Answer:
Number of dollar = 28.28 (Approx)
Step-by-step explanation:
Given:
176 dollar = 140 pound
1 pound = Rs.130
Find:
Number of dollars in Rs 2925
Computation:
1 pound = Rs.130
Number of pound = 2925 / 130
Number of pound = 22.5 pound
1 pound = 176 / 140
Number of dollar = [176 / 140]22.5
Number of dollar = 28.28 (Approx)
Look at picture (15 point)
Answer:
[tex]x \sqrt{2} [/tex]Option C is the correct option
Step by step explanation
[tex] \sqrt{ \frac{22 {x}^{6} }{11 {x}^{4} } } [/tex]
Reduce the fraction with 11
[tex] \sqrt{ \frac{2 {x}^{6} }{ {x}^{4} } } [/tex]
Simplify the expression
[tex] \sqrt{2 {x}^{6 - 4} } [/tex]
[tex] \sqrt{2 \: {x}^{2} } [/tex]
Simplify the radical expression
[tex]x \sqrt{2} [/tex]
Hope this helps...
Good luck on your assignment..
A bag contains a collection of distinguishable marbles. The bag has two red marbles, three green ones, one lavender one, two yellows, and two orange marbles. HINT [See Example 7.] How many sets of four marbles include exactly two green marbles
Answer:
63
Step-by-step explanation:
Given that;
The bag has two red marbles, n(red) =2
three green ones marbles, n(green) = 3
one lavender one marbles, n(lavender) = 1
two yellows marbles, n(yellow ) = 2
two orange marbles. n(orange) = 2
number of non green marbles = 2+1+2+2 = 7
The objective is to find out how many sets of four marbles include exactly two green marbles
Since sets of four marbles contain exactly two green marbles, then N(select 2 from 3 marbles and 2 from 7 marbles)
= [tex]^3C_2 \times ^{7}C _2[/tex]
= [tex]\dfrac{3!}{2!(3-2)!} \times \dfrac{7!}{2!(7-2)!}[/tex]
= [tex]\dfrac{3*2!}{2!} \times \dfrac{7*6*5!}{2!(5)!}[/tex]
= [tex]3 \times 7\times 3[/tex]
= 63
Given that a function, g, has a domain of -20 ≤ x ≤ 5 and a range of -5 ≤ g(x) ≤ 45 and that g(0) = -2 and g(-9) = 6, select the statement that could be true for g. A. g(0) = 2 B. g(7) = -1 C. g(-13) = 20 D. g(-4) = -11
Answer:
C. g(-13) = 20
Step-by-step explanation:
Let's check the offered statements:
A. g(0) = 2 . . . . . . doesn't match g(0) = -2
B. g(7) = -1 . . . . . . 7 is not in the domain of g
C. g(-13) = 20 . . . could be true
D. g(-4) = -11 . . . . -11 is not in the range of g
An epidemiologist wishes to know what proportion of adults living in a large metropolitan area have subtype ayr hepatitis B virus. Determine the sample size that would be required to estimate the true proportion to within 3% margin of error with 95 percent confidence.
Answer:
Sample size 'n' = 1067
Step-by-step explanation:
Explanation:-
Given margin of error of the true proportion
M.E = 0.03
The margin of error is determined by
[tex]M.E =Z_{\alpha } \frac{\sqrt{p(1-p)} }{\sqrt{n} }[/tex]
Level of significance = 0.95
The critical value Z₀.₀₅ = 1.96
The margin of error is
[tex]0.03 =1.96 \frac{\sqrt{p(1-p)} }{\sqrt{n} }[/tex]
we know that
[tex]\sqrt{p(1-p} \leq \frac{1}{2}[/tex]
[tex]0.03 =\frac{1.96 X\frac{1}{2} }{\sqrt{n} }[/tex]
on cross multiplication , we get
√n = 32.66
Squaring on both sides, we get
n = 1066.6≅1067
Solve the system for x. x+y+z=5 2x-y-z=-2 2x=10
Answer:
x = 1.
Step-by-step explanation:
x + y + z = 5
2x - y - z = -2
3x = 3
x = 1
Hope this helps!
Solve the system of linear equations and check any solutions algebraically.
Answer:
[tex]\boxed{\sf \ \ x = 9, \ y = -5, \ z = 5 \ \ }[/tex]
Step-by-step explanation:
Hello,
(1) 2x + 4y + z = 3
(2) x - 2y - 3z = 4
(3) x + y - z = -1
From (3) we can write z = x + y + 1 and we replace in (1)
2x + 4y + x + y + 1 = 3 <=> 3x + 5y = 3-1 =2
(1') 3x + 5y = 2
and we replace in (2)
x - 2y -3(x+y+1) = 4 <=> -2x -5y -3 = 4 <=> -2x -5y = 4 + 3 = 7
(2') -2x - 5y = 7
(1') + (2') gives
3x - 2x + 5y - 5y = 2 + 7 = 9
x = 9
we replace in (1')
3*9 + 5y = 2 <=> 27 + 5y = 2 <=> 5y = 2-27 = -25 <=> y = -25/5 = -5
y = -5
and then in (3)
9 - 5 - z = -1 <=> 4 - z = -1 <=> z = 4 + 1 = 5
z = 5
hope this helps
Answer:
work is shown and pictured
How many odd 2 digit positive odd integers geater than 50 are there?
Answer:
25
Step-by-step explanation:
Let's break this down step by step:
"2 digit positive odd integers greater than 50"
So we start at 50
Don't exceed 99 since 2-digit limit
Any 2-digit integer greater than 50 will be positive (So that's a redundant statement)
Well...we know that from 50-99, is 50 integers counting by ones.
We know that half will be even and half will be odd.
With this we can say 50/2 == 25
Hence, there are 25 2 digit positive odd integers greater than 50.
Cheers.
A factory manufactures chairs and tables, each requiring the use of three operations: cutting, assembly, and finishing. The first operation can use at most 40 hours; the second at most 42 hours; and the third at most 25 hours. A chair requires 1 hour of cutting, 2 hours of assembly, and 1 hour of finishing; a table needs 2 hours of cutting, 1 hour of assembly, and 1 hour of finishing. If the profit is $20 per unit for a chair and $30 for a table, what is the maximum revenue? Round your answer to the nearest whole number. Do not include a dollar sign or comma in your answer.
Answer:
z(max) = 650 $
x₁ = 10 units
x₂ = 15 units
Step-by-step explanation:
That is a linear programming problem, we will use a simplex method to solve it
Formulation:
Let´s call x₁ number of chairs and x₂ number of tables then :
Item (in hours) cutting assembly finishing Profit ($)
Chairs (x₁) 1 2 1 20
Tables (x₂) 2 1 1 30
Availability 40 42 25
Objective Function
z = 20*x₁ + 30x₂ ( to maximize) subject to:
x₁ + 2x₂ ≤ 40
2x₁ + x₂ ≤ 42
x₁ + x₂ ≤ 25
x₁ , x₂ >= 0
Using excel or any other software we find:
z(max) = 650
x₁ = 10
x₂ = 15
The chairs and tables manufactured by the factory is an illustration of linear programming, where the maximum revenue is 674
Let x represent chairs, and y represent tables
So, the given parameters are:
Cutting:
Chairs: 1 hourTable: 2 hoursHour available: 40So, the constraint is:
[tex]\mathbf{x + 2y \le 40}[/tex]
Assembly:
Chairs: 2 hoursTable: 1 hourHour available: 42So, the constraint is:
[tex]\mathbf{2x + y \le 42}[/tex]
Finishing:
Chairs: 1 hourTable: 1 hourHour available: 25So, the constraint is:
[tex]\mathbf{x + y \le 25}[/tex]
The unit profit on the items are:
Chairs: $20Table: $30So, the objective function to maximize is:
[tex]\mathbf{Max\ z = 20x + 30y}[/tex]
And the constraints are:
[tex]\mathbf{x + 2y \le 40}[/tex]
[tex]\mathbf{2x + y \le 42}[/tex]
[tex]\mathbf{x + y \le 25}[/tex]
[tex]\mathbf{x,y \ge 0}[/tex]
Using graphical method (see attachment for graph), we have the following feasible points:
[tex]\mathbf{(x,y) = \{(10,15),\ (17,8),\ (14.67, 12.67)\}}[/tex]
Calculate the objective function using the feasible points.
[tex]\mathbf{z = 20 \times 10 + 30 \times 15}[/tex]
[tex]\mathbf{z = 650}[/tex]
[tex]\mathbf{z = 20 \times 17 + 30 \times 8}[/tex]
[tex]\mathbf{z = 580}[/tex]
[tex]\mathbf{z = 20 \times 14.67+ 30 \times 12.67}[/tex]
[tex]\mathbf{z = 673.5}[/tex]
Approximate
[tex]\mathbf{z = 674}[/tex]
Hence, the maximum revenue is 674
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A coin is tossed and an eight-sided die numbered 1 through 8 is rolled. Find the probability of tossing a tail and then rolling a number greater than 3. The probability of tossing a tail and then rolling a number greater than 3 is
Answer:
5/16
Step-by-step explanation:
P(tails) = 1/2
P(>3) = 5/8
P(tails AND >3) = 1/2 × 5/8 = 5/16
Cassie has test grades of 71, 78 and 83 on the first three tests in her
pre-algebra class. What are the possible scores she can make on the
fourth test in order to make at least a letter grade of B after the fourth
test? A letter grade B means an average of at least 80. Let x represent
the score on the fourth test.
Answer:
x ≥ 88
Step-by-step explanation:
In order to have at least an average of 80 after 4 tests, the sum of her scores must be at least 80 * 4 = 320 so we can write the following inequality:
71 + 78 + 83 + x ≥ 320
232 + x ≥ 320
x ≥ 88
Answer:
Your correct answer to this problem is x ≥ 88
Step-by-step explanation:
71 + 78 + 83 + x ≥ 320
232 + x ≥ 320
= x ≥ 88
A political analyst predicts Mr. Smith will only get 122 votes for mayor. If Mr. Smith only gets 57 votes, what is the political analyst's percent error?
Answer:
65%
Step-by-step explanation:
A=63°
C = 7.75 inch
B = 47°
Oblique Triangle
13. Refer to the oblique triangle shown. What's the length of side a? Round to the nearest hundredth of an inch.
O A. 7.75 inches
O B. 7.35 inches
O C.4.72 inches
O D. 6.03 inches
Answer:
B. 7.35 inches
Step-by-step explanation:
In the triangle:
A=63° c = 7.75 inch B = 47°Now we know that:
[tex]\angle A+\angle B+\angle C=180^\circ$ (Sum of angles in a \triangle)\\63^\circ+47^\circ+\angle C=180^\circ\\\angle C=180^\circ-(63^\circ+47^\circ)\\\angle C=70^\circ[/tex]
Using the Law of Sines
[tex]\dfrac{a}{\sin A} =\dfrac{c}{\sin C}\\\\\dfrac{a}{\sin 63^\circ} =\dfrac{7.75}{\sin 70^\circ} \\\\a=\dfrac{7.75}{\sin 70^\circ} \times \sin 63^\circ\\\\a=7.35$ inches (to the nearest hundredth of an inch)[/tex]
Answer:
B. 7.35 inches
Step-by-step explanation:
just use the law of sines
Solve for X in the equation, where X = 3A − 2B
Answer:
work is shown and pictured
Answer:
Image is attached.
Solve for the x in the diagram below. 50°, 2x°, and 150°
The value of x from the diagram is 50 degrees. Vertical angles are angles that meets at a point of intersection.
Vertical anglesVertical angles are angles that meets at a point of intersection. From the given diagram 150 and 50+2x are vertical angles showing that they are equal to each other. Hence;
50 + 2x = 150
2x = 150 - 50
2x = 100
Divide both sides by 2
2x/2 = 100/2
x = 50
Hence the value of x from the diagram is 50 degrees
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In order to sustain itself in its cold habitat, a Siberian tiger requires 25 pounds of meat per day.
How much meat would seven Siberian tigers need for the month of April?
Select one:
a. 750 pounds
b. 175 pounds
c. 5425 pounds
d. 5250 pounds
Answer:
the answer is 750 because there are 30 days in the month of april and you just need to multiply it by how much meat they need to have per day.
Step-by-step explanation:
30 x 25 = 750
i got 11 first but im not too sure cause sometimes it will ask me it's wrong Use the integers that are closest to the number in the middle.
Answer:
11 < √137 < 12
Step-by-step explanation:
the closest squares are 121 and 144; 11² and 12²
There are two frozen yogurt stores in the mall. Both stores sell frozen yogurt by the ounce. Hammy's Froyo charges $2.40 for the container and $0.40 for each ounce of yogurt. Yogurt Palace charges $0.80 for each ounce of yogurt (no charge for the container). Graph the line that shows the cost of frozen yogurt at Hammy's Froyo. Graph the line that shows the cost of frozen yogurt at Yogurt Palace.
Answer:
The graphs for the lines of the costs are in the attachment. For this answer you have to first determine the equations for each cost. Since Hammy's Froyo charges $2.40 for the container and $.40 for each ounce, the equation would be y=.40x+2.40. For Yogurt Palace, which charges $0.80 for each ounce, the equation would be y=.80x.
Find x and y, please solve with steps and leave answers in fraction form, THANK YOU
Answer:
Below
Step-by-step explanation:
Using the proprtionality relation:
● 8/10 =5/x
● (4*2)/(5*2) = 5/x
Simplify using 2
● 4/5 = 5/x
Multiply both sides by 5
● (4/5)*5 = (5/x)*5
● 4 = 25/x
Switch x and 4
● x= 25/4
■■■■■■■■■■■■■■■■■■■■■■■■■
Again use the proportionality relation but this time with y.
● 8/10 =7/y
8/10 = 4/5
● 4/5 = 7/y
Multiply both sides by 5
● (4/5)*5 =(7/y)*5
● 4 = 35/y
Switch 4 and y
● y = 35/4
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2-cm and a standard deviation of 2.1-cm. For shipment, 17 steel rods are bundled together. Find the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259-cm.
Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let [tex]\bar X[/tex] = the average length of rods in a randomly selected bundle of steel rods
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean length of rods = 259.2 cm
[tex]\sigma[/tex] = standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P([tex]\bar X[/tex] > 259 cm)
P([tex]\bar X[/tex] > 259 cm) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{259-259.2}{\frac{2.1}{\sqrt{17} } }[/tex] ) = P(Z > -0.39) = P(Z < 0.39)
= 0.65173
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
6th grade math, help me please.
Answer:
1:3
Step-by-step explanation:
3/3=1
9/3=6
Answer:
1 : 3Option A is the correct option.
Step-by-step explanation:
Given,
Number of pears = 3
Number of apples = 9
Find : Ratio of the number of pears to the number of apples on the fruit salad
Now,
[tex] \frac{pear}{apples} [/tex]
Plug the values
[tex] = \frac{3}{9} [/tex]
Divide the numerator and denominator by 3
[tex] = \frac{3 \div 3}{9 \div 3} [/tex]
Divide the numbers
[tex] = \frac{1}{3} [/tex]
It can be written as :
1 : 3
Hope this helps..
Best regards!!!
someone could help me?
Answer:
Step-by-step explanation:
From 6 to 9 is 3 units, the horizontal distance between C and D. From 4 to 5 is 1 unit, the vertical distance between C and D.
Using the Pythagorean Theorem (or the closely related distance formula), we find the distance between C and D as follows:
distance between C and D: sqrt(3^2 + 1^2) = sqrt(10)
helpppppppppppppppppppppppppppppppppppppppppppppppppppppp
Answer:
4
Step-by-step explanation:
Answer:
1/8 < 1/6
Step-by-step explanation:
The top is divided into 8 and 1 part is shaded so 1/8
The bottom is divided into 6 and 1 part is shaded so 1/6
Comparing
1/8 < 1/6
An account is opened with an initial deposit of $100 and earns 3.0% interest compounded monthly. What will the account be worth in 25 years? Round your answer to the nearest dollar.
Answer:
A = $211.50
A = P + I where
P (principal) = $100.00
I (interest) = $111.50
Step-by-step explanation:
$209.37 will the account be worth in 25 years.
What is compound interest?Compound Interest is defined as interest earn on interest.
[tex]A = P(1 + \frac{r}{100})^{t}[/tex]
P= $100
r = 3%
t=25 years
substitute the values in formula,
[tex]A = 100(1 + \frac{3}{100})^{25}[/tex]
[tex]A = 100(1 + 0.03)^{25}[/tex]
[tex]A = 100(1.03)^{25}[/tex]
[tex]A=100(2.0937)[/tex]
[tex]A=209.37[/tex]
Hence, $209.37 will the account be worth in 25 years.
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A college graduate is curious about the proportion of graduates who have loan debt 20 years after graduating. Let the proportion of graduates who have loan debt 20 years after graduating be p. If the college graduate wishes to know if the proportion of graduates who have loan debt 20 years after graduating is less than 18%, what are the null and alternative hypotheses?
Answer: Null Hypothesis [tex]H_{0}[/tex]: p = 0.18
Alternative Hypothesis [tex]H_{a}[/tex]: p < 0.18
Step-by-step explanation: When doing an experiment, first define the hypotheses you want to test. These hypotheses are Null Hypothesis and Alternative Hypothesis
Null Hypothesis is a general assumption and discloses that there is no relationship between the conditions under consideration. It is the hypothesis the researcher is trying to disprove. It is denoted by the symbol [tex]H_{0}[/tex].
For the college graduate curiosity, the hypothesis the graduate is trying to disprove is that the proportion of students who have loan debt after 20 years of graduation is 18%. Then, Null Hypothesis is [tex]H_{0}[/tex]: p = 0.18
Alternative Hypothesis is the a statement describing a relationship between the collected data. It is what researches try to prove and the results are observations of real causes. It is denoted by the symbol [tex]H_{a}[/tex].
For the graduate study, the alternative is that the proportion is less tahn 18% or 0.18. Then, Alternative Hypothesis: [tex]H_{a}[/tex]: p < 0.18
help i need to know pls
Answer:
7.8 =x
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp / adj
tan 48 = x/7
7 tan 48 = x
7.774287604 = x
To the nearest tenth
7.8 =x
Look at the number pattern shown below:3 × 17 = 5133 × 167 = 5511333 × 1667 = 555111What will be 33333 × 166667?
Answer:
33333 x 166667 = 5555511111
I think that is the answer you wanted
Step-by-step explanation:
166667
x 33333
5555511111
Problem 2
In the above diagram, circles O and O' are tangent at X, and PQ is tangent to both circles. Given that
OX= 3 and O'X = 8. find PQ.
Answer:
√96
Step-by-step explanation:
PQ is tangent to both lines, so PQ is perpendicular to PO and QO'.
The radius of the smaller circle is 3, and the radius of the larger circle is 8.
If we draw a line from O to O', and another line from point O to line QO' that is parallel to PQ, we get a right triangle where OO' is the hypotenuse, the short leg is 8−3=5, and the long leg is the same length as PQ.
Using Pythagorean theorem:
x² + 5² = 11²
x = √96
Need help with graphing
Part F
I NEED HELP!
What is the geometric mean of the measures of the line segments A Dand DC? Show your work.
Answer:
The geometric mean of the measures of the line segments AD and DC is 60/13
Step-by-step explanation:
Geometric mean: BD² = AD×DC
BD = √(AD×DC)
hypotenuse/leg = leg/part
ΔADB: AC/12 = 12/AD
AC×AD = 12×12 = 144
AD = 144/AC
ΔBDC: AC/5 = 5/DC
AC×DC = 5×5 = 25
DC = 25/AC
BD = √[(144/AC)(25/AC)]
BD = (12×5)/AC
BD= 60/AC
Apply Pythagoras theorem in ΔABC
AC² = 12² + 5²
AC² = 144+ 25 = 169
AC = √169 = 13
BD = 60/13
The geometric mean of the measures of the line segments AD and DC is BD = 60/13
A passcode can have 5 or 6 digits. Digits can be repeated and leading 0s are allowed. So, 1234 would be a 4 digit code that is different from 01234, which is a 5 digit code. How many different passcodes are possible
Answer:
The number of passcodes possible is 1,100,000
Step-by-step explanation:
Here , we want to calculate the number of different possible passcodes.
For the five digit code,
each number in the code has a possibility of choosing from the digits 0 to 9, so this means that each of the numbers in the code has 10 options.
So for a five digit code, the number of possible choices would be 10 * 10 * 10 * 10 * 10 = 10^5
For a six digit code, the number of possible choice would be 10 * 10 * 10 * 10 * 10 * 10 * 10 = 10^6
So for 5 or 6 digits code, the number of possible choices would be;
10^5 + 10^6 = 10^5(1 + 10)
= 11(10^5) = 1,100,000
The number of passcodes possible is 1,100,000
Calculation of the no of passcode:For the five-digit code, the no of possible choices should be [tex]10^5[/tex]
For the six-digit code, the no of possible choices should be [tex]10^6[/tex]
So, the possible choices should be
[tex]10^5 + 10^6 = 10^5(1 + 10)\\\\= 11(10^5)[/tex]
= 1,100,000
Hence, The number of passcodes possible is 1,100,000
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