Answer:
Percent yield = 7.1%
Explanation:
The general reaction of the problem is:
Ca(OH)₂ + CO₂ → H₂O + CaCO₃
To solve this question we need to find theoretical yield using the amount of carbon dioxide added because:
Percent yield = Actual yield (3.22g) / Theoretical yield * 100
Theoretical yield is the maximum amount of product that could be obtained. To find it we need to convert the mass of CO₂ to moles. The moles of CO₂ = Moles of CaCO₃:
Moles CO₂ -Molar mass: 44.01g/mol):
20.0g * (1mol / 44.01g) = 0.454 moles CO₂ = Moles of CaCO₃ produced
Mass CaCO₃ = Theoretical yield -Molar mass: 100.09g/mol-:
0.454 moles * (100.09g / mol) = 45.5g of CaCO₃ = Theoretical yield.
Replacing:
Percent yield = 3.22g / 45.5g * 100
Percent yield = 7.1%