If 5.60 mol of a substance releases 14.9 kJ when it decomposes, what is ΔH for the process in terms of kJ/mol of reactant?

Answer:

You take the atomic, or proton number of the element, and you subtract it from the element's mass number.

Answer:

protons

Explanation:

neutrons and protons make up the mass of the atom

Answer:

weight of H₂O formed = 2.3 grams H₂O (2 sig. figs.)

Explanation:

Rxn:                  CH₄(g)         +      2O₂(g)          =>     CO₂(g)           +  2H₂O(g)

Given:                 1.16g                   4.16g                     3.52g                  ? (g)

Moles:         1.16g/16g·mol⁻¹    4.16g/32g·mol⁻¹    3.52g/44g·mol⁻¹

                     = 0.0725mol.        = 0.13mol.             = 0.08mol.    => ? (moles)

Limiting Reactant: Divide each mole value by related coefficient of balanced standard equation (that is, balanced with coefficients in lowest whole number ratios). The smaller value is the limiting reactant.

                    0.0725/1                   0.13/2                0.080/1

                    = 0.0725                 = 0.065              = 0.080

Limiting Reactant is O₂(g) => 0.065 is smaller value after dividing each mole value by related coefficient of balanced equation.

NOTE: When working problem, however, one must use the mole value calculated from given amount in grams. That is, in this case 0.13 mole O₂. The 'divide by related coefficient and check smaller value' is ONLY for identifying the limiting reactant. This trick works for ALL general chemistry problems.

Moles H₂O formed: Since the coefficient of the limiting reactant (O₂) equals the coefficient of water (H₂O), then the moles of water formed is 0.065 mole H₂O.

Weight (in grams) of H₂O formed:

Grams H₂O = moles H₂O  x  formula weight H₂O

                   = 0.13 mole H₂O  x  18 g H₂O/mole H₂O

                   = 2.34 g H₂O  (calculator answer)

                   = 2.3 g H₂O  (final answer should be rounded to  2 sig. figs.)                                                                                                                                        => form of final answer should be based on data in final computation having the least number of sig. figs.                                      

Review: Sequence of calculations

       =>  moles of limiting reactant / coefficient of same cpd. in std. equation               = unknown (X) / coefficient of same (unknown) cpd. in std. equation

       => cross multiply and solve for unknown (X)

       => L.R.(moles) / eqn. coef. of L.R. = X / eqn. coef. of X  

       => (L.R.(calc'd moles)(eqn. coef. of X) = (X)(eqn. coef. of L.R.)

       => X (in moles) = (L.R.(calc'd. moles)(eqn. coef. of X) / (eqn. coef. of L.R.)

        => grams = moles x formula wt.                                                                

        => volume (L) = moles x std. volume (= 22.4L/mole)                                  

        => #particles = moles x Avogadro's Number (= 6.02 x 10²³ parts/mole)

Answer:

2.04 moles

Explanation:

Since the ratio of Na2O to NaOH is 1:2, you multiply the number of moles by 2, equaling 2.04 moles.

Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new volume we have

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

First convert 745 mmHg to atm

760 mmHg = 1 atm

745 mmHg = 745/760 = 0.98 atm

We have

[tex]V_2 = \frac{500 \times 0.98}{1.8} \\ = 272.222...[/tex]

We have the final answer as

Hope this helps you

Answer:

C.same as [H+]

Explanation:

Autoionization of water is expressed as H+ * OH-  = Kc

The value of Kc is 1*10^-14. Now simply plug thus in and the value of given H+ to solve

(1*10^-7) * OH- = 1*10^-14

OH- = 1*10^-7

Thus, in this scenario, the H+ and OH- ions have same concentration and solution is said to be neutral.

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Answer: 1.535e42 (or 1.535x10^42) moles of CO2

Explanation: i know this is six days late, but all you have to do for this one is multiply 2.55e18 by the standard mole value, 6.02e23 and your calculator will give you 1.535e42 moles!

Reaction 1 → Al + Zn²⁺ ⟶ Al³⁺ + Zn

Reaction 2 → Al³⁺ + Li ⟶ Al + Li⁺

Reaction 1 :-

Substance Oxidised :- Al

Substance Reduced :- Zn²⁺

Oxidizing Agent :- Zn²⁺

Reducing Agent :- Al

Reaction 2 :-

Substance Oxidised :- Li

Substance Reduced :- Al³⁺

Oxidizing Agent :- Al³⁺

Reducing Agent :- Li

Reaction 1 :-

Al

Zn²⁺

Zn²⁺

Al

Reaction 2 :-

Li

Al³⁺

Al³⁺

Li

Answer:

Q = 20377.5 Joules

Explanation:

Given the following data;

Mass = 75g

Initial temperature = 65°C

Final temperature = 0°C

Specific heat capacity of water = 4.18 J/g°C.

To find the quantity of heat released;

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Substituting into the equation, we have;

[tex] Q = 75 * 4.18 * 65 [/tex]

Q = 20377.5 Joules

Answer:

CATION

Explanation:

If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion. If it loses an electron, it becomes positively charged and is known as a cation.

Answer:

none

Explanation:

It is given that there are 3 cats.

Each of the cats die with different diseases. One of cats died due to heart failure, the second cats died because of brain tumor and the third cat died due to an experiment gone wrong.

So there are none of the cats left out. All the cats died due to different reasons.

P2 = 54.6 kPa

Explanation:

Given:

V1 = 10.0 L. V2 = 50.0 L

P1 = 273 kPa. P2 = ?

We can use Boyle's law to solve this problem.

P1V1 = P2V2

Solving for P2,

P2 = (V1/V2)P1

= (10.0 L/50.0 L)(273 kPa)

= 54.6 kPa

Answer:

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Answer:

Number 3 alkyne is the answer

Explanation:

Answer: The answer is Alkyne.

Explanation:

It's (D), nuclear fission................

Answer:

Extinct

Explanation:

Extinct volcanos are not expected to erupt, and have not erupted in a very long time.

Answer:

7242.1g

Explanation:

The balanced equation for this reaction is as follows:

Mg + 2HCl → MgCl2 + H2

From the above equation, it can be observed that 2 moles of HCl is needed to produce 1 mole of H2.

Using the formula below, we convert the mass of H2 to moles;

Molar mass of H2 = 2.016g/mol

mole = 200/2.016

mole = 99.21mol of H2

Since 2 moles of HCl is needed to produce 1 mole of H2.

Then 99.21 moles of H2 will be produced by 99.21 × 2 = 198.4mol of HCl

Molar mass of HCl = 1 + 35.5

= 36.5g/mol

Mole = mass/molar mass

Mass = molar mass × mole

Mass = 36.5 × 198.4

Mass = 7242.1g

Answer:

The force applied to the object is an external force, from outside the system. When it does positive work it increases the gravitational potential energy of the system. Because gravitational potential energy depends on relative position, we need a reference level at which to set the potential energy equal to 0.

If an object is on top of a hill or in a position raised above the ground, it must have gravitational potential energy.

In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors

If an object is lifted, work is done against the force of gravity.

When work is done energy is transferred to the object and it gains gravitational potential energy.

If the object falls from that height, the same amount of work would have to be done by the force of gravity to bring it back to the Earth’s surface.

Due to the Principle of Conservation of Energy we can say that:

Gravitational potential energy at the top = kinetic energy at the bottom

To know more about Potential Energy

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Answer:

I think it can dissolve 80.0 grams

Answer:

The evolution of the peppered moth is an evolutionary instance of directional colour change in the moth. The frequency of dark-coloured moths increased at that time, an example of industrial melanism.

Explanation:

I did this on Savvas Realize got it right.

Genetic variation is said to be the difference in the hereditary sequence. After the industrial revolution, the frequency of the dark-colored moth increased dramatically more than the light-colored moths.

Industrial melanism was an example of the evolutionary effect that occurred in the moths where the dark-colored species were favored over the light-colored species of peppered moths.

Before the industrial population, light-colored moths were large in number which later decreased with an increase in pollution. This occurred due to an increase in the pollutants and dust deposition that altered the environment.

As the pollution increased over time the dark-colored moths became dominant and increased their population over time. This is an example of industrial melanism as the color of the body was the determining factor in survival.

Therefore, dark-colored moths were prevalent after the industrial revolution.

Learn more about industrial melanism here:

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Count the in between joint bunches of curve lines .

Frequency is 3-1=2

Answer:

divide the mass of element in 1 mole of the compound by the compound's molar mass and multiply the answer by 100.

Explanation:

take the molar mass of hydrogen in the water molecule, divide by the total molar mass of water, and multiply by 100.

does it help?

Answer:

WATER

Explanation:

Water melting  point 0 c boiling 100c

Answer:

Controls the movement of substances into and out of the cell.

Answer:

A toad on lily pad

Explanation:

have a great day

Answer: 6.45 Joules

Explanation: I just did it

Answer:

amount of gas and pressure