Answer:
4
Step-by-step explanation:
Hope it helps out!
Let y=f(x) be the particular solution to the differential equation dy/dx=(2x−1)/y^2 with the initial condition y(0)=3. Which of the following is an expression for f(x) ?
Answer:
y= (3x^2-3x+27)^1/3
Step-by-step explanation:
Someone help me with this question
the answer is 7 because thats what photo math told me
Answer:
7
Step-by-step explanation:
(8+56)÷4-3^2
PEMDAS:
(64)÷4-3^2
PEMDAS:
(64)÷4-9
PEMDAS:
(16)-9
7
hope this helps
find out the total volume of cube _Edge Length =6 inches
Given:
The edge length of a cube = 6 inches
To find:
The volume of the cube.
Solution:
We know that, the volume of a cube is
[tex]V=a^3[/tex] ...(i)
Where, a is the edge length.
Substituting a=6 in (i), we get
[tex]V=(6)^3[/tex]
[tex]V=216[/tex]
Therefore, the total volume of the cube is 216 cubic inches.
Use the distributive property to remove the parentheses.
4(x+8)
Answer: 18+6w
Step-by-step explanation:
Answer:
4(x+8)
4x+32
4 x X = 4x 4 x 8 = 32
Step-by-step explanation:
Find the area of the shaded region. Round your answer to the nearest tenth if needed.
Answer:
140 inches
Step-by-step explanation:
Find the area of the square.
4 + 10 = 14 (Length)
11 + 4 = 15 (Breadth/Width)
Area = 14 x 15 = 210 inches
Find the area of the 2 unshaded squares in the square.
Area of square at the top = 4 x 4 = 16 inches
Area of square at the bottom = 6 x 9 = 54 inches
Add the 2 squares of the area together.
16 + 54 = 70 inches
Now deduct the area of the huge box by the area of the 2 unshaded squares.
210 - 70 = 140 inches
An artist builds a sculpture out of metal and wood that weighs 14.9 kilograms. 3/4 of this weight is metal, and the rest is wood. How much does the wood part of the sculpture weigh? (no decimals)
Answer:Weight of wood part of the sculpture (no decimals) =4kg
Step-by-step explanation:
Weight of sculpture containing metal and wood = 14.9 kg
weight of metal =3/4 x 14.9 kg =11.175kg
weight of wood =Entire sculpture − weight of metal
= 14.9 kg−11.175kg
=3.725kg
Rounding up to remove decimals we have that Weight of wood part =4kg