If a 15% discount is applied to a 15,000,000 car, what will its price be.

Answer:

V = 60 m³

Step-by-step explanation:

Volume of Triangular Pyramid: V = 1/3bh

Area of Triangle: A = 1/2bh

b = area of bottom triangle (base)

h = height of triangular pyramid

Step 1: Find area of base triangle

A = 1/2(8)(5)

A = 4(5)

A = 20

Step 2: Plug in known variables into volume formula

V = 1/3(20)(9)

V = 1/3(180)

V = 60

Answer:

The ratio of the number of mangoes in the $3 stack to those in the $6 stack is 1 : 2

Step-by-step explanation:

Let the number of mangoes bought by the grocery store be n. Also let the number of mango sold for $3 in one stack be x and the number of mango sold for $6 in the second stack be y.

Therefore:

x + y = z                                  (1)

Also, the mangoes was sold at break even price, that is the cost of the mango and the price it was sold for was the same. Therefore:

Cost of buying = Price it was sold for

The cost of the mango = 5z and the price it was sold for = 3x + 6y

3x + 6y = 5z                            (2)

Substituting z = x + y in equation 1

3x + 6y = 5(x + y)

3x + 6y = 5x + 5y

6y - 5y = 5x - 3x

y = 2x

x / y = 1/ 2 = 1 : 2

The ratio of the number of mangoes in the $3 stack to those in the $6 stack is 1 : 2

9514 1404 393

Answer:

  (a)  1/12

Step-by-step explanation:

The difference of adjacent terms is ...

  1/4 -1/6 = 3/12 -2/12 = 1/12

Answer:

None of the options are correct

Step-by-step explanation:

Let us assume point B is at (x, y) and the center of dilation is at (a, b). Therefore the distance between the two points is:

[tex]Distance =\sqrt{(b-y)^2+(a-x)^2}=11 \\\\\sqrt{(b-y)^2+(a-x)^2}=11[/tex]

If Triangle ABC is then dilated by 3/4, the new coordinate is B'(3/4 (x-a) + a, 3/4 (y - b) + b). The distance between B' and the center of dilation would be:

[tex]Distance =\sqrt{(b-[\frac{3}{4}( y-b)+b])^2+(a-[\frac{3}{4} (x-a)+a])^2}[/tex]

Therefore the distance cannot be gotten until the center of dilation is given

Answer:

1.5 per hour

Step-by-step explanation:

Answer:

The hypotenuse of a right triangle is 4m longer than the shorter leg and 2m longer than the longer leg. What are the lengths of the sides?

Just for variety, consider the hypotenuse = h, the short leg h-4 and the long leg h-2.

c^2 = a^2 + b^2; so h^2 = (h-4)^2 + (h-2)^2; h^2 = h^2 - 8h + 16 +h^2 -4h +4;

h^2 -12h +20 = 0 factors to (h - 10)(h - 2) = 0 so h = 2 or h = 10

Since (h - 2) = (2 - 2) = 0 and a triangle cannot have a side of zero length, 10 is the length of the hypotenuse.

h^2 = (h-4)^2 + (h-2); 10^2 = (10-4)^2 + (10-2); (10)^2 = (6)^2 + (8)

The hypotenuse is 10 cm, short leg 6 cm and long leg 8 cm.

Answer:

Step-by-step explanation:

Given three elements A, B and C related together according to the expression A(B+C), according to distributive property, the element A will be distributed to the rest of the element as shown;

A(B+C) = A(B)+A(C)

A(B+C) = AB + AC (Law of distributivity)

Given the expression according to the question (1−2g+4h)⋅5, in order to use the distributive law to find the equivalent expression, we will use the concept above as shown;

= (1−2g+4h)⋅5

= 5.(1−2g+4h)

= 5(1)-5(2g)+5(4h)

= 5 - 10g + 20h

Hence the equivalent expression using the distributive property is 5 - 10g + 20h

Answer:

5 - 10g + 20h

[tex] 5 day= 120h \\ 600m = 10h \\ 120 + 10 + 4 = 134h[/tex]

Answer:

mate....where is red shaded region....

probably this will help ..... ;)

find the probability that a randomly selected point within the circle falls in the red shaded area

https://brainly.com/question/14113463?utm_source=android&utm_medium=share&utm_campaign=question

Answer:

the correct answer is b. Initially the car is 420 miles from its destination.

Step-by-step explanation:

Answer:

2/13

Step-by-step explanation:

Cdgfsggdehfetgfrhfer

Answer:

9108

Step-by-step explanation:

23^3+(-12)^3+(-11)^3                              remove parentheses

= 23^3-12^3-11^3                                  group difference of two cubes

= (23-12)(23^2+23*12+12^2) + 11^3      factor difference of two cubes

= 11 (23^2+23*12+12^2-11^2)                factor ou 11

= 11(23(23+12) + (12+11)(12-11))              apply difference of two squares

= 11 (23*35+23*1)                                  factor out 23

= 11(23*(35+1))                                       simplify

= 11*23*36                                             convert 11*23 into difference of 2 squares                                                                    

= (17^2-6^2)*6^2                                   expand parentheses

= 102^2-36^2                                       evaluate squares

= 10404 - 1296                                     subtraction

= 9108

(no calculator required)

Step-by-step explanation:

The set of Natural numbers: {1, 2, 3, 4, 5, ...}

The set of Whole numbers: {0, 1, 2, 3, 4, 5, ...} ← it has the number 0

Answer:

water in quarts is in the first jar after 10th pour = 12/11

Step-by-step explanation:

Let X represent first jar and Y represents second jar.

Lets give the initial value of 2 to the first jar which is filled with water. Lets say there are two liters of water in first jar.

Lets give the initial value of 0 to the second as it is empty.

So before any pour, the values are:

X: 2

Y: 0

After first pour the value of jar X becomes:

Previously it was 2.

Now half of water is taken i.e. half of 2

2 - 1 = 1

So X = 1

The value of jar Y becomes:

The half from jar X is added to second jar Y which was 0:

After first pour the value of jar Y becomes:

0 + 1 = 1

Y = 1

After second pour the value of jar X becomes:

Previously it was 1.

Now third of the water in second jar Y is added to jar X

1 + 1/3

=  (3 + 1)/3

= 4/3

X = 4/3

After second pour the value of jar Y becomes:

Previously it was 1.

Now third of the water in Y jar is taken and added to jar X so,

1 - 1/3

=  (3 - 1)/3

= 2/3

Y = 2/3

After third pour the value of jar X becomes:

Previously it was 4/3.

Now fourth of the water in the first jar X is taken and is added to jar Y

= 3/4 * (4/3)

= 1

X = 1

After third pour the value of jar Y becomes:

Previously it was 2/3

Now fourth of the water in the second jar X is added to jar Y

= 2/3 + 1/4*(4/3)

= 2/3 + 4/12

= 1

Y = 1

After fourth pour the value of jar X becomes:

Previously it was 1

Now fifth of the water in second jar Y is added to jar X

= 1 + 1/5*(1)

= 1 + 1/5

=  (5+1) / 5

= 6/5

X = 6/5

After fourth pour the value of jar Y becomes:

Previously it was 1.

Now fifth of the water in Y jar is taken and added to jar X so,

= 1 - 1/5

= (5 - 1)  / 5

= 4/5

Y = 4/5

After fifth pour the value of jar X becomes:

Previously it was 6/5

Now sixth of the water in the first jar X is taken and is added to jar Y

5/6 * (6/5)

= 1

X = 1

After fifth pour the value of jar Y becomes:

Previously it was 4/5

Now sixth of the water in the first jar X is taken and is added to jar Y

= 4/5 + 1/6 (6/5)

= 4/5 + 1/5

= (4+1) /5

= 5/5

= 1

Y = 1

After sixth pour the value of jar X becomes:

Previously it was 1

Now seventh of the water in second jar Y is added to jar X

= 1 + 1/7*(1)

= 1 + 1/7

=  (7+1) / 7

= 8/7

X = 8/7

After sixth pour the value of jar Y becomes:

Previously it was 1.

Now seventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/7

=  (7-1) / 7

= 6/7

Y = 6/7

After seventh pour the value of jar X becomes:

Previously it was 8/7

Now eighth of the water in the first jar X is taken and is added to jar Y

7/8* (8/7)

= 1

X = 1

After seventh pour the value of jar Y becomes:

Previously it was 6/7

Now eighth of the water in the first jar X is taken and is added to jar Y

= 6/7 + 1/8 (8/7)

= 6/7 + 1/7

= 7/7

= 1

Y = 1

After eighth pour the value of jar X becomes:

Previously it was 1

Now ninth of the water in second jar Y is added to jar X

= 1 + 1/9*(1)

= 1 + 1/9

=  (9+1) / 9

= 10/9

X = 10/9

After eighth pour the value of jar Y becomes:

Previously it was 1.

Now ninth of the water in Y jar is taken and added to jar X so,

= 1 - 1/9

=  (9-1) / 9

= 8/9

Y = 8/9

After ninth pour the value of jar X becomes:

Previously it was 10/9

Now tenth of the water in the first jar X is taken and is added to jar Y

9/10* (10/9)

= 1

X = 1

After ninth pour the value of jar Y becomes:

Previously it was 8/9

Now tenth of the water in the first jar X is taken and is added to jar Y

= 8/9 + 1/10 (10/9)

= 8/9 + 1/9

= 9/9

= 1

Y = 1

After tenth pour the value of jar X becomes:

Previously it was 1

Now eleventh of the water in second jar Y is added to jar X

= 1 + 1/11*(1)

= 1 + 1/11

= (11 + 1) / 11

= 12/11

X = 12/11

After tenth pour the value of jar Y becomes:

Previously it was 1.

Now eleventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/11

=  (11-1) / 11

= 10/11

Y = 10/11

Answer:

6/11

Step-by-step explanation:

1/2 + (1/2)(2/11) = 6/11

sus

Answer:

If Jorge goes up 25 (positive) and then goes 75 steps south (negative). Then you have to calculate 25-75. This equals -50. We know negative distance is south so he's final position will be 50 steps south.

Step-by-step explanation:

the answer is in the photo

Answer:

2/5

Step-by-step explanation:

[tex] - 2\frac{4}{5} \div ( - 7)[/tex]

[tex] = \frac{2 \times 5 + 4}{5} [/tex]

[tex] = \frac{10 + 4}{5} [/tex]

[tex] = \frac{14}{5} [/tex]

[tex] = - \frac{14}{5} \times 7[/tex]

[tex] = \frac{14}{5} \div 7[/tex]

[tex] = \frac{2}{5} [/tex]

Answer:

Because <CBD is an inscribed angle and <CAD is a central angle with the same intercepted arc, m<CBD = 55°, or half of the measure of <CAD.

Step-by-step explanation:

The Inscribed Angle Theorem proves that an inscribed angle is half the measure of a central angle, if both the inscribed angle and the central angle intercepts the same arc.

Also, according to the inscribed angle theorem, an inscribed angle is ½ of the measure of the arc it intercepts.

Therefore, m<CBD is half of m<CAD, or half of the measure of the arc CD that they both intercept together.

Thus, m<CBD = 55°, which is ½ of m<arc CD.

m<arc CD = 110° = m<CAD.

m<CBD = ½ of m<CAD = 55°.

The statement that best describes the relationship between <CBD and <CAD is "Because <CBD is an inscribed angle and <CAD is a central angle with the same intercepted arc, m<CBD = 55°, or half of the measure of <CAD."

Answer:

see below

Step-by-step explanation:

The phrase "at least" indicates that you use the symbol ≥, so that's where they got the ≥ from. The amount of water needed for each bushel is 1/3 * f or 1/3f because you need 1/3 gallons of water per one bushel. We know that the amount of water needed is at least 1/3 gallons per bushel. Since the amount of water is w, "at least" is ≥ and 1/3 gallons per bushel is 1/3f, the inequality is w ≥ 1/3f. I hope this makes sense.

Answer:

[tex]cos\alpha =\frac{7}{25}; \ tan\alpha =-\frac{7}{24}.[/tex]

Step-by-step explanation:

if π<α<2π and cotα<0, then 1.5π<α<2π. It means, that cosα>0 and tanα<0.

1) tanα=1/cotα; ⇒tanα= -7/24;

2) [tex]cos\alpha =\frac{1}{\sqrt{1+cot^2\alpha }}}; \ cos\alpha =\frac{7}{25}.[/tex]

Answer:

I have explained the answer in detailed steps for you. If you do not understand any steps, please comment below, and I will help you out.

( a ) Well we know that the limit for the range is 400 dollars, as ( 1 ) her greatest balance was 400 dollars, and ( 2 ) the balance is dependent on the days, and hence represents the range. Respectively the limit for the domain would be 3 weeks.

( b ) Remember that B(0) models the balance over the course of 0 days. As you can see that starting mark is about half of the greatest balance on the graph, 400 dollars. Therefore you can estimate B(0) to be $200.

( c ) B(12) models the balance over the course of 12 days. It mentions that at B(12) the balance reaches $0, so in function notation that would be :

B(12) = 0

( d ) Segment 4 would represent that information. As you can see on the graph, the only time period with which the balance became 0 is represented by the fourth segment.

Answer:

No

Step-by-step explanation:

405 repeating is

405/999

not 405/99

405/99=4.090909090909....

4.05 repeating is not equivalent to 405/99.

A summation, also abbreviated as a sum, is the outcome of adding two or more numbers or quantities.

The division is to divide two numbers by each other example 2/4.

The division is a very common phenomenon in mathematics so we need to divide two numbers or expressions.

Subtraction is a mathematical operation such that two values are going to subtract and give a resultant value.

The most common mathematical operation is multiplication, which involves adding two or more integers to get a new multiplied number.

Given,

405/99

If we divide 405 by 99 then it will go 4 times and leave the remainder as 9.

Further, we make a decimal and again divide it will go 090909091 so it means it is repeating 09 four times.

Hence, 4.05 repeating is not equivalent to 405/99.

To learn more about the arithmetic operator

brainly.com/question/25834626

#SPJ2

25) First, find the amount of minutes in 2 hours. Note that there are 60 minutes in one hour:

2 x 60 = 120 minutes per 2 hours.

Next, the bacteria doubles every 20 minutes. 120/20 = 6, which means that the bacteria will double 6 times:

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 bacteria will be your answer.

~

26) The Area of a circle = πr²

Set the equation:

400π = π(r + 2)²

First, divide common factors from both sides, or π.

(400π)/π = (π(r + 2)²)/π

400 = (r + 2)²

√400 = √(r + 2)²

r + 2 = √400

r + 2 = √(20 x 20)

r + 2 = 20

r + 2 (-2) = 20 (-2)

r = 20 - 2

r = 18

18 is your final answer.

~

27)

The volume of a box can be found by multiplying length x width x height:

[tex]V (box) = l * w * h[/tex]

The volume given is 90, the height 3, and the width is 1 foot less then length:

First solve what you know:

[tex]V(box) = 90\\h = 3\\l = l\\w = l - 1[/tex]

Plug in the corresponding terms with the corresponding variable. Isolate the variable, l. Divide 3 from both sides of the equation:

[tex]90 = 3 * l (l - 1)\\\frac{90}{3} = \frac{3 * l(l -1)}{3}\\30 = l(l - 1)\\[/tex]

Distribute l to both terms in the parenthesis:

[tex]30 = l(l - 1)\\30 = l^2 - l[/tex]

Solve:

[tex]30 = (6)^{2} -6\\30 = 36 - 6\\30 = 30[/tex]

∴ [tex]l = 6[/tex]

Solve for width. Width is 1 less foot then length:

[tex]l - 1 = w\\l = 6\\[/tex]

∴ [tex]6 - 1 = w\\w = 5[/tex]

Equation: [tex]V (box) = l * w * h[/tex]

or

[tex]l = \frac{V(box)}{w * h}[/tex]

[tex]V(box) = 90\\h = 3\\l = 6\\w = 5[/tex]

Answer:

A

Step-by-step explanation:

In this question, we are concerned with selecting which of the options best represents the difference of two squares.

Let’s have an exposition below as follows;

Consider two numbers, which are perfect squares and can be expressed as a square of their square roots;

a^2 and b^2

where a and b represents the square roots of the numbers respectively.

Inserting a difference between the two, we have;

a^2 - b^2

Now by applying the difference of two squares, these numbers will become;

a^2 - b^2 = (a + b)(a-b)

So our answer out of the options will be that option that could be expressed as above.

The correct answer to this is option A

Kindly note that;

x^2 -9 can be expressed as x^2 - 3^2 and consequently, this can be written as;

(x-3)(x + 3)

9514 1404 393

Answer:

  x = (√2)/2

Step-by-step explanation:

The diagonal is √2 times the side length (x), so ...

  1 = x√2

  √2 = 2x . . . . . multiply by √2

  (√2)/2 = x . . . . divide by 2

The side length x is (√2)/2.

Answer:

Geometric mean of a and b: Square root of axb.

16x64 = 1024

Square root of 1024: 32.

So, the geometric mean is 32.

Hope this helps!

Answer:

[tex]{ \boxed{ \bf{c}}} \: \: \frac{3.8}{4} = s[/tex]

Step-by-step explanation:

[tex]{ \tt{4 \: pies \: = \: 3.8 \: ounces}} \\ { \tt{1 \: pie \: = \: ( \frac{1}{4} \times 3.8) \: ounces}} \\ { \tt{ = 0.95 \: ounces}}[/tex]

[tex]{ \underline{ \sf{ \blue{christ \: † \: alone}}}}[/tex]