find the mass of an object with a density of 1.5 g/cm^3 and had a volume of 8cm^3
Answer:
12 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volume
From the question we have
mass = 1.5 × 8
We have the final answer as
12 gHope this helps you
Freida wants to model the way atoms move when a substance changes its state. To do this, Freida makes a pyramid of marshmallows. Then, she knocked down the pyramid causing the marshmallows to fall. If the marshmallows represent the atoms in the substance, which change of state is Freida modeling?
Answer:melting 2020 edge
Explanation:
:)
Answer:
Melting
Explanation:
Please select the word from the list that best fits the definition The skeletons of tiny ocean animals grow together to form ______, structures that are found only in warm, clear ocean water.
Answer:
coral reef
Explanation:
A person picking apples stand on a ladder 3.0 m above the ground. He throws them into
a basket 2.0 m away. How fast must the person throw the apple in order for it to land in
the basket?
Answer:
The speed the apple must be thrown in order for it to land in the basket is 2.554 m/s.
Explanation:
Given;
height above the ground, h = 3.0 m
horizontal distance, X = 2.0 m
The time to drop from the given height;
h = ¹/₂gt²
[tex]t = \sqrt{\frac{2h}{g} }\\\\t = \sqrt{\frac{2*3}{9.8} }\\\\t = 0.783 \ s[/tex]
The horizontal speed traveled by the apple is given by;
vₓ = X / t
vₓ = 2 / 0.783
vₓ = 2.554 m/s
Therefore, the speed the apple must be thrown in order for it to land in the basket is 2.554 m/s.
A boy throws a tell ball straight up . disregarding any effects of air resistance, the forces acting 9n the ball untill it returns to the ground is are
If the resistance in the coil is 2.0 , what is the magnitude of the induced current in the coil while the field is changing
This question is incomplete, the complete question is;
A coil consists of 200 turns of wire. Each turn is a square of side 18 cm, and a uniform magnetic field directed perpendicular to the plane of the coil is turned on. If the field changes linearly from 0 to 0.50 T in 0.80 s,
a) what is the magnitude of the induced emf in the coil while the field is changing?
b) if the resistance of the coil is 2.0, what is the magnitude of the induced current in the coil while the field is changing?
Answer:
a) the magnitude of the induced emf in the coil is 4.05 V
b) induced current in the coil I is 2.025 A
Explanation:
Given that;
side of turn a = 18 cm = 0.18 m
no. of turns N = 200
dB = 0.50 T
time t = 0.80 sec
(a)
what is the magnitude of the induced emf in the coil while the field is changing?
we know that the magnetic flux is equal to the product of the magnetic field in a loop and the area of the loop so;
∅ = NBA
expression for the electromotive force is expressed as;
∈ = d∅/dt
Now replace NBA for ∅ in the above equation.
∈ = d(NBA) / dt
= NA(dB/dt)
The expression for the area of each square turn is expressed as follows
A = a²
a is the side of the turn
so we substitute the value of a
A = (0.18) ²
A= 0.0324 m²
As earlier derived
formula for the electromotive force is as follows:
∈ = NA(dB/dt)
so we substitute all our values
∈ = (200)(0.0324m²) (0.50T/0.80s)
∈ = 6.48 × 0.625
∈ = 4.05 V
Therefore the magnitude of the induced emf in the coil is 4.05 V
(b)
if the resistance of the coil is 2.0, what is the magnitude of the induced current in the coil while the field is changing?
we know that the current induced in the circuit is equal to the ratio between the electromotive forces to the resistance of the ring so;
I = ∈ / R
given that; resistance of the coil = 2.0
so we substitute
I = 4.05 / 2.0
I = 2.025 A
Therefore induced current in the coil I is 2.025 A
During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the trebuchet launches the stones with a velocity of +48.5" m"/s at an angle of 42.0°, how long does it take the stone to hit the ground? For those settings, what is the maximum range? How high will the stones go? Show all your work
Answer:
a) t = 6.62 s
b) x = 238.6 m
c) H = 53.7 m
Explanation:
a) We can find the time of flight as follows:
[tex] y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} [/tex]
Where:
[tex]y_{f}[/tex] is the final height = 0
[tex]y_{0}[/tex] is the initial height = 0
[tex]v_{0_{y}}[/tex] is the initial vertical velocity of the stone
t: is the time
g: is the gravity = 9.81 m/s²
[tex] v_{0}sin(42)t - \frac{1}{2}gt^{2} = 0 [/tex]
[tex] 48.5 m/s*sin(42)*t - \frac{1}{2}9.81 m/s^{2}*t^{2} = 0 [/tex]
By solving the above quadratic equation we have:
t = 6.62 s
b) The maximum range is:
[tex] x = v_{0_{x}}t = 48.5 m/s*cos(42)*6.62 s = 238.6 m [/tex]
c) The maximum height (H) can be found knowing that at this height the final vertical velocity of the stone is zero:
[tex] v_{f_{y}}^{2} = v_{0_{y}}^{2} - 2gH [/tex]
[tex] H = \frac{v_{0_{y}}^{2} - v_{f_{y}}^{2}}{2g} = \frac{(48.5 m/s*sin(42))^{2} - 0}{2*9.81 m/s^{2}} = 53.7 m [/tex]
I hope it helps you!