = v/u

|m| = h1/h0 = |v|/|u|

6/3 = v/10

v = (6 * 10)/3

v = 20 cm

An object moves from position x = -1.88 m to x = -4.27 m. What is it's displacement?

Answers

Answer: Displacement = -2.39 m

Explanation: The displacement of an object is the difference between its final position and its initial position. In this case, the object moved from x = -1.88 m to x = -4.27 m, so its displacement is:

Displacement = Final position - Initial position

Displacement = (-4.27 m) - (-1.88 m)

Displacement = -4.27 m + 1.88 m

Displacement = -2.39 m

Therefore, the displacement of the object is -2.39 m.

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