Answer is given below
Explanation:
When current occurs due to charge flow, it is called conduction. Since there are no conductors between the plates of the capacitor, there is no charge transfer between them and the conduction current becomes zero. However, when the capacitor is charged, the charges accumulate on the plates and, therefore, the electric field across the plates E increases with time. This variation of the electric field in the plates of the capacitor is called the displacement current, so in the displacement current, there is no electric current due to the movement of the charges, but due to the variation of the electric field between the two points.so I ∝ Rate of accumulations of the charge across plate capacitorI = [tex]\frac{dQ}{dt}[/tex] I = i (cond)I = 1 AA projectile is launched from ground level with an initial speed of 47 m/s at an angle of 0.6 radians above the horizontal. It strikes a target 1.7 seconds later. What is the vertical distance from where the projectile was launched to where it hit the target.
Answer:
30.67m
Explanation:
Using one of the equations of motion as follows, we can describe the path of the projectile in its horizontal or vertical displacement;
s = ut ± [tex]\frac{1}{2} at^2[/tex] ------------(i)
Where;
s = horizontal/vertical displacement
u = initial horizontal/vertical component of the velocity
a = acceleration of the projectile
t = time taken for the projectile to reach a certain horizontal or vertical position.
Since the question requires that we find the vertical distance from where the projectile was launched to where it hit the target, equation (i) can be made more specific as follows;
h = vt ± [tex]\frac{1}{2} at^2[/tex] ------------(ii)
Where;
h = vertical displacement
v = initial vertical component of the velocity = usinθ
a = acceleration due to gravity (since vertical motion is considered)
t = time taken for the projectile to hit the target
From the question;
u = 47m/s, θ = 0.6rads
=> usinθ = 47 sin 0.6
=> usinθ = 47 x 0.5646 = 26.54m/s
t = 1.7s
Take a = -g = -10.0m/s (since motion is upwards against gravity)
Substitute these values into equation (ii) as follows;
h = vt - [tex]\frac{1}{2} at^2[/tex]
h = 26.54(1.7) - [tex]\frac{1}{2} (10)(1.7)^2[/tex]
h = 45.118 - 14.45
h = 30.67m
Therefore, the vertical distance is 30.67m
A woman is standing at the rim of a nonuniform cylindrical horizontal platform initially at rest. The platform is free to rotate about frictionless orthogonal axle that goes through its center and has 4 m in diameter and moment of inertia of 500 kgm2. The woman then starts walking along the rim in clockwise direction at a constant speed of 1.50 m/s relative to the Earth. If a woman has 60 kg, how much work does she do to set herself and the platform into motion?
Answer:
e
Explanation:
i took it myself and got it right
A spherical balloon is being inflated. Find the rate of increase of the surface area (S = 4Ï€r2) with respect to the radius r when r is each of the following. (Answers in unit ft2/ft)
(a) 1 ft
(b) 3 ft
(c) 6 ft
Answer:
A) 8π ft²/ft
B) 24π ft²/ft
C) 48π ft²/ft
Explanation:
Surface area of the spherical balloon is not clear here but it is supposed to be;
S = 4πr²
where:
r is the radius of the spherical balloon
So thus, the rate of change of the surface area of the spherical balloon by its radius will be:
dS/dr = 8πr
A) at r = 1ft;
dS/dr = 8 × π × 1
dS/dr = 8π ft²/ft
B) at r = 3 ft;
dS/dr = 8 × π × 3
dS/dr = 24π ft²/ft
C) at r = 6ft;
dS/dr = 8 × π × 6
dS/dr = 48π ft²/ft
An alpha particle (charge +2e) and an electron move in opposite directions from the same point, each with the speed of 2.80×10^5 m/s . Find the total magnetic field these charges produce at point P, which is 8.25 nm from each charge. μ0=4πx10^-7 H/m, 1nm= 10^-9 m.
Answer:
Explanation:
Magnetic field due to moving charge =
[tex]B=\frac{\mu_0}{4\pi} \times \frac{qv}{r^2}[/tex]
q is charge moving with velocity v and r is distance from point at which field is calculated .
For alpha particle
[tex]B_1=\frac{\mu_0}{4\pi} \times \frac{2\times 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}[/tex]
= 0.1316 x 10⁻³ T
For electron
[tex]B_2=\frac{\mu_0}{4\pi} \times \frac{ 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}[/tex]
= .0658 x 10⁻³ T .
Both these magnetic field will be same in direction because direction of equivalent current is same for both the particles .
Hence
Total magnetic field
= B₁ + B₂ = .1974 x 10⁻³
= 1.974 x 10⁻⁴ T .
The total magnetic field produced by these charges at the given point is 1.98 x 10⁻⁴ T.
The given parameters;
charge of the alpha-particle, q = 2espeed of the charges, v = 2.8 x 10⁵ m/sseparation distance, r = 8.25 nmThe magnetic field produced by each charge is calculated using Biot-Savart law;
[tex]B = \frac{\mu _o q}{4\pi } \times \frac{v}{r^2} \\\\B_1 = \frac{(4\pi \times 10^{-7} ) \times (1.602 \times 10^{-19})}{4\pi } \times \frac{2.8 \times 10^5}{(8.25 \times 10^{-9} )^2}\\\\B_1 = 6.6 \times 10^{-5} \ T[/tex]
[tex]B_2 = \frac{(4\pi \times 10^{-7} ) \times (2\times 1.602 \times 10^{-19})}{4\pi } \times \frac{2.8 \times 10^5}{(8.25 \times 10^{-9} )^2}\\\\B_2 = 1.32 \times 10^{-4} \ T[/tex]
The total magnetic field produced by these charges at the given point P;
[tex]B_T = B_1 + B_2\\\\B_T = 6.6\times 10^{-5} \ + \ 1.32 \times 10^{-4}\\\\B_T = 1.98 \times 10^{-4} \ T[/tex]
Learn more here:https://brainly.com/question/12984403
A piece of purple plastic is charged with 9.31×106 extra electrons compared to its neutral state. What is its net electric charge (including its sign) in coulombs?
Answer:
Q = - 1.5 x 10⁻¹² Coulomb
Explanation:
While in the neutral state, the charge on the piece of purple plastic must be zero. So the net charge is due to the charge of the extra electrons. Therefore,
Q = ne
where,
Q = net charge on piece of purple plastic = ?
n = No. of extra electrons on piece of purple plastic = 9.31 x 10⁶ electrons
e = Charge on one electron = - 1.6 x 10⁻¹⁹ Coulomb
Therefore,
Q = (9.31 x 10⁶)(- 1.6 x 10⁻¹⁹ Coulomb)
Q = - 1.5 x 10⁻¹² Coulomb
A 6- F capacitor is charged to 90 V and is then connected across a 700- resistor. What is the initial charge on the capacitor
Answer:
540C.
Explanation:
A capacitor of capacitance C when charged to a voltage of V will have a charge Q given as follows;
Q = CV ----------(i)
From the question, the initial charge on the capacitor is the charge on it before it was connected to the resistor. In other words, the initial charge on the capacitor will have a maximum value which can be calculated using equation (i) above.
Where;
C = 6F
V = 90V
Substitute these values into equation (i) as follows;
Q = 6 x 90
Q = 540 C
Therefore, the initial charge on the capacitor is 540C.
A positive charge moves in the direction of an electric field. Which of the following statements are true?
a. The potential energy associated with the charge decreases.
b. The electric field does positive work on the charge.
c. The electric field does negative work on the charge.
d. The potential energy associated with the charge increases.
e. The electric field does not do any work on the charge.
f. The amount of work done on the charge cannot be determined without additional information.
Answer:
The potential enwrgy associated with charge decreases.
The ele ric field does negative work on the charge.
Explanation:
Answer:
The potential energy associated with the charge decreases
The electric field does positive work on the charge.
Two cylindrical resistors are made from the same material. The shorter one has length L, diameter D, and resistance R1. The longer one has length 8L, diameter 4D, and resistance R2. How do the resistances of these two resistors compare
Answer:
the resistance of the longer one is twice as big as the resistance of the shorter one.
Explanation:
Given that :
For the shorter cylindrical resistor
Length = L
Diameter = D
Resistance = R1
For the longer cylindrical resistor
Length = 8L
Diameter = 4D
Resistance = R2
So;
We all know that the resistance of a given material can be determined by using the formula :
[tex]R = \dfrac{\rho L }{A}[/tex]
where;
A = πr²
[tex]R = \dfrac{\rho L }{\pi r ^2}[/tex]
For the shorter cylindrical resistor ; we have:
[tex]R = \dfrac{\rho L }{\pi r ^2}[/tex]
since 2 r = D
[tex]R = \dfrac{\rho L }{\pi (\frac{2}{2 \ r}) ^2}[/tex]
[tex]R = \dfrac{ 4 \rho L }{\pi \ D ^2}[/tex]
For the longer cylindrical resistor ; we have:
[tex]R = \dfrac{\rho L }{\pi r ^2}[/tex]
since 2 r = D
[tex]R = \dfrac{ \rho (8 ) L }{\pi (\frac{2}{2 \ r}) ^2}[/tex]
[tex]R = \dfrac{32\rho L }{\pi \ (4 D) ^2}[/tex]
[tex]R = \dfrac{2\rho L }{\pi \ (D) ^2}[/tex]
Sp;we can equate the shorter cylindrical resistor to the longer cylindrical resistor as shown below :
[tex]\dfrac{R_s}{R_L} = \dfrac{ \dfrac{ 4 \rho L }{\pi \ D ^2}}{ \dfrac{2\rho L }{\pi \ (D) ^2}}[/tex]
[tex]\dfrac{R_s}{R_L} ={ \dfrac{ 4 \rho L }{\pi \ D ^2}}* { \dfrac {\pi \ (D) ^2} {2\rho L}}[/tex]
[tex]\dfrac{R_s}{R_L} =2[/tex]
[tex]{R_s}=2{R_L}[/tex]
Thus; the resistance of the longer one is twice as big as the resistance of the shorter one.
A particle located at the position vector m has a force N acting on it. The torque about the origin is
Complete question:
A particle located at the position vector r = (i + j) m has a force F = (2i + 3j) N acting on it. The torque about the origin is
Answer:
The torque about the origin is (5k) N.m
Explanation:
The torque about the origin is the vector or cross product of the two vectors.
τ = r x F (N.m)
Where;
τ is the torque about the origin
τ = r x F
τ = (i + j) x (2i + 3j)
For cross product;
i x j = k
i x k = j
j x k = i
i x i = 0
j x j = 0
k x k = 0
τ = (i + j) x (2i + 3j)
τ = (i x 2i) + (i x 3j) + (j x 2i) + (j x 3j)
τ = (0) + (3k)+ (2k) + 0
τ = (5k) N.m
Therefore, the torque about the origin is (5k) N.m
A long straight metal rod has a radius of 2.0 mm and a surface charge of density 0.40 nC/m2. Determine the magnitude of the electric field 3.0 mm from the axis.
Answer:
Explanation:
Gauss Theorem
E2πrL=o2πRL/εo
then
E=oR/(rεo)
E=(0.4*10^-9*2*10^-3) / (3*10^-3*8.85*10^-12)
= 30.13 N/C
An 100 V/m electric field is directed along the x axis. If the potential at the origin is 300 V, what is potential at the point ( -2m, 0) point
Answer:
200volts
Explanation:
Pls see attached file
Answer:
100 V
Explanation:
Electric field E = 100 V/m
Potential at the origin = 300 V
Potential at point (-2m, 0) i.e 2 m behind the origin = ?
From the equation ΔV = EΔd,
ΔV = [tex]V_{0} - V_{x}[/tex]
where [tex]V_{0}[/tex] is the potential at origin,
and [tex]V_{x}[/tex] is the potential at point (-2, 0)
E = electric field
Δd = 0 - (-2) = 2 m
[tex]V_{0} - V_{x}[/tex] = 300 - [tex]x[/tex]
equating, we have
300 - [tex]x[/tex] = 100 x 2
300 - [tex]x[/tex] = 200
[tex]x[/tex] = 100 V
At a certain instant, coil A is in a 10-T external magnetic field and coil B is in a 1-T external magnetic field. Both coils have the same area and are oriented at right angles to the field. Which coil will have a greater emf induced in it
Answer:
Impossible to know without more information about the fields.
Explanation:
Changing the magnetic field induces the external magnetic field, but the information regarding magnetic field variation is not provided. We need to required more information for this
Therefore according to the above explanation the correct option is Impossible to know without more information about the fields.
Hence, the b option is correct
The orbit of a certain a satellite has a semimajor axis of 4.0 x 107 m and an eccentricity of 0.15. Its perigee (minimum distance) and apogee (maximum distance) are respectively
Answer:
100KM and 1kkm
Explanation:
Molecules in the combustion chamber of a rocket engine are in a high state of random motion. When the molecules are expelled through a nozzle in a more ordered state, will their temperature be higher than, lower than, or the same as their initial temperature in the chamber before being exhausted?
Answer:
The temperature of molecules exhausted through the nozzle
is lower than the temperature in the chamber before being exhausted.
Explanation:
Two long, parallel wires carry currents in the same direction. If I1 = 10 A, and I2 = 20 A, and they are d = 1.0 m apart, what is the magnetic field at a point P midway between them?
Answer:
The magnetic field at mid point between two parallel wires is 1.2 x 10⁻⁵ T
Explanation:
Given;
current in the first wire, I₁ = 10 A
current in the second wire, I₂ = 20 A
distance between the two wires, d = 1.0 m
Magnetic field at mid point between two parallel wires is calculated as;
[tex]B = \frac{\mu_o I_1}{2\pi r} + \frac{\mu_o I_2}{2\pi r} \\\\B = \frac{\mu_o }{2\pi r}(I_1 +I_2)[/tex]
where;
r is the midpoint between the wires, = 0.5 m
μ₀ is the permeability of free space, = 4π x 10⁻⁷
[tex]B = \frac{\mu_o }{2\pi r}(I_1 +I_2)\\\\B = \frac{4\pi*10^{-7} }{2\pi *0.5}(10 +20)\\\\B = \frac{4\pi*10^{-7} *30}{2\pi *0.5}\\\\B = 1.2 *10^{-5} \ T[/tex]
Therefore, the magnetic field at mid point between two parallel wires is 1.2 x 10⁻⁵ T
At what speed would a 3.00 x 10^4 kg airplane have to fly and with a momentum of 1.60 x 10^9 kg.m/s
Answer:
5.3×10⁴ m/s
Explanation:
From the question,
Momentum = mass× velocity
M = mV................ Equation 1
Where M = momentum of the airplane, m = mass of the airplane, V = Velocity of the airplane
make V the subject of the equation
V = M/m.................. Equation 2
Given: M = 1.6×10⁹ Kg.m/s, m = 3.0×10⁴ kg
Substitute these values into equation 2
V = 1.6×10⁹/3.0×10⁴
V = 5.3×10⁴ m/s
Identify the term used to describe the ability of a liquid to flow against gravity up a narrow tube.
Answer:
This would be capillary action.
Explanation:
The physics behind it is gravity adhesion. The forces that attract between dissimilar molecules or atoms, in our case the contact area between the particles of the liquid and the particles forming the tube.
In the photoelectric effect, if the intensity of light shone on a metal increases, what will happen?
Answer:
C) There will be more electrons ejected
Explanation:
The number of electrons ejected whenever a photoelectric effect is identified it is proportional to the intensity of the incident light
Nevertheless, the photoelectrons' maximal kinetic energy is independent of their light intensity
Therefore, the maximum speed of the electron ejected doesn't really depend on the light intensity
So, if the intensity rises, only the number of electrons ejected will rised
Therefore the option c is correct
Answer:
C) There will be more electrons ejected
Explanation:
In the photoelectric effect, photons with an energy of E are shone upon a piece of metal, and if the energy of the photons overcome the work function ϕ of the metal, then electrons with will be ejected from the metal with a kinetic energy KE.
E_photon = Φ + KE
Each photon is capable of ejecting one electron from the metal. Therefore, increasing the intensity of the light (the number of photons shone on the metal) will increase the number of electrons ejected from the metal.
A skydiver of mass 80.0 kg jumps from a slow-moving aircraft and reaches a terminal speed of 50.0 m/s. (a) What is her acceleration when her speed is 30.0 m/s
Answer:
6.22²
Explanation:
Given that
Mass of the skydiver, m = 80 kg
Terminal speed of the skydiver, v(f) = 50 m/s
Speed of the skydiver, v(i) = 30 m/s
Acceleration of the skydiver, a = ?
To solve this, we use the formula
W - k v² = ma, where
W = weight of the skydiver
k = constant
v = speed of the skydiver
m = mass of the skydiver
So, if we substitute the values into it we have
W = mg = 80 * 9.8 = 784 N
784 - k 50² = 80 *0
784 - 2500k = 0
784 = 2500k
k = 0.3136
Now, we use this value of k to find the needed acceleration using the same formula at a speed of 30 m/s
784 - 0.3136 * 30² = 80 * a
784 - 0.3136 * 900 = 80a
784 - 282.24 = 80a
497.76 = 80a
a = 497.76 / 80
a = 6.22 m/s²
Thus, we can conclude that the acceleration when the speed of the skydiver is 30 m/s, is 6.22 m/s²
A rod has length 0.900 mm and mass 0.500 kgkg and is pivoted at one end. The rod is not uniform; the center of mass of the rod is not at its center but is 0.500 mm from the pivot. The period of the rod's motion as a pendulum is 1.49 ss. What is the moment of inertia of the rod around the pivot
Answer:
The moment of inertia is [tex]I =0.14 \ kg \cdot m^2[/tex]
Explanation:
From the question we are told that
The length of the rod is [tex]l = 0.900 \ m[/tex]
The mass of the rod is [tex]m = 0.500 \ kg[/tex]
The distance of the center of mass from the pivot is [tex]d = 0.500 \ m[/tex]
The period of the rod's motion is [tex]T = 1.49 \ s[/tex]
Generally the period of the motion is mathematically represented as
[tex]T = 2 \pi * \sqrt{\frac{I}{m* g * d} }[/tex]
Where [tex]I[/tex] is the moment of inertia about the pivot so making [tex]I[/tex] the subject of formula
[tex]I = [\frac{T}{2\pi } ]^2 * m * g * d[/tex]
substituting values
[tex]I = [\frac{1.49}{2* 3.142 } ]^2 * 0.5 * 9.8 * 0.5[/tex]
[tex]I =0.14 \ kg \cdot m^2[/tex]
How much heat had to be put in during the process to increase the internal energy of the gas by 2.00×104 JJ ?
Complete question:
The pv diagram in the figure below (see attached file) shows a process abc involving 0.920 of an ideal gas.
How much heat had to be put in during the process to increase the internal energy of the gas by 2.00×10⁴ J ?
Answer:
The amount of heat required to increase the internal energy of the gas is 2,000 J
Explanation:
Work done in gas is given as;
W = ΔPV
The pressure of the gas at "a" = 2 x 10⁵ Pa
The pressure of the gas at "b" = 5 x 10⁵ Pa
The volume of the gas at "a" = 0.01 m³
The volume of the gas at "b" = 0.07 m³
The work done = (5 x 10⁵ Pa - 2 x 10⁵ Pa) x (0.07 m³ - 0.01 m³)
The work done = 3 x 10⁵ Pa x 0.06 m³
The work done = 18000 J
The work done = 1.8 x 10⁴ J
Determine, the amount of heat required to increase the internal energy of the gas by 2.00×10⁴ J.
1.8 x 10⁴ J + H = 2.00 x 10⁴ J
H = 2.00 x 10⁴ J - 1.8 x 10⁴ J
H = 0.2 x 10⁴ J
H = 2,000 J
Therefore, the amount of heat required to increase the internal energy of the gas by 2.00×10⁴J is 2,000 J
What is the purpose of guarding electrical equipment with exposed parts operating at 50 volts or more?
Answer:
Electrical equipment should be guarded with exposed parts operating at 50 volts or more to avoid the accidental shock and also to prevent accidental contact by workers and their tools.
Explanation:
Electrical guarding involves the process by which electrical equipment are enclosed so that people do not accidentally come in contact with it in order to avoid accidental shock.
Electrical components operating at 50 volts or more must be guarded with covers or other permanent barriers and it should be put where the people that are authorized to it have acess to it.
Besides the gravitational force, a 2.80-kg object is subjected to one other constant force. The objectstarts from rest and in 1.20 s experiences a displacement of (4.20 i - 3.30 j) m, where the direction of jis the upward vertical direction. Determine the other force.
Answer:
the other force= (16.3i + 14.6j)N
EXPLANATION:
Given:
Mass=2.80-kg
t= 1.2s
Since the object started from rest, the origin is (0,0) which symbolize the the object's initial position.
We will need to calculate the magnitude of the displacement using the below formula;
d = (1/2)at2 + v0t + d0
But note that
d0 = 0,( initial position)
v0 = 0( initial position)
a is the net acceleration
d = √[4.202 + (-3.30)2] m = 5.34 m
Hence, the magnitude of the displacement is 5.34 m, then we can make 'a' the subject of formula in the above expression in order to calculate the value for acceleration, note that d0 = 0,( initial position) and v0 = 0( initial position)
d = (1/2)at2
a = 2d/t2 = 2(5.34)/(1.20)2 m/s2 = 7.42 m/s2
the net acceleration is 7.42 m/s2
Acceleration in terms of the vector can be calculated as
a=2(ri - r0)/t^2
Where t =1.2s which is the time
a= 2(4.2i - 3.30j)/ 1.2^2
a=( 5.83i - 4.58j)m/s
now the net force can now be calculated since we have known the value of acceleration, using the formula below;
F(x) = ma - mg
Where a = 5.83i - 4.58j)m/s and g= 9.8m/s
2.8(5.83i - 4.58j)m/s - (2.80 × 9.8)m/s^2
Therefore, the other force= (16.3i + 14.6j)N
A train at rest emits a sound at a frequency of 1057 Hz. An observer in a car travels away from the sound source at a speed of 20.6 m/s. What is the frequency heard by the observer
Answer:
993.52 Hz
Explanation:
The frequency of sound emitted by the stationery train is 1057 Hz.
The car travels away from the train at 20.6 m/s.
The frequency the observer hears is given by the formula:
[tex]f_o = \frac{v - v_o}{v}f[/tex]
where v = velocity of sound = 343 m/s
vo = velocity of observer
f = frequency from source
This phenomenon is known as Doppler's effect.
Therefore:
[tex]f_o = \frac{343 - 20.6}{343} * 1057\\ \\f_o = 322.4 / 343 * 1057\\\\f_o = 993.52 Hz[/tex]
The frequency heard by the observer is 993.52 Hz.
Suppose that the moment of inertia of a skater with arms out and one leg extended is 3.1 kg⋅m2 and for arms and legs in is 0.90 kg⋅m2 . If she starts out spinning at 4.0 rev/s , what is her angular speed (in rev/s) when her arms and one leg open outward?
Answer:
The angular speed (in rev/s) when her arms and one leg open outward is 1.161 rev/s
Explanation:
Given;
moment of inertia of a skater with arms out, [tex]I_{arms \ out}[/tex] = 3.1 kg.m²
moment of inertia of a skater with arms in, [tex]I_{arms \ in}[/tex] = 0.9 kg.m²
inward angular speed, [tex]\omega _{in}[/tex] = 4 rev/s
The angular momentum of the skater when her arms are out and one leg extended is equal to her angular momentum when her arms and legs are in.
[tex]L_{out} = L_{in}[/tex]
[tex]I_{out} \omega_{out} = I_{in} \omega_{in}\\\\\omega_{out} = \frac{ I_{in} \omega_{in} }{I_{out} } \\\\\omega_{out} = \frac{0.9*4}{3.1} \\\\\omega_{out} = 1.161 \ rev/s[/tex]
Therefore, the angular speed (in rev/s) when her arms and one leg open outward is 1.161 rev/s
Transverse waves are sent along a 4.50 m long string with a speed of 85.00 m/s. The string is under a tension of 20.00 N. What is the mass of the string (in kg)?
Answer:
m = 0.0125 kg
Explanation:
Let us apply the formula for the speed of a wave on a string that is under tension:
[tex]v = \sqrt{\frac{F}{\mu} }[/tex]
where F = tension force
μ = mass per unit length
Mass per unit length is given as:
μ = m / l
where m = mass of the string
l = length of the string
This implies that:
[tex]v = \sqrt{\frac{F}{m/l} }\\ \\v = \sqrt{\frac{F * l}{m} }[/tex]
Let us make mass, m, the subject of the formula:
[tex]v^2 = \frac{F * l}{m}\\\\m = \frac{F * l}{v^2}[/tex]
From the question:
F = 20 N
l = 4.50 m
v = 85 m/s
Therefore:
[tex]m = \frac{20 * 4.5}{85^2}\\\\m = \frac{90}{7225}\\ \\m = 0.0125 kg[/tex]
Which types of basketball injuries do you believe the warm-up could prevent? Explain
Answer:
pulling a muscle. putting too much strain on a muscle causing a tear.
Explanation:
Doing warm ups help your muscles adjust to the full extent of a basketball game. Warming up is like stretching, helps your muscles adjust before going full out on the court.
Answer:
Jogging and skipping can prevent any kind of leg injury because they strengthen the whole leg. Walking on heels might prevent an injury to an ankle. I know that basketball players often roll their ankles when they land on other players’ feet after jumping. I haven’t figured out what walking backward could prevent. That might just be an exercise to build skill and agility rather than prevent any kind of injury.
Explanation:
Word for word from edmentum
Refer the attached photo
Answer:
A
Explanation:
since the wooden bat is an opaque object placed after a translucent object, light will come through the plastic sheet but will be unable to go through the bat. hence the dark shadow of the bat on a lit sheet
⦁ Of the following answer choices which provides the best match between an established energy type & its use or traits? a. Chemical energy: radiation c. Potential energy: stored energy b. Kinetic energy: chemical bonds d. Mechanical energy: energy waves
Answer:
Potential energy: stored energy
Explanation:
Energy is the capacity to do work. It exists in various forms which can be converted from one form to another. It is measured in Joules (J).
The energy possessed by an object at rest is called potential energy. It is a form of mechanical energy. It is a stored energy which can be converted to kinetic energy when the object start to move.
The best match between an established energy type and its use or trait as given in the question is: Potential energy: stored energy
What is the work-energy theorem equation?
Answer:
W = Fd = KE =1/2mv²
Explanation:
not sure if that's what your looking for but i'm pretty sure this is it.