Answer:
16.9g
Explanation:Cu+2AgNO3→2Ag+Cu(NO3)2
Cu will likely have a +2 oxidation state. It is higher in the activity series than Ag, so it is a stronger reducing agent and will reduce Ag in a displacement reaction. Then you need to balance the coefficients knowing than NO3 is -1 and Ag is +1.
Then to calculate the theoretical yield you need to compare moles of the reactants:
m(Cu)=5g
M(Cu)=63.55
n(Cu)=5/63.55=0.0787
By comparing coefficients you require twice as much silver: 0.157mol
n(Ag)=0.157
M(Ag)=107.86
m(Ag)=0.157x107.86=16.9g
Hence, the theoretical yield of this reaction would be 16.9g
What has caused air quality in United States to improve/get better since the 1950s?
Answer:
better mileage on cars, took lead out of paint, smaller packaging like for delivery and store products, EPA laws updating
Answer:
Reducing pollution from transportation sources has led to healthier air for Americans. In cities, smog has been visibly reduced.
Explanation:
i hope this helped
Where is the youngest part of the ocean floor found?
A. along the deep sea trenches
B. where ocean sediments are the thickest
C. near ocean ridges
D. where Earth's magnetic field changes polarity
Answer:
the youngest crust of the ocean floor can be found near the seafloor
a 5 g ice cube starts life at -1 C if 2182.5 j are added to it what will be the final temperature upon his demise ?
Answer:
Final Temp = 23.92°C
Explanation:
ΔH(total) = (m·c·ΔT)ice + (m·ΔH(f))melt'g + (m·c·ΔT)water
2182.5j = (5g)(2.092j/g·°C)(1°C) + (5g)(334.56j/g) + (5g)(4.184j/g·°C)(ΔT)
(2182.5 - 10.46 - 1672.8)j = 20.92j/°C·ΔT
ΔT = (2182.5 - 10.46 - 1672.8)j / 20.92j/°C = 23.92°C
Since the melting ice starts and ends at 0°C and is then warmed to 23.92°C then the temperature change is also the final temp of the water based upon given energy input values.
A reaction in the laboratory yields 5.98 g KAI(SO2)2, How many moles of potassium aluminum
sulfate were produced?
Answer:
0.0308 mol
Explanation:
In order to convert from grams of any given substance to moles, we need to use its molar mass:
Molar mass of KAI(SO₂)₂ = MM of K + MM of Al + (MM of S + 2*MM of O)*2Molar mass of KAI(SO₂)₂ = 194 g/molNow we calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g:
5.98 g ÷ 194 g/mol = 0.0308 molHow many moles of helium are needed to fill a balloon to a volume of 6.3 L at 28 °C and 320
mmHg?
Round answer to 0.01 decimals
Answer:
.11 mol
Explanation:
Convert mmHg to atms by dividing by 760. Then multiply 6.3 by the atms and divide by .08206*(273+28) to get mol
When(NH4)2SO4(aq) and Ba(NO3)2(aq) react
Answer:
1 (NH4)2SO4 + Ba(NO3)2 → NH4NO3 + BaSO4
2 (NH4)2SO4 + Ba(NO3)2 → Ba(SO4) + (NH4)(NO3)
Explanation:
What method can be used to separate benzoic acid and potassium carbonate
Answer:
To separate the components, a water wash may be attempted to remove benzoic acid, but benzoic acid is not particularly water-soluble due to its nonpolar aromatic ring, and only small amounts would be extracted into the aqueous layer
The method that can be used to separate Benzoic acid and potassium carbonate is : The application of water wash separation method
Benzoic acid is slightly soluble in cold water but becomes more soluble as the temperature of water is increased. Water wash separation method is a methodology used for the selective removal of unwanted compounds in a mixture.
Separation method based on solubility water wash methodprecipitationThe separation of benzoic acid and potassium carbonate is based on the solubility differences between Benzoic acid and potassium carbonate when dissolved in a solvent ( water ) therefore the water wash separation method is the most effective method.
Hence we can conclude that The method that can be used to separate Benzoic acid and potassium carbonate is : The application of water wash separation method.
Learn more about separation methods : https://brainly.com/question/735172
Please help me with this question!!
Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex] [tex]\text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles[/tex]
[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]
According to stoichiometry :
1 mole of [tex]Cl_2[/tex] produce = 2 moles of [tex]NaCl[/tex]
Thus 7.04 moles of [tex]Cl_2[/tex] will produce=[tex]\frac{2}{1}\times 7.04=14.08moles[/tex] of [tex]NaCl[/tex]
Mass of [tex]NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g[/tex]
Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.
When this gas is burned what will happen to the surface of this type of star?
In a unit circle, ø = pi radians What is the terminal point? A. (1,0) B. (0,-1) C. (0,1) D. (-1,0)
Answer:
(-1,0)
Explanation: